Maximum likelihood Estimation for Stochastic Differential Equations with
two Random Effects in the Diffusion Coefficient
Alsukaini Mohammed Sari
1,2, AlkreemawiWalaa khazaal
1,2, Wang xiang-jun
1* 1School of Mathematics and Statistics, Huazhong University of Science and Technology, Wuhan, Hubei, 430074P.R.China.
2
Department of Mathematics, College of Science, Basra University, Basra, Iraq [email protected],2
Abstract
We study π independent stochastic processes ππ π‘ , π‘ β 0, ππ , π = 1, β¦ , π , defined by a stochastic differential equation
with diffusion coefficients depending nonlinearly on a random variables β π and ππ (the random effects).The distributions of
the random effects β π and ππ depends on unknown parameters which are to be estimated from the continuous
observations of the processes ππ π‘ . When the distributions of the random effects β π ,ππ are Gaussian and exponential
respectively, we obtained an explicit formula for the likelihood function and the asymptotic properties (consistency and asymptotic normality) of the maximum likelihood estimator (MLE) are derived when π tend to infinity.
Keywords:
stochastic differential equations, Maximum likelihood estimator; nonlinear random effects; strongconsistency; asymptotic normality
.
Council for Innovative Research
Peer Review Research Publishing System
1 INTRODUCTION
Stochastic differential equations play an important role in many areas of science fields as physics, engineering, chemistry, neuroscience, biology, finance (Gugushvili and P. Spreij (2012)[11]). Statistical estimation of parameters in the diffusion processes has been studied for a long time; Feigin [10] provided a useful historical overview of the early studies and introduced a general asymptotic theory of maximum likelihood estimation for continuous diffusion processes. In the recent years, the stochastic differential equations with random effects have been the subject of diverse applications such as pharmacokinetic/pharmacodynamics, neuronal modeling (Delattre and Lavelle, 2013[5], Donnet and Samson, 2013[9], Picchini et al. 2010[15]).Maximum likelihood estimator of the parameters of the random effect, is generally not possible, because of the likelihood function is not available in most cases, exceptin (Ditlevsen and De Gaetano (2005) [5]) and [8] which are found a special case of SDE and derived an explicit MLE. Many references proposed approximations for the unknown likelihood function, for general mixed SDEs an approximations of the likelihood have been proposed (Picchini and Ditlevsen, 2011[14]), linearization (Beal and Sheiner (1982)[4]),Laplace's approximation (Wolfinger, (1993)[17]) or approximating the conditional transition density of the diffusion process given the random effects by a Hermit expansion, (AΓ―t-Sahalia (2002)[1]).
Delattre et al. (2012) [7] and alkreemawi et al. (2015) [2] are studied the maximum likelihood estimator for random effects
in more generally for fixedπ and π tending to infinity (for non i.i.d. sample paths, see Maitra et al. (2014) [13]) and they
found an explicit expression for likelihood function and exact likelihood estimator by investigate the linear random effect in the drift (multiple and additive case respectively) together with a specific distribution for the random effect. Almost researcher studied the random effect in the drift not in diffusion except Delattre et al.(2014) [6] and alsukaini et al. (2015) [3]who used one random effect in the diffusion coefficient (linearly and nonlinearly respectively) with a specific distributions and focus on (discretely and continuously) observed SDEs respectively.
In the present work we focus on stochastic differential equation with two random effects in diffusion term and without
random effect in drift term. We consider π real valued stochastic processes ππ π‘ , π‘ β 0, ππ , π = 1, β¦ , π , with dynamics
ruled by the following SDEs:
whereπ1, β¦ , ππ are π independent wiener processes, β 1 , β¦ , β π and π1 , β¦ , ππare ππ. π. π. random variables taking values in
( β and β+) respectively, β
1 , β¦ , β π ,π1 , β¦ , ππ and π1, β¦ , ππ are independent and π₯π, π = 1, β¦ , π are known real values.
The functions π π₯ and π(π₯)are known real valued. Each processππ π‘ represents an individual, the variables β π and ππ
represents the random effects of individual π, the random variablesβ 1 , β¦ , β π have a common distribution π π, π ππ(π)
on β and the random variables π1 , β¦ , ππ have a common distribution π π, π½ ππ’(π) on β+where π and π½ are an unknown
parameters belonging to a set π― β βπ where π and π’ are a dominating
measures.
Our aim is to estimate π = (π, π½) from the continuous observations ππ π‘ , π‘ β 0, ππ , π = 1, β¦ , π , we focus on a special
case of nonlinear random effect in the diffusion coefficient in the model (1), i.e. Ο π₯, β π, ππ = 1
β π+ππ π(π₯) , where π is a
known real function and β π is a Gaussian and ππ is an exponential, we find an explicit likelihood formula and the maximum
likelihood estimator of π .We use the following sufficient statistics ππ and ππ as in [7]:
ππ= π ππ π π2(π π π ) ππ 0 πππ π , ππ= π2 π π π π2(π π π ) ππ 0 ππ , π = 1, β¦ , π.
The consistency and asymptotic normality of the maximum likelihood estimator of π are proved without invoking the
result in the literature.
The rest of this paper is organized as follows. Section 2 contains the notation and assumptions that we will need throughout the paper. The explicit likelihood function, specific distributions for the random effects and the maximum likelihood estimators of the parameters of random effects are introduced in section 3. In section 4 we study the asymptotic properties of the maximum likelihood estimator when the random effects are Gaussian and exponential distribution respectively.
2 Notations and Assumptions
Consider π real valued stochasticprocesses (ππ π‘ , π‘ β₯ 0), π = 1, β¦ , πwith dynamics ruled by (1). The
processesπ1, β¦ , ππand the random variables β 1 , β¦ , β πand π1 , β¦ , ππare defined on a common probability space
(Ξ©, β±, β).Consider the filtration(β±π‘, π‘ β₯ 0)defined byβ±π‘= π(β π, ππ, ππ π , π β€ π‘, π = 1, β¦ , π).As β±π‘= π(β π, ππ, ππ π , π β€ π‘)ββ±π‘π
withβ±π‘π = π(β π, β π, ππ, ππ, ππ π , π β€ π‘ , π β π) independent of ππ , each process ππ is a (β±π‘, π‘ β₯ 0)-Brownian motion.
Moreover, the random variables β π , ππ are β±0 β measurable. We used β‘ referring to the end of the proofs.
We assume that:
H1the function π belongs to π2(β Γ β Γ β+) and for all π₯ β β , 0 < π
02 β€ π2(π₯, π, π) β€ π12
From H1 , the process (ππ π‘ ) is well define and (β π, ππ, ππ π‘ ) adapted to filtration (β±π‘, π‘ β₯ 0) .The π processes
ππππ ,π π‘ = π πππ ,π ππ‘ + π πππ ,π, π, π πππ π‘ , ππ
π,π 0 = π₯π (2).
Admits a unique strong solution process (πππ ,π π‘ , π‘ β₯ 0) adapted to filtration (β±π‘, π‘ β₯ 0) . We infer that the conditional
distribution of ππ given β π= π and ππ= π identical to the distribution of ππ
π ,π
.
3 Likelihood, A specific distributions for the random effects and Maximum likelihood
estimators
3.1 Likelihood
We introduce the distribution ππ,ππ₯π,ππof (π
π π ,π
π‘ , π‘ β 0, ππ ).
Letπππ = π π, π ππ£(π)β¨ π π, π½ ππ’(π)β¨πππ₯
π,π
πdenote the joint distribution of (β
π, ππ, ππ π‘ ) and let πππ denote the
marginal distribution of (ππ π‘ , π‘ β 0, ππ ). Let us consider the following assumption:
H2For π = 1, β¦ , π and for all π, π, πβ², πβ², ππ,ππ₯
π,π π π 2 π π π ,π π‘ π2 π π π ,π π‘ ,πβ²,πβ² ππ 0 ππ‘ < +β = 1.
Proposition 3.1
under H1-H2 and let π β β , π β β+, we have, the distribution π π,π π₯π,ππare absolutely continuous
w.r.t. ππ= π π0,π0 π₯π,π π with density: πππ,ππ₯ π,π π πππ ππ = πΏππ ππ, π, π = exp π ππ π π2 π π π , π, π ππ 0 πππ π β 1 2 π2 π π π π2 π π π , π, π ππ 0 ππ 3 .
(See Liptser and Shiryaev [12]), which is admits a continuous version ππ a.s.
Proof: (see the proof of proposition 2) in [7].
By independent of individuals, ππ= β¨π=1π πππ is the distribution of (β π, ππ, ππ . ), π = 1, β¦ , π and ππ= β¨π=1π πππ is the
distribution of the sample ππ π‘ , π‘ β 0, ππ , π = 1, β¦ , π .
We can compute the density of ππ w.r.t. π = β¨π=1π ππ as follow:
πππ
πππ ππ = πΏππ ππ, π, π π π, π π π, π½ ππ£(π)ππ’(π)
β
β+ = πΎπ
ππ, π .
The distribution ππ admits a density given by:
πππ
ππ π1, β¦ , ππ = πΎπ ππ, π ,
π
π=1
And the exact likelihood of whole sample ππ π‘ , π‘ β 0, ππ , π = 1, β¦ , π is
ππ(π) = πΎπ ππ, π . π
π=1 3.2 A Specific distributions for the random effects
Consider model (1) with nonlinear random effects in the diffusion coefficient π π₯, π, π =π +π1 π(π₯) where π β β , π β
β+ and π . , π(. ) are known functions. We assume that:
π2 π π π π2 π π π ππ 0 ππ < β , ππ ,ππ₯ π,π πβ π. π ,
for all π, π and for π = 1, β¦ , π ; ππ= π, π₯π= π₯, so that ππ π‘ , π‘ β 0, π , π = 1, β¦ , π are π. π. π. We will use the well define
statistics as follow: ππ= π ππ π π2(π π π ) π 0 πππ π , ππ= π2 π π π π2(π π π ) π 0 ππ 4 . So that the density πΎπ(ππ, π) is given by:
πΎπ ππ, π = exp π + π 2 ππβ 1 2ππ π π, π π π, π½ ππ£ π ππ’ π β β+ 5 .
For a general distributions, π π, π ππ£ π of the random effect β π and π π, π½ ππ£(π)of the random effect π, it is not
possible find an explicit expression for πΎπ(ππ, π) above, therefor we propose a specific distributions (Gaussian
(π, π2)for the random effects π and exponential (π½) for the random effect π ) which will give an explicit likelihood and
then find the maximum likelihood estimators of the unknown parameters. In the next proposition an evident
expression for πΎπ(ππ, π)is obtained when the above distributions of the random effects is with unknown parameter π =
(π, π2, π½) β β Γ β+Γ β+.The true value is denoted byπ
0= (π0, π20, π½0).
Proposition 3.2
suppose that π π, π ππ£ π = π©(π, π2), and π π, π½ ππ’ π = ππ₯π(π½) then:πΎπ ππ, π = ππ½ ππ ππ₯π β1 4 (π½ 1 β 2πππ2 β 2πππ)2 ππ 1 β 2π2ππ + π 2β π(1 β 2π ππ2) 2π2 1 β 2π ππ2 , where ππ= ππβ 1 2ππ .
Proof:
from (5) we compute the joint density of β π, ππ, ππ :exp π + π 2 π πβ 1 2ππ Γ 1 2ππ2ππ₯π β 1 2π2 π β π 2 Γ π½ππ₯π βπ½π . Let ππ= ππβ 1
2ππ , then the exponent become:
π·π= π2ππβ
1
2π2 π β π 2+ 2ππππ+ π2ππβ π½π. 6 .
We will compute the first part (π2π
πβ 1
2π2 π β π
2+ 2πππ
π) of the exponent as follow:
π2π πβ 1 2π2 π β π 2+ 2ππππ= ππβ 1 2π2 π2+ π π2+ 2πππ π β π2 2π2 =β1 2 1 π2β 2ππ π2β 2 π + 2π2π ππ 1 β 2π2π π π β π 2 2π2 =β1 2 1 π2β 2ππ π2β π + 2π2π ππ 1 β 2π2π π 2 β π + 2π 2π ππ 1 β 2π2π π 2 β π 2 2π2 =β1 2 1 β 2π2π π π2 π β π + 2π2π ππ 1 β 2π2π π 2 + π + 2π 2π ππ 2 2π2 1 β 2π2π π β π2 2π2 .
Now, bysplliting the result into two parts that are independent and dependent on the random effect π respectively, the integral of the dependent part is the integral of a Gaussian density.
Then the first integral in (5) with respect to π yields the following result : 1 1 β 2π2π π ππ₯π π + 2π 2π ππ 2 2π2 1 β 2π2π π β π 2 2π2 .
By substituting in (5), the second part of the exponent is: πΈπ= π + 2π2π ππ 2 2π2 1 β 2π2π π + π2π πβ π½π β π2 2π2 = 2π 2π π2 1 β 2π2π π+ ππ π 2β π½ β 2πππ 1 β 2π2π π π + π2β π 1 β 2π2π π 2π2 1 β 2π2π π = ππ 1 β 2π2π π π2β π½ 1 β 2π2ππ β 2πππ ππ π + π 2β π 1 β 2π2π π 2π2 1 β 2π2π π = ππ 1 β 2π2π π π β1 2 π½ 1 β 2π2π π β 2πππ ππ 2 β 1 2 π½ 1 β 2π2π π β 2πππ ππ 2 + π 2β π 1 β 2π2π π 2π2 1 β 2π2π π = β1 2 ππ π2π πβ 1 2 π β1 2 π½ 1 β 2π2π π β 2πππ ππ 2 β1 4 π½ 1 β 2π2π π β 2πππ 2 ππ 1 β 2π2ππ + π2β π 1 β 2π2π π 2π2 1 β 2π2π π .
Now, by rearrange the second integral we see that the first part is normal depend on the random effect π with mean is
πΏπ= 1 2 π½ 1 β 2π2π π β 2πππ ππ ,
And variance, ππ2= π2π πβ 1 2 ππ , Then, the conditional distribution of (β π, ππ) given ππis π©(πΏπ, ππ2).
And hence, πΎπ ππ, π = ππ½ ππ ππ₯π β1 4 π½ 1 β 2πππ2 β 2πππ 2 ππ 1 β 2π2ππ +π 2β π(1 β 2π ππ2) 2π2 1 β 2π ππ2 . β‘
3.3 Maximum likelihood estimator for
π = (π, π2, π½):Since we find the density πΎπ ππ, π , a natural approach to estimateπ is the maximum likelihood estimation, so in order
to find MLE π , the likelihood function is written as:
ππ π = π π=1 ππ½ ππ ππ₯π β1 4 π½ 1 β 2πππ2 β 2πππ 2 ππ 1 β 2π2ππ + π 2β π 1 β 2π ππ2 2π2 1 β 2π ππ2 . And hence, the logarithm of likelihood function is,
βπ π = πππ ππ=1 ππ(π) (7) = ππππ12π½π+1 2log ππ β 1 4 π½ 1 β 2πππ2 β 2πππ 2 ππ 1 β 2π2ππ β π 2β π(1 β 2π ππ2) 2π2 1 β 2π ππ2 . π π=1
We will study the following score function
πΊπ π = β βπβπ π , β βπ½βπ π , β βπ2βπ π β²
, where π₯β²denotes the transpose of π₯, such that:
β βπβπ π = π½ 1 β 2πππ2 β 2πππ 1 β 2π2π π +2π β (1 β 2πππ 2) 2π2 1 β 2π ππ2 π π=1 , β βπ2βπ π = π½ 1 β 2πππ2 β 2πππ π½ 1 β 2πππ2 β 1 2 π½ 1 β 2πππ2 β 2πππ 2 1 β 2π2π π 2 β π2 2 β 8π ππ2 2π2 1 β 2π ππ2 2+ π 2 π2 2 , π π=1 β βπ½βπ π = 1 π½β 1 2π½ 1 β 2πππ 2 ππ + π . π π=1
When π02, π½0 are known, the explicit estimator π0 is:
π π= 1β2πππ02π½0 2ππ π π=1 1β2πππ02 1β2πππ02 π π=1 ,
and when π02, π0 are known, the explicit estimator of π½0 is:
π½ π= β2ππ + 4π2π02+ 8ππΎπ 2πΎπ β2ππ β 4π2π 0 2+ 8ππΎ π 2πΎπ , whereπΎπ= 1β2πππ02 ππ π π=1 .
If all the parameters are unknown, the MLEs of π0= (π0, π02, π½0) are given by the system:
π π= 1 β 2ππππ2π½ π 2ππ π π=1 1 β 2ππππ 2 1 β 2ππππ2 π π=1 β1
π½ π= β2ππ + 4π2π π 2+ 8ππΎ π 2πΎπ β2ππ β 4π2π π 2+ 8ππΎ π 2πΎπ ,
Such that π½ π is a maximum likelihood estimator defined as any solution of
βπ π½ π = π π’ππβπ―βπ π . 1 2 π½ π 1 β 2ππππ2 β 2π πππ 2 π π 1 β 2ππ2ππ 2 β π½ π 1 β 2ππππ 2 β 2π πππ π½ π π π 1 β 2ππππ2 β π π 2 2 β 8π πππ2 π π 2ππ2 1 β 2ππππ2 2 π π=1 = 1 2 ππ2 2 π π=1 .
The second derivatives of βπ π with respect to the parameters isas follow:
β2 βπ2βπ π = β2ππ 1 β 2π2π π+ 1 π2 1 β 2π ππ2 8 , π π=1 β2 βπ2βπ2βπ π = β4πππ2π½ 1 β 2π2π π 2 +2πππ½ π½ 1 β 2πππ 2 β 2ππ π 1 β 2π2π π 2 β π π2 3 π π=1 β2ππ π½ 1 β 2πππ 2 β 2ππ π 2 1 β 2π2π π 3 + 8ππ 2π2 2π2 1 β 2π2π π 2β 2π2 2 β 8π2 2 2π2 1 β 2π2π π 3 9 , β2 βπ½2βπ π = β 1 β 2πππ2 ππ π π=1 10 , β2 βπ βπ2βπ π = β4πππ2 1 β 2π2π π 2 β π 1 β 4πππ 2 π2 1 β 2π ππ2 2+ 1 2 π2 2 π π=1 = β 2 βπ2βπβπ π 11 , β2 βπ βπ½βπ π = π = β2 βπ½ βπβπ π , β2 βπ2βπ½βπ π = ππ½ = β2 βπ½ βπ2βπ π 12 .
And the information matrix ,
πΌ(π) = πΈπ β2 βπ2βπ π πΈπ β2 βπ βπ2βπ π πΈπ β2 βπ βπ½βπ π πΈπ β 2 βπ2βπβπ π πΈπ β2 βπ2βπ2βπ π πΈπ β2 βπ2βπ½βπ π πΈπ β 2 βπ½ βπβπ π πΈπ β2 βπ½ βπ2βπ π πΈπ β2 βπ½2βπ π (13),
is the covariance matrix of the vector
β βπβπ π β βπ2βπ π β βπ½βπ π .
The following lemma is important to investigate the consistency and asymptotic normality of the estimators.
Lemma 3.1
If π»π= β2ππ, for all π = (π, π2, π½) β β Γ β+Γ β+ and all π β β,πΈπ ππ₯π π
ππ
1 + π2π»
π < +β.
The proof of the above lemma is similar to proof of lemma 1 in [7] and omitted.
Remark 3.1
from lemma (3.1) and proof of proposition (7) in [7], the second derivatives of log-likelihood functionWe need the following additional assumptions to prove the asymptotic properties:
H3 The parameter set π― is a compact subset of β Γ β Γ β+.
H4 The true value π0 belongs to π―o.
H5 The matrix πΌ π0 is invertible.
4 Asymptotic properties of maximum likelihood estimator
4.1 Consistency of MLE
We consider the theorem 7.49 and 7.54 of schervish (1995) [16] and verify the regularity conditions in this theorem for our purpose with suppose that πΊ is compact. The consistency here is strong consistency that is mean any solution of
the likelihood is consistent
.
Theorem 1
[16]:Let {π₯π}π=1β be conditionally π. π. π given π with density π1(π₯ π ) with respect to a measure π£ on a space(π1, β¬1). Fix
ππβ πΊ , and define, for each π β πΊ and π₯ β π1,
π π, π₯ = ππππΌ βππππ
π1(π₯ ππ )
π1(π₯ πΌ )
.
Assume that for each π β ππ, there is an open set ππ such that π β ππ and thatπΈπππ ππ, ππ > ββ .
Also assume that π1(π₯ . ) is continuous at π for every π, a.s. [πππ].
Then if π π is the MLE of π corresponding to π observations. It holds that limπ ββπ π= ππ a.s. [πππ].
We note that for any π₯ , π1 π₯ π = π1 π₯, π = π π₯, π . Which is clearly continuous in π. In our case we compute for
every π β ππ: ππππ1 π₯ ππ π1 π₯ π = πππ π½0 π½ β 1 4 π½0 1 β 2π02ππ β 2π0ππ 2 ππ 1 β 2π02ππ +π0β 2 π 0 1 β 2π02ππ 2π02 1 β 2π 02ππ +1 4 π½ 1 β 2π2π π β 2πππ 2 ππ 1 β 2π2ππ +π 2β π 1 β 2π2π π 2π2 1 β 2π2π π = ππππ½0 π½ β 1 4 π½02 1 β 2π02ππ 2β 4π½0π0ππ 1 β 2π02ππ + 4π02ππ2 2 ππ 1 β 2π02ππ + π0 2 2π02 1 β 2π02ππ β π0 2π02 + 1 4 π½2 1 β 2π2π π 2β 4π½πππ 1 β 2π2ππ + 4π2ππ2 2 ππ 1 β 2π2ππ + π2 2π2 1 β 2π2π π β π 2π2 = ππππ½0 π½ β 1 4 π½02 1 β 2π02ππ ππ + π½0π0β π20ππ 1 β 2π02ππ + π0 2 2π02 1 β 2π02ππ β π0 2π02 +1 4 π½2 1 β 2π2π π ππ β π½π + π 2π π 1 β 2π2π π + π 2 2π2 1 β 2π2π π β π 2π2 = ππππ½0 π½ β 1 4 π½02 1 β 2π02ππ ππ βπ½ 2 1 β 2π2π π ππ β π0 2π π 1 β 2π02π π β π 2π π 1 β 2π2π π + π0 2 2π02 1 β 2π 0 2π π + π 2 2π2 1 β 2π2π π β π½πβπ½0π0 β π0 2π02β π 2π2 . We note that πΈπππππ π½0 π½ , πΈππ π½πβπ½0π0 and πΈππ π0 2π02β π
2π2 are finite and by using lemma(3.1) ,πΈππ
π½02 1β2π02ππ
ππ β
π½21β2π2ππππ,πΈπππ02ππ1β2π02ππβπ2ππ1β2π2ππandπΈπππ022π021β2π02ππ+π22π21β2π2ππ are also finite, and by assume that ππ= (π, π) Γ (π2, π2) Γ (π½, π½) , follows thatπΈπππ ππ, ππ > ββ, hence limπ ββπ π= ππ a.s.
[πππ]. β‘
4.2 Asymptotic normality of MLE
To corroborate asymptotic normality of MLE π , we investigate the conditions in the next theorem provided in ([16], Theorem 7.63):
Theorem 2 [16]:
Let πΊ be a subset of βπ and let {π₯π}π =1β be conditionally π. π. π given π with density π1(. π ) .let
π π be an MLE .Assume that π π π
derivatives with respect to π and that differentiation can be passed under the integral sign. Assume that there exist
π»π π₯, π such that, for each π0β πππ‘(πΊ) and each π, π ,
sup πβπ0 β€π β2 βππβππlog ππ1 Ξ π₯ π0 β β2 βππβππlog ππ1 Ξ π₯ π β€ π»π π₯, π0 , (14) With limπβ0πΈπ0π»π π₯, π0 = 0. (15)
Assume that the fisher information matrix πΌ(π) is finite and non-singular. Then under πππ,
π π πβ π0 β
β π©(π, πΌβ1(π
0)).
The maximum likelihood estimator π is almost sure consistency (see section 4.1 above) that is mean π π
π
β π0 under
ππ, βπ .The differentiation can be passed under the integral sign (see [7], proof of proposition 5) and from H4 we
fined π0β πππ‘(πΊ) .from (8),(9),(10),(11) and (12), we deduce that β
2
βππβππlog ππ1 Ξ (π₯ π ) is differentiable in π =
(π, π2, π½).From remark (3.1) , the derivatives has finite expectation , Hence (14) and (15) holds, we obtain that the
information matrix πΌ(π) is finite and from H5 , πΌ(π) is invertible, hence π is asymptotically normal.β‘
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