http://dx.doi.org/10.4236/am.2014.516248
Some Lacunary Sequence Spaces of
Invariant Means Defined by Musielak-Orlicz
Functions on 2-Norm Space
Mohammad Aiyub
Department of Mathematics, University of Bahrain, Sakhir, Bahrain Email: maiyub2002@gmail.com
Received 11 July 2014; revised 15 August 2014; accepted 25 August 2014
Copyright © 2014 by author and Scientific Research Publishing Inc.
This work is licensed under the Creative Commons Attribution International License (CC BY).
http://creativecommons.org/licenses/by/4.0/
Abstract
The purpose of this paper is to introduce and study some sequence spaces which are defined by combining the concepts of sequences of Musielak-Orlicz functions, invariant means and lacunary convergence on 2-norm space. We establish some inclusion relations between these spaces under some conditions.
Keywords
Invariant Means, Musielak-Orlicz Functions, 2-Norm Space, Lacunary Sequence
1. Introduction
Let ω be the set of all sequences of real numbers ∞,c and c0 be respectively the Banach spaces of bounded, convergent and null sequences x=
( )
xk with( )
xk ∈ or the usual norm x =supk xk ,where k∈ = 1, 2, 3,, the positive integers.
The idea of difference sequence spaces was first introduced by Kizmaz [1] and then the concept was gene- ralized by Et and Çolak [2]. Later on Et and Esi [3] extended the difference sequence spaces to the sequence spaces:
( )
m{
( )
:( )
m}
,v k v
X ∆ = x= x ∆ x ∈X
for X =∞, c and c0, where v=
( )
vk be any fixed sequence of non zero complex numbers and(
) (
1 1)
1 .
m m m
vxk v xk v xk
− −
+
∆ = ∆ − ∆
( )
01 , for all .
m i m
v k k i k i i
m
x v x k
i + +
=
∆ = − ∈
∑
The sequence spaces ∆mv
( )
∞ ,( )
m v c∆ and
( )
0m v c
∆ are Banach spaces normed by
1
.
m
m i i v i
x∆ v x x∞
=
=
∑
+ ∆The concept of 2-normed space was initially introduces by Gahler [4] as an interesting linear generalization of normed linear space which was subsequently studied by many others [5] [6]). Recently a lot of activities have started to study summability, sequence spaces and related topics in these linear spaces [7] [8]).
Let X be a real vector space of dimension d, where 2≤ < ∞d . A 2-norme on X is a function
.,. :X×X → which satisfies:
1) x y, =0 if and only if x and y are linearly dependent, 2) x y, = y x, ,
3) αx y, = α x y, ,α∈, 4) x y, + ≤z x y, + x z, .
The pair
(
X, .,.)
is called a 2-normed space. As an example of a 2-normed space we may take X =2being equiped with the 2-norm x y, = the area os paralelogram spaned by the vectors x and y, which may be given explicitly by the formula
11 22 1 2
21 22 ,
E
x x
x x abs
x x
=
.
Then clearly
(
X, .,.)
is 2-normed space. Recall that(
X, .,.)
is a 2-Banach space if every cauchy sequence in X is convergent to some x∈X .Let σ be a mapping of the positive integers into itself. A continuous linear functional φ on ∞ is said to be an invariant mean or σ-mean if and only if
1) φ
( )
x ≥0, when the sequence x=( )
xn has, xn≥0 for all n, 2) φ( )
e =1,e=(
1,1,1,)
,3) φ
( )
xσ( )n =φ( )
x for all x∈∞.If x=
( )
xk , where Tx=( )
Txk =( )
xσ( )k . It can be shown that( )
{
: lim kn , uniformly in}
k
Vσ = x∈∞ t x =l n
lim ,
l= −σ x where
( )
1( ) 2( ) ( )1
n k n
n n
kn
x x x x
t x
k
σ σ σ
+ + + +
=
+
[9].
In the case σ is the translation mapping n→ +n 1, σ -mean is often called a Banach limit and Vσ the set of bounded sequences of all whose invariant means are equal is the set of almost convergent sequence [10].
By Lacunary sequence θ =
( )
kr ,r=0,1, 2, where k0=0 we mean an increasing sequence of non neg- ative integers hr=(
kr−kr−1)
→ ∞(
r→ ∞)
. The intervals determined by θ are denoted by Ir =[
kr−1−kr]
and the ratio 1
r r
k
k−
will be denoted by qr. The space of lacunary strongly convergent sequence Nθ was de-
fined by Freedman et al. [11] as follows:
( )
1: lim 0 for some .
r
i k
r k I
r
N x x x l
h
θ →∞
=
= = − =
∑
An Orlicz function is a function M: 0,
[
∞ →)
[
0,∞)
which is continuous, non-decreasing and convex with( )
0 0, 0( )
It is well known that if M is convex function and M
( )
0 =0 then M( )
λx ≤λM x( )
, for all λ with0≤ ≤λ 1.
Lindenstrauss and Tzafriri [12] used the idea of Orlicz function and defined the sequence space which was called an Orlicz sequence space M such as
( )
1: k , for some 0
M k
k
x
x x M ρ
ρ ∞
=
= = < ∞ >
∑
which was a Banach space with the norm
1
inf 0 : k 1
k
x
x ρ M
ρ ∞
=
= > ≤
∑
which was called an Orlicz sequence space. The M was closely related to the space p which was an Orlicz
sequence space with M t
( )
= tp, for 1≤ < ∞p . Later the Orlicz sequence spaces were investigated by Prashar and Choudhry [13], Maddox [14], Tripathy et al. [15]-[17] and many others.A sequence of function M =
( )
Mk of Orlicz function is called a Musielak-Orlicz function [18] [19]. Also aMusielak-Orlicz function Φ = Φ
( )
k is called complementary function of a Musielak-Orlicz function M if( )
sup{
( )
: 0 , for}
1, 2, 3, .k t t s Mk s s k
Φ = − ≥ =
For a given Musielak-Orlicz function M, the Musielak-Orlicz sequence space lM and its subspaces M
are defined as follow:
( )
{
: , for some 0}
M k M
l = x=x ∈ω I cx < ∞ c>
( )
{
: , for all 0}
M = x=xk∈ω IM cx < ∞ c>
where IM is a convex modular defined by
( )
( )
( )
1
, .
M k k k M
k
I x M x x x l
∞
=
=
∑
= ∈We consider lM equipped with the Luxemburg norm
inf 0 : M 1
x
x k I
k
= > ≤
or equipped with the Orlicz norm
( )
(
)
0 1
inf 1 M : 0 .
x I kx k
k
= + >
The main purpose of this paper is to introduce the following sequence spaces and examine some properties of the resulting sequence spaces. Let M =
( )
Mk be a Musielak-Orlicz function,(
X, .,.)
is called a 2-normedspace. Let p=
( )
pk be any sequences of positive real numbers, for all k∈ and u=( )
uk such that(
)
0 1, 2, 3,
k
u ≠ k= . Let s be any real number such that s≥0. By ω
(
2−X)
we denote the space of all sequences defined over(
X, .,.)
. Then we define the following sequence spaces:( )
( )
(
)
(
)
, , , , , , .,.
1
2 :sup , 0, 0
k
r
m v
p m
kn v k s
k k k
r n rk I
M p u s
t x
x x X k u M z s
h
θ
σ ω
ω ρ
ρ ∞
−
∈
∆
∆
= = ∈ − < ∞ > ≥
( )
( )
(
)
(
)
, , , , , .,.
1
2 ::lim , 0 for some , 0, 0
k
r
m v
p m
kn v k s
k k k
r k I
r M p u s
t x
x x X k u M z l s
h
θ
σ ω
ω ρ
ρ
−
∈
∆
∆
= = ∈ − = > ≥
∑
( )
( )
(
)
(
)
0 , , , , , .,.
1
2 ::lim , 0 0, 0
k
r
m v
p m
kn v k s
k k k
r r k I
M p u s
t x
x x X k u M z s
h
θ
σ ω
ω ρ
ρ −
∈
∆
∆
= = ∈ − = > ≥
∑
Definition 1. A sequence space E is said to be solid or normal if
(
αkxk)
∈E whenever( )
xk ∈E and forall sequences of scalar
( )
αk with αk ≤1 [20].Definition 2. A sequence space E is said to be monotone if it contains the canonical pre-images of all its
steps spaces, [20].
Definition 3. If X is a Banach space normed by . , then ∆m
( )
X is also Banach space normed by( )
1
.
m
m k
k
x∆ x f x
=
=
∑
+ ∆Remark 1. The following inequality will be used throughout the paper. Let p=
( )
pk be a positive sequenceof real numbers with 0< pk ≤suppk =G,
(
)
1 max 1, 2G
D= − . Then for all a bk, k∈ for all k∈. We
have
(
)
.k k k
p p p
k k k k
a +b ≤D a + b (1)
2. Main Results
Theorem 1. Let M =
( )
Mk be a Musielak-Orlicz function, p=( )
pk be a bounded sequence of positive realnumber and θ =
( )
kr be a lacunary sequence. Then , , , , , .,.( )
,m v M p u s
θ
σ
ω ∞
∆
, , , , , .,.
( )
mv
M p u s
θ
σ ω
∆
and , , , , , .,. 0
( )
m v M p u sθ
σ ω
∆
are linear spaces over the field of complex numbers.
Proof 1. Let x
( )
xk ,y( )
yk θ,M p u s, , , , .,. 0( )
mvσ ω
= = ∈ ∆ and α β, ∈C . In order to prove the result we
need to find some ρ3 such that,
(
)
(
)
3 1
lim , 0, uniformly in .
k
r
p m
nk v k k
s
k k
r k I r
t x y
u k M z n
h
α β
ρ
−
→∞ ∈
∆ +
=
∑
Since
( ) ( )
, , , , , , .,. 0( )
mk k v
x y θ M p u s
σ ω
∈ ∆ , there exist positive ρ ρ1, 2 such that
(
)
1
lim , 0 uniformly in
k
r
p m
kn v k s
k k r
k I r
t x
u k M z n
h ρ
−
→∞ ∈
∆
=
∑
and
(
)
1
lim , 0 uniformly in .
k
r
p m
kn v k s
k k r
k I r
t x
u k M z n
h ρ
−
→∞ ∈
∆
=
∑
(
)
(
)
(
)
(
)
(
(
)
)
(
)
(
)
(
)
3 3 3 1 2 1 , 1 , , 1 , , , k r k r k r r p mnk v k k s k k k I r p m m
nk v k nk v k s k k k I r p m m
nk v k nk v k s
k k k I
r
m nk v k s
k k k I
r
t x y
u k M z
h
t x t y
u k M z z
h
t x t y
u k M z z
h
t x
D
u k M z
h α β ρ α β ρ ρ ρ ρ ρ − ∈ − ∈ − ∈ − ∈ ∆ + ∆ ∆ ≤ + ∆ ∆ ≤ + ∆ ≤
∑
∑
∑
∑
(
)
,0, as , uniformly in .
k k
r
p p
m nk v k s k k k I r t y D
u k M z
h r n ρ − ∈ ∆ + → → ∞
∑
So that
(
xk) (
yk)
θ,M p u s, , , , .,. 0( )
vm .σ
α + β ∈ω ∆ This completes the proof. Similarly, we can prove that
( )
, , , , , .,. m v
M p u s
θ
σ ω
∆
and θ,M p u s, , , , .,.
( )
mvσ
ω ∞
∆
are linear spaces.
Theorem 2. Let M=
( )
Mk be a Musielak-Orlicz function, p=( )
pk be a bounded sequence of positivereal number and θ =
( )
kr be a lacunary sequence. Then( )
0 , , , , , .,. m
v M p u s
θ
σ ω
∆
is a topological linear
space totalparanormed by
( )
(
)
1
1
1
inf : , 1 for some , 1, 2,
k r r H p m m
nk v k
p H s
k k k
k rk I
t x
g x x u k M z r
h ρ ρ ρ − ∆ = ∈ ∆ = + ≤ =
∑
∑
Proof 2. Clearly g∆
( )
x =g∆( )
−x . Since Mk( )
0 =0, for all k∈. we get g∆( )
θ =0, for x=θ. Let( )
kx= x , y
( )
yk ,M p u s, , , , .,. 0( )
mvθ
σ ω
= ∈ ∆ and let us choose ρ >1 0 and ρ >2 0 such that
( )
(
)
1
1
sup , 1 1, 2, 3,
k
r
p m
nk v k s
r k k
r k I
t x
h u k M z r
ρ − − ∈ ∆ ≤ =
∑
and( )
(
)
1 2sup , 1 1, 2, 3,
k
r
p m
nk v k s
r k k
r k I
t y
h u k M z r
ρ − − ∈ ∆ ≤ =
∑
Let ρ ρ ρ= 1+ 2, then we have
(
)
(
)
( )
(
)
( )
(
)
1 1 11 2 1
1 1
1 2 2
sup ,
sup ,
sup , 1.
k r k r k r p m
nk v k k
s
r k k
r k I
p m
nk v k
s
r k k
r k I
p m
nk v k
s
r k k
r k I
t x y
h u k M z
t x
h u k M z
t y
h u k M z
ρ
ρ
ρ ρ ρ
ρ
ρ ρ ρ
Since ρ>0, we have
(
)
(
)
( )
1 1 1 1 1 1 1inf : , 1 for some 0, 1, 2,
1
inf : , 1 for some
k r r k r r H p m m
nk v k k
p H s
k k k k
k rk I
H p m
m
nk v k
p H s
k k k
k rk I
g x y
t x y
x y u k M z r
h
t x
x u k M z
h ρ ρ ρ ρ ρ ∆ − = ∈ − = ∈ + ∆ +
= + + ≤ > =
∆ ≤ + ≤
∑
∑
∑
∑
( )
1 1 2 2 1 20, 1, 2,
1
inf : , 1 for some 0, 1, 2, .
k r r H p m m
nk v k
p H s
k k k
k rk I
r
t y
y u k M z r
h ρ ρ ρ ρ − = ∈
> =
∆
+ + ≤ > =
∑
∑
(
)
( )
( )
.g∆ x+y ≤g∆ x +g∆ y
Finally, we prove that the scalar multiplication is continuous. Let λ be a given non zero scalar in . Then the continuity of the product follows from the following expression.
( )
(
)
(
)
( )
1 1 1 1 1inf : , 1 for some 0, 1, 2,
1
inf : , 1 for some 0
k r r k r r H p m m
nk v k
p H s
k k k
k r k I
H p m
m p H
nk v k s
k k k
k r k I
t x
g x x u k M z r
h
t x
x u k M z
h
λ
λ λ ρ ρ
ρ
λ λ ζ ζ
ζ − ∆ = ∈ − = ∈ ∆
= + ≤ > =
∆
= + ≤ >
∑
∑
∑
∑
, r 1, 2,
=
where ζ ρ 0. λ
= > Since λ pr ≤max 1,
(
λ)
suppr ,( )
(
)
(
)
sup 1 max 1, 1inf : , 1, for some 0, 1, 2, .
r k r r p H p m
nk v k
p H s
k k k I
r
g x
t x
u k M z r
h λ λ ρ ρ ρ ∆ − ∈ = ∆
+ ≤ > =
∑
This completes the proof of this theorem.
Theorem 3. Let M=
( )
Mk be a Musielak-Orlicz function, p=( )
pk be a bounded sequence of positivereal number and θ=
( )
kr be a lacunary sequence. Then( )
( )
0( )
,M p u s, , , , .,. mv ,M p u s, , , , .,. vm ,M p u s, , , , .,. mv .
θ θ θ
σ σ σ
ω ∞ ω ω
∆ ⊂ ∆ ⊂ ∆
Proof 3. The inclusion θ,M p u s, , , , .,. 0
( )
mv θ,M p u s, , , , .,.( )
mvσ σ
ω ω
∆ ⊂ ∆ is obvious. Let
( )
, , , , , .,. m
k v
x ∈ωθ M p u s σ ∆ . Then there exists some positive number ρ1 such that
(
)
1 1
lim , 0
k
r
p m
nk v k s
k k r
k I r
t x le
u k M z
h ρ − →∞ ∈ ∆ − →
∑
as r→ ∞, uniformly in n. Define ρ=2ρ1. Since Mk is non decreasing and convex for all k∈, we
(
)
(
)
(
)
1 1 1 1 1 , , , ,max 1, ,
k r k r k r k r p m
nk v k s k k k I r p m
nk v k s k k k I r p k k I r p m
nk v k k
k I r
t x
u k M z
h
t x le
D
u k M z
h
D le
M z
h
t x le
D
M z
h
le
D M z
ρ ρ ρ ρ ρ − ∈ − ∈ ∈ ∈ ∆ ∆ − ≤ + ∆ − ≤ +
∑
∑
∑
∑
G where G=supk
( )
pk , max 1, 2(
1)
G
D= − by (1). Thus xk ,M p u s, , , , .,.
( )
vmθ
σ ω
∈ ∆ .
Theorem 4. Let M=
( )
Mk be a Musielak-Orlicz functions. If sup( )
k
p
kMk z < ∞ for all z>0, then
( )
( )
,M p u s, , , , .,. mv ,M p u s, , , , .,. mv .
θ θ
σ σ
ω ω ∞
∆ ⊂ ∆
Proof 4. Let xk ,M p u s, , , , .,.
( )
mvθ
σ ω
∈ ∆ by using (1), we have
(
)
(
)
1 , , , . k r k r k r p mnk v k s k k k I r p m
nk v k k k I r p k k I r t x
u k M z
h
t x le
D M z h le D M z h ρ ρ ρ − ∈ ∈ ∈ ∆ ∆ − ≤ +
∑
∑
∑
Since supkM z
( )
pk < ∞, we can take the supkM z( )
pk =K . Hence we can get( )
, , , , , .,. m
k v
x ∈ωθ M p u s σ ∆ .
This complete the proof.
Theorem 5. Let m≥1 be fixed integer. Then the following statements are equivalent: 1) , , , , , .,.
(
m 1)
, , , , , .,.( )
mv v
M p u s M p u s
θ θ
σ σ
ω ∞ − ω ∞
∆ ⊂ ∆
,
2)
( )
1( )
, , , , , .,. m , , , , , .,. m
v v
M p u s M p u s
θ θ
σ σ
ω − ω
∆ ⊂ ∆
,
3) , , , , , .,. 0
(
m1)
, , , , , .,. 0( )
m .v v
M p u s M p u s
θ θ
σ σ
ω − ω
∆ ⊂ ∆
Proof 5. Let xk∈ωθ,M p u s, , , , .,.σ0
( )
∆vm−1 . Then there exist ρ>0 such that(
)
1
lim , 0.
k
r
p m
nk v k s k k r k I r t x
u k M z
h ρ − →∞ ∈ ∆ →
∑
(
)
(
)
(
)
(
)
1 1 1 1 1 1 1 , 2 1 , 2 1 1 , , 2 2 k r k r k r r p mnk v k s k k k I r p m m
nk v k k
s k k k I r p m m
nk v k nk v k
s s
k k k k
k I k I
r r
t x
u k M z
h
t x x
u k M z
h
t x t x
u k M z u k M z
h h ρ ρ ρ ρ − ∈ − − + − ∈ − − + − − ∈ ∈ ∆ ∆ − ∆ = ∆ ∆ ≤ +
∑
∑
∑
∑
(
1)
(
1)
1 , , . k k k r r p p p m m
nk v k nk v k
s s
k k k k
k I k I
r r
t x t x
D D
u k M z u k M z
h ρ h ρ
− − + − − ∈ ∈ ∆ ∆ ≤ +
∑
∑
Taking limr→∞, we have
(
)
1 , 0, k r p mnk v k s
k k k I
r
t x
u k M z
h ρ − ∈ ∆ =
∑
i.e. 0
( )
1, , , , , .,. m .
k v
x ∈ωθ M p u s σ ∆ − The rest of these cases can be proved in similar way.
Theorem 6. Let M=
( )
Mk and T =( )
Tk be two Musielak-Orlicz functions. Then we have1) θ,M p u s, , , , .,.
( )
vm θ, , , , , .,.T p u s( )
vm θ,M T p u s, , , , .,.( )
mv .σ σ σ
ω ∞ ω ∞ ω ∞
∆ ∆ ⊂ + ∆
2) ,M p u s, , , , .,.
( )
vm , , , , , .,.T p u s( )
mv ,M T p u s, , , , .,.( )
mv .θ θ θ
σ σ σ
ω ω ω
∆ ∆ ⊂ + ∆
3) θ,M p u s, , , , .,. 0
( )
vm θ, , , , , .,.T p u s 0( )
vm θ,M T p u s, , , , .,. 0( )
mv .σ σ σ
ω ω ω
∆ ∆ ⊂ + ∆
Proof 6. Let , , , , , .,.
( )
m , , , , , .,.( )
m .k v v
x θ M p u s θ T p u s
σ σ
ω ∞ ω ∞
∈ ∆ ∆ Then
(
)
, 1 sup , k r p mnk v k s
k k r n rk I
t x
u k M z
h ρ
−
∈
∆
< ∞
∑
and(
)
, 1 sup , k r p mnk v k s
k k r n r k I
t x
u k T z
h ρ
−
∈
∆
< ∞
∑
uniformly in n. We have
(
)
(
)
,(
)
,(
)
,k k k
p p p
m m m
nk v k nk v k nk v k
k k k k
t x t x t x
M T z D M z D T z
ρ ρ ρ
∆ ∆ ∆
+ ≤ +
by (1). Applying r
k I∈
∑
and multiplying by k,1r
u
h and
s
k− both side of this inequality, we get
(
)
(
)
(
)
(
)
1 , , , k r k k r r p mnk v k s
k k k k I
r
p p
m m
nk v k nk v k
s s
k k k k
k I k I
r r
t x
u k M T z
h
t x t x
D D
u k M z u k T z
uniformly in n. This completes the proof 2) and 3) can be proved similar to 1).
Theorem 7. 1) The sequence spaces θ,M p u s, , , , .,.
σ
ω ∞
and θ,M p u s, , , , .,. 0
σ ω
are solid and hence
they are monotone.
2) The space θ,M p u s, , , , .,. σ ω
is not monotone and neither solid nor perfect.
Proof 7. We give the proof for θ,M p u s, , , , .,. 0
σ ω
. Let xk θ,M p u s, , , , .,. 0
σ ω
∈ and
( )
αk be asequence of scalars such that αk ≤1 for all k∈. Then we have
(
)
( )
1 1
, , 0
k k
r r
p p
nk k k nk k
s s
k k k k
k I k I
r r
t x t x
u k M z u k M z
h h
α
ρ ρ
− −
∈ ∈
≤ →
∑
∑
(
r→ ∞)
, uniformly in n. Hence(
kxk)
θ,M p u s, , , , .,. 0σ
α ∈ ω for all sequence of scalars
( )
αk with1
k
α ≤ for all k∈, whenever xk θ,M p u s, , , , .,. 0
σ ω
∈ . The spaces are monotone follows from the re- mark (1).
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