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e-ISSN: 2278-067X, p-ISSN: 2278-800X, www.ijerd.com

Volume 8, Issue 8 (September 2013), PP. 53-61

www.ijerd.com 53 | Page

On The Zeros of a Polynomial in a Given Circle

M. H. Gulzar

Department of Mathematics University of Kashmir, Srinagar 190006

Abstract:- In this paper we discuss the problem of finding the number of zeros of a polynomial in a given circle when the coefficients of the polynomial or their real or imaginary parts are restricted to certain conditions. Our results in this direction generalize some well- known results in the theory of the distribution of zeros of polynomials.

Mathematics Subject Classification: 30C10, 30C15

Keywords and phrases:- Coefficient, Polynomial, Zero.

I.

INTRODUCTION AND STATEMENT OF RESULTS

In the literature many results have been proved on the number of zeros of a polynomial in a given circle. In this direction Q. G. Mohammad [6] has proved the following result:

Theorem A: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

a

n

a

n1

...

a

1

a

0

0

.

Then the number of zeros of P(z) in

2

1

z

does not exceed

0

log

2

log

1

1

a

a

n

.

K. K. Dewan [2] generalized Theorem A to polynomials with complex coefficients and proved the following results:

Theorem B: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

1

0

0

.

Then the number of zeros of P(z) in

2

1

z

does not exceed

0 0

log

2

log

1

1

a

n

j j

n

.

Theorem C: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n with complex coefficients such that for some

real

,

,

a

j

,

j

0

,

1

,

2

,...,

n

2

arg

and

a

n

a

n1

...

a

1

a

0 .

Then the number f zeros of P(z) in

2

1

(2)

www.ijerd.com 54 | Page

0

1

0

sin

2

)

1

sin

(cos

log

2

log

1

a

a

a

n

j j

n

.

The above results were further generalized by researchers in various ways. M. H. Gulzar[4,5,6] proved the following results:

Theorem D: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

,

k

1

...

1



0,

for

k

1

,

0

1

,

0

n

.

Then the number of zeros of P(z) in

z

,

0

1

does not exceed

0

0 0

0

0

(

)

2

2

)

)(

1

(

log

1

log

1

a

k

n

j j n

n

 

.

Theorem E: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

1



0,

for some

0

,

0

1

,

,then the number f zeros of P(z) in

z

,

0

1

, does not exceed

0

0 0

0

0

)

2

2

(

2

log

1

log

1

a

n

j j n

n

.

Theorem F: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n with complex coefficients such that for some

real

,

,

a

j

,

j

0

,

1

,

2

,...,

n

2

arg

and

a

n

a

n1

...

a

1

a

0 ,

for some

0

,

,then the number of zeros of P(z) in

z

,

0

1

, does not exceed

0 1

1

0

(cos

sin

1

)

sin

2

)

1

sin

)(cos

(

log

1

log

1

a

a

a

a

n

j j

n

.

The aim of this paper is to find a bound for the number of zeros of P(z) in a circle of radius not necessarily less than 1. In fact , we are going to prove the following results:

Theorem 1: Let

0

)

(

j j j

z

a

z

P

be a polynomial of degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

(3)

www.ijerd.com 55 | Page

for

k

1

,

0

1

,

0

n

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

does not exceed

0

0 0

0 0

1

]

2

)

(

2

)

)(

1

(

[

log

log

1

a

k

R

c

n

j j n

n

n

 

 

for

R

1

and

0

1 0

0 0 0

0

[

(

1

)(

)

(

)

2

]

log

log

1

a

k

R

a

c

n

j j n

n

for

R

1

.

Remark 1: Taking R=1 and

1

c

in Theorem 1, it reduces to Theorem D .

If the coefficients

a

j are real i.e.

j

0

,

j

, then we get the following result from Theorem 1:

Corollary 1: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

a

n

a

n1

...

a

,

ka

a

1

...

a

1

a

0,

for

k

1

,

0

1

,

0

n

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

does not exceed

0

0 0 0

1

)]

(

2

)

)(

1

(

[

log

log

1

a

a

a

a

a

a

k

a

a

R

c

n n

n

 

for

R

1

and

0

0 0 0

0

[

(

1

)(

)

(

)]

log

log

1

a

a

a

a

a

a

k

a

a

R

a

c

n

n

for

R

1

. Applying Theorem 1 to the polynomial –iP(z) , we get the following result:

Theorem 2: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

,

k

1

...

1



0,

for

k

1

,

0

1

,

0

n

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

does not exceed

0

0 0

0 0

1

]

2

)

(

2

)

)(

1

(

[

log

log

1

a

k

R

c

n

j j n

n

n

 

 

for

R

1

and

0

1 0

0 0

0

0

[

(

1

)(

)

(

)

2

]

log

log

1

a

k

R

a

c

n

j j n

n

(4)

www.ijerd.com 56 | Page

for

R

1

.

Taking

n

in Theorem 1, we get the following result :

Corollary 2: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

k

n

n1

...

1



0,

for

k

1

,

0

1

,

0

n

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

does not exceed

0

0 0

0 0

1

]

2

)

(

2

)

(

[

log

log

1

a

k

R

c

n

j j n

n

n

 

for

R

1

and

0

0 0

0 0

0

[

(

)

(

)

2

]

log

log

1

a

k

R

a

c

n

j j n

n

for

R

1

.

Theorem 3: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

1



0,

for some

,

0

1

,

,then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

, does not exceed

0

0 0

0 0 1

]

2

2

)

(

[

log

log

1

a

R

c

n

j j n

n

n

 

for

R

1

and

0

0 0

0 0

0

[

(

)

2

]

log

log

1

a

R

a

c

n

j j n

n

for

R

1

.

Remark 2: Taking R=1 and

1

c

in Theorem 3, it reduces to Theorem E .

If the coefficients

a

j are real i.e.

j

0

,

j

, then we get the following result from Theorem 3:

Corollary 3: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

a

n

a

n1

...

a

1

a

0,

for some

,

0

1

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

, does not exceed

0

0 0

0 1

]

2

)

(

[

log

log

1

a

a

a

a

a

a

R

c

n n

n

(5)

www.ijerd.com 57 | Page

and

0

0 0 0

0

[

(

)

]

log

log

1

a

a

a

a

a

a

R

a

c

n

n

Applying Theorem 3 to the polynomial –iP(z) , we get the following result:

Theorem 4: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

n

n1

...

1



0,

for some

0

,

0

1

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

, does not exceed

0

0 0

0 0 1

]

2

2

)

(

[

log

log

1

a

R

c

n

j j n

n

n

 

for

R

1

and

0

0 0

0 0

0

[

(

)

2

]

log

log

1

a

R

a

c

n

j j n

n

for

R

1

. Taking

(

k

1

)

n

,

k

1

in Corollary 3 , we get the following result:

Corollary 4: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

Re(

a

j

)

j,

Im(

a

j

)

jand

k

n

n1

...

1



0,

for some

,

0

1

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

, does not exceed

0

0 0

0 0 1

]

2

2

)

(

)

(

[

log

log

1

a

k

R

c

n

j j n

n

n

 

for

R

1

and

0

0 0

0 0

0

[

(

)

(

)

2

]

log

log

1

a

k

R

a

c

n

j j n

n

for

R

1

.

Theorem 5: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n such that

a

n

a

n1

...

a

1

a

0

for some

,

0

1

.

Then the number of zeros of P(z) in

(

R

0

,

c

1

)

c

R

z

, does not exceed

log

1

[

{(

)(cos

sin

1

)

(cos

sin

1

)

2

}]

log

1

0 0

1 0

n n

a

R

a

(6)

www.ijerd.com 58 | Page

for

R

1

and

log

1

[

{(

)(cos

sin

1

)

(cos

sin

1

)

}]

log

1

0 0

0 0

a

a

a

R

a

a

c

n

for

R

1

. For different values of the parameters

k

,

,

in the above results, we get many other interesting results.

II.

LEMMAS

For the proofs of the above results we need the following results:

Lemma 1: If f(z) is analytic in

z

R

,but not identically zero, f(0)

0 and

n

k

a

f

(

k

)

0

,

1

,

2

,...,

, then

n

j j

i

a

R

f

d

f

1 2

0

log

(Re

log

(

0

)

log

2

1

.

Lemma 1 is the famous Jensen’s theorem (see page 208 of [1]).

Lemma 2: If f(z) is analytic and

f

(

z

)

M

(

r

)

in

z

r

, then the number of zeros of f(z) in

,

c

1

c

r

z

does not exceed

)

0

(

)

(

log

log

1

f

r

M

c

.

Lemma 2 is a simple deduction from Lemma 1.

Lemma 3: Let

0

)

(

j j j

z

a

z

P

be a polynomial o f degree n with complex coefficients such that for some

real

,

,

,

0

,

2

arg

a

j

j

n

and

a

j

a

j1

,

0

j

n

,

then any t>0,

ta

j

a

j1

(

t

a

j

a

j1

)

cos

(

t

a

j

a

j1

)

sin

. Lemma 3 is due to Govil and Rahman [4].

III.

PROOFS OF THEOREMS

Proof of Theorem 1: Consider the polynomial F(z) =(1-z)P(z)

(

1

)(

...

1 0

)

1

1

z

a

z

a

a

z

a

z

n n

n

n

a

z

1

(

a

n

a

n 1

)

z

n

...

(

a

1

a

0

)

z

a

0 n

n

a

n

z

n1

a

0

(

n

n1

)

z

n

...

(

1

)

z

1

 

   

n

j

j j

j

z

i

z

z

z

k

k

0

1 0

0 0

1

1 2 1

1

)

(

)]

(

)

[(

...

)

(

]

)

1

(

)

[(





    

For

z

R

, we have by using the hypothesis

F

(

z

)

a

n

R

n 1

a

0

+

  

n

n1

R

n

...

1

R

1

k

1

R

(

k

1

)

R

1

2

R

1

...

1



0

R

(

1

)

0

R

 

n

j

j j 1

1

)

(7)

www.ijerd.com 59 | Page

0

[

1

...

1

1

(

1

)

1

k

k

R

a

R

a

n n

n n

n

...

(

1

)

2

]

1

1 0

0 0

1 2

1

 

n

j j

n



 

a

n

R

n

a

0

R

n

n

k

0

0

0

0

n 1

)

(

)

)(

1

(

[

2

]

1

1

 

n

j j

R

1

[

n

n

(

k

1

)(

)

(

0

0

)

2

0

n

2

]

0

n j

j

for

R

1

and

n

j j n

n

k

R

a

z

F

1 0

0 0 0

0

[

(

1

)(

)

(

)

2

]

)

(

for

R

1

. Therefore , by Lemma 3, it follows that the number of zeros of F(z) and hence

P(z) in

(

R

0

,

c

0

)

c

R

z

does not exceed

0

0 0

0 0

1

2

)

(

2

)

)(

1

(

[

log

log

1

a

k

R

c

n

j j n

n

n

 

 

for

R

1

and

0

1 0 0 0 0

0

[

(

1

)(

)

(

)

2

log

log

1

a

k

R

a

c

n

j j n

n

for

R

1

. That proves Theorem 1.

Proof of Theorem 3: Consider the polynomial F(z) =(1-z)P(z)

(

1

)(

...

1 0

)

1

1

z

a

z

a

a

z

a

z

n n

n

n

a

n

z

n1

(

a

n

a

n1

)

z

n

...

(

a

1

a

0

)

z

a

0

a

z

1

a

0

z

(

n n 1

)

z

n

...

(

2 1

)

z

2 n

n

n

 

n

j

j j

j

z

i

z

0

1 0

0 0

1

)

(

)]

(

)

[(





.

For

z

R

, we have by using the hypothesis

F

(

z

)

a

n

R

n1

a

0 +

R

n

n

n1

R

n

...

2

1

R

2

1



0

R

+ j n

j

j

j

R

R

 

0

1

0

(

)

)

1

(

R

n1

[

n

0

n

n1

...

2

1

1



0

n

j j 0 0

2

)

1

(8)

www.ijerd.com 60 | Page

[

(

)

2

2

]

0 0

0 0

1

n

j j n

n n

R

for

R

1

and

n

j j n

n

R

a

z

F

0 0 0 0

0

[

(

)

2

]

)

(

for

R

1

.

Therefore , by Lemma 2, it follows that the number of zeros of F(z) and hence

P(z) in

(

R

0

,

c

0

)

c

R

z

does not exceed

0

0 0

0 0 1

]

2

2

)

(

[

log

log

1

a

R

c

n

j j n

n

n

 

for

R

1

and

0

0 0

0 0

0

[

(

)

2

]

log

log

1

a

R

a

c

n

j j n

n

for

R

1

. That proves Theorem 3.

Proof of Theorem 5: Consider the polynomial F(z) =(1-z)P(z)

(

1

)(

...

1 0

)

1

1

z

a

z

a

a

z

a

z

n n

n

n

a

n

z

n1

(

a

n

a

n1

)

z

n

...

(

a

1

a

0

)

z

a

0

a

z

1

a

0

z

(

a

n

a

n 1

)

z

n

...

(

a

2

a

1

)

z

2 n

n

n

[(

a

1

a

0

)

(

a

0

a

0

)]

z

.

For

z

R

, we have by using the hypothesis and Lemma 3

0 1

)

(

z

a

R

a

F

n n

+

R

n

a

n

a

n1

R

n

...

a

2

a

1

R

2

a

1

a

0

R

+

(

1

)

0

R

a

n

R

n1

a

0

R

n

[(

a

n

a

n1

)

cos

(

a

n

a

n1

)

sin

]

R

n

R

a

a

a

a

R

a

R

a

a

a

a

]

sin

)

(

cos

)

[(

)

1

(

]

sin

)

(

cos

)

[(

...

0 1 0

1

2 0 2

1 2 1

2

R

n1

[(

a

n

)(cos

sin

1

)

0

(cos

sin

1

)

2

a

0

]

for

R

1

and

a

0

R

[(

a

n

)(cos

sin

1

)

a

0

(cos

sin

1

)

a

0

]

for

R

1

. Hence , by Lemma 2, it follows that the number of zeros of F(z) and therefore P(z)

in

(

R

0

,

c

0

)

c

R

z

does not exceed

}]

2

)

1

sin

(cos

)

1

sin

)(cos

{(

[

1

log

log

1

0 0

1 0

n n

a

R

a

(9)

www.ijerd.com 61 | Page

for

R

1

and

log

1

[

{(

)(cos

sin

1

)

(cos

sin

1

)

}]

log

1

0 0

0 0

a

a

a

R

a

a

c

n

for

R

1

. That completes the proof of Theorem 5.

REFERENCES

[1]. L.V.Ahlfors, Complex Analysis, 3rd edition, Mc-Grawhill

[2]. K. K. Dewan, Extremal Properties and Coefficient estimates for Polynomials with restricted Zeros and on location of Zeros of Polynomials, Ph.D. Thesis, IIT Delhi, 1980.

[3]. N. K. Govil and Q. I. Rahman, On the Enestrom- Kakeya Theorem, Tohoku Math. J. 20(1968),126-136.

[4]. M. H. Gulzar, On the Zeros of a Polynomial inside the Unit Disk, IOSR Journal of Engineering, Vol.3, Issue 1(Jan.2013) IIV3II, 50-59.

[5]. M. H. Gulzar, On the Number of Zeros of a Polynomial in a Prescribed Region, Research Journal of Pure Algebra-2(2), 2012, 35-49.

[6]. M. H. Gulzar, On the Zeros of a Polynomial, International Journal of Scientific and Research Publications, Vol. 2, Issue 7,July 2012,1-7.

[7]. Q. G. Mohammad, On the Zeros of Polynomials, Amer. Math. Monthly 72(1965), 631-633.

References

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