High Performance Computing for Science and Engineering II
11.5.2020 - Lecture: Parallel Reduction (GPU)
Lecturer: Dr. Sergio Martin
Today's Class
Optimizations:
- Improving Warp Efficiency
- Improving Memory Bank Access
- Addressing Instruction Bottlenecks The Reduction Pattern
- Principles and parallel approach pattern.
- Cost and Complexity
- Brent's Theorem
Algorithm Cascading:
Vector Reduction
Fact: Some problems require reading from an entire array but write to a smaller set.
Example: Vector reduction
double mySum = 0.0;
for (int i = 0; i < N; i++) mySum += vector[i];
10 Inputs
1 Output
Sum: 45
Parallel Vector Reduction
Thread 1 Thread 2
T1Sum: 25 T2Sum: 20
Sum: 45
Barrier
Distributed Parallel Vector Reduction
Thread 1 Thread 2
T1Sum: 25 T2Sum: 20
Sum: 45
Barrier
Thread 1 Thread 2
T1Sum: 25 T2Sum: 20
Sum: 45
Barrier
Node 0 Node 1
Sum: 90
MPI_Reduce
Tree-like Pattern
(also within MPI)
Optimizing Parallel Reduction in CUDA
Mark Harris
NVIDIA Developer Technology
The next set of slides are adapted from the presentation:
Parallel Reduction
Common and important data parallel primitive Easy to implement in CUDA
- Harder to get it right
Serves as a great optimization example
- We’ll walk step by step through 7 different versions
- Demonstrates several important optimization strategies
!7
Parallel Reduction Complexity
Log(N) parallel steps, each step S does N/2
Sindependent ops:
- Step Complexity is O(log N)
For N=2
D, performs ∑
S∈[1..D]2
D-S= N-1 operations
- Work Complexity is O(N) – It is work-efficient- i.e. does not perform more operations than a sequential algorithm
With P threads physically in parallel (P processors), time complexity is O(N/P + log N)
-
Compare to O(N) for sequential reductionGPU Parallel Reduction
Need to be able to use multiple thread blocks -
To process very large arrays- To keep all multiprocessors on the GPU busy
- Each thread block reduces a portion of the array
But how do we communicate partial results between thread blocks?
!9
4 7 5 9
Tree-based approach used within each thread block
3 1 7 0 4 1 6 3
11 14
25
Block
Problem: Global Synchronization
If we could synchronize across all thread blocks, could easily reduce very large arrays.
- Global sync after each block produces its result - Once all blocks reach sync, continue recursively
But CUDA has no global synchronization. Why?
- Expensive to build in hardware for GPUs with high processor count...
- Would force programmer to run fewer blocks to avoid deadlock, which may reduce overall efficiency (no more than # multiprocessors * # resident blocks / multiprocessor)
Solution: decompose into multiple kernels
- Kernel launch serves as a global synchronization point.
- Kernel launch has negligible HW overhead, low SW overhead
Solution: Kernel Decomposition
Avoid global sync by decomposing computation into multiple kernel invocations
In the case of reductions, code for all levels is the same
Recursive kernel invocation
25
Level 0:
8 blocks
!11
Level 1:
1 block
25 25 25 25 25 25 25 25 25
50 50 50 50 100 100
200
3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3 3 1 7 0 4 1 6 3
4 7 5 9 4 7 5 9 4 7 5 9 4 7 5 9 4 7 5 9 4 7 5 9 4 7 5 9 4 7 5 9
11 14 11 14 11 14 11 14 11 14 11 14 11 14 11 14
25 25 25 25 25 25 25 25
What is Our Optimization Goal?
We should strive to reach GPU peak performance.
Choose the right metric:
- GFLOP/s: for compute-bound kernels - Bandwidth: for memory-bound kernels
Reductions have very low arithmetic intensity:
- 1 flop per element loaded (bandwidth-optimal) - Therefore we should strive for peak bandwidth
Will use G80 GPU for this example:
-
384-bit memory interface, 900 MHz DDR 384 * 1800 / 8 = 86.4 GB/sReduction #1: Interleaved Addressing
!13
__global__ void reduce0(int *g_idata, int *g_odata) {
extern __shared__int sdata[];
// each thread loads one element from global to shared mem unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*blockDim.x + threadIdx.x;
sdata[tid] = g_idata[i];
__syncthreads();
// do reduction in shared mem
for(unsigned int s=1; s < blockDim.x; s *= 2) {
if (tid % (2*s) == 0)
sdata[tid] += sdata[tid + s];
__syncthreads();
}
// write result for this block to global mem if (tid == 0) g_odata[blockIdx.x] = sdata[0];
}
Parallel Reduction: Interleaved Addressing
10 1 8 -1 0 -2 3 5 -2 -3 2 7 0 11 0 2
Values (shared memory)
0 2 4 6 8 10 12 14
11 1 7 -1 -2 -2 8 5 -5 -3 9 7 11 11 2 2
0 4 8 12
18 1 7 -1 6 -2 8 5 4 -3 9 7 13 11 2 2
0 8
24 1 7 -1 6 -2 8 5 17 -3 9 7 13 11 2 2
0
41 1 7 -1 6 -2 8 5 17 -3 9 7 13 11 2 2
Step 1 Stride 1
Step 2 Stride 2
Step 3 Stride 4
Step 4 Stride 8
Thread IDs Values Thread
IDs Values Thread
IDs Values Thread
IDs Values
Reduction #1: Interleaved Addressing
!15
__global__ void reduce0(int *g_idata, int *g_odata) {
extern __shared__int sdata[];
// each thread loads one element from global to shared mem unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*blockDim.x + threadIdx.x;
sdata[tid] = g_idata[i];
__syncthreads();
// do reduction in shared mem
for(unsigned int s=1; s < blockDim.x; s *= 2) {
if (tid % (2*s) == 0)
sdata[tid] += sdata[tid + s];
__syncthreads();
}
// write result for this block to global mem if (tid == 0) g_odata[blockIdx.x] = sdata[0];
}
Problem: highly divergent
warps are very inefficient, and
% operator is very slow
Performance for 4M element reduction
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Note: Block Size = 128 threads for all tests
Bandwidth Time (222 ints)
for (unsigned int s=1; s < blockDim.x; s *= 2 {
if (tid % (2*s) == 0) sdata[tid] += sdata[tid + s];
__syncthreads();
}
Reduction #2: Interleaved Addressing
!17
Just replace divergent branch in inner loop:
for (unsigned int s=1; s < blockDim.x; s *= 2) {
int index = 2 * s * tid;
if (index < blockDim.x) sdata[index] += sdata[index + s];
__syncthreads();
}
With strided index and non-divergent branch:
Parallel Reduction: Interleaved Addressing
10 1 8 -1 0 -2 3 5 -2 -3 2 7 0 11 0 2
Values (shared memory)
0 1 2 3 4 5 6 7
11 1 7 -1 -2 -2 8 5 -5 -3 9 7 11 11 2 2
0 1 2 3
18 1 7 -1 6 -2 8 5 4 -3 9 7 13 11 2 2
0 1
24 1 7 -1 6 -2 8 5 17 -3 9 7 13 11 2 2
0
41 1 7 -1 6 -2 8 5 17 -3 9 7 13 11 2 2
Step 1 Stride 1
Step 2 Stride 2
Step 3 Stride 4
Step 4 Stride 8
Thread IDs Values Thread
IDs Values Thread
IDs Values Thread
IDs Values
New Problem: Shared Memory Bank Conflicts
Performance for 4M element reduction
!19
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
Parallel Reduction: Sequential Addressing
10 1 8 -1 0 -2 3 5 -2 -3 2 7 0 11 0 2
Values (shared memory)
Values
0 1 2 3 4 5 6 7
8 -2 10 6 0 9 3 7 -2 -3 2 7 0 11 0 2
0 1 2 3
8 7 13 13 0 9 3 7 -2 -3 2 7 0 11 0 2
0
21 20 13 13 0 9 3 7 -2 -3 2 7 0 11 0 2
41 20 13 13 0 9 3 7 -2 -3 2 7 0 11 0 2
Thread Step 1 IDs
Stride 8
Step 2 Stride 4
Step 3 Stride 2
Step 4 Stride 1
Thread IDs
Values Thread
IDs Values Thread
IDs Values
Sequential addressing is conflict free
1
0
for (unsigned int s=1; s < blockDim.x; s *= 2) {
int index = 2 * s * tid;
if (index < blockDim.x) sdata[index] += sdata[index + s];
__syncthreads();
}
Reduction #3: Sequential Addressing
!21
Just replace strided indexing in inner loop:
for (unsigned int s=blockDim.x/2; s>0; s>>=1) {
if (tid < s) sdata[tid] += sdata[tid + s];
__syncthreads();
}
With reversed loop and threadID-based indexing:
Performance for 4M element reduction
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Kernel 3:
sequential addressing
1.722 ms 9.741 GB/s 2.01x 4.68x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
for (unsigned int s=blockDim.x/2; s>0; s>>=1 {
if (tid < s) sdata[tid] += sdata[tid + s];
__syncthreads();
}
Problem: Idle Threads
!23
Problem:
Half of the threads are idle on first loop iteration!
This is wasteful…
// each thread loads one element from global to shared mem unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*blockDim.x + threadIdx.x;
sdata[tid] = g_idata[i];
__syncthreads();
Reduction #4: First Add During Load
Halve the number of blocks, and replace single load:
// perform first level of reduction,
// reading from global memory, writing to shared memory unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockDim.x*2) + threadIdx.x;
sdata[tid] = g_idata[i] + g_idata[i+blockDim.x];
__syncthreads();
With two loads and first add of the reduction:
Performance for 4M element reduction
!25
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Kernel 3:
sequential addressing
1.722 ms 9.741 GB/s 2.01x 4.68x Kernel 4:
first add during global load
0.965 ms 17.377 GB/s 1.78x 8.34x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
Instruction Bottleneck
At 17 GB/s, we’re far from bandwidth bound -
And we know reduction has low arithmetic intensityTherefore a likely bottleneck is instruction overhead
-
Ancillary instructions that are not loads, stores, or arithmetic for the core computation - In other words: address arithmetic and loop overheadStrategy: unroll loops
Unrolling the Last Warp
As reduction proceeds, # “active” threads decreases -
When s <= 32, we have only one warp leftInstructions are SIMD synchronous within a warp.
- That means when s<=32 (depending on architecture)
-
We don’t need to __syncthreads()- We don’t need “if (tid < s)” because it doesn’t save any work
Let’s unroll the last 6 iterations of the inner loop
!27
__device__ void warpReduce(volatile int* sdata, int tid) { sdata[tid] += sdata[tid + 32];
sdata[tid] += sdata[tid + 16];
sdata[tid] += sdata[tid + 8];
sdata[tid] += sdata[tid + 4];
sdata[tid] += sdata[tid + 2];
sdata[tid] += sdata[tid + 1];
}
// later…
for (unsigned int s=blockDim.x/2; s>32; s>>=1) { if (tid < s)
sdata[tid] += sdata[tid + s];
syncthreads();
}
if (tid < 32) warpReduce(sdata, tid);
Reduction #5: Unroll the Last Warp
Note: This saves useless work in all warps, not just the last one!
Without unrolling, all warps execute every iteration of the for loop and if statement IMPORTANT:
For this to be correct, we must use the
“volatile” keyword! This prevents concurrency-unaware compiler
optimizations
Performance for 4M element reduction
!29
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Kernel 3:
sequential addressing
1.722 ms 9.741 GB/s 2.01x 4.68x Kernel 4:
first add during global load
0.965 ms 17.377 GB/s 1.78x 8.34x Kernel 5:
unroll last warp
0.536 ms 31.289 GB/s 1.8x 15.01x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
Complete Unrolling
If we knew the number of iterations at compile time, we could completely unroll the reduction
-
Luckily, the block size is limited by the GPU to 512 threads - Also, we are sticking to power-of-2 block sizesSo we can easily unroll for a fixed block size -
But we need to be generic
-
How can we unroll for block sizes that we don’t know at compile time?Templates to the rescue!
- CUDA supports C++ template parameters on device and host functions
Unrolling with Templates
Specify block size as a function template parameter:
!31
template <unsigned int blockSize>
global void reduce5(int *g_idata, int *g_odata)
Reduction #6: Completely Unrolled
if (blockSize >= 512) {
if (tid < 256) { sdata[tid] += sdata[tid + 256]; } __syncthreads(); } if (blockSize >= 256) {
if (tid < 128) { sdata[tid] += sdata[tid + 128]; } __syncthreads(); } if (blockSize >= 128) {
if (tid < 64) { sdata[tid] += sdata[tid + 64]; } __syncthreads(); } if (tid < 32) warpReduce<blockSize>(sdata, tid);
Note: all code in RED will be evaluated at compile time.
Results in a very efficient inner loop!
template <unsigned int blockSize>
__device__ void warpReduce(volatile int* sdata, int tid) { if (blockSize >= 64) sdata[tid] += sdata[tid + 32];
if (blockSize >= 32) sdata[tid] += sdata[tid + 16];
if (blockSize >= 16) sdata[tid] += sdata[tid + 8];
if (blockSize >=
if (blockSize >=
if (blockSize >=
8) sdata[tid] += sdata[tid + 4];
4) sdata[tid] += sdata[tid + 2];
2) sdata[tid] += sdata[tid + 1];
}
27
Invoking Template Kernels
Don’t we still need block size at compile time?
Nope, just a switch statement for 10 possible block sizes:
switch (threads) {
case 512:
reduce5<512><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 256:
reduce5<256><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 128:
reduce5<128><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 64:
reduce5< 64><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 32:
reduce5< 32><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 16:
reduce5< 16><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
case 8:
8><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
4><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
2><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
1><<< dimGrid, dimBlock, smemSize >>>(d_idata, d_odata); break;
reduce5<
case 4:
reduce5<
case 2:
reduce5<
case 1:
reduce5<
}
Performance for 4M element reduction
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Kernel 3:
sequential addressing
1.722 ms 9.741 GB/s 2.01x 4.68x Kernel 4:
first add during global load
0.965 ms 17.377 GB/s 1.78x 8.34x Kernel 5:
unroll last warp
0.536 ms 31.289 GB/s 1.8x 15.01x Kernel 6:
completely unrolled
0.381 ms 43.996 GB/s 1.41x 21.16x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
What About Cost?
Cost of a parallel algorithm is processor's time complexity
Allocate threads instead of processors: O(N) threads
Time complexity is O(log N), so cost is O(N log N) : not cost efficient!
!35
Cost = Time * # Threads
Brent's Theorem
What About Cost?
Cost of a parallel algorithm is processor's time complexity
Allocate threads instead of processors: O(N) threads
Time complexity is O(log N), so cost is O(N log N) : not cost efficient!
!37
Brent’s theorem suggests O(N/log N) threads
Each thread does O(log N) sequential work
Then all O(N/log N) threads cooperate for O(log N) steps Cost = O((N/log N) * log N) = O(N) ! cost efficient
Sometimes called algorithm cascading
Can lead to significant speedups in practice
Algorithm Cascading
Combine sequential and parallel reduction
Each thread loads and sums multiple elements into shared memory Tree-based reduction in shared memory
Brent’s theorem says each thread should sum O(logN) elements
i.e. 1024 or 2048 elements per block vs. 256
In my experience, beneficial to push it even further
Possibly better latency hiding with more work per thread
More threads per block reduces levels in tree of recursive kernel invocation
High kernel launch overhead in last levels with few blocks
On G80, best perf with 64-256 blocks of 128 threads (1024-4096 elements per thread)
unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockDim.x*2) + threadIdx.x;
sdata[tid] = g_idata[i] + g_idata[i+blockDim.x];
__syncthreads();
Reduction #7: Multiple Adds / Thread
while (i < n) {
sdata[tid] += g_idata[i] + g_idata[i+blockSize];
i += gridSize;
}
__syncthreads();
!39
Replace load and add of two elements:
With a while loop to add as many as necessary:
unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockSize*2) + threadIdx.x;
unsigned int gridSize = blockSize*2*gridDim.x;
sdata[tid] = 0;
unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockDim.x*2) + threadIdx.x;
sdata[tid] = g_idata[i] + g_idata[i+blockDim.x];
syncthreads();
Reduction #7: Multiple Adds / Thread
Replace load and add of two elements:
unsigned int gridSize = blockSize*2*gridDim.x;
sdata[tid] = 0;
With a while loop to add as many as necessary:
unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockSize*2)+threadIdx.x;
while (i < n) {
sdata[tid] += g_idata[i] + g_idata[i+blockSize];
i += gridSize;
}
syncthreads();
Use Grid Size Loop Stride
to maintain coalescing!
Performance for 4M element reduction
Kernel 7 on 32M elements: 73 GB/s!
!41
Kernel 1:
interleaved addressing with divergent branching
8.054 ms 2.083 GB/s
Kernel 2:
interleaved addressing with bank conflicts
3.456 ms 4.854 GB/s 2.33x 2.33x
Kernel 3:
sequential addressing
1.722 ms 9.741 GB/s 2.01x 4.68x Kernel 4:
first add during global load
0.965 ms 17.377 GB/s 1.78x 8.34x Kernel 5:
unroll last warp
0.536 ms 31.289 GB/s 1.8x 15.01x Kernel 6:
completely unrolled
0.381 ms 43.996 GB/s 1.41x 21.16x Kernel 7:
multiple elements per thread
0.268 ms 62.671 GB/s 1.42x 30.04x
Step Speedup Bandwidth
Time (222 ints) Cumulative
Speedup
template <unsigned int blockSize> __device__ void warpReduce(volatile int *sdata, unsigned int tid) {
if (blockSize >= 64) sdata[tid] += sdata[tid + 32];
if (blockSize >= 32) sdata[tid] += sdata[tid + 16];
if (blockSize >= 16) sdata[tid] += sdata[tid + 8];
if (blockSize >=
if (blockSize >=
if (blockSize >=
8) sdata[tid] += sdata[tid + 4];
4) sdata[tid] += sdata[tid + 2];
2) sdata[tid] += sdata[tid + 1];
}
template <unsigned int blockSize> global void reduce6(int *g_idata, int *g_odata, unsigned int n) {
extern shared int sdata[];
unsigned int tid = threadIdx.x;
unsigned int i = blockIdx.x*(blockSize*2) + tid;
unsigned int gridSize = blockSize*2*gridDim.x; sdata[tid] = 0;
while (i < n) { sdata[tid] += g_idata[i] + g_idata[i+blockSize]; i += gridSize; } __syncthreads();
if (blockSize >= 512) { if (tid < 256) { sdata[tid] += sdata[tid + 256]; } __syncthreads(); } if (blockSize >= 256) { if (tid < 128) { sdata[tid] += sdata[tid + 128]; } __syncthreads(); } if (blockSize >= 128) { if (tid < 64) { sdata[tid] += sdata[tid + 64]; } __syncthreads(); } if (tid < 32) warpReduce(sdata, tid);
if (tid == 0) g_odata[blockIdx.x] = sdata[0];
}
Final Optimized Kernel
Performance Comparison
0.01 0.1 1 10
131072
262144
524288
1048576
2097152
4194304
8388608
16777216
33554432
# Elements
Time (ms)
1: Interleaved Addressing: Divergent Branches
2: Interleaved Addressing: Bank Conflicts
3: Sequential Addressing
4: First add during global load
5: Unroll last warp
6: Completely unroll
7: Multiple elements per thread (max 64 blocks)
!43
Types of optimization
Interesting observation:
Algorithmic optimizations
Changes to addressing, algorithm cascading 11.84x speedup, combined!
Code optimizations
Loop unrolling
2.54x speedup, combined
Conclusion
Understand CUDA performance characteristics
Memory coalescing Divergent branching Bank conflicts
Latency hiding
Use peak performance metrics to guide optimization Understand parallel algorithm complexity theory
Know how to identify type of bottleneck
e.g. memory, core computation, or instruction overhead
Optimize your algorithm, then unroll loops
Use template parameters to generate optimal code
!45