Published online May 20, 2014 (http://www.sciencepublishinggroup.com/j/pamj) doi: 10.11648/j.pamj.20140302.13
A convex hull’ characterization
Franco Fineschi, Giovanni Quaranta
Department DISAG, University of Siena, Italy
Email address:
[email protected] (F. Fineschi), [email protected] (G. Quaranta)
To cite this article:
Franco Fineschi, Giovanni Quaranta. A Convex Hull’ Characterization. Pure and Applied Mathematics Journal. Vol. 3, No. 2, 2014, pp. 40-48. doi: 10.11648/j.pamj.20140302.13
Abstract: Conditions so that a vector belongs to a convex hull are obtained. Multilinear convex functions are considered. If
these maps are defined on a convex set, it is obtained the algebraic expression. As an application, infinite games, with linear convex payoff, are studied.Keywords
:
Convex, Linear, Game1. Introduction
Some properties of the class of the k-linear convex functions are considered. These maps seem to be the natural extention of k-linear functions if the domain is bounded. Given a linear convex mapping, defined on a body, it is possible to extend its definition if an argument is outside of the domain. This property enables us to find the analytical form of a k-linear convex functionφ:Xk →Y
,
if X is a convex set which contains the null vector. An arbitrary element of a convex set can be represented in three different ways using finite sequence of elements of the set; these representations are obtained by the following theorems: the Shapley-Folkman lemma, Carathéodory’s theorem and Fenchel-Bunt’ theorem.
For example by the last theorem, for any element sof a convex, connected set X, a sequence of
n
elements of X exists such that s is expressed by a convex combination of the sequence. In spite of this, it is well known that an arbitrary convex set has not a “convex basis”, that is, it is impossible to find an unique sequence, with finite number of elements of the set, which span, by linear convex combinations, any other. In Algebra it is proved that ℜn is free over the standard basis, this implies some properties, one of these is that an arbitrary sequence of a module A may be written as a linear combination of the vectors) ( , ), (e1 ten
t … for an unique morphism :ℜn
→
. This concept of free set is now moved to convex sets by linear convex functions. One result obtained in this paper is that a convex combination for an element of a convex, connected set A is expressed by a unique convex combination of vectors φ(e1),…,φ(en) for a linear convex functionφ
, thatis, any element
a
of A determines aφ
such that ∑ξiφ(ei)=a.Conditions are obtained in order that a vector belongs to a convex hull if it is spanned by a finite set. The conditions give new expression to the convex hull.
It is known, see [7] and [8], that two persons, infinite, symmetric games, with a compact, convex set as strategy space and a linear convex function as payoff, have solutions. In the last section we obtain the form of the payoff of these games.
2. Free Convex Sets
Let S be a set of vectors in ℜn, with the null vector S
∈
0 , then denote by X =coS the convex hull of S . Suppose k ≤n the maximal number of linearly independent vectors in X and x1,…,xk be a set of
linearly independent vectors of X.
A k-linear convex mapping : , for , is defined by
∑
∑
= =
r
i
k i i
k r
i i i k
i a a b a a b a a
a
1 1 1
1
1, , , , )= ( , , , , )= ( , , , , )
( … … φ … λ … λφ … …
φ
where 0 and∑ 1, ℜn.
Example 2.1Consider the function
b y a x xy
y x
f( , )=2 0≤ ≤ , 0≤ ≤
Let , then f(x1,y)=2x1y and
y x y x
) , (x y
f is not a bilinear function. Whereas, for 0<λ<1,
y x x
y x x
f(λ1+(1−λ) 2, )=2(λ 1+(1−λ) 2)
y x y
x1 2(1 ) 2
2
= λ + −λ
) , ( ) (1 ) , (
=λf x1 y + −λ f x2 y
that is, f(x,y) is a convex linear function of each variable separately.
The following is a known basic statement
Proposition 2.1 Let
φ
:Xk →ℜm be a k-linear convexmapping and X a convex subset of ℜn . The image
) (Xk
φ
is convex in ℜm.Proof. The image under
φ
of every convexcombination of elements of
X
is a convex combination inℜ
m.A point of a convex hull has three known representations by sequences of elements of the same convex set.
a)The first representation is founded on the Shapley-Folkman lemma, see [1], [2] and [10].Consider a finite family , 1, … , " of subset of
ℜ
n, the Minkowsky sum # ∑ # is defined by element-wise addiction of vectors# $# % # : # &
The Minkowsky sum has an immediate property: for any
nonempty finite family of sets of ℜn'( ∑ ∑ '( .
So if # ∑ '( and # # % # with # '( .
The expression of sby # % # depends on the same point s. For the representation # # % # , in the
space
ℜ
n, holdsLemma (Shapley-Folkman) If the number k of is greater than the dimension n of the space, the point s has the expression
# ) #
* *+
) #, +- *,*
where # '( and #, ,.
In other words # ∑ * *+'( ∑+- *,* ,.
b)By the Carathéodory’s theorem, any s∈coS⊂ℜn may be represented as a convex combination of n+1 elements of S .
c)In particular, if
S
is connected, the Fenchel-Bunt’ theorem, see [3] and [8], proves that any s∈coS can be expressed as a convex combination ofn
elements ofS
. Thesethree representations of an element do not establish the existence of a “convex basis” for coS, because then
elements may depend on the particular s to be computed, see [6]. Nevertheless, the next definition asserts the condition in order that a convex set is free. For a definition of a free module on a subset, see [4].In the following we present a different representation for
elements of convex set based on the definition of free convex set.
Definition 2.1 Let K be a subset of a convex set X in
n
ℜ and let j:K→X be the insertion of K in X.
Denote by A a subset of
ℜ
m, then X is free over K if, for every function f :K→A, an unique linear convexmapping
φ
:X →A exists such thatφ
j= f .Example 2.2. Let . $ , & / ℜ2be a subset and '(. its convex hull. We want to prove that '(. is free over ., i.e., for every : . an unique linear convex function
: '(. exists such that 0 1 .
Unicity. The condition 0 1 means that
and . Then for every : . , we have
to prove the unicity of : '(. such that
and . For any " '(. and for
every linear convex function holds "
so is
univocally defined.
Existence. The function , defined by
, is linear convex, in fact for every
2 2 '(.
2 2 2 2 2 2
Explicitly the expression of the unique linear convex is given by
"
' , ' , '3 ' , ' , '3 =
4'' ''
'3 '3 5 6 7 896 7
Where it is supposed ' , ' , '3 ,
' , ' , '3 and , : ℜ3 ,for any " '(. with fixed a and b. Then,
φ
is the matrix 89.The underlying property of the example above will be proved in a more general setting.
Some properties of the mapping
φ
:Xk →A follow. SinceX
is convex, ∀ai∈X,0<α<1 ,X a
ai+ −α α i∈
α (1 )0= . In particular
α
ai∈X . Moreover) , , 0 ) (1 , , ( = ) , , , ,
(a1…αai … ak Φ a1…αai+ −α … ak
Φ
(1)
supposed ai=ajand Φ skewsymmetric it follows
(2)
comparing 1 and 2, it follows Φ skewsymmetric and
) , , , , , , ( = ) , , , , , ,
(a1… ai … aj … ak a1 …αai … aj … ak
αΦ Φ
) , , , , , ,
(a1…αaj …aj … ak Φ
− (3)
) , , 0 , , ( ) (1 ) , , , , (
=αΦa1… ai … ak + −α Φ a1… … ak
) , , , , 0 , , ( ) (1 = ) , , , , , ,
(a1… ai…aj…ak − Φa1… …aj …ak
Let
β
∈ℜ+ and m∈N−{0} such that0 =< 1, Xai∈
∀ , by the (3) it holds
) , , , , , , ( = ) , , , , , ,
( 1 i j k 1 ai aj ak
m a m a a a
a … … … φ … β … …
βφ
) , , , , , ,
( 1 aj aj ak
m a
m
φ
…β
… …− (4)
Proposition 2.2 Let
λ
∈ℜ+(λ
∈ℜ−) and Xx∈
λ , > |1|, then αx∈X(−αx∈X), for 0<α <1.
Proof. If 0<β<1 satisfies
α
=β
⋅λ
, then0 ) (1 ) (
=β λ β
αx x + − , so αx∈X . If −
α
=β
⋅λ
then0 ) (1 ) (
=β λ β
α + −
− x x and −αx∈X .
The next proposition extends the (1) and defines a linear convex mapping if its argument is outside the body
Proposition 2.3 Let x1,…,xi,…,xk be vectors in X
and δ∈ℜ, then a linear convex mapping
φ
:Xk→Asatisfies
) , , 0 , , ( ) (1
) , , , , ( ) , , , , (
1
1 1
k
k i k
i
x x
x x x x
x x
… …
… … …
…
φ δ
δφ δ
φ
− +
=
(5)
Proof. Let 0<
λ
,µ
,ν
<1 such that @ AB C DAA E andλ
|δ
|<1. It is always possible to determinate such numbersλ
,µ
,ν
. Indeed, if F <1, the relation @ AB C DAA E becamesδ
=αµ
−(α
−1)ν
, then, for example supposeE , forα
>2|δ
|+1 , it holds1 < 2
1 2 = < 0
α α δ
µ + − .
Then, by the Proposition 2.2, the vectors
µ
x
i,
ν
x
i are inX
and the mappingφ
is defined on them.(
(
1
)
)
)
,
,
)
,
,
(
=
)
,
,
,
,
(
x
1…
µ
x
i…
x
kφ
x
1…
λδ
λ
ν
x
i…
x
kφ
+
−
) , , , , ( ) (1 ) , , , , (
=
λφ
x1…δ
xi … xk + −λ
φ
x1…ν
xi … xk that is)
,
,
,
,
(
)
(1
)
,
,
,
,
(
=
)
,
,
,
,
(
1
1 1
k i
k i k
i
x
x
x
x
x
x
x
x
x
…
…
…
…
…
…
ν
φ
λ
µ
φ
δ
λφ
−
−
by the (1)
) , , 0 ) (1 , , ( 1 = ) , , , ,
(x1… xi… xk φ x1… µxi µ … xk
λ δ
φ + −
) , , 0 ) (1 , , ( ) (1
1 xi xk
x …ν ν …
φ λ
λ + −
− −
) , , 0 , , ( ) (1 ) , , , , (
= x1… xi… xk φ x1… … xk
λµ φ
λ
µ + −
) , , , , ( ) (1
1 xi xk
x … …
φ λλν
− −
) , , 0 , , ( ) )(1 (1
1 xk
x … … φ
λ ν
λ −
− −
) , , , , ( ) ) (1 (
= φ x1…xi…xk λλν
λ µ− −
) , , 0 , , ( ) ) )(1 (1 ) (1
( φ x1… … xk
λ ν
λ λµ
− − − − +
) , , 0 , , ( ) (1 ) , , , , (
=δφ x1… xi… xk + −δ φ x1… … xk
Theorem 2.1 Let
φ
:Xk →Y be a k-linear convexfunction and X a convex set with 0∈X , then
) , , (a1… ak
φ
may be expressed by a linear combination of) , , (
1 jk
j x
x …
φ , where x X
i
j ∈ span the vectors ai∈X .
Proof. The nonnull vectors a1,…,ak in X may be written as
G % G G , … , G
i i
b
a
k
||
||
=
) 1
1 (
= 1 1
k i ki
i i
i x
a k x
a k a k
|| || ||
|| ||
||
γ
+⋯+γ
j i ji k
j
i
x
a
k
a
k
||
||
||
||
1
γ
=
1 =
∑
{0} 1
=
1 =
− ∈
∑
b x k Nk a
k ji j
k
j i|| ||
where −1≤ = ≤1
|| || i
ji ij
a
b
γ
, i,j=1,…,k.By k applications of the Proposition 2.3 to the arguments of
φ
, it follows) ,
, (
= ) , ,
(a1… ak
φ
k||a1||b1… k||ak||bkφ
) , , , 0 ( ) (1
) , , , (
=k||a1||
φ
b1 a2… ak + −k||a1||φ
a2 … ak) , , , , (
=k2||a1|| ||a2||φ b1 b2 a3 … ak
) , , , 0 , ( )
(1 2 1 3
1 k a b a ak
a
k|| || − || || φ …
+
) , , , , 0 ( ) (1
|| 1 2 3
2 k a b a ak
a
k|| − || || φ …
+
) , , , 0 , 0 ( ) )(1
(1−k||a1|| −k||a2|| φ a3…ak +
⋯ ⋯ ⋯ ⋯
=
) , , ( =kk||a1||⋯||ak||φ b1… bk
⋅ −
+
∑
− 1 −1 +1 (1 )1
1 =
|| || || || || || || || ||
|| i i k i k
k
i
a k a a
a a
k ⋯ ⋯
⋯ …
… +
⋅ −
−
+
∑
− − (1 ) (1 )1 1
< < 1
|| || ||
|| || || || ||
r i i
r k j j r k
r i i
a k a
k a
a
k ⋯ ⋯
⋯
⋯ …
…
… +
⋅ ( , , =0, , =0, , )
1
1 bi bir bk
b
φ
) 0 , , 0 , 0 ( ) (1
) )(1
(1 || 1|| || 2|| ⋯ || || φ …
k
a k a
k a
k − −
−
+ (6)
where , … , is the complement of 1 , … , 1 D with respect to the set 1, … , " and the sum in (6) is over all the subsets , … ,
Now use the convex linearity on all the vectors bi
) 1 , , 1 ( = ) , , (
1 = 1 1 =
1 jk j
k
j j j k
j
k b x
k x
b k b
b … φ
∑
…∑
φ
) , , , ( 1
= 1 2
1 =
k i i k
i
b b x b k
…
φ
∑
⋯ ⋯ ⋯ ⋯
=
) , , ( 1
=
1 1 1 1
k j k k j j j k j j
k b x b x
k
…
…
∑
φ∑
where, by the (1)
) ,
, ( = ) ,
, (
1 1 1 1
1
1 j jkk jk j j jkk jk
j x b x b x b x
b … φ …
φ
) , , , 0 ( ) (1
2 2 2 1
1 j j jkk jk
j b x b x
b φ …
− +
⋯ ⋯ ⋯ ⋯
=
) , , ( , , =
1 1
1 jkk j jk
j b x x
b … φ …
⋅ − +
∑
11, , −1−1, +1+1, , (1 )1
= i
j k k j i i j i i j j k j
j i j
b b b
b
b … …
⋯ …
… +
⋅ ( , , =0, , )
1 ji jk
j x x
x
φ
⋅ − − +
−
∑
(1 ) (1 )1 1
< < 1
r i i r k s s r i i
b b b
b ⋯ ⋯
⋯
⋯ …
…
… +
⋅ ( , , =0, , =0, , )
1
1 i ir jk
j x x x
x
φ
) 0 , , 0 , 0 ( ) (1 ) (1
1
…
⋯ φ
k j
j b
b −
−
+ (7)
where i1,…,ir is the complement of
r k
s
s1,…, − with
respect to the set 1,…,k and the sum in (7) is over all the subsets i1,…,ir.
So φ(a1,…,ak) is obtained by a linear expression in
) , , (
1 jk j x x …
φ , where some
i j
x
can be the null vector0
.In the n-dimensional vector space ℜn, denote by
S
n the convex hull of the vectors {e1,…,en} of the standard basis. Sn is a compact, connected, convex set and its elements may be expressed by convex combinations of theunit vectors {e1,…,en}.
Theorem 2.2 The set Sn is free over the standard
basis {e1,…,en} of ℜn.
Proof. Let K ={e1,…,en} , the condition
φ
j= f impliesφ
(ei)= f(ei)=ai and the functionφ
is defined byA a a
e
e + + n)=
∑
i i i∈ℜ+,∑
i =1, i∈(ξ1 1 ξ ξ ξ ξ
φ ⋯
Uniqueness. If
φ
is a linear convex function withi i a
e)= (
φ
, then, for any k∈Sn1 = =
) ( = ) (
= )
(k φξ1e1 ξnen ξiφ ei ξiai ξi
φ +⋯+
∑
∑
∑
so
φ
is unique.Existence. φ(k)=
∑
ξiai defines a functionφ
:Sn→A. Let us prove thatφ
is a linear convex function. ∀k∈Sn let k=ξ1e1+⋯+ξnen,∑
ξi=1, then) ( )
( = =
) (
= )
(k φξ1e1 ξnen ξiai ξ1φ e1 ξnφ en
φ +⋯+
∑
+⋯+By the Fenchel-Bunt’ theorem, any element
a
of a compact, connected, convex set A is expressed as a convex combination of the sequence a1,…,an of vectors of A, that is a=ξ
1a1+⋯+ξ
nan. By the theorem 2.2 exists an unique linear convex functionφ
such that) ( = = =
)
(ξ1e1 ξnen ξiai a ξiφ ei
φ +⋯+
∑
∑
so, any element a∈A may be expressed as a convex combination of the vectors
φ
(ei),…,φ
(en). In other words, any a∈A determines a linear convex functionφ
such that∑
ξiφ(ei)=a.Example 2.3 Let A be a convex, connected set in ℜ2. If a=ξ1a1+ξ2a2,ξi ≥0,
∑
ξi =1,ai =(ai1,ai2) is an element of A, then, by the theorem 2.2, it follows) ( ) ( = =
) (
= 1e1 2e2 1a1 2a2 1 e1 2 e2
a
φ
ξ
+ξ
ξ
+ξ
ξ
φ
+ξ
φ
where φ:S2→ A is linear convex. This implies
2 2 1
1)= , ( )=
(e a φ e a
φ , and so
2 22
12 21 11
) ( =
)
( x x S
a a
a a
x ∈
φ
3. A Convex Hull’ Characterization
} ) , , ( = , { = } , ,
{ 1
1 =
1 i i m m
m
i
m a
a a
co …
∑
α α α …α ∈Σwhere
Σ
m is the unit simplex inℜ
m . The next proposition lays down a condition so that a vector belongs to a convex hull.Theorem 3.1 Let co{a1,…,am} be a convex hull where )
, , (
= a1 am
A … is a matrix with |A|≠0 , then
} , ,
{a1 am
co
b∈ … iff
(i). =0
1 1
1
1
1 11
1
mm m
m
m
a a
b
a a
b
… … … … …
… …
(ii). The determinants
| | |, , , , , | , |, , , , , | |, , , ,
|ba2… am a1b a3… am … a1 a2… am−1b A
have the same sign.
Proof. Suppose b∈co{a1,…,am}, then iai b
m i=1
α
=∑
for
α
=(α
1,…,α
m)∈Σm, that is, Aα=b. Then| |
| , , , , , , |
= 1 1 1
A
a a
b a
a j j m
j
…
… − +
α
is the solution of the system Aα =b . Impose 1
= 1 = j
m j a
∑
, we obtain| |=| , , , , | | , , , , | | , , ,
|ba2…am + a1ba3…am +…+ a1a2…am−1b A and so the (i).
Conversely, if (i) and (ii) hold, moving backward, we get
α
such that Aα=b, then b∈co{a1,…,am}.Next step is the extension of the Theorem 3.1 to a convex hull given by the vectors a1,…,an, in ℜm, with
m
n> and r(A)=r. For this purpose it is necessary to introduce some generalizations of elementary definitions in linear algebra. For more details see [5].
The multindex
I
rn of lengthr
is defined by}
<
<
1
:
)
,
,
{(
=
i
1i
i
1i
n
I
r rn
r
…
≤
…
≤
besides we define, for a fixed natural number
k
,} 1
, < < = < < 1 : ) , , {( = )
( 1 1
n k where
n i k i i i i i
Irn k p r p r
≤ ≤
≤
≤ … …
… …
Let F be a field with
char
(
F
)
≠
2
, then, for anarbitrary matrix, consider the linear form in the parameters
F
∈
α β
λ
given byDefinition 3.1 Let ∗
× →
∆ : ( r )
n r m n m
r F F be a map
defined by
. , ,
| | =
,
n r m r
rA A ∈I ∈I
∆
∑
λ
αα
β
β α β β α
If m=r=r(A), then |Aαβ |, in ∆mA, are the Plücker
coordinates of the subspace spanned by the rows of A.
Example 3.1 For the matrix
23 22 21
13 12 11
=
a a a
a a a
A , with
2 = ) (A r
23 22 21
13 12 11 2 =
a a a
a a a A
∆
12 23 23 22
13 12 12 13 23 21
13 11 12 12 22 21
12 11
=
λ
λ
λ
a a
a a a
a a a a
a a a
+ +
The definition of cofactor
α
ij can be extended to an arbitrary matrix.Definition 3.2 Let A∈Fm×n be a matrix with r
A
r( )= , the cofactor
α
ijr of the entrya
ij ofA
, forn
m
<
, is defined byα
λ α
α β
∈
≠ +
− ∆
i if only
0 and 1 = a n, , 1, j 1, j , 1, = for x 0 = : =
0 1
0 =
ij 1
1 11
… …
… … …
… … …
… …
… … …
… … …
ix r
i
mn m
n
r ij
a A
a a
a a
| )
( |
= 1
1 1
1 1
1
' j e row th i r i i i
r j j j r i i i
r j j j r j j j r i i i
A
−
∑
……… … …
… … … … … … …
λ
where in the last determinant the i-th row is ,0)
,1, (0,
= … …
' j
e , i.e. the j-th unit vector. The sum is over
all i1,…,i,…,ir∈(Irm)i and
j n r r I
j j
j1,…, ,…, ∈( ) .
Similarly, for
m
>
n
,j mn m
in i
n
r ij
a a
a a
a a
… …
… … … … …
… …
… … … … …
… …
0 1 0
=
1 1
1 11
α
) 0 1 1 0 1 0 ( ) 0 1
1 0 1 0 ( = 0 1 0 0
0 1 0 0 = 0 1 0 0 =
23 34 34 33 23 23 33 32 23 13 33 31 12 34 14 13
12 23 13 12 12 13 13 11 23
34 33 32 31
12 14 13 12 11 2
34 33 32 31
14 13 12 11 23
λ λ
λ λ
λ λ
α
a a a a a a a
a
a a a a a a a a
a a a a
a a a a
a a a a
r
+ +
+ +
+ +
As in the example, it will be useful to write the numbers of the rows (columns) involved in the expansion of the cofactor like apexes (indexes).
Let C=(αijr) the r-cofactor matrix of A . The transpose of C, i.e. the r-adjoints of A will be denoted by Aad.
Theorem 3.2 Any consistent linear system Ax=b,b≠0, where A∈Fm×n, r(A)=r, has as set of solutions
n j
A b b
x
r m r mj r
j
j= =1, ,
1 1
… ⋯
∆ +
+ α
α
for any
λ
αβ∈F such that r A rad)≥
( .
Proof.(∆rA)−1Aad are the (1)-inverses of
A
, then the solutions of Ax=b are x=(∆rA)−1Aadb.The Theorem 3.2 is an evident Cramer’s rule generalization.
All that is necessary to the next proposition is now ready.
Theorem 3.3 Let co{a1,…,an} be a convex hull where )
, , ( = a1 an
A … is a matrix with r(A)=m, a i n
i≠0 =1,…, ,
then b∈co{a1,…,an} iff
(i)
γ
11m+b1γ
21m+⋯+bmγ
mm+1,1=0where the cofactors
γ
ijm are obtained by the matrix
mm m
m
m
a a
b
a a
b C
… … … … …
… …
1
1 11
1
1 1
1 =
(ii) The sums αmjb +⋯+αmjmbm
1
1 , with
n
j=1,…, , have the same sign of ∆mA.
Proof. Suppose b∈co{a1,…,an}, then a b
i i n i=1α =
∑
for α=(α1,…,αn)∈Σn, that is, Aα =b. Then, by Theorem
3.2
A b b
m m m mj m
j
j ∆
+
+ α
α
α ⋯
1 1 =
is the solution of the system Aα=b . Impose 1
= 1 = j
n j a
∑
using linearity by rows, it follows1 1
1 1
=
1 1,1
1 11
1
2 21
1
… …
… … …
…
⋯
… … … …
… …
n m m
n
m
mn m
n m
a a
a a
b
a a
a a
b A
− −
+ + ∆
and so the (i). By αj≥0, j=1,…,n, we obtain the (ii). If
α
r is null in the solution of the system Aα=b, then b∈co(a1,…,ar−1,ar+1,…,an). As a special case, if only αi,αj are nonnull in the solution of Aα=b andj i a
a, are extreme points, then
b
is an extreme point ofthe convex hull.
Example 3.3 A vector
b
is in ∈co{a1,a2,a3}, with 0,
2 ≠
ℜ
∈ i
i a
a , r(A)=2, if it satisfies the following
conditions
1,2,3 = 0 ) (
1 2
2 2 2 1 1 2
j b
b
A j+ j ≥
∆ α α
0 = 1 1 1 1
23 22 21 2
13 12 11 1
a a a b
a a a b
Given any matrix
A
, a matrixA
(2) such that (2)(2) (2)
=A
AA
A is called a (2)-inverse of
A
. Letn m
C
A∈ × and r(A)=r. Then (∆rA)−1Aad is the set of (2)-inverses of
A
iff r(Aad)≤r, see [9].A (2)-inverse
A
RN(2) with prescribed rangeR
and null spaceN
is the matrix(
∆
rA
)
−1A
ad such that(i). (∆rA)−1AadAx=x x∈R
(ii). (∆rA)−1Aady=0 y∈N
By the next proposition, a matrix
A
c such thatα
α
= AAc with
α
∈Σn is obtained.Theorem 3.4 Let A∈Cm×n and r(A)=m. The matrix
c
A
is given by0. , )
) ( ) ( ( ) (
= A ++Q I − A A + Q∈C × Q≠
A m mn
c α α α α
where (Aα)+ denotes the Moore-Penrose inverse of
α
A .
Proof. It is known that the matrix equation XB=C
equation, B= Aα and C=α, since (A
α
)+Aα
=1 the equation has the general solution0. , ) ) ( ( ) (
= A ++Q I −A A + Q∈C × Q≠
Ac α α m α α m n
Theorem 3.5 Let co(a1,…,an) be a convex hull. The following four statements are equivalent
(a). b∈co(a1,…,an),
(b). the linear system Aα=b has the solution
n Σ ∈
α
,(c). co(A,b)=co(A),
(d). Acb=
α
.Proof. It is immediate that (a) and (b) are equivalent. Let us show that (b) and (c) are equivalent. Suppose
) ( = ) ,
(Ab co A
co
b∈ , then b=
α
1a1+,⋯,+α
nan , sob
Aα= with
α
∈Σn. Conversely, suppose Aα=b withn Σ ∈
α
, that is b=α
1a1+,⋯,+α
nan and b∈co(A), but it also b=α
1a1+⋯+α
nan+0b where1
,0)
(
α
∈Σn+ , then ), (Ab co
b∈ . Moreover ∀k∈co(A,b) is
b a
a
k=
δ
1 1+⋯+δ
n n+δ
n+1) (
=
δ
1a1+⋯+δ
nan+δ
n+1α
1a1+⋯+α
nann n n n
n )a ( )a
(
=
δ
1+δ
+1α
1 1+⋯+δ
+δ
+1α
since ) ( ) ( = )
(δ1+δn+1α1 +⋯+δn+δn+1αn δ1+⋯+δn +δn+1α1+⋯+αn
1 1
=δ +⋯+δn+δn+
1 =
and (
δ
i+δ
n+1+α
i), i=1,…,n , are nonnegative, then)
(
A
co
k
∈
.(b)
→
(d) . Let Aα
=b,α
∈Σn, then there existsc
A
such that AcAα
=α
, so Acb=α
. Conversely, the relation Acb=α
is satisfied by b=Aα, then there exists) , , (
=A coa1 an
b
α
∈ … .Example 3.4 Consider the convex hull
0 , ),
, ,
(a1 a2 a3 ai∈ℜ2 ai ≠
co and let
3 3 2 1 3 3 2 1 2 3 2 1
1 , , )
(
= ∈Σ
+ + + + +
+λ λ λ λλ λ λ λλ λ
λ λ
α , then
+ + − + − − − − + − + + − + + − + − + + − − − + − − + + + − + − + + − + + − − − − + − + + − + − + − + } ) 1 ( ) ( ) , ) (1 ) ( ) { } ) ( ) 1 ( ) , ) ( ) (1 ) { } ) ( ) ( ) (1 , ) ( ) ( ) (1 { 2 1 = 3 23 2 22 1 21 3 32 23 31 13 2 32 22 31 12 1 32 21 31 11 3 13 2 12 1 11 3 32 23 31 13 2 32 22 31 12 1 32 21 31 11 3 23 2 22 1 21 3 22 23 21 13 2 22 22 21 12 1 22 21 21 11 3 13 2 12 1 11 3 22 23 21 13 2 22 22 21 12 1 22 21 21 11 3 23 2 22 1 21 3 12 23 11 13 2 12 22 11 12 1 12 21 11 11 3 13 2 12 1 11 3 12 23 11 13 2 12 22 11 12 1 12 21 11 11 λ λ λ λ λ
λ λ λ λ
λ λ
λ λ λ λ
λ λ
λ λ λ λ
λ λ
λ λ λ λ
λ λ
λ λ λ λ
λ λ λ a a a q a q a q a q a q a q a a a a q a q a q a q a q a q a a a a q a q a q a q a q a q a a a a q a q a q a q a q a q a a a a q a q a q a q a q a q a a a a q a q a q a q a q a q a Ac
the condition Acb=
α
implies for b=(b1,b2)) , ( = 3 2 1 3 23 2 22 1 21 3 2 1 3 13 2 12 1 11 λ λ
λ λ λ
λ λ
λ
λ λ λ
λ + + + + + + +
+a a a a a
a b so } : { = ) , ,
(a1 a2 a3 b i∈ℜ+
co λ
4. Symmetric Two Persons Games
Denote by Γ2=(X,X,Φ) the triplet of a two persons
infinite, symmetric game in normal form, with
X
the full strategy space, see [7] and [8].X
=
coS
is the convex hull of subset S of Euclidean n-dimensional linear spacen
ℜ , with the null vector 0∈S, and let Φ:X×X →ℜ be the bilinear, skewsymmetric, convex payoff function.
Explicitly, impose the following axioms 1) If x1
λ
1+⋯+xnλ
n =x∈X , where x Xi∈ and
0
≥ i
λ
, =11 = i
n
i
λ
∑
, thenX y y x y x y
x i i
n i i i n i ∈ Φ Φ
Φ( , )= (
∑
, )=∑
( , )1 = 1 = λ λ
likewise, if y1
δ
1+⋯+ynδ
n=y∈Y, where y Xi∈ and
0
≥ i
δ
, =11 = i
n
i
δ
∑
, thenX x y x y x y
x i i
n i i i n i ∈ Φ Φ
Φ( , )= ( ,
∑
)=∑
( , ) 1 = 1 = δ δ2) For every x,y∈X×X , it holds Φ(x,y)=−Φ(y,x)
The payoff function Φ:X×X →ℜ satisfies the following properties
a)∀x∈X, by the second axiom, Φ(x,x)=−Φ(x,x), that is Φ(x,x)=0.
b)∀x,y∈X,0<
α
<1, since X is convex, Xx
x+ −α α ∈
α (1 )0= . Moreover
) , 0 ( ) (1 ) , ( = ) , 0 ) (1 ( = ) ,
( x y Φ x+ − y Φ x y + − Φ y
Φα α α α α that is
) , 0 ( ) (1 ) , ( = ) ,
( x y Φ x y + − Φ y
by x=y, it follows ) , 0 ( ) (1 = ) ,
( y y − Φ y
Φα α (9)
comparing (8) and (9), it follows
) , ( ) , ( = ) ,
(x y
α
x yα
y yα
Φ Φ −Φ (10)In the same way of theorem 2.1, the analytic form of the payoff Φ is now obtained.
For any two vectors a1,a2∈X let
i i n i ni i i i j i ji n j i
i x n a b
a a n x a a n a n x a a n a n
a || ||
|| || || || || || || || ||
|| 1 = (1 1 )=
= 1 1
1 =
+ +
∑
⋯then, by the proposition 2.3, it follows
) , ( = ) ,
(a1 a2 Φ n||a1||b1 n||a2||b2 Φ ) 0 , ( ) (1 ) , (
=n2||a1||||a2||Φb1b2 +n||a1|| −n||a2||Φb1
) 0 , 0 ( ) )(1 (1 ) , 0 ( )
(1 1 2 1 2
2 − Φ + − − Φ
+n||a || n||a || b n||a || n||a ||
using convex linearity
) , ( 1 ) , ( 1 ( = ) , ( 2 1 1 2 1 1 11 2 1 2 2
1 x b
a a n b x a a n a a n a
a n n
|| || || || || || ||
|| Φ + + Φ
Φ ⋯ ) 0 , ( 1 ) 0 , ( 1 )( (1 1 1 1 1 11 2
1 n xn
a a n x a a n a n a n || || || || || || ||
|| − Φ + + Φ
+ ⋯ ) , 0 ( 1 ) , 0 ( 1 )( (1 2 2 1 2 12 1
2 n xn
a a n x a a n a n a n || || || || || || ||
|| − Φ + + Φ
+ ⋯ ) 0 , 0 ( ) )(1
(1− 1 − 2 Φ
+ n||a || n||a ||
) , ( ) ( = 2 2 1 1 1 = 1 = 2 1 j j i i n j n i x a a x a a a a || || || || || || ||
||
∑
∑
Φ) 0 , ( ) (1 1 1 1 = 2 1 i i n i x a a a n a || || || || ||
|| − Φ
+
∑
) , 0 ( ) (1 2 2 1 = 1 2 j j n j x a a a n a || || || || |||| − Φ
+
∑
) 0 , 0 ( ) )(1(1− 1 − 2 Φ
+ n||a || n||a ||
by the (1)
) 0 , ( ) ( ) , ( = ) ,
( 1 2 2
1 = 1 = 2 1 1 = 1 = 2
1 i j i
n j n i j i j i n j n i x a a a x x a a a
a Φ + − Φ
Φ
∑
∑
∑
∑
|| ||) 0 , 0 ( ) )( ( ) , 0 ( )
( 1 1 2 2
1 = 1 = 2 1 2 1 = 1 = Φ − − + Φ −
+
∑
∑
∑
∑
i jn j n i i j i n j n i a a a a x a a
a || || || || || ||
) , 0 ( ) (1 ) 0 , ( )
(1 2 1
1 = 2 1 1 = i i n i i i n i x a n a x a n
a − Φ + − Φ
+
∑
|| ||∑
|| || ) 0 , 0 ( ) )( (1 ) 0 , 0 ( ) )((1 1 2 2
1 = 1 1 2 1 = Φ − − + Φ − −
+
∑
∑
in i i n i a a a n a a a
n|| || || || || || || ||
) 0 , 0 ( ) )(1
(1− 1 − 2 Φ
+ n||a || n||a ||
By the symmetry of the game, Φ(0,0)=0. The real value Φ(a1,a2) is so determined by Φ(xi,xj) and
) 0 , (xi
Φ . Denoting by (x,y) a solution of the game, the choice of the Φ(xi,xj) and Φ(xi,0) must satisfy the following inequalites Φ ≥ Φ ≥ Φ Φ ≥ Φ ≥ Φ n , 1, = i ) , 0 ( ) , ( ) 0 , ( ) , ( ) 0 , ( ) 0 , ( … y y x x y x x
x i i
and Φ ≥ Φ ≥ Φ Φ ≥ Φ ≥ Φ n , 1, = j i, ) , ( ) , ( ) , ( ) , ( ) , ( ) , ( … y x y x x x y x x x x x i j i j i j
Suppose
X
be a compact, convex set and defineX y y x y x X x x
maxy ={ : ∈ ⇒Φ( , )≥Φ( , )} ∈
* * and X x y x y x X y y
minx ={ : ∈ ⇒Φ( , )≤Φ( , )} ∈
* *
then, by the imposed conditions on Φ and X, maxy
and minx are not empty and compact, convex sets.
The map 2
) , ( }, {
:X×X→ minx×maxy ∀xy∈X
Φ is upper
semicontinuous and we can use the following proposition, see [8]
Theorem 4.1 (Kakutani’s fixed-point theorem) If }
{ ) , (
: x y → minx×maxy
Φ is an upper semicontinuous
map on compact, convex X×X and {Φ(x,y)} is a convex set, then, at least an element (x,y)∈X×X exists such that (x,y)∈Φ(x,y).
By the theorem 4.1, an element (x,y) exists with
x
min
y∈ and x∈maxy . Since x∈maxy it holds
) , ( ) , (
, x y x y
x Φ ≤Φ
∀ and ∀y,Φ(x,y)≤Φ(x,y), then
) , ( ) , ( ) , (
,y X x y x y x y
x ∈ Φ ≤Φ ≤Φ
∀
that is, (x,y) is a solution of the game Γ2 .
References
[1] M.Carter Foundations of mathematical economics, Cambridge MIT PRESS, 2001.
[2] J.W.S. Cassels Measures of the non-convexity of sets and the Shapley-Folkman-Starr theorem Mathematical Proceedings of the Cambridge Philosophical Society Vol. 78 pp. 433-436, 1975.
[4] C.Faith Algebra I Rings, Modules, and Categories Springer-Verlag, 1981.
[5] F.Fineschi, R.Giannetti Adjoints of a Matrix Journal of Interdisciplinary Mathematics. Vol.11, No. 1, pp.39-65. Taru Publications, 2008 .
[6] J.B.Hiriart-Urruty, C.Lemaréchal Fundamentals of Convex Analysis Springer-Verlag, 2001.
[7] T. Iimura, T. Watanabe Existence of a pure strategy equilibrium in finite symmetric games where payoff functions are integrally concave Discrete Applied Mathematics, Forthcoming 2012.
[8] S. Karlin Mathematical Methods and Theory in Games, Programming, and Economics - The Theory of Infinite Games Addison-Wesley, 1959.
[9] Y. Wey A characterization and representation of the generalized inverse ARN(2) and its applicatations, Linear Algebra Appl. N. 280 pp 87-96, 1998.