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R E S E A R C H

Open Access

Multi-parameter fourth order impulsive

integral boundary value problems with

one-dimensional

m-Laplacian and deviating

arguments

Meiqiang Feng

*

and Jingliang Qiu

*Correspondence:

[email protected] School of Applied Science, Beijing Information Science & Technology University, Beijing, 100192, People’s Republic of China

Abstract

Using inequality techniques and fixed point theories, several new and more general existence and multiplicity results are derived in terms of different values of

λ

> 0 and

μ

> 0 for a fourth order impulsive integral boundary value problem with

one-dimensionalm-Laplacian and deviating arguments. We discuss our problems under two cases when the deviating arguments are delayed and advanced. Moreover, the nonexistence of a positive solution is also studied. In this paper, our results cover fourth order boundary value problems without deviating arguments and impulsive effect and are compared with some recent results by Jankowski.

Keywords: multi-parameter; impulsive integral boundary value problems with advanced and delayed arguments; inequality techniques and fixed point theories; one-dimensionalm-Laplacian; existence and nonexistence of positive solutions

1 Introduction

Functional differential equations with impulse effect occur in many applications, such as population dynamics, biology, biotechnology, industrial robotic, pharmacokinetics, opti-mal control,etc., and can be expressed by functional differential equations with impulses, see [–]. Functional differential equations with impulses are characterized by sudden changing of their state and by the fact that the processes under consideration depend on their prehistory at each moment of time. Therefore, the study of impulsive functional dif-ferential equations has gained prominence and it is a rapidly growing field, see Zhang and Feng [], Nieto and Rodríguez-López [], Yan and Shen [], Li and Shen [], Yang and Shen [], YS Liu [], YJ Liu [], He and Yu [] and Dinget al.[] and the references therein. We note that the difficulties dealing with such problems are that they have deviat-ing arguments and their states are discontinuous. Therefore, the results of impulsive func-tional differential equations, especially for higher order impulsive funcfunc-tional differential equations, are fewer than those of differential equations without impulses and deviating arguments.

Moreover, owing to its importance in modeling the stationary states of the deflection of an elastic beam, fourth order boundary value problems have attracted much attention from many authors; for example, see Sun and Wang [], Yao [], O’Regan [], Yang [],

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Zhang [], Gupta [], Agarwal [], Bonanno and Bella [] and Han and Xu []. In particular, we would like to mention some results of Zhang and Liu [] and Feng []. In [], Zhang and Liu studied the following fourth order four-point boundary value problem without impulsive effect:

⎧ ⎪ ⎨ ⎪ ⎩

(φp(x(t)))=w(t)f(t,x(t)), t∈[, ],

x() = , x() =ax(ξ),

x() = , x() =bx(η),

where  <ξ,η< , ≤a<b< . By using the upper and lower solution method, fixed point theorems and the properties of Green’s functionG(t,s) andH(t,s), the authors give sufficient conditions for the existence of one positive solution.

Recently, Feng [] studied a fourth order boundary value problem with impulses and integral boundary conditions

⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩

(φp(y(t)))=f(t,y(t)), tJ,t=tk,k= , , . . . ,n,

y|t=tk= –Ik(y(tk)), k= , , . . . ,n, y() =y() =g(s)y(s)ds,

φp(y()) =φp(y()) =

h(s)φp(y(s))ds.

Using a suitably constructed cone and fixed point theory for cones, the existence of mul-tiple positive solutions was established. Furthermore, upper and lower bounds for these positive solutions were given.

However, to the best of our knowledge, no paper has considered the existence, multi-plicity and nonexistence of positive solutions for fourth order impulsive differential equa-tions with one-dimensionalm-Laplacian, multiple parameters and deviating arguments till now; for example, see [–] and the references therein.

In this paper, we investigate a fourth order impulsive integral boundary value problem with one-dimensionalm-Laplacian and deviating arguments

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

(φm(y(t)))=λω(t)f(t,y(α(t))), tJ,t=tk,k= , , . . . ,n,

y|t=tk= –μIk(tk,y(tk)), k= , , . . . ,n, ay() –by() =g(s)y(s)ds,

ay() +by() =g(s)y(s)ds,

φp(y()) =φp(y()) =

h(t)φp(y(t))dt,

(.)

whereλ>  andμ>  are two parameters,a,b> ,J= [, ],φm(s) is anm-Laplace op-erator,i.e.,φm(s) =|s|m–s,m> , (φm)–=φ

m∗, m +m∗ = ,tk(k= , , . . . ,n) (wherenis a fixed positive integer) are fixed points with  =t<t<t<· · ·<tk<· · ·<tn<tn+= ,

y|t=tk =y(t

+

k) –x(tk–), wherey(tk+) andy(tk–) represent the right-hand limit and the left-hand limit ofy(t) att=tk, respectively. In addition,ω,f,Ik,gandhsatisfy

(H) ωLp[, ]for some≤p≤+∞, and there existsη> such thatω(t)≥ηa.e. onJ;

(H) f :J×R+→R+is continuous withf(t,y) > for alltJandy> ,αC(J,J)with

R+= [, +∞);

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(H) g,hL[, ]are nonnegative andξ∈[,a),ν∈[, ), where

ξ=

g(t)dt, ν=

h(t)dt. (.)

Some special cases of (.) have been investigated. For example, Jankowski [] consid-ered problem (.) withλ= ,Ik=  andωC[, ], notωLp[, ] for some ≤p≤+∞. By using a fixed point theorem for cones due to Avery and Peterson, the author proved the existence results of positive solutions for problem (.).

Motivated by the results mentioned above, in this paper we study the existence, multi-plicity and nonexistence of positive solutions for problem (.) by using different meth-ods from that of the proof of Theorem . and Theorem . in [] to overcome difficul-ties arising from the appearances ofα(t)≡tandω(t) isLp-integrable. The arguments are based upon a fixed point theorem due to Krasnoselskii which deals with fixed points of a cone-preserving operator defined on an ordered Banach space.

The organization of this paper is as follows. In Section , we present the expression and properties of Green’s function associated with problem (.). In Section , we present some definitions and lemmas which are needed throughout this paper. In Section , we use a fixed point theorem to obtain the existence, multiplicity and nonexistence of positive solutions for problem (.) with advanced argumentα. In Section , we formulate sufficient conditions under which delayed problem (.) has positive solutions. In particular, our results in these sections are new whenα(t)≡tontJ. Finally, in Section , we offer some remarks and comments of the associated problem (.).

2 Expression and properties of Green’s function

We shall reduce problem (.) to an integral equation. To this goal, firstly by means of the transformation

φm

y(t) = –x(t), (.)

we convert problem (.) into

x(t) +λω(t)f(t,y(α(t))) = , tJ,

x() =x() =h(t)x(t)dt (.)

and

⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩

y(t) = –φm∗(x(t)), tJ,t=tk,

y|t=tk= –μIk(tk,y(tk)), k= , , . . . ,n, ay() –by() =g(s)y(s)ds,

ay() +by() =g(s)y(s)ds.

(.)

Theorem . If(H), (H)and(H)hold,then problem(.)has a unique solution x given

by

x(t) =λ

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where

H(t,s) =G(t,s) +   –ν

G(s,τ)h(τ), (.)

G(t,s) =

t( –s), ≤ts≤,

s( –t), ≤st≤. (.)

Proof The proof of Theorem . is similar to that of Lemma . in [].

Writee(t) =t( –t). Then from (.) and (.) we can prove thatH(t,s) andG(t,s) have the following properties.

Theorem . Let G and H be given as in Theorem..If(H)holds,then

H(t,s) > , G(t,s) > , ∀t,s∈(, ), (.)

H(t,s)≥, G(t,s)≥, ∀t,sJ, (.)

e(t)e(s)≤G(t,s)≤G(t,t) =t( –t) =e(t)≤ ¯e=max

tJ e(t) = 

, ∀t,sJ, (.)

ρe(s)≤H(t,s)≤γs( –s) =γe(s)≤

γ, ∀t,sJ, (.)

where

γ = 

 –ν, ρ=

e(τ)h(τ)

 –ν . (.)

Theorem . If(H), (H)and(H)hold,then problem(.)has a unique solution y

ex-pressed in the form

y(t) =

H(t,s)φm

x(s) ds+μ

n

k=

H(t,tk)Ik

tk,y(tk), (.)

where

H(t,s) =G(t,s) + 

aξ

G(s,τ)g(τ), (.)

G(t,s) = 

d

(b+as)(b+a( –t)), if≤st≤,

(b+at)(b+a( –s)), if≤ts≤ (.)

and

d=a(b+a).

Proof The proof of Theorem . is similar to that of Lemma . in [].

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Theorem . Letζ∈(,t),Gand Hbe given as in Theorem..If(H)holds,then we

have

db

G

(t,s)≤G(s,s)≤ 

d(b+a)

, t,sJ, (.)

ρ≤H(t,s)≤

a

aξG(s,s)≤ρ, ∀t,sJ, (.)

G(t,s)≥δG(s,s)≥

bδ

d , H(t,s)≥

δa

aξG(s,s)≥δρ, ∀t∈[ζ, ],sJ, (.)

where

δ= b

a+b, ρ= bγ

a+ b, ρ=

γ(b+a)

a+ b , γ=

aξ. (.)

Proof It follows from the definition ofG(t,s) andH(t,s) that (.) and (.) hold. Now, we show that (.) also holds.

In fact, fort∈[ζ, ] andsJ, we have that

G(t,s)

G(s,s)

=b+a( –t)

b+a( –s)≥

b

b+a forst,

G(t,s)

G(s,s)

=b+at

b+asb+

b+a forts.

This and (.) show that

H(t,s)≥δG(s,s)

 + 

aξ

g(τ)

aξG(s,s), t∈[ζ, ],sJ.

This together with (.) and (.) finishes the proof of (.).

From Theorem . and Theorem ., we have the following result.

Theorem . Assume that(H)-(H)hold. Then problem(.)has a unique solution y

given by

y(t) =

H(t,s)φm

λ

H(s,τ)ω(τ),(τ)

ds

+μ

n

k=

H(t,tk)Ik

tk,y(tk).

3 Preliminaries for the case

α

(t)≥tonJ

We begin by introducing the notations

f=lim sup y→+ maxtJ

f(t,y)

φm(y)

, f∞=lim sup

y→∞

max

tJ

f(t,y)

φm(y),

f=lim inf y→+ mintJ

f(t,y)

φm(y), f∞=lim infy→∞ mintJ

f(t,y)

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I(k) =lim sup

y→+ max

tJ

Ik(t,y)

y , I

(k) =lim sup y→∞

max

tJ

Ik(t,y)

y ,

I(k) =lim inf y→+ mintJ

Ik(t,y)

y , I∞(k) =lim infy→∞ mintJ

Ik(t,y)

y , k= , , . . . ,n.

We will also need the functions

f∗(u) =max

max

tJ f(t,y),y∈[,u]

, Ik∗(u) =max

max

tJ Ik(t,y),y∈[,u]

,

and let

f∗= lim

u→+ f∗(u)

φm(u)

, f∗ = lim

u→∞

f∗(u)

φm(u) ,

I∗(k) = lim

u→+ Ik∗(u)

u , I

∞(k) =ulim→∞

Ik∗(u)

u ,

wherek= , , . . . ,n.

Our first lemma gives some relationships between the functionsf andf∗andIkandIk.

Lemma .(See []) Assume that(H)holds.Then

f∗=f, f∗ =f∞, I∗(k) =I(k), I∗(k) =I∞(k),

where k= , , . . . ,n.

Proof The proof of Lemma . is similar to that of Lemma . in [].

The following fixed point theorem of a cone is crucial in the proofs of our results.

Lemma .(See []) Let P be a cone in a real Banach space E.Assume thatand

are bounded open sets in E with∈,¯⊂.If

A:P∩(¯\)→P

is completely continuous such that either

(i) Axx,∀xPandAxx,∀xP,or

(ii) Axx,∀xPandAxx,∀xP,

then A has at least one fixed point in P∩(¯\). LetJ=J\{t,t, . . . ,tm}, and

PC[, ] =yC[, ] :y|(tk,tk+)∈C(tk,tk+),y

tk ,y

t+k exist,k= , , . . . ,m.

ThenPC[, ] is a real Banach space with the norm

yPC=max

y∞,y, (.)

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A functionyPC[, ]C(J) withϕp(y)C(, ) is called a solution of problem (.) if it satisfies (.).

Define a cone inPC[, ] by

K=

yPC[, ] :y(t)≥ onJand min

t∈[ζ,]y(t)≥δ

ρ

ρ

yPC

, (.)

whereδ,ρandρare defined in (.) and (.), respectively. Forr> , let

r=

yK:yPC<r

. (.)

Define an operatorTλμ:KPC[, ] by

Tλμy(t) =

H(t,s)φm

λ

H(s,τ)ω(τ),(τ)

ds +μ n k=

H(t,tk)Ik

tk,y(tk) . (.)

It follows from (.) and Theorem . that the following lemma holds.

Lemma . Assume that(H)-(H)hold.Then yK is a positive fixed point of Tλμif and

only if y is a positive solution of problem(.).

Lemma . Suppose that(H)-(H)hold.Then Tλμ(K)⊂K and T μ

λ :KK is completely

continuous.

Proof For alluK, thenTλu≥ onJand it follows from (.) and (.) that

Tλμy(t) =

H(t,s)φm

λ

H(s,τ)ω(τ),(τ)

ds +μ n k=

H(t,tk)Ik

tk,y(tk)

ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

,

tJ, (.)

Tμ λy

(t)≤

H

t(t,s)φm

λ

H(s,τ)ω(τ),y(τ)

ds +μ m k=

Ht(t,tk)Ik

tk,y(tk)

ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

,

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whereρ=da(a+b),

Ht(t,s) =Gt(t,s) = 

d

a(b+as), if ≤st≤,

a(b+a( –s)), if ≤ts≤

and

max

t,sJ,t=s

Ht(t,s)= max

t,sJ,t=s

Gt(t,s)= 

da(b+a).

It follows from (.) and (.) that

TλμyPC≤ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds

+μ

n

k=

Ik

tk,y(tk)

, (.)

where

ρ=max{ρ,ρ}. (.)

Noticing (.), (.) and (.), we have

min

t∈[ζ,]

Tλμy(t)

= min

t∈[ζ,]

H(t,s)φm

λ

H(s,τ)ω(τ),(τ)

ds

+μ

n

k=

H(t,tk)Ik

tk,y(tk)

δρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

=δρρ

ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

δρρ

TλμyPC.

Thus,Tλμ(K)⊂K.

Finally, similar to the proof of Lemma . in [], one can prove thatTλμ:KK is completely continuous. This gives the proof of Lemma ..

To obtain some of the norm inequalities in Lemma . and Lemma ., we employ Hölder’s inequality.

Lemma .(Hölder) Let fLp[a,b]with p> ,gLq[a,b]with q> ,andp+

q= .Then

fgL[a,b]and

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Let fL[a,b],gL[a,b].Then fgL[a,b]and

fg≤ fg∞.

Next, we consider the following cases forωLp[, ]:p> ,p= ,p=. Casep>  is treated in Lemma . and Lemma ..

Lemma . Assume that(H)-(H)hold,α(t)≥t on J and let r> be given.If there exist

ε> andε> such that f∗(r)≤εφm(r)and Ik∗(r)≤εr(k= , , . . . ,n),then

TλμyPC≤ρ

φm

λγ εeqωp +μnεyPC, y∂r. (.)

Proof By the definition off∗(r) andIk∗, iff∗(r)≤εφm(r) andIk∗(r)≤εr(k= , , . . . ,n), then

f(t,y)≤εφm(r), Ik(t,y)≤εr fortJand ≤yr.

Since ≤tα(t)≤ onJ, it follows from ≤y(t)≤ronJthat ≤y(α(t))≤r. Therefore, we havef(t,y(α(t)))≤εφm(r) fortJ, and it follows from (.) that

TλμyPC≤ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

ρ

φm

λ

γe(τ)ω(τ),(τ)

+μ

n

k=

Ik

tk,y(tk)

ρ

φm

λγ

e(τ)ω(τ)εφm(r)

+μ

n

k=

εr

=ρ

φm

λγ εφm(r)

e(τ)ω(τ)

+μ

n

k=

εr

ρ

φm

λγ εφm(r)eqωp +μnεr =ρ

φm

λγ εeqωp +μnεr yPC, ∀y∂r.

This completes the proof.

The following result deals with the casep= .

Corollary . Assume that(H)-(H)hold,α(t)≥t on J and let r> be given.If there

existε> andε> such that f∗(r)≤εφm(r)and Ik∗(r)≤εr(k= , , . . . ,n),then

TλμyPC≤ρ

φm

λγ εeω +μnεr yPC, y∂r.

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Corollary . Assume that(H)-(H)hold,α(t)≥t on J and let r> be given.If there

existε> andε> such that f∗(r)≤εφm(r)and Ik∗(r)≤εr(k= , , . . . ,n),then

TλμyPC≤ρ

φm

λγ εeω∞ +μnεr yPC, y∂r.

Proof By Lemma ., leteω∞replaceeqωpand repeat the argument above. Lemma . Assume that(H)-(H)hold,α(t)≥t on J and let l> and lbe given.If

f(t,y)≥lφm(y)and Ik(t,y)≥ly(k= , , . . . ,n)for tJ and yK,then

TλμyPC≥δ

ρρ

(lλρη)m

–

β+μnlyPC, (.)

whereβ=φm∗(

ζ e(τ)).

Proof By the definition ofK, ifyK, then we have

y(t)≥ onJ and min

t∈[ζ,]y(t)≥δ

ρ

ρ

yPC.

Since ≤tα(t)≤ onJ, it follows fromy(t)≥ onJthaty(α(t))≥.

Similarly, sinceζtα(t)≤ on [ζ, ], it follows frommint∈[ζ,]y(t)≥δρρyPCthat

min

t∈[ζ,]y

α(t) ≥δρρ

yPC.

Therefore,f(t,y(α(t)))≥lφm(y) fortJ, and it follows from the definition ofTλμand (.) that

TλμyPC≥ρφm

λ

ρe(τ)ω(τ),(τ)

+μρn

k=

Ik

tk,y(tk)

ρ(λρη)m

–

φm

e(τ),(τ)

+μρn

k=

Ik

tk,y(tk)

ρ(λρη)m

–

φm

e(τ)lφm

(τ)

+μρn

k=

ly(tk)

ρ(lλρη)m

–

φm

ζ

e(τ)φm

(τ)

+μρln

k=

y(tk)

ρ(lλρη)m

–

φm

ζ

e(τ)φm

δρρ

yPC

+μρln

k=

δρρ

yPC

=δρ

 

ρ

(lλρη)m

–

β+μnlyPC.

This completes the proof.

Lemma . Assume that(H)-(H)hold andα(t)≥t on J.If y∂r,r> ,then

TλμyPC≤ρ

φm

(11)

where

Mr= max tJ,≤yr

f(t,y)> , M∗=maxMk∗,k= , , . . . ,n> ,

Mk= max

tJ,≤yr

Ik(t,y), k= , , . . . ,n.

Proof Ify∂r, then y(t)≤rfortJ.

Since ≤tα(t)≤ onJ, it follows from ≤yrthat ≤(t) ≤r.

Therefore, fromf(t,y)≤MrfortJandy∂r, we have

ft,(t) ≤Mr. So, fory∂r, we have

TλμyPC≤ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

ρ

φm

λ

γe(τ)ω(τ),(τ)

+μ

n

k=

Ik

tk,y(tk)

ρ

φm

λγ

e(τ)ω(τ)Mrdτ

+μ

n

k=

M

=ρ

φm

λγMr

e(τ)ω(τ)

+μnM

ρ

φm

λγMreqωp +μnM∗ .

This gives the proof.

Corollary . When p= ,assume that(H)-(H)hold andα(t)≥t on J.If y∂r,r> ,

then

TλμyPC≤ρ

φm

λγMreω +μnM∗ .

Proof By Lemma ., leteωreplaceeqωpand repeat the argument above. Corollary . When p=∞,assume that(H)-(H)hold andα(t)≥t on J. If y∂r,

r> ,then

TλμyPC≤ρ

φm

λγMreω∞ +μnM∗ .

Proof By Lemma ., leteω∞replaceeqωpand repeat the argument above. Lemma . Assume that(H)-(H)hold andα(t)≥t on J.If y∂r,r> ,then

TλμyPC≥ρ(σrλρη)m

–

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where

σr= min tJ,≤yr

f(t,y)> , σ∗=min{mk,k= , , . . . ,n}> ,

σk= min tJ,≤yr

Ik(t,y), k= , , . . . ,n.

Proof Ify∂r, then y(t)≤rfortJ.

Since ≤tα(t)≤ onJ, it follows from ≤y(t)≤rfortJthat ≤(t) ≤r.

Therefore, fromf(t,y)≥σrfortJand ≤yr, we have

ft,(t) ≥σr. So, fory∂r, we have

TλμyPC≥ρφm

λ

ρe(τ)ω(τ),(τ)

+μρn

k=

Ik

tk,y(tk)

ρ(λρη)m

–

φm

e(τ),(τ)

+μρn

k=

Ik

tk,y(tk)

ρ(λρη)m

–

φm

e(τ)σrdτ

+μρn

k=

σr

ρ(σrλρη)m

–

φm

ζ

e(τ)

+μρnσr∗ =ρ(σrλρη)m

–

β+μρnσr∗.

This finishes the proof.

4 Main results for the case

α

(t)≥tonJ

In this section, we apply Lemma . to establish the existence, multiplicity and nonex-istence of positive solutions for problem (.). We consider the following three cases for

ωLp[, ]:p> ,p=  andp=. Casep>  is treated in the following theorem. Theorem . Assume that(H)-(H)hold andα(t)≥t on J.Then:

(a) Iff= andI(k) = orf= andI(k) = ,then there existλ

> andμ> 

such that problem(.)has a positive solution forλ>λandμ>μ.

(b) Iff=∞andI(k) =∞orf∞=∞andI∞(k) =∞,then there existλ> andμ> 

such that problem(.)has a positive solution for <λ<λand <μ<μ.

(c) Iff=f∞= andI(k) =I∞(k) = ,then there existλ> andμ> such that

problem(.)has at least two positive solutions forλ>λandμ>μ.

(d) Iff=f∞=∞andI∞(k) =I∞(k) =∞,then there existλ> andμ> such that

problem(.)has at least two positive solutions for <λ<λand <μ<μ.

(e) Iff<,I(k) <,f<andI<,then there existλ

> andμ> such

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(f ) Iff> ,I(k) > ,I∞> andf∞> ,then there existλ> andμ> such that

problem(.)has no positive solution forλ>λandμ> .

Proof Part (a). Choose a numberr> . By Lemma ., we haveT μ

λyPC>yPC for y∂r,λ>λandμ>μ, where

λ=

 ρβ

r

m–

(σrρη)–> , μ=  ρnσr∗

r> .

Iff=  andI(k) = , then from Lemma . we havef∗=  andI∗(k) = , and so we can chooser∈(,r) so thatf∗(r)≤εrandIk∗(r)≤εr, whereε>  andε>  respec-tively satisfy

ρφm

λγ εeqωp < , ρμnε< . (.)

Then Lemma . shows that

TλμyPC≤ρ

φm

λγ εeqωp +μnεyPC<yPC foryr.

Iff∞=  andI∞(k) = , then from Lemma .,f∗ =  andI(k) = . Hence, there exists

r∈(r,∞) such thatf∗(r)≤εrandIk(r)≤εr, whereε>  andε>  satisfies (.). Thus

TλμyPC≤ρ

φm

λγ εeqωp +μnεyPC<yPC foryr.

Therefore, it follows from Lemma . thatTλμhas a fixed point in¯r\r or¯r\r,

according to whetherf=  andI(k) =  orf=  andI(k) = , respectively. Conse-quently, problem (.) has a positive solution forλ>λandμ>μ.

Part (b). Choose a numberr> . By Lemma ., there existsλ>  such that

Tμ

λyPC<yPC foryr,  <λ<λand  <μ<μ,

where

λ=

 ρ

m–

γMreqωp –

, μ=  ρnM

.

Iff=∞andI(k) =∞, there existsr∈(,r) such thatf(t,y)≥lφm(y) andIk(t,y)≥ly fortJand ≤yr, wherel>  andl>  are chosen so that

δρ

 

ρ

(lλρη)m

–

β> , δρ

 

ρ

μnl> . (.)

Obviously,

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Then, from Lemma ., we can obtain

TλμyPC≥δ

ρρ

(lλρη)m

–

β+μnlyPC>yPC foryr.

Iff∞=∞andI∞(k) =∞, then there existsNˆ >  such thatf(t,y)≥lφm(y),Ik(t,y)≥ly (k= , , . . . ,n) fortJandy≥ ˆN, andl>  andl>  satisfy (.).

Letr=max{r,Nˆρ/δρ}. Ify∂r, then

min

t∈[ζ,]y(t)≥

δρ

ρ

yPC≥ ˆN.

So,

f(t,y)≥lφm(y), Ik(t,y)≥ly (k= , , . . . ,n) fortJandy∂r.

From Lemma ., we can get

TλμyPC≥δ

ρρ

(lλρη)m

–

β+μnlyPC>yPC foryr.

Therefore, it follows from Lemma . thatTλμhas a fixed point in¯r\r or¯r\r,

according to whetherf=∞andI(k) =∞orf∞=∞andI∞(k) =∞, respectively. Con-sequently, problem (.) has a positive solution for  <λ<λand  <μ<μ.

Part (c). Choose two numbers  <r<r. By Lemma ., there existλ>  andμ>  such that

TλμyPC>yPC foryri,i= , .

Sincef=f=  andI(k) =I(k) = , from the proof of part (a), it follows that we can chooser∈(,r/) andr∈(r,∞) such that

TλμyPC<yPC foryri,i= , .

It follows from Lemma . thatTλμhas two fixed pointsyandysuch thaty∈ ¯r\r

andy∈ ¯r\r. These are the desired distinct positive solutions of problem (.) for

λ>λandμ>μsatisfying

r≤ yPC≤r<ryPC≤r. (.)

Part (d). Choose two numbers  <r<r. By Lemma ., there existλ>  andμ>  such that

Tμ

λyPC<yPC for  <λ<λ,  <μ<μandyri,i= , .

Sincef=∞andf∞=∞andI∞(k) =I∞(k) =∞, from the proof of part (b), we know that we can chooser∈(,r/) andr∈(r,∞) such that

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It follows from Lemma . thatTλμhas two fixed pointsyandysuch thaty∈ ¯r\r

andy∈ ¯r\r. These are the desired distinct positive solutions of problem (.) for

 <λ<λand  <μ<μsatisfying (.).

Part (e). Sincef<,I(k) <,f<andI(k) <, there exist positive numbers

li>  (i= , , , ),h>  andh>  such thath<hand fortJ,  <yh, we have

f(t,y)≤lφm(y), Ik(t,y)≤ly and fortJ,yh, we have

f(t,y)≤lφm(y), Ik(t,y)≤ly. Let

l=max

l,l,max

f(t,y)

φm(y):tJ,h≤yh

> ,

l∗=max

l,l,max

Ik(t,y)

y :tJ,h≤yh

> .

Thus, we have

f(t,y)≤lφm(y), Ik(t,y)≤ly fortJandy∈[,∞).

Since ≤tα(t)≤ onJ, it follows from ≤y(t)≤h,y(t)≥handh≤y(t)≤hon

Jthat ≤y(α(t))≤h,y(α(t))≥handh≤y(α(t))≤honJ, respectively.

Assume thatyis a positive solution of problem (.). We will show that this leads to a contradiction for

 <λ<λ=

 ρ

m–

γleqωp –

and

 <μ<μ=  ρnl

.

Since (Tλμy)(t) =y(t) fortJ, by Lemma . we have that

yPC=Tλμy

PC≤ρ

φm

λγleqωp +μnlyPC<yPC,

which is a contradiction.

Part (f ). Sincef> ,I(k) > ,I∞>  andf∞> , there exist positive numbersli>  (i= , , , ),h>  andh>  such thath<hand fortJ, ≤yh, we have

f(t,y)≥lφm(y), Ik(t,y)≥ly, and fortJ,yh, we have

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Let

l∗∗=min

l,l,min

f(t,y)

φm(y):tJ,h≤yh

> ,

l∗∗∗=min

l,l,min

Ik(t,y)

y :tJ,h≤yh

> .

Then

f(t,y)≥l∗∗φm(y), Ik(t,y)≥l∗∗∗y fortJandy∈[,∞).

Assume thatyis a positive solution of problem (.). We will show that this leads to a contradiction for

λ>λ=

ρ δρβ

m–

l∗∗ρη –,

μ>μ=

ρ δρnl∗∗∗.

Since (Tλμy)(t) =y(t) fortJ, by Lemma . we have that

yPC=Tλμy

PC≥δ

ρρ

l∗∗λρη m∗–β+μnl∗∗∗ yPC>yPC,

which is a contradiction.

The results of the following theorem deal with the casep= .

Corollary . Assume that(H)-(H)hold andα(t)≥t on J.Then:

(a) Iff= andI(k) = orf= andI(k) = ,then there existλ

> andμ> 

such that problem(.)has a positive solution forλ>λandμ>μ.

(b) Iff=∞andI(k) =∞orf∞=∞andI∞(k) =∞,then there existλ> andμ> 

such that problem(.)has a positive solution for <λ<λand <μ<μ.

(c) Iff=f= andI(k) =I(k) = ,then there existλ

> andμ> such that

problem(.)has at least two positive solutions forλ>λandμ>μ.

(d) Iff=f∞=∞andI∞(k) =I∞(k) =∞,then there existλ> andμ> such that

problem(.)has at least two positive solutions for <λ<λand <μ<μ.

(e) Iff<,I(k) <,f<andI<,then there existλ

> andμ> such

that problem(.)has no positive solution for <λ<λand <μ<μ.

(f ) Iff> ,I(k) > ,I∞> andf∞> ,then there existλ> andμ> such that

problem(.)has no positive solution forλ>λandμ> .

Proof It follows from the proofs of Corollary . and Corollary . that Corollary .

holds.

Finally we consider the case ofp=∞.

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(a) Iff= andI(k) = orf= andI(k) = ,then there existλ

> andμ> 

such that problem(.)has a positive solution forλ>λandμ>μ.

(b) Iff=∞andI(k) =∞orf∞=∞andI∞(k) =∞,then there existλ> andμ> 

such that problem(.)has a positive solution for <λ<λand <μ<μ.

(c) Iff=f= andI(k) =I(k) = ,then there existλ

> andμ> such that

problem(.)has at least two positive solutions forλ>λandμ>μ.

(d) Iff=f∞=∞andI∞(k) =I∞(k) =∞,then there existλ> andμ> such that

problem(.)has at least two positive solutions for <λ<λand <μ<μ.

(e) Iff<,I(k) <,f<andI<,then there existλ

> andμ> such

that problem(.)has no positive solution for <λ<λand <μ<μ.

(f ) Iff> ,I(k) > ,I∞> andf∞> ,then there existλ> andμ> such that

problem(.)has no positive solution forλ>λandμ> .

Proof It follows from the proofs of Corollary . and Corollary . that Corollary .

holds.

5 Positive solutions of problem (1.1) for the case of

α

(t)≤tonJ

Now we deal with problem (.) for the case ofα(t)≤tonJ. Similarly as Theorem . and Lemmas .-., we can prove the following results.

Lemma . Letζ∗∈(tn, ),Gand Hbe given as in Theorem..If(H)holds,then we

have

G(t,s)≥δG(s,s)≥

bδ

d , H(t,s)≥

δa

aξG(s,s)≥δρ, ∀t

,ζ∗,sJ, (.)

where d is defined in Theorem.,δandρare defined in(.).

Proof In fact, fort∈[,ζ∗] andsJ, we have that

G(t,s)

G(s,s)

=b+a( –t)

b+a( –s)≥

b+a( –ζ∗)

b+a forst,

G(t,s)

G(s,s)

=b+at

b+asb

b+a forts.

This and (.) show that

H(t,s)≥δG(s,s)

 + 

aξ

g(τ)

aξG(s,s), t

,ζ∗,sJ.

This together with (.) and (.) finishes the proof of (.).

LetPC[, ] be as defined in Section . We define a coneKinPC[, ] by

K∗=

yPC[, ]y(t)≥ onJand min

t∈[,ζ∗]≥δ

ρ

ρ

yPC

,

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Define∗Tλμ:K∗→PC[, ] by

Tλμy(t) =

H(t,s)φm

λ

H(s,τ)ω(τ),(τ)

ds +μ n k=

H(t,tk)Ik

tk,y(tk) . (.)

It is clear thatyis a positive solution of problem (.) if and only ofyis a fixed point of∗Tλμ.

Lemma . Assume that(H)-(H)hold.Then yKis a positive fixed point ofTλμ if

and only if y is a positive solution of problem(.).

Lemma . Assume that(H)-(H)hold.ThenTλμ(K∗)⊂KandT μ

λ :K∗→Kis

com-pletely continuous.

Letf∗andIk∗be defined as in Section . Similar to the proof of that in Lemmas .-., we have the following results. Here, we only consider the casem>  and only give the proof of Lemma ..

Lemma . Assume that(H)-(H)hold,α(t)≤t on J and let r> be given.If there exist

ε> andε> such that f∗(r)≤εφm(r)and Ik∗(r)≤εr(k= , , . . . ,n),then

Tμ λyρ

φm

λγ εeqωp +μnεyPC, y∂r. (.) Proof By the definition off∗(r) andIk∗, iff∗(r)≤εφm(r) andIk∗(r)≤εr(k= , , . . . ,n), then

f(t,y)≤εφm(r), Ik(t,y)≤εr fortJand ≤yr.

Since ≤α(t)≤t≤ onJ, it follows from ≤y(t)≤ronJthat ≤y(α(t))≤r. Therefore, we havef(t,y(α(t)))≤εφm(r) fortJ, and it follows from (.) and (.) that

Tμ

λyPC≤ρ

φm

λ

H(s,τ)ω(τ),(τ)

ds+μ

n

k=

Ik

tk,y(tk)

ρ

φm

λ

γe(τ)ω(τ),(τ)

+μ n k= Ik tk,y(tk)

ρ

φm

λγ

e(τ)ω(τ)εφm(r)

+μ

n

k=

εr

=ρ

φm

λγ εφm(r)

e(τ)ω(τ)

+μ

n

k=

εr

ρ

φm

λγ εφm(r)eqωp +μnεr =ρ

φm

λγ εeqωp +μnεr yPC, ∀y∂r.

(19)

Lemma . Assume that(H)-(H)hold,α(t)≤t on J and let l> and lbe given.If

f(t,y)≥lφm(y)and Ik(t,y)≥ly for tJ and yK∗,then

Tμ

λyPC≥δ

ρρ

(lλρη)m

–

β+μnlyPC.

Letˆr={yK∗:yPC<r}.

Lemma . Assume that(H)-(H)hold andα(t)≤t on J.If yˆr,r> ,then

Tμ

λyPC≤ρ

φm

λγMreqωp +μnM∗ ,

where Mrand Mare defined in Lemma..

Lemma . Assume that(H)-(H)hold andα(t)≤t on J.If yˆr,r> ,then

T

λuPC≥ρ(σrλρη)m

–

β+μρnσr∗,

whereσrandσare defined in Lemma.. Letf,f,f

,f∞,I(k),I∞(k),I(k) andI∞(k) be defined as in Section . Similar to the proof of Theorem ., we have the following results.

Theorem . Assume that(H)-(H)hold andα(t)≤t on J.Then:

(a) Iff= andI(k) = orf= andI(k) = ,then there existλ

> andμ> 

such that problem(.)has a positive solution forλ>λandμ>μ.

(b) Iff=∞andI(k) =∞orf∞=∞andI∞(k) =∞,then there existλ> andμ> 

such that problem(.)has a positive solution for <λ<λand <μ<μ.

(c) Iff=f= andI(k) =I(k) = ,then there existλ

> andμ> such that

problem(.)has at least two positive solutions forλ>λandμ>μ.

(d) Iff=f∞=∞andI∞(k) =I∞(k) =∞,then there existλ> andμ> such that

problem(.)has at least two positive solutions for <λ<λand <μ<μ.

(e) Iff<∞,I(k) <∞,f∞<∞andI∞<∞,then there existλ> andμ> such

that problem(.)has no positive solution for <λ<λand <μ<μ.

(f ) Iff> ,I(k) > ,I∞> andf∞> ,then there existλ> andμ> such that

problem(.)has no positive solution forλ>λandμ> .

6 Remarks and comments

In this section, we offer some remarks and comments of the associated problem (.).

Remark . The idea of deviating arguments for problem (.) is from Jankowski [],

but the method and conclusion are quite different, and Jankowski only considered the caseλ= ,μ=  andωC[, ], notω(t) isLp-integrable.

Remark . Generally, it is difficult to study the existence of positive solutions for

References

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