R E S E A R C H
Open Access
Best proximity point theorems for
generalized contractions in partially ordered
metric spaces
Jingling Zhang, Yongfu Su
*and Qingqing Cheng
*Correspondence:
suyongfu@gmail.com; suyongfu@tjpu.edu.cn
Department of Mathematics, Tianjin Polytechnic University, Tianjin, 300387, P.R. China
Abstract
The purpose of this paper is to obtain four best proximity point theorems for generalized contractions in partially ordered metric spaces. Further, ourP-operator technique, which changes a non-self mapping to a self-mapping, plays an important role. Some recent results in this area have been improved.
MSC: 47H05; 47H09; 47H10
Keywords: generalized contraction; fixed point; best proximity point; weak P-monotone property
1 Introduction and preliminaries
LetAandBbe nonempty subsets of a metric space (X,d). An operatorT:A→Bis said to be contractive if there existsk∈[, ) such thatd(Tx,Ty)≤kd(x,y) for anyx,y∈A. The well-known Banach contraction principle is as follows: Let (X,d) be a complete metric space, and letT:X→Xbe a contraction ofXinto itself. ThenThas a unique fixed point inX.
In the sequel, we denote byΓ the functionsβ: [,∞)→[, ) satisfying the following condition:
β(tn)→ ⇒ tn→.
In , Geraghty introduced the Geraghty-contraction and obtained Theorem . as fol-lows.
Definition .[] Let (X,d) be a metric space. A mappingT :X→X is said to be a
Geraghty-contractionif there existsβ∈Γ such that for anyx,y∈X,
d(Tx,Ty)≤βd(x,y)d(x,y).
Theorem .[] Let(X,d)be a complete metric space,and let T:X→X be an operator.
Suppose that there existsβ∈Γ such that for any x,y∈X,
d(Tx,Ty)≤βd(x,y)d(x,y).
Then T has a unique fixed point.
Obviously, Theorem . is an extensive version of the Banach contraction principle. Re-cently, the generalized contraction principle has been studied by many authors in metric spaces or more generalized metric spaces. Some results have been got in partially ordered metric spaces as follows.
Theorem .[] Let(X,≤)be a partially ordered set,and suppose that there exists a
met-ric d such that(X,d)is a complete metric space.Let f :X→X be an increasing mapping such that there exists an element x∈X with x≤f(x).Suppose that there existsβ∈Γ such that
df(x),f(y)≤βd(x,y)d(x,y), ∀y≥x.
Assume that either f is continuous or X is such that if an increasing sequence xn→x∈X, then xn≤x,∀n.Besides,if for each x,y∈X,there exists z∈X which is comparable to x and y,then f has a unique fixed point.
Theorem .[] Let(X,≤)be a partially ordered set,and suppose that there exists a met-ric d∈X such that(X,d)is a complete metric space.Let f :X→X be a continuous and nondecreasing mapping such that
df(x),f(y)≤d(x,y) –ψd(x,y) for y≥x,
whereψ: [,∞)→[,∞)is a continuous and nondecreasing function such thatψis pos-itive in(,∞),ψ() = andlimt→∞ψ(t) =∞.If there exists x∈X with x≤f(x),then f has a fixed point.
Definition .[] An altering distance function is a functionψ: [,∞)→[,∞) which
satisfies
(i) ψis continuous and nondecreasing. (ii) ψ(t) = if and only ift= .
Theorem .[] Let X be a partially ordered set,and suppose that there exists a metric d in X such that(X,d)is a complete metric space. Let T:X→X be a continuous and nondecreasing mapping such that
ψd(Tx,Ty)≤φd(x,y), ∀y≥x,
whereψis an altering distance function andφ: [,∞)→[,∞)is a continuous function with the conditionψ(t) >φ(t)for all t> .If there exists x∈X such that x≤Tx,then T has a fixed point.
Theorem .[] Let(X,≤)be a partially ordered set,and suppose that there exists a met-ric d∈X such that(X,d)is a complete metric space.Let f :X→X be a continuous and nondecreasing mapping such that
whereψandφare altering distance functions.If there exists x∈X with x≤f(x),then f has a fixed point.
In , Caballeroet al.introduced a generalized Geraghty-contraction as follows.
Definition .[] LetA,Bbe two nonempty subsets of a metric space (X,d). A mapping
T :A→Bis said to be aGeraghty-contractionif there exists β∈Γ such that for any
x,y∈A,
d(Tx,Ty)≤βd(x,y)d(x,y).
Now we need the following notations and basic facts. LetAandBbe two nonempty subsets of a metric space (X,d). We denote byAandBthe following sets:
A=x∈A:d(x,y) =d(A,B) for somey∈B,
B=y∈B:d(x,y) =d(A,B) for somex∈A,
whered(A,B) =inf{d(x,y) :x∈Aandy∈B}.
In [], the authors give sufficient conditions for when the setsAandBare nonempty. In [], the authors prove that any pair (A,B) of nonempty, closed convex subsets of a uni-formly convex Banach space satisfies theP-property.
Definition .[] Let (A,B) be a pair of nonempty subsets of a metric space (X,d) with
A=∅. Then the pair (A,B) is said to have theP-propertyif and only if for anyx,x∈A
andy,y∈B,
⎧ ⎨ ⎩
d(x,y) =d(A,B)
d(x,y) =d(A,B) ⇒ d(x,x) =d(y,y).
LetA,Bbe two nonempty subsets of a complete metric space, and consider a mapping
T :A→B. The best proximity point problem is whether we can find an elementx∈A
such thatd(x,Tx) =min{d(x,Tx) :x∈A}. Sinced(x,Tx)≥d(A,B) for anyx∈A, in fact, the optimal solution to this problem is the one for which the valued(A,B) is attained.
In [], the authors give a generalization of Theorem . by considering a non-self map-ping, and they get the following theorem.
Theorem .[] Let(A,B)be a pair of nonempty closed subsets of a complete metric
space(X,d)such that Ais nonempty.Let T:A→B be a Geraghty-contraction satisfying T(A)⊆B.Suppose that the pair(A,B)has the P-property.Then there exists a unique x* in A such that d(x*,Tx*) =d(A,B).
2 Main results
Before giving our main results, we first introduce the weakP-monotone property.
Weak P-monotone property Let (A,B) be a pair of nonempty subsets of a partially ordered metric space (X,d) with A=∅. Then the pair (A,B) is said to have theweak P-monotone propertyif for anyx,x∈Aandy,y∈B,
⎧ ⎨ ⎩
d(x,y) =d(A,B)
d(x,y) =d(A,B)
⇒ d(x,x)≤d(y,y);
furthermore,y≥yimpliesx≥x.
Now we are in a position to give our main results.
Theorem . Let(X,≤)be a partially ordered set, and let(X,d)be a complete metric space.Let(A,B)be a pair of nonempty closed subsets of X such that A=∅.Let f :A→B be an increasing mapping with f(A)⊆B,and let there existβ∈Γ such that
df(x),f(y)≤βd(x,y)d(x,y), ∀y≥x.
Assume that either f is continuous or that Ais such that if an increasing sequence xn→x∈ A,then xn≤x,∀n.Suppose that the pair(A,B)has the weak P-monotone property.And for some x∈A,there existsxˆ ∈Bsuch that d(x,xˆ ) =d(A,B)andxˆ ≤f(x).Besides,
if for each x,y∈A,there exists z∈Awhich is comparable to x and y,then there exists an x*in A such that d(x*,fx*) =d(A,B).
Proof We first prove thatBis closed. Let{yn} ⊆Bbe a sequence such thatyn→q∈B.
It follows from the weakP-monotone property that
d(yn,ym)→ ⇒ d(xn,xm)→,
asn,m→ ∞, wherexn,xm∈Aandd(xn,yn) =d(A,B),d(xm,ym) =d(A,B). Then{xn}is a
Cauchy sequence so that{xn}converges strongly to a pointp∈A. By the continuity of a
metricd, we haved(p,q) =d(A,B), that is,q∈B, and henceBis closed.
LetAbe the closure ofA, we claim thatf(A)⊆B. In fact, ifx∈A\A, then there exists a sequence{xn} ⊆Asuch thatxn→x. By the continuity off and the closeness of B, we havefx=limn→∞fxn∈B. That is,f(A)⊆B.
Define an operatorPA:f(A)→A, byPAy={x∈A:d(x,y) =d(A,B)}. Since the pair (A,B) has the weakP-monotone property andf is increasing, we have
d(PAfx,PAfy)≤d(fx,fy)≤β
d(x,y)d(x,y), PAfy≥PAfx,
for anyy≥x∈A. Obviously,PAf is increasing. Letxn,x∈A,xn→x, whenf is contin-uous, then we have
ThenPAf is continuous. WhenAis such that if an increasing sequencexn→x∈A, thenxn≤x(∀n), we need not prove the continuity ofPAf. For somex∈A, there exists
ˆ
x∈Bsuch thatd(x,xˆ ) =d(A,B) andxˆ ≤f(x). That is,
d(x,xˆ ) =d(A,B), d(PAfx,fx) =d(A,B), xˆ ≤f(x).
By the weakP-monotone property, we havePAfx≥x.
This shows thatPAf :A→Ais a contraction satisfying all the conditions in The-orem .. Using TheThe-orem ., we can get PAf has a unique fixed point x
*. That is,
PAfx*=x*∈A, which implies that
dx*,fx*=d(A,B).
Therefore,x*is the unique one inAsuch thatd(x*,fx*) =d(A,B).
Theorem . Let(X,≤)be a partially ordered set,and let(X,d)be a complete metric space.Let(A,B)be a pair of nonempty closed subsets of X such that A=∅.Let f :A→B be a continuous and nondecreasing mapping with f(A)⊆B,and let f satisfy
df(x),f(y)≤d(x,y) –ψd(x,y) for y≥x,
whereψ: [,∞)→[,∞)is a continuous and nondecreasing function such thatψis pos-itive in(,∞),ψ() = andlimt→∞ψ(t) =∞.Suppose that the pair(A,B)has the weak P-monotone property.If for some x∈A,there existsxˆ ∈Bsuch that d(x,xˆ ) =d(A,B)
andxˆ≤f(x),then there exists an x*in A such that d(x*,fx*) =d(A,B).
Proof In Theorem ., we have proved thatBis closed andf(A)⊆B. Now we define an operatorPA:f(A)→AbyPAy={x∈A:d(x,y) =d(A,B)}. Since the pair (A,B) has the weakP-monotone property, by the definition off, we have
d(PAfx,PAfy)≤d(fx,fy)≤d(x,y) –ψ
d(x,y), PAfy≥PAfx,
for anyy≥x∈A. Obviously,PAf is continuous and nondecreasing. For somex∈A, there existsxˆ∈Bsuch thatd(x,xˆ) =d(A,B) andxˆ≤f(x). That is,
d(x,xˆ) =d(A,B), d(PAfx,fx) =d(A,B), xˆ≤f(x).
By the weakP-monotone property, we havePAfx≥x.
This shows thatPAf :A→Ais a contraction satisfying all the conditions in Theo-rem .. Using TheoTheo-rem ., we can getPAf has a fixed pointx*. That is,PAfx*=x*∈A, which implies that
dx*,fx*=d(A,B).
Therefore,x*is the one inA
Theorem . Let X be a partially ordered set,and let(X,d)be a complete metric space.
Let(A,B)be a pair of nonempty closed subsets of X such that A=∅.Let T:A→B be a continuous and nondecreasing mapping with T(A)⊆B,and let T satisfy
ψd(Tx,Ty)≤φd(x,y), ∀y≥x,
whereψ is an altering distance function andφ: [,∞)→[,∞)is a continuous func-tion with the condifunc-tionψ(t) >φ(t)for all t> .Suppose that the pair(A,B)has the weak P-monotone property.If for some x∈A,there exists y∈Bsuch that d(x,y) =d(A,B)
and y≤Tx,then there exists an x*in A such that d(x*,Tx*) =d(A,B).
Proof In Theorem ., we have proved thatBis closed andf(A)⊆B. Define an operator
PA:T(A)→AbyPAy={x∈A:d(x,y) =d(A,B)}. Since the pair (A,B) has the weak
P-monotone property andψis nondecreasing, by the definition ofT, we have
ψd(PATx,PATy)
≤ψd(Tx,Ty)≤φd(x,y), PATy≥PATx,
for anyy≥x∈A. Since
φd(x,y)→ ⇔ d(x,y)→
⇒ ψd(PATx,PATy)
→ ⇔ d(PATx,PATy)→,
this shows thatPAT is continuous and nondecreasing. Because there existx∈Aand
y∈Bsuch thatd(x,y) =d(A,B) andy≤Tx, by the weakP-monotone property, we
havex≤PATx.
This shows thatPAT:A→Ais a contraction from a complete metric subspaceA into itself and satisfies all the conditions in Theorem .. Using Theorem ., we can get
PAThas a fixed pointx*. That is,PATx*=x*∈A, which implies that
dx*,Tx*=d(A,B).
Therefore,x*is the one inAsuch thatd(x*,Tx*) =d(A,B).
Theorem . Let(X,≤)be a partially ordered set,and let(X,d)be a complete metric space.Let(A,B)be a pair of nonempty closed subsets of X such that A=∅.Let T:A→B be a continuous and nondecreasing mapping with T(A)⊆B,and let T satisfy
ψdT(x),T(y)≤ψd(x,y)–φd(x,y) for y≥x,
whereψ andφare altering distance functions.Suppose that the pair(A,B)has the weak P-monotone property.If for some x∈A,there exists y∈Bsuch that d(x,y) =d(A,B)
and y≤Tx,then there exists an x*in A such that d(x*,Tx*) =d(A,B).
Proof In Theorem ., we have proved thatBis closed andf(A)⊆B. Define an operator PA:T(A)→AbyPAy={x∈A:d(x,y) =d(A,B)}. Since the pair (A,B) has the weak
P-monotone property andψis nondecreasing, by the definition ofT, we have
ψd(PATx,PATy)
for anyy≥x∈A. Since
d(x,y)→ ⇒ ψd(x,y)–φd(x,y)→
⇒ ψd(PATx,PATy)
→ ⇔ d(PATx,PATy)→.
This shows thatPATis continuous and nondecreasing. Because there existx∈Aand
y∈Bsuch thatd(x,y) =d(A,B) andy≤Tx, by the weakP-monotone property, we havex≤PATx.
This shows thatPAT:A→Ais a contraction from a complete metric subspaceA into itself and satisfies all the conditions in Theorem .. Using Theorem ., we can get
PAThas a fixed pointx*. That is,PATx*=x*∈A, which implies that
dx*,Tx*=d(A,B).
Therefore,x*is the one inAsuch thatd(x*,Tx*) =d(A,B).
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All the authors contributed equally to the writing of the present article. All authors read and approved the final manuscript.
Acknowledgements
This project is supported by the National Natural Science Foundation of China under grant (11071279).
Received: 17 January 2013 Accepted: 14 March 2013 Published: 4 April 2013
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