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Punnett Squares

Science 30

Chapter 2.2 - page 96

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1. Punnett Square Definition:

• A table that uses the

alleles

alleles

of the

parents to show all the

possible

possible

outcomes

(3)

2. Rules of probability are relevant

to genetics.

• Express probability as a number

between 0-1, (decimal), as a fraction or

a percentage

(4)
(5)

Example Problem: Punnett Square

• Two pea plants in the parent generation each

contain the dominant allele P that codes for

purple flowers and the recessive allele p that

codes for white flowers. Use a Punnett

(6)

Example Problem: Punnett Square

• Step 1 … 2 … 3 … Fraction of offspring

with genotype:

PP

p p

P p

Pp

PP: 2Pp : pp

25% :50% : 25%

PHENOTYPE

purple: white

(7)

Example - Tongue rolling

• In human beings the ability to roll one’s

tongue is dominant over non-tongue rolling. • Identify Alleles =

• Can YOU roll? a) YES

(8)

Example Problem: Punnett Square

• Step 1 … 2 … 3 … Fraction of offspring

with genotype:

R

r

r

r

R r

r r

R r

r r

R r : r r

50% : 50%

PHENOTYPE

ROLL : NON-ROLL

(9)

3. Identifying Alleles:

Heterozygous

:

two

different alleles,

one

dominant

one

recessive

Heterozygous for flower color =

P p

• This is the GENOTYPE (description of alleles using letters) =

P = purple OR p = white

What color is this plant?

P p= purple

• This is the PHENOTYPE (what we

(10)

Identifying Alleles

• Homozygous:

two

copies of the same

allele,

either

both dominant or both

recessive

Homozygous recessive for flower

color = p p

• Phenotype of this plant is:

white

Homozygous dominant for flower

color =

P P

(11)

Practice

• For the following questions use the trait Tongue Rolling. Identify the alleles below:

Tongue Rolling =

R

Non-rolling =

r

1.Use letters to describe the genotype of each following individual:

a. A homozygous tongue roller

b. A heterozygous tongue roller

c. A homozygous non-roller

(12)

Practice

2. The fuzzy skin of a peach is produced by a

dominant allele N, and the smooth skin of a

nectarine is produced by the recessive allele

n. State whether the skin phenotype of the

following individuals is fuzzy or smooth

a. NN

b. Nn

c. nn

(13)

Practice

3. State the

most likely

genotype of

each example

a. A smooth skinned nectarine

b. A fuzzy-skinned peach bred from a cross between a peach – producing tree and a nectarine-producing tree

c. A fuzzy-skinned peach produced from a long line of peach-producing trees

Nn

NN

(14)

Practice

4) Predict the following:

a)A smooth skinned nectarine tree is crossed with another smooth skinned nectarine … the offspring are then crossed with a

heterozygous fuzzy peach tree … what will be the genotypes and phenotypes of the resulting offspring?

(15)

4. Monohybrid Problems

• One trait being followed from one generation to the next.

Eg. A cross between a heterozygous

peach and a homozygous nectarine

• Steps in doing Monohybrid Crosses:

1. Identify the gametes

2. Identify the parent cross 3. Draw the Punnett Square

(16)

Example #1:

Homozygous tall X Homozygous pea plant recessive

1.Determine the genotypic and phenotypic ratios of the offspring

T t

T t

T t

T t

T

T

t

t

(17)

Example #2

Heterozygous Tall X Heterozygous Tall

Determine the genotypic and phenotypic ratios of the offspring

T T

t t

T t

T t

T

t

T

(18)

Do we get it?

1) Two heterozygous parents have a child – what is the percentage probability that their offspring will be able to roll their tongue?

(19)

Do we REALLY get it?

2. A heterozygous man marries a

homozygous recessive woman.

What is the probability that their

offspring can roll their tongue?

(20)

OTHER PATTERNS OF

INHERITANCE

Science 30

Unit 1 – Biology

(21)

Other Pattern of Inheritance

(page 99)

Multiple allelesMultiple alleles:: Not all traits are controlled by one gene or only have two alleles for a gene.

For example: hair and eye color are determined by many pairs of alleles

(22)

Other Pattern of Inheritance

(page 99)

CodominanceCodominance in alleles: some times both alleles are expressed equally.

For example coat color in cattle. A

(23)
(24)

Other Patterns of Inheritance

• Blood typing in humans reflects both of these patterns of inheritance:

Three alleles: A, B and O produce four

blood types or phenotypes

– A and B alleles are

codominant and are both dominant over

O

Table of Blood Types Genotype Phenotype

AA or AO

A

BB or BO

B

AB

AB

(25)

HETEROCHROMIA IRIDIUM

• Eye color is a manifestation of the pigment that is present in the iris.

• Brown eyes are rich in melanin deposits, and blue eyes indicate a lack of melanin. • The melanocytes of the iris rest in a richly innervated psuedosyncytium, which is

necessary to maintain eye color.

• Two genes control eye color: EYCL3, found on chromosome 15, which codes for brown/blue eye color (BEY), and EYCL1, found on chromosome 19, which codes for green/blue eye color (GEY).

• Although previously believed to be inherited in simple Mendelian fashion, eye color has proved to be a polygenic trait.

Precisely how these genes interact to provide the full constellation of colors, such as hazel and gray, is as yet unknown.

• Furthermore, other genes may determine the pattern and placement of pigment in the iris, thereby accounting for solid brown as opposed to rays of color.

• Heterochromia iridium (two different-colored eyes within a single individual) and

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(27)

Sex Chromosomes

• The X and Y chromosomes that determine gender also carry other genes that do not

determine the sexual characteristics

• Autosomal inheritance:

trait linked to

autosomal

(28)

Sex Chromosomes

• Sex-linked inheritance:

trait linked to sex chromosomes X or Y

More than 120 known sex-linked traits in humans

Almost always found on the X chromosome,

single recessive gene on the X will cause the disease

Genes on Y only inherited by males

Examples include:

(29)

Sex-linked traits

• Red-Green color blindness is the inability to

(30)

Sex-Linked problems

• When solving sex-linked cross problems

the alleles used are the X and Y and the

trait is denoted with a superscript letter.

• If

N

is full color vision and

n

is

color-blind then:

a man that is color-blind has the

genotype

X

n

Y

and a woman who is a

(31)

Sex-linked problems

Example One: What is the outcome of a

cross between a normal male and a

woman who is a carrier for hemophilia?

X

N

Y

(32)

Sex-linked problems

Example Two: What is the outcome of a cross between a color blind man and a woman who is homozygous for full color vision?

X

b

Y

X

B

X

B

X

b

X

B

Y

(33)

Your turn!

Figure

Table of Blood Types Genotype Phenotype

References

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