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ESTIMATION OF ADDITIVE ERROR IN MIXED SPECTRA

FOR STABLE PROCESSES

Rachid Sabre1

Laboratory LE2I UMR6306, CNRS, University of Bourgogne, Agrosup, Department DSIP, Dijon, France.

1. INTRODUCTION

In this paper, the class of symmetric alpha stable processes have been considered. It is a particular family of processes with infinite energy. Theory of these processes have been covered in numerous papers including Cambanis (1983), Cambanis and Mae-jima (1989), Marcus and Shen (1989), Masry and Cambanis (1984), Samorodnitsky and Taqqu (1994), Panki and Renming (2014), Zhen-Qing and Longmin (2016) to name a few. Symmetric alpha processes are considerably accurate models for many phenomenons in several fields such as: physics, biology, electronic and electric, hy-drology, economies, communications and radar applications, see Sousa (1992), Shao and Nikias (1993), Nikias and Shao (1995), Kogon and Manolakis (1996), Azzaouiet al.(2002), Montillet and Kegen (2015), Pereyra and Batalia (2012), Zhong and Premku-mar (2012), Ligang and Zidong (2015), Pankiet al.(2017), Briceet al. (2017).

In this work, a stationary symmetricαstable harmonizable process is precisely discussed,Z={Zn:n∈Z}. AlternativelyZhas the integral representation

Zn=

Zπ

−π

exp[i(nλ)]dξ(λ),

where 1< α <2 andξ is a complex valued symmetricα-stable random measure onR

with independent and isotropic increments. The measure defined bym(A) =|ξ(A)|αα (see Masry and Cambanis, 1984) is called "control" measure or spectral measure. Sup-pose that this measure is absolutely continuous with respect to Lebegue measure: md(x) = φ(x)d x. The functionφis called the spectral density. The spectral den-sity function was already estimated by Masry and Cambanis (1984), when the time of the process is continuous, by Sabre (1995) when the time of the process is discrete and by Sabre (2012) when the time of the process is p-adic.

In this work, we consider the case where can not be observed this process without an unknown constant error. The processXn=a+Znis observed instead of the process Z alone.

(2)

Our goal is to estimate this constanta, when the spectral measure is the sum of an absolutely continuous measure with respect to Lebesgue measure and a discrete measure

dµ(λ) =φ(x)d x+

q X

i=1

ciδw

i,

whereδ is a Dirac measure, φis nonnegative integrable and bounded function, ci is unknown positive real number and wi is unknown real number. Assume that wi 6= 0. We study the case where the spectral density is zero at origin, particularly atφ(λ) =sin2kα€λ2Šg(λ)andφ(λ) =|λ|βg(λ). We show that the rate of convergence is improved in accordance with the value ofβ.

This paper is organized as follows. Section 2 gives some definitions and proprieties of symmetric stable processes and an estimator of the constantais defined. We show that this estimate converges in probability toa. Then we show that the estimate con-verges toainLp(p< α)which will replace the convergence in mean square because the second moment of the processes is infinite. In Section 3, the spectral density of Z is assumed vanishing at origin precisely:φ(λ) =|λ|βg(λ). We improve the rate of convergence in accordance with the values ofβ. Section 4 is reserved to numerical studies. Section 5, Appendix, is reserved to prove the elementary results.

2. THE ESTIMATE OF THE CONSTANTa

First, are introduced some basic notation and properties used throughout the paper. A random variableXis symmetricα-stable (SαS), 0< α <2, if its characteristic function is defined by

φX(θ) =e−σα|θ|α,

whereαis the characteristic exponent andσis the dispersion of the distribution. By lettingαtake the values 1 and 2, we obtain two important special cases of (SαS) distri-bution, namely Cauchy distribution and Gaussian distribution.

The random variablesX1, . . . ,Xd are jointly (SαS) if there is a single positive mea-sureΓX(d) onSd, unit sphere ofRd, where its characteristic function is of the form

φX(θ1, . . . ,θd) =exp §

Z

Sd

|θ1s1+. . .+θdsd|αdΓX(d)(s1, . . . ,sd)

ª

.

WhenX1andX2are jointly (SαS), the covariation of(X1,X2)is defined in Camba-nis (1983) by

[X1,X2]α=

Z S2

s1.(s2)<α−1>dΓX

1,X2(s1,s2),

where s<β> = sign(s).|s|β. This covariation plays the same role as the covariance because the moment of second order is infinity.

From the definition of the covariation Schilder (1970) defined the following norm on the linear space of (SαS) random variables

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The processξ = (ξt,t∈R)is symmetricα-stable if all linear combinationsPni=1λiξt

i

are (SαS) variables.

This paper considers a (SαS) process where its spectral representation is

ZN=

Zπ

−π

eiNλdξ(λ),

whereξ is a isotropic symmetricα-stable with independent increments.

The measure defined byµ(]s,t]) =|ξ(t)−ξ(s)|ααis Lebesgue-Stiel measure called the spectral measure(see Cambanis, 1983; Masry and Cambanis, 1984). Whenµis ab-solutely continuous dµ(x) = f(x)d x, the function f is calledthe spectral densityof the processZ.

As in Demesh (1988), Sabre (1994) and Sabre (1995), we give the definition of the Jack-son polynomial kernel.

Let Z1, . . . ,ZN observations of the process Z: €Z(n)Š

0≤n≤N−1, where N satisfies:

N−1=2k(n−1) with n∈N k∈N∪ ¦1

2 ©

if k=1

2 then n=2n1−1,n1∈N.

The Jackson’s polynomial kernel is defined by: |HN(λ)|α= ANH

(N)(λ)

α where

H(N)(λ) = 1 qk,n

sin(n2λ)

sin(λ2)

!2k

with qk,n= 1 2π

Zπ

−π sinn2λ

sinλ2

!2k

dλ.

In addition, we have AN= (Bα,N)−α1 with B

α,N= Zπ

−π

H

(N)(λ)

α dλ.

We give the following lemmas which are used in the reminder of this paper. Their proof are given in Section 5.

LEMMA1. There is a non negative function hksuch as

H(N)(λ) = k(n−1)

X m=−k(n−1)

hkm n

cos(mλ).

LEMMA2. Let Bα0,N=

Zπ

−π

sinn2λ

sinλ2

2kα

dλ and JN,α=

Zπ

−π|

u|γ|HN(λ)|αdλ,

whereγ∈]0, 2].

Then, B0

α,N       

≥2π

2 π

‹2kα

n2kα−1 if 0< α <2

≤ 4πkα 2kα−1n

2kα−1 if 1

(4)

and JN,α

        

πγ+2kα 22kα(γ2kα+1)

1

n2kα−1 if

1 2k < α <

γ+1 2k , 2kαπγ+2kα

22kα(γ+1)(2kαγ1) 1 nγ if

γ+1

2k < α <2.

In this paper, we propose an estimate of the constant erroradefined by

ˆ

a= AN

HN(0)

k((n−1)

X n0=k(n1)

hk

n0 n

X n0+k(n−1)

. (1)

THEOREM3. Let p a real number such that0< p< α. Then

|aˆ−a|p=O

 1

npα

‹

.

PROOF. From the spectral representation of the process, the estimator proposed

becomes

ˆ

a= AN

HN(0)

k((n−1)

X n0=k(n1)

•

hk

n0 n

Zπ

−π e x p

i [n0+k(n−1)]λ

dξ(λ) +a

˜

.

Using Cambanis (1983), the characteristic function of(aˆ−a)can be written as

Eexp[iℜe r(aˆ−a)] =exp

–

−Cα|r|α

Zπ

−π

AN HN(0)

k((n−1)

X n0=k(n1)

hk

n0 n

ei n0λ

α dξ(λ)

™

.

wherer=r1+i r2. It is easy to show that

Eexp[iℜe r(aˆ−a)] =exp(−Cα|r|αψN),

whereψN=ψN,1+ψN,2with

ψN,1= Zπ

−π

|HN(λ)|α

|HN(0)|αφ(λ)dλandψn,2=

q X

i=1

ci|HN(wi)| α

|HN(0)|α .

The functionφbeing bounded on[−π,π]and|HN(.)|αbeing a kernel, it can be shown

that

Zπ

−π|

HN(λ)|αφ(λ)dλis converging toφ(0). On the other hand, from Lemma 2,

we have

1 |HN(0)|α =

B0 α,N

n2kα =O

1

n

‹

. (2)

ThereforeψN,1converges to 0.

ψn,2≤ q X

i=1

ci B0

α,N

1

sin

”1 2wi

—

2kα B0

α,N

(5)

Therefore

ψN,2=O  1

n2kα

‹

.

Thus

ψN=O 1

n

‹

.

Consequently, the characteristic function of ˆa−aconverges to 1 whenNapproaches infinity. Hence we have the convergence in probability of ˆatoa.

We study now the convergence of ˆatoainLpwhere 0< p< α, which replaces the convergence in mean square, because the second order moment ofX is infinity.

Let

Dp=ℜe

Z∞

−∞

Z π4

π4

1−ei rcosθ |r|1+p d r dθ.

Lett=r0eiθ0 andx=%eiτ0.

Assuming nowr="r0, τ=τ0τ

0

Dp=ℜe

Z∞

−∞

Z π4+τ0

π4+τ0

1−ei"r0cos(τ0−τ 0)

|"|1+p|r0|1+p "d r

0dθ0

Dp|x|p=ℜe

Z∞ 0

Z π4+τ0

π4+τ0

1−eiℜe(t x¯)

|t|1+p d|t|dθ

0− ℜeZ0 −∞

Z π4+τ0

π4+τ0

1−eiℜe(¯t x)

|t|1+p d|t|dθ

0.

Replacing in this formulaxby ˆa−a, from the previous result we have

DpE|x|p =

Z∞

−∞

Z π4+τ0

π4+τ0

1−e−Cα|t|αψN

|t|1+p d|t|dθ

0

= π 2

Z∞

−∞

1−e−Cα|t|αψN

|t|1+p d t.

Letu=t[ψN]1α and using (2), we obtain

2

πCp,αE|aˆ−a|p= (ψN)

p

α =O

 1

np

‹

, (3)

where

Cp,α=RpFp,α1(Cα)−αp

with

Rp=

Z 1

−cos(u)

|u|1+p d uandFp,α=

Z 1

−e−|u|α |u|1+pα

(6)

3. IMPROVEMENT OF THE RATE OF CONVERGENCE

In this section, we study the cases where the spectral density is zero at the origin. We prove that the convergence rate of the estimator ˆawill be improved.

THEOREM4. Assume that the spectral density is satisfying

φ(λ) =|λ|βg(λ),

whereβ∈]0, 2kα−1[,λ∈[−π,π]and g(λ)is a bounded function on[−π,π], contin-uous in neighborhood of0and g(0)6=0. Then

24k pL≤ lim

N→∞n

p(β+1)

α E|aˆa|pπ4k pL,

where L is the following constant

L= π

2Cp,α

 g(0)

Z∞

−∞

sinu2

2kα

|u|2kα−β d u

 

p α

.

PROOF. From (2), the functionψNcan be written as

ψN=n−2kα Zπ −π

sinn2λ

sinλ2

2kα

|λ|βg(λ)dλ+n−2kα

q X

i=1

ci

sinnwi 2

sinwi

2

2kα .

Using the following inequality

sinx 2 ≥ x

π 0≤x≤π, (4)

we maximizeψNas follows

ψN≤π4kαn−2kα Zπ −π sin nλ 2

2kα

|λ|2kα−β g(λ)dλ+n−

2kαXq i=1

ci 1 sinwi

2

2kα .

Puttingnλ=u, we have

ψN≤π4kαn−1−β   Z∞ −∞ sin u 2

2kα

|u|2kα−β g

u

n

d u+n−

2kα+1+β

π4kα

q X

i=1

ci 1 sinwi

2

2kα .

On the other hand, using Lebesgue’s dominated convergence theorem, we show that

lim

N→∞

Z∞

−∞

sinu2

2kα

|u|2kα−β g

u

n

d u+n−

2kα+1+β

π4kα

q X

i=1

ci 1 sinwi

2

2kα =g(0)

Z∞

−∞

sinu2

2kα

(7)

Lemma 2 gives

lim

N→∞n

p(β+1)

α (ψ

N)

p

α π4k p g(0)

Z+∞

−∞

sinu2

2kα

|u|2kα−β d u

!pα

.

ThusψN converges to zero. Using the following inequality

|sinx| ≤ |x| ∀x∈[−π,π], (6)

we obtain

ψN≥24kαn−2kα

Zπ −π sin nλ 2

2kα

|λ|2kα−β g(λ)dλ+n−

2kαXq i=1

ci

sinnwi 2

sinwi 2

2kα ,

ψN≥24kαn−β−1  

Zπ

−π

sinu2

2kα

|u|2kα−β g( u

n)d u+Rn

 ,

whereRn=n−22kα+β+4kα 1P

q i=1ci

sin[nwi2 ] sin[wi2]

2kα

. SinceRnconverges to zero, the equality (5)

gives

lim

N→∞n

p(β+1)

α (ψ

N)

p

α 24k p g(0)

Z+∞

−∞

sinu2

2kα

|u|2kα−β d u

!αp

.

The first equality of (3) reaches the result of this theorem.

THEOREM5. Assuming that the spectral density satisfies

φ(λ) =sin2kα

λ

2

‹

g(λ),

where the function g is integrable on[−π,π]and g(0)6=0. Then

c t e π 2Cp,α

Zπ

−π g(λ)dλ

αp

≤ lim

N→∞n

2pkE|aˆa|p

π

2Cp,α

Zπ

−π

g(λ)dλ+

q X

i=1

ci 1 sinwi

2

2kα!αp

.

PROOF. From the definition ofψNand (2), we have

ψN=n−2kα Zπ −π

sinnλ 2

2kα

g(λ)dλ+n−2kα

q X

i=1

ci

sinnwi 2

sinwi 2

2kα .

As 1≤kαand the sinus function is smaller than 1, the next expression is connected to

ψN≤n−2kα Zπ −π sin nλ 2 2

g(λ)dλ+n−2kα

q X

i=1

ci

sinnwi 2

sinwi

2

(8)

ψN≤n−2kα

 

Zπ

−π

g(λ)dλ+

q X

i=1

ci

sinnwi 2

sinwi 2

2kα .

So, from Lemma 2, we have

lim

N→∞ψNn

2kαZπ −π

g(λ)dλ+

q X

i=1

ci 1 sinwi

2

2kα .

Using the fact that the sinus function is between−1 and 1 and thatkα <[kα] +1 where[kα]represents the integer part ofkα, we obtain

ψN≥n−2kα Zπ

−π



sinnλ 2

‹2[kα]+1

g(λ)dλ+n−2kαXq i=1

ci

sinnwi

2

sinwi 2

2kα

ψN≥n−2kα

n−1

2B0 α,N

Zπ

−π

•1cosnλ

2

˜[kα]+1

g(λ)dλ+n−2kαXq i=1

ci

sinnwi

2

sinwi 2

2kα .

The binomial formula gives

2[kα]+1ψN ≥ n−2kα

Zπ

−π g(λ)dλ

+ n−2kα

[kα]+1 X

r=1

(−1)rC[rkα]+1

Zπ

−π

cosr(nλ)g(λ)dλ

+ n−2kα

q X

i=1

ci

sinnwi 2

sinwi 2

2kα .

We know that

Zπ

−π

cosr(nλ)g(λ)dλ is converging to a constant. Indeed, using the

binomial formula, we obtain

cosr(nλ)=

ei nλ+e−i nλ 2 r = 1 2r r X

j=0

Crjei j nλe−i(r−j)nλ.

Hence

Zπ

−π

cosr(nλ)g(λ)dλ = 1 2r

r X

j=0

Crj

Zπ

−π

ei(2j−r)nλ

= 1 2r

r X

j=0

Crj

Zπ

−π

cos((2j−r)nλ)g(λ)dλ.

The right side of the last equality converges to 1 2r

Zπ

−π

g(λ)dλwhen r is even, and

converges to 0 whenris odd. Consequently,

lim

N→∞

[kα]+1 X r=1

(−1)rC[rkα]+1

Zπ

−π

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            

[kα]+1 2 X

p=1

(−1)2pC[2kpα]+1 1 22p

Zπ

−π

g(λ)dλ if [kα] +1 is even

[kα]

2 X

p=1

(−1)2pC[2kpα]+1 1 22p

Zπ

−π

g(λ)dλ else.

Since limN→∞n−2kαPq i=1ci

sin[nwi2 ] sin[wi2]

2kα

= 0. The similar arguments are used for showing that

lim

N→∞(ψN)

p

αn2k pc t e

Zπ

−π g(λ)dλ

pα

. (7)

THEOREM6. Assume that spectral density satisfies

φ(λ) =|λ|βg(λ),

whereβ >2kα−1and g is measurable positive function bounded on[−π,π]. Then

c t e×R≤ lim

N→∞n

2k pE|aˆa|pR,

where R= π

2Cp,α

  

Zπ

−π |λ|β

sin

λ

2

2kαg(λ)dλ

  

p α

.

PROOF. Define the continuous functionlas follows

l(λ) =

            

π2kα if |λ|> π

|λ|2kα

sin

λ

2

2kα if 0<|λ| ≤π

22kα ifλ=0. The functionψNcan be written as

ψN=n−2kα Zπ

−π

sinn2λ

sinλ2

2kα

sin2kα

λ

2

‹

h(λ)dλ+n−2kα

q X

i=1

ci

sinnwi 2

sinwi 2

2kα ,

whereh(λ) =l(λ)|λ|β−2kαg(λ). We know that the functionhis integrable on[−π,π]. Indeed, since the function g is bounded, we get

Zπ

−π

h(λ)dλ≤sup(g)

Zπ

−π

l(λ)|λ|β−2kαdλ.

Using the inequality (6), we obtainl(λ)≤π2kα. Thus

Zπ

−π

h(λ)dλ≤2π2kαsup(g)

Zπ

0

(λ)β−2kαdλ.

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THEOREM7. Assume that the spectral density has the following form:φ(λ) =|λ|βg(λ) whereβ <2kα−1and g is a continuous positive function on[−π,π]. Then

Q×22k p≤ lim

N→∞n

(β+1)p

α |E|aˆa|pπ2k p×Q,

where Q=

g(0)

Z∞ −∞

sinu1 2

2kα

|u1|β1−2kαd u 1

pα

.

PROOF. From the definition of the kernel|HN(λ)|α and the inequality (6), we obtain

ψNπ

2kαn−1

B0 α,N

Zπ −π

sinnλ 2

2kα

|λ|β−2kαg(λ)dλ+n−2kα

q X

i=1

ci

sinnwi 2

sinwi 2

2kα .

Puttingnλ=u, we obtain

ψNπ

2kαn2kα−β1−2

B0 α,N

Z∞ −∞ sinu 2

2kα

|u|β−2kαg(u

n)d u+n −2kαXq

i=1

ci 1 sinwi

2

2kα .

whenN approaches infinity, we obtain

lim

N→∞n β+1ψ

N≤π2kα Z∞ −∞ sin u 2

2kα

|u|β−2kαg(0)d u.

Similarly, from the inequality (6) we minimizeψNas follow

nψN≥ 2

2kα

B0 α,N

Zπ −π sin nλ 2

2kα

|λ|β−2kαdλ+Qn,

whereQn=n−2kα+1Pq i=1ci

sin[nwi2 ] sin[wi2]

2kα

. SinceQnconverges to zero and the function

λ−→g(λ)is continuous, Lemma 2 gives

lim

N→∞n β+1ψ

N≥22kα Z∞ −∞

sinu1 2

2kα

|u1|β−2kαg(0)d u.

Thus from (3) we obtain the result of this theorem.

4. NUMERICAL STUDIES

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their arrival times are modeled by Poisson distributions independent to the direction (isotropic). From the series representation theory shown by Janicki and Weron (1993), the sum of the arrival times can be modeled by a stable harmonizable processZn as the process defined by (8). It is supposed that these signals are observed in an aquatic environment causing a constant disturbance. The signal arrival delay model in this case can be considered to be affected by a constant error (Xn=Zn+a).

Throughout this section, we give the simulation of the studied process

Zn=

Zπ

−π

ei nλdξ(λ), (8)

where 1< α <2 andξ is a complex symmetricα-stable measure onRwith

indepen-dent and isotropic increments and with control measuremsuch thatmd x=φ(x)d x. For that, we use the series representations given by Janick and Weron (1993). Therein the authors have shown that the processZdefined by (8) can be expressed as follows

Zn=Cα

Z

φ(x)d x

‹1αX

k=1 "kΓ

−1α

k e

i nVkeiθk, (9)

where

"kis a sequence of i.i.d. random variables such asP["k=0] =P["k=1] = 1 2,

Γk is a sequence of arrival times of Poisson process,

• Vk is a sequence of i.i.d. random variables independent of"k and ofΓk having the same distribution of control measurem, which has probability densityφ,

θkis a sequence of i.i.d. random variables that have the uniform distribution on [−π,π], independent of"k,Γk andVk.

To generateNvalues(N=101, 501, 1001)of the processZn, we use the following steps:

• generate 2000 values of"k,

• generate 2000 values ofΓk,

• generate 2000 values ofVk,

• generate 2000 values ofθk.

Then we calculate for all 0≤n≤N

Zn=Cα

Z

φ(x)d x

‹1α2000 X k=1

"kΓ

−1α

k e

i nVkeiθk, (10)

(12)

We calculate the estimator ˆagiven in (1) for different sizes of sampleN=101, 501, 1001. The result is given in Table 1.

Comparing ˆato 30 (value of the constanta), we find that the estimator ˆa increas-ingly approaching the constant errorawhen the sample size is large. And the approx-imation is better when the parameterβof the spectral density is greater than 2kα−1 compared to the case whereβis smaller than 2kα−1.

TABLE 1

Values of the estimator for two values ofβone is smaller than2kα−1other is bigger than

2kα−1.

2kα−1=12.6 β=0.21 β=38 N=101 aˆ=20.30 aˆ=36.45 N=501 aˆ=35.10 aˆ=31.03 N=1001 aˆ=28.89 aˆ=30.28

5. APPENDIX

PROOF OF LEMMA1. For all nonnegative integer,n, we have

n−1 X s=0

ei sλ=sin(

nλ

2)

sin(λ2)e

i(n−1)λ

2 .

Therefore we can writeH(N)(λ) = 1 qk,n

‚n1 X s=0

ei sλ

Œ2k

e−i k(n−1)λ

HenceH(N)(λ) =e−

i k(n−1)λ

qk,n

X t∈S2k

exp

•

i(t1+t2+· · ·+t2k)λ

˜

, where

S2k=

§

t= (t1,t2,· · ·,t2k)∈Z2k; ∀j∈ {1, 2,· · ·, 2k} 0≤tj≤n−1 ª

.

Let τ=t1+t2+· · ·+t2k, we haveH(N)(λ) =e

−i k(n−1)λ

qk,n

2k(n−1)

X

τ=0

exp

•

iτλ

˜

QN(k)(τ),

where QN(k)(τ) =X

t∈S2k

χ0(t1+t2+· · ·+t2kτ).

QN(k)(τ)is the number of the terms (t1,t2,· · ·,t2k) which satisfy: ∀j∈ {1, 2,· · ·, 2k} tj∈Z, 0≤tj≤n−1 et t1+t2+· · ·+t2k=τ.

Ifk=1

2 andτ∈Z then Q

(k)

N (τ) =1. On the other hand, putting

m=τ−k(n−1), we get

H(N)(λ) = 1 qk,n

k(n−1)

X m=−k(n−1)

exp[iλm]QN(k)(m+k[n−1]).

SinceH(N)(.)is even function, by using H(N)(λ) = H(

N)(λ) +H(N)(λ)

2 we obtain

H(N)(λ) = 1 qk,n

k(n−1)

X m=−k(n−1)

exp

•

iλm

˜

+exp

•

−iλm

˜

2 Q

(k)

(13)

H(N)(λ) 1 qk,n

k(n−1)

X m=−k(n−1)

cos(λm)QN(k)(m+k[n−1]).

It follows from the definition ofqk,n, we obtain

qk,n = 1 2π

Zπ

−π

sin(n2λ)

sin(λ2)

!2k

dλ

qk,n = 1 2π

Zπ

−π

 

k(n−1)

X

τ=−k(n−1)

cos(λτ)QN(k)(τ+k[n−1])

 dλ

qk,n = 1 2π

k(n−1)

X

τ=−k(n−1)

Zπ

−π

cos(λτ)dλ

QN(k)(τ+k[n−1]).

Since τ∈Z, we have

Zπ

−π

cos(λτ)dλ=

§ 0 if τ

6

=0

2π if τ=0

We haveqk,n=QN(k)(k[n−1]). By substituting this in the expression forH(N)(λ), we

obtainH(N)(λ) =

k(n−1)

X m=−k(n−1)

cos(λm)

 

QN(k)(m+k[n−1])

QN(k)(k[n−1])

. Therefore the function

hkis defined by

hk(u) =

( •Q(k)

N(nu+k[n−1])

QN(k)(k[n−1])

˜

ifnu∈Z

0 ifnu∈/Z

We note that ifk=1

2 then qk,n=hk

m n

=1.

PROOF OFLEMMA2. We first state some inequalities which we are using in this proof

|sin(λ)| ≤ |λ| ∀λ∈R (11)

|sin(λ 2)| ≥

|λ|

πλ∈[−π,π] (12)

|sin(nλ)| ≤n|sin(λ)| ∀λ∈R, (13)

It follows from (11) and (12) that

Bα0,N=

Zπ

−π

sinn2λ

sinλ2

2kα

dλ≥2

Z πn

0

nλ/π λ/2

2kα

dλ=2π

2 π

‹2kα

n2kα−1. (14)

(14)

Bα0,N =

Zπ

−π

sinn2λ

sinλ2

2kα

dλ≤2

  

Z πn

0

n2kαdλ+

Zπ

π n

1

€λ

π

Š2kαdλ

  

Thus we obtain

Bα0,N

 4πkα

2kα−1

‹

n2kα−1. (15)

Using (12) and (11) we get

JN,α = 2

B0 α,N

Zπ

0

(λ)γ

sinn2λ

sinλ2

2kα

dλ≤ 2

B0 α,N

‚Z πn

0

λγn2kαdλ+Zπ

π n

λγπ λ

2kα dλ

Œ

≤ 2

B0 α,N

πγ+1 γ+1n

2kα−γ−1+ π2kα γ−2kα+1

•

πγ−2kα+1π

n

γ−2kα+1˜

≤ 2

B0 α,N

πγ+1 γ+1n

2kα−γ−1+ πγ+1 γ−2kα+1−

πγ+1 γ−2kα+1

1 nγ−2kα+1

.

We distinguish two cases according to the sign ofγ−2kα+1

JN,α≤ 2 B0

α,N       

πγ+1 γ+1−2kα

2kαπγ+1

(γ+1)(γ−2kα+1) 1

nγ−2kα+1 if γ−2kα+1>0

2kαπγ+1

(γ+1)(2kαγ−1) 1 nγ−2kα+1−

πγ+1

2kαγ−1 if γ−2kα+1<0.

From (13) we get

JN,α

            

2πγ+1 γ−2kα+1

1

2π€π2Š2kαn2kα−1

if 1

2k < α <

γ+1 2k

4kαπγ+1

(γ+1)(2kαγ−1)

n2kα−γ−1

2π€2

π

Š2kα n2kα−1

if 2> α >γ+1 2k .

This inequality implies the results of the lemma.

CONCLUSION

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ACKNOWLEDGEMENTS

I would like to thank the referees for their interest in this paper and their valuable comments and suggestions.

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SUMMARY

Consider a symmetricαstable process having a spectral representation with an additive con-stant error. An estimator of that error and its rate of convergence are given. We study the rate of convergence when the spectral density have some behaviors at origin. Few long memory processes are taken here as example.

References

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