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On the Negative Pell Equation

y

2

48

x

2

23

S. Mallika1, G. Ramya2

1Assistant Professor, 2M. Phil Scholar, Department of Mathematics, SIGC, Trichy-620002, Tamilnadu, India.

Abstract: The binary quadratic equation represents by negative Pellian

y

2

48

x

2

23

is analyzed for its distinct integer

solutions. A few interesting relations among the solution are given. Further, employing the solutions of the above hyperbola, we have obtained solutions of other choices of hyperbolas and parabolas.

Keywords: Binary quadratic, Hyperbola, Parabola, Integral solutions, Pell equation. AMS Mathematics subject Classification (2010):11D09

I. INTRODUCTION

The binary quadratic Diophantine equations (both homogeneous and non-homogeneous) are rich in variety. In [1-17] the binary quadratic non-homogeneous equations representing hyperbolas respectively are studied for their non-zero integral solutions. This communication concerns with yet another binary quadratic equation given by

y

2

48

x

2

23

.The recurrence relations satisfied by the solutions x and y are given. Also a few interesting properties among the solutions are exhibited.

II. METHOD OF ANALYSIS

The negative Pell equation representing hyperbola under consideration is

48

23

2 2

x

y

(1) whose smallest positive integer solution is

5

,

1

0

0

y

x

To obtain the other solutions of (1), consider the Pell equation

1

48

2 2

x

y

whose smallest positive integer solution is

7

~

,

1

~

0

0

y

x

whose general solution is given by

n n

n

n

g

y

f

x

2

1

~

,

48

2

1

~

where

1

1

48

7

48

7

n n

n

f

1

1

48

7

48

7

n n

n

g

Applying Brahmagupta lemma between

x

0

,

y

0

and

~

x

n

,

y

~

n

, the other integer solutions of (1) are given by

n n

n

f

g

x

3

8

5

2

1

1

n n

n

f

g

y

3

6

2

5

1

The recurrence relations satisfied by x and y are given by

0

14

2 1

3

n n

n

x

x

x

0

14

y

y

(2)

Table: 1 Numerical Examples

n

1  n

x

y

n1

-1 1 5

0 12 83 1 167 1157 2 2326 16115 3 32397 224453 4 451232 3126227

From the above table, we observe some interesting relations among the solutions which are presented below:

A.

x

n1 values are alternatively odd and even according as n values &

y

n1values are alternatively odd.

B. Relations Among The Solutions 1)

x

n3

14

x

n2

x

n1

0

2)

7

x

n1

x

n2

y

n1

0

3)

x

n1

7

x

n2

y

n2

0

4)

7

x

n1

97

x

n2

y

n3

0

5)

97

x

n1

x

n3

14

y

n1

0

6)

x

n1

x

n3

2

y

n2

0

7)

x

n1

97

x

n3

14

y

n3

0

8)

y

n2

7

y

n1

48

x

n1

0

9)

y

n3

97

y

n1

672

x

n1

0

10)

7

y

n3

97

y

n2

48

x

n1

0

11)

97

x

n2

7

x

n3

y

n1

0

12)

7

x

n2

x

n3

y

n2

0

13)

x

n2

7

x

n3

y

n3

0

14)

7

y

n3

7

y

n1

672

x

n2

0

15)

48

x

n2

y

n1

7

y

n2

0

16)

y

n3

7

y

n2

48

x

n2

0

17)

97

y

n2

7

y

n1

48

x

n3

0

18)

97

y

n3

y

n1

672

x

n3

0

19)

7

y

n3

y

n2

48

x

n3

0

20)

y

n1

14

y

n2

y

n3

0

C. Each Of The Following Expressions Represents A Nasty Number

1)

996

60

276

23

1

3 2 2

2n

x

n

(3)

2)

6942

30

1932

161

1

4 2 2

2n

x

n

x

3)

576

60

276

23

1

2 2 2

2n

y

n

x

4)

6912

60

1932

161

1

3 2 2

2n

y

n

x

5)

96192

60

26772

2231

1

4 2 2

2n

y

n

x

6)

13884

996

276

23

1

4 2 3

2n

x

n

x

7)

576

996

1932

161

1

2 2 3

2n

y

n

x

8)

6912

996

276

23

1

3 2 3

2n

y

n

x

9)

96192

996

1932

161

1

4 2 3

2n

y

n

x

10)

576

13884

26772

2231

1

2 2 4

2n

y

n

x

11)

6912

13884

1932

161

1

3 2 4

2n

y

n

x

12)

96192

13884

276

23

1

4 2 4

2n

y

n

x

13)

72

864

1656

138

1

2 2 3

2n

y

n

y

14)

6

1002

1932

161

1

2 2 4

2n

y

n

y

15)

432

6012

828

69

1

3 2 4

2n

y

n

y

D. Each Of The Following Expressions Represents A Cubical Integer

1)

166

3 3

10

3 4

498

1

30

2

23

1

 

n

n

n

n

x

x

x

x

2)

1157

3 3

5

3 5

3471

1

15

3

161

1

 

n

n

n

n

x

x

x

x

3)

96

3 3

10

3 3

228

1

30

1

23

1

 

n

n

n

n

y

x

y

x

4)

1152

3 3

10

3 4

3456

1

30

2

161

1

 

n

n

n

n

y

x

y

x

5)

16032

3 3

10

3 5

48096

1

30

3

2231

1

 

n

n

n

n

y

x

y

(4)

6)

2314

3 4

166

3 5

6942

2

498

3

23

1

  

n

n

n

n

x

x

x

x

7)

96

3 4

116

3 3

288

2

498

1

161

1

 

n

n

n

n

y

x

y

x

8)

1152

3 4

166

3 4

3456

2

498

2

23

1

 

n

n

n

n

y

x

y

x

9)

16032

3 4

166

3 5

48096

2

498

3

161

1

 

n

n

n

n

y

x

y

x

10)

96

3 5

2314

3 3

288

3

6942

1

2231

1

 

n

n

n

n

y

x

y

x

11)

1152

3 5

2314

3 4

3456

3

6942

2

161

1

 

n

n

n

n

y

x

y

x

12)

16032

3 5

2314

3 5

48096

3

6942

3

23

1

 

n

n

n

n

y

x

y

x

13)

12

3 4

144

3 3

36

2

432

1

138

1

 

n

n

n

n

y

y

y

y

14)

3 5

167

3 3

3

3

501

1

161

1

 

n

n

n

n

y

y

y

y

15)

72

3 5

1002

3 4

216

3

3006

2

69

1

 

n

n

n

n

y

y

y

y

E. Each Of The Following Expressions Represents A Bi-Quadratic Integer

1)

166

10

664

40

138

23

1

3 2 2 2 5 4 4

4n

x

n

x

n

x

n

x

2)

1157

5

4628

20

966

161

1

4 2 2 2 6 4 4

4n

x

n

x

n

x

n

x

3)

96

10

384

40

138

23

1

2 2 2 2 4 4 4

4n

y

n

x

n

y

n

x

4)

1152

10

4608

40

966

161

1

3 2 2 2 5 4 4

4n

y

n

x

n

y

n

x

5)

16032

10

64128

40

13386

2231

1

4 2 2 2 6 4 4

4n

y

n

x

n

y

n

x

6)

2314

166

9256

664

138

23

1

4 2 3 2 6 4 5

4n

x

n

x

n

x

n

x

7)

96

166

384

664

966

161

1

2 2 3 2 4 4 5

4n

y

n

x

n

y

n

x

8)

1152

166

4608

664

138

23

1

3 2 3 2 5 4 5

4n

y

n

x

n

y

n

x

9)

16032

166

64128

664

966

161

1

4 2 3 2 6 4 5

4n

y

n

x

n

y

n

(5)

10)

96

2314

384

9256

13386

2231

1

2 2 4 2 4 4 6

4n

y

n

x

n

y

n

x

11)

1152

2314

4608

9256

966

161

1

4 3 5 3 5 4 6

4n

y

n

x

n

y

n

x

12)

16032

2314

64128

9256

138

23

1

4 2 4 2 6 4 6

4n

y

n

x

n

y

n

x

13)

12

144

48

576

828

138

1

2 2 3 2 4 4 5

4n

y

n

y

n

y

n

y

14)

167

4

668

966

161

1

2 2 4 2 4 4 6

4n

y

n

y

n

y

n

y

15)

72

1002

288

4008

414

69

1

3 2 4 2 5 4 6

4n

y

n

y

n

y

n

y

F. Each Of The Following Expressions Represents A Quintic Integer

1)

166

5 5

10

5 6

830

3 3

50

3 4

1660

1

100

2

23

1

    

n

n

n

n

n

n

x

x

x

x

x

x

2)

1157

5 5

5

5 7

5785

3 3

25

3 5

11570

1

50

3

161

1

    

n

n

n

n

n

n

x

x

x

x

x

x

3)

96

5 5

10

5 5

480

3 3

50

3 3

960

1

100

1

23

1

    

n

n

n

n

n

n

y

x

y

x

y

x

4)

1152

5 5

10

5 6

5760

3 3

50

3 4

11520

1

100

2

161

1

    

n

n

n

n

n

n

y

x

y

x

y

x

5)

16032

5 5

10

5 7

80160

3 3

50

3 5

160320

1

100

3

2231

1

    

n

n

n

n

n

n

y

x

y

x

y

x

6)

2314

5 6

166

5 7

11570

3 4

830

3 5

23140

2

1660

3

23

1

    

n

n

n

n

n

n

x

x

x

x

x

x

7)

96

5 6

166

5 5

480

3 4

830

3 3

960

2

1660

1

161

1

    

n

n

n

n

n

n

y

x

y

x

y

x

8)

1152

5 6

166

5 6

5760

4 5

830

4 5

11520

2

1660

2

23

1

    

n

n

n

n

n

n

y

x

y

x

y

x

9)

16032

5 6

166

5 7

80160

3 4

830

3 5

160320

2

1660

3

161

1

    

n

n

n

n

n

n

y

x

y

x

y

x

10)

96

5 7

2314

5 5

480

3 5

11570

3 3

960

3

23140

1

1

`

223

1

    

n

n

n

n

n

n

y

x

y

x

y

x

11)

1152

5 7

2314

5 6

5760

3 5

11570

3 4

11520

3

23140

2

161

1

    

n

n

n

n

n

n

y

x

y

x

y

x

12)

16032

5 7

2314

5 7

80160

3 5

11570

3 5

160320

3

23140

3

23

1

    

n

n

n

n

n

n

y

x

y

x

y

x

13)

12

5 6

144

5 5

60

3 4

720

3 3

120

2

1440

1

138

1

    

n

n

n

n

n

n

y

y

y

y

y

(6)

14)

5 7

167

5 5

5

3 5

835

3 3

10

3

1670

1

161

1

 

 

n

n

n

n

n

n

y

y

y

y

y

y

15)

72

5 7

1002

5 6

360

3 5

5010

3 4

720

3

10020

2

69

1

 

 

n

n

n

n

n

n

y

y

y

y

y

y

III. REMARKABLE OBSERVATIONS

A. Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of hyperbola which are presented in the Table: 2 below:

Table: 2 Hyperbolas

S. No Hyperbola

X

,

Y

1 2

48

2

529

Y

X

83

x

n1

5

x

n2

,

x

n2

12

x

n1

2 2

48

2

103684

Y

X

1157

x

n1

5

x

n3

,

x

n3

167

x

n1

3 2

48

2

529

Y

X

48

x

n1

5

y

n1

,

y

n1

5

x

n1

4 2

48

2

25921

Y

X

576

x

n1

5

y

n2

,

y

n2

83

x

n1

5 2

48

2

4977361

Y

X

8016

x

n1

5

y

n3

,

y

n3

1157

x

n1

6 2

48

2

529

Y

X

1157

x

n2

83

x

n3

,

12

x

n3

167

x

n2

7 2

48

2

25921

Y

X

48

x

n2

83

y

n1

,

12

y

n1

5

x

n2

8 2

48

2

529

Y

X

576

x

n2

83

y

n2

,

12

y

n2

83

x

n2

9 2

48

2

25921

Y

X

8016

x

n2

83

y

n3

,

12

y

n3

1157

x

n2

10 2

48

2

4977361

Y

X

48

x

n3

1157

y

n1

,

167

y

n1

5

x

n3

11 2

48

2

25921

Y

X

576

x

n3

1157

y

n2

,

167

y

n2

83

x

n3

12 2

48

2

529

Y

X

8016

x

n3

1157

y

n3

,

167

y

n3

1157

x

n3

13

16

2

3

2

76176

Y

X

3

y

n2

36

y

n1

,

83

y

n1

5

y

n2

14

48

2 2

4976832

Y

X

y

n3

167

y

n1

,

1157

y

n1

5

y

n3

(7)

B. Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of parabola which are presented in the Table: 3 below:

Table: 3 Parabolas

S. No Parabola

X

,

Y

1

23

96

2

529

Y

X

83

x

2n2

5

x

2n3

,

x

n2

12

x

n1

2

322

96

2

103684

Y

X

1157

x

2n2

5

x

2n4

,

x

n3

167

x

n1

3

23

96

2

529

Y

X

48

x

2n2

5

y

2n2

,

y

n1

5

x

n1

4

161

96

2

25921

Y

X

576

x

2n2

5

y

2n3

,

y

n2

83

x

n1

5

2231

96

2

4977361

Y

X

8016

x

2n2

5

y

2n4

,

y

n3

1157

x

n1

6

23

96

2

529

Y

X

1157

x

2n3

83

x

2n4

,

12

x

n3

167

x

n2

7

161

96

2

25921

Y

X

48

x

2n3

83

y

2n2

,

12

y

n1

5

x

n2

8

23

96

2

529

Y

X

576

x

2n3

83

y

2n3

,

12

y

n2

83

x

n2

9

161

96

2

25921

Y

X

8016

x

2n3

83

y

2n4

,

12

y

n3

1157

x

n2

10

2231

96

2

4977361

Y

X

48

x

2n4

1157

y

2n2

,

167

y

n1

5

x

n3

11

161

96

2

25921

Y

X

576

x

2n4

1157

y

2n3

,

167

y

n2

83

x

n3

12

23

96

2

529

Y

X

8016

x

2n4

1157

y

2n4

,

167

y

n3

1157

x

n3

13

552

3

2

38088

Y

X

3

y

2n3

36

y

2n2

,

83

y

n1

5

y

n2

14

23184

3

2

7465248

Y

X

y

2n4

167

y

2n2

,

1157

y

n1

5

y

n3

15

552

3

2

38088

Y

X

36

y

2n4

501

y

2n3

,

1157

y

n2

83

y

n3

IV. CONCLUSION

In this paper, we have presented infinitely many integer solutions for al hyperbola represented by the negative Pell Equation

23

48

2 2

x

(8)

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