R E S E A R C H
Open Access
Approximation of the multiplicatives on
random multi-normed space
Ravi P Agarwal
1, Reza Saadati
2*and Ali Salamati
2*Correspondence: [email protected] 2Department of Mathematics, Iran
University of Science and Technology, Tehran, Iran Full list of author information is available at the end of the article
Abstract
In this paper, we consider random multi-normed spaces introduced by Dales and Polyakov (Multi-Normed Spaces, 2012). Next, by the fixed point method, we approximate the multiplicatives on these spaces.
MSC: Primary 39A10; 39B52; 39B72; 46L05; 47H10; 46B03; secondary 54E40; 54E35; 54H25
Keywords: approximation; homomorphisms; random multi-normed space; dual
random multi-normed space
1 Introduction
The concept of random normed spaces and their properties are discussed in []. Also, the concept of multi-normed spaces was introduced by Dales and Polyakov. In this paper we combine the mentioned concepts and introduce random multi-normed spaces. Next, we get an approximation for homomorphisms in these spaces. For more results and applica-tions, one can see [–].
Definition . Let (E,μ,∗) be a random normed space.∗is a continuous t-norm. A multi-random norm on{Ek,k∈N}is sequence{N
k}such thatNkis a random norm onEk(k∈N),
μx(t) =μx(t) for eachx∈Eandt∈Rand the following axioms are satisfied for eachk∈N
withk≥:
(NF) μkAσ(x)(t) =μk
x(t), for eachσ∈σk,x∈Ek,t∈R,
(NF) μkMα(x)(t)≥μkmax
i∈Nk|αi|x(t), for eachα= (α, . . . ,αk)∈R
k,x∈Ek,t∈R,
(NF) μk(x+
,...,xk,)(t) =μ
k
(x,...,xk)(t), for eachx, . . . ,xk∈Eandt∈R,
(NF) μk(x+
,...,xk,xk)(t) =μ
k
(x,...,xk)(t), for eachx, . . . ,xk∈Eandt∈R.
In this case{(Ek,μk,∗),k∈N}is called a random multi-normed space. Moreover, if ax-iom (NF) is replaced by the following axax-iom:
(DF) μk+
(x,...,xk,xk)(t) =μ
k
(x,...,xk)(t), for eachx, . . . ,xk∈Eandt∈R,
then{μk} is called a dual random multi-normed and{(Ek,μk,∗),k∈N}is called a dual
random multi-normed space.
2 Approximation of the multiplicatives
We apply fixed point theory [] to get an approximation for multiplicatives. A metricd on non-empty setϒwith range [,∞] is called a generalized metric.
Lemma .([, ]) Let k∈N,and let E and F be linear spaces such that(Fk,μk,∗)is
a complete random multi-normed space.Let there exist≤M< ,λ> ,and a function ψ:Ek−→[,∞)such that
ψ(λx, . . . ,λxk)≤λMψ(x, . . . ,xk) (x, . . . ,xk∈E). (.)
We setϒ:={η:E−→F:η() = },and define d:ϒ×ϒon[,∞]by
d(η,ζ)
=inf
c> :μ(η(x)–ζ(x),...,η(xk)–ζ(xk))(ct)≥
t t+ψ(x, . . . ,xk)
,x, . . . ,xk∈E
.
Then(ϒ,d)is a complete generalized metric space,and the mapping J:ϒ−→ϒdefined by(Jg)(x) :=g(λλx) (x∈ϒ)is a strictly contractive mapping.
Theorem . Let E be a linear space and let((Fn,μn,∗) :n∈N)be a complete random multi-normed space.Let k∈Nand let there exist≤M< and a functionϕ:Ek−→
[,∞)satisfying
ϕ(x, y, . . . , xk, yk)≤Mϕ(x,y, . . . ,xk,yk) (.)
for all x,y, . . . ,xk,yk∈E.Suppose that f :E−→F is a mapping with f() = and
μk(f(λx
+λy)–λf(x)–λf(y),...,f(λxk+λyk)–λf(xk)–λf(yk))(t)
≥ t
t+ϕ(x,y, . . . ,xk,yk)
, (.)
μk(f(x
y)–f(x)f(y),...,f(xkyk)–f(xk)f(yk))(t)≥
t
t+ϕ(x,y, . . . ,xk,yk)
, (.)
for allλ∈T:={λ∈C:|λ|= }and x,y, . . . ,xk,yk∈E,t> .
Then
H(x) := lim
n→∞ nf
x n
(.)
exists for any x, . . . ,xk∈E and defines a random homomorphism H:E−→F such that
μ(f(x)–H(x),...,f(xk)–H(xk))(t)≥
( –M)t
( –M)t+Mψ(x, . . . ,xk)
, (.)
ψ(x, . . . ,xk) =ϕ
x ,
x , . . . ,
xk
, xk
, (.)
for all x, . . . ,xk∈E and t> .
Proof Letx=x
, . . . ,xk=
xk
,y=
y
, . . . ,yk=
yk
in (.). We get
ϕ(x,y, . . . ,xk,yk)≤Mϕ
x ,
y , . . . ,
xk
, yk
sincef is odd,f() = . Soμf()(t) = . Lettingλ= andy=x, we get
μk(f(x)–f(x),...,f(x
k)–f(xk))(t)≥
t
t+ϕ(x,x, . . . ,xk,xk)
(.)
for allx,y, . . . ,xk,yk∈E. Consider the following set:
s=:{g:E−→F}
and introduce the generalized metric ons:
d(g,h)
=inf
ν∈R+:μk(g(x)–h(x),...,g(x
k)–h(xk))(νt)≥
t t+ϕ(x, . . . ,xk)
,x, . . . ,xk∈E,t>
,
where, as usual,infφ= +∞. It is easy to show (s,d) is complete. Now, we consider the linear mappingJ:s−→ssuch that
Jg(x):= g
x
for allx∈E. Letg,h∈sbe given such thatd(g,h) =ε. Then we have
μk(g(x)–h(x),...,g(x
k)–h(xk))(εt)≥
t
t+ϕ(x,x, . . . ,xk,xk)
,
for allx, . . . ,xk∈Eand allt> and hence we have
μk(Jg(x
)–Jh(x),...,Jg(xk)–Jh(xk))(Mεt) =μ
k
g(x )–h(
x
),...,g(xk)–h(xk))
(Mεt)
=μk
g(x )–h(
x
),...,g(xk)–h(xk))
M εt
≥
M
t
M
+ϕ(
x
,
x
, . . . ,
xk
,
xk
)
≥
M
t
M
+
M
ϕ(x,x, . . . ,xk,xk)
= t
t+ϕ(x,x, . . . ,xk,xk)
for allx, . . . ,xk∈Eandt> . Thend(g,h) =εimplies thatd(Jg,Jh)≤Mε. This means
that
d(Jg,Jh)≤Mε
for allg,h∈s. It follows that
μ(f(x
)–f(x),...,f(xk)–f(xk))
M t
≥ t
t+ϕ(x,x, . . . ,xk,xk)
Now, there exists a mappingH:E−→Fsatisfying the following: () His a fixed point ofJ,i.e.,
H
x
=
H(x) (.)
for allx∈E. Sincef :E−→Eis odd,H:E−→Fis an odd mapping. The mappingH is a unique fixed point ofJin the set
M=g∈s:d(f,g) <∞ .
This implies thatHis a unique mapping satisfying (.) such that there exists a ν∈(,∞)satisfying
μk(f(x
)–H(x),...,f(xk)–H(xk))(νt)≥
t t+ϕ(x, . . . ,xk)
for allx, . . . ,xk∈E,
() d(Jnf,H)→asn→ ∞. This implies that
lim
n→∞
nf
x n
=H(x)
for allx∈E, () d(f,H)≤–M
d(f,Jf), which implies
d(f,H)≤ M – M
.
Putλ= in (.). Then
μk (n(f(x
n+ y n)–f(
x n)–f(
y
n)),...,n(f(xkn+ykn)–f(xkn)–f(ykn)))
(t)
≥
t
n
t
n+
Mn
nϕ(x,y, . . . ,xk,yk)
for allx, . . . ,xk,y, . . . ,yk∈E,t> andn≥. Since
lim
n→∞
t
n
t
n +
Mn
nϕ(x,y, . . . ,xk,yk)
=
for allx, . . . ,xk,y, . . . ,yk∈E,t> . It follows that
μk(H(x+y)–H(x)–H(y),...,H(x
k+yk)–H(xk)–H(yk))(t) =
for allx, . . . ,xk,y, . . . ,yk∈E,t> . So mappingH:E−→Fis Cauchy additive.
Lety=x, . . . ,yk=xkin (.). Then we have
μk n(f(βx
n)–f(βxn),...,f(
βxk
n)–f(
βxk
n))
nt≥ t
t+ϕ(x
for allλ,β∈T,λ=β,x, . . . ,xk∈E,t> andn≥. So we have
μk n(f(βx
n)–f(
βx n),...,f(
βxk n)–f(
βxk n))
(t)≥
t
n
t
n+
Mn
nϕ(x,x, . . . ,xk,xk)
for allβ∈T,x, . . . ,xk∈E,t> andn≥. We have
lim
n→∞
t
n
t
n +
Mn
nϕ(x,x, . . . ,xk,xk)
=
for allx, . . . ,xk∈E,t> , and
μk(H(βx
)–βH(x),...,H(βxk)–βH(xk))(t) =
for allβ∈T,x, . . . ,xk∈E,t> . Thus, the additive mappingH:E−→FisR-linear. From
(.), we have
μk (nf(x
nyn)–nf(xn)nf(yn),...,nf(xknykn)–nf(xkn)nf(ykn))
nt
≥ t
t+ϕ(x
n, . . . ,xkn,yn, . . . ,ykn)
for allx, . . . ,xk∈E,t> andn≥.
Then we have
μk (nf(x
n y n)–nf(
x n)nf(
y
n),...,nf(xknykn)–nf(xkn)nf(ykn))
nt
≥
t
n
t
n+
Mn
tn ϕ(x, . . . ,xk,y, . . . ,yk)
for allx, . . . ,xk∈E,t> andn≥.
Since
lim
n→∞
t
n
t
n+
Mn
tnϕ(x, . . . ,xk,y, . . . ,yk)
=
for allx, . . . ,xk∈E,t> , we have
μk(H(x
y)–H(x)H(y),...,H(xkyk)–H(xk)H(yk))(t) =
for allx, . . . ,xk,y, . . . ,yk∈E,t> . Thus, the mappingH:E−→Fis multiplicative.
There-fore, there exists a unique random homomorphismH:E−→Fsatisfying (.), and this
completes the proof.
3 Approximation in dual random multi-normed space
Lemma . Let {(Ek,μk,∗),k ∈N} be a dual random multi-normed space, k,n∈ N,
x,x, . . . ,xk,xk+, . . . ,xk+n∈Eandλ, . . . ,λkbe real numbers of absolute value.Then we
have: (i) μk(λ
x,...,λkxk)(t) =μ
k
(x,...,xk)(t),
(ii) μk
(x,...,xk)(t)≥μ
k+
(x,...,xk,xk+)(t),
(iii) μk(x+n
,...,xk,xk+,...,xk+n)(t)≥TM(μ
k
(x,...,xk)(αt),μ
n
(xk+,...,xk+n)(βt)),whereα,β≥and
α+β= ,
(iv) mini∈Nkμxi(t)≥μ
k
(x,...,xk)(t)≥mini∈Nkμxi(αit),
whereα, . . . ,αk≥and
k
i=αi= .In particular,we have
μk(x,...,x
k)(t)≥mini∈Nkμkxi(t).
Theorem . Let E be a linear space,and{(Ek,μk,∗),k∈N}be a random multi space.Let
α∈(, )and f :E−→F is a mapping satisfying f() = and
μk (f(x+y
)– f(x)
– f(y)
,...,f(xk +yk )–
f(xk) –
f(yk) )
t s
≥ –α
t, (.)
where x, . . . ,xk,y, . . . ,yk∈E and t,s∈Nwith the greatest common divisor(t,s) = .
Then there exists a unique additive mapping T:E−→F such that
μk(f(x
)–T(x),...,f(xk)–T(xk))
t s
≥ –α
t (.)
for all x, . . . ,xk∈E and t,s∈Nwith(t,s) = .
Proof Replacingx, . . . ,xk andy, . . . ,yk by x, . . . , xk and , . . . , in (.), respectively,
yields
μk(f(x)–f(x),...,f(x
k)–f(xk))
t s
≥ –α
t. (.)
Replacingx, . . . ,xk,t,s by x, . . . , xk, t, s, respectively, in (.) and repeating this
process for n-time (n∈N), it follows that
μk (f(n–x)
n– – f(nx)
n ,..., f(n–xk)
n– – f(nxk)
n )
t n–s
≥ – α
n–t (.)
forn,m∈Nwithn>m. Using (.) and (RN) we get
μk (f(mx)
m – f(nx)
n ,..., f(mxk)
m – f(nxk)
n ) n–
i=m
–it s
≥ – α mt.
Then
μk
(f(mxm)–f(nxn),..., f(mxk)
m – f(nxk)
n )
t s
≥ – α
forx∈E. Then, replacingx, . . . ,xkbyx, x, . . . , k–xin (.), we have
μk
(f(mx)m –f(nx)n ,...,f( m+k–x)
m+k– – f(n+k–x)
n+k– )
t s
≥ – α mt
≥ – α
m. (.)
Letε> be given. Then there existsn∈Nsuch that αn <ε. Now we substitutem,n
withn,n+p(p∈N), respectively, in (.), for eachn≥n, and we get
μk (f(nx)n –f(
n+px) n+p ,...,
f(n+k–x) n+k– –
f(n+p+k–x) n+p+k– )
t s
≥ – α nt
> –ε.
By Lemma ., we have
μf(nx) n –f(
n+px)
n+p
t s
> –ε (.)
for alln>nandp∈N. The density of rational numbers inRis useful in checking cor-rectness of (.) with positive real numberrinstead of ts. Then we have
μf(nx) n –f(
n+px)
n+p
(r) > –ε
for eachx∈E,r∈R+,n≥nandp∈N. Then{f(nnx)}is a Cauchy sequence, so it is
conver-gent in the random multi-Banach space{(Ek,μk,∗),k∈N}. SettingT(x) :=lim n→∞f(
nx)
n
and applying again Lemma ., for eachr> , we have
μk (f(nx)
n –T(x),..., f(nxk)
n –T(xk))
(r)≥min
i∈Nkμf(nxin )–T(xi)
r k
,
and
lim
n→∞ f(nx
k)
n =T(xk).
We putm= in (.), and we get
μk
(f(x)–f(nxn),...,f(xk)–f(nxnk))
t s
≥ –α
t. (.)
Then
μkf(x
)–T(x),...,f(xk)–T(xk)
t s
≥TM
μk
(f(x)–f(nxn),...,f(xk)– f(nxk)
n )
t s
μk (f(nx)
n –T(x),..., f(nxk)
n –T(xk))
t s
≥ –α
t (.)
by (.) and whenn→ ∞, which implies that (.).
Now, we show thatT is additive. Letx,y∈Eand replacex, . . . ,xk by nx,y, . . . ,ykby
ny, andtby ntin (.). We get
μk (f(n x+y
)– f(nx)
– f(ny)
,...,f(n x +y )– f(nx) – f(ny) )
nt
s
≥ – α nt.
Using (NF), we conclude that
μfn(x+y ) n –
f(nx) n –
f(ny) n t s
≥ – α
nt. (.)
On the other hand, we obtain that
μT(x+y
)–T(x)–T(y)
t s
≥TM
μ
T(x+y )–f(
n(x+y )) n t s , μT(x) – f(nx) n t s , μT(y) – f(ny) n t s ,
μf(n(x+y )) n –
f(n) nx–
f(ny) n t s
≥ – α
n (.)
for eachx,y∈E,t,s∈Nwith (t,s) = . Utilizing again the density ofQinR, we find that (.) remains true if st is substituted with a positive real numberr.
Consequently,
μT(x+y
)–T(x)–T(y)(r)≥ –
α n
for eachx,y∈Eandr∈R. Lettingn→ ∞reveals thatTcomplies with Jensen, and using the fact thatT() = , we conclude thatT is additive [, Theorem ].
It remains to show the uniqueness ofT. Suppose thatTis another additive mapping satisfying (.). Then, for eacht,s∈N, sufficiently largeninNandx∈E,
μT(x)–T(x)
t s
=μT(nx) n –
T(nx) n t s
≥TM
μT(nx)–f(nx)
n–t s
,μT(nx)–f(nx)
n–t s
≥ – α n–t
This inequality holds for eachr∈R+instead oft
s, too. Therefore, for eachr∈R+,n∈N,
μT(x)–T(x)(r)≥ –n–α , lettingn→ ∞, it follows thatT=T.
4 Conclusion
In this paper, we consider multi-Banach spaces, approximate by multiplicatives, and pro-vide some controlled mappings, which are stable by control functions.
Acknowledgements
The authors are grateful to the reviewer(s) for their valuable comments and suggestions.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors contributed equally and significantly in writing this paper. All authors read and approved the final manuscript.
Author details
1Department of Mathematics, Texas A & M University - Kingsville, Kingsville, TX 78363, USA.2Department of Mathematics,
Iran University of Science and Technology, Tehran, Iran.
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Received: 15 May 2017 Accepted: 23 August 2017 References
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