Journal of Inequalities and Applications Volume 2010, Article ID 751721,11pages doi:10.1155/2010/751721
Research Article
On Certain Multivalent Starlike or
Convex Functions with Negative Coefficients
Neslihan Uyanik,
1Erhan Deniz,
2Ekrem Kadio ˇglu,
2and Shigeyoshi Owa
31Department of Mathematics, Kazim Karabekir Faculty of Education, Atat ¨urk University,
Erzurum 25240, Turkey
2Department of Mathematics, Science and Art Faculty, Atat ¨urk University, Erzurum 25240, Turkey 3Department of Mathematics, Kinki University, Higashi-Osaka, Osaka 577-8502, Japan
Correspondence should be addressed to Shigeyoshi Owa,[email protected]
Received 2 April 2010; Accepted 3 June 2010
Academic Editor: N. Govil
Copyrightq2010 Neslihan Uyanik et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
By means of a differential operator, we introduce and investigate some new subclasses of p -valently analytic functions with negative coefficients, which are starlike or convex of complex order. Relevant connections of the definitions and results presented in this paper with those obtained in several earlier works on the subject are also pointed out.
1. Introduction
LetAmpdenote the class of functions of the following form:
fz zp− ∞ kpm
akzk
ak≥0; m, p∈N:{1,2,3, . . .}
, 1.1
which are analytic and multivalent in the open unit dicsU{z:z∈Cand|z|<1}.
Letfqdenote theqth-order ordinary differential operator for a functionf ∈ Amp, that is,
fqz p! p−q!z
p−q− ∞ kpm
k!
k−q!akz
k−q, 1.2
Next, we define the differential operatorDnfqas
Dnfqz p! p−q!z
p−q− ∞ kpm
k!
k−q!
k−q p−q
n
akzk−q m∈N; z∈ U. 1.3
In view of1.3, it is clear that
D0fqz fqz, D1fqz Dfqz 1 p−qz
fqz,
Dnfqz Dn−1Dfqz.
1.4
If we takep1 andq0 forDnfq, thenDnfqbecome the differential operator defined by S˘al˘agean1 .
Finally, in terms of a differential operator Dnfqdefined by1.3above, let En m,pq denote the subclass of Ampconsisting of functions f which satisfy the following inequality:
Em,pn
q
⎧ ⎨ ⎩f∈ Am
p: D
nfqz
zp−q /0, z∈C− {0}, fz z p− ∞
kpm
akzk, ak≥0 ⎫ ⎬ ⎭,
1.5
wherek∈N,n∈N0,k > n,m∈N;k−q/p−q≥p−q−n−1≥0;z∈ U.
Form∈N,n∈N0, andγ∈C− {0}, we define the next subclasses ofEnm,pq.
Enm,p
q, γ
f ∈Enm,p
q: Re
11
γ
Dn1fqz
Dnfqz −pqn
>0, z∈ U
,
Nm,pn
q, γ
⎧ ⎨
⎩f∈Enm,p
q: ∞
kpm
k!
k−q!
k−q p−q
nk−q
p−q −pqn
Re
γ
γ γ
ak
≤ p!
p−q!
γ
−pqn1Re γ
γ
,
Knm,p
q, γ
⎧ ⎨
⎩f∈Enm,p
q: ∞
kpm
k!
k−q!
k−q p−q
n
k−q
p−q−pqnγ
ak
≤ p!
p−q!γ−pqn1
,
1.6
Remark 1.1. 1E0m,10, γ S∗bwas studied by Nasr and Aouf2 also see Bulboac˘a et al. 3 .
2E0
m,10,1−α TαmandE1m,10,1−α Cαm,α∈ 0,1were introduced by
Srivastava et al.4 .
3 E01,10,1 −α T∗αand E11,10,1−α Cα,α ∈ 0,1 were introduced by Silverman5 .
4 Km,0 10, γ O0
mγand K1m,10, γ O1mγ were introduced by Parvathan and Ponnusanny6, pages 163-164 .
5For p 1 andq 0, the classesEn
m,pq, γ,Nm,pn q, γ, andKnm,pq, γare closely related withTn,mγ,On,mγ, andPn,mγwhich are defined by Owa and S˘al˘agean in7 .
In this paper we give relationships between the classes ofEnm,pq, γ,Nm,pn q, γ, and
Kn
m,pq, γ.In the particular case whenm∈Nandn0,p1, andq0, we obtain the same results as in8 .
2. Main Results
Our main results are contained in
Theorem 2.1. Letm∈N,n∈N0 and letγ∈C− {0}; then
1Kn
m,pq, γ⊆Enm,pq, γ; 2En
m,pq, γ⊆Nnm,pq, γ; 3ifγ∈0,∞, then
Knm,p
q, γEnm,p
q, γNm,pn
q, γ; 2.1
4ifγ∈−∞,0, thenNn
m,pq, γ/⊆Enm,pq, γ; 5ifγ∈−∞,0, thenEn
m,pq, γ/⊆Km,pn q, γ. Proof. 1Letf∈Kn
m,pq, γ.We prove that
Dn1fqz
Dnfqz −pqn
<γ, z∈ U. 2.2
Iff has the series expansion
fz zp−
∞
kpm
then
Dn1fqz
Dnfqz −pqn
−γ
≤ −
p!/p−q!1−pqn
p!/p−q!−∞kpmk!/k−q!k−q/p−qnak|z|k−p
∞
kpm
k!/k−q!k−q/p−qnak
k−q/p−q−pqn|z|k−p p!/p−q!−k∞pmk!/k−q!k−q/p−qnak|z|k−p −
γ.
2.4
We use the fact thatDnfqz/zp−q
/
0 forz∈ U − {0}and limz→oDnfqz/zp−q
p!/p−q!; these imply
p!
p−q!− ∞
kpm
k!
k−q!
k−q p−q
n
ak|z|k−p>0 2.5
forz∈ U.
From2.4and2.5, we deduce
D
n1fqz
Dnfqz −pqn −γ
< −
p!/p−q!1−pqnγ
p!/p−q!−∞kpmk!/k−q!k−q/p−qnak
.
∞
kpm
k!/k−q!k−q/p−qnak
k−q/p−q−pqnγ p!/p−q!−∞kpmk!/k−q!k−q/p−qnak
.
2.6
By using the definition ofKn
m,pq, γfrom this last inequality we, obtain2.2which implies
Re
1
γ
Dn1fqz
Dnfqz −pqn
>−1 z∈ U, 2.7
2Letf be inEn
m,pq, γ.Then2.7holds and, by using2.3, this is equivalent to
Re ⎧ ⎨ ⎩ 1 γ ⎛ ⎝
p!/p−q!zp−q−∞ kpm
k!/k−q!k−q/p−qn1akzk−q
p!/p−q!zp−q−∞ kpm
k!/k−q!k−q/p−qnakzk−q
−pqn
⎞ ⎠
⎫ ⎬ ⎭
>−1 z∈ U.
2.8
Forzt∈0,1ift → 1−, from2.8we obtain ⎧ ⎨ ⎩ ⎛ ⎝−
p!/p−q!∞kpmk!/k−q!k−q/p−qn1ak
p!/p−q!−∞kpmk!/k−q!k−q/p−qnak ⎞ ⎠
⎫ ⎬ ⎭≤
γ2
Reγ −pqn
2.9
which is equivalent to
∞
kpm
k!
k−q!
k−q p−q
n
k−q p−q
γ2
Reγ −pqn
ak≤
p!
p−q!
γ2
Reγ −pqn1
.
2.10
Then multiplying the relation last inequality with Reγ/|γ|,we obtainf∈Nn m,pq, γ. 3ifγis a real positive number, then the definitions ofNn
m,pq, γandKnm,pq, γare equivalent, henceNn
m,pq, γ Knm,pq, γ.By using1and2from this theorem, we obtain 3.
4We have the following two cases.
Case 1. γ∈p−q−n−1−m/p−q,0.
Letfm,αp, q, n;zbe defined by
fm,α
p, q, n;zzp−α
pm−q p−q
−n p!
pm!
pm−q!
p−q! z
pm 2.11
and letα >0.We have
∞
kpm
k!
k−q!
k−q p−q
nk−q
p−q −pqn
Re
γ
γ γ
ak
≤
pm!
pm−q!
pm−q p−q
n
pm−q
p−q −pqn
Reγ
γ γ
×α
pm−q p−q
−n p!
pm!
pm−q!
p−q!
α p! p−q!
pm−q
p−q −pqn
γ
−γ −γ
or
∞
kpm
k!
k−q!
k−q p−q
n
k−q
p−q−pqn
Re
γ
γ γ
ak
≤ −α p! p−q!
−pqn1 m
p−qγ
≤0
< p! p−q!
−pqn1Re γ
γ γ
,
2.13
and then fm,αp, q, n;z∈Nm,pn q, γ see the definition ofNm,pn q, γ. Let now
Fz 11
γ
⎛
⎝Dn1fm,αq
p, q, n;z Dnfq
m,α
p, q, n;z −pqn
⎞
⎠ z∈ U. 2.14
Then, by a simple computation and by using the fact that
fm,αq
p, q, n;zfm,αqz
p!
p−q!z p−q−α
pm!
pm−q!
pm−q p−q
−n p!
pm!
pm−q!
p−q! z pm−q
p!
p−q!z
p−q−α p!
p−q!
pm−q p−q
−n
zpm−q.
Dnfm,αqz
p!
p−q!z
p−q−α p!
p−q!
pm−q p−q
−npm−q
p−q
n
zpm−q
p!
p−q!z
p−q1−αzm,
Dn1fm,αqz
p!
p−q!z p−q
1−αpm−q p−q z
m
,
we obtain
Fz 11
γ
Dn1fq m,αz
Dnfq m,αz
−pqn
11
γ
p!/p−q!zp−q1−αpm−q/p−qzm
p!/p−q!zp−q1−αzm −pqn
1−pqn1−αz
m−pqnpm−q/p−q
γ1−αzm
1a−αbζ
γ1−αζ 1ϕζ,
2.16
whereζzm,a−pqn1, b−pqn1m/p−q, and
ϕζ a−αbζ
γ1−αζ . 2.17
Forα >1 we, haveϕU C∞−Dc, d,whereDis the disc with the center
c α
2b−a
γα2−1 2.18
and the radius
d αb−a
γ1−α2. 2.19
We haveFU C∞−Dc1, dwhereDc, d {w:|w−c|< d}and we deduce that ReFz>0 for allz∈ Udoes not hold.
We have obtained that forα >1, fm,α∈Nm,pn q, γ,butfm,α/∈Enm,pq, γand in this case
Nn
m,pq, γ/⊆Enm,pq, γ.
Case 2. γ∈−∞, p−q−n−1−m/p−q.
We consider the functionfm,αdefined by2.11forα∈ 1,−pqn1γ/−p
qn1m/p−q. In this case, the inequality2.13 holds too and this implies that
fm,α∈Nm,pn q, γ.
We also obtain that f /∈En
5Letffm,αbe given by2.11, where α >|γ| −pqn1/|γ| −pqn1
m/p−qand|γ| −pqn1m/p−q>0.Then
∞
kpm
k!
k−q!
k−q p−q
n
k−q
p−q−pqnγ
ak
pm!
pm−q!
pm−q p−q
n
pm−q
p−q −pqnγ
×α
pm−q p−q
−n p!
pm!·
pm−q!
p−q!
α p! p−q!
pm−q
p−q −pqn
γ
> p!
p−q!γ
−pqn1
2.20
which implies that
fm,α/∈Knm,p
q, γ form∈N, n∈N0, γ∈−∞,0. 2.21
We have
Fz 1 1
γ
Dn1fq m,αz
Dnfq m,αz
−pqn
1 a−αbζ
γ1−αζ1ϕζ, 2.22
whereϕis given by2.17.
FromϕU Dc, dwherecanddare given by2.18and2.19, we obtain
ReFz≥1 αba
γα1. 2.23
If γ∈−∞, p−q−n−1−m/p−qand α∈|γ| −pqn1/|γ| −pqn1
m/p−q,1, then
αγbγa
and if
γ∈
p−q−n−1− m
p−q,0
,
α∈
γ−pqn1
γ−pqn1m/p−q,
γ−pqn1
−pqn1m/p−q−γ
∩0,1,
2.25
then 2.24also holds. By combining2.24with 2.23and the definition ofEn
m,pq, γ, we obtain that
fm,α∈Enm,p
q, γ forα∈
γ−pqn1 γ−pqn1m/
p−q,
γ−pqn1 −pqn1m/
p−q−γ
∩0,1, γ∈−∞,0.
2.26
Appendix
In this paper, we discuss the classEn
m,pq, γof analytic functions with negative coefficients. Let us consider the functionsfgiven by
fz zp
∞
kp1
akzk A.1
which are analytic inU. For such a functionf, we say thatf∈Gn1,pq, γif it satisfies
Re
11
γ
Dn1fqz
Dnfqz −pqn
>0 z∈ U A.2
for some complex numberγwith 0<Re1/γ<1/p−q−n−1. If we define the functionFforf∈Gn1,pq, γby
Fz 1
1/γDn1fqz/Dnfqz−pqn−i1−pqnIm1/γ
then we know thatF is analytic in U,F0 1, and Refz > 0 z ∈ U. ThusF is the Carath´eodory function. Since the extremal function for the Carath´eodory functionFis given by
Fz 1z
1−z, A.4
we can write
11/γDn1fqz/Dnfqz−pqn−i1−pqnIm1/γ
11−pqnRe1/γ
1z
1−z. A.5
This shows us that
Dn1fqz
Dnfqz −pqnγ−iγ
1−pqnIm
1
γ
γ
11−pqnRe
1
γ
1z
1−z.
A.6
Noting that
Dn1fqz 1 p−qz
Dnfqz, A.7
we see that
1
p−q
Dnfqz
Dnfqz −
1
z
p−q−n−γiγ1−pqnIm
1
γ
γ
11−pqnRe
1
γ
2 1−z
1
z
,
A.8
that is,
1
p−q
Dnfqz Dnfqz −
1
z 2γ
11−pqnRe
1
γ
1
1−z. A.9
It follows from the above that
!z
0
1
p−q
Dnfqt
Dnfqt − 1
t
dt2γ
11−pqnRe
1
γ
!z
0
1
1−tdt. A.10
Calculating the above integrations, we have that
1
p−qlogD
nfqz−logz−2γ11−pqnRe1
γ
Therefore, we obtain that
Dnfqz1/p−q z
1−z2γ11−pqnRe1/γ, A.12
that is,
Dnfqz
z
1−z2γ11−pqnRe1/γ
p−q
. A.13
Consequently, the function f defined by the above is the extremal function for the class
Gn1,pq, γ. But our class En
m,pq, γ is defined with analytic functions f with negative coefficients. Thus we do not know how we can consider the extremal function for this class.
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