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HEREDITARY PROPERTIES

ADNAN AL-BSOUL

Received 11 October 2004 and in revised form 8 September 2005

A topological property isproperly hereditary propertyif whenever every proper subspace has the property, the whole space has the property. In this note, we will study some topo-logical properties that are preserved by proper subspaces; in fact, we will study the fol-lowing topological properties: Baire spaces, second category, sequentially compact, hemi-compact,δ-normal, and spaces having dispersion points. Also, we will solve some open problems raised by Al-Bsoul (2003) and Arenas (1996) and conclude this note by some open problems.

1. Introduction

In 1996, Professor M. L. Puertas suggested the following question which was studied by Arenas in his paper [2]:

()if every proper subspace has the property, the whole space has the property.

Any topological property satisfying the property () is calledproperly hereditary prop-erty. Moreover, if every proper closed (resp., open,,, etc.) subspace has the property, then the whole space has the property, and we call such a propertyproperly closed(resp., open,Fσ,Gδ, etc.)hereditary.

In [2], Arenas studied some topological properties having the property (). In fact, Arenas [2] proved that the topological propertiesTi,i=0, 1, 2, 3, are properly hereditary properties. He also studied countability axioms and metrizability. Nevertheless, for Are-nas, the property () makes sense only for the topological properties that are hereditary to all subsets. On the other hand, as we saw in [1], there are some topological properties which are properly hereditary properties but are not hereditary properties, for instance, paracompactness. Thus, we may ask the converse.

Question 1.1. Is there a topological propertyP which is hereditary but is not properly hereditary?

It is obvious to see that if a topological property is properly hereditary, it is not neces-sary that it is properly open (closed) hereditary. So, it is natural to redefine the following (compare with the definition in [2]).

Copyright©2005 Hindawi Publishing Corporation

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Definition 1.2. A topological property is called strong (resp., closed, open,,Gδ, etc.) hereditary property provided that it is (resp., closed, open,,, etc.) hereditary prop-erty and properly (resp., closed, open,,, etc.) hereditary property.

Hence,Ti is a strong hereditary property fori=0, 1/4, 1/2, 1, 1(1/3), 2, 2(1/2), 3, but T1,T1(1/3),T2,T2(1/2),T3are neither strong open hereditary properties nor strong closed hereditary properties.

In [1], Al-Bsoul studied some topological properties as some nonfamiliar separation axioms beside some strong separation axioms, and also some covering properties.

Reading [1,2], the reader may conclude that all classical topological properties are properly hereditary properties. This is not the case; however, in this note we are going to give two topological properties which are not properly (resp., closed, open) hereditary properties. Moreover, we will positively solve two open problems raised in [1,2]. Also, we will prove that some topological properties, such as sequential compactness, hemicom-pactness, andδ-normality, are properly hereditary properties.

2. Baire spaces andk-spaces

In this section we will positively solve the following open problem raised in [1].

Question 2.1[1]. Are Baire spaces and second category properly hereditary properties?

Theorem2.2. If every proper subspace ofXis a Baire subspace, thenXis a Baire space. Proof. Let {Gn:n∈N} be a countable family of open dense subsets ofX. Pick x0∈ X\(nNGn). If suchx0does not exist, thenn∈NGn=X, and the proof is finished.

LetY=X\{x0}, thenGn\{x0} =Φfor alln∈N. IfGi\{x0}Y=Yfor somei∈N, then there existt∈Y\(Gi\{x0}Y) and an open setVinYsuch thatt∈V⊆Y\(Gi\{x0}Y). So, there exists an open setUinXsuch thatV=U∩Y. Now,U∩Gi=ΦandU=V∪ {x0}, soV∩Gi=Φ, and henceU∩Gi= {x0}, which is a contradiction. ThusGn\{x0}is an open dense set inYfor alln∈N. Therefore, (nNGn) is dense inX.

Corollary2.3. LetXbe aT1-space. If every proper open subspace ofXis a Baire subspace, thenXis a Baire space.

Corollary2.4. Second category is properly hereditary property.

Proof. LetXbe a space such that every proper subspace ofXis a second category, and let

{Gn:n∈N}be a countable family of open dense subsets ofX. Suppose thatn∈NGn= Φ. Pickx0∈X, and letY =X\{x0}, thenGn\{x0}is an open dense subset ofY for all

n∈N. Therefore,n∈NGn=Φ.

Also, we will solve the following open problem fork-spaces positively.

Question 2.5[2]. Is being ak-space a properly (closed) hereditary property?

Recall that a HausdorffspaceXis called ak-spaceif and only if the following condition holds:

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In [2, Example 2.2], we see that every proper closed subspace ofXis ak-subspace, but Xitself is not ak-space. Also, [1, Example 1.1], shows that every proper open subspace of Xis ak-subspace, butXitself is not ak-space. But we have the following theorem.

Theorem2.6. If every proper subspace ofXis ak-subspace, thenXis ak-space.

Proof. LetUbe an open subset inXand letK be any compact subset inX. IfU⊆K or K⊆U, we are done. Assume thatU\K=ΦandK\U=Φ. Fix a pointx0∈U\K, then U∩K=(U\{x0})∩Kis open inK.

Conversely, Assume thatU∩K is open inK for each compact setK inX. IfU=X orU=Φ, we are done. Assume thatU is a nonempty proper subset ofX, so choose y0∈X\U, and letY=X\{y0}, soU∩KY is open inKY for each compact setKY inY,

soUis open inYand hence inX.

Corollary2.7. For Hausdorffspaces, if every proper closed (resp., open) subspace ofXis a k-subspace, thenXis ak-space.

3. More topological properties satisfying()

Several topological properties will be studied in this section. Let us start with some types of compactness.

Theorem3.1. σ-compactness is a properly hereditary property.

Theorem3.2. Sequential compactness is a properly hereditary property.

Proof. Let{xn}be a sequence in X. If|{xn:n∈N}|<ℵ0, then it has a constant sub-sequence. If the valuexn0is repeated infinitely many times, that is, the set{n:xn=xn0}

is infinite, then this sequence has a constant subsequence. Ifx1is repeated only finitely many times, assume thatxn=x1for alln > n0, hence the subsequencexnj=xn0+j has a

convergent subsequence inX\{x1}and hence inX.

Since the following topological property (hemicompact or denumerable at infinity) is not familiar, we give its definition.

Definition 3.3. A HausdorffspaceXis said to be hemicompact or denumerable at infinity if and only if there is a sequenceK1,K2,...of compact subsets ofXsuch that ifKis any compact subset ofX, thenK⊆Knfor somen.

Theorem3.4. If every proper subspace ofXis a hemicompact subspace, thenXis a hemi-compact space.

Proof. Letx=yinX, so there exists an open setV inXsuch thatx /∈V. SinceY=X\V andV are hemicompact, there exist compact subsetsC1,C2,...ofY, such that for every compact subset KY of Y there existsCn0 such thatKY⊆Cn0, and there exist compact

subsetsD1,D2,...ofV, such that for every compact subsetKV ofV there existsDm0such

thatKV⊆Dm0. LetW= {0} ∪N, and define a sequence of compact subsetsKm,nofXas

follows:Km,n=Cm∪Dn,Km,0=Cm, andK0,n=Dnfor all (m,n)∈W×W\{(0, 0)}. Now, if K is any compact subset ofX, then K∩Y is compact inY and K∩V is compact inV. Thus, there existCm0 andDn0 such thatK∩Y⊂Cm0 andK∩V⊂Dn0,

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It is easy to construct examples to show that hemicompactness is neither a properly open hereditary property nor a properly closed hereditary property. Recall that a spaceX is said to beδ-normalif wheneverAandBare disjoint closed subsets ofX, there exist two disjointGδ-setsHandKsuch thatA⊆HandB⊆K.

Example 1.1 in [1], shows that if every closed proper subspace ofXis aδ-normalT1 subspace, thenXneed not be aδ-normal space. Moreover, [2, Example 2.2] shows that if every open proper subspace ofX is aδ-normalT1-subspace, thenX need not be a δ-normal space. Fortunately, we have the following result.

Theorem3.5. If every proper subspace ofXis aδ-normalT1-subspace, thenXis aδ-normal space.

Proof. LetAandBbe two nonempty disjoint closed subsets ofX. The caseX=A∪B is evident. Let y0∈X\(A∪B), and letY =X\{y0}, so there exist two disjoint-sets H0,K0inY such thatA⊆H0andB⊆K0, thusH0=∞i=1HiandK0=

i=1Ki, whereHi andKiare open inYfor alli∈N. Hence, there exist open setsUiandViinX, such that Hi=Ui∩Y andKi=Vi∩Y for alli∈N. Thus,U=∞i=1Ui andV=

i=1Viare -sets. IfU∩V=Φ, the proof is completed, otherwise,U∩V= {y0}. Takez0∈X\(A∪ B∪ {y0}), and letZ=X\{z0}, so there exist two disjoint-setsH0,K0inZsuch that A⊆H0andBK0, thusH0=

i=1HiandK0=

i=1Ki, whereHiandKiare open in Zfor alli∈N. Hence, there exist open setsUiandViinX, such thatHi=Ui∩Zand Ki=ViZ for alliN. LetLi=UiUi and Mi=ViVi, and define the required -setsL=∞i=1LiandM=

i=1Mi.

It is easy to prove the following.

Theorem3.6. Pseudocompactness is a properly hereditary property.

Recall that a spaceXisextremely disconnectedif and only if the closure of every open set is open. This topological property is not a properly (resp., closed, open) hereditary property, as we will see in the next example.

Example 3.7. Let X= {u,x,y}and letτ= {{u},{y},{u,y},Φ,X}, hence every proper subspace ofXis an extremely disconnected subspace, butXitself is not.

Theorem3.8. The topological property “extremely disconnected” is a properly hereditary property in the class ofT1-spaces.

Remark 3.9. If every proper open subspace of X is an extremely disconnected T1 -subspace, thenXis not necessarily an extremely disconnected space.

4. Open problems

In this section, we will study a special kind of topological properties, namely,having a dispersion point. For this, let us state its definition. Recall that a connected spaceXis said to have adispersion point pif and only ifX\{p}is totally disconnected. Thus, no space Xof cardinality greater than 2 has the property that every subspace ofXhas a dispersion point because, ifx,y∈X\{p}, where pis the dispersion point ofX, then the subspace

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Question 4.1. Is there a connected space for which every proper open (closed) subspace ofXhas a dispersion point?

Indeed, take [2, Example 2.2] under consideration for the case of proper open sub-spaces, and take [1, Example 1.1] for the case of proper closed subspaces. Thus, one may ask the following.

Question 4.2. Is the property of having a dispersion point a properly open (closed) hered-itary property?

The next example is a modification of [1, Example 1.1], which shows that the answer ofQuestion 4.2is negative in general.

Example 4.3. LetX=Z∪ {π,2}, and topologizeXas

τ=A∪ {π}:A⊆Z∪ {X}. (4.1)

So,π is a dispersion point of every nonempty proper open subspace of X, and 2 is a dispersion point of every nonempty proper closed subspace ofX. ButXitself has no dispersion points.

Note that the space inExample 4.3is not aT1-space, but it is easy to see that there is noT1-space for which every proper closed (open) subspace has a dispersion point. A topological spaceXis calledT1/2if and only if every singleton is open or closed. Also, a topological spaceXis calledT1/4if and only if for every finite subsetFofXand for every y∈X\F, there exists a setAcontainingF and not containingywhich is either open or closed inX. Hence we can restate the previous questions as follows.

Question 4.4. Is there aT1/4(T1/2)-space for which every proper open (closed) subspace ofXhas a dispersion point? If so, doesXhave a dispersion point?

Questions1.1and4.4are still open.

For the following two questions, the reader may consult [3].

Question 4.5. Is maximal compactness (minimal Hausdorffness, realcompactness, abso-lutely countably compactness) a properly (resp., closed, open,,, etc.) hereditary property?

Question 4.6. Is H-closedness a properly (resp., closed, open, , , etc.) hereditary property?

References

[1] A. Al-Bsoul,Some separation axioms and covering properties preserved by proper subspaces, Questions Answers Gen. Topology21(2003), no. 2, 171–175.

[2] F. G. Arenas,Topological properties preserved by proper subspaces, Questions Answers Gen. Topology14(1996), no. 1, 53–57.

[3] S. Willard,General Topology, Addison-Wesley, Massachusetts, 1970.

Adnan Al-Bsoul: Department of Mathematics and Physics, Faculty of Arts and Science, Qatar University, P.O. Box 2713, Doha, Qatar

References

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