PRUEBAS.pdf

(1)

LAS PREGUNTAS QUE TIENE 0/1 YA ESTAN CORREGUIDAS

CAPÍTULO 1 CAPÍTULO 1 Pregunta 1 Pregunta 1 0 / 1 ptos. 0 / 1 ptos.

The English language is an example of The English language is an example of a programming language a programming language a natural language a natural language a machine language a machine language Pregunta 2 Pregunta 2 1 / 1 ptos. 1 / 1 ptos. A high-level language is A high-level language is

a type of programming language a type of programming language

a language spoken by the high society a language spoken by the high society

a language spoken by mountain tribes a language spoken by mountain tribes

Incorrecto

IncorrectoPregunta 3Pregunta 3 0 / 1 ptos.

0 / 1 ptos.

A compiler is A compiler is

an alternative name for a processor an alternative name for a processor

a computer program designed to translate programs from a machine language into a computer program designed to translate programs from a machine language into a high-level language

(2)

(3)

a computer program designed to translate programs from a high-level language a computer program designed to translate programs from a high-level language into a machine language

into a machine language Pregunta 4

Pregunta 4 1 / 1 ptos.

1 / 1 ptos.

Data of type

Data of type intint is is

an integral number an integral number an internal number an internal number an integer number an integer number a fractional number a fractional number Pregunta 5 Pregunta 5 1 / 1 ptos. 1 / 1 ptos.

The following string: The following string:

ThisIsTheNameOfTheVariable

can be used as a variable name can be used as a variable name

cannot be used as a variable name cannot be used as a variable name

Pregunta 6 Pregunta 6 1 / 1 ptos.

1 / 1 ptos.

The following string: The following string:

101Dalmatians

(4)

cannot be used as a variable name cannot be used as a variable name

can be used as a variable name can be used as a variable name

1 / 1 ptos.

What is the value of the

What is the value of the varvar variable after executing the following snippet of code: variable after executing the following snippet of code: int var; int var; var = 100; var = 100; var = var + 100; var = var + 100;

var = var + var;

400 400 100 100 300 300 200 200 Pregunta 8 Pregunta 8 1 / 1 ptos. 1 / 1 ptos. A

A keywordkeyword is a word that is a word that

cannot be used in the meaning other than defined in the language standard cannot be used in the meaning other than defined in the language standard functions as a password needed to launch a program

(5)

is the most important word in a program

A comment placed anywhere inside the code is a syntactic equivalent of

a space

a keyword

a number

Every variable has the following attributes:

type, name, value

variability, stability, readability

header, footer, setter

CAPÍTULO 2 Pregunta 1 1 / 1 ptos.

Which of the following strings is a proper integer number (in the “C” language

(6)

123456 123,456 123.456 123_456 IncorrectoPregunta 2 0 / 1 ptos.

What is the value of the following integer literal?

08

8

1000

the literal is invalid

10

What is the value of the following integer literal?

0x8

10

(7)

the literal is invalid

1000

Which of the following strings is a valid variable name? Monte_Carlo Monte Carlo Monte-Carlo Monte@Carlo Pregunta 5 1 / 1 ptos.

Which of the following strings is an invalid variable name? _0_ 0_ ___ _0 Pregunta 6 1 / 1 ptos.

Is the following declaration valid?

(8)

No

Yes

IncorrectoPregunta 7 0 / 1 ptos.

What is the value of the var variable at the end of the following snippet? int var;

var = 2;

var = var * var; var = var + var; var = var / var; var = var % var;

16 8 0 1 IncorrectoPregunta 8 0 / 1 ptos.

What is the value of the var variable at the end of the following snippet? int var;

var = 2;

var = var * var; var = var + var;

/*

var = var / var; var = var % var;

*/

(9)

8

16

0

Which of the following strings is a proper floating-point number (in the ”C” language

sense)? 123,456 123.456 123456 123_456 IncorrectoPregunta 10 0 / 1 ptos.

What is the value of the following floating-point literal?

8765E-2

8.765

87.65 876.5

(10)

What is the value of the x variable at the end of the following snippet? int x; x = 1 / 2; 0 0.5 2 1 IncorrectoPregunta 12 0 / 1 ptos.

What is the value of the x variable at the end of the following snippet? int x; x = 1 / 2 * 3; /*** 2 1.5 0 1 Pregunta 13 1 / 1 ptos.

(11)

float x; x = 1. / 2 * 3; /*** 2 1.5 0 1

IncorrectoPregunta 14

0 / 1 ptos.

What is the value of the k variable at the end of the following snippet? int i,j,k; i = 4; j = 5; --i; k = i * j; 15 18 16 12 Pregunta 15 1 / 1 ptos.

(12)

int i,j,k; i = 4; j = 5; ++j; k = i * j; 24 18 21 28 IncorrectoPregunta 16 0 / 1 ptos.

What is the value of the k variable at the end of the following snippet?

int i,j,k; i = 3; j = -3; k = i * j; k += j; k /= i; 4 8 -4 8 Pregunta 17 1 / 1 ptos.

(13)

char c; c = '\';

the assignment is invalid and causes a compilation error

\0

\

'

What is the value of the c variable at the end of the following snippet? char c;

c = 'a'; c -= ' ';

the assignment is invalid and causes a compilation error

\0

A

a

What is the value of the k variable at the end of the following snippet? int i,j,k;

(14)

j = -3; k = (i >= i) + (j <= j) + (i == j) + (i > j); 2 1 3 0 IncorrectoPregunta 20 0 / 1 ptos.

What happens if you try to compile and run this program?

#include <stdio.h> int main(void) { int i,j,k; i = 2; j = -2; if(i) i--; if(j) j++; k = i * j; printf("%d",k); return 0; } 1 -2 -1 2

(15)

#include <stdio.h> int main(void) { int i, j, k; i = -1; j = 1; if(i) j--; if(j) i++; k = i * j; printf("%d",k); return 0; }

the program outputs2

the program outputs 0

the program outputs -1

#include <stdio.h> int main(void) { int i, j, k; i = 0; j = 0; if(j) j--; else

(16)

i++; if(i) i--; else j++; k = i + j; printf("%d",k); return 0; }

#include <stdio.h> int main(void) { int i, j, k; i = 2; j = 3; if(j) j--; else if(i) i++; else j++; if(j) i--; else if(j) j++; else j = 0;

(17)

k = i + j;

printf("%d",k); return 0;

}

#include <stdio.h> int main(void) { double x = -.1; int i = x; printf("%d",i); return 0; }

the program outputs 0.100000

the program outputs -0.100000

(18)

#include <stdio.h> int main(void) { float x,y; int i,j; x = 1.5; y = 2.0; i = 2; j = 3; x = x * y + i / j; printf("%f",x); return 0; }

#include <stdio.h> int main(void) { float x,y; int i,j; x = 1.5; y = 2.0; i = 2; j = 4; x = x * y + (float)i / j; printf("%f",x); return 0; }

(19)

#include <stdio.h> int main(void) { int i; i = 1; while(i < 16) i *= 2; printf("%d",i); return 0; }

(20)

#include <stdio.h> int main(void) { int i, j; i = 1; j = 1; while(i < 16) { i += 4; j++; } printf("%d",j); return 0; }

#include <stdio.h> int main(void) { int i = 7, j = i - i; while(i) { i /= 2; j++; } printf("%d",j); return 0; }

(21)

#include <stdio.h> int main(void) { int i = 7, j = i - i; while(!i) { i /= 2; j++; } printf("%d",j); return 0; }

(22)

#include <stdio.h> int main(void) { int i, j = 1; for(i = 11; i > 0; i /= 3) j++; printf("%d",j); return 0; }

#include <stdio.h> int main(void) { int i, j = 0; for(i = 0; !i ; i++) j++; printf("%d",j); return 0; }

(23)

#include <stdio.h> int main(void) { int i = 1, j = -2; for(;;) { i *= 3; j++; if(i > 30) break; } printf("%d",j); return 0; }

(24)

1 / 1 ptos.

#include <stdio.h> int main(void) { int i = 1, j = -2, k; k = (i >= 0) && (j >= 00) || (i <= 0) && (j <= 0); printf("%d",k); return 0; }

#include <stdio.h> int main(void) { int i = 1, j = -2, k; k = (i >= 0) || (j >= 00) && (i <= 0) || (j <= 0); printf("%d",k); return 0; }

(25)

#include <stdio.h> int main(void) {

int i = 1, j = -2, k;

k = !(i >= 0) || !(j >= 00) && !(i <= 0) || !(j <= 0); printf("%d",k);

return 0; }

#include <stdio.h> int main(void) { int i = 1, j = 0, k; k = i & j; k |= !!k; printf("%d",k);

(26)

return 0; }

#include <stdio.h> int main(void) { int i = 1, j = 0, k; k = !i | j; k = !k; printf("%d",k); return 0; }

(27)

#include <stdio.h> int main(void) { int i = 1, j = 0, k; k = (i ^ j) + (!i ^ j) + (i ^ !j) + (!i ^ !j); printf("%d",k); return 0; }

#include <stdio.h> int main(void) { int i = 0, j = 1, k; k = i << j + j << i; printf("%d",k); return 0; }

(28)

#include <stdio.h> int main(void) { int i = 3, j = i - 2; switch(i - 2) { case 1: j++; case 2: j++; case 0: j++; break; default:j = 0; } printf("%d",j); return 0; }

(29)

What happens if you try to compile and run this program? #include <stdio.h> #include <stdio.h> int main(void) { int i = 3, j = i - 2; switch(i + 2) { case 1: j++; case 2: j++; default:j = 0; case 0: j++; break; } printf("%d",j); return 0; }

#include <stdio.h> int main(void) { int i, t[5]; t[0] = 0; for(i = 1; i < 5; i++) t[i] = t[i - 1] + i; printf("%d",t[4]); return 0; }

(30)

#include <stdio.h> int main(void) { int i, t[5]; t[4] = 0; for(i = 3; i >= 0; i--) t[i] = t[4] * i; printf("%d",t[0]); return 0; }

(31)

#include <stdio.h> int main(void) { int t[2]; t[0] = 1; t[1] = 0; printf("%d",t[t[t[t[t[0]]]]]); return 0; }

#include <stdio.h> int main(void) { int i,t[3]; for(i = 2; i >=0 ; i--) t[i] = i - 1; printf("%d",t[1] - t[t[0] + t[2]]); return 0; }

(32)

#include <stdio.h> int main(void) { int i,t[4] = { 1, 2, 4, 8 }; for(i = 0; i < 2 ; i++) t[i] = t[3 - i]; printf("%d",t[2]); return 0; }

(33)

1 / 1 ptos.

#include <stdio.h> int main(void) { int s,i,t[] = { 0, 1, 2, 3, 4, 5 }; s = 1; for(i = 2; i < 6 ; i += i + 1) s += t[i]; printf("%d",s); return 0; }

char t[] = { 'a', 'b', 'A', 'B' };

printf("%d",t[1] - t[0] + t[3] - t[2]); return 0;

}

(34)

float t[5] = { 1E0, 1E1, 1E2, 1E3, 1E4 }; printf("%f",t[0] + t[2] + t[3]);

return 0; }

(35)

int i = 1, *j = &i, **k = &j; printf("%d",**k);

return 0; }

the program outputs NULL

the program outputs nul

#include <stdio.h> int main(void) { char t[3]; printf("%d",sizeof(t) - sizeof(t[0])); return 0; }

(36)

#include <stdio.h> int main(void) { int t[6]; printf("%d",sizeof(t) / sizeof(int)); return 0; }

#include <stdio.h> int main(void) { int t[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }, *p = t + 4; p += *p; printf("%d",*p); return 0; }

(37)

#include <stdio.h> int main(void) { int t[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }, *p = t; p += 2; p += p[-1]; printf("%d",*p); return 0; }

(38)

#include <stdio.h> int main(void) { char s[] = "\0\1\2\3\4"; printf("%c",'A' + s[3]); return 0; }

the program outputs A

the program outputs C

the program outputs B

the program outputs D

printf("%c","ACEGIK"[3] - 1); return 0;

}

the program outputs F

(39)

the program outputs E

the program outputs G

#include <stdio.h> #include <string.h> int main(void) { char s[10] = "ABCDE"; strcpy(s + 2, "ABCDE"); printf("%d", s[0] - s[2]); return 0; }

#include <stdio.h> #include <string.h> int main(void) {

(40)

strcat(s + 2, "CABDE"); printf("%d", s[0] - s[2]); return 0;

}

#include <stdio.h> #include <string.h> int main(void) { char s[10] = "ABCDE"; strcat(s + 2, "ABCDE"); printf("%d", s[0] - s[2]); return 0; }

(41)

#include <stdio.h> int main(void) { char s[10] = "ABCDE", *p = s + 3; printf("%d", p[1] - p[-1]); return 0; }

#include <stdio.h> int main(void) { char s[] = "ABCDE", *p = s + 5; printf("%d", p[-1] - *(p - 4)); return 0; }

(42)

the program outputs 3 the program outputs 3

1 / 1 ptos.

What happens if you try to compile and run this program? What happens if you try to compile and run this program?

#include <stdio.h> #include <stdio.h> int main(void) { int main(void) { char *p = "12345", *q = p - 10; char *p = "12345", *q = p - 10; printf("%d", q[14] - q[13]); printf("%d", q[14] - q[13]); return 0; return 0; } }

Pregunta 4 Pregunta 4

(43)

1 / 1 ptos.

#include <stdio.h> #include <stdio.h> int main(void) { int main(void) { int t[] = { 1, 2, 3, 4, 5 }, int t[] = { 1, 2, 3, 4, 5 }, *p = t;*p = t; *p++; *p++; (*p)++; (*p)++; *p++; *p++; printf("%d",p[-1]); printf("%d",p[-1]); return 0; return 0; } }

1 / 1 ptos.

#include <stdio.h> #include <stdio.h> int main(void) { int main(void) { int t[2][2] = { 1, 2, 4, 8 }; int t[2][2] = { 1, 2, 4, 8 }; int s = 0, i, j; int s = 0, i, j; for(i = 2; i; i -= 2) for(i = 2; i; i -= 2) for(j = 1; j < 2; j += 2) for(j = 1; j < 2; j += 2) s += t[i - 1][j]; s += t[i - 1][j]; printf("%d",s); printf("%d",s); return 0; return 0; } }

(44)

1 / 1 ptos.

#include <stdio.h> #include <stdio.h> int main(void) { int main(void) { int t[1][2][2] = { { { 1, 2 }, { 3, 4 } } }; int t[1][2][2] = { { { 1, 2 }, { 3, 4 } } }; int s = 0, i, j, k; int s = 0, i, j, k; for(i = 1; i > 0; i -= for(i = 1; i > 0; i -= 2)2) for(j = 1; j < 2; j += 2) for(j = 1; j < 2; j += 2) for(k = 0; k < 3; k += 3) for(k = 0; k < 3; k += 3) s += t[k][i - 1][j]; s += t[k][i - 1][j]; printf("%d",s); printf("%d",s); return 0; return 0; } }

(45)

#include <stdio.h> #include <stdlib.h> int main(void) {

int *p = (int *)malloc(2 * sizeof(int)); *p = 2; *(p + 1) = *(p) - 1; *p = p[1]; printf("%d",*p); free(p); return 0; }

int t[] = { 8, 4, 2, 1 };

int *p = (int *)malloc(sizeof(t)); int i; for(i = 0; i < 4; i++) p[3 - i] = t[i]; printf("%d",*(p + 2)); free(p); return 0; }

(46)

int i,j;

int **p = (int **)malloc(2 * sizeof(int *)); p[0] = (int *)malloc(2 * sizeof(int));

p[1] = p[0]; for(i = 0; i < 2; i++) for(j = 0; j < 2; j++) p[i][j] = i + j; printf("%d",p[0][0]); return 0; }

(47)

int i,j;

int **p = (int **)malloc(2 * sizeof(int *)); p[0] = (int *)malloc(2 * sizeof(int));

p[1] = (int *)malloc(2 * sizeof(int)); for(i = 0; i < 2; i++) for(j = 0; j < 2; j++) p[i][j] = i + j; printf("%d",p[0][0]); return 0; }

int *t[10]; int (*u)[10];

(48)

return 0; }

#include <stdio.h> int main(void) { int *(t[10]); int *u[10]; printf("%d",sizeof(t) != sizeof(u)); return 0; }

(49)

#include <stdio.h> struct S { int S; }; int main(void) { struct S S; S.S = sizeof(struct S) / sizeof(S); printf("%d",S.S); return 0; }

#include <stdio.h> #include <string.h> struct Q { char S[3]; }; struct S { struct Q Q; }; int main(void) { struct S S = { '\0', '\0','\0' }; S.Q.S[0] = 'A'; S.Q.S[1] = 'B';

(50)

printf("%d",strlen(S.Q.S)); return 0;

}

#include <stdio.h> #include <string.h> struct Q { char S[3]; }; struct S { struct Q Q; }; int main(void) { struct S S = { '\0', '\0','\0' }; S.Q.S[0] = 'A'; S.Q.S[2] = 'B'; printf("%d",strlen(S.Q.S)); return 0; }

(51)

#include <stdio.h> struct Q { int a,b,c; }; struct S { int a,b,c; struct Q Q; }; int main(void) { struct Q Q = { 3,2,1 }; struct S S = { 4,5,6 }; S.Q = Q; printf("%d",S.b - S.Q.b); return 0; }

(52)

What happens if you try to compile and run this program? #include <stdio.h> #include <stdlib.h> struct S { int a; struct S *b; }; int main(void) {

struct S *x = (struct S*) malloc(sizeof(struct S)); struct S *y = (struct S*) malloc(sizeof(struct S)); x->a = 2; x->b = y; y->a = 4; y->b = x; printf("%d",x->b->b->b->a); free(x); free(y); return 0; }

#include <stdio.h> #include <stdlib.h> struct S { int a; struct S *b; }; int main(void) {

struct S *x = (struct S*) malloc(sizeof(struct S)); struct S *y = (struct S*) malloc(sizeof(struct S));

(53)

struct S *p; x->a = 2; x->b = y; y->a = 4; y->b = x; p = x; p = p->b->b->b->b; printf("%d",p->a); return 0; }

#include <stdio.h> struct S { int a[2]; }; int main(void) { struct S S[2]; int i; for(i = 0; i < 2; i++) S[i].a[1-i] = 4 * !i; printf("%d",S[0].a[1]); return 0; }

(54)

#include <stdio.h> struct S { char *p; }; int main(void) { char *p = "abcd"; struct S S[2]; int i; for(i = 0; i < 2; i++) S[i].p = p + i; printf("%c",S[1].p[0]); return 0; }

the program outputs c

the program outputs b

the program outputs d

the program outputs a

(55)

What happens if you try to compile and run this program? void f(void) { } int main(void) { int i; i = f(); printf("%d",i); return 0; }

the program outputs nul

compilation fails

#include <stdio.h> int f(void) { } int main(void) { int i; i = f(); printf("%d",i); return 0; }

the compilation fails

(56)

the program outputs an unpredictable value

#include <stdio.h> void f(int i) { i++; } int main(void) { int i = 1; f(i); printf("%d",i); return 0; }

(57)

#include <stdio.h> int f(int i) { ++i; return i; } int main(void) { int i = 1; i = f(i); printf("%d",i); return 0; }

#include <stdio.h> int f(int i) { return ++i; } int main(void) { int i = 0; i = f(f(i)); printf("%d",i); return 0; }

(58)

#include <stdio.h> int main(void) { int i = 0; { int i = 1; main.i = i; } printf("%d",i); return 0; }

compilations fails

(59)

#include <stdio.h> int i = 0; void f(void) { int i = 1; } int main(void) { int i = 2; f(); printf("%d",i); return 0; }

#include <stdio.h> int i = 0; void f(void) { int i = 1; } int main(void) { f(); printf("%d",i); return 0; }

(60)

#include <stdio.h> int i = 1; int *f(void) { return &i; } int main(void) { int i = 0; i = *f(); printf("%d",i); return 0; }

(61)

What happens if you try to compile and run this program? #include <stdio.h> int i = 2; int *f(void) { return &i; } int main(void) { int *i; i = f(); printf("%d",++(*i)); return 0; }

#include <stdio.h> int i = 0;

int *f(int *i) { (*i)++; return i; } int main(void) { int i = 1; i = *f(&i); printf("%d",i); return 0; }

(62)

#include <stdio.h> struct S { int S; }; int f(struct S s) { return --s.S; } int main(void) { int i; struct S S = { 2 }; i = f(S); printf("%d",i); return 0; }

(63)

#include <stdio.h> struct S { int S; }; int f(struct S *s) { return --s.S; } int main(void) { int i; struct S S = { 2 }; i = f(S); printf("%d",i); return 0; }

compilation fails

#include <stdio.h> int f(int t[\]) { return t[0\] + t[2\]; } int main(void) { int i,a[\] = { -2,-1,0,1,2 };

(64)

i = f(a + 2); printf("%d",i); return 0;

}

#include <stdio.h> int f(int t[\][\]) { return t[0\][0\] + t[1\][0\]; } int main(void) { int i,a[2\][2\] = { {-2,-1},{1,2} }; i = f(a + 2); printf("%d",i); return 0; }

(65)

#include <stdio.h> int f(int t[2\][\]) { return t[0\][0\] + t[1\][0\]; } int main(void) { int i,a[2\][2\] = { {-2,-1},{1,2} }; i = f(a + 2); printf("%d",i); return 0; }

#include <stdio.h> int f(char t[\]) { return t[1\] - t[0\]; } int main(void) { int i = 2; i -= f("ABDGK" + 1);

(66)

printf("%d",i); return 0;

}

#include <stdio.h> int f(char t[\]) { return t[0\] - t[-1\]; } int main(void) { int i = 2; i -= f("ABDGK" + 1); printf("%d",i); return 0; }

(67)

#include <stdio.h> #include <string.h> void f(char *s,int i) {

*(s + i) = '\0'; }

int main(void) {

char a[\] = { 'a','b','c','d' }; f(a[1\],1);

printf("%d",strlen(a)); return 0;

}

Sin responderPregunta 20 0 / 1 ptos.

#include <stdio.h> #include <string.h> void f(char *s,int i) {

*(s + i) = '\0'; }

(68)

char a[\] = { 'a','b','c','d' }; f(a+1,1);

printf("%d",strlen(a)); return 0;

}

CAPÍTULO 7

Pregunta 1 0.5 / 1 ptos.

The following string:

JohnDoe

is a valid file name in

MS Windows systems Unix/Linux systems

Unix/Linux systems treat the following names

JohnDoe johndoe

(69)

as different file names

as identical file names

IPregunta 3 0 / 1 ptos.

HomeDir/HomeFile

is a valid file name in:

D:\USERDIR\johndoe.txt

is a valid file name in

int main(void) { FILE *f; f = fopen("file","wb"); printf("%d",f != NULL); fclose(f); return 0; }

(70)

#include <stdio.h> int main(void) { FILE f; f = fopen("file","wb"); printf("%d",f != NULL); fclose(f); return 0; }

the execution fails

What happens if you try to compile and run this program assuming that fopen() succeeds?

#include <stdio.h> int main(void) { FILE *f; f = fopen("file","wb"); printf("%d",f != NULL); fclose(f); return 0; }

(71)

the compilation or execution fails

#include <stdio.h> int main(void) { int i; i = fprintf(stdin,"Hello!"); printf("%d",i == EOF); return 0; }

#include <stdio.h> int main(void) { int i; i = fprintf(stderr,"Hello!"); printf("%d",i == EOF); return 0; }

the program outputs 2 to the stdout stream

(72)

the program outputs 0 to the stdout stream

#include <stdio.h> int main(void) { FILE *f; int i = fprintf(f,"Hello!"); printf("%d",i == EOF); return 0; }

the program outputs 1 the program outputs 2 the program outputs 0

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i = fprintf(f,"Hello!"); printf("%d",i != EOF); return 0; }

(73)

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i = fputs(f,"Hello!"); printf("%d",i != EOF); fclose(f); return 0; }

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i = fputs("Hello!",f); printf("%d",i != EOF); return 0; }

(74)

#include <stdio.h> int main(void) { char s[20]; FILE *f = fopen("file","w"); int i = fputs("12A",f); fclose(f); f = fopen("file","r"); fgets(s,2,f); puts(s); fclose(f); return 0; }

the program outputs 12A

char s[20];

FILE *f = fopen("file","w"); int i = fputs("12A",f);

(75)

fclose(f); f = fopen("file","r"); fgets(s,20,f); puts(s); fclose(f); return 0; }

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i; fputs("12A",f); fclose(f); f = fopen("file","r"); fseek(f,0,SEEK_END); i = ftell(f); fclose(f); printf("%d",i); return 0; }

(76)

Pregunta 17 1 / 1 ptos. What happens if you try to compile and run this program assuming that fopen() succeeds?

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i; fputs("12A",f); fclose(f); f = fopen("file","r"); fseek(f); i = ftell(f,0,SEEK_END); fclose(f); printf("%d",i); return 0; }

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); int i; fputs("12A",f); fclose(f); f = fopen("file","r"); fscanf(f,"%d",&i); fclose(f); printf("%d",i); return 0; }

(77)

#include <stdio.h> int main(void) { FILE *f = fopen("file","w"); char c; fputs("12A",f); fclose(f); f = fopen("file","r"); fscanf(f,"%c",&c); fclose(f); printf("%c",c); return 0; }