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www.elsevier.com/locate/spa

A strong uniform approximation of fractional Brownian

motion by means of transport processes

I

J. Garz´on

a

, L.G. Gorostiza

a,∗

, J.A. Le´on

b aDepartment of Mathematics, CINVESTAV, A.P. 14-740, M´exico 07000 D.F., Mexico bDepartment of Automatic Control, CINVESTAV, A.P. 14-740, M´exico 07000 D.F., Mexico

Received 29 November 2008; received in revised form 28 May 2009; accepted 6 June 2009 Available online 11 June 2009

Abstract

We construct a sequence of processes that converges strongly to fractional Brownian motion uniformly on bounded intervals for any Hurst parameter H, and we derive a rate of convergence, which becomes better whenHapproaches 1/2. The construction is based on the Mandelbrot–van Ness stochastic integral representation of fractional Brownian motion and on a strong transport process approximation of Brownian motion. The objective of this method is to facilitate simulation.

c

2009 Elsevier B.V. All rights reserved. MSC:primary 60F15; secondary 60G15; 60G18

Keywords:Fractional Brownian motion; Transport processes; Almost sure convergence; Rate of convergence

1. Introduction

Fractional Brownian motion (fBm) with Hurst parameter H ∈ (0,1), W = (Wt)t≥0, is a

centered Gaussian process with covariance functionE(WtWs)=(1/2)[s2H+t2H− |t−s|2H].

It is standard Brownian motion (Bm) for H = 1/2 (we exclude this case). The covariance of its increments on intervals decays asymptotically as a negative power of the distance between the intervals.W is the only finite-variance process which is self-similar (with index H) and has stationary increments. See [1,17–19] for general background. This process is employed in many areas of application (see e.g. [5,11]), and therefore it is useful to have strong approximations that

IResearch partially supported by a CONACYT grant (Mexico).Corresponding author. Tel.: +52 55 5747 3868; fax: +52 55 5747 3390.

E-mail addresses:[email protected](J. Garz´on),[email protected](L.G. Gorostiza),

[email protected](J.A. Le´on).

0304-4149/$ - see front matter c2009 Elsevier B.V. All rights reserved.

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provide simple methods for simulating its paths. The purpose of the present paper is to propose such an approximation. We prove strong and uniform convergence theorems forH >1/2 and

H < 1/2, by means of the Mandelbrot–van Ness stochastic integral representation of W with respect to Bm [16] (formula(2.1) below), and a strong approximation of Bm with transport processes [8]. The approximation of W improves when H approaches 1/2 (described more precisely in the next paragraph). Thenth approximation step requires generating three sequences of i.i.d. exponentially distributed random variables with parameter n2, in order to construct corresponding transport processesXi(n),i=1,2,3, which are used to define the approximations

W(n)andWˆ(n)toW forH >1/2 andH<1/2, respectively (formulas(2.9)and(2.10)below). There are many methods for simulating fBm paths in the literature (see e.g. [6,19], and references in there). Different weak approximations of fBm have been given (e.g. [4,7,10,

14,15,20,23]), some of them based on random walks. Szabados [22], using his approach to Bm [21] and the Mandelbrot–van Ness representation of fBm, gave a strong random walk approximation of fBm for H ∈ (1

4,1), with convergence rate O(n

−min(H−1/4,1/4)2 log 2logn)

at the nth approximation step. We obtain convergence rate O(n−|1/2−β|(logn)5/2) for 0 < |H − 1

2| < β < 1

2. This rate becomes better whenH approaches 1

2, it becomes worse when

H approaches 0 or 1, and it is better than that of [22] for H ∈ (1

4,0.653). On the other hand,

the construction in [22] is more elaborate than ours and it converges to some fBm, whereas ours converges to the given fBm, since it is constructed only from the Bm in the Mandelbrot–van Ness representation of the fBm.

In Section2 we describe the approximating processes and state the convergence theorems, and in Section3we give the proofs.

2. Approximation of fractional Brownian motion

For eachn = 1,2, . . ., let(X(n)(t))t≥0be a process such that X(n)(t)is the position on the

real line at timet of a particle moving as follows. It starts from 0 with constant velocity+n

or−n, each with probability 1/2. It continues until a random timeτ1which is exponentially distributed with parametern2, and at that time it switches from velocity±nto∓nand continues for an additional independent random timeτ2−τ1 which is again exponentially distributed with parametern2. At timeτ2 it changes velocity as before, and so on. This process is called a (uniform) transport process. Griego, Heath and Ruiz-Moncayo [9] showed thatX(n)converges strongly and uniformly on bounded time intervals to Brownian motion, and later a rate of convergence was derived in [8]. The result of [8] is the following:

Theorem 2.1. There exist versions of the transport processes X(n)on the same probability space as a given Brownian motion(B(t))t≥0such that for each q>0,

P sup

a≤t≤b

|B(t)−X(n)(t)|>C n−1/2(logn)5/2

!

=o(n−q) as n → ∞,

where C is a positive constant depending on a,b and q.

Remark 2.1. A better rate of convergence is proved in [3] (Theorem 2.2) for a sequence

of Brownian motions (which is suitably defined) and a corresponding sequence of transport processes, using the KMT approximation [13]. (Regarding the KMT approximation, see also [2].) However the construction in the approximation of [12,13] is intricate, as explained in [22]

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(Section2), and therefore is not practical. On the other hand, in our setup we need to approximate a single given Brownian motion by transport processes, therefore the convergence rate of [3] is not applicable for our objective.

Let(Wt)0≤t≤T be fBm with Mandelbrot–van Ness representation

Wt =CH Z 0 −∞ [(t−s)H−1/2−(−s)H−1/2]dB(s)+ Z t 0 (t−s)H−1/2dB(s) , (2.1)

whereCH is a positive constant, andB =(B(t))t∈Ris Bm on whole real line. We fixT >0 and

a<0, and we define the following Brownian motions: 1. (B1(s))0≤s≤T, the restriction ofBto the interval [0,T].

2. (B2(s))a≤s≤0, the restriction of Bto the interval [a,0].

3. B3(s)= s B 1 s ifs∈ 1 a,0 , 0 ifs=0.

ByTheorem 2.1, there are three transport processes

(X(1n)(s))0≤s≤T, (X2(n)(s))a≤s≤0 and (X(3n)(s))1

a≤s≤0, (2.2)

such that for eachq>0,

P sup bi≤t≤ci |Bi(t)−Xi(n)(t)|>C( i)n−1/2(logn)5/2 ! =o(n−q) asn → ∞, (2.3)

wherebi,ci,i =1,2,3, are the endpoints of the corresponding intervals, andC(i)is a positive

constant that depends onbi,ci andq. Note thatX2(n)andX3(n)are constructed going backwards

in time.

From(2.3), for each 0< β < 12andC>C(i)we have

P sup bi≤t≤ci |Bi(t)−X(in)(t)|>C n−(1/2−β)(logn)5/2 ! =o(n−q) asn → ∞, (2.4) and takingεn˜ = −nβ/(H−1/2), P sup bi≤t≤ci |Bi(t)−Xi(n)(t)|>C(−˜εn) 1/2−Hn−(1/2−β)( logn)5/2 ! =o(n−q) asn→ ∞. (2.5)

We define the following functions, which will be used throughout,

ft(s)=(t−s)H−1/2−(−s)H−1/2 fors<0≤t, (2.6)

and

gt(s)=(t−s)H−1/2 fors<t, (2.7)

and for 0< β < 12we put

εn= −n−β/|H−1/2|. (2.8)

Now we define two different approximating processes, the first one for H > 1/2 and the second one forH<1/2 (the caseH=1/2 is given byTheorem 2.1).

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ForH >1/2 the processW(n)= W(n)(t)0tT is defined as W(n)(t)=CH Z t 0 gt(s)dX(1n)(s)+ Z 0 a ft(s)dX(2n)(s)+ ft(a)X2(n)(a) + Z 0 1 a − Z s∧εn 1 a ∂sft 1 v 1 v3dv dX(3n)(s) , (2.9)

and forH <1/2 the processWˆ(n)=Wˆ(n)(t)

0≤t≤T is defined as ˆ W(n)(t)=CH Z (t+εn)∨0 0 gt(s)dX1(n)(s)+ Z t (t+εn)∨0 gt(εn+s)dX(1n)(s) + Z εn a ft(s)dX2(n)(s)+ ft(a)X2(n)(a) + Z 0 1 a − Z s 1 a ∂s ft 1 v 1 v3dv dX3(n)(s) . (2.10)

The following theorems give the convergence and the rates of convergence of the processes

W(n)andWˆ(n)to fBm forH>1/2 andH <1/2, respectively.

Theorem 2.2. Let H > 12 and let W and W(n) be the processes defined by(2.1)and (2.9), respectively. Then for each q>0and eachβsuch that0<H−1

2 < β < 1 2, there is a constant C>0such that P sup 0≤t≤T W(t)−W (n)(t) >C n −(1/2−β)(logn)5/2 ! =o(n−q) as n→ ∞.

Theorem 2.3. Let H < 12 and let W and Wˆ(n) be the processes defined by(2.1)and (2.10), respectively. Then for each q>0and eachβsuch that0<12−H < β < 12, there is a constant

ˆ C>0such that P sup 0≤t≤T W(t)− ˆW (n)(t) > ˆ C n−(1/2−β)(logn)5/2 ! =o(n−q) as n→ ∞. For the proofs we will use repeatedly the pathwise H¨older continuity of Brownian motion:

Proposition 2.4.Let(Bt)t≥0be Brownian motion. For each T >0and each0< γ <1/2there

is a positive random variable Y =Yγ with E(Yn) <∞for all n=1,2,3, . . ., such that

|B(t)−B(s)|<Y|t−s|1/2−γ a.s. t,s∈ [0,T]. 3. Proofs

The proofs are based on the following series of lemmas.

Lemma 3.1. For each fixed t>0, the function ftgiven by(2.6)has the following properties:

1.

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2. |∂sft(s)| ≤ |H−1/2|t(3/2−H)(−s)H−5/2. (3.2) 3. Z a −∞ |∂sft(s)|(−s)1/2+γds<∞ for each0< γ <1−H. (3.3) 4. lim b→−∞ ft(b)B(b) =0 a.s. (3.4) 5. Z a −∞ ft(s)dB(s)= ft(a)B2(a)− Z 0 1 a ∂sft 1 v 1 v3B3(v)dv. (3.5)

Proof. 1. ∂sft(s)=(H−1/2)[(−s)H−3/2−(t−s)H−3/2]. Since 0<H <1, thenH−3/2<0, hence(t−s)H−3/2< (−s)H−3/2, so the sign of the derivative depends on the sign ofH−1/2. 2. Taking p(x) = xH−3/2, p0(x)=(H −3/2)xH−5/2, x ∈ [−s,t−s]. By the mean value

theorem, for somer∈ [−s,t−s],

(−s)H−3/2−(t−s)H−3/2 =t(3/2−H)rH−5/2≤t(3/2−H)(−s)H−5/2.

3. From part 2 we have

Z a −∞ |∂sft(s)|(−s)1/2+γds ≤ Z a −∞ |H−1/2|t(3/2−H)(−s)H−5/2(−s)1/2+γds = |H−1/2|t(3/2−H) Z a −∞ (−s)H−2+γds =|H−1/2|t(3/2−H) 1−γ−H (−a) H−1+γ < ifγ <1−H.

4. Forb<a, for the Bms B(1/s)on[1/a,0], takingγ < (1−H)∧(1/2)inProposition 2.4, we have|s B(1/s)|<Y(−s)1/2−γ for eachs∈ [1/a,0], then|B(s)|<Y(−s)1/2+γ for each

s∈(−∞,a]. Therefore, |ft(b)B(b)| ≤ (t−b) H−1/2(b)H−1/2 Y(−b) 1/2+γ = 1− t b H−1/2 −1 Y(−b)H+γ,

and using the l’Hˆopital rule, lim

b→−∞

|1−t/b|H−1/2−1

(−b)−γ−H =0.

5. Since ft is square-integrable, limb→−∞Rba ft(s)dB(s) = R−∞a ft(s)dB(s). Now, applying

integration by parts, Z a b ft(s)dB(s)= ft(a)B(a)− ft(b)B(b)− Z a b ∂sft(s)B(s)ds,

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by(3.3), Z a −∞ |∂sft(s)B(s)|ds<∞, and using(3.4), Z a −∞ ft(s)dB(s)= lim b→−∞ Z a b ft(s)dB(s) = lim b→−∞ ft(a)B(a)− ft(b)B(b)− Z a b ∂sft(s)B(s)ds = ft(a)B(a)− Z a −∞ ∂sft(s)B(s)ds. Now, puttings=1/v, Z a −∞ ∂sft(s)B(s)ds = Z 1a 0 ∂sft 1 v 1 v2 B 1 v dv = Z 0 1 a ∂sft 1 v 1 v2B 1 v dv = Z 0 1 a ∂sft 1 v 1 v3B3(v)dv, and we obtain Z a −∞ ft(s)dB(s)= ft(a)B2(a)− Z 0 1 a ∂sft 1 v 1 v3B3(v)dv. 3.1. CaseH>1/2

In the following lemmas 0< β <1/2,εndefined by(2.8), andαn=n−(1/2−β)(logn)5/2.

Lemma 3.2. Let X2(n)be the process defined by(2.2). Then for each q >0there is C1>0such

that I1=P sup 0≤t≤T CH ft(a)B2(a)− ft(a)X (n) 2 (a) >C1 αn 5 ! =o(n−q) as n→ ∞. Proof. Since ft(a)(B2(a)−X (n) 2 (a)) ≤ sup a≤s≤0 B2(s)−X (n) 2 (s) (t−a) H−1/2, then I1≤ P CH(T −a)H−1/2 sup a≤s≤0 B2(s)−X (n) 2 (s) >C1 αn 5 ! ≤ P sup a≤s≤0 B2(s)−X (n) 2 (s) >C1CTαn ! .

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Lemma 3.3. Let X(1n)be the process defined by(2.2). Then for each q >0there is C2>0such that I2 = P sup 0≤t≤T CH Z t 0 gt(s)dB1(s)− Z t 0 gt(s)dX1(n)(s) > C2αn 5 =o(n−q) as n→ ∞. Proof. By integration by parts,

Z t 0 gt(s)dB1(s)=(H−1/2) Z t 0 (t−s)H−3/2B1(s)ds.

Analogously (using thatX(1n)(0)=0),

Z t 0 gt(s)dX1(n)(s)=(H−1/2) Z t 0 (t−s)H−3/2X(1n)(s)ds, therefore Z t 0 gt(s)dB1(s)− Z t 0 gt(s)dX1(n)(s) ≤(H−1/2) Z t 0 (t−s)H−3/2 B1(s)−X (n) 1 (s) ds ≤ sup 0≤s≤t B1(s)−X (n) 1 (s) t H−1/2. Consequently, I2 ≤ P sup 0≤t≤T CHtH−1/2 sup 0≤s≤t B1(s)−X (n) 1 (s) >C2 αn 5 ! ≤ P CHTH−1/2 sup 0≤s≤T B1(s)−X (n) 1 (s) >C2 αn 5 ! = P sup 0≤s≤T B1(s)−X (n) 1 (s) >CTC2 αn 5 ! ,

and we obtain the result from(2.4)takingC2such thatC2CT/5>C(1).

Lemma 3.4. Let X(2n)be the process defined by(2.2). Then for each q >0there is C3>0such

that I3 = P sup 0≤t≤T CH Z 0 a ft(s)dB2(s)− Z 0 a ft(s)dX(2n)(s) >C3αn 5 ! =o(n−q) as n→ ∞. Proof. By integration by parts,

Z 0 a ft(s)dB2(s)= −ft(a)B2(a)− Z 0 a ∂sft(s)B2(s)ds,

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and (using thatX(2n)(0)=0) Z t 0 ft(s)dX2(n)(s)= −ft(a)X2(n)(a)− Z 0 a ∂sft(s)X2(n)(s)ds. Then, Z 0 a ft(s)dB2(s)− Z 0 a ft(s)dX2(n)(s) ≤ |ft(a)(B2(a)−X(2n)(a))| + Z 0 a ∂sft(s)B2(s)ds− Z 0 a ∂sft(s)X2(n)(s)ds ≤ sup a≤s≤0 B2(s)−X (n) 2 (s) ! " |ft(a)| + Z 0 a |∂sft(s)|ds # = sup a≤s≤0 B2(s)−X (n) 2 (s) [ft(a)+ ft(0)− ft(a)] = sup a≤s≤0 B2(s)−X (n) 2 (s) t H−1/2. Thus, I3≤ P sup 0≤t≤T CHtH−1/2 sup a≤s≤0 B2(s)−X (n) 2 (s) >C3 αn 5 ! ≤ P CHTH−1/2 sup a≤s≤0 B2(s)−X (n) 2 (s) >C3 αn 5 ! = P sup a≤s≤0 B2(s)−X (n) 2 (s) >CTC3 αn 5 ! ,

and the result follows from(2.4)takingC3such thatC3CT/5>C(2).

Lemma 3.5. Let X3(n)be the process defined by(2.2). Then for each q >0there is C4>0such

that I4= P sup 0≤t≤T CH Z εn 1/a ∂sft 1 v 1 v3B3(v)dv − Z 0 1 a − Z s∧εn 1 a ∂sft 1 v 1 v3dv ! dX(3n)(s) >C4αn 5 ! =o(n−q) as n → ∞.

Proof. By Fubini’s theorem we have

Z 0 1 a − Z s∧εn 1 a ∂sft 1 v 1 v3dv ! dX(3n)(s)= Z εn 1/a ∂sft 1 v 1 v3X (n) 3 (v)dv.

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Then, using(3.2)we obtain Z εn 1 a ∂sft 1 v 1 v3B3(v)dv− Z 0 1 a − Z s∧εn 1 a ∂sft 1 v 1 v3dv ! dX(3n)(s) ≤ sup 1/a≤s≤0 B3(s)−X (n) 3 (s) ! Z εn 1 a ∂s ft 1 s 1 s3 ds ≤ sup 1/a≤s≤0 B3(s)−X (n) 3 (s) ! Z εn 1 a (3/2−H)(H−1/2)t(−s)−H−1/2ds ≤ sup 1/a≤s≤0 B3(s)−X (n) 3 (s) (3/2−H)t(−εn) 1/2−H. Hence, I4 ≤ P CH(3/2−H)T(−εn)1/2−H sup 1/a≤s≤0 B3(s)−X (n) 3 (s) >C4 αn 5 ! ≤ P sup 1/a≤s≤0 B3(s)−X (n) 3 (s) >CTC4 αn 5 n −β ! = P sup 1/a≤s≤0 B3(s)−X (n) 3 (s) >CTC4n −1/2(logn)5/2 ! ,

and the result follows from(2.3)takingC4such thatC4CT/5>C(3).

Lemma 3.6. Let H−1/2< β <1/2. Then for each q >0

I5=P sup 0≤t≤T CH Z 0 εn ∂sft 1 v 1 v3B3(v)dv > αn 5 ! =o(n−q) as n → ∞.

Proof. FromProposition 2.4withγ <1−H, and(3.2), Z 0 εn ∂sf 1 v 1 v3B3(v)dv ≤ Z 0 εn (3/2−H)(H−1/2)t Y(−v)−H−1/2(−v)1/2−γdv = (3/2−H)(H−1/2)t Y (1−H−γ ) (−εn) 1−H−γ =C t Y n−β(1−H−γ )/(H−1/2).

By Chebyshev’s inequality, forr >0,

I5 ≤ P C T Y n−β(1−H−γ )/(H−1/2)> αn 5 = PC Y˜ >nκ(logn)5/2≤ E(| ˜C Y| r) nrκ(logn)r5/2, whereκ = −(1/2−β)+β(1−H−γ )/(H−1/2). TakingH−1/2< (H−1/2)/(1−2γ ) <

β <1/2, thenκ >0. Forq >0 there isr>0 such thatq <rκ, then lim

n→∞n qI

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Proof of Theorem 2.2. From(2.1)and(3.5)we have W(t)=CH ( Z t 0 gt(s)dB(s)+ Z 0 a ft(s)dB(s)+ Z a −∞ ft(s)dB(s) ) =CH Z t 0 gt(s)dB1(s)+ Z 0 a ft(s)dB2(s)+ ft(a)B2(a) − Z 0 1 a ∂sft 1 v 1 v3B3(v)dv =CH Z t 0 gt(s)dB1(s)+ Z 0 a ft(s)dB2(s)+ ft(a)B2(a) − Z εn 1 a ∂sft 1 v 1 v3B3(v)dv− Z 0 εn ∂sft 1 v 1 v3B3(v)dv ,

which together with(2.9)yields |W(t)−W(n)(t)| ≤CH ( Z t 0 gt(s)dB1(s)− Z t 0 gt(s)dX(1n)(s) + Z 0 a ft(s)dB2(s)− Z 0 a ft(s)dX(2n)(s) + ft(a)B2(a)− ft(a)X (n) 2 (a) + Z εn 1 a ∂sft 1 v 1 v3B3(v)dv− Z 0 1 a − Z s∧εn 1 a ∂sft 1 v 1 v3dv ! dX3(n)(s) + Z 0 εn ∂s ft 1 v 1 v3B3(v)dv ) .

Therefore, takingβ such that 0<H−1/2< β <1/2, and puttingC =max{C1,C2,C3,C4},

byLemmas 3.2–3.6, P sup 0≤t≤T W(t)−W (n)(t) >C n −(1/2−β)( logn)5/2 ! ≤I1+I2+I3+I4+I5=o(n−q) asn → ∞.

and the proof is finished.

3.2. CaseH<1/2

In the following lemmasβ,εnandαnare similar as in case H>1/2.

Lemma 3.7. Let X2(n)be the process defined by(2.2). Then for each q >0there isCˆ1>0such

that J1=P sup 0≤t≤T CH ft(a)B2(a)− ft(a)X (n) 2 (a) > ˆ C1 αn 7 ! =o(n−q) as n→ ∞.

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Proof. By similar arguments as in the proof of Lemma 3.2, with (2.4)putting Cˆ1 such that (−a)H−1/2Cˆ1/7>C(2), we have the result.

Lemma 3.8. Let X(1n)be the process defined by(2.2). Then for each q >0there isCˆ2>0such

that J2= P sup 0≤t≤T CH Z (t+εn)∨0 0 gt(s)dB1(s)− Z (t+εn)∨0 0 gt(s)dX1(n)(s) >Cˆ 2αn 7 =o(n−q) as n→ ∞. Proof. By integration by parts,

Z (t+εn)∨0 0 gt(s)dB1(s)=gt((t+εn)∨0)B1((t+εn)∨0) − Z (t+εn)∨0 0 ∂sgt(s)B1(s)ds, (3.6) and Z (t+εn)∨0 0 gt(s)dX1(n)(s)=gt((t+εn)∨0)X1(n)((t+εn)∨0) − Z (t+εn)∨0 0 ∂sgt(s)X1(n)(s)ds. (3.7) Note that Z (t+εn)∨0 0 ∂sgt(s)B1(s)ds− Z (t+εn)∨0 0 ∂sgt(s)X(1n)(s)ds ≤ sup 0≤s≤t B1(s)−X (n) 1 (s) [gt((t+εn)∨0)−gt(0)] ≤ sup 0≤s≤t B1(s)−X (n) 1 (s) (−εn) H−1/2, (3.8) and gt((t+εn)∨0)B1((t+εn)∨0)−gt((t+εn)∨0)X (n) 1 ((t+εn)∨0) = |gt((t+εn)∨0)| B1((t+εn)∨0)−X (n) 1 ((t+εn)∨0) ≤ sup 0≤s≤t B1(s)−X (n) 1 (s) (−εn) H−1/2. (3.9)

Therefore, from(3.6)–(3.9), we obtain

J2≤ P sup 0≤t≤T 2CH sup 0≤s≤t B1(s)−X (n) 1 (s) (−εn) H−1/2>Cˆ 2αn 7 ! ≤ P sup 0≤s≤T B1(s)−X (n) 1 (s) > (2CH) −1Cˆ2(εn)1/2−Hαn 7 ! ,

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Lemma 3.9. For1/2−H < β <1/2and each q>0, J3 = P sup 0≤t≤T CH Z t (t+εn)∨0 [gt(s)−gt(εn+s)]dB1(s) > αn 7 ! =o(n−q) as n→ ∞.

Proof. ByProposition 2.4withγ <Hand Fubini’s theorem for Brownian motion, Z t (t+εn)∨0 [gt(s)−gt(εn+s)]dB1(s) = Z t (t+εn)∨0 Z t−s−εn t−s (1/2−H)xH−3/2d xdB1(s) = Z −2εn∧(t−εn) −εn (1/2−H)xH−3/2 Z t−x−εn (t+εn)∨0 dB1(s)dx + Z −εn∧t 0 (1/2−H)xH−3/2 Z t t−x dB1(s)dx + Z −εn −εn∧t (1/2−H)xH−3/2 Z t 0 dB1(s)dx ≤Y(1/2−H) Z −2εn∧(t−εn) −εn xH−3/2|t−x−εn−(t+εn)∨0|1/2−γdx +Y(1/2−H) Z −εn∧t 0 xH−3/2x1/2−γdx+Y(1/2−H) Z −εn −εn∧t xH−3/2t1/2−γdx ≤Y(1/2−H) (−2εn)1/2−γ 1 H−1/2[(−2εn∧(t−εn)) H−1/2(εn)H−1/2] + 1 H−γ(−εn∧t) H−γ + t1/2−γ 1 H−1/2[(−εn) H−1/2(εnt)H−1/2] ≤ Y 21/2−γ(−εn)H−γ+1/2−H H−γ (−εn) H−γ + tH−γI{t<−εn} ≤C Y(−εn)H−γ =C Y nβ(H−γ )/(H−1/2). Hence, P sup 0≤t≤T CH Z t (t+εn)∨0 [gt(s)−gt(εn+s)] dB1(s) > αn 7 ! ≤P7CHC Y > αnn−β(H−γ )/(H−1/2) =PC Y˜ >nκ(logn)5/2,

whereκ = −(1/2−β)−β(H−γ )/(H−1/2). Taking(1/2−H)/(1−2γ ) < β <1/2, then

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Lemma 3.10. Let X1(n) be the process defined by(2.2). Then for each q >0 there isCˆ3 >0 such that J4= P sup 0≤t≤T CH Z t (t+εn)∨0 gt(εn+s)dB1(s) − Z t (t+εn)∨0 gt(εn+s)dX(1n)(s) > ˆ C3αn 7 =o(n−q) as n→ ∞. Proof. By integration by parts,

Z t (t+εn)∨0 gt(εn+s)dB1(s) =(−εn)H−1/2B1(t)−(t−εn−(t+εn)∨0)H−1/2B1((t+εn)∨0) + Z t (t+εn)∨0 (H−1/2)(t−εn−s)H−3/2B1(s)ds, (3.10) and Z t (t+εn)∨0 gt(εn+s)dX(1n)(s) =(−εn)H−1/2X1(n)(t)−(t−εn−(t+εn)∨0)H−1/2X(1n)((t+εn)∨0) + Z t (t+εn)∨0 (H−1/2)(t−εn−s)H−3/2X(1n)(s)ds. (3.11) Since |(−εn)H−1/2B1(t)−(t−εn−(t+εn)∨0)H−1/2B1((t+εn)∨0) −(−εn)H−1/2X1(n)(t)+(t−εn−(t+εn)∨0)H−1/2X1(n)((t+εn)∨0)| ≤(−εn)H−1/2 B1(t)−X (n) 1 (t) +(t−εn−(t+εn)∨0)H−1/2 B1((t+εn)∨0)−X (n) 1 ((t+εn)∨0) ≤(−εn)H−1/2h B1(t)−X (n) 1 (t) +2H−1/2 B1((t+εn)∨0)−X (n) 1 ((t+εn)∨0) i ≤2(−εn)H−1/2 sup 0≤t≤T B1(t)−X (n) 1 (t) , (3.12) and Z t (t+εn)∨0 (H−1/2)(t−εn−s)H−3/2B1(s)ds − Z t (t+εn)∨0 (H−1/2)(t−εn−s)H−3/2X1(n)(s)ds

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≤ sup 0≤s≤T B1(s)−X (n) 1 (s) ! Z t (t+εn)∨0 (1/2−H)(t−εn−s)H−3/2ds ≤ sup 0≤s≤T B1(s)−X (n) 1 (s) (−εn) H−1/2. (3.13) Then, from(3.10)–(3.13), J4≤ P sup 0≤s≤T B1(s)−X (n) 1 (s) >2 ˆ C3(−εn)1/2−Hαn 7 ! ,

the result follows by(2.5)takingCˆ3such that 2Cˆ3/7>C(1).

Lemma 3.11.Let X(2n)be as in(2.2). Then for each q >0there isCˆ4>0such that

J5 = P sup 0≤t≤T CH Z εn a ft(s)dB2(s)− Z εn a ft(s)dX(2n)(s) > ˆ C4αn 7 ! =o(n−q) as n→ ∞. (3.14)

Proof. By integration by parts, Z εn a ft(s)dB2(s)= ft(εn)B2(εn)− ft(a)B2(a)− Z εn a ∂s ft(s)B2(s)ds, and Z εn a ft(s)dX2(n)(s)= ft(εn)X2(n)(εn)− ft(a)X2(n)(a)− Z εn a ∂sft(s)X2(n)(s)ds.

Proceeding similarly as inLemma 3.7we have

P sup 0≤t≤T CH ft(a)B2(a)− ft(a)X (n) 2 (a) > ˆ C4α14n ! =o(n−q) asn→ ∞. (3.15) Since∂s ft(s)=(H−1/2)[(−s)H−3/2−(t−s)H−3/2](see(2.6)), we have

ft(εn)B2(εn)− Z εn a ∂sft(s)B2(s)ds− ft(εn)X(2n)(εn)+ Z εn a ∂sft(s)X2(n)(s)ds ≤ sup a≤s≤0 B2(s)−X (n) 2 (s) |ft(εn)| + sup a≤s≤εn B2(s)−X (n) 2 (s) Z εn a |∂sft(s)|ds ≤ sup a≤s≤0 B2(s)−X (n) 2 (s) 2(−εn) H−1/2. (3.16)

Thus,(3.15)and(3.16)together with(2.5)allow to see that(3.14)holds.

Lemma 3.12.For1/2−H< β <1/2and each q >0, J6=P sup 0≤t≤T CH Z 0 εn ft(s)dB2(s) > αn 7 ! =o(n−q) as n→ ∞.

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Proof. ByProposition 2.4withγ <H, Z 0 εn ∂sft(s)B2(s)ds ≤Y(1/2−H) Z 0 εn [(−s)H−3/2−(t−s)H−3/2](−s)1/2−γds ≤ Y(1/2−H) Z 0 εn (−s)H−3/2(−s)1/2−γds=Y(1/2−H) Z 0 εn (−s)H−1−γds = Y1/2−H H−γ (−εn) H−γ. (3.17) Using the fact that limb→0−Rb

εn ft(s)dB2(s) =

R0

εn ft(s)dB2(s)in L

2, the integration by parts

formula implies Z b εn ft(s)dB2(s)= ft(b)B2(b)− ft(εn)B2(εn)− Z b εn ∂sft(s)B2(s)ds and since lim b→0−|ft(b)B2(b)| ≤Yblim0−|ft(b)kb| 1/2−γ =Y lim b→0− |(t−b)H−1/2−(−b)H−1/2kb|1/2−γ =Y lim b→0− |(t−b)H−1/2(−b)1/2−γ −(−b)H−γ| =0, then Z 0 εn ft(s)dB2(s)= lim b→0− Z b εn ft(s)dB2(s) = −ft(εn)B2(εn)− Z 0 εn ∂sft(s)B2(s)ds. (3.18) From(3.17) Z 0 εn ∂sft(s)B2(s)ds ≤Y1/2−H H−γ (−εn) H−γ =Y1/2−H H−γ n β(H−γ )/(H−1/2). (3.19)

On the other hand,

|ft(εn)B2(εn)| ≤ Y[(−εn)H−1/2−(t−εn)H−1/2](−εn)1/2−γ

≤ Y(−εn)H−γ

=Y nβ(H−γ )/(H−1/2). (3.20)

Now,(3.19)and(3.20)lead to

J6≤ P sup 0≤t≤T CH " |ft(εn)B2(εn)| + Z 0 εn ∂sft(s)B2(s)ds # >αn 7 ! ≤ P sup 0≤t≤T CHC Y nβ(H−γ )/(H−1/2) >αn 7 !

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= PY >C n˜ κ(logn)5/2,

whereκ = −(1/2−β)−β(H−γ )/(H−1/2). Taking(1/2−H)/(1−2γ ) < β <1/2, then

κ >0, and the proof ends as that ofLemma 3.9.

Lemma 3.13.Let X(3n)be the process given by(2.2). Then for each q>0there isCˆ5>0such

that J7 = P sup 0≤t≤T CH Z 0 1 a ∂sft 1 v 1 v3B3(v)dv − Z 0 1 a − Z s 1 a ∂sft 1 v 1 v3dv ! dX3(n)(s) >Cˆ 5αn 7 ! =o(n−q) as n→ ∞.

Proof. By(3.2)we can apply Fubini’s theorem,

Z 0 1 a − Z s 1 a ∂sft 1 v 1 v3dv ! dX(3n)(s)= Z 0 1 a ∂sft 1 v 1 v3X (n) 3 (v)dv. Consequently(3.2)gives Z 0 1 a ∂sft 1 v 1 v3B3(v)dv− Z 0 1 a − Z s 1 a ∂sft 1 v 1 v3dv ! dX(3n)(s) ≤ sup 1/a≤s≤0 B3(s)−X (n) 3 (s) ! Z 0 1 a ∂s ft 1 s 1 s3 ds ≤ sup 1/a≤s≤0 B3(s)−X (n) 3 (s) ! Z 0 1 a (3/2−H)|H−1/2|t(−s)−H−1/2ds = sup 1/a≤s≤0 B3(s)−X (n) 3 (s) (3/2−H)t −1 a 1/2−H . Hence, J7 ≤ P (3/2−H)CHT −1 a 1/2−H sup 1/a≤s≤0 B3(s)−X (n) 3 (s) > ˆ C5αn 7 ! ≤ P sup 1/a≤s≤0 B3(s)−X (n) 3 (s) >CT ˆ C5n−(1/2−β)(logn)5/2 ! =o(n−q),

which follows from(2.4)takingCˆ5such thatCTCˆ5>C(3).

Proof of Theorem 2.3. From(2.1)and(3.5)we obtain

W(t)=CH ( Z t 0 gt(s)dB(s)+ Z 0 a ft(s)dB(s)+ Z a −∞ ft(s)dB(s) )

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=CH ( Z (t+εn)∨0 0 gt(s)dB1(s)+ Z t (t+εn)∨0 [gt(s)−gt(εn+s)]dB1(s) + Z t (t+εn)∨0 gt(εn+s)dB1(s)+ Z εn a ft(s)dB2(s)+ Z 0 εn ft(s)dB2(s) + ft(a)B2(a)− Z 0 1 a ∂sft 1 v 1 v3B3(v)dv ) ,

which together with(2.10)yields |W(t)− ˆW(n)(t)| ≤CH ( Z (t+εn)∨0 0 gt(s)dB1(s)− Z (t+εn)∨0 0 gt(s)dX(1n)(s) + Z t (t+εn)∨0 [gt(s)−gt(εn+s)]dB1(s) + Z t (t+εn)∨0 gt(εn+s)dB1(s)− Z t (t+εn)∨0 gt(εn+s)dX1(n)(s) + Z εn a ft(s)dB2(s)− Z εn a ft(s)dX2(n)(s) + Z 0 εn ft(s)dB2(s) + ft(a)B2(a)− ft(a)X (n) 2 (a) + Z 0 1 a ∂sft 1 v 1 v3B3(v)dv− Z 0 1 a − Z s 1 a ∂s ft 1 v 1 v3dv ! dX(3n)(s) ) ,

and the result follows fromLemmas 3.7–3.13, similarly as the proof ofTheorem 2.2.

Acknowledgment

J. Garz´on thanks CONACYT for support.

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