103
Some New Subclasses Of Bi-Univalent Functions
Defined By Convolution Associated With Linear
Differential Operator
M.Thirucheran
1, T. Stalin
2Associate Professor and Head, Post Graduate and Research Department of Mathematics1, Assistant Professor, Department of Mathematics2,
LN Government College, University of Madras, Chennai, India1. Gojan School of Business and Technology, Anna University, Chennai, India2.
Email: [email protected], [email protected]
Abstract:The main object of this paper is investigating a new subclass of bi-univalent function in the open unit disk U which is defined by convolution of Al-Oboudi Differential Operator. And obtained the initial two Taylor -McLaurin co-efficient a2 and a3 for the subclass ,,,
,
b n m
r
S of Bi-Univalent function.
2010 Mathematics Subject classification:30C45,30C55 and 30C80.
Keywords:Analytic functions, univalent functions, bivalent functions, convolution and Al-Oboudi differential operator.
1. INTRODUCTION AND DEFINITIONS
Definition 1.1
Let A denote the class of functions f
normalized by
2
) (
j j jz
a z z
f (1.1)
Which are analytic in the open unit disc
} 1 : {z
U C z .
Forf A, Al-Oboudi [1] introduces the
following operator.
) ( ) (
0
z f z f
D ,
0 ), ( ) ( ) ( ) 1 ( )
(
f z
f z
zf z Df z
D
,.... 3 , 2 , 1 )),
( ( )
(z D D 1f z nN
f
Dn n
1 ( 1) , 0. )
( 0
2
N N n z a j z z f D
j
j j n
n (1.2)
If
1, then we get Salagean [7]differential operator.
Koebe One -Quarter Theorem [5]
The range of every function of class A
contains the disk of radius
4 1 : w
w .
It is well known that every function f Ahas an
inverse 1
f defined by f1(f(z))zand w
w f
f( 1( ))
, .
4 1 ) ( );
( 0
0
f r f r w
For this inverse function 1
f , we have: ...
) 5
5 (
) 2 ( )
( : ) (
4 4 3 2 3 2
3 3 2 2 2 2 1
w a a a a
w a a w a w w f w g
(1.3).
Let j
n jz
r z z
r
2
)
( , (rj 0)&
2
, , , ,
) (
j
b n m
r j jz S a z z
f
Then the Hadamard product (f*r)defined by if
and only if
2
, , , ,
) ( ) * (
j
b n m
r j j ja z S r
z z r
f
Definition 1.2
If both the function f and its inverse function 1
f are univalent in U , then the function
f is called bi-univalent.
For example,
z
z z
z z
1 1 l o g 2 1 , ) 1 l o g ( ,
1 ,
and so on.
However, the familiar Koebe function is not a bi-univalent function.
For example, 2
2
1 ,
2 z
z z z
, and so on.
Let the class of bi-univalent function first investigated by Levin[8]and found that
Afterward, Brannan and Clunie [2] conjectured
that a2 2.
Later, Brannan and Taha [3] introduced the new subclass of bi-univalent function of the class like the familiar subclasses S*()and C() of starlike and convex functions of .(01)
,respectively. If a function f A is in the class )
(
*
S of strongly bi-starlike function of order
) 1 0 (
.
104
satisfied f(z)and
2 ) (
) (
arg
z f
z f z
,
) (zU and
2 ) (
) (
arg
w g
z wg
,(wU)
where the function g is the extension of 1
f to U
.Similarly, a function f A is in the class
) (
C of strongly bi-convex function of order
) 1 0 (
.
if each of the following conditionssatisfied f(z)and
2 ) (
) ( 1
arg
z f
z f z
,
) (zU and
2 ) (
) ( 1
arg
w g
z g w
, (wU). Where the function g is the extension of 1
f to
U . For each function *()
S and C(
). Theyfound nonsharp estimates on the first two Taylor -McLaurin co-efficient a2 and a3 .
Recently, Qing-Hua Xu, Ying-Chun Gui and H.M. Srivastava [9], B.A. Frasin and M.K. Aouf [6], Seker.B [11], and R.M. El-Ashwah [10] investigated some subclasses of bi-univalent function and obtained non-sharp estimates on the first two co-efficient.
By motivated this study we introduce and obtained the initial two co-efficient a2 and a3 for
the subclass ,,, ,
b n m
r S . Definition: 1.3
A function f(z) given by (1.1) is said to
be in the class f ,,, ( )
,
b n m
r S
) 1 0 , , , (
, mnN0 mn
. if the followingconditions are satisfied: f(z),r(z)Aand 2
1 ) )( * (
) )( * ( 1 1
arg
z r f D
z r f D
b n
m
, (zU)
(1.4)
and
2 1 ) )( * (
) )( * ( 1 1
arg
w r g D
w r g D
b n
m
,
)
(wU (1.5)
Where the function g is given by (1.3).
Definition: 1.4
A function f(z) given by (1.1) is said to
be in the class f ,,, ( )
,
b n m
r S
) 1 0 , , , (
, mnN0 mn
, if the followingconditions are satisfied: f(z),r(z)Aand
1
) )( * (
) )( * ( 1 1
z r f D
z r f D
b n
m
,(zU) (1.6)
&
1
) * (
) )( * ( 1 1
r g D
w r g D
b n
m
,(wU)(1.7) Where the function g is given by (1.3).
Definition: 1.5
A function h(z),p(z):UC satisfy the conditions min
h(z)
,p(z)
0 , zU and h(0)p(0)1.For a function
f
,,, ( ( ), ( )), h z p z
Smnb r
defined by (1.1),(m,nN0,mn,0
1). ifthe following conditions are satisfied: f,rAand )
( 1 ) )( * (
) )( * ( 1
1 h z
z r f D
z r f D
b n
m
,(zU) (1.8)
& 1 ( )
) )( * (
) )( * ( 1
1 p z
w r g D
w r g D
b n
m
,(wU)
(1.9)
Where the function g is given by (1.3).
Remarks
(i). ,,1,1( )
1 ,
n m
S =Hm,n(),( Seker.B [11])
(ii). 1,0,1,1( )
1 ,
S = *()
S , (Brannan and Taha [3])
(iii). 2,1,1,1( )
1 ,
S =C(), (Brannan and Taha [3])
2. MAIN RESULT
To derive our main results, we should recall the following lemma [4].
Lemma 2.1
Let hPthe family of all functions h
analytic in U for which Re
h(z)0
and have theform ( ) 1 3 ...
3 2 2
1
pz p z p z
z
h for zU
.Then pn 2, for each
n
.Theorem 2.2
Let the function f(z) given by (1.1) be in the bi-univalent function class Sm,n,b,(h,p)
.Then
n n
m
n m
r
b a
2 2
2
) 1 ( ) 1 (
) 2 1 ( ) 2 1 ( 2
2
(2.1)
and
n m
n m
b b
r a
) 2 1 ( ) 2 1 (
2 ) 1 ( ) 1 (
4
1 2
2
3 3
(2.2)
Proof
Let consider the function hand p
Satisfying the conditions of the definition (1.5)
with the form
U z z
h z h z h z
h( )1 3... ,
3 2 2
1 &
U w w
p w p w p w
p( )1 3... ,
3 2 2 1
105
Since
,
,,,(
,
)
,
h
p
S
r
f
mnbr
,then ) ( 1 ) )( * ( ) )( * ( 11 h z
z r f D z r f D b n m
, (zU) (2.3)
and ) ( 1 ) )( * ( ) )( * ( 1
1 p z
w r g D w r g D b n m
,(wU) (2.4)
respectively.
By equating the coefficient of (2.3 and (2.4), we get
(1 ) (1 )
a2r2 bh1n
m
(2.5)
22 2 2 2 2 3 3 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( bh r a r a n n m n m (2.6)
(1 ) (1 )
a2r2 bp1n
m
(2.7)and
22 2 2 2 2 3 3 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( 2 ) 2 1 ( ) 2 1 ( bp r a r a n n m n m n m (2.8) From (2.5)&(2.7), 1 1 p
h (2.9)
And
(1 ) (1 )
( )2 2 1 2 1 2 2 2 2 2 2 p h b r a n
m
(2.10)
22 2 2 1 2 1 2 2 2 ) 1 ( ) 1 ( 2 ) ( n m r p h b a
(2.11)
From (2.6)&(2.8),
( ) ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 (2 2 2
2 2 2 2
2n a r bh p n m n m
(2.12)
n n
m n m r p h b a 2 2 2 2 2 2 2 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( 2 ) (
(2.13)
(1 2 ) (1 2 )
( )2 ) 2 1 ( ) 2 1 ( 2 2 2 2 2 2 2 3 3 p h b r a r a n m n m (2.14)
n m n m p h b p h b r a ) 2 1 ( ) 2 1 ( 2 ) ( ) 1 ( ) 1 ( 2 ) ( 1 2 2 2 2 1 2 1 2 3 3
(2.15)From Lemma (2.1),(2.11),(2.13) and (2.15), we get
n n
m n m r b a 2 2 2 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( 2 2
and
n m n m b b r a ) 2 1 ( ) 2 1 ( 2 ) 1 ( ) 1 ( 4 1 2 2 3 3 This completes the theorem (2.2).
Theorem 2.3
Let the function f,r given by (1.1) be in the bi-univalent function class ,,, ( )
,
b n m rS .Then
n n
m n m r b a 2 2 2 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( 2 2 (2.16)
and
n m n m b b r a ) 2 1 ( ) 2 1 ( 2 ) 1 ( ) 1 ( 4 1 2 2 2 3 3 (2.17) ProofLet consider the function
h
andp
Satisfying the conditions of the definition (1.5) with the form
U z z h z h z h z
h( )1 3... ,
3 2 2 1 and U w w p w p w p w
p( )1 3... ,
3 2 2 1
respectively.
Since
,
,,,(
)
,
b n m rS
r
f
,then
) ( 1 ) )( * ( ) )( * ( 11 h z
z r f D z r f D b n m
,(zU)
(2.18)
and 1
( )
) )( * ( ) )( * ( 1
1 p z
w r g D w r g D b n m
,(wU)
(2.19) respectively.
From Lemma (2.1),(2.11),(2.13) and (2.15), we get
n n
m n m r b a 2 2 2 ) 1 ( ) 1 ( ) 2 1 ( ) 2 1 ( 2 2 and
n m n m b b r a ) 2 1 ( ) 2 1 ( 2 ) 1 ( ) 1 ( 4 1 2 2 2 3 3 This completes the theorem (2.3).
Theorem 2.4
Let the function f,r given by (1.1) be in the
bi-univalent function class ,,, ( )
,
b n m r106
n n
m
n m
r
b a
2 2
2
) 1 ( ) 1 (
) 2 1 ( ) 2 1 ( ) 1 ( 2
) 1 ( 2
(2.20)
and
n m
n m
b b r
a
) 2 1 ( ) 2 1 (
) 1 ( 2
) 1 ( ) 1 (
) 1 ( 4
1 2
2 2
3 3
(2.21)
Proof
Let consider the function
h
andp
Satisfying the conditions of the definition (1.5) with the form
U z z
h z h z h z
h( )1 3... ,
3 2 2
1 and
U w w
p w p w p w
p( )1 3... ,
3 2 2 1
respectively.
Since
,
,,,(
)
,
b n m
r
S
r
f
,then) ( ) 1 ( 1
) )( * (
) )( * ( 1
1 h z
z r f D
z r f D
b n
m
,
)
(zU (2.22)
and 1 (1 ) ( )
) )( * (
) )( * ( 1
1 p z
w r g D
w r g D
b n
m
, (wU) (2.23)
respectively.
From Lemma (2.1),(2.11),(2.13) and (2.15), we get
n n
m
n m
r
b a
2 2
2
) 1 ( ) 1 (
) 2 1 ( ) 2 1 ( ) 1 ( 2
) 1 ( 2
and
n m
n m
b b r
a
) 2 1 ( ) 2 1 (
) 1 ( 2
) 1 ( ) 1 (
) 1 ( 4
1 2
2 2
3 3
Letting
1in theorem (2.2), (2.3) and (2.4), we obtain the following corollaries.Corollary2.5
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,,1( , )
1 , h p
Smnb
.Then a2
m n
b m n 2n
) 2 ( ) 2 ( ) 3 ( ) 3 (
2
(2.24)
and
m n
m n
b b
a
) 3 ( ) 3 (
2
) 2 ( ) 2 (
4
2 2 3
(2.25)
Corollary2.6
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,,1
(
)
1
,
b n m
S
.Then(using definition (1.3))
m n m n n
b
a2 2
) 2 ( ) 2 ( ) 3 ( ) 3 (
2
(2.26)
and
m n
m n
b b
a
) 3 ( ) 3 (
2
) 2 ( ) 2 (
4
2 2 2 3
(2.27)
Corollary2.7
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,,1
(
)
1
,
b n m
S
.Then(using definition (1.4))
m n m n n
b
a2 2
) 2 ( ) 2 ( ) 3 ( ) 3 (
) 1 ( 2
(2.28)
and
m n
m n
b b
a
) 3 ( ) 3 (
) 1 ( 2
) 2 ( ) 2 (
) 1 ( 4
2 2 2 3
(2.29)
Letting
1&b1in theorem (2.2), (2.3) and (2.4), we obtain the following corollaries Seker [6].Corollary2.8
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,1,1( , )
1 , h p
Smn
.Then a2
m n
m n 2n
) 2 ( ) 2 ( ) 3 ( ) 3 (
2
(2.30)
and
m n
m n
a
) 3 ( ) 3 (
2
) 2 ( ) 2 (
4
2 3
(2.31)
Corollary2.9
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,1,1
(
)
1
,
n m
S
.Then(using definition (1.3))
m n m n n
a2 2
) 2 ( ) 2 ( ) 3 ( ) 3 (
2
(2.32)and
m n
m n
a
) 3 ( ) 3 (
2
) 2 ( ) 2 (
4
2 2 3
(2.33)
Corollary2.10
Let the function f(z) given by (1.1) be in the bi-univalent function class ,,1,1
(
)
1
,
n m
S
.Then(using definition (1.4))
m n m n n
a2 2
) 2 ( ) 2 ( ) 3 ( ) 3 (
) 1 ( 2
(2.34)and
m n
m n
a
) 3 ( ) 3 (
) 1 ( 2
) 2 ( ) 2 (
) 1 ( 4
2 2 3
107
ACKNOWLEDGMENT
The authors thank the referees for their valuable suggestions which lead to the improvement of this paper.
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