REVISION RECORD:
Revision
No.
Reason for revision
Date
0
Issued for Construction
19.12.2012
C
Re-Issued for Approval incorporating Client comments
09.12.2012
B
Issued for Approval incorporating Client comments
06.11.2012
A
Issued for Client Review
16.10.2012
TABLE OF CONTENTS
1.
INTRODUCTION ...
5
1.1.
Background ...
5
1.2.
Project Description ...
5
2.
DEFINITIONS ...
5
3.
SCOPE ...
6
4.
REFERENCE CODES, STANDARDS AND SPECIFICATIONS ...
6
4.1.
General ...
6
4.2.
International Codes and Standards ...
6
4.3.
Project Documents ...
6
5.
PIPELINE DESIGN DATA ...
7
6.
DESCRIPTION / METHODOLOGY - WALL THICKNESS CALCULATION...
8
6.1.
General ...
8
6.2.
Pipe Thickness Check for Stress Value ...
9
6.3.
Minimum Elastic Bending Radius ...
11
6.4.
Bend Thinning Requirements ...
11
7.
DESCRIPTION / METHODOLOGY - UPHEAVAL BUCKLING CALCULATION
12
7.1.
General ...
12
7.2.
Methodology ...
12
7.3.
Calculation for Axial Force (P) ...
12
7.4.
Imperfection Length ...
13
8.
DESCRIPTION / METHODOLOGY – ROAD CROSSING CALCULATION ...
14
8.1.
General ...
14
8.2.
Methodology ...
14
9.
CALCULATION RESULT / SUMMARY ...
17
9.1.
Result for Wall Thickness Calculation ...
17
9.2.
Result for Upheaval Buckling Calculation ...
21
9.3.
Result for Crossing Calculation ...
22
9.4.
Result for Anchor Load, Active length, free end expansion and Buoyancy
23
Corroded Condition...
24
ATTACHMENT-1A & 1B: WALL THICKNESS CALCULATIONS (CORRODED & NEW CONDITION)
...
26
ATTACHMENT-2: UPHEAVAL BUCKLING CALCULATION ...
27
ATTACHMENT-4: PIPELINE BUOYANCY CALCULATION ...
29
ATTACHMENT-5: ANCHOR LOAD, ACTIVE LENGTH & FREE EXPANSION CALCULATION 30
1. INTRODUCTION
1.1. Background
Abu Dhabi Gas Industries Limited (GASCO) intends to supply sales gas to Emirates Aluminium
(EMAL) for their second expansion requirements, to MASDAR for their new Carbon Capture &
Storage Project Requirements and other new consumers identified by ADNOC as part of their
next five year gas supply plan in Taweelah Area.
DODSAL ENGINEERING & CONSTRUCTION PTE LIMITED is EPC Contractor for the project of
Habshan – Maqta -Taweelah Gas Pipelines Project abbreviated to HMT Gas Pipelines Project.
The Owner Company for this project is Abu Dhabi Gas Industries Ltd. (GASCO).
1.2. Project Description
Two (2) Nos. new 52” pipelines from Habshan to Maqta premises (approx. 125 km.each) with
Scraper Launcher, Scraper Receiver and intermediate Block Valve Stations.
One (1) No. new 52” pipeline from Maqta to Taweelah KM42 point (approx. 42 km.) with
Scraper Launcher, Scraper Receiver and intermediate Block Valve Stations.
One (1) No. new 42” pipeline from Taweelah KM42 point to ADWEC CRS (approx. 11 km.)
with Scraper Launcher and Receiver Stations. Scraper receiver station at ADWEC CRS shall
include ROV, FCV, Filters, Metering skid and PRS for custody transfer to Khalifa Port
(KIZAD). Scraper Receiver station shall also include plot area provision for future filters,
Custody Transfer/Metering and PRS for ADWEC (Taweelah) and MASDAR (with ADWEC).
Supervisory and Monitoring Systems for the new pipelines and upgrading of the existing SMC
system to include new facilities.
Associated Civil, Electrical, Instrumentation, Telecom and Cathodic Protection works
Demolition of existing 30” pipeline from Bab to Maqta manifold.
Demolition of existing 24” pipeline from Maqta to Taweelah Consumer Receipt Station.
2. DEFINITIONS
In this document following words and expressions shall have the meanings hereby assigned to
them except where the content otherwise requires:
COMPANY
: Abu Dhabi Gas Industries Ltd. (GASCO)
CONTRACTOR
: Dodsal Engineering & Construction Pte. Ltd.
3. SCOPE
This document covers the Calculations for Pipeline Wall Thickness, Upheaval buckling,
Buoyancy, Crossing, Anchor load, Active length and Free expansion for
“Habshan-Maqta-Taweelah (HMT) Gas Pipelines Project”. The thickness will be verified as per ASME B31.8 for gas
pipelines.
4. REFERENCE CODES, STANDARDS AND SPECIFICATIONS
4.1. General
These pipeline calculations were performed in conformance with the current issue, amendments
and Project Addendum of the following codes, standards and specifications prevailing on the
effective date of the contract.
4.2. International Codes and Standards
The following codes and standards form the basis for the pipelines calculations.
ASME B 31.8 Ed 2010
Gas Transmissions and Distribution Piping Systems
PD 8010-1:2004
Code of Practice for Pipelines Part 1 - Steel Pipelines on Land
API 5L 44
thEdition
Specification for Line Pipe
API RP 1102 7
thEdition
Steel Pipeline Crossing Rail, Roads and Highways
4.3. Project Documents
5272-PP-GEN-00-001
Process Design Basis.
5272-RT-GEN-95-001
Pipeline Design Basis
5272-ADD-9550-004
Addendum to DGS Flexibility analysis (Pipeline)
5272-ADD-9550-003
Addendum to DGS for Pipeline Hydrostatic Testing
5272-ADD-9550-002
Addendum to DGS Pipeline Construction
5. PIPELINE DESIGN DATA
Parameters
Thammama C - Maqta
Maqta – KM 42
KM 42 –
Taweelah
SV2 to
Yas
island
tie-in
Pipeline diameter. NB
52
52
42
16
Outside Diameter mm
1320.8
1320.8
1066.8
406.4
Design Code, ASME
B31.8
B31.8
B31.8
B31.8
Design Pressure, bar
(g)
63.5
63.5
63.5
63.5
Corrosion Allowance,
mm
1.5
1.5
1.5
1.5
Maximum Design
Temp. Above Ground
(ºC)
100
100
100
100
Maximum Design
Temp. Below Ground
(ºC)
65
65
65
65
Warmest or Coldest
Operating Temp. (ºC)
65
65
65
65
Minimum Design
Temp. of pipeline
system (ºC)
0 (Note 1)
0 (Note 1)
0 (Note 1) 0 (Note1)
Max. Temp. at 1m
depth of soil (ºC)
38
38
38
38
Minimum Tie-in Temp.,
underground section
(ºC)
13
13
13
13
Minimum Tie-in Temp.,
aboveground section
(ºC)
5
5
5
5
Flange Rating, ASME
Class
600
600
600
600
Min burial depth to top
of pipe (normal terrain),
m
1
1
1
1
Material Grade, API 5L
X 65MS, PSL 2
X 65MS, PSL 2
X 65MS,
PSL 2
X 65MS,
PSL 2
Material SMYS, MPa
450
450
450
450
Design Factor, F
CLASS 1
CLASS
3
CLASS
Parameters
Thammama C - Maqta
Maqta – KM 42
KM 42 –
Taweelah
SV2 to
Yas
island
tie-in
Mainline
0.72
0.5
0.4
0.5
0.4
0.5
0.5
Track/Asphalt
Road/Rig Crossings
0.5
0.5
0.4
0.5
0.4
0.5
0.5
Stations (SVs &
Launcher/receivers)
0.5
0.5
0.4
0.5
0.4
0.5
0.5
Co-efficient of Thermal
Expansion, mm/deg C
11.7 x 10
-611.7 x 10
-611.7 x 10
-611.7 x 10
-6Elastic Modulus E, Mpa
207.0 x 10³
207.0 x 10³
207.0 x
10³
207.0 x
10³
Internal coating
thickness
60 – 100 microns
60 – 100 microns
60 – 100
microns
Not
applicable
External Coating
3 Layer Polyethylene
3 Layer Polyethylene
3 Layer
Polyethylen
e
3 Layer
Polyethylen
e
Minimum External
Coating Thickness, mm
(FBE+Adhesive+PE)
3.55
3.55
3.55
3.05
Note 1: Min. Design temperature is confirmed as per depressurization study.
6. DESCRIPTION / METHODOLOGY - WALL THICKNESS CALCULATION
6.1. General
Pipelines wall thickness is calculated based on the internal design pressure and in accordance
with the Design codes for gas pipelines as described below. Calculations are done for location
class 1, 3 and 4 of gas pipeline with design factors of 0.72, 0.5 and 0.4 respectively.
The wall thickness for the CS pipe shall be initially calculated by following expression.
As per ASME B31.8 clause 841.1.1, the formula for the wall thickness calculation of gas pipeline
is:
t
min= [P
DD / (2FSET)] + A
where,
S
= Specified Minimum Yield Strength (SMYS)
t
min= Calculated Minimum Wall thickness
D
= Outside diameter of pipe
F
= Design factor (Ref Table 841.1.6-1 of ASME B31.8)
E
= Longitudinal joint factor (Ref Table 841.1.7-1 of ASME B31.8)
T
= Temperature derating factor (Ref Table 841.1.8-1 of ASME B31.8)
A
= Corrosion Allowance
The Thickness calculated from above is then checked for acceptability of the ratio of diameter to
thickness for final thickness selection and it should not exceed 96.
6.2. Pipe Thickness Check for Stress Value
The stresses are calculated for the pipe wall thickness as per equations given below:
a) Hoop Stress
Hoop stress, S
H= P
DD / 2t
(Clause 805.2.3 of ASME B31.8)
b) Longitudinal Stress
Longitudinal stress due to pressure:
For restrained pipe:
S
P= 0.3 S
H(Clause 833.2 (a) of ASME B31.8)
For unrestrained pipe:
S
P= 0.5 S
H(Clause 833.2 (b) of ASME B31.8)
Longitudinal stress due to thermal expansion in restrained pipe (thermal stress):
S
T= E
(T
1– T
2) (Clause 833.2 (c) of ASME B31.8)
Longitudinal stress due to bending:
S
B= M / Z (Clause 833.2 (d) of ASME B31.8)
Longitudinal stress due to axial loading other than thermal expansion and pressure:
S
X= R / A (Clause 833.2 (f) of ASME B31.8)
For restrained pipe:
S
L= S
P+ S
T+ S
B+ S
X(Clause 833.3 (a) of ASME B31.8)
For unrestrained pipe: S
L= S
P+ S
B+ S
X(Clause 833.6 (a) of ASME B31.8)
Where:
E
=
Modulus of elasticity at ambient temperature
=
Thermal expansion coefficient
T
1=
pipe temperature at the time of installation, tie-in or burial
T
2=
Warmest operating temperature
M =
Bending moment across the pipe cross-section
Z =
Pipe section modulus
R =
External force axial component
A =
Pipe metal cross-sectional area
c) Combined / Equivalent Stress
The combined/equivalent stress of the restrained pipe is evaluated using the calculation in
either (1) or (2) below (Ref clause 833.4(a) of ASME B31.8):
(1) S
E1= S
H– S
L(2) S
E2= [S
H2+ S
L2- S
HS
L] ½
d) Criteria
The calculated stress needs to fulfill the criteria given below:
The net longitudinal stress, S
L:
For restrained pipe (Ref clause 833.3(b) of ASME B31.8):
S
L≤ 0.9 SMYS x T
For unrestrained pipe (Ref clause 833.6(b) of ASME B31.8): S
L≤ 0.75 SMYS x T
The combined / equivalent stress for restrained pipe (Ref clause 833.4 of ASME B31.8),
S
E1and S
E2≤ k x SMYS x T, where k ≤ 0.9 for load of long durations
6.3. Minimum Elastic Bending Radius
The route and profile of any fully restrained section of pipelines should be controlled to ensure
that the elastic bend limit or minimum allowable elastic bending radius is not exceeded.
The minimum elastic bending radius is determined as explained below.
1. The net longitudinal stress S
Lin section 6.2(b) shall be calculated in terms of S
B2. By substituting the calculated S
Lin terms of S
Binto combined / equivalent stress equation
6.2 (c), S
Eis derived in terms of S
B.
3. Based on criteria mentioned in section 6.2 (d), combined / equivalent stress shall be less
than 90% of SMYS for k = 0.9 and T = 1. Hence, maximum allowable margin for bending
stress can be derived by substituting the values of combined / equivalent stress S
Ein terms
of S
Binto the criteria.
By adjusting the Minimum Elastic Bending Radius (R) in below equation, we can ensure that
Bending Stress is within the allowable margin to meet the above criteria.
R = ED / 2S
BFor pipelines assuming a natural curvature that incurs a permanent elastic bending stress, the
minimum bending radius as per the calculation specified in Attachment-1 for respective wall
thickness shall be followed.
6.4. Bend Thinning Requirements
Wall thickness check, also takes into account the bend thinning requirements in accordance
with Clause 6.2.2.3 of PD 8010-1:2004. This is in the case of subjecting the pipe to field
bending or cold bending having a minimum bend radius of 40D and Factory hot bends with a
bend radius of 5D.
The wall thinning as a percentage is given by following empirical formula.
Wall thinning % = 50 / (n +1)
Where n = inner bend radius divided by pipe diameter.
By equating the calculated pipe thickness and bend thickness after bending, the calculated
thickness for design pressure = (1- thinning %) x pipe thickness before bend.
Pipe thickness before bending = (Calculated thickness for design pressure) / (1 – Thinning %)
The bend wall thinning allowance considered for the project shall be verified / confirmed by Hot
Bends Supplier.
7. DESCRIPTION / METHODOLOGY - UPHEAVAL BUCKLING CALCULATION
7.1. General
The simplified method presented in OTC Paper 6335 by A.C. Palmer, C. P. Ellinas, D.M.
Richards and J. Guijt (presented at 22nd Annual OTC in Houston, Texas, May 7-10, 1990) is
used to check that the selected depth of cover for pipeline is adequate to prevent upheaval
buckling.
The calculation is done for both new and corroded condition of pipes.
7.2. Methodology
The required downward force to prevent upheaval buckling of pipe is a function of pipe flexural
rigidity (EI) and the axial compressive force due to pressure and temperature load. The equation
12 of OTC paper 6335 gives the required download for stability in the operating condition:
W = [1.16 – 4.76 (EI W
o/ δ)
0.5/ P
P (δW
o/ EI)
0.5…………. (1)
Where,
W
=
Required download force to prevent upheaval buckling
E
=
Young’s modulus of steel
I
=
Section modulus for pipe
δ
=
Allowable Imperfection height
P
=
Effective axial force in operation
W
o=
Weight of pipe + Weight of content + Weight of corrosion coating
per unit length
The vertical download force that resists uplift of pipeline is related to the profile imperfection and
therefore a term imperfection height is appearing in the above formula. The soil resistance also
changes with increase in imperfection height. Upheaval buckling check has been carried out for
various imperfection heights from 0.1 to 0.5m.
7.3. Calculation for Axial Force (P)
The axial force on buried pipeline section will include following forces:
a) Axial tensile stress due to hoop stress = ٧Sh
Where,
٧
=
Poissons ratio i.e. 0.3 for steel pipe
b) Axial Compressive stress due to internal pressure = 0.3 x Sh
c) Axial Compressive force due to temperature change = Eα(T2-T1)
Where,
E
=
Modulus of elasticity
α
=
Thermal expansion coefficient
T
2=
Design temperature for underground section
T
1=
Installation temperature
The Axial Force,
P = P
D*Ai + A*{E α (T2-T1) - ٧Sh } …………. (2)
Where,
Ai
=
Area corresponding to internal cross-section of Pipe
A
=
Cross-Section area of Pipe
P
D=
Design pressure
Axial force calculated above is considering fully restrained condition of pipeline (more
conservative scenario)
The soil above the buried pipeline will provide an uplift resistance, (as per OTC paper Eq 13),
Q = H*D* Ƴ*[1+f *H / D] …………. (3)
Where,
Q
=
Uplift Soil resistance per unit length
H
=
pipe cover
D
=
Pipe outside diameter
Ƴ
=
Soil density
f
=
Uplift
coefficient
(0.1
for
loose
material
&
0.5 for dense material)
To prevent the upheaval buckling of pipeline, |W| < |Wo + Q|
7.4. Imperfection Length
Maximum downward force per unit length required to stabilize the pipeline at the crest of the
profile imperfection (as per OTC paper Eq 4 )
where, L
imp= Imperfection Length
L
impshall be calculated by solving the quadratic equation as follows
(π / L
imp)
4– [P / 4*E*I] (π / L
imp)
2+ [ W / 8δEI ] = 0
8. DESCRIPTION / METHODOLOGY – ROAD CROSSING CALCULATION
8.1. General
The purpose of this calculation is to ensure satisfactory and optimal design in compliance with
criteria (circumference stress due to internal pressure as per Barlow formula, effective stress
and fatigue) defined in API RP 1102, and to determine whether wall thicknesses heavier than
the selected wall thickness would be required at road crossing.
The following wheel loadings were taken into account in determining the stresses imposed on
pipeline.
Asphalt Road/ Highway /Track crossings: 112kN per wheel at 900mm centers with
maximum of four (4) wheels per axle. Contact area per API RP 1102 is 0.093 square
meters, giving surface pressure = 1204 kN/m
2.
Rig crossings: 2200 kN on a single axle (2 wheel set) and the maximum single axle wheel
load is 1100kN. The contact area, over which the wheel load is applied, shall be taken as
0.403 square meters.
8.2. Methodology
The methodology for track/asphalt road/rig crossing calculations (as mentioned in API 1102) is
described briefly in the following steps:
a. Begin with the wall thickness (calculated with design factor 0.5 for Class 1 and 3 and design
factor 0.4 for Class 4) for pipeline of given diameter approaching the crossing. Determine
the pipe, soil, construction, and operational characteristics.
b. Use the Barlow formula to calculate the circumferential stress due to internal pressure, S
hi(Barlow). Check S
hiagainst the maximum allowable value.
c. Calculate the circumferential stress due to earth load, S
He.
d. Check the critical axle configuration as per figure A-1 Annex. A of API 1102.
e. Calculate the external live load, w, and determine the appropriate impact factor, Fi.
f.
Calculate the cyclic circumferential stress, ΔS
H, and the cyclic longitudinal stress, ΔS
L, due
to live load.
g. Calculate the circumferential stress due to internal pressure, S
Hih. Check effective stress, S
eff, as follows:
1. Calculate the principal stresses, S
1in the circumferential direction, S
2in longitudinal
direction, and S
3in the radial direction.
2. Calculate the effective stress, S
eff.
3. Check by comparing S
effagainst the allowable stress, SMYS x F.
i.
Check weld for fatigue as follows:
1. Check with weld fatigue by comparing ΔS
Lagainst the girth weld fatigue limit, S
FGx F.
2.
Check longitudinal weld fatigue by comparing, ΔS
Hagainst the longitudinal weld fatigue
limit, S
FLx F.
where,
Circumferential stress due to internal pressure,
S
hi(Barlow) = P
DD ⁄ 2t
w(refer section 4.8.1.1 of API 1102)
Circumferential stress due to earth load,
S
He= K
HeB
eE
eγ D
(refer section 4.7.2.1 of API 1102)
K
Heis the stiffness factor for circumferential stress from earth load.
B
eis the burial factor for earth load.
E
eis the excavation factor for earth load.
γ is the soil unit weight.
Surface pressure due to Live load,
w = P ⁄ A
P(refer section 4.7.2.2 of API 1102)
P may be Design single wheel load P
Sor Design tandem wheel load P
TA
Pis the contact area over which the wheel load is applied
ΔS
Hh= K
HhG
HhRLF
iw
(refer section 4.7.2.2.4.1 of API 1102)
K
Hhis the highway stiffness factor for cyclic circumferential stress.
G
Hhis the highway geometry factor for cyclic circumferential stress.
R is the highway Pavement type factor.
L is the highway axle configuration factor.
Fi is the impact factor.
w is the applied design surface pressure.
Cyclic longitudinal stress due to highway vehicular load,
ΔS
Lh= K
LhG
LhRLF
iw
(refer section 4.7.2.2.4.2 of API 1102)
K
Lhis the highway stiffness factor for cyclic longitudinal stress.
G
Lhis the highway geometry factor for cyclic longitudinal stress.
R is the highway pavement type factor.
L is the highway axle configuration factor.
F
iis the impact factor.
w is the applied design surface pressure.
Circumferential stress due to internal pressure,
S
Hi= P
D(D– t
w) ⁄ 2t
w(refer section 4.7.3 of API 1102)
Maximum circumferential stress,
S
1= S
He+ ΔS
H+ S
Hi(refer section 4.8.1.2 of API 1102)
Maximum longitudinal stress,
S
2= ΔS
L– E
sα
T(T
2– T
1) + ν
s(S
He+ S
Hi)
(refer section 4.8.1.2 of API 1102)
Maximum radial stress,
S
3= –p = –P
D(Design Pressure)
(refer section 4.8.1.2 of API 1102)
Total effective stress,
9. CALCULATION RESULT / SUMMARY
For calculation details, refer to Attachments - 1, 2, 3, 4 and 5.
Based on the calculation results, the selected wall thicknesses for pipelines as listed below are
found adequate for the anticipated design pressures and temperatures, combined / equivalent
stresses, upheaval buckling and withstand the expected traffic / wheel loadings at Track,
Asphalt Road/ Highway and Rig crossing at the specified depth.
9.1. Result for Wall Thickness Calculation
Wall thickness of Pipeline
52” Sales Gas
Pipeline, API 5L X65
42” Sales Gas
Pipeline, API 5L X65
16” Sales Gas
Pipeline, API 5L X65
Location
Class
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
4
24.8
25.2
NA
NA
NA
NA
3
20.1
20.5
16.5
16.9
7.2
14.7
1
14.4
14.7
NA
NA
NA
NA
Wall thickness check for 40D field/cold bends
52” Sales Gas
Pipeline, API 5L X65
42” Sales Gas
Pipeline, API 5L X65
16” Sales Gas
Pipeline, API 5L X65
Location
Class
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
4
25.1
25.2
NA
NA
NA
NA
3
20.4
20.5
16.8
16.9
7.3
14.7
1
14.6
14.7
NA
NA
NA
NA
Wall thickness of Mother pipes for 5D Factory Hot bends
52” Sales Gas
Pipeline, API 5L X65
42” Sales Gas
Pipeline, API 5L X65
16” Sales Gas
Pipeline, API 5L X65
Location
Class
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
Calculated
WT (mm)
Selected
WT (mm)
4
27.3
28.0
NA
NA
NA
NA
3
22.1
25.2
18.2
18.8
8.0
14.7
1
15.9
20.5
NA
NA
NA
NA
Check for D/t ratio
Description
Class - 4 Class -3 Class -1 Class-3 Class-3
Pipeline Diameter , inch
52
52
52
42
16
Pipeline Outer Diameter D, mm
1320.8
1320.8
1320.8
1066.8
406.4
Selected Wall Thickness t, mm
25.2
20.5
14.7
16.9
14.7
D/t Ratio
52
64
90
63
28
Result for Stresses and minimum elastic bending radius (Non-Corroded condition)
52” (Location
Class 4)
52”
(Location
Class 3)
52”
(Location
Class 1)
42”
(Location
Class 3)
16”
(Location
Class 3)
Selected Wall
Thickness (mm)
25.2
20.5
14.7
16.9
14.7
Combined /
Equivalent
Stress of
unrestrained
section in MPa
(% of SMYS)
144.1(32.02%)
177.2
(39.37%)
247.1
(54.91%)
173.6
(38.57%)
76
(16.89%)
Combined /
Equivalent
Stress of
Restrained
section in MPa
(% of SMYS)
238.6
(53.02%)
265.3
(58.95%)
321.8
(71.51%)
262.4
(58.31%)
183.6
(40.8%)
Margin for
Bending Stress
in MPa (% of
SMYS)
166.6
(37.02%)
139.9
(31.08%)
83.4
(18.53)
142.8
(31.73)
221.6
(49.24)
Min. Elastic Bend
Result for Stresses and Minimum Elastic Bend Radius (Corroded Condition)
52” (Location
Class 4)
52”
(Location
Class 3)
52”
(Location
Class 1)
42”
(Location
Class 3)
16”
(Location
Class 3)
Selected Wall
Thickness (mm)
25.2
20.5
14.7
16.9
14.7
Corroded wall
thickness (mm)
23.7
19.0
13.2
15.4
13.2
Combined /
Equivalent
Stress of
unrestrained
section in MPa
(% of SMYS)
153.2
(34.04%)
191.1
(42.46%)
275.1
(61.13%)
190.5
(42.33%)
84.7
(18.82%)
Combined /
Equivalent
Stress of
Restrained
section in MPa
(% of SMYS)
246 (54.66%)
276.6
(61.46%)
344.5
(76.55%)
276.1
(61.35%)
190.5
(42.33%)
Margin for
Bending Stress
in MPa (% of
SMYS)
159.2(35.37%)
128.6
(28.57%)
60.7
(13.48%)
129.1
(28.68%)
214.7
(47.71%)
Min. Elastic Bend
Radius (m)
832
1031
2184
829
190
Minimum elastic bending radius to be considered for Construction shall be as per the value
calculated in corroded condition.
9.2. Result for Upheaval Buckling Calculation
Calculation for Non-Corroded & Corroded Conditions
Result
Size
Location
Class
Wall Thickness
(mm)
Depth of Cover
(m)
52” SALES GAS
PIPELINE, API 5L X65
4
25.2
1.5
OK
3
20.5
1.0
OK
1
14.7
1.0
OK
42” SALES GAS
PIPELINE, API 5L X65
3
16.9
1.0
OK
16” SALES GAS
PIPELINE, API 5L X65
3
14.7
1.0
OK
9.3. Result for Crossing Calculation
Crossing
52” SALES GAS
PIPELINE, API 5L
X65
42” SALES GAS
PIPELINE, API 5L
X65
16” SALES GAS
PIPELINE, API 5L X65
Wall Thick.
(mm)
Burial
Depth
(m)
Wall
Thick.
(mm)
Burial
Depth
(m)
Wall
Thick.
(mm)
Burial
Depth (m)
Location Class = 4
Track Crossing
25.2
2
NA
NA
NA
NA
Asphalt Road
Crossing/
Highway
Crossing
25.2
(Note-1)
2
NA
NA
NA
NA
Rig Crossing
25.2
2
NA
NA
NA
NA
Location Class = 3
Track Crossing
20.5
1.5
16.9
1.5
14.7
1.5
Asphalt Road
Crossing/
Highway
Crossing
20.5
(Note-1)
2
16.9
(Note-1)
2
NA
NA
Rig Crossing
20.5
2
16.9
2
NA
NA
Location Class = 1
Track Crossing
20.5
1.5
N/A
N/A
NA
NA
Asphalt Road
Crossing/
Highway
Crossing
20.5
(Note-1)
2
N/A
N/A
NA
NA
Rig Crossing
20.5
2
N/A
N/A
NA
NA
Result
OK
OK
OK
9.4. Result for Anchor Load, Active length, free end expansion and Buoyancy
Non Corroded Condition
52”
(Location
Class 4)
52”
(Location
Class 3)
52”
(Location
Class 1)
42”
(Location
Class 3)
16”
(Location
Class 3)
Selected Wall
Thickness (mm)
25.2
20.5
14.7
16.9
14.7
Free End
Expansion
(Non-compacted) (mm)
495
(Note-1)
440
(Note-1)
N/A
366
(Note-1)
259
(Note-1)
Free End
Expansion
(Compacted) (mm)
445
(Note-1)
395
(Note-1)
N/A
328
(Note-1)
232
(Note-1)
Anchor Load in
Tonne
1616
(Note 3)
1384
(Note 3)
N/A
916
(Note 3)
256
(Note 3)
Active Length
(Non-compacted)
(m)
753.86
659.5
N/A
549.8
407.78
Active Length
(Compacted) (m)
678.59
592.41
N/A
493
365.23
Factor of Safety
against floatation
0.573
(Note-2)
0.468
(Note-2)
0.337
(Note-2)
0.477
(Note-2)
1.068
(Note-2)
Corroded Condition
52”
(Location
Class 4)
52”
(Location
Class 3)
52”
(Location
Class 1)
42”
(Location
Class 3)
16”
(Location
Class 3)
Selected Wall
Thickness (mm)
25.2
20.5
14.7
16.9
14.7
Corroded wall
thickness (mm)
23.7
19
13.2
15.4
13.2
Free End
Expansion
(Compacted)
(mm)
429
(Note-1)
379
(Note-1)
N/A
311
(Note-1)
214
(Note-1)
Anchor Load
(tonne)
1542
(Note 3)
1310
(Note 3)
N/A
857
(Note 3)
234
(Note 3)
Active Length
(Compacted)
(m)
651.51
564
N/A
463.65
336
Factor of Safety
against
floatation
0.540
(Note-2)
0.434
(Note-2)
0.303
(Note-2)
0.436
(Note-2)
0.963
(Note-2)
Anchor load shall be considered based on non corroded condition. However, the value obtained
from approved stress analysis shall be used for design of anchor block.
Notes:
1) Values less than 25mm at A/G U/G transition point can be accepted and these can be
accommodated in A/G portion of the pipeline with sliding supports in the pig trap. Values
greater than 25mm are not acceptable and should be reduced by anchoring in the U/G
section of the pipeline as per the stress analysis report.
2) It is not anticipated that construction will be carried out in ground water because where
ground water is encountered; the pipeline will be installed on filled ground above the water
table in accordance with the typical drawings for Sabkha Construction. However,
Anti-buoyancy calculation is carried out to check pipeline stability in case pipeline installation
inside the water table is approved by COMPANY in unavoidable circumstances. The
calculation result FOS value less than 1.0 indicates that the pipeline is buoyant. A FOS
value greater than 1.1 is recommended to prevent pipe floatation against negative buoyancy
in case pipeline is laid inside water table.
ATTACHMENT-1A & 1B: WALL THICKNESS CALCULATIONS (CORRODED & NEW CONDITION)
(No. of Sheets – 10+5)
ATTACHMENT-2: UPHEAVAL BUCKLING CALCULATION
(No. of Sheets – 10)
ATTACHMENT-3: CROSSING CALCULATIONS
(No. of Sheets – 13)
ATTACHMENT-4: PIPELINE BUOYANCY CALCULATION
(No. of Sheets – 5)
ATTACHMENT-5: ANCHOR LOAD, ACTIVE LENGTH & FREE EXPANSION CALCULATION
(No. of Sheets – 15)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 24.8 mm 0.976 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 25.2 mm 0.992 inch
25 D/t Check ( Should be < 96) 52
26
27 B. COMBINED / EQUIVALENT STRESS CHECK FOR NEW PIPE CONDITION
28 Wall thickness (t) 25.2 mm 0.992 inch
29 Hoop Stress = SH = PD/2t 166.4 MPa 24136 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 49.9 MPa 7241 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -72.2 MPa -10471 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 238.6 MPa 34606 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 211.9 MPa 30739 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 238.6 MPa 34606 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 83.2 MPa 12068 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 83.2 MPa 12068 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 83.2 MPa 12068 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 144.1 MPa 20902 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 144.1 MPa 20902 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 166.6 MPa 24163 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 796 m
67 68 69 70 71 72 73 74 75 Page 1 of 10
11
Corrosion Allowance
A
1.5
mm
12
13
A. CHECK ON THINNING FOR FACTORY HOT BENDS: BEND RADIUS = 5 D
14
Calculated required thk, t
24.8
mm
15
t = P x D / (2x Sx Fx E x T) + A
16
Selected Mainline Wall Thickness
25.2
mm
17
n, Inner Bend radius divided by diameter
4.5
18
9.1 %
19
Pipe Thk. Before bending (cal thk)/(1-thinning %)
27.3
mm
20
Selected thickness for bend making
28.0
mm
21
Adequacy Check (Pipe thk before bending < Available thk)
OK
22
23
24
B. CHECK ON THINNING FOR FIELD OR COLD BENDS: BEND RADIUS = 40 D
25
Inner bend radius divided by diameter, (n)
39.5
26
1.23
%
27
Pipe thk. before bending = cal thk/(1-thinning %)
25.1
mm
28
Available thickness for bending (= Selected thk)
25.2
mm
29
Adequacy Check (Pipe thk before bending < Available thk)
OK
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9 18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 20.1 mm 0.792 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 20.5 mm 0.807 inch
25 D/t Check ( Should be < 96) 64
26
27 B. COMBINED / EQUIVALENT STRESS CHECK FOR NEW PIPE CONDITION
28 Wall thickness (t) 20.5 mm 0.807 inch
29 Hoop Stress = SH = PD/2t 204.6 MPa 29669 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 61.4 MPa 8901 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -60.7 MPa -8811 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 265.3 MPa 38480 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 240.8 MPa 34919 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 265.3 MPa 38480 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 102.3 MPa 14835 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 102.3 MPa 14835 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 102.3 MPa 14835 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 177.2 MPa 25694 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 177.2 MPa 25694 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 139.9 MPa 20290 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 948 m
67 68 69 70 71 72 73 74 75 Page 3 of 10
11
Corrosion Allowance
A
1.5
mm
12
13
A. CHECK ON THINNING FOR FACTORY HOT BENDS: BEND RADIUS = 5 D
14
Calculated required thk, t
20.1
mm
15
t = P x D / (2x Sx Fx E x T) + A
16
Selected Mainline Wall Thickness
20.5
mm
17
n, Inner Bend radius divided by diameter
4.5
18
9.1 %
19
Pipe Thk. Before bending (cal thk)/(1-thinning %)
22.1
mm
20
Selected thickness for bend making
25.2
mm
21
Adequacy Check (Pipe thk before bending < Available thk)
OK
22
23
24
B. CHECK ON THINNING FOR FIELD OR COLD BENDS: BEND RADIUS = 40 D
25
Inner bend radius divided by diameter, (n)
39.5
26
1.23
%
27
Pipe thk. before bending = cal thk/(1-thinning %)
20.4
mm
28
Available thickness for bending (= Selected thk)
20.5
mm
29
Adequacy Check (Pipe thk before bending < Available thk)
OK
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 14.4 mm 0.568 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 14.7 mm 0.579 inch
25 D/t Check ( Should be < 96) 90
26
27 B. COMBINED / EQUIVALENT STRESS CHECK FOR NEW PIPE CONDITION
28 Wall thickness (t) 14.7 mm 0.579 inch
29 Hoop Stress = SH = PD/2t 285.3 MPa 41376 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 85.6 MPa 12413 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -36.5 MPa -5299 psi
40 Combined/Equivalent Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 321.8 MPa 46674 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 305.2 MPa 44264 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 321.8 MPa 46674 psi
46 Combined Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 142.6 MPa 20688 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 142.6 MPa 20688 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 142.6 MPa 20688 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 247.1 MPa 35832 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 247.1 MPa 35832 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 83.4 MPa 12096 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 1589 m
67 68 69 70 71 72 73 74 75 Page 5 of 10
11
Corrosion Allowance
A
1.5
mm
12
13
A. CHECK ON THINNING FOR FACTORY HOT BENDS: BEND RADIUS = 5 D
14
Calculated required thk, t
14.4
mm
15
t = P x D / (2x Sx Fx E x T) + A
16
Selected Mainline Wall Thickness
14.7
mm
17
n, Inner Bend radius divided by diameter
4.5
18
9.1 %
19
Pipe Thk. Before bending (cal thk)/(1-thinning %)
15.9
mm
20
Selected thickness for bend making
20.5
mm
21
Adequacy Check (Pipe thk before bending < Available thk)
OK
22
23
24
B. CHECK ON THINNING FOR FIELD OR COLD BENDS: BEND RADIUS = 40 D
25
Inner bend radius divided by diameter, (n)
39.5
26
1.23
%
27
Pipe thk. before bending = cal thk/(1-thinning %)
14.6
mm
28
Available thickness for bending (= Selected thk)
14.7
mm
29
Adequacy Check (Pipe thk before bending < Available thk)
OK
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 16.5 mm 0.651 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 16.9 mm 0.665 inch
25 D/t Check ( Should be < 96) 63
26
27 B. COMBINED / EQUIVALENT STRESS CHECK FOR NEW PIPE CONDITION
28 Wall thickness (t) 16.9 mm 0.665 inch
29 Hoop Stress = SH = PD/2t 200.4 MPa 29068 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 60.1 MPa 8721 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -62.0 MPa -8991 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 262.4 MPa 38059 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 237.6 MPa 34455 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 262.4 MPa 38059 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 100.2 MPa 14534 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 100.2 MPa 14534 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 100.2 MPa 14534 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 173.6 MPa 25174 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 173.6 MPa 25174 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 142.8 MPa 20711 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 750 m
67 68 69 70 71 72 73 74 75 Page 7 of 10
11
Corrosion Allowance
A
1.5
mm
12
13
A. CHECK ON THINNING FOR FACTORY HOT BENDS: BEND RADIUS = 5 D
14
Calculated required thk, t
16.5
mm
15
t = P x D / (2x Sx Fx E x T) + A
16
Selected Mainline Wall Thickness
16.9
mm
17
n, Inner Bend radius divided by diameter
4.5
18
9.1 %
19
Pipe Thk. Before bending (cal thk)/(1-thinning %)
18.2
mm
20
Selected thickness for bend making
18.8
mm
21
Adequacy Check (Pipe thk before bending < Available thk)
OK
22
23
24
B. CHECK ON THINNING FOR FIELD OR COLD BENDS: BEND RADIUS = 40 D
25
Inner bend radius divided by diameter, (n)
39.5
26
1.23
%
27
Pipe thk. before bending = cal thk/(1-thinning %)
16.8
mm
28
Available thickness for bending (= Selected thk)
16.9
mm
29
Adequacy Check (Pipe thk before bending < Available thk)
OK
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 7.2 mm 0.285 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 14.7 mm 0.579 inch
25 D/t Check ( Should be < 96) 28
26
27 B. COMBINED / EQUIVALENT STRESS CHECK FOR NEW PIPE CONDITION
28 Wall thickness (t) 14.7 mm 0.579 inch
29 Hoop Stress = SH = PD/2t 87.8 MPa 12731 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 26.3 MPa 3819 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -95.8 MPa -13892 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 183.6 MPa 26623 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 159.0 MPa 23064 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 183.6 MPa 26623 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 43.9 MPa 6365 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 43.9 MPa 6365 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 43.9 MPa 6365 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 76.0 MPa 11025 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 76.0 MPa 11025 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 221.6 MPa 32147 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 184 m
67 68 69 70 71 72 73 74 75 Page 9 of 10
11
Corrosion Allowance
A
1.5
mm
12
13
A. CHECK ON THINNING FOR FACTORY HOT BENDS: BEND RADIUS = 5 D
14
Calculated required thk, t
7.2
mm
15
t = P x D / (2x Sx Fx E x T) + A
16
Selected Mainline Wall Thickness
14.7
mm
17
n, Inner Bend radius divided by diameter
4.5
18
9.1 %
19
Pipe Thk. Before bending (cal thk)/(1-thinning %)
8.0
mm
20
Selected thickness for bend making
14.7
mm
21
Adequacy Check (Pipe thk before bending < Available thk)
OK
22
23
24
B. CHECK ON THINNING FOR FIELD OR COLD BENDS: BEND RADIUS = 40 D
25
Inner bend radius divided by diameter, (n)
39.5
26
1.23
%
27
Pipe thk. before bending = cal thk/(1-thinning %)
7.3
mm
28
Available thickness for bending (= Selected thk)
14.7
mm
29
Adequacy Check (Pipe thk before bending < Available thk)
OK
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
As per Cl 6.2.2.3 of PD 8010-1:2004,% of wall thinning
(50)/(n+1)
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 24.8 mm 0.976 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 25.2 mm 0.992 inch
25 D/t Check ( Should be < 96) 52
26
27 B. COMBINED /EQUIVALENT STRESS CHECK FOR CORRODED PIPE CONDITION
28 Wall thickness (t) 23.7 mm 0.933 inch
29 Hoop Stress = SH = PD/2t 176.9 MPa 25663 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 53.1 MPa 7699 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -69.0 MPa -10012 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 246.0 MPa 35676 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 219.7 MPa 31872 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 246.0 MPa 35676 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 88.5 MPa 12832 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 88.5 MPa 12832 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 88.5 MPa 12832 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 153.2 MPa 22225 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 153.2 MPa 22225 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 159.2 MPa 23094 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 832 m
67 68 69 70 71 72 73 74 75 Page 1 of 5
13 Aboveground Design Temp. T2 100
o
C 212.0 oF
14 Underground Design Temp. T3 65
oC
149.0 oF
15 Weld joint factor E 1
16 Temperature Derating Factor T 1
17 Max. factor for load of long durations k 0.9
18
19 A. WALL THICKNESS
20 Grade X65
21 SMYS of Line Pipe S 65300 psi 450 MPa
22 Wall Thickness Calculated tmin 20.1 mm 0.792 inch
23 tmin = PD / (2SFET) + A
24 Selected wall thickness t 20.5 mm 0.807 inch
25 D/t Check ( Should be < 96) 64
26
27 B. COMBINED /EQUIVALENT STRESS CHECK FOR CORRODED PIPE CONDITION
28 Wall thickness (t) 19.0 mm 0.748 inch
29 Hoop Stress = SH = PD/2t 220.7 MPa 32012 psi
30
31 B.1 Restrained Pipe (Underground)
32 Thermal Stress = ST = α (T1 - T3) E -122.1 MPa -17711 psi
33 Longitudinal Stress due to pressure = SP = 0.3 SH 66.2 MPa 9603 psi
34
35 Longitudinal Stress, SL
36 SL = SP + ST + SB + SX ≤ 0.9 x SMYS x T = 406 MPa 58770 psi
37
38 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
39 SL = SP + ST -55.9 MPa -8108 psi
40 Longitudinal Stress check : SL ≤ 0.9 x SMYSxT hence OK 41 42 Combined Stress, SE 43 SE1 = | SH - SL | SE1 276.6 MPa 40120 psi 44 SE2 = [ SH 2 + SL 2 - SH SL ] 1/2 S E2 253.3 MPa 36743 psi
45 SE = Max (SE1, SE2) ≤ k x SMYS xT = 406 MPa SE 276.6 MPa 40120 psi
46 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 47
48 B.2 Unrestrained Pipe (Aboveground)
49 Longitudinal Stress due to pressure = SP = 0.5 SH 110.4 MPa 16006 psi
50
51 Longitudinal Stress, SL
52 SL = SP +SB + SX ≤ 0.75 x SMYS x T = 338 MPa 48975 psi
53 Without considering SB (Bending stress) and SX (Axial stress due to external loading):
54 SL = SP 110.4 MPa 16006 psi
55 Longitudinal Stress check : SL ≤ 0.75 x SMYSxT hence OK 56
57 Combined Stress, SE
58 SE1 = | SH - SL | SE1 110.4 MPa 16006 psi
59 SE2 = [ SH2 + SL2 - SH SL ]1/2 SE2 191.1 MPa 27723 psi
60 SE = Max (SE1, SE2) ≤ k x SMYS xT = 0 MPa SE 191.1 MPa 27723 psi
61 Combined/Equivalent Stress check : SE≤ 0.9 x SMYSxT hence OK 62
63 C. MINIMUM BENDING RADIUS
64 Minimum bending radius for underground section is calculated from margin for elastic bending,
65 = (0.9 x SMYS x T) - SE 128.6 MPa 18650 psi
66 R (Minimum Bend Radius) = E D / (2 |Sb|) 1031 m
67 68 69 70 71 72 73 74 75 Page 2 of 5