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R E S E A R C H

Open Access

Central limit theorems for sub-linear

expectation under the Lindeberg condition

Cheng Hu

1*

*Correspondence: [email protected] 1School of Mathematics and Statistics, Shandong Normal University, Jinan, China

Abstract

In this paper, we investigate the central limit theorems for sub-linear expectation for a sequence of independent random variables without assumption of identical

distribution. We first give a bound on the distance between the normalized sum distribution and G-normal distribution which can be used to derive the central limit theorem for sub-linear expectation under the Lindeberg condition. Then we obtain the central limit theorem for capacity under the Lindeberg condition. We also get the central limit theorem for capacity for summability methods under the Lindeberg condition.

MSC: 60F05

Keywords: Central limit theorem; Sub-linear expectation; Capacity; Lindeberg condition; G-normal distribution

1 Introduction

Peng [15] put forward the theory of sub-linear expectation to describe the probability un-certainties in statistics and economics which are difficult to be handled by classical prob-ability theory. There has been increasing interest in sub-linear expectation (see, for exam-ple, [1,2,4,11,18,26]).

The classical central limit theorem (CLT for short) is a fundamental result in probabil-ity theory. Peng [16] initiated the CLT for sub-linear expectation for a sequence of i.i.d. random variables with finite (2 +α)-moments for someα> 0. The CLT for sub-linear ex-pectation has gotten considerable development. Hu and Zhang [10] obtained a CLT for capacity. Li and Shi [13] got a CLT for sub-linear expectation without assumption of iden-tical distribution. Hu [9] extended Peng’s CLT by weakening the assumptions of test func-tions. Zhang and Chen [21] derived a weighted CLT for sub-linear expectation. Hu and Zhou [12] presented some multi-dimensional CLTs without assumption of identical dis-tribution. Li [14] proved a CLT for sub-linear expectation for a sequence of m-dependent random variables. Rokhlin [19] gave a CLT under the Lindeberg condition under classical probability with variance uncertainty. Zhang [22] gained a CLT for sub-linear expectation under a moment condition weaker than (2 +α)-moments. Zhang [23] established a mar-tingale CLT and functional CLT for sub-linear expectation under the Lindeberg condition. The purpose of this paper is to investigate the CLTs for sub-linear expectation for a se-quence of independent random variables without assumption of identical distribution. We first give a bound on the distance between the normalized sum distributionE[ϕ(Sn

Bn)] and

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G-normal distributionE[ϕ(ξ)], whereξN({0}; [σ2, 1]). It can be used to derive the CLT for sub-linear expectation under the Lindeberg condition directly, which coincides with the result in Zhang [23]. Different from the classical case, when choosingBnas the nor-malizing factor, we can also obtain a bound on the distance between the normalized sum distribution E[ϕ(Sn

Bn)] and the corresponding G-normal random variableE[ϕ(η)] where

ηN({0}; [1,σ2]). Secondly, we obtain a CLT for capacity under the Lindeberg condition

which extends the CLT for capacity for a sequence of i.i.d. random variables in Hu and Zhang [10]. We also study the CLT for capacity for summability methods under the Lin-deberg condition. The regular summability method is an important subject in functional analysis. In recent years it has been found that summability method plays an important role in the study of statistical convergence (see [5–7,20]). So it is meaningful to investigate the CLT for capacity for summability methods.

This paper is organized as follows. In Sect.2, we recall some basic concepts and lemmas related to the main results. In Sect.3, we give a bound on the distance between the normal-ized sum distribution and G-normal distribution. In Sect.4, we prove a CLT for capacity under the Lindeberg condition. In Sect.5, we show a CLT for capacity for summability methods under the Lindeberg condition.

2 Basic concepts and lemmas

This paper is studied under the sub-linear expectation framework established by Peng [15–18]. Let (Ω,F) be a given measurable space. LetHbe a linear space of real func-tions defined on Ω such that ifX1,X2, . . . ,XnHthenϕ(X1,X2, . . . ,Xn)H for each ϕCl,Lip(Rn) whereCl,Lip(Rn) denotes the linear space of local Lipschitz continuous

func-tionsϕsatisfying

ϕ(x) –ϕ(y)≤C1 +|x|m+|y|m|xy|, ∀x,y∈Rn,

for someC> 0,m∈Ndepending onϕ.Hcontains allIAwhereAF. We also denote

Cb,Lip(Rn) as the linear space of bounded Lipschitz continuous functionsϕsatisfying

ϕ(x) –ϕ(y)≤C|xy|, ∀x,y∈Rn,

for someC> 0.

Definition 2.1 A functionalE:H→Ris said to be a sub-linear expectation if it satisfies: for∀X,YH,

(a) Monotonicity:XYimpliesE[X]≥E[Y]. (b) Constant preserving:E[c] =c,∀c∈R. (c) Positive homogeneity:E[λX] =λE[X],∀λ≥0.

(d) Sub-additivity:E[X+Y]≤E[X] +E[Y]wheneverE[X] +E[Y]is well defined. The triple (Ω,H,E) is called a sub-linear expectation space.

Remark2.1 The sub-linear expectation E[·] satisfies translation invariance: E[X+c] =

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Definition 2.2([3]) A set functionV:F→[0, 1] is called a capacity if it satisfies (a) V(∅) = 0,V(Ω) = 1.

(b) V(A)≤V(B),AB,A,BF.

Definition 2.3 For a capacityV, a setAis a polar set ifV(A) = 0. And we say a property holds “quasi-surely” (q.s.) if it holds outside a polar set.

Definition 2.4 A sub-linear expectationE:H→Ris said to be continuous if it satisfies: (1) continuity from below:XnXimpliesE[Xn]↑E[X], where0≤Xn,XH. (2) continuity from above:XnXimpliesE[Xn]↓E[X], where0≤Xn,XH. A capacityV:F→[0, 1] is said to be continuous if it satisfies:

(1) continuity from below:AnAimpliesV(An)V(A), whereAn,AF. (2) continuity from above:AnAimpliesV(An)V(A), whereAn,AF.

The conjugate expectationEof sub-linear expectationEis defined by

E[X] := –E[–X], ∀XH.

Obviously, for allXH,E[X]≤E[X]. A pair of capacities can be induced as follows:

V(A) :=E[IA],v(A) :=E[IA] = 1 –V(Ac),∀AF.

Definition 2.5([15–18]) (Independence)Y= (Y1, . . . ,Yn) (YiH) is said to be indepen-dent ofX= (X1, . . . ,Xm) (XiH) if, for each test functionϕCl,Lip(Rm×Rn),

Eϕ(X,Y)=EEϕ(x,Y)|x=X

,

whenever the sub-linear expectations are finite.

{Xn}∞n=1is said to be a sequence of independent random variables ifXn+1is independent of (X1, . . . ,Xn) for eachn≥1.

LetXbe ann-dimensional random variable on a sub-linear expectation space (Ω,H,E). We define a functional onCl,Lip(Rn) such that

FX[ϕ] :=E

ϕ(X), ϕCl,Lip

RnR.

ThenFX[·] can be regarded as the distribution ofX underEand it characterizes the

un-certainty of the distribution ofX.

Definition 2.6 ([15–18]) (Identical distribution) Twon-dimensional random variables

X1,X2on respective sub-linear expectation spaces (Ω1,H1,E1) and (Ω2,H2,E2) are called

identically distributed, denoted byX1=dX2, if

E1

ϕ(X1)=E2

ϕ(X2), ∀ϕCl,Lip

Rn,

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Definition 2.7([15–18]) A one-dimensional random variableξon sub-linear expectation (Ω,H,E) is said to beG-normal distributed, denoted byξN(0, [σ2,σ2]), if for anyϕ

Cl,Lip(R) the following function defined by

u(t,x) :=Eϕ(x+√), (t,x)∈[0,∞)×R,

is the unique viscosity solution of the following parabolic partial differential equation (PDE) defined on [0,∞)×R:

⎧ ⎨ ⎩

∂tuG(∂xxu) = 0,

u|t=0=ϕ,

whereG(a) =12a+σ2–12aσ2,a∈R.

Remark2.2 TheG-normal distributed random variableξ satisfies:+ =da2+b2ξ,

a,b≥0, whereξ=andξis independent ofξ. This impliesE[ξ] =E[–ξ] = 0.

Next we recall the definition of G-expectation. LetΩ=C[0,∞) be a space of allR -valued continuous paths (ωt)t≥0withω0= 0, equipped with distance

ρω1,ω2:= ∞

i=1

2–imax

t∈[0,i]ω 1

tω2t∧1

.

DenoteWt(ω) :=ωtfor eachωΩand

Lip(Ω) :=

ϕ(Wt1, . . . ,Wtk) :k∈N,t1, . . . ,tk∈[0,∞),ϕCb,Lip

Rk.

For each given monotonic and sub-linear functionG(a) =12a+σ21

2aσ2, 0≤σσ<∞,

a∈R, let the canonical process (Wt)t≥0be G-Brownian motion on a G-expectation space (Ω,Lip(Ω),E). That is,

Eϕ(Wt1, . . . ,Wtn–1,WtnWtn–1)

=Eψ(Wt1, . . . ,Wtn–1)

,

whereψ(x1, . . . ,xn–1) =E[ϕ(x1, . . . ,xn–1,tntn–1W1)],W1∼N({0}; [σ2,σ2]). For eachp≥1, we denoteLpG(Ω) as the completion ofLip(Ω) under the normXLp

G:=

(E[|X|p])1/p. Then the G-expectationEcan be continuously extended to (Ω,LpG(Ω)). We still denote the extended G-expectation space by (Ω,LpG(Ω),E).

Proposition 2.1([4,11]) There exists a weakly compact set of probability measuresPon

(Ω,B(Ω))such that

E[X] =sup

P∈PEP[X] for any XL

1 G(Ω),

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Given a G-expectation space (Ω,L1

G(Ω),E), we can define a pair of capacities:

V(A) :=sup

P∈PP(A) =

E[IA], v(A) :=inf

P∈PP(A) = 1 –V

Ac, AB(Ω).

Obviously, by Proposition2.1,E[·] andV(·) are continuous from below.

Definition 2.8 A sub-linear expectationE is said to be regular if, for each sequence

{Xn}∞n=1satisfyingXn↓0, we haveE[Xn]↓0.

Lemma 2.1([4,11])

(1) For any closed setsFnF,it holds thatV(Fn)↓V(F). (2) G-expectationE[·]is regular.

Hu et al. [11] indicated thatG-Brownian motion does not converge to any single point in probability under capacityVas follows.

Lemma 2.2 Given a G-expectation space(Ω,L2G(Ω),E),for any fixed a∈R,it holds that

lim ε0supa∈R

V|Wta| ≤ε

= 0, ∀t> 0.

In particular,the above equation holds for G-normal distribution W1.

Lemma 2.3([8]) E[|X|] <∞implies|X|<∞q.s.,i.e.,V(|X|=∞) = 0.

The following Rosenthal’s inequality under sub-linear expectation was obtained by Zhang [24].

Proposition 2.2 Assume that{Xn}∞n=1is a sequence of independent random variables.

De-note Sn:=ni=1Xi.Then,for any p≥2,we have

Emax

i≤n |Si| p

Cp

n

i=1

E|Xi|p

+

n

i=1

E|Xi|2

p2 +

n

i=1

E[Xi]++E[Xi]

p

, (2.1)

where Cpis a positive constant depending on p.

Lemma 2.4 Assume thatEis continuous from below andlimn→∞Xn=X.Then

E[X]≤lim inf

n→∞ E[Xn].

If we further assume thatEis continuous,then

E[X] = lim

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Proof Sinceinfi≥nXiis non-decreasing inn, we have

E[X] =Elim inf

n→∞ Xn

=Elim

n→∞infi≥nXi

= lim

n→∞E

inf

i≥nXi

=lim inf

n→∞ E

inf

i≥nXi

≤lim inf

n→∞ E[Xn].

IfEis continuous, by noting thatsupi≥nXiis non-increasing inn, we have

E[X] =E

lim sup

n→∞ Xn

=E

lim

n→∞supi≥nXi

= lim

n→∞E

sup

i≥nXi

=lim sup

n→∞ E

sup

i≥nXi

≥lim sup

n→∞ E[Xn]≥lim infn→∞ E[Xn]≥E[X].

Thuslimn→∞E[Xn] =E[X].

Lemma 2.5 Assume thatEis continuous from below and regular. Let{Xn}∞n=1 be a

se-quence of independent random variables with E[Xn] =E[Xn] = 0 for any n≥1 and

i=1E[Xi2] <∞.Then S:=

i=1Xiconvergence q.s.under capacityVand,for any p≥2,

we have

E|S|pCp

i=1

E|Xi|p

+

i=1

E|Xi|2

p2

. (2.2)

Proof One can refer to Zhang and Lin [25] for the proof of the convergence ofS. Now we prove (2.2). ByE[Xn] =E[Xn] = 0, takinglim supn→∞on both sides of (2.1), we have

lim sup

n→∞ E

max

i≤n |Si| pC

p

i=1

E|Xi|p

+

i=1

E|Xi|2

p2 .

On the other hand,

Emax

i≤n |Si|

pE|S n|p

.

Note thatlimn→∞Sn=S. By Lemma2.4we have

lim inf

n→∞ E

max

i≤n |Si|

plim inf n→∞ E

|Sn|p

≥E|S|p.

Combining the above inequalities, we have

E|S|pCp

i=1

E|Xi|p

+

i=1

E|Xi|2

p2 .

Throughout the rest of this paper, let {Xn}∞n=1 be a sequence of independent random variables on a sub-linear expectation space (Ω,H,E) withE[Xn] =E[Xn] = 0,E[Xn2] =σ2n,

E[Xn2] =σ2n, 0 <σnσn<∞. DenoteSn:=

n

i=1Xi,B 2 n:=

n

i=1σ2i, andB2n:=

n

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Zhang [23] obtained the following CLT for sub-linear expectation under the Lindeberg condition as a corollary of the martingale CLT for sub-linear expectation.

Theorem 2.1 Letξbe G-normal distributed on a G-expectation space(Ω,L2G(Ω),E)with

ξN({0}; [σ2, 1]), 0 <σ1.Assume that

(1)

lim

n→∞ 1

B2n

n

i=1

σσ2iσ2i= 0. (2.3)

(2) For anyε> 0,

lim

n→∞ 1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

= 0. (2.4)

Then,for anyϕCb,Lip(R),

lim

n→∞E

ϕ

Sn

Bn

=Eϕ(ξ). (2.5)

3 The bound on the distance between the normalized sum distribution and G-normal distribution

The following theorem gives a bound on the distance between the normalized sum distri-butionE[ϕ(Sn

Bn)] and G-normal distributionE[ϕ(ξ)] whereξN({0}; [σ

2, 1]).

Theorem 3.1 Letξbe G-normal distributed on a G-expectation space(Ω,L2G(Ω),E)with

ξN({0}; [σ2, 1]), 0 <σ≤1.

Then,for any fixedϕCb,Lip(R)and any h> 0, 0 <ε< 1,there exist some0 <α< 1,C> 0,

and Ch> 0 (a positive constant depending on h)such that

E

ϕ

Sn

Bn

–Eϕ(ξ)

Ch

B2n

n

i=1

σσ2iσ2i+Ch

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

+Ch

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

+Chεα+C(

h+√1 +h– 1). (3.1)

Remark3.1 By Theorem3.1we can derive Theorem2.1. If (2.3) and (2.4) hold, taking

n→ ∞,ε→0, andh→0 in turn on both sides of (3.1), we can get (2.5).

Proof For any fixedϕCb,Lip(R) and anyh> 0, letV(t,x) =E[ϕ(x+

1 +h)]. By Def-inition2.7, we have thatVis the unique viscosity solution of the following parabolic PDE:

⎧ ⎨ ⎩

∂tV+12(∂xxV)+–12(∂xxV)–σ2= 0,

V|t=1+h=ϕ.

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LetX(n)i = (–Bn)∨(XiBn),Si(n)=B1n i

j=1X (n) j ,S

(n) 0 = 0,δ

(n) i =B12

n i

j=1σ2j,δ (n)

0 = 0 for each

i= 1, 2, . . . ,n. Then we have

E

ϕ

Sn

Bn

–Eϕ(ξ)

≤E

ϕ

Sn

Bn

–EϕSn(n)+EϕS(n)n –Eϕ(ξ)

=E

ϕ

Sn

Bn

–EϕS(n)n +EV1 +h,S(n)nV(h, 0)

≤E

ϕ

Sn

Bn

–EϕSn(n)+EV1 +h,Sn(n)–EV1,S(n)n

+EV1,S(n)nV(0, 0)+V(0, 0) –V(h, 0).

SinceϕCb,Lip(R), for any 0 <ε< 1, it holds that

E

ϕ

Sn

Bn

–EϕS(n)n

C

Bn n

i=1

EXiXi(n)≤

C Bn

n

i=1

E|Xi|I

|Xi|>Bn

C

B2n

n

i=1

E|Xi|2I

|Xi|>Bn

C

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

,

E

V1 +h,Sn(n)–EV1,S(n)n

≤sup

x

V(1 +h,x) –V(1,x)=sup

x

ϕ(x) –Eϕ(x+√)

≤sup

x

Eϕ(x) –ϕ(x+√)≤ChE|ξ|≤Ch,

and

V(0, 0) –V(h, 0)=Eϕ(√1 +)–Eϕ(ξ)

C(√1 +h– 1)E|ξ|≤C(√1 +h– 1).

Then

E

ϕ

Sn

Bn

–Eϕ(ξ)≤EV1,Sn(n)–V(0, 0)+ C

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

+C(√h+√1 +h– 1). (3.3)

So it is sufficient to get the bound of|E[V(1,S(n)n )] –V(0, 0)|.

V1,S(n)nV(0, 0)

= n–1

i=0

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= n–1

i=0

(n)i+1,Si+1(n)–(n)i ,S(n)i+1+(n)i ,S(n)i+1i(n),S(n)i

:= n–1

i=0

Ii(n)+Ji(n),

whereIi(n)andJi(n)are obtained by Taylor expansion:

Ii(n)=σ 2 i+1

B2n

∂tV

δi(n),Si(n)+ 1 2B2n

∂xxV

δi(n),S(n)i Xi+1(n)2+ 1

Bn ∂xV

δi(n),S(n)i Xi+1(n)

=

σ2i+1

B2n

∂tV

δi(n),S(n)i + 1 2B2n

∂xxV

δi(n),S(n)i Xi+12 + 1

Bn ∂xV

δ(n)i ,S(n)i Xi+1

+

1

2B2n

∂xxV

δ(n)i ,S(n)i Xi+1(n)2–Xi+12 + 1

Bn ∂xV

δi(n),S(n)i Xi+1(n)–Xi+1

:=I1,i(n)+I2,i(n).

Ji(n)=σ 2 i+1

B2n

∂tV

δ(n)i ,S(n)i+1∂tV

δ(n)i ,S(n)i

+σ 2 i+1

B2n

1

0

∂tV

δ(n)i +β·σ 2 i+1

B2n ,S

(n) i+1

∂tV

δi(n),Si+1(n)

+ 1 0 1 0

∂xxV

δi(n),Si(n)+γ βX (n) i+1

Bn

∂xxV

δi(n),Si(n)|X

(n) i+1|2

B2n

γdβdγ.

SinceXi+1is independent ofSi(n), we have

E∂xV

δi(n),Si(n)Xi+1

=EE[r·Xi+1]|r=

xV(δ(in),S

(n)

i )

=E∂xV

δi(n),S(n)i +E[Xi+1] –

∂xV

δi(n),Si(n)–E[Xi+1]

= 0.

Similarly, we can also haveE[–∂xV(δ(n)i ,S (n)

i )Xi+1] = 0. It follows that

EI1,i(n)=E

σ2i+1

B2n

∂tV

δi(n),Si(n)+ 1 2B2n

∂xxV

δi(n),S(n)i X2i+1

= 1

B2nE

E

σ2i+1p+1 2qX

2 i+1

p=∂tV(δ(in),S(in)),q=∂xxV(δi(n),Si(n))

= 1

B2nE

σ2i+1p+1 2q

+EX2 i+1

–1 2q

EX2 i+1

p=∂tV(δi(n),Si(n)),q=∂xxV(δ(in),S(in))

= 1

B2nE

∂tV

δ(n)i ,S(n)i σ2i+1+1 2

∂xxV

δi(n),S(n)i +σ2i+1

–1 2

∂xxV

δ(n)i ,S(n)iσ2i+1

σ2i+1

B2n E

∂tV

δi(n),Si(n)+1 2

∂xxV

δi(n),Si(n)+–1 2

∂xxV

δi(n),Si(n)–σ2

(10)

+ 1 2B2nE

∂xxV

δ(n)i ,S(n)iσσ2i+1∂xxV

δi(n),Si(n)–σ2i+1

≤ 1

2B2n

σσ2i+1σ2i+1·E∂xxV

δi(n),S(n)i .

By the interior regularity ofV (see Peng [18]), it holds that

V

C1+α2 ,2+α([0,1]×R)<∞ for someα∈(0, 1),

which implies∂tV,∂xV, and∂xxV are uniformly α2-Hölder continuous intandα-Hölder continuous inxon [0, 1]×R. For anyn≥1 andin, it holds that

E∂xxV

δi(n),Si(n)≤∂xxV(0, 0)+Chδ(n)i

α

2 +ES(n) i

α

Ch

1 +ES(n)i 2α2.

By Proposition2.2, we have

ES(n)i 2≤ C B2n

n

i=1

EXi(n)2+ C

B2n

n

i=1

EXi(n)++E–Xi(n)+

2

C

B2n

n

i=1

E|Xi|2

+ C

B2n

n

i=1

EXiXi(n)

2

C+C

1

Bn n

i=1

E|Xi|I

|Xi|>Bn

2

C+C

1

B2n

n

i=1

E|Xi|2

2

C.

So we haveE[|∂xxV(δi(n),S (n)

i )|]≤Ch. SimilarlyE[|∂xV(δi(n),S (n)

i )|]≤Ch. Then

E n–1

i=0

I1,i(n)

n–1

i=0

EI1,i(n)≤Ch B2n

n

i=1

σσ2iσ2i.

On the other hand,

E n–1

i=0

I1,i(n)

=E

n–2

i=0

I1,i(n)+σ 2 n

B2n

∂tV

δn–1(n),Sn–1(n)+ 1 2B2n

∂xxV

δn–1(n) ,Sn–1(n)X2n

+ 1

Bn ∂xV

δn–1(n) ,Sn–1(n)Xn

=E

n–2

i=0

I1,i(n)+σ 2 n

B2n

∂tV

δn–1(n),Sn–1(n)+ 1 2B2n

∂xxV

δn–1(n) ,Sn–1(n)X2n

(11)

=E

n–2

i=0

I1,i(n)+σ 2 n

B2n

∂tV

δn–1(n),Sn–1(n)

+ 1 2B2n

∂xxV

δn–1(n),S(n)n–1+σ2n– 1 2B2n

∂xxV

δn–1(n),Sn–1(n)–σ2n

=E

n–2

i=0

I1,i(n)+σ 2 n

B2n

∂tV

δn–1(n) ,Sn–1(n)+1 2

∂xxV

δn–1(n),S(n)n–1+

–1 2

∂xxV

δn–1(n),S(n)n–1σ2

+ 1 2B2n

∂xxV

δn–1(n),S(n)n–1σσ2n– 1 2B2n

∂xxV

δ(n)n–1,S(n)n–1σ2n

=E

n–2

i=0

I1,i(n)+ 1 2B2n

∂xxV

δ(n)n–1,S(n)n–1σσ2nσ2n

≥E n–2

i=0

I1,i(n)

–E

– 1 2B2n

∂xxV

δn–1(n),S(n)n–1σσ2nσ2n

≥E n–2

i=0

I1,i(n)

Ch

B2n

σσ2nσ2n

≥–Ch

B2n

n

i=1

σσ2iσ2i.

So we have

E n–1 i=0

I1,i(n)

Ch

B2n

n

i=1

σσ2iσ2i. (3.4)

Since |Xi+1(n)|2X2

i+1 is independent of∂xxV(δi(n),S (n) i ) andX

(n)

i+1Xi+1 is independent of ∂xV(δi(n),S

(n)

i ), we have

n–1

i=0

EI2,i(n)≤

n–1

i=0

1

2B2nE

∂xxV

δi(n),S(n)i EXi+1(n)2–Xi+12

+ 1

Bn

E∂xV

δi(n),S(n)i EXi+1(n)–Xi+1

Ch

B2n

n

i=1

E|Xi|2I

|Xi|>Bn

+Ch

Bn n

i=1

E|Xi|I

|Xi|>Bn

Ch

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

. (3.5)

On the other hand,

σ2i+1

B2n

∂tV

δi(n),Si+1(n)–∂tV

δ(n)i ,S(n)i Ch· σ2i+1

B2n ·

|

Xi+1(n)| Bn

α

(12)

σ2i+1

B2n

1

0

∂tV

δ(n)i +β·σ 2 i+1

B2n

,S(n)i+1

∂tV

δ(n)i ,S(n)i+1Ch· σ2i+1

B2n ·

σ2i+1

B2n

α

2 ,

0101∂xxV

δi(n),Si(n)+γ βX (n) i+1

Bn

∂xxV

δ(n)i ,S(n)i |X

(n) i+1|2

B2n

γdβdγ

Ch·|

Xi+1(n)|2

B2n ·

|Xi+1(n)|

Bn α . Then n–1 i=0

EJi(n)≤ Ch B2+n α

n

i=1

σ2iEXi(n)α+ Ch

B2+nα

n

i=1

σ2+i α+ Ch

B2+nα

n

i=1

EX(n)i 2+α. (3.6)

For any 0 <ε< 1, we have

1

B2+nα

n

i=1

EX(n)i 2+α

= 1

B2+n α

n

i=1

E|Xi|2+αI

|Xi| ≤Bn

+B2+n αI|Xi|>Bn

≤ 1

B2+nα

n

i=1

E|Xi|2+αI

|Xi| ≤εBn

+ 1

B2+n α

n

i=1

E|Xi|2+αI

εBn<|Xi| ≤Bn

+ 1

B2+nα

n

i=1

E|Xi|2B

α

nI

|Xi|>Bn

≤ 1

B2+nα

n

i=1

εαBαnE|Xi|2

+ 1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

+ 1

B2n

n

i=1

E|Xi|2I

|Xi|>Bn

εα+ C

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

. (3.7)

By Hölder’s inequality under sub-linear expectation, we have

1

B2+nα

n

i=1 σ2+i α

= 1

B2+n α

n

i=1

E|Xi|2I

|Xi| ≤εBn

+|Xi|2I

|Xi|>εBn

1+α2

C

B2+nα

n

i=1

E|Xi|2I

|Xi| ≤εBn

1+α2 + C

B2+nα

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

C

B2+nα

n

i=1

E|Xi|2+αI

|Xi| ≤εBn

+ C

B2+n α

n

i=1

E|Xi|2I

|Xi|>εBn

(13)

Cεα+C

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

. (3.8)

1

B2+nα

n

i=1

σ2iEXi(n)α

≤ 1

B2+nα

n

i=1

σ2iE|Xi|α

≤ 1

B2+nα

n

i=1 σ2+i α

Cεα+C

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

. (3.9)

Combining (3.7), (3.8), and (3.9), we have

n–1

i=0

EJi(n)≤Chεα+

Ch

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

+Ch

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

. (3.10)

By (3.4), (3.5), and (3.10), it holds that

E

V1,S(n)nV(0, 0)≤

E

n–1

i=0

I1,i(n)

+

n–1

i=0

EI2,i(n)+ n–1

i=0

EJi(n)

Ch

B2n

n

i=1

σσ2iσ2i+Chεα

+Ch

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

+Ch

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2 .

Thus we obtain (3.1).

By a similar method, we can obtain a bound on the distance between the normalized sum distributionE[ϕ(Sn

Bn)] and the corresponding G-normal distributionE[ϕ(η)]. And it

can also be used to derive the CLT for normalizing factorBn. We only give the theorem and omit the proof.

Theorem 3.2 Letηbe G-normal distributed on a G-expectation space(Ω,L2

G(Ω),E)with ηN({0}; [1,σ2]),σ≥1.

Then,for any fixedϕCb,Lip(R)and any h> 0, 0 <ε< 1,there exist some0 <α< 1,C> 0,

and Ch> 0 (a constant depending on h)such that

E

ϕ

Sn

Bn

–Eϕ(η)

Ch

B2n

n

i=1

σσ2iσ2i+Ch

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

(14)

+Ch

1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

1+α2

+Chεα+C(

h+√1 +h– 1).

If we further assume that

(1)

lim

n→∞ 1

B2n

n

i=1

σσ2iσ2i= 0.

(2) For anyε> 0,

lim

n→∞ 1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

= 0.

Then,for anyϕCb,Lip(R),

lim

n→∞E

ϕ

Sn

Bn

=Eϕ(η).

4 Central limit theorem for capacity

The following theorem is the CLT for capacity under the Lindeberg condition.

Theorem 4.1 Assume that

(1) ξisG-normal distributed on a G-expectation space(Ω,L2G(Ω),E)with

ξN({0}; [σ2, 1]),0 <σ≤1,and

lim

n→∞ 1

B2n

n

i=1

σσ2iσ2i= 0. (4.1)

(2) For anyε> 0,

lim

n→∞ 1

B2n

n

i=1

E|Xi|2I

|Xi|>εBn

= 0. (4.2)

Then,for any a∈R,

lim

n→∞V

Sn

Bn

a

=V(ξa), lim

n→∞v

Sn

Bn

a

=v(ξa). (4.3)

Proof For any fixedε> 0, define

f(x) =

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

1, xa,

–1ε(xaε), a<xa+ε,

(15)

and

g(x) =

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

1, xaε,

–1ε(xa), aε<xa,

0, x>a.

It is easy to verify thatf,gCb,Lip(R) andg(x)≤I(xa)≤f(x). It follows that

V

Sn

Bn

a

–V(ξa)

=E

I

Sn

Bn

a

–EI(ξa)

≤E

f

Sn

Bn

–Eg(ξ)∨E

g

Sn

Bn

–Ef(ξ)

≤E

f

Sn

Bn

–Ef(ξ)+Ef(ξ)–Eg(ξ)

∨E

g

Sn

Bn

–Eg(ξ)+Eg(ξ)–Ef(ξ)

≤E

f

Sn

Bn

–Ef(ξ)∨E

g

Sn

Bn

–Eg(ξ)+Ef(ξ) –g(ξ).

By Theorem2.1we have

lim

n→∞

E

f

Sn

Bn

–Ef(ξ)= 0, lim

n→∞

E

g

Sn

Bn

–Eg(ξ)= 0.

Then

lim sup

n→∞

V

Sn

Bn

a

–V(ξa)≤Ef(ξ) –g(ξ).

Note that

0≤f(x) –g(x)≤I(aε<xa+ε),

which implies

Ef(ξ) –g(ξ)≤V(aε<ξa+ε).

By the arbitrariness ofε> 0 and Lemma2.2, we have

lim

n→∞

V

Sn

Bn

a

–V(ξa)= 0,

which implies

lim

n→∞V

Sn

Bn

a

(16)

Similarly, we can also obtain

lim

n→∞V

Sn

Bn

a

=V(ξa).

That is,

lim

n→∞v

Sn

Bn

a

=v(ξa).

Remark4.1 By a similar method, we can also obtain the CLT for capacity for the normal-ized sumSn/Bn. We omit the details here.

5 Central limit theorem for summability methods

Letci(λ) be continuous functions on (0,∞) orλonly valued inN∗. Assume that 0≤ci(λ)≤ 1 and, for anyλ> 0,

i=1

ci(λ) = 1 +θ(λ),

wherelimλ→∞θ(λ) = 0. DenoteB

2

λ=

i=1ci(λ)2σ2i,B2λ=

i=1ci(λ)2σ2i, whereB 2

λ<∞for

anyλ> 0. Assume thatEis continuous from below and regular, then by Lemma2.5,:=

i=1ci(λ)Xiis well defined q.s. under capacityV.

Theorem 5.1 Given a sub-linear expectation space(Ω,H,E),Eis continuous from below and regular.Assume that

(1) ξisG-normal distributed on a G-expectation space(Ω,L2

G(Ω),E)with ξN({0}; [σ2, 1]),0 <σ≤1,and

lim λ→∞

1

B2λ

i=1

c2i(λ)σσ2iσ2i= 0. (5.1)

(2) For anyε> 0,

lim λ→∞

1

B2λ

i=1

c2i(λ)E|Xi|2I

ci(λ)|Xi|>εBλ

= 0. (5.2)

Then,for any a∈R,

lim λ→∞V

a

=V(ξa), lim λ→∞v

a

=v(ξa). (5.3)

Proof Denote

,N= N

i=1

ci(λ)Xi, Sλ,N= ∞

i=N+1

ci(λ)Xi, B 2

λ,N = N

i=1

c2i(λ)σ2i.

Note thatlimN→∞B2λ,N=B 2

λ. For anyk> 1, we can chooseN sufficiently large such that B2λ,N≥B

2

(17)

For anya> 0,t> 0, andX,YH, it holds that

{X+Ya} ⊂ {Xa+t} ∪|Y| ≥t.

Then

V(X+Ya)≤V(Xa+t) +V|Y| ≥t.

Hence

V

a

=V

,N

+S

λ,N

a

≤V

,N

a+t

+V

|S

λ,N|

t

≤V

,N

,N

k(a+t)

+VSλ,NtBλ

.

For anyη> 0, let

f(x) =

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

1, xk(a+t),

–1η(xk(a+t) –η), k(a+t) <xk(a+t) +η,

0, x>k(a+t) +η,

and

g(x) =

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

1, xk(a+t) –η,

–1

η(xk(a+t)), k(a+t) –η<xk(a+t),

0, x>k(a+t).

It is easy to verify thatf,gCb,Lip(R) andg(x)≤I(xk(a+t))≤f(x). By the proof process of Theorem4.1, we have

V

,N

,N

k(a+t)

≤Vξk(a+t)+E

f

,N

,N

–Ef(ξ)∨E

g

,N

,N

–Eg(ξ)

+Vk(a+t) –η<ξk(a+t) +η.

By (3.1), for any 0 <ε< 1, we have

E

f

,N

,N

–Ef(ξ)∨E

g

,N

,N

–Eg(ξ)

Ch

B2λ,N N

i=1

c2i(λ)σσ2iσ2i+ Ch

B2λ,N N

i=1

c2i(λ)E|Xi|2I

ci(λ)|Xi|>εBλ,N

(18)

+Ch

1

B2λ,N N

i=1

c2i(λ)E|Xi|2I

ci(λ)|Xi|>εBλ,N

1+α2

+Chεα+C(

h+√1 +h– 1).

Note thatB2λ,N≥B 2

λ/k2, we have

E

f

,N

,N

–Ef(ξ)∨E

g

,N

,N

–Eg(ξ)

k2Ch

B2λ

i=1

c2i(λ)σσ2iσ2i+k 2C

h

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

+Ch

k2

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

1+α2

+Chεα+C(

h+√1 +h– 1).

In addition, by Lemma2.5we have

ESλ,N 2 =E ∞ i=N+1

ci(λ)Xi

2 ≤Ci=N+1

c2i(λ)E|Xi|2

0 asN→ ∞.

Lett= (E[|Sλ,N|2]) 1

3. We havelimN→∞t= 0 and

VSλ,NtBλ

≤ 1

t2B2

λ

ESλ,N2= 1

B2λ

ESλ,N213 →0 asN→ ∞.

So we have

V a

≤Vξk(a+t)+Vk(a+t) –η<ξk(a+t) +η+ 1

t2B2

λ

E∗,N 2

+k 2C

h

B2λ

i=1

c2i(λ)σσ2iσ2i+k 2C

h

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

+Ch

k2

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

1+α2 +Chεα

+C(√h+√1 +h– 1).

By (5.1), (5.2), Lemma2.1, and Lemma 2.2, lettingt= (E[|∗,N|2]) 1

3, N→ ∞, λ→ ∞, ε→0, andη→0 in turn, we have

lim sup λ→∞ V a

(19)

By the arbitrariness ofk> 1 andh> 0, we get

lim sup λ→∞ V

a

≤V(ξa). (5.4)

On the other hand, for anya> 0, 0 <t<a, andX,YH,

{X+Ya} ⊃ {Xat}\|Y| ≥t.

Then

V(X+Ya)≥V(Xat) –V|Y| ≥t.

Hence

V

a

=V

,N

+S

λ,N

a

≥V

,N

at

–V

|

Sλ,N|

t

≥V

,N

,N

at

–V∗,N≥tBλ

.

By the same method as before, we have

V

a

≥V(ξat) –V(atη<ξat+η) – 1

t2B2

λ

ESλ,N2

Ch

B2λ

i=1

c2i(λ)σσ2iσ2iCh

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

Ch

1

B2λ

i=1

c2i(λ)E

|Xi|2I

ci(λ)|Xi|> ε

kBλ

1+α2

ChεαC(

h+√1 +h– 1).

Lettingt= (E[|Sλ,N|2])31,N→ ∞,λ→ ∞,ε0, andη0 in turn, we have

lim inf λ→∞ V

a

≥V(ξa) –C(√h+√1 +h– 1).

By the arbitrariness ofh> 0, we have

lim inf λ→∞ V

a

≥V(ξa). (5.5)

Combining (5.5) with (5.4), we obtain

lim λ→∞V

a

(20)

Similarly, we can also have

lim λ→∞V

a

=V(ξa).

This is equivalent to

lim λ→∞v

a

=v(ξa).

Acknowledgements

The author would like to thank the editor and referees for their valuable comments.

Funding Not applicable.

Competing interests

The author declares that there are no competing interests.

Authors’ contributions

The author organized and wrote this paper. The author read and approved the final manuscript.

Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.

Received: 23 May 2018 Accepted: 5 November 2018 References

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