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UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 10.5 Prof. Steven Errede LECTURE NOTES 10.5

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LECTURE NOTES 10.5

EM Standing Waves in Resonant Cavities

 One can create a resonantcavity for EM waves by taking a waveguide (of arbitrary shape) and closing/capping off the two open ends of the waveguide.

StandingEM waves exist in (excited) resonant cavity (= linear superposition of two counter-propagating traveling EM waves of same frequency).

 Analogous to standing acoustical/sound waves in an acoustical enclosure.

 Rectangular resonant cavity – use Cartesian coordinates

 Cylindrical resonant cavity – use cylindrical coordinates to solve the EM wave eqn.  Spherical resonant cavity – use spherical coordinates

A.) Rectangular Resonant Cavity: (L W H   a b d) with perfectly conducting walls

(i.e. no dissipation/energy loss mechanisms present), with 0 x a, 0 y b, 0 z d.

n.b. Again, by convention: a > b > d.

Since we have rectangular symmetry, we use Cartesian coordinates - seek monochromatic

EM plane wave type solutions of the general form:

, , , , , , , , , , i t o i t o E x y z t E x y z e B x y z t B x y z e           

Maxwell’s Equations (inside the rectangular resonant cavity – away from the walls):

(1) Gauss’ Law: (2) No Monopoles:

 E0   Eo 0  B0   Bo 0

(3) Faraday’s Law: (4) Ampere’s Law:

E B t          Eoi Bo   B 12 E c t         Bo i 2 Eo c      

Take the curl of (3): = 0 {Gauss’ Law}

 

 

 

2 2 o o o o o E i B E E i B E c                              

 {using (4) Ampere’s Law}

 2 2 2 2 2 2 ox ox oy oy oz oz E E c E E c E E c                              

, , , , . . each is a fcn , , , , ox ox oy oy oz oz E E x y z E E x y z i e x y z E E x y z                      

Subject to the boundary conditions

|| 0

E  andB 0 at all inner surfaces.

(2)

For each component

x y z, ,

of Eo

x y z, ,

we try product solutions and then use the separation of variables technique:

, ,

     

i o i i i Ex y zX x Y y Z z for

2 2 , , i i o o E x y z E c            where subscript ix y z, , .

   

2 2

 

   

2 2

 

   

2 2

 

2

     

i i i i i i i i i i i i X x Y y Z z c Y y Z z X x Z z X x Y y X x Y y Z z x y z c             

Divide both sides by Xi

     

x Y y Z zi i : The wave equation becomes:

 

 

 

 

 

 

 

 

  2 2 2 2 2 2 2

only only only

1 i 1 i 1 i i i i fcn x fcn y fcn z X x Y y Z z X x x Y y y Z z z c                      

This equation must hold/be true for arbitrary (x, y, z) pts. interior to resonant cavity 0 0 0 x a y b z d                

This can only be true if:

 

 

2 2 2 1 constant i x i X x k X x x      

 

 

2 2 2 0 i x i X x k X x x    

 

 

2 2 2 1 constant i y i Y y k Y y y      

 

 

2 2 2 0 i y i Y y k Y y y    

 

 

2 2 2 1 constant i z i Z z k Z z z      

 

 

2 2 2 0 i z i Z z k Z z z     with: 2 2 2 2 2 x y z k k k k c             characteristic equation

General solution(s) are of the form:

ix y z, ,

:

, ,

cos

 

sin

 

cos

 

sin

 

cos

 

sin

 

i

o i x i x i y i y i z i z

Ex y zA k xB k x C k yD k yE k zF k z n.b. In general, , and k kx y kz should each have subscript ix y z, , , but we will shortly find out that

i

x

ksame for all , , ,

i

y

ix y z ksame for all ix y z, , , and

i

z

ksame for all ix y z, , . n.b. We seek

oscillatory

(not damped)

(3)

Boundary Conditions: E||0 @ boundaries and B 0 @ boundaries: 0, 0 at 0, ox y y b E z z d          coefficients 0 0 x x E C         and , 1, 2,3,.... , 1, 2,3,.... y z k n b n k d               0, 0 at 0, oy x x a E z z d          coefficients 0 0 y y A E         and , 1, 2,3,.... , 1, 2,3,.... x z k m b m k d             0, 0 at 0, oz x x a E y y b          coefficients 0 0 z z A C         and , 1, 2,3,.... , 1, 2,3,.... x y k m a m k n d n              

n.b. m = 0, and/or n = 0 and/or 0are not allowed, otherwise

, ,

0

i

o

Ex y z  (trivial solution).

Thus we have (absorbing constants/coefficients, & dropping x,y,z subscripts on coefficients):

 

 

 

 

 

 

 

 

 

 

 

 

, , cos sin sin sin

, , sin cos sin sin

, , sin sin cos sin

ox x x y z oy x y y z ox x y z z E x y z A k x B k x k y k z E x y z k x C k y D k y k z E x y z k x k y E k z F k z                  

But (1) Gauss’ Law:  E0  Eox Eoy Eoz 0

x y z         Thus:

 

 

 

 

 

 

 

 

 

 

 

 

sin cos sin sin

sin sin cos sin

sin sin sin cos 0

x x x y z y x y y z z x y z z k A k x B k x k y k z k k x C k y D k y k z k k x k y E k z F k z                      

This equation must be satisfied for any/all points inside rectangular cavity resonator.

In particular, it has to be satisfied at

x y z, ,

0,0,0

.

We see that for the locus of points associated with (x = 0,y,z) and (x,y = 0,z) and (x,y,z = 0), we must have BD  F 0 in the above equation.

Note also that for the locus of points associated with

xm 2 , ,kx y z

and

x y, n 2 ,ky z

and

x y z, ,  2kz

where , ,m n odd integers (1, 3, 5, 7, etc. …) we must have:

0

x y z

Ak Ck Ek  .

(4)

Thus:

 

 

 

 

 

 

 

 

 

1, 2,3, 4,

, , cos sin sin

, , sin cos sin 1, 2,3, 4,

, , sin sin cos

1, 2,3, 4, x ox x y z oy x y z y oz x y z z m k m a E x y z A k x k y k z n E x y z C k x k y k z k n b E x y z E k x k y k z k d                                       

With: Eo

x y z, ,

E xoxˆE yoyˆE zozˆ n.b.: m  n  0 simultaneously is not allowed!

Now use Faraday’s Law to determine B:

i B E       

 

 

 

 

 

 

sin cos cos sin cos cos

oy oz ox y x y z z x y z E E i i B Ek k x k y k z Ck k x k y k z y z                    

 

 

 

 

 

 

cos sin cos cos sin cos

ox oz oy z x y z x x y z E E i i B Ak k x k y k z Ek k x k y k z z x                  

 

 

 

 

 

 

oy ox cos cos sin cos cos sin

oz x x y z y x y z E E i i B Ck k x k y k z Ak k x k y k z x y                      or:

 

 

 

 

 

 

 

 

 

ˆ ˆ ˆ , , ˆ

sin cos cos

ˆ

cos sin cos

ˆ

cos cos sin

o ox oy oz y z x y z z x x y z x y x y z B x y z B x B y B z i Ek Ck k x k y k z x Ak Ek k x k y k z y Ck Ak k x k y k z y                  

This expression for Bo

x y z, ,

(already) automatically satisfies boundary condition (2) B 0: 0 ox B  at 0,xxa Boy 0at 0,yyb Boz 0at 0,zzd with kx m a         with y n k b         with kz d          m0,1, 2, n0,1, 2, 0,1, 2,

(5)

Does  Bo

x y z, ,

0 ???

 

 

 

, ,

cos cos cos

oy ox oz o x y z x y z x y B B B B x y z x y z i i k Ek Ck k x k y k z k k E                        

x z k k C  

 

 

 

ky AkzEkx cos k xx cos k yy cos k zzk k Ay z   k k Ex y

 

 

 

k CkzxAky cos k xx cos k yy cos k zzk k Cx z   k k Ay z

 

 

 

cos  k xx cos k yy cos k zz

B x y z

o

, ,

0

 

YES!!!

For TE Modes: 0

z

E   coefficient E 0. Then AkxCkyEkz 0 tells us that: AkxCky 0 or: x y k C A k           Thus:

, , ,

cos

 

sin

 

sin

 

i t

ox x y z Ex y z tAk x k y k z e kx m ,m 1, 2,3, a        

, , ,

x sin

 

cos

 

sin

 

i t

oy x y z y k E x y z t A k x k y k z e k             , 1, 2,3, y n k n b         Eoz

x y z t, , ,

0 kz , 1, 2,3, d          

(n = 0 is NOT allowed for TE modes!!!)

, , ,

x sin

 

cos

 

cos

 

i t

ox z x y z y k i B x y z t A k k x k y k z e k            

, , ,

cos

 

sin

 

cos

 

i t

oy z x y z i B x y z t k A k x k y k z e       

, , ,

x cos

 

cos

 

sin

 

i t

oz x y x y z y k i B x y z t A k k k x k y k z e k                 

The angular cutoff frequency for , , th

m n  mode for TE modes in a rectangular cavity is:

2 2 2 mn m n c a b d                 and: vg c v k      no dispersion. The lowest , , m n TE mode

a b d

is: TE111

(6)

For TM Modes: 0 z B  

CkxAky

0 or: y x k C A k           Thus:

, , ,

cos

 

sin

 

sin

 

i t

ox x y z Ex y z tAk x k y k z e kx m ,m 1, 2,3, a        

, , ,

y sin

 

cos

 

cos

 

i t

oy x y z x k E x y z t A k x k y k z e k          , 1, 2,3, y n k n b        

(m = 0 is NOT allowed for TM modes!!!) kz , 1, 2,3, d          

, , ,

x y y sin

 

sin

 

cos

 

i t

oz x y z z x z k k k E x y z t A k x k y k z e k k k                  

, , ,

y y y sin

 

cos

 

cos

 

i t

ox x y z x y z x z x k k k i B x y z t A k k A k k x k y k z e k k k                               

, , ,

y x cos

 

sin

 

cos

 

i t

oy z x y x y z x x k k i B x y z t Ak A k k k x k y k z e k k                           Boz

x y z t, , ,

0

For either TE or TM modes:

2 2 2 2 2 x y z k k k k c            with: , 1, 2, x m k m a         y , 1, 2, n k n b         kz , 1, 2, d          

The angular cutoff frequency for , , th

m n  mode is the same for TE/TM modes in a rectangular cavity:

2 2 2 mn m n c a b d                 and: vg c v k      no dispersion. The lowest , , m n TM mode

a b d

is: TM111

(7)

B.) The Spherical Resonant Cavity:

The general problem of EM modes in a spherical cavity is mathematically considerably more involved (e.g. than for the rectangular cavity) due to the vectorial nature of the E and B-fields.

For simplicity’s sake, it is conceptually easier to consider the scalar wave equation, with a

scalar field 

 

r t, satisfying the free-source wave equation

 

 

2 2 2 , 1 , r t 0 r t c t         

which can be Fourier-analyzed in the complex time-domain

 

r t, 

r,

ei td



 

with each Fourier component 

r,

satisfying the Helmholtz wave equation:

2 2

,

0 kr

    with: 2

2

k   c i.e. no dispersion.

In spherical coordinates, the Laplacian operator is:

2

2

2 2 2 2 2 2 , , 1 1 1 , , sin sin sin r r r r r r r r r                               

To solve this scalar wave equation – we again try a product solution of the form:

,

R r

     

i t r P Q e r       

  

, spherical harmonics , m m m f r Y  

   

Plug this 

r,

into the above scalar wave equation, use the separation of variables technique:

Get radial equation:

 

2 2 2 2 1 2 0 d d k f r dr r dr r               where: = 0, 1, 2, 3, . . . Let: f

 

r 1 u r

 

r

  . Then we obtain Bessel’s equation with index v  12 :

2

 

2 1 2 2 2 2 1 0 d d k u r dr r dr r             

Solutions of the (radial) Bessel’s equation are of the form:

 

1

 

1

 

2 2

1 1

2 2

Bessel fcn of 1st Bessel fcn of 2nd kind of order kind of order

m m m A B f r J kr N kr rr              

It is customary to define so-called spherical Bessel functions and spherical Hankel functions:

 

 

1 2 1 2 2 j x J x x          where: xkr

 

 

1 2 1 2 2 n x N x x          The Ym

 ,

satisfy the angular portion of scalar wave equation…

(8)

and:  

 

 

 

 

 

1 2 1 1 2 2 1,2 2 h x J x iN x j x i n x x                

 

 

1 d sin

 

x j x x x dx x           

 

 

1 d cos

 

x n x x x dx x            

 

 

0 sin x j x x   1

 

0 ix e h x ix

 

 

0 cos x n x x    2

 

0 ix e h x ix   

 

 

 

1 2 sin cos x x j x x x   1 1

 

1 ix e i h x x x      

 

 

 

1 2 cos x sin x n x x x    1 2

 

1 ix e i h x x x     For x1, :

 

1

2

... 2 1 !! 2 2 3 x x j x          where:

21 !!

 

 21 2



1 2



3 ... 5 3 1

  

 

2 11 !!

1

2

... 2 1 2 x n x x                  For x1, :

 

sin 1 2 j x x x        

 

1cos 2 n x x x         

The general solution to Helmholtz’s equation in spherical coordinates can be written as:

 

  1  1

 

 2  2

 

, , m m m , m r t A h kr A h kr Y           

      

Coefficients are determined by boundary conditions. For the case of EM waves in a spherical resonant cavity we will (here) only consider TM modes, which for spherical geometry means that the radial component of B B, 0r  . We further assume

(for simplicity’s sake) that the E and B-fields do not have any explicit -dependence.

n.b. If x = kr is real, then

 2

 

* 1 

 

(9)

Hence:

2 1 ! , cos 4 ! m im m m Y P e m               

Will have some restrictions imposed on it Associated Legendré Polynomial If Br 0 and B

explicit function of , then:  B0  B 0 {necessarily}

But: E B t         requires: E 0

 TM modes with no explicit -dependence involve onlyEr, E and B

Combining E B t         and B 12 E c t       

with harmonic time dependence i t

e of solutions, We obtain: 2 0 B B c              

The -component of this equation is:

 

 

2 2 2 2 1 1 sin 0 sin rB rB rB crr                    But:

 

2

~Legendré equation with 1

1 1

sin sin

sin sin sin

m rB rB rB                           

 Try product solutions of the form: B

 

r, u r

   

P1 cos r

     

Substituting this into the above equation gives a differential equation for u r

 

of the form of:

Bessel’s equation:

 

  

2 2 2 2 1 0 d u r u r dr c r                  

with = 0, 1, 2, 3, . . . defining the

angular dependence of the TM modes.

Let us consider a resonant spherical cavity as two concentric, perfectlyconducting spheres of

inner radius a and outer radius b. If

 

, u r

   

1 cos

B r P

r

      , the radial and tangential electric fields (using Ampere’s Law) are:

 

, 2

sin

2

1

   

cos

sin r u r ic ic E r B P rr r                 

 

, ic2

 

ic2 u r

   

1 cos E r rB P r r r r             

(10)

But EE which must vanish at r = a and r = b

 

r a

 

r b 0 u r u r rr         

The solutions of the radial Bessel equation are spherical Bessel functions (or spherical Hankel functions).

The above radial boundary conditions on

 

r a 0 r b u r r      lead to

transcendental equations for

the characteristic frequencies,  {eeeEEK}!!!

However {don’t panic!}, if: (ba) = h is such that ha then:

2 1

2 1

constant!!!

r a

 

 

   

And thus in this situation, the solutions of Bessel’s equation:

 

2

 

2 2 2 1 0 d u r u r dr c a                     

 

 

2 2 2 0 d u r k u r dr     where:

2 2 2 1 k c a           

are simply sin (kr) and cos (kr) !!! i.e. u r

 

Acos

 

krBsin

 

kr

Then: sin

 

cos

 

0

r a u kA ka kB ka r       

and sin

 

cos

 

0

r b u kA kb kB kb r        

For

b a

ha an approximate solution is: u r

 

Acos

krka

with: khk b a

n , n = 0, 1, 2, . . . Thus:

2 2 2 2 1 n n k c a h                   , n = 0, 1, 2, 3, . . . and = 0, 1, 2, 3, . . . The corresponding angular cutoff frequency is:

2

2 2 2 1 1 n n n c k c a h a                 for ha, n = 0, 1, 2, 3, . . . and = 0, 1, 2, 3, . . .

Because ha, we see that the modes with n = 1, 2, 3, . . . turn out to have relatively high frequencies n n c h       

 for n1. However, the n = 0 modes have relatively low frequencies:

0 2 1 1 c c a a           for ha.

An exact solution (correct to first order in (h/a) expansion) for n = 0 is:

 

0 1 2 1 c a h       

These eigen-mode frequencies are known as Schumann resonance frequencies. = 1, 2, 3, . . .

(11)

For n = 0, the EM fields are: E0 0, Er0 12 P

cos

r     and 0 1 1

cos

B P r    

Very Useful Table:

ˆ ˆ ˆ r   ˆ  rˆ ˆ ˆ ˆ ˆr     ˆ  ˆ rˆ ˆ ˆ ˆr   rˆ  ˆ ˆ Poynting’s vector:

 

1

 

1

 

0 0 0 3 3 0 1 ˆ ˆ 1 1 ˆ

cos cos cos cos

S E B r P P P P r r                        

The Earth’s surface and the Earth’s ionosphere behave as a spherical resonant cavity (!!!) with the Earth’s surface {approximately} as the inner spherical surface: arr 6378 km

6 6.378 10 m

  (= Earth’s mean equatorial radius), the height h (above the surface of the Earth) of the ionosphere is: 100 105

hkmm(a) → b = a + h 6.478 x 106m. For the n = 0 Schumann resonances:

 

0 1 2 1 c a h        for ha. 1:  

01 1 2 2 c a h     01 01 10.5 2 fHz    2 :  

02 1 2 6 c a h     02 02 18.3 2 fHz    3:  

03 1 2 12 c a h     03 03 25.7 2 fHz    4 :  

04 1 2 20 c a h     04 04 33.2 2 fHz    5 :  

05 1 2 30 c a h     05 05 46.7 2 fHz    (. . . etc.)

The n = 0 Schumann resonances in the Earth-ionosphere cavity manifest themselves as peaks in the noise power spectrum in the VLF (Very Low Frequency) portion of the EM spectrum → VLF EM standing waves in the spherical cavity of the Earth-ionosphere system!!!

ˆ y ˆ z ˆ x  ˆ  0 ˆ,B ˆ   0 ˆ, r ˆ r E r  0 S  a b Circumpolar N-S waves! n.b. For the n = 1 Schumann resonances: 1 1.5 f  KHz

(12)

Schumann resonances in the Earth-ionosphere cavity are excited by the radial E-field component of lightning discharges (the frequency component of EM waves produced by lightning at these Schumann resonance frequencies).

Lightning discharges (anywhere on Earth) contain a wide spectrum of frequencies of EM radiation – the frequency components f01, f02, f03, f04, . . excite these resonant modes – the Earth literally “rings like a bell” at these frequencies!!! The n = 0 Schumann resonances are the lowest-lying normal modes of the Earth-ionosphere cavity.

Schumann resonances were first definitively observed in 1960. (M. Balser and C.A. Wagner, Nature 188, 638 (1960)).

 Nikola Tesla may have observed them before 1900!!! (Before the ionosphere was known to

even exist!!!) He also estimated the lowest modal frequency to be f01 ~ 6 Hz!!!

(13)

The observed Schumann resonance frequencies are systematically lower than predicted, (primarily) due to damping effects: 2 02 1 1 i

Q

     

  where Q = Quality factor

0

 = “Q

of resonance, and  = width at half maximum of power spectrum: The Earth’s surface is also not perfectly conducting.

Seawater conductivity C 0.1 Siemens!!

Neither is the ionosphere! → Ionosphere’s conductivity 10 4 10 7

C

Siemens

 On July 9, 1962, a nuclear explosion (EMP) detonated at high altitude (400 km) over

Johnson Island in the Pacific {Test Shot: Starfish Prime, Operation Dominic I}.

- Measurably affected the Earth’s ionosphere and radiation belts on a world-wide scale!

- Sudden decrease of ~ 3 – 5% in Schumann frequencies – increase in height of ionosphere!

- Change in height of ionosphere:   h hh2 0.03 0.05

R 400 600  km !!!

- Height changes decayed away after ~ several hours. - Artificial radiation belts lasted several years!

 Note that # of lightning strikes, (e.g. in tropics) is strongly correlated to average temperature.

Scientists have used Schumann resonances & monthly mean magnetic field strengths to monitor lightning rates and thus monitor monthly temperatures – they all correlate very well!!!

 Monitoring Schumann Resonances → Global Thermometer → useful for Global Warming studies!!

Earth Coordinate System:

 

0 1 2 1 2 c f a h        0 0 E  (north – south)

0 2 1 cos r E P r     (up – down)

0 1 1 cos B P r    (east – west)

 

1

 

0 3 1 ˆ cos cos S P P r         (north – south)

For the n = 0 modes of Schumann Resonances:

ˆ

(14)

We can observe Schumann resonances right here in town / @ UIUC!! Use e.g. Gibson P-90 single-coil electric guitar pickup

LP90 10 Henrys, ~10K turns #42AWG copper wire

for

detector of Schumann waves and a spectrum analyzer (e.g. HP 3562A Dynamic Signal Analyzer) – read out the HP 3562A into PC via GPIB.

 Orientation/alignment of Gibson P-90 electric guitar pickup is important – want axis of

pickup aligned  B ˆ (i.e. oriented eastwest) as shown in figure below. n.b. only this

orientation yielded Schumann-type resonance signals {also tried 2 other 90o orientations {up-down} and {north-south} but observed no signal(s) for Schumann resonances for these.}

Electric guitar PU’s are very sensitive – e.g. they can easily detect car / bus traffic on street below from 6105 ESB (6th Floor Lab) – can easily see car/bus signal from PU on a ‘scope!!!

(15)

References

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