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Aryabhatta Journal of Mathematics and Informatics (Impact Factor- 5.856)

Double-Blind Peer Reviewed Refereed Open Access International e-Journal - Included in the International Serial Directories

Aryabhatta Journal of Mathematics and Informatics

http://www.ijmr.net.in

email id- irjmss@gmail.com

Page 816 CYCLOTOMIC INDEX OF GRAPHS

Dr Ajitha V ,Associate Professor P.G Department of Mathematics Mahatma Gandhi College, Iritty-670703

Kerala, India Silja C,Research Scholar Mary Matha Arts & Science College

Mananthavady - 670 645 Kerala, India

Abstract

Let

G

( , )

V E

be a

( , )

p q

graph and

p

( ) 1

x

  

x

x

2

 

...

x

p1be the cyclotomic

polynomial associated with G. Then the cyclotomic index of G is defined as

p

( )(mod )

q

p

and is

denoted by cyl(G). In this paper we shall attempt to compute the cyclotomic index of some special type of graphs. We also establish some fundamental properties of cyclotomic index of certain graphs.

Keywords

Cyclotomic polynomial of graphs, cyclotomic index of graphs .

Introduction

By a graph

G

( , )

V E

we mean a finite undirected graph with neither loops nor multiple edges. The order and size of the graph are denoted by p and q respectively. For various graph theoretic notations and terminology we follow F. Harrary [1] and for basic number theoretic results we refer [4].

Definition 1.1 Let G be a

( , )

p q

graph. Consider the

p

th cyclotomic polynomial associated with G

given by

p

( ) 1

x

  

x

x

2

 

...

x

p1. Then the cyclotomic index of G defined as

p( )(mod )q p

(2)

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Page 817 Every graph G has a cyclotomic polynomial and every cyclotomic polynomial is of some simple graph

G. But There is infinite number of graph for a given cyclotomic polynomial.

The following are some simple observations which follow immediately from the definition of a cyclotomic polynomial.

Observation 1.2 G be a graph of order n then

cyl G

( )

n

.

Observation 1.3 LetG G1, 2 be two isomorphic graph then cyl G( 1)cyl G( 2).

Observation 1.4 The cyclotomic polynomial of trivial graphs with n vertices is

2 1

( ) 1 ... n

n x x x x

    

and cyl G( )

n(0) mod

n

1.

Observation 1.5 The cyclotomic polynomial of a

( , )

p q

graphs G with

p

n q

,

 

n

1

is

2 1

( ) 1 ... n

n x x x x

    

and

cyl G

( )

0

.

Observation 1.6 The cyclotomic polynomial of a

( , )

p q

graphs G with

p

n q

,

1

is

2 1

( ) 1 ... n

n x x x x

    

and

cyl G

( )

0

.

Observation 1.7 The cyclotomic polynomial of a

( , )

p q

graphs G with

p

n q

,

 

n

1

is

2 1

( ) 1 ... n

n x x x x

    

and

( )

0 if n is even

1 if n is odd

cyl G

 

.

Observation 1.8 The star graph K1n, 1

0 if n is odd

(

)

1 if n is even

n

cyl K

 

.

1. Main Results

Theorem 2.1 : For any tree T with order n,

( )

0 if n is even

1 if n is odd

cyl T

 

(3)

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Page 818 Proof : If T is a tree with n vertices then it has precisely n1 edges. Then the cyclotomic polynomial

2 1

( ) 1

...

n

n

x

x

x

x

  

 

and

2 1

2 1

( ) 1 (

1) (

1)

... (

1)

(mod )

1 ( 1) ( 1)

... ( 1)

(mod )

0 if n is even

1 if n is odd

n

n

cyl T

n

n

n

n

n

    

  

    

  

 

.

Hence the proof.

Theorem 2.2 : Let G be connected

( , )

p q

graph which is unicyclic then ,

cyl G

( ) 1

.

Proof : G be connected graph with

p

vertices and it is unicyclic then it has precisely

p

edges. Then the cyclotomic polynomial

p

( ) 1

x

  

x

x

2

 

...

x

p1 and

2 1

( ) 1

...

(mod )

1(mod )

1

p

cyl G

p

p

p

p

p

  

 

.

Theorem 2.3 : There is no graph G of 3 vertices with

cyl G

( )

2

.

Proof : : Let G be a

(3, )

q

graph. Then the cyclotomic polynomial 2 3( ) 1x x x

   and

2

( ) 1 (mod 3)

cyl G   q q .

Now consider

q

is of the form

3

n

r

,where

0

 

r

2

.

If

q

3

n

2

2

( ) 1

(mod 3)

1 3

(3 ) (mod 3)

1

cyl G

q

q

n

n

  

 

(4)

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Page 819

2

2

( ) 1

(mod 3)

1 3

1 (3

1) (mod 3)

1 1 1(mod 3)

0

cyl G

q

q

n

n

  

 

 

  

If

q

3

n

2

2

2

( ) 1

(mod 3)

1 3

2 (3

2) (mod 3)

1 2 4(mod 3)

1

cyl G

q

q

n

n

  

 

 

  

So the possible

cyl G

( )

are o and 1. For any graph of 3 vertices

cyl G

( )

0 or 1

.

Theorem 2.3 : There is no graph G of 4 vertices with

cyl G

( )

2

.

Proof : : Let G be a

(4, )

q

graph. Then the cyclotomic polynomial

4( ) 1x   x x2x3 and

2 3

( ) 1 (mod 4)

cyl G   q qq .

Now consider

q

is of the form

4

n

r

,where

0

 

r

3

.

If

q

4

n

2 3

2 3

( ) 1

(mod 4)

1 4

(4 )

(4 ) (mod 4)

1

cyl G

q

q

q

n

n

n

  

 

If

q

4

n

1

2 3

2 3

( ) 1

(mod 4)

1 4

1 (4

1)

(4

1) (mod 4)

1 1 1 1(mod 4)

0

cyl G

q

q

q

n

n

n

  

 

 

   

(5)

Aryabhatta Journal of Mathematics and Informatics (Impact Factor- 5.856)

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Page 820 If

q

4

n

2

2 3

2 3

( ) 1

(mod 4)

1 4

2 (4

2)

(4

2) (mod 4)

1 2 4 8(mod 4)

3

cyl G

q

q

q

n

n

n

  

 

 

   

If

q

4

n

3

2 3

2 3

( ) 1

(mod 4)

1 4

3 (4

3)

(4

3) (mod 4)

1 3 9 27(mod 4)

0

cyl G

q

q

q

n

n

n

  

 

 

   

So the possible

cyl G

( )

are

0, 1 and 3

. For any graph of 4 vertices

cyl G

( )

0, 1 or 3

.

Theorem 2.4 : There is no graph G of 5 vertices with

cyl G

( )

2,3 and 4

.

Proof : : Let G be a

(5, )

q

graph. Then the cyclotomic polynomial 2 3 4 5( ) 1x x x x x

     and

2 3 4

( ) 1 (mod 5)

cyl G   q qqq .

Now consider

q

is of the form

5

n

r

,where

0

 

r

4

.

If

q

5

n

2 3 4

2 3 4

( ) 1

(mod 5)

1 5

(5 )

(5 )

(5 ) (mod 5)

1

cyl G

q

q

q

q

n

n

n

n

  

 

(6)

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Page 821

2 3 4

2 3 3

( ) 1

(mod 5)

1 5

1 (5

1)

(5

1)

(5

1) (mod 5)

1 1 1 1 1(mod 5)

0

cyl G

q

q

q

q

n

n

n

n

  

 

 

    

If

q

5

n

2

2 3 4

2 3 4

4

( ) 1

(mod 5)

1 5

2 (5

2)

(5

2)

(5

2) (mod 5)

1 2 4 8 2 (mod 5)

1

cyl G

q

q

q

q

n

n

n

n

  

 

 

    

If

q

5

n

3

2 3 4

2 3 4

4

( ) 1

(mod 5)

1 5

3 (5

3)

(5

3)

(5

3) (mod 5)

1 3 9 27 3 (mod 5)

1

cyl G

q

q

q

q

n

n

n

n

  

 

 

   

If

q

5

n

4

2 3 4

2 3 4

2 3 4

( ) 1

(mod 5)

1 5

4 (5

4)

(5

4)

(5

4) (mod 5)

1 4 4

4

4 (mod 5)

1

cyl G

q

q

q

q

n

n

n

n

  

 

 

  

So the possible

cyl G

( )

are 0 and 1. For any graph of 5 vertices

cyl G

( )

0 or 1

.

Theorem 2.5 : There is no graph G of

2

p

vertices with

cyl G

( )

2

, where

p

is a prime number .

Proof : : Let G be a

( , )

n q

graph.

n

2

p

. Then the cyclotomic polynomial

2 1

( ) 1 ... n

n x x x x

    

and

2 1

( ) 1 ... n (mod n)

(7)

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Page 822 If

q

1(mod )

n

then

cyl G

( )

0

If

q

1(mod )

n

then

2 1

( ) 1

...

(mod n)

1

(mod n)

1

n

n

cyl G

q

q

q

q

q

  

 

By Euler theorem q( )n 1(mod )n since

gcd( , ) 1

q n

.

( )

n

(2 )

p

p

1

 

So 1

1(mod )

p

q   n that is qpq(mod )n then

2 2

(mod )

n p

qqq n

2

1

q

1

( )

( mod )

(mod )

1

1

1(mod )

n

q

cyl G

n

n

q

q

q

n

 

Since

q

1(mod )

n

,

cyl G

( )

 

q

1

cannot be 2.

Theorem 2.6 : Let G is

( , )

p q

graph. If

p

is a prime number then

cyl G

( ) 1

, provided

q

1(mod )

p

.

Proof : : Let G be a

( , )

p q

.Then the cyclotomic polynomial

2 1

( ) 1

...

p

p

x

x

x

x

  

 

and

2 1

( ) 1

...

(mod )

1

(mod )

1

p

p

cyl G

q

q

q

p

q

p

q

  

 

.

Now consider

q

is of the form

np

r

,where

0

 

r

p

.

(

)

mod

p p p

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Page 823 Since

0

 

r

p

and p is prime ,

gcd( , ) 1

r p

r

p

r

(mod )

p

so

q

p

r

(mod )

p

1

( )

(mod )

1

1

(mod ) [

q

r mod ]

1

1

1(mod )

1

p

q

cyl G

p

q

r

p

p

q

r

p

r

Corollary 2.5 : There is no graph G of

p

vertices with

cyl G

( )

2,3,...

p

1

. where

p

is a prime number .

Problem 2.6 : The Cycle Cn, cyl C( n) 1 .

Problem 2.7 : The Path Pn,

0 if n is even

(

)

1 if n is odd

n

cyl P

 

.

Problem 2.8 : The Complete graph Kn,

n

2

+1 if n is even

(

)

1 if n is odd

n

cyl K

 

.

Problem 2.9: The regular graph Gof order n,

n

2

+1 if k is odd

( )

1 if k is even

cyl G

 

.

Problem 2.10 : The Wheel Wn1, 1

1 if n is even

(

)

3 if n is odd

n

cyl W

 

.

REFERENCES

[1] F. Harary Graph Theory, Addition-Wesley, Reading, Mass, 1972

(9)

Aryabhatta Journal of Mathematics and Informatics (Impact Factor- 5.856)

Double-Blind Peer Reviewed Refereed Open Access International e-Journal - Included in the International Serial Directories

Aryabhatta Journal of Mathematics and Informatics

http://www.ijmr.net.in

email id- irjmss@gmail.com

Page 824 Sequence of a Graph, Int. Jonl of Math. Analysis, Vol.8, 2014.no.29.

[3] Graph Polynomials and Their Representations, Technische Universitat Bergakademie Freiberg, 1765.

[4] David M. Burton, Elementary Number Theory, Second Edition, Wm. C. Brown Company Publishers, 1980.

[5] J.A. Gallian, A Dynamic Survey of Graph Labeling, Electronic Journal of Combinatorics, 17 (2010), DS6.

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