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Boundary Value Problems

Volume 2008, Article ID 937138,16pages doi:10.1155/2008/937138

Research Article

Existence of Solutions of Periodic Boundary

Value Problems for Impulsive Functional Duffing

Equations at Nonresonance Case

Xingyuan Liu1and Yuji Liu2

1Department of Mathematics, Shaoyang University, Shaoyang, Hunan 422000, China 2Department of Mathematics, Guangdong University of Business Studies, Guangzhou,

Guangdong 510320, China

Correspondence should be addressed to Xingyuan Liu,[email protected]

Received 19 June 2008; Accepted 27 August 2008

Recommended by Zhitao Zhang

This paper deals with the existence of solutions of the periodic boundary value problem of the impulsive Duffing equations: xt αxt βxt ft, xt, xα1t, . . . , xαnt,a.e.t

0, T,Δxtk Ikxtk, xtk, k 1, . . . , m,Δxtk Jkxtk, xtk, k 1, . . . , m, xi0

xiT, i 0,1. Sucient conditions are established for the existence of at least one solution of

above-mentioned boundary value problem. Our method is based upon Schaeffer’s fixed-point theorem. Examples are presented to illustrate the efficiency of the obtained results.

Copyrightq2008 X. Liu and Y. Liu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

In recent years, many authors studied the solvability of the periodic boundary value problems PBVPs for short for second-order ordinary or functional differential equations with or without impulse effects; see1–24and the references therein. For example, consider the following PBVP:

xt ft, xt, t∈0,2π,

x0 x2π, x0 x2π, 1.1

the well-known result is that iffsatisfies the nonresonance condition

N12fut, u≤ −N2, 1.2

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For PBVP of the Duffing equation

xt cxt gt, xtet, t∈0,2π,

x0 x2π, x0 x2π, 1.3

in16, the authors proved the following results.

Theorem 1.1. Supposegis aL2-Caratheodory function, and there areaA, r <0< Rsuch that

gt, xA, xR, t∈0,2π, gt, xa, xr, t∈0,2π, 1.4

and further there isrL0,2πwith||r||<1C2such that

lim

|x| → ∞

gt, x

x < rt, t∈0,2π. 1.5

Then, PBVP1.3has at least one solution for eacheL20,2πwitha1/2π2π

0 esdsA.

In17, Nieto and Rodr´ıguez-L ´opez studied the following PBVP:

xt axt bxt cxtdxtσt, t∈0, T,

x0 xT, x0 xT. 1.6

They gave Green’s function to express the unique solution for the correspondence second-order functional differential equation with periodic boundary conditions and the functional dependence given by the piecewise constant function. Using upper and lower solution methods, they presented sufficient conditions to assure the existence of solutions of PBVP1.6. The authors in 3,21 also studied the solvability of PBVP1.6 by the similar method.

In2, Ding et al. studied the PBVP:

xt ft, xt, xθt0, t∈0, T,

x0 xT, x0 xT. 1.7

Sufficient conditions for the existence of solutions of PBVP1.7are given by using upper and lower solution method.

The PBVPs,

xt ρ2xt ft, xt, t0,2π,

x0 x2π, x0 x2π, 1.8

xt ρ2xt ft, xt, t0,2π,

x0 x2π, x0 x2π, 1.9

were studied in 8,18–20. In 19, based upon Krasnoselskii fixed-point theorems, Jiang proved that PBVP1.8 and PBVP1.9 with singularity have at least one positive solution provided thatft, xis superlinear or sublinear atx 0 andx ∞. In 21, Wang, who

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least one positive solution provided thatft, xis sublinear atx ∞. In18, Zhang and

Wang established multiplicity results to positive solutions of PBVP1.8and PBVP1.9with

fbeing a Caratheodory function.

In paper24, Liu and Ge studied the following equation:

xtptxt qtxt λft, xtτtrt; 1.10

they established sufficient conditions for the existence of positive periodic solutions of1.10.

In 11, Peng studied the existence of periodic solutions of the functional Duffing

equation:

xt cxt g1

t, xtτ1t

g2

t, xtτ2t

pt. 1.11

The studies on the existence of solutions of the periodic boundary value problems of the second-order impulsive differential equations,

xt ft, xt0, t∈0, T, x0 xT, x0 xT,

Δxitk

Ii, k

xtk

, k1, . . . , p, i0,1,

1.12

can be found in3,4,12–14,20,22,23and the references therein. The methods used there are of lower and upper solutions methods, the monotone iterative technique.

In all above-mentioned papers, the results are based upon the following assumptions. Hf satisfies either the Lipschitzian condition, left Lipschitzian condition, right Lipschitzian condition, or Nagumo conditions.

To the best of our knowledge, the existence of solutions of periodic boundary value problems for impulsive Duffing functional differential equations has not been well studied till now.

In this paper, we investigate the following periodic boundary value problem for the impulsive functional Duffing equation:

xt αxt βxt ft, xt, xα1t

, . . . , xαnt

, a.e.t∈0, T,

Δxtk Ik

xtk

, xtk

, k1, . . . , m,

Δxtk Jk

xtk

, xtk

, k1, . . . , m,

xi0 xiT, i0,1,

1.13

where mis a positive integer,α, βR,f : 0, T×Rn1R is a impulsive Caratheodory

function,αiC10, T,0, T, whose inverse function is denoted byβi withβiC10, T,

Ik, Jk:R2→Rare continuous.

Our purpose here is to provide sufficient conditions for the existence of solutions of 1.13at nonresonance case. This will be done by applying the well-known Schaeffer’s

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The main results and examples in this paper are established inSection 2. The proofs of the main results are presented inSection 3.

2. Main results and examples

In this section, we establish the main results and examples to illustrate the main theorems. To define solutions of PBVP1.13, we introduce the following Banach spaces and definitions.

Supposeu : J 0, TR, and 0 t0 < t1 < · · · < tm < tm1 T. Fork 0, . . . , m,

define the functionuk:tk, tk1→Rbyukt ut. Choose

X

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

u:JR

ukC0

tk, tk1

, k0, . . . , m, there exist the limits lim

t→tkut utk,

lim

t→tkut,

lim

t→0ut u0,

lim

t→Tut uT ⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭

2.1

with the norm

||u||X||u|| sup

t∈0,T

ut 2.2

foruX. Choose

Y X×Rm×Rm 2.3

with the norm

||y||Y ||y||max

sup

t∈0,T

ut , max

1≤k≤m xk ,1max≤k≤m yk

2.4

fory{u, x1, . . . , xm, y1, . . . , ym} ∈Y. Then,XandY are real Banach spaces.

A functionF:0,Rn1Ris called an impulsive Caratheodory function if

iF, u0, u1, . . . , unXfor eachu u0, . . . , unRn1;

iiFt,, . . . ,•is continuous fort /tk k1, . . . , m.

By a solution of PBVP1.13, we mean a functionx:0, TRsatisfying the following conditions:

ixX is differentiable in tk, tk1 k 0,1, . . . , m, there exist the limits

limt→tkxt, limt→tkxt xtk k 0,1, . . . , m, limt→0xt x0 and limt→Txt xT;

iixX is differentiable in tk, tk1 k 0,1, . . . , m, there exist the limits

limt→tkxt, limt→t

kx

t xt

k k 0,1, . . . , m, limt→0xt x0, and limt→Txt xT;

iiixX;

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Consider the following homogenous PBVP:

xt αxt βxt 0, t∈0, T,

Δxtk

0, k1, . . . , m,

Δxtk

0, k1, . . . , m, x0 xT, x0 xT.

2.5

IfxXis a solution of problem2.5, then

xtxt αxtxt βxt2 0,

xtxt αxt2βxtxt 0. 2.6

Integrating them from 0 toT, one sees that

T

0

xt2dtβ

T

0

xt2dt0, α

T

0

xt2dt0. 2.7

Ifβ >0 andα /0 orβ <0, we getxt≡0, then problem2.5has unique solutionxt 0 at the cases eitherβ >0 andα /0 orβ <0. We call PBVP1.13at nonresonance case. It suffices

to consider the following cases:

Case 1. α≥0, β <0,

Case 3. α >0, β >0,

Case 2. α <0, β <0,

Case 4. α <0, β >0. 2.8

We set the following assumptions which should be used in the main results. A1xIkx, y≥0 for allx, yR.

A1 Ikx, y2xIkx, y≤0 for allx, yR.

A2xJkx, y yIkx, y λIkx, yJkx, y≥0 for allx, yR, λ∈0,1.

A2xJkx, y yIkx, y λIkx, yJkx, y≤0 for allx, yR, λ∈0,1.

A3 There exist constantsθk ≥ 0 such that|Ikx, y| ≤ θk|x|for all x, yR with

m

k1θk<1.

CThere exist impulsive Caratheodory functionsh:0, T×RnR,g

i:0, T×RR,

and functionrXand such that ift, x0, . . . , xn ht, x0, . . . , xn

n

i0git, xirtholds for allt, x0, . . . , xn

0, T×Rn1.

iiThere exist constantsq≥0 andθ >0 such that

ht, x0, . . . , xnx0≥θ|x0|q1 2.9

holds for allt, x0, . . . , xn∈0, T×Rn1.

iiilim|x| →∞supt∈0,T|git, x|/|x|

q r

i∈0,∞fori0, . . . , n.

CThere exist impulsive Caratheodory functionsh:0, T×RnR,g

i:0, T×RR,

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iiThere exist constantsq≥0 andθ >0 such that

ht, x0, . . . , xnx0 ≤ −θ|x0|q1 2.10

holds for allt, x0, . . . , xn∈0, T×Rn1.

Theorem 2.1. Supposeα≥0andβ <0,A1,A2,A3, andChold. Then, PBVP1.13has at

least one solution if

θ > r0 n

k1

rk βk

q/q1 2.11

holds.

Theorem 2.2. Supposeα <0andβ <0,A1,A2,A3, andChold. Then, PBVP1.13has at

least one solution if2.11holds.

Theorem 2.3. Supposeα >0andβ >0,A1,A2,A3, andChold. Then, PBVP1.13has at

least one solution if2.11holds.

Theorem 2.4. Supposeα <0andβ >0,A1,A2,A3, andChold. Then, PBVP1.13has at

least one solution if2.11holds.

To illustrate our main results, we present two boundary value problems that our results can readily apply, whereas the known results in the current literature do not cover.

Example 2.5. Consider the following PBVP:

xt αxt βxt

2q1

k0

kxkt rt, t∈0, T, t /tk, k1, . . . , m,

Δxtk

0, k1, . . . , m,

Δxtk bk

xtk 3

, k1, . . . , m, x0 xT, x0 xT,

2.12

whereqis a positive integer,k≥0,T >0,ris a continuous function. Corresponding to PBVP

1.13, one finds that

ft, x0, x1, . . . , xn

2q1

k0

kxk0rt,

Ikx, y 0, Jkx, y bkx3,

2.13

It is easy to see that

i A1holds,

iisinceak ≥0, one gets thatyIkx, y xJkx, y λIkx, yJkx, y bkx4 ≥0, then

A2holds,

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ivht, x 2q1x2q1withα2q1>0 andgkt, x αkxkfork0,1, . . . ,2qimplies that

Cholds.

It follows fromTheorem 2.1that PBVP2.12has at least one solution.

Example 2.6. Consider the following PBVP:

xt αxt βxt

2q1

k0

αkxkt n

k1

βkx2q1

1

n1t

rt,

t∈0, T, t /tk, k1, . . . , m,

Δxtk

0, k1, . . . , m,

Δxtk

bk

xtk 5

, k1, . . . , m,

x0 xT, x0 xT,

2.14

where α ≥ 0, β < 0, T > 0, q is a positive integer,α2q1 > 0, m, n are positive integers,

rL10, T,b

kR, 0< t1<· · ·< tm< T,αk, βkR.

It is easy to see that i A1holds,

iiIt is easy to see that

xJkx, y yIkx, y λIkx, yJkx, y bkx6≥0 2.15

ifbk≥0, thenA2holds,

iii A3holds,

ivif2ht, x α2q1x2q1withα2q1 >0 andgkt, x βkx2q1fork1, . . . , n,g0t, x q

k0αkxk, thenCholds.

It follows fromTheorem 2.2that PBVP2.14has at least one solution if

bk≥0, k1, . . . , m, m

k1

|bk|<1,

α2q1>0, n

k1

βkα2q1/0, n

k1

βkn12q1/2q2< α2q1.

2.16

3. Proofs of theorems

In this section, we prove that main theorems are presented inSection 2. We define the linear operatorL:DLXY and the nonlinear operatorN:XYby

Lxt

⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝

xt αxt βxt

Δxt1

.. . Δxtm

Δxt1

.. . Δxtm

⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠

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where

DL

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

u:0, T−→R

uX is differentiable intk, tk1

k0,1, . . . , m,

there exist the limits lim

t→tkx t,

lim

t→tkx

t xt k

k0,1, . . . , m,

lim

t→0x

t x0, lim t→T−x

t xT,

xX there exist the limits lim

t→tkx t,

lim

t→tkx

t xtk k0,1, . . . , m,

lim

t→0x

t x0, lim

t→Tx

t xT,

xX,

⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭ ,

Nxt

⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝

ft, xt, xα1t

, . . . , xαnt

I1

xt1

, xt1

.. .

Im

xtm

, xtm

J1

xt1

, xt1

.. .

Jm

xtm

, xtm ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠

forxX.

3.2 Lemma 3.1. Suppose α /0, β /0, or α 0 and β < 0, f : 0, T×Rn1R is an impulsive

Caratheodory function,Ik, Jk:R2→Rare continuous. Then, the following results hold.

iKerL{0}.

iiLis a Fredholm operator of index zero.

iiiNisL-compact onΩwithΩbeing open and bounded.

Lemma 3.2 15. Let X and Y be Banach spaces. Suppose L : DLXY is a Fredholm operator of index zero withKerL{0},N:XY isL-compact on any open-bounded subset ofX. If0 ∈Ω⊂Xis an open-bounded subset andLx /λNxfor allxDLΩandλ∈0,1, then there exists at least onex∈Ωsuch thatLxNx.

Lemma 3.3. Supposeβ <0andα≥0andA1,A2,A3, andChold. LetΩ1 {xDL:

LxλNx,λ∈0,1}.Then,Ω1is bounded if2.11holds.

Proof. Supposex∈Ω1, then

xt αxt βxt λft, xt, xα1t

, . . . , xαnt

, a.e.t∈0, T,

Δxtk

λIk

xtk

, xtk

, k1, . . . , m,

Δxtk

λJk

xtk

, xtk

, k1, . . . , m, x0 xT, x0 xT.

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Step 1. Prove that there exists a constantM1>0 so that T

0|xs|

q1dsM

1for eachx∈Ω1.

Multiplying both sides of the first equation of3.3byxt, integrating it from 0 toT, we get fromCthat

xTxTx0x0−

m

k1

xtkxtkxtk

xtk

T

0

xs2ds

α 2

xT2−x02−α

2

m

k1

xtk2−xtk

2

β

T

0 xt 2

dt

λ

T

0

fs, xs, xα1s

, . . . , xαns

xsds

λ

T

0

hs, xs, xα1s

, . . . , xαns

xsds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsds

.

3.4

It follows fromA1that

m

k1

xtk2−xtk 2

m

k1

xtkxtk

xtk xtk

m

k1

Δxtk

2xtk

Δxtk

λ

m

k1

Ik

xtk

, xtk

2xtk

λIk

xtk

, xtk

≥2λ

m

k1

Ik

xtk

, xtk

xtk

≥0.

3.5

On the other hand,A2implies that

m

k1

xtkxtkxtk

xtk

m

k1

xtkxtkxtk

xtkxtk

xtk

λ

m

k1

xtk

Ik

xtk

, xtk

xtk

Jk

xtk

, xtk

λ2m k1

Ik

xtk

, xtk

Jk

xtk

, xtk

≥0.

3.6

We get

T

0

hs, xs, xα1s

, . . . , xαns

xsds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsds≤0.

(10)

It follows fromCthat

θ

T

0

xs q1ds≤ −

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsdsβ

T

0

xt 2dt

T

0 g0

s, xs xs ds

n

i1 T

0 gi

s, xαis xs ds

T

0

rs xs ds.

3.8

Let >0 satisfy

θ >r0

n

k1

rk βk q/q1. 3.9

For such >0, there existsδ >0 such that for everyi0,1, . . . , n,

git, x <

ri

|x|q for a.e.t∈0, Tand all xsuch that|x|> δ. 3.10

Let, fori1, . . . , n,Δ1,i {t: t∈0, T,|xαit| ≤δ}, Δ2,i {t: t∈0, T,|xαit|> δ},

gδ,i maxt∈0,T,|x|≤δ|git, x|, andΔ1{t∈0, T,|xt| ≤δ},Δ2 {t∈0, T,|xt|> δ},and

δmax{gδ,k:k0, . . . , n}. Then, we get

θ

T

0

xs q1

ds Δ1 g0

s, xs xs ds

Δ2 g0

s, xs xs ds

n

i1

Δ1,i

gi

s, xαis xs ds

n

i1

Δ2,i

gi

s, xαis xs ds T

0

rs xs ds

r0

T

0

xs q1

ds

n

k1

rk

T

0 x

αks q xs ds

T

0

rs xs dsgδ,0 T

0

xs ds

n

k1

gδ,k T

0

xs ds

r0

T

0

xs q1ds

n

k1

rk

T

0

xαks q1ds

q/q1T

0

xs q1ds

1/q1

T

0

rs q1/qds

q/q1T

0

xs q1ds

1/q1

n1δ

T

0

xs ds

r0

T

0

xs q1ds

n

k1

rk αkT

αk0

xu q1 βku du

q/q1T

0

xs q1ds

(11)

T

0

rs q1/q

ds

q/q1T

0

xs q1

ds

1/q1

n1δTq/q1

T

0

xs q1

ds

1/q1

r0

T

0

xs q1ds

n

k1

rk βk q/q1

T

0

xu 1q

du

q/q1T

0

xs q1

ds

1/q1

T

0

rs q1/q

ds

q/q1T

0

xs q1

ds

1/q1

n1δTq/q1

T

0

xs q1ds

1/q1

r0

n

k1

rk βk q/q1

T

0

xs q1ds

T

0

rs q1/q

ds

q/q1T

0

xs q1

ds

1/q1

n1δTq/q1

T

0

xs q1

ds

1/q1

.

3.11

Then,3.9implies that there exists a constantM1>0 such that T

0|xs|

q1dsM 1.

Step 2. Prove that there exists a constantM2>0 such that||x||M2for eachx∈Ω1.

It follows from Step1that there existsξ∈0, Tsuch that|| ≤M1/T1/q1.

Multiplying both sides of the first equation of3.3byxt, integrating it from 0 toT, we get, usingA1,A2, andC,

T

0

xs2ds−1

2

m

k1

xtk2−xtk 2

m k1

xtkxtkxtkx

tk

λ

T

0

fs, xs, xα1s

, . . . , xαns

xsdsλβ

T

0 xt 2

dt

≤ −λ

T

0

fs, xs, xα1s

, . . . , xαns

xsdsλβ

T

0

xt 2dt

≤ −λ

T

0

hs, xs, xα1s

, . . . , xαns

xsds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsds

λβ

T

0 xt 2

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≤ −λ

T

0

g0

s, xsxsdsλ

n

i1 T

0

gi

s, xαis

xsdsλ

T

0

rsxsds

T

0 g0

s, xs xs ds

n

i1 T

0 gi

s, xαis xs ds T

0

rs xs ds

≤ ! r0 n

k1

rk βk q/1q

T

0

xs q1ds

T

0

rs q1/qds

q/q1T

0

xs q1ds

1/q1"

n1δTq/q1

T

0

xs q1ds

1/q1

. 3.12

Then,

T

0

xs2ds

!

r0

n

k1

rk βk q/1q

M1

T

0

rs q1/qds

q/q1

M11/q1

"

n1δTq/q1M11/q1

:M2.

3.13 Due toA3, one sees that

xt ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

λ

ξ≤tk<t

Ik

xtk

, xtk

t

ξ

xsds iftξ,

λ

t≤tk<ξ

Ik

xtk

, xtk

ξ

t

xsds

ift < ξ,

M1

T

1/q1 m

k1

θk x T

0

xs ds

M1

T

1/q1 m

k1

θk x T1/2

T

0 xs 2

ds

1/2

M1

T

1/q1

m

k1

θk x T1/2M12/2.

3.14

It follows fromA3that

||x||≤ 1

1−mk1θk

M

1

T

1/q1

T1/2M12/2

. 3.15

It follows thatΩ1is bounded. This completes the proof ofLemma 3.3.

Lemma 3.4. Supposeβ <0andα >0andA1,A2,A3, andChold. LetΩ1 {xDL:

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Proof. The proof is similar to that ofLemma 3.3.

Lemma 3.5. Supposeβ >0andα >0andA1,A2,A3, andChold. LetΩ1 {xDL:

LxλNx,λ∈0,1}.Then,Ω1is bounded if2.11holds.

Proof. Supposex∈Ω1, then we get3.3.

Step 1. Prove that there exists a constantM1>0 so that T

0|xs|

q1dsM

1for eachx∈Ω1.

Multiplying both sides of the first equation of3.3byxt, integrating it from 0 toT, we get fromC

xTxTx0x0−

m

k1

xtkxtkxtk

xtk

T

0

xs2ds

α 2

xT2−x02−α

2

m

k1

xtk2−xtk

2

β

T

0

xt 2dt

λ

T

0

hs, xs, xα1s

, . . . , xαns

xsds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsds

.

3.16

It follows fromA1that

m

k1

xtk2−xtk

2m

k1

xtkxtk

xtkxtk

m

k1

Δxtk

2xtk

Δxtk

λ

m

k1

Ik

xtk

, xtk

2xtk

λIk

xtk

, xtk

λ

m

k1

Ik

xtk

, xtk

2xtk

Ik

xtk

, xtk

≤0.

3.17

On the other hand,A2implies that

m

k1

xtkxtkxtk

xtk

m

k1

xtkxtkxtk

xtkxtk

xtk

λ

m

k1

xtk

Ik

xtk

, xtk

xtk

Jk

xtk

, xtk

λ2

m

k1

Ik

xtk

, xtk

Jk

xtk

, xtk

≤0.

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We get

λ

T

0

hs, xs, xα1s

, . . . , xαns

xsds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsds

≥0.

3.19

It follows fromCthat

θ

T

0

xs q1

ds

T

0

g0

s, xsxsds

n

i1 T

0

gi

s, xαis

xsds

T

0

rsxsdsβ

T

0 xt 2

dt

T

0 g0

s, xs xs ds

n

i1 T

0 gi

s, xαis xs ds

T

0

rs xs ds.

3.20

The remainder of the proof is similar to that of the corresponding part of the proof of

Lemma 3.3.

Lemma 3.6. Supposeβ >0andα <0andA1,A2,A3, andChold. LetΩ1 {xDL:

LxλNx,λ∈0,1}.Then,Ω1is bounded if2.11holds.

Proof. The proof is similar to that ofLemma 3.5.

Proof ofTheorem 2.1. It is easy to show thatL:DLXY is a Fredholm operator of index zero with KerL {0},N : XY isL-compact on any open-bounded subset ofX. Let Ω satisfy 0∈Ω1⊂Ω⊂Xwhich is a open-bounded subset, whereΩ1is given inLemma 3.3. It

follows fromLemma 3.3thatLx /λNxfor allxDLΩandλ∈0,1, then there exists

at least onex∈Ωsuch thatLxNx. Hence,xis a solution of PBVP1.13.

Proof ofTheorem 2.2. FollowingLemma 3.4, the proof is similar to that ofTheorem 2.1.

Proof ofTheorem 2.3. FollowingLemma 3.5, the proof is similar to that ofTheorem 2.1.

Proof ofTheorem 2.4. FollowingLemma 3.6, the proof is similar to that ofTheorem 2.1.

Acknowledgments

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