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Research Article

New Difference Sequence Spaces Defined by

Musielak-Orlicz Function

M. Mursaleen,

1

Sunil K. Sharma,

2

S. A. Mohiuddine,

3

and A. K

JlJçman

4

1Department of Mathematics, Aligarh Muslim University, Aligarh 202002, India

2Department of Mathematics, Model Institute of Engineering & Technology, Kot Bhalwal, Jammu and Kashmir 181122, India 3Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia 4Department of Mathematics, University Putra Malaysia (UPM), 43400 Serdang, Selangor, Malaysia

Correspondence should be addressed to A. Kılıc¸man; [email protected]

Received 17 March 2014; Revised 11 July 2014; Accepted 11 July 2014; Published 22 July 2014 Academic Editor: Feyzi Bas¸ar

Copyright © 2014 M. Mursaleen et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We introduce new sequence spaces by using Musielak-Orlicz function and a generalized𝐵𝜇-difference operator on𝑛-normed space. Some topological properties and inclusion relations are also examined.

1. Introduction and Preliminaries

The notion of the difference sequence space was introduced by Kızmaz [1]. It was further generalized by Et and C¸ olak [2] as follows:𝑍(Δ𝜇) = {𝑥 = (𝑥𝑘) ∈ 𝜔 : (Δ𝜇𝑥𝑘) ∈ 𝑧} for 𝑧 = ℓ, 𝑐, and𝑐0, where𝜇 is a nonnegative integer and

Δ𝜇𝑥𝑘= Δ𝜇−1𝑥𝑘− Δ𝜇−1𝑥𝑘+1, Δ0𝑥𝑘= 𝑥𝑘 ∀𝑘 ∈ N (1) or equivalent to the following binomial representation:

Δ𝜇𝑥𝑘=∑𝜇

V=0

(−1)V(𝜇V)𝑥𝑘+V. (2) These sequence spaces were generalized by Et and Basarir [3] taking𝑧 = ℓ(𝑝), 𝑐(𝑝), and 𝑐0(𝑝).

Dutta [4] introduced the following difference sequence spaces using a new difference operator:

𝑍 (Δ(𝜂)) = {𝑥 = (𝑥𝑘) ∈ 𝜔 : Δ(𝜂)𝑥 ∈ 𝑧} for 𝑧 = ℓ, 𝑐, 𝑐0, (3) whereΔ(𝜂)𝑥 = (Δ(𝜂)𝑥𝑘) = (𝑥𝑘− 𝑥𝑘−𝜂) for all 𝑘, 𝜂 ∈ N.

In [5], Dutta introduced the sequence spaces 𝑐(‖⋅, ⋅‖, Δ𝜇(𝜂), 𝑝), 𝑐0(‖⋅, ⋅‖, Δ𝜇(𝜂), 𝑝), ℓ(‖⋅, ⋅‖, Δ𝜇(𝜂), 𝑝), 𝑚(‖⋅, ⋅‖, Δ𝜇(𝜂), 𝑝), and 𝑚0(‖⋅, ⋅‖, Δ𝜇(𝜂), 𝑝), where 𝜂, 𝜇 ∈ N and

Δ𝜇(𝜂)𝑥𝑘 = (Δ𝜇(𝜂)𝑥𝑘) = (Δ𝜇−1(𝜂)𝑥𝑘 − Δ𝜇−1(𝜂)𝑥𝑘−𝜂) and Δ0

(𝜂)𝑥𝑘 = 𝑥𝑘

for all𝑘, 𝜂 ∈ N, which is equivalent to the following binomial representation:

Δ𝜇(𝜂)𝑥𝑘 =∑𝜇

V=0(−1) V

(𝜇V)𝑥𝑘−𝜂V. (4)

The difference sequence spaces have been studied by authors [6–14] and references therein. Bas¸ar and Altay [15] introduced the generalized difference matrix𝐵 = (𝑏𝑚𝑘) for all 𝑘, 𝑚 ∈ N, which is a generalization ofΔ(1)-difference operator by

𝑏𝑚𝑘={{{{ { 𝑟, 𝑘 = 𝑚 𝑠, 𝑘 = 𝑚 − 1 0, (𝑘 > 𝑚) or (0 ≤ 𝑘 < 𝑚 − 1) . (5)

Bas¸arir and Kayikc¸i [16] defined the matrix𝐵𝜇(𝑏𝑚𝑘𝜇 ) which reduced the difference matrixΔ𝜇(1) in case𝑟 = 1, 𝑠 = −1. The generalized𝐵𝜇-difference operator is equivalent to the following binomial representation:

𝐵𝜇𝑥 = 𝐵𝜇(𝑥 𝑘) = 𝜇 ∑ V=0(𝜇V)𝑟 𝜇−V𝑠V𝑥 𝑘−V. (6)

Volume 2014, Article ID 691632, 9 pages http://dx.doi.org/10.1155/2014/691632

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Let ∧ = (∧𝑘) be a sequence of nonzero scalars. Then, for a sequence space 𝐸, the multiplier sequence space 𝐸, associated with the multiplier sequence∧, is defined as

𝐸= {𝑥 = (𝑥𝑘) ∈ 𝜔 : (∧𝑘𝑥𝑘) ∈ 𝐸} . (7) An Orlicz function𝑀 is a function, 𝑀 : [0, ∞) → [0, ∞), which is continuous, nondecreasing, and convex with𝑀(0) = 0, 𝑀(𝑥) > 0 for 𝑥 > 0, and 𝑀(𝑥) → ∞ as 𝑥 → ∞.

We say that an Orlicz function 𝑀 satsfies the Δ2 -condition if there exists𝐾 > 2 and 𝑥0≥ 0 such that 𝑀(2𝑥) ≤ 𝐾𝑀(𝑥) for all 𝑥 ≥ 𝑥0. TheΔ2-condition is equivalent to 𝑀(𝐿𝑥) ≤ 𝐾𝐿𝑀(𝑥) for all 𝑥 > 𝑥0> 0 and for 𝐿, 𝐾 > 1.

Lindenstrauss and Tzafriri [17] used the idea of Orlicz function to define the following sequence space:

𝑀= {𝑥 ∈ 𝜔 :∑∞

𝑘=1

𝑀 (󵄨󵄨󵄨󵄨𝑥𝜌𝑘󵄨󵄨󵄨󵄨) < ∞} (8) which is called an Orlicz sequence space. The spaceℓ𝑀is a Banach space with the norm

‖𝑥‖ = inf {𝜌 > 0 :∑∞

𝑘=1

𝑀 (󵄨󵄨󵄨󵄨𝑥𝜌𝑘󵄨󵄨󵄨󵄨) ≤ 1} . (9) It is shown in [17] that every Orlicz sequence space ℓ𝑀 contains a subspace isomorphic toℓ𝑝(𝑝 ≥ 1).

A sequence M = (𝑀𝑘) of Orlicz function is called a Musielak-Orlicz function; see [18,19]. A sequenceN = (𝑁𝑘) defined by

𝑁𝑘(V) = sup {|V| 𝑢 − 𝑀𝑘(𝑢) : 𝑢 ≥ 0} , 𝑘 = 1, 2, . . . , (10)

is called the complimentary function of a Musielak-Orlicz function M. For a given Musielak-Orlicz function M, the Musielak-Orlicz sequence space𝑡Mand its subspaceℎMare defined as follows:

𝑡M = {𝑥 ∈ 𝜔 : 𝐼𝑀(𝑐𝑥) < ∞ for some 𝑐 > 0} , ℎM= {𝑥 ∈ 𝜔 : 𝐼𝑀(𝑐𝑥) < ∞ ∀𝑐 > 0} , (11) where𝐼Mis a convex modular defined by

𝐼M(𝑥) =∑∞

𝑘=1

𝑀𝑘(𝑥𝑘) , 𝑥 = (𝑥𝑘) ∈ 𝑡𝑀. (12) We consider𝑡Mequipped with the Luxemburg norm

‖𝑥‖ = inf {𝑘 > 0 : 𝐼𝑀(𝑥𝑘) ≤ 1} (13)

or equipped with the Orlicz norm

‖𝑥‖0= inf {1𝑘(1 + 𝐼𝑀(𝑘𝑥)) : 𝑘 > 0} . (14)

By a lacunary sequence𝜃 = (𝑖𝑟), 𝑟 = 0, 1, 2, . . ., where 𝑖0 = 0, we will mean an increasing sequence of nonnegative integers ℎ𝑟 = (𝑖𝑟− 𝑟𝑟−1) → ∞ (𝑟 → ∞). The intervals determined

by𝜃 are denoted by 𝐼𝑟 = (𝑖𝑟−1, 𝑖𝑟] and the ratio 𝑖𝑟/𝑖𝑟−1 will

be denoted by𝑞𝑟. The space of lacunary strongly convergent sequences𝑁𝜃was defined by Freedman et al. [20] as follows:

𝑁𝜃 ={{ { 𝑥 = (𝑥𝑘) : lim𝑟 → ∞1 ℎ𝑟𝑘∈𝐼∑ 𝑟 󵄨󵄨󵄨󵄨𝑥𝑘− 𝐿󵄨󵄨󵄨󵄨 = 0, for some 𝐿 } } } . (15) The concept of 2-normed spaces was initially developed by G¨ahler [21] in the mid of 1960’s, while that of 𝑛-normed spaces one can see in Misiak [22]. Since then, many others have studied this concept and obtained various results; see Gunawan [23,24] and Gunawan and Mashadi [25]. For more details about sequence spaces see [26–33] and references therein. Let𝑛 ∈ N and 𝑋 be linear space over the field K, whereK is the field of real or complex numbers of dimension 𝑑, where 𝑑 ≥ 𝑛 ≥ 2.

A real valued function ‖⋅, . . . , ⋅‖ on 𝑋𝑛 satisfying the following four conditions:

(1)‖(𝑥1, 𝑥2, . . . , 𝑥𝑛)‖ = 0 if and only if 𝑥1, 𝑥2, 𝑥3, . . . ,𝑥𝑛 are linearly dependent in𝑋;

(2)‖(𝑥1, 𝑥2, . . . , 𝑥𝑛)‖ is invariant under permutation; (3)‖(𝛼𝑥1, 𝑥2, . . . , 𝑥𝑛)‖ = |𝛼|‖(𝑥1, 𝑥2, . . . , 𝑥𝑛)‖ for any 𝛼 ∈

K;

(4)‖(𝑥 + 𝑥󸀠, 𝑥2, . . . , 𝑥𝑛)‖ ≤ ‖(𝑥, 𝑥2, . . . , 𝑥𝑛)‖ + ‖(𝑥󸀠, 𝑥

2, . . . , 𝑥𝑛)‖

is called an 𝑛-norm on 𝑋 and the pair (𝑋, ‖⋅, . . . , ⋅‖) is called an𝑛-normed space over the field K. For example, we may take 𝑋 = R𝑛 being equipped with the Euclidean 𝑛-norm‖(𝑥1, 𝑥2, . . . , 𝑥𝑛)‖𝐸 = the volume of the 𝑛-dimensional parallelepiped spanned by the vectors 𝑥1, 𝑥2, . . . , 𝑥𝑛 which may be given explicitly by the formula

󵄩󵄩󵄩󵄩(𝑥1, 𝑥2, . . . , 𝑥𝑛)󵄩󵄩󵄩󵄩𝐸= 󵄨󵄨󵄨󵄨󵄨det(𝑥𝑖𝑗)󵄨󵄨󵄨󵄨󵄨, (16)

where𝑥𝑖= (𝑥1, 𝑥2, 𝑥3, . . . , 𝑥𝑛) ∈ R𝑛for each𝑖 = 1, 2, 3, . . . , 𝑛 and‖ ⋅ ‖𝐸denotes the Euclidean norm. Let(𝑋, ‖⋅, . . . , ⋅‖) be an 𝑛-normed space of dimension 𝑑 ≥ 𝑛 ≥ 2 and {𝑎1, 𝑎2, . . . , 𝑎𝑛} linearly independent set in𝑋. Then the following function ‖(⋅, . . . , ⋅)‖on𝑋𝑛−1defined by

󵄩󵄩󵄩󵄩(𝑥1, 𝑥2, . . . , 𝑥𝑛)󵄩󵄩󵄩󵄩∞

= max {󵄩󵄩󵄩󵄩(𝑥1, 𝑥2, . . . , 𝑥𝑛−1, 𝑎𝑖)󵄩󵄩󵄩󵄩 : 𝑖 = 1, 2, . . . , 𝑛}

(17) defines an(𝑛−1) norm on 𝑋 with respect to {(𝑎1, 𝑎2, . . . , 𝑎𝑛)}. A sequence (𝑥𝑘) in an 𝑛-normed space (𝑋, ‖⋅, . . . , ⋅‖) is said to converge to some𝐿 ∈ 𝑋 if

lim

𝑘 → ∞󵄩󵄩󵄩󵄩(𝑥𝑘− 𝐿, 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩 = 0,

for every𝑧1, . . . , 𝑧𝑛−1∈ 𝑋.

(18) A sequence(𝑥𝑘) in a normed space (𝑋, ‖⋅, . . . , ⋅‖) is said to be Cauchy if lim 𝑘 → ∞ 𝑝 → ∞󵄩󵄩󵄩󵄩󵄩(𝑥𝑘 − 𝑥𝑝, 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩 = 0, for every𝑧1, . . . , 𝑧𝑛−1∈ 𝑋. (19)

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If every Cauchy sequence in𝑋 converges to some 𝐿 ∈ 𝑋 then𝑋 is said to be complete with respect to the 𝑛-norm. Any complete𝑛-normed space is said to be 𝑛-Banach space.

Let(𝑋, ‖⋅, . . . , ⋅‖) be an 𝑛-normed space and let 𝑠(𝜔 − 𝑥) denote the space of𝑋-valued sequences. Let 𝑝 = (𝑝𝑘) be any bounded sequence of positive real numbers andM = (𝑀𝑘) a Musielak-Orlicz function. We define the following sequence spaces in this paper:

𝑤0𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵∧𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 = 0, 𝜌 > 0}} } , 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = 0, for some𝐿, 𝜌 > 0}} } , 𝑤𝜃 (M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 < ∞, 𝜌 > 0}} } ; (20) whenM(𝑥) = 𝑥, we get 𝑤0𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = 0, 𝜌 > 0}} } , 𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = 0, for some𝐿, 𝜌 > 0}} } , 𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑠 (𝑤 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 < ∞, 𝜌 > 0}} } ; (21) when𝑝𝑘= 1, for all 𝑘, we get

𝑤𝜃0(M, 𝐵𝜇, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑤 (𝑠 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) = 0, 𝜌 > 0 } } } , 𝑤𝜃(M, 𝐵𝜇, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑤 (𝑠 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) = 0, for some𝐿, 𝜌 > 0}} } , 𝑤𝜃(M, 𝐵𝜇, ‖⋅, . . . , ⋅‖) ={{ { 𝑥 = (𝑥𝑘) ∈ 𝑤 (𝑠 − 𝑥) : lim𝑟 → ∞1 𝑟 × ∑ 𝑘∈𝐼𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) < ∞, 𝜌 > 0 } } } . (22)

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The following inequality will be used throughout the paper. If 0 ≤ 𝑝𝑘≤ sup 𝑝𝑘= 𝐻, 𝑘 = max(1, 2𝐻−1), then

󵄨󵄨󵄨󵄨𝑎𝑘+ 𝑏𝑘󵄨󵄨󵄨󵄨𝑝𝑘 ≤ 𝐾 {󵄨󵄨󵄨󵄨𝑎𝑘|𝑝𝑘+󵄨󵄨󵄨󵄨 𝑏𝑘|𝑝𝑘} (23)

for all𝑘 and 𝑎𝑘, 𝑏𝑘∈ C. Also |𝑎|𝑝𝑘 ≤ max(1, |𝑎|𝐻) for all 𝑎 ∈ C.

2. Main Results

Theorem 1. Let M = (𝑀𝑘) be a Musielak-Orlicz function and

𝑝 = (𝑝𝑘) a bounded sequence of positive real numbers; the

spaces 𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖), 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖), and

𝑤𝜃

∞(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) are linear over the field of complex

numbersC.

Proof. Let𝑥 = (𝑥𝑘), 𝑦 = (𝑦𝑘) ∈ 𝑤0𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖), and

𝛼, 𝛽 ∈ C. Then there exist positive real numbers 𝜌1 and𝜌2 such that lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = 0, lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 = 0. (24)

Define𝜌3= max(2|𝛼|𝜌1, 2|𝛽|𝜌2). Since ‖⋅, . . . , ⋅‖ is an 𝑛-norm on𝑋 and 𝑀󸀠𝑘𝑠 are nondecreasing and convex functions so by using inequality (23) we have

lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇(𝛼𝑥𝑘+ 𝛽𝑦𝑘) 𝜌3 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ≤ lim𝑟 → ∞1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝛼𝑥𝑘 𝜌3 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 +󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝛽𝑦𝑘 𝜌3 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ≤ 𝐾 lim𝑟 → ∞1 ℎ𝑟𝑘∈𝐼∑ 𝑟 1 2𝑝𝑘𝑀𝑘( 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 + 𝐾 lim𝑟 → ∞1 𝑟𝑘∈𝐼∑𝑟 1 2𝑝𝑘𝑀𝑘( 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 = 0. (25) Thus, we have 𝛼𝑥 + 𝛽𝑦 ∈ 𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Hence 𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) is a linear space. Similarly, we can prove that 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) and 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) are linear spaces. This completes the proof of the theorem.

Theorem 2. Let M = (𝑀𝑘) be a Musielak-Orlicz function

and𝑝 = (𝑝𝑘) a bounded sequence of positive real numbers;

the space𝑤0𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) is a topological linear space

paranormed by 𝑔 (𝑥) = inf{{ { 𝜌𝑝𝑟/𝑀: (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } , (26)

where𝑀 = max(1, sup𝑘𝑝𝑘 < ∞).

Proof. Clearly 𝑔(𝑥) ≥ 0 for 𝑥 = (𝑥𝑘) ∈ 𝑤𝜃0(M, 𝐵𝜇,

𝑝, ‖⋅, . . . , ⋅‖). Since 𝑀𝑘(0) = 0, we get 𝑔(0) = 0. Again, if 𝑔(𝑥) = 0, then 𝑔 (𝑥) = inf{{ { 𝜌𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } = 0. (27)

This implies that, for a given𝜀 > 0, there exist some 𝜌𝜀 (0 < 𝜌𝜀< 𝜀) such that (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌𝜀 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1. (28) Thus (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜀 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌𝜀 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1 (29)

for each𝑟, and suppose that 𝑥𝑘 ̸= 0 for each 𝑘 ∈ N. This implies that𝐵𝜇𝑥𝑘 ̸= 0 for each 𝑘 ∈ N. Let 𝜀 → 0, then

((󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌𝜀 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 󳨀→ ∞; (30)

(5)

which is a contradiction. Therefore,𝐵𝜇𝑥𝑘 = 0 for each 𝑘 and thus𝑥𝑘= 0 for each 𝑘 ∈ N. Let 𝜌1> 0 and 𝜌2> 0 be such that

(1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1, (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1 for each 𝑟. (31)

Let𝜌 = 𝜌1+𝜌2; then by using Minkowski’s inequality, we have

(1 ℎ𝑟𝑘∈𝐼𝑟𝑀𝑘( 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇(𝑥𝑘+ 𝑦𝑘) 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘+ 𝐵𝜇𝑦𝑘 𝜌1+ 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘 × (( 𝜌1 𝜌1+ 𝜌2)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 + ( 𝜌2 𝜌1+ 𝜌2) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ (𝜌 𝜌1 1+ 𝜌2) × (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 + (𝜌 𝜌2 1+ 𝜌2) × (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1. (32)

Since𝜌󸀠𝑠 are nonnegative, we have 𝑔 (𝑥 + 𝑦) = inf{{ { 𝜌𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } ≤ inf{{ { 𝜌1𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } + inf{{ { 𝜌2𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑦𝑘 𝜌2 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } . (33) Therefore,𝑔(𝑥 + 𝑦) ≤ 𝑔(𝑥) + 𝑔(𝑦).

Finally, we prove that the scalar multiplication is contin-uous. Let] be any complex number. By definition,

𝑔 (]𝑥) = inf{{ { 𝜌𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( ]𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } . (34)

(6)

Then 𝑔 (]𝑥) = inf{{ { (|]| 𝑡)𝑝𝑟/𝑀: (1 ℎ𝑟𝑘∈𝐼∑𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝑡 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } , (35) where𝑡 = 𝜌/|]|. Since |]|𝑝𝑟 ≤ max(1, |]| sup 𝑝

𝑘), we have

𝑔 (]𝑥) = max (1, |]| sup 𝑝𝑘) inf

×{{ { (𝑡)𝑝𝑟/𝑀: (1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘 × (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝑡 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ) 1/𝑀 ≤ 1}} } . (36) So, the fact that scalar multiplication is continuous follows from the above inequality. This completes the proof of theorem.

Theorem 3. Let M = (𝑀𝑘) be a Musielak-Orlicz

func-tion. If sup𝑘(𝑀𝑘(𝑥))𝑝𝑘 < ∞ for all fixed 𝑥 > 0, then

𝑤𝜃(M, 𝐵𝜇

∧, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤∞𝜃 (M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖).

Proof. Let𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Then there

exists some positive number𝜌1such that lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼𝑟𝑀𝑘( 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = 0. (37) Define𝜌 = 2𝜌1. Since𝑀𝑘is nondecreasing and convex and by using inequality (23), we have

lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 = lim𝑟 → ∞1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 + 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ≤ 𝐾{{ { lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘21𝑝 𝑘( 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘− 𝐿 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 + lim𝑟 → ∞1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘 1 2𝑝𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩( 𝐿 𝜌1, 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘} } } < 𝐾{{ { lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌1 , 𝑧1, . . . , 𝑧𝑛−1) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 + lim𝑟 → ∞1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩(𝜌𝐿 1, 𝑧1, . . . , 𝑧𝑛−1) 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩)𝑝𝑘}} } . (38) Hence𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). This completes the proof of the theorem.

Theorem 4. Let M = (𝑀𝑘) be a Musielak-Orlicz function and

0 < ℎ = inf 𝑝𝑘. Then 𝑤𝜃 (M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃0(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) (39) if and only if lim 𝑟 → ∞ 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(𝑡)𝑝𝑘 = ∞, 𝑓𝑜𝑟 𝑠𝑜𝑚𝑒 𝑡 > 0. (40) Proof. Let𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖).

Suppose (40) does not hold. Therefore there are a subinterval 𝐼𝑟(𝑚) of the set of intervals𝐼𝑟 and a number𝑛0, where𝑛0 = ‖(𝐵𝜇𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1)‖ for all 𝑘, such that

1 ℎ𝑟(𝑚)𝑘∈𝐼

𝑟(𝑚)

𝑀(𝑛0)𝑝𝑘≤ 𝑁 < ∞, 𝑚 = 1, 2, 3, . . . .

(41) Let us define𝑥 = (𝑥𝑘) as follows:

𝐵𝜇𝑥𝑘 = {𝜌𝑛0, 𝑘 ∈ 𝐼𝑟(𝑚)

0, 𝑘 ∉ 𝐼𝑟(𝑚). (42) Thus by (41),𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). But 𝑥 = (𝑥𝑘) ∉ 𝑤𝜃

0(M, 𝐵∧𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Hence (40) must hold.

Conversely, suppose that (40) holds and let𝑥 = (𝑥𝑘) ∈ 𝑤𝜃 ∞(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Then, 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ≤ 𝑁 < ∞. (43) Suppose that𝑥 = (𝑥𝑘) ∉ 𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Then for some number𝜀, 1 > 𝜀 > 0, there is a number 𝑁0such that, for a subinterval𝐼𝑟(𝑚)of the set of intervals𝐼𝑟,

󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩(

𝐵𝜇𝑥𝑘

(7)

We have 𝑀𝑘(‖(𝐵𝜇𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1)‖) ≥ 𝑀(𝜀)𝑝𝑘, which

contradicts (40) by using (43). Hence we get

𝑤𝜃 (M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤0𝜃(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) . (45)

This completes the proof.

Theorem 5. Let 0 < ℎ = inf 𝑝𝑘 ≤ sup 𝑝𝑘 = 𝐻 < ∞. For

any Musielak-Orlicz functionM = (𝑀𝑘) which satisfies Δ2

-condition, one has

(i)𝑤𝜃0(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤0𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) (ii)𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) (iii)𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖).

Proof. (i) Let𝑥 = (𝑥𝑘) ∈ 𝑤0𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Then, we have

1 ℎ𝑟𝑘∈𝐼∑ 𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 󳨀→ 0 as 𝑟 󳨀→ ∞. (46) Let𝜀 > 0, and choose 𝛿 with 0 < 𝛿 < 1 such that 𝑀𝑘< 𝜀 for 0 ≤ 𝑡 ≤ 𝛿. We can write 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 = 1 𝑟 𝑘∈𝐼∑𝑟 ‖(𝐵𝜇 ∧𝑥𝑘/𝜌,𝑧1,...,𝑧𝑛−1)‖≤𝛿 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵∧𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 +1 𝑟 𝑘∈𝐼∑𝑟 ‖(𝐵𝜇∧𝑥𝑘/𝜌,𝑧1,...,𝑧𝑛−1)‖>𝛿 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 . (47) For the first summation above, we can write

1 ℎ𝑟 𝑘∈𝐼∑ 𝑟 ‖(𝐵𝜇∧𝑥𝑘/𝜌,𝑧1,...,𝑧𝑛−1)‖≤𝛿 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 < max (𝜀, 𝜀ℎ) . (48)

By using continuity of𝑀𝑘, for the second summation we can write 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩< 1 + (󵄩󵄩󵄩󵄩(𝐵𝜇∧𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩) 𝛿 . (49)

Since each𝑀𝑘is nondecreasing and convex and satisfiesΔ2 -condition, it follows that

1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ≤ max (𝜀, 𝜀ℎ) + max {1, [2𝑀𝑘(󵄩󵄩󵄩󵄩(𝐵𝜇∧𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩) 𝛿 ] ℎ } ×1 𝑟𝑘∈𝐼∑𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 . (50)

Taking limit as𝜀 → 0 and 𝑟 → ∞, it follows that 𝑥 = (𝑥𝑘) ∈ 𝑤𝜃

0(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Hence 𝑤𝜃0(𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) ⊂

𝑤𝜃

0(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Similarly, we can prove (ii) and (iii).

This completes the proof of the theorem.

Theorem 6. Let M = (𝑀𝑘) be a Musielak-Orlicz function.

Then the following statements are equivalent:

(i)𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖); (ii)𝑤𝜃0(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃 (M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖); (iii) sup𝑟(1/ℎ𝑟) ∑𝑘∈𝐼𝑟𝑀𝑘(𝑡)𝑝𝑘 < ∞ for all 𝑡 > 0, where 𝑡 =

‖𝐵𝜇𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1‖.

Proof. (i)⇒ (ii) Suppose (i) holds. In order to prove (ii) we

have to show that

𝑤𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤∞𝜃 (M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) . (51)

Let𝑥 = (𝑥𝑘) ∈ 𝑤0𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). Then for a given 𝜀 > 0 there exists𝑠 > 𝑠𝜀such that

1 ℎ𝑟𝑘∈𝐼∑ 𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 < 𝜀. (52) Hence there exists𝐾 > 0 such that

sup 𝑟 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 (󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 < 𝐾. (53) This shows that𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖).

(ii)⇒ (iii) Suppose (ii) holds and (iii) fails to hold. Then for some𝑡 > 0, sup 𝑟 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(𝜀)𝑝𝑘 = ∞, (54) and, therefore, we can find a subinterval𝐼𝑟(𝑚) of the set of intervals𝐼𝑟such that

1 ℎ𝑟(𝑚)𝑘∈𝐼∑ 𝑟(𝑚) 𝑀𝑘(1 𝑚) 𝑝𝑘 ≥ 𝑚, 𝑚 = 1, 2, 3, . . . . (55)

(8)

Let us define𝑥 = (𝑥𝑘) as follows: 𝐵𝜇𝑥𝑘={{ { 𝜌 𝑚, 𝑘 ∈ 𝐼𝑟(𝑚) 0, 𝑘 ∉ 𝐼𝑟(𝑚). (56) Thus 𝑥 = (𝑥𝑘) ∈ 𝑤𝜃0(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). But by (55), 𝑥 = (𝑥𝑘) ∉ 𝑤𝜃∞(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) which contradicts (ii). Hence

(iii) must hold.

(iii)⇒ (i) Let (iii) hold. Suppose that 𝑥 = (𝑥𝑘) ∉ 𝑤𝜃(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Then for 𝑥 = (𝑥𝑘) ∈ 𝑤∞𝜃 (𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). sup 𝑟 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 = ∞. (57) Let𝑡 = ‖𝐵𝜇𝑥𝑘/𝜌, 𝑧1, . . . , 𝑧𝑛−1‖ for each 𝑘, and then by (57) sup𝑟(1/ℎ𝑟) ∑𝑘∈𝐼𝑟𝑀𝑘(𝑡)𝑝𝑘 = ∞, which contradicts (iii). Hence

(i) must hold. This completes the proof of the theorem.

Theorem 7. Let M = (𝑀𝑘) be a Musielak-Orlicz function.

Then the following statements are equivalent:

(i)𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤0𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖); (ii)𝑤𝜃0(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) ⊂ 𝑤𝜃 (𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖); (iii) inf𝑟(1/ℎ𝑟) ∑𝑘∈𝐼

𝑟𝑀𝑘(𝑡)

𝑝𝑘 > 0 for all 𝑡 > 0.

Proof. (i)⇒ (ii) is obvious

(ii)⇒ (iii) Let (ii) hold and let (iii) fail to hold. Then inf𝑟 1

𝑟𝑘∈𝐼

𝑟

𝑀𝑘(𝑡)𝑝𝑘= 0 for some 𝑡 > 0, (58) and we can find a subinterval𝐼𝑟(𝑚) of the set of intervals𝐼𝑟 such that 1 ℎ𝑟(𝑚)𝑘∈𝐼∑ 𝑟(𝑚) 𝑀𝑘(𝑚)𝑝𝑘 < 1 𝑚, 𝑚 = 1, 2, 3, . . . . (59) Let us define𝑥 = (𝑥𝑘) as follows:

𝐵𝜇𝑥𝑘= {𝜌𝑚, 𝑘 ∈ 𝐼𝑟(𝑚)

0, 𝑘 ∉ 𝐼𝑟(𝑚). (60) Thus by (iii),𝑥 = (𝑥𝑘) ∈ 𝑤0𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖). But 𝑥 = (𝑥𝑘) ∉ 𝑤𝜃

∞(𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) which contradict (ii). Hence (iii)

must hold.

(iii) ⇒ (i) Let (iii) hold. Suppose that 𝑥 = (𝑥𝑘) ∈ 𝑤𝜃 0(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Therefore, 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 󳨀→ 0 as 𝑟 󳨀→ ∞. (61) Again suppose 𝑥 = (𝑥𝑘) ∉ 𝑤0𝜃(𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖) for some number𝜀 > 0 and a subinterval 𝐼𝑟(𝑚) of the set of intervals 𝐼𝑟, we have 󵄩󵄩󵄩󵄩 󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩≥ 𝜀 ∀𝑘. (62)

Then, from properties of the Orlicz function, we can write 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) 𝑝𝑘 ≥ 𝑀𝑘(𝜀)𝑝𝑘. (63)

Consequently, by (61), we have lim𝑟 → ∞(1/ℎ𝑟)∑𝑘∈𝐼𝑟𝑀𝑘 (𝜀)𝑝𝑘 = 0, which contradicts (iii). Hence (i) must hold. This

completes the proof of the theorem.

Theorem 8. (i) If 0 < inf 𝑝𝑘 ≤ 𝑝𝑘 ≤ 1 for all 𝑘, then

𝑤𝜃(M, 𝐵𝜇

∧, ‖⋅, . . . , ⋅‖) ⊆ 𝑤𝜃(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖).

(ii) If 1 ≤ 𝑝𝑘 ≤ sup 𝑝𝑘 = 𝐻 < ∞, then

𝑤𝜃(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖) ⊆ 𝑤𝜃(M, 𝐵𝜇∧, ‖⋅, . . . , ⋅‖).

Proof. (i) Let𝑥 ∈ 𝑤𝜃(M, 𝐵𝜇, ‖⋅, . . . , ⋅‖). Since 0 < inf 𝑝𝑘 ≤ 1,

we get 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) ≤ 1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 , (64) and hence𝑥 ∈ 𝑤𝜃(M, 𝐵𝜇, 𝑝, ‖⋅, . . . , ⋅‖).

(ii) 1 ≤ 𝑝𝑘 ≤ sup 𝑝𝑘 = 𝐻 < ∞ and 𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇∧, 𝑝, ‖⋅, . . . , ⋅‖). Then for each 0 < 𝜀 < 1 there exists a

positive integer𝑠0such that 1 ℎ𝑟𝑘∈𝐼∑ 𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ≤ 𝜀 < 1 ∀𝑟 > 𝑠0. (65)

This implies that 1 ℎ𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩) 𝑝𝑘 ≤1 𝑟𝑘∈𝐼∑𝑟 𝑀𝑘(󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩( 𝐵𝜇∧𝑥𝑘− 𝐿 𝜌 , 𝑧1, . . . , 𝑧𝑛−1)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩 󵄩) . (66)

Therefore𝑥 = (𝑥𝑘) ∈ 𝑤𝜃(M, 𝐵𝜇, ‖⋅, . . . , ⋅‖). This completes the proof of the theorem.

Conflict of Interests

The authors declare that there is no conflict of interests regarding the publication of this paper.

Acknowledgments

The authors gratefully acknowledge that this research was partially supported by the University Putra Malaysia under the ERGS Grant Scheme having Project no. ERGS 1-2013/5527179. The authors are grateful also to the anonymous referees for a careful checking of the details and for helpful comments that improved the paper.

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