CAMBRIDGE A – LEVEL
PHYSICS
PARTICLE AND
NUCLEAR PHYSICS
(A2)
L E A R N I N G O U TC O M E S
No.
LEARNING OUTCOME
i
A p p l y t h e m a s s – e n e r g y c o n s e r v a t i o n p r i n c i p l e t o
c a l c u l a t e t h e r e a c t i o n e n e r g y i n a n u c l e a r p r o c e s s .
iiU n d e r s t a n d w h a t i s m e a n t b y m a s s e x c e s s a n d t h e
r e l a t i o n s h i p a n d m a s s e x c e s s a n d n u c l e a r
p r o c e s s e s .
iiiR e l a t e t h e c o n c e p t o f b i n d i n g e n e r g y w i t h t h e
m a s s d e f e c t .
ivR e l a t e b i n d i n g e n e r g y a n d b i n d i n g e n e r g y p e r
n u c l e o n .
vG r a p h t h e r e l a t i o n s h i p b e t w e e n b i n d i n g e n e r g y
p e r n u c l e o n a g a i n s t n u c l e o n n u m b e r.
L E A R N I N G O U T C O M E S
No.
LEARNING OUTCOME
vi
D i f f e r e n t i a t e b e t w e e n n u c l e a r f i s s i o n a n d f u s i o n .
vii
U n d e r s t a n d t h e t e r m a c t i v i t y a n d d e c a y c o n s t a n t .
viii
U s e t h e e x p o n e n t i a l d e c a y m e t h o d t o c a l c u l a t e t h e
n u m b e r o f u n d e c a y e d n u c l e i a n d a c t i v i t y.
ix
U n d e r s t a n d w h a t i s m e a n t b y h a l f l i f e a n d
c a l c u l a t e t h e h a l f l i f e o f a r a d i o a c t i v e s a m p l e .
U N I T S O F M A S S
• As we have learned at AS Level,
the SI unit for mass is the
kilogram.
• Physicists have also developed an
alternative unit for mass, the
U N I T S O F M A S S
• 1 u
is equivalent to
the
mass
of
1
atom
of
the
isotope,
in kilograms
.
• The mass of one atom of
=
U N I T S O F M A S S
• Hence,
kg
.
• The table on the next slide shows
the masses of some light nuclides
in atomic mass units.
Table 43.2, page 1441, Section 43.1: Properties of Nuclei; Chapter 43: Nuclear Physics; Sear’s and Zemansky’s University Physics, Young and Freedman, 13th edition, Pearson Education, San Francisco, 2012.
U N I T S O F M A S S
U N I T S O F M A S S
• The table below lists the masses
of the nucleons and the electron
in atomic mass units:
Particle
Mass (u)
Proton
1.007276
Neutron
1.008665
Electron
0.000549
M A S S - E N E R G Y
C O N S E R VAT I O N
M A S S - E N E R G Y
C O N S E R VAT I O N
• As we have learned at AS
Level,
mass
–
energy
is
conserved
in
a
nuclear
process
, but, however,
mass
itself is not conserved
.
M A S S - E N E R G Y
C O N S E R VAT I O N
M A S S - E N E R G Y
C O N S E R VAT I O N
• The
difference between the total
mass after the reaction and the
total mass before the reaction
gives us an idea of the amount of
M A S S - E N E R G Y
C O N S E R VAT I O N
M A S S - E N E R G Y
C O N S E R VAT I O N
.
.
• We may use Einstein’s mass – energy
equation
; where:
reaction energy
, in J;
∑
∑
, in
kg, and
speed of light, .
.
M A S S - E N E R G Y
C O N S E R VAT I O N
M A S S - E N E R G Y
C O N S E R VAT I O N
• What if we have masses in atomic
• What if we have masses in atomic
mass units (u)?
• We now use
,
where:
E = energy, MeV
, and
m = mass, in u
.
931.494 MeV/u is a conversion
M A S S - E N E R G Y
C O N S E R VAT I O N
M A S S - E N E R G Y
C O N S E R VAT I O N
• We can also use a different
version of Einstein’s equation:
• This version
relates the change in
EX A M P L E
Table 43.1, page 1441, Section 43.1: Properties of Nuclei; Chapter 43: Nuclear Physics; Sear’s and Zemansky’s University Physics, Young and Freedman, 13th
M A S S E XC ES S
mass
mass
mass
mass excess
excess
excess
excess
mass
mass
mass
mass #in
#in u'
#in
#in
u'
u'
u'
neutron
neutron
neutron number
neutron
number
number
number
• The
mass excess of a nuclide is the
difference between its actual mass,
in atomic mass units (u) and its
mass number
.
• Mathematically:
mass
mass
mass
M A S S E XC ES S
Figure 31.3, page 493, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
M A S S E XC ES S
• The table on the previous slide gives
some nuclides and their masses.
Question 7, page 494, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
M A S S E XC ES S
We can use mass excess values to find
• We can use mass excess values to find
out whether a nuclear reaction is
feasible.
• We can do this by calculating:
I.
the total mass excess of the reactants,
II.
the total mass excess of the products,
and
M A S S E XC ES S
• If the
total mass excess of the
products is smaller than the total
mass excess of the reactants
, the
reaction is feasible
.
• On the other hand,
if the converse is
true, then the reaction will not be
feasible
.
M A S S E XC ES S
,
-
→
1
/0
2
5
34
2 37
• Let us have a look at an example:
,
-
→
1
/0
2
5
34
2 37
Nuclide
Mass Excess (u)
,
-
+0.045563
/0
1
−0.073843
34
5
−0.085588
7
+0.008665
M A S S E XC ES S
0.073843 2 0.085588 2 3
0.008665 0.133436 u
• Using the values from the table in the
previous slide, we can obtain:
I. Total
mass
excess
of
reactants
u
II. Total
mass
excess
of
products
0.073843 2 0.085588 2 3
M A S S E XC ES S
• In this example, the total mass
excess of the reactants is larger than
the
total
mass
excess
of
the
products.
• This means that
the products will be
more stable than the reactants
.
Hence, this
reaction will occur
.
M A S S D E F EC T
• If we were to measure the mass
of
one
nucleus
of
the
isotope, it will be different from
the total mass of the 6 neutrons
and the 6 protons make up the
nucleus.
Figure 31.1, page 492, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
Cambridge University Press, Cambridge, UK,2014.
M A S S D E F EC T
• By using the values from the
table on the previous slide, we
will obtain a mass defect of
kg for this
carbon nuclide.
M A S S D E F EC T
• Definition: “
The mass defect is
the difference between the
total mass of the individual
nucleons and the mass of the
nucleus
.”
M A S S D E F EC T
• Why is there a mass defect?
• Why is there a mass defect?
• This mass defect exists because
when the individual nucleons
formed the nucleus, some of the
mass
was
converted
into
potential energy that is used to
hold the nucleons together.
B I N D I N G E N E R GY
• The strong force is responsible in
• The strong force is responsible in
producing
this
change
in
potential energy and thus binds
the nucleons.
• Work must be done to separate
these
nucleons
apart
to
an
infinite amount of separation.
B I N D I N G E N E R GY
• Definition:
“
The
binding
energy of a nucleus is the
energy required to separate
all the nucleons in a nucleus
to
an
infinite
amount
of
separation
.”
B I N D I N G E N E R GY
• By using mass – energy equivalence,
we can use the mass defect and
convert it into the binding energy.
• To achieve this, use this conversion
factor:
of mass defect is
equivalent to
of
EX A M P L E
Exercise 43.39, page 1476; Chapter 43: Nuclear Physics; Sear’s and Zemansky’s University Physics, Young and Freedman, 13th edition, Pearson Education, San
B I N D I N G E N E R GY
Examples from Page 367; Section 13.7: The Mass Defect, Chapter 13: Nuclear Physics;
International A/AS Level Physics, by Mee, Crundle, Arnold and Brown, Hodder Education, United Kingdom, 2008.
B I N D I N G E N E R G Y P E R
N U C L E O N
B I N D I N G E N E R G Y P E R
N U C L E O N
• The
binding energy per nucleon
is equal to the binding energy of
the nucleus divided by the total
number of nucleons present.
B I N D I N G E N E R G Y P E R
N U C L E O N
B I N D I N G E N E R G Y P E R
N U C L E O N
• Why is the binding energy per
• Why is the binding energy per
nucleon important?
• The binding energy per nucleon
value gives us the stability of that
nuclide relative to its neighbours,
i.e. how hard is it for that nuclei to
radioactively
decay
into
its
neighbours.
B I N D I N G E N E R G Y P E R
N U C L E O N
B I N D I N G E N E R G Y P E R
N U C L E O N
Figure 31.4, page 495, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition, Cambridge University Press, Cambridge, UK,2014.B I N D I N G E N E R G Y P E R
N U C L E O N
B I N D I N G E N E R G Y P E R
N U C L E O N
The graph on the previous slide shows a
• The graph on the previous slide shows a
sketch of the binding energy per nucleon
for several elements.
• The
higher the value of the binding
energy per nucleon compared to its
neighbours, the harder it is for that
nuclei to decay radioactively into one of
its neighbours.
B I N D I N G E N E R G Y P E R
N U C L E O N
B I N D I N G E N E R G Y P E R
N U C L E O N
?
• The nuclide with the
highest
binding energy per nucleon is
@
.
• Peaks representing
5
,
and
?
indicate nuclides that are
EX A M P L E
Questions 9 amd 10, page 496, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
NU C L EA R FI S S I O N
• Nuclear fission is a decay
process in which an unstable,
heavy nucleus splits into two
fragments of almost the same
mass
.
NU C L EA R FI S S I O N
• The two fragments, known as
fission
fragments will have a higher binding
energy per nucleon as compared to
the parent nucleus
.
• Nuclear
fission
is
achieved
by
bombarding the heavy nucleus with
a neutron
.
NU C L EA R FI S S I O N
• An example of a fission reaction
is seen below:
Page 370; Section 13.10: Nuclear Fission, Chapter 13: Nuclear Physics; International A/AS Level Physics, by Mee, Crundle, Arnold and Brown, Hodder Education, United Kingdom, 2008.
NU C L EA R FI S S I O N
• Fission
reactions
are
accompanied by the release of
energy
because
the
binding
energy per nucleon after the
reaction is higher than that
NU C L EA R FU S I O N
• Nuclear fusion occurs when
two or more small nuclei
come together (fuse) to form
a larger nucleus.
NU C L EA R FU S I O N
• Nuclear fusion only
occurs under
conditions of high pressure and
temperature;
e.g. on the Sun’s
NU C L EA R FU S I O N
The examples below are of nuclear fusion
• The examples below are of nuclear fusion
reactions:
Page 1469, Section 43.8: Nuclear Fussion; Chapter 43: Nuclear Physics; Sear’s and Zemansky’s University Physics, Young and Freedman, 13th edition, Pearson
F U S I O N v s . F I S S I O N
Figure 31.6, page 496, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
F U S I O N v s . F I S S I O N
• As seen on the graph on the previous
• As seen on the graph on the previous
slide, fusion and fission occur in
order to increase the binding energy
per nucleon.
• Nuclei
in between A and B tend to
undergo fusion
,
while
nuclei in
between B and C tend to undergo
fission
.
E X A M P L E S
Question 16; Set 45: Structure of the Nucleus and Radioactivity; page 228; PROBLEMS IN PHYSICS ; E.D GARDINER, B.L McKITTRICK; McGraw – Hill Book Company, Sydney 1985.
E X A M P L E S
Question 17; Set 45: Structure of the Nucleus and Radioactivity; page 228; PROBLEMS IN PHYSICS ; E.D GARDINER, B.L McKITTRICK; McGraw – Hill Book Company, Sydney 1985.
E X A M P L E S
Question 18; Set 45: Structure of the Nucleus and Radioactivity; page 228; PROBLEMS IN PHYSICS ; E.D GARDINER, B.L McKITTRICK; McGraw – Hill Book Company, Sydney 1985.R A D I AT I O N D E T E C T I O N
• Outlined below are methods of radiation
detection:
R A D I AT I O N D E T E C T I O N
Examples from Pages 355 - 357; Section 13.14: Detecting Radioactivity; Chapter 13: Nuclear Physics; International A/AS Level Physics, by Mee, Crundle, Arnold and Brown, Hodder Education, United Kingdom, 2008.
N U C L EA R D EC AY
• If we were to use a GM
• If we were to use a GM
counter
to
measure
radioactivity by listening to the
number of clicks, we will not
be able to predict when the
next click is heard.
N U C L EA R D EC AY
• If we were to use a ratemeter,
• If we were to use a ratemeter,
the reading on the ratemeter
fluctuates up and down.
• This occurs because of the
random
and
spontaneous
nature of nuclear processes
.
N U C L EA R D EC AY
• It is
random because
• It is
random because
i.
we
cannot predict which
nucleus in a sample will
decay
, and
ii. The
probability that each of
the nuclei will decay in per
unit of time
is
constant
. This
probability is known as the
decay constant, λ.
N U C L EA R D EC AY
• If we plot a graph of count
• If we plot a graph of count
rate vs. time, we would
obtain a graph as seen on
the next slide.
• The fluctuations indicate
the
random
nature
of
N U C L EA R D EC AY
Figure 31.8, page 497, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
Cambridge University Press, Cambridge, UK,2014.
N U C L EA R D EC AY
• Nuclear decay is
spontaneous
• Nuclear decay is
spontaneous
because
:
i.
its
occurrence
is
independent of any external
or
environmental
factors,
and
ii. not affected by the presence
ACTIVITY
ACTIVITY
• Radioactive
nuclei
undergo
decay.
• Therefore,
the
amount
of
parent nuclei reduces with
time.
ACTIVITY
ACTIVITY
AB
AC
AB
AC
• The
rate of nuclei decay,
AB
AC
is
directly proportional to the
amount of undecayed nuclei
present in the sample
,
.
• We can rewrite this expression
AB
• We can rewrite this expression
as
AB
AC
where:
decay constant
that has
units of
.
the minus sign indicated this is
a decay.
ACTIVITY
ACTIVITY
• Definition
: “
The decay constant,
AC
• Definition
: “
The decay constant,
is defined as the probability
per unit time interval that the
nuclei will undergo decay
.”
•
AB
AC
is also known as the
activity of the source,
.
ACTIVITY
ACTIVITY
• Definition
:
“
The
activity
of
a
radioactive source is the number of
nuclear decays produced per unit of
time in the source”
.
• Activity is
measured in Becquerels
(Bq)
, and
1 Becquerel is 1 decay per
second
.
ACTIVITY
ACTIVITY
• By
combining
the
equations
AB
AB
D
E
.
• By
combining
the
equations
AB
AC
and
AB
AC
, we will
obtain
, where:
activity of the sample, in Bq;
B
number of undecayed nuclei,
and
D
decay constant, in
E
.
ACTIVITY
ACTIVITY
E X A M P L E S
Questions 12 and 13, page 499, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
E X A M P L E S
Questions 15 and 16, page 501, Chapter 31: Nuclear Physics; Cambridge
International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
Cambridge University Press, Cambridge, UK,2014.
• The
solution
of
the
equation
is in
the form of
.
HALF LIFE
HALF LIFE
• The
quantities
number
of
undecayed nuclei,
activity,
and received count rate,
all
have
the
general
form
DC
.
HALF LIFE
HALF LIFE
• We now have three equations
DC
• We now have three equations
that
relate
these
three
quantities with time,
DC
DC
DC
HALF LIFE
HALF LIFE
B B
F
DC
λ
• If we plot the equation
B B
F
DC
,
for
three different values of
λ ,we would
obtain:
HALF LIFE
HALF LIFE
Figure 31.9, page 497, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,Cambridge University Press, Cambridge, UK,2014.
H
I
J
• Definition
: “
The half life,
H
, of a
radioactive nuclide is the time taken
for the number of undecayed nuclei
to be reduced to half its original
number
”.
• How do we calculate the value of
I
K
J
⁄
?
HALF LIFE
HALF LIFE
K
J
⁄
M
H
D
• At
K
J
⁄
,
M
. When we
substitute
into
the
equation
DC
, we obtain
NO
K
H
J
.
• By taking the natural logarithms on
both sides, we get
H
.P
D
HALF LIFE
HALF LIFE
E X A M P L E S
Question 18, page 501, Chapter 31: Nuclear Physics; Cambridge International AS and A Level Physics Coursebook, Sang, Jones, Chadha and Woodside, 2nd edition,
Cambridge University Press, Cambridge, UK,2014.