• No results found

Definite and Indefinite Integration

N/A
N/A
Protected

Academic year: 2021

Share "Definite and Indefinite Integration"

Copied!
36
0
0

Loading.... (view fulltext now)

Full text

(1)

K

K E

E Y

Y

C

C O

O N

N C

C E

E P

P T

T S

S

1

1 . . D ED E F IF I N IN I T IT I O NO N ::

If f &

If f & g g areare functions functions of x such that g'(x) = of x such that g'(x) = f(x) f(x) then  then the functhe function g tion g is calis called aled aPRIMITIVE PRIMITIVE OO RR ANTIDE

ANTIDERIVATIVE RIVATIVE OO R INTEGRALR INTEGRAL of f(x) of f(x) w.r.t. x w.r.t. x and iand is s wriwrittetten symbolically asn symbolically as

f ci

f ci

II  f(x)  f(x) dx = g(x) dx = g(x) ++ c c < <==>> —  — (g(x) + (g(x) + c) =c) = f(x), f(x), where  where c is c is called called thethe  constant of integration,  constant of integration, dx

dx 2.

2. STANDARD STANDARD RESULTS RESULTS ::

\ n + l \ n + l r (ax+b) r (ax+b)nn i) i) JJ ((aax x + + b)°dx= b)°dx= , , \ \ ++ c nc n ** -- ll   a(n+l)   a(n+l) iii) f 

iii) f  eeax+bax+bdx dx = - = - eeax+bax+b + c + c aa

v)

v) f sif si n(an(a x+bx+b ) ) dx dx = = -— co-— co s(s( axax +b+b ) ) + + cc aa

vii)

vii) j j tan(ax tan(ax + + b) b) dx dx == —  —  InIn sec (ax + b) + c sec (ax + b) + c aa

ix) J

ix) J secsec22 (ax + b) dx = (ax + b) dx = — —  tan(ax + b) + ctan(ax + b) + c aa

xi) J

xi) J sec (axsec (ax + + b) b) .. tan (ax tan (ax + b) + b) dx = dx = — —   sec (ax  sec (ax + b) + + b) + c c aa

xii) J

xii) J  co  cosec sec (ax (ax + + b) b) . co. cot t (ax (ax + + b) b) dx dx = = cosec cosec (ax (ax + + b) b) + + cc aa

xiii)

xiii) JJ secx secx dxdx =I=I n (secx n (secx + + tanx) + tanx) + cc OR OR  InIn tan { tan { + + y y jj + + cc

xiv) J

xiv) J cosec x cosec x dx dx = I= In n (cose(cosecx - cx - cotx) + ccotx) + c OR OR  In In tan ^ tan ^ + + cc OR OR -- In In (cose(cosecx + cx + cotx)cotx) xv) J

xv) J sinh sinh x dx = cosh x + cx dx = cosh x + c (xvi) (xvi) JJ cosh cosh xxdx dx = sin= sinh h x + cx + c (xvii) (xvii) JJ  sech  sech22x dx = tanh x + cx dx = tanh x + c xviii) J

xviii) J  cosech  cosech22x dx x dx = - = - coth x + ccoth x + c (xix) (xix) JJ sech sech xx . . tanh x dtanh x dx x = - = - sech sech x + x + cc xx)

xx) J cosechxJ cosechx. . cotcot hxdhxd x= x= -co-co sese chx + cchx + c   (xxi)(xxi) jj"" (ii)

(ii)

j

j

=

=--

/n/n (ax + (ax + b) b) + c+ c

ax+b a ax+b a r r 1 1 nn px+ px+ qq (iv) I (iv) I aPaPx+x+i i dx dx == — —  (a (a > > 0) 0) + + cc . . p p fnfn aa (vi) J

(vi) J  cos(ax  cos(ax ++bb)dx= - sin(ax)dx= - sin(ax+b+b )) + c+ c aa

(viii) f 

(viii) f   cot(ax+  cot(ax+b)b) dx dx = - = - /n /n sin(asin(ax+x+b)+b)+ c c aa

(x)

(x)  j cosec  j cosec22(ax(ax + b) + b) dx  dx = = _ _  1 1  cot(ax  cot(ax + b)+ + b)+ c c

dx dx . . , , x x ,, = sin = sin 11 — + c — + c xxii) xxii) J J „„dxdx „ „ = = -- tata nn-1-1 — — + c+ c aa22++ xx22 (xxiii) J(xxiii) J dx dx x-v/x x-v/x22-a-a22 aa 1 1 -l -l xx ^^ = = — —  secsec 11 —  —  +1+1 xxiv) xxiv) J J 7 7 =l=ln n ++ '' JJ xx22 LL  +  + a a22 x

x22 + + aa22 OR OR    sinhsinh-1-1 - - + + cc aa xxv) J xxv) J xxvi) | xxvi) | dx dx Tn

Tn x x ++ OR OR    cosh"cosh"11 - - + + cc aa dx dx l l , , a+a+ xx In In 2 2 2 2 --a a -- x x 2a 2a aa -- xx + + cc (xxvii)(xxvii) jj dx dx 1 1 , , xx -- aa In In + + cc x x22-- aa22   2a 2a x+ax+a <!SBansal

(2)
(3)

(xxviii) j

.y

]a2-x2 dx = - A/a2-x2 + — sin"1 - + c 2 2 a (xxix) { *Jx2+a2 dx= —  ^ x2+ a2 + — sinlr 1 - + c 2 2 a (xxx) j J xv 2- a2  dx= - J x2- a2 - — cosh"1 - + c 2 v 2 a f e3*

(xxxi) I eax. sin bx dx = —-—x- (a sin bx - b cos bx) + c

a +b

f ax

(xxxii) J eax. cos bx dx = — — - (a cos bx + b sin bx) + c

a +b

3. TECHNIQUES OF INTEGRATION:

(i) Substitution or change ofindependent variable.

Integral 1= j f(x) dx is changed to }  f(4> (t)) f'(t) dt, by a suitable substitution x = (J) (t) provided the later integral is easier to integrate.

(ii) Integration by part: {  u.vdx=u j" vdx- {

(a) J v dx is simple & (b) /

0) d U f A . vd? r1Y J f vdx r)v J du dx

function. Note: While using integration by parts, choose u & v such that du

dx

dx where u&varedifferentiable

dx is simple to integrate. This is generally obtained, by keeping the order of u & v as per the order of the letters in ILATE, where ; I-Inverse function, L-Logarithmic function,

A-Algebraic function,  T-Trigonometric function  & E-Exponential function

(iii) Partial fraction,  spiliting a bigger fractioninto smaller fraction by known methods.

4. INTEGRALS OF THE TYPE:

 j  [f(x)]"f'(x)dx OR { dx putf (x ) = t & proceed

(") j J  ax' + bx + c > 1 I ,yax + bx + cdX > f VaxJ y 2 + bx + c <k

Express ax2 + bx + c in the form of perfect square & then apply the standard results.

("0 Jf —?PX ^— dx, f i = q = dx .

ax2 + bx + c ' J  ^/ax2 + bx + c

Express px + q= A (differential co-efficient of denominator) + B.

(iv) j ex [f(x) + f'(x)] dx = ex. f(x) + c (v) J  [f(x) + xf'(x)] dx - x f(x) + c

f  dx

(vi) J J n s N Take xn  common & put 1 + x n = t .

x(xn+l)

r

dx

(vii) J (n l) / n e N , take xn  common & put 1+x n = tn

2

(xn+l)n"^ x2'

(4)
(5)

(viii) dx c»(l+ x f n

take xn common as x and put 1+ x n = t.

dx

OR

J

dx OR

J

dx

a+bsin z x " a+bcos 2 x asin 2  x+bsin xcos x + ccos 2 x

r r

Multiply N" & D by sec2x & put ta nx = t .

00 dx

a+bsin x OR

dx

a+bcos x OR

i

dx

a + bsin x + ccos x

(xii)

(xiii)

(xiv)

(xv)

Hint: Convert sines & cosines into their respective tangents of half the angles, put tan  — = t

a.cos x + b.sin x + c ^ Express Nr = A(Dr) + B — (Dr) + c & proceed .

 Lcos x + m.sin x + n dx

x2+ l

x 4 + K  x 2 +1 dx OR |

x2- l

 —; dx where K is any constant .

x + K x + 1 J

Hint: Divide Nr & Dr by x2  & proceed .

dx „ r dx

1

&

 J

7

 —t—;

\— 

;

put px + q = t .

(ax + b) Vpx + q (ax2 + bx + cj ^px + q dx (ax + b) J- px + qx + r • j-u 1 ( dx • 1 , put ax + b = - ; . , , p u t x = -1 (ax + bx + cj yj px + qx + r  1 x - a  p - x

 — ^ °r  I V(x ~ a) (x ~ P) > put x = a sec20 - 0 tan20

dx or J - a) (p - x) ; put x = a cos20 + P sin20

dx

J(x - a) (x - p) ; put x - a = t

2

  or x - P = t2

(ilZ?a«sa/  Classes Definite & Indefinite Integration [18]

(6)
(7)

DEFINITE INTEGRAL

1 . f f(x) dx = F(b) - F(a) where J f(x) dx = F(x) + c

a

 b

VERY IMPORTANT NOTE : If F f(x) dx = 0 =>  then the equation  f(x) = 0  has atleast one

a

root lying in (a, b) provided f  is a  continuous function in (a, b) .

2 . PROPERTIES O F DEFI NITE INTEGRAL :

 b b b a

P-L j  f(x) dx = J f(t) dt provided f  is same P - 2 f  f(x) dx = - J f(x) dx

a a • a b

 b c b

P- 3 J f(x) dx= J f(x) dx+ J f(x) dx, where c may lie inside or  outside the interval [a, b] . This property

a a c

to be used when f  is piecewise continuous in (a, b).

a

P-4 J f(x) dx = 0 if  f(x) is an odd function i.e.  f(x) = -f(-x) .

= 2 j f(x) dx if  f(x) is an even function  i.e. f(x) = f(-x) . 0

 b b a a

P-5 J f(x) dx = j f(a + b - x) dx, In particular  J f(x) dx = J f(a - x)dx

P-6 j f(x) dx - J f(x) dx + J f(2a - x) dx = 2 J f(x) dx if   f(2a - x) = f(x)

0 0 0 0

= 0 if   f(2a - x) = - f(x)

na a

P-7 J f(x) dx = n Jf(x) dx ; where'a'is the period ofthe function i.e. f( a+x) = f(x)

0 0

 b+ nT b

P-8 j f(x) dx = J f(x) dx where f(x) is periodic with period T& n e l .

a+nT a

na a

P-9 j  f(x) dx = (n - m) j f(x) dx if  f(x) is periodic with period 'a'.

ma 0

 b b

P-10 If  f(x) < ())(x) for a < X < b  then J f(x) dx < J 4> (x) dx

P - L L Jf (x)dx < ] I f(x) I dx.

P-12 If  f(x) >0 on the interval [a, b], then J f(x) dx > 0.

(8)
(9)

WALLI'S FORMULA:  ji/2

J sm-x. co s ^ dx - [Q -l )( n- 3) (n- 5 ) . . . . l ot 2 X ( m- 1 ) ( m- 3 ) . .. . l o r 2 j K

( m + n ) ( m + n - 2 ) ( m + n - 4 ) . . . . l o r 2

7C

Where K = if both m and n are even (m, n e N)

2

- 1 otherwise

4. DERIVATIVE OF AN TIDERIVATIV E  FUNCTION :

If h(x) & g(x) are differentiable functions of x then, m

- p 1 m d t - f [ h (x)]. h'(x) - f [g (x)]. g'(x)dx g(x)

5. DEFINITE INTEGRAL AS LIMIT OF A SUM :

 b

J f(x) dx = Lmut h [f (a) + f (a + h) + f (a + 2h) + + f ( a + n-1T»)]

a

= h I f (a + rh) where b - a = nh

f=0

If a = 0 & b = 1  then, Limit h f (r h) = Jf (x) d x . w h e r e n h = l 0 R

Limit

v n ; r=i2 f f- - ] = J f(x) dx .vny o

6. ESTIMATION OF DEFINITE INTEGRAL:

 b

(i) For  a monotonic decreasing function in (a , b) ; f(b). (b - a) < J f(x) dx < f(a). (b - a) &

a  b

(ii) For a monotonic increasing function in (a, b) ; f(a).(b - a) < j f(x) dx < f(b).(b - a)

a

7. SOME IMPORTANT EXPANSIONS :

. . . , 1 1 1 1 , „ , .... 1 1 1 1 7T

0) 00 = In 2 (u) - 5 - + — T+~T+ — T+ 00 :

2 3 4 5 l2 22 3 4 6

1 1 1 1 7 t2 , . , 1 1 1 1 7 t2

(iii) — - + — - + 00=7— (iv) - r - + — + — + . — +

co=-1 2 3 4 12 1 3 5 7

, v 1 1 1 1 712

(v) —2~I 2-"1

22 42 62 82 24

(10)
(11)

 EXERCISE-I Q l l Q.4 J Q.6 j Q.9 j tan 20 Vcos6 9 + sin6 0 dx d0 Q 2 f 5x 4  + 4x5 (x5+ x + l)2 K - ' f Q.5 Integrate j dx dx cos X 1 + tanxdx X ^ X2  + 2 X - 1

 by the substitution z=x + ^/x'2 +2x-1

I s

eJ +l x ^nxdx

a2 s in2x+b2 cos2x

4 - 2 i 4 2

a sin x+b cos x

Q.7 | cos 20 . Incos 9+sin 9

cos 0-sin 9 d0 Q-8 f - y ^J sin x +

dx sin ^x + sin 2x dx Q.IO J dx Q.12 f si n( x- a)d x V sin(x+a) (x + Vx(l + x) )2 Q.13 J (sinx)"11/3 (cosx)"1/3dx Q.14 j Q .l l J V x ^ + 2 dx cot xdx (1-sin x)(sec x+1) Q.15 j Q.17 | 1-Vx dx !l+Vx ^/x2+l[ln(x2+l)-21nx] Q.16 j sin"-l l + X dx X dx Q.18 j ln(lnx)+ (lnx) dx Q.19 j x+1

Q.20 Integrate ^ f'(x) w.r.t. x4  , where f(x) = tan-1x + /n^/l+x - / n ^ l ^

Q.21 j (Vx + l)dx Vx(Vx+1) Q.22 f -dx sin^ ,/cos3 ^

J:

4+xe*)2 dx dx Q.27 j ^Q-30

\

cosec x-cotx secx

 ]j cosec x+cotx^/l+2secx dx cosx-sinx 7-9sin2x dx Q-23 J 3V(x + l )2(x-l) „ _ , r dx Q.26 j dx sinx+secx \2 x cosx-si nx dx

V

Q.33 f ^ S m X dx V sinx + V cosx

r ecosx(x sin3 x + cosx)

Q.36 j • v '

Q.3'9 j

Q.28 J tan x.tan 2x.tan 3x dx

r 3+4sinx+2cosx Q.31 J :   3+2sinx+cosx Q.34 f — ^J sin x +1 secx+cos ecx dx dx Q.29 j —  f  — sinx Jsin(2x + a) . ^n(cosx+Vcos2x] Q.32 [ —^ J ~ dx sm x -tan x 2 Q 35 \ 3x 2 +1 ( x2- l )3 dx sin2 x dx r (ax -b) dx Q '3 7  J xVc2x2-(ax2+b)2 r e \z—a Q.38 /= (l-x)Vl dx

 ,„

2\3/2 dx (7x-10-x ) Q.40

J

xlnx dx Q.42 j 2 - 3 x j1+x 2 + 3x (^J } E i x q.43 f f " " dx Q.44 { 1- x J 1 + 3sm2x J Q.41 f J i z * dx v J   Ali+x X 4x5 - 7x4 + 8x3 - 2x2 + 4x - 7 x2(x2 +1)2 dx

(12)
(13)

Q4 5 1 ( 2(x +3x+3 j^/x+1XI2 V> r ~ T Q.46 j ^ -J x - x 2 dx Q.47 J x2 J  (x-a)V(x-a)(x-(3) ^ r dx f  Jcos2x <• (l + x2)dx Q.48 Y Q.49 f — dx Q.50 I S — r a e ( 0 , TC) x3V(l + x)3 v J si n x v J  l - 2 x2c o s a + x4 V J

 EXERCISE-II

71

q'!^™ 

Q2

IV 

T

H3I

dx

QJ

!

 /n3xdx

0

 ji/2 TI/2 TI/4

x dx

Q.4 J sin2x. arctan(sinx)dx Q.5 J cos43x. sin26xdx Q.6 j _

o o • o  c o s x  (cosx + sinx)

Q.7 Let h (x) = (fog) (x) + K where K is any constant. If (h(x)) = ^ ^ — then compute the

dx cos (cos x)

f(x)

value of j (0) where j (x) = j" —— dt; where f and g are trigonometric functions.

g ( x ) S W n/2

Q.8 j 7(co s2n_1x - cos2n+1x) dx where n e N

- i t / 2

Q.9 Evaluate the integral: J (jx  + 2 yflx  - 4 + Jx-2 ^2x^4  j dx

3

00 00 oo

i x2 r xdx r dx

Q.10 I f P = - d x ; Q = and R = T then prove that

 j  l + x J  1+ X j  1+ X 0 0 0 (a) Q= (b) P = R, (C) P - V 5 Q + R = ^ Q.ll Provethat ? . ( n - l K a , h)x +n a h ) ^ ^ bn . _ an-! J a (x+ a) (x-t- b) 2(a + b) l   x(l-x)r x i i - x 4 , f vf x22l n v.In x , r yf  x 2" x Q.12 J , dx q.13 J 2LJE2L dx Q. 14 Evaluate: J 7 2

0

1+ X

0

 Jl-x2

_2"VX +4

^ n/2 271 Q.15  f ^ - f j d x   Q.1 6 J d x Q. 17 j 0 1 + x 0 sm(f +xj ^ J0 dx 2-n , dx 2+sin2x 2ti / \ ' 7T XN Q .1 8 J e x  cosf  — + — dx Q 1 9 f  2X7+3X6-10X5-7X3-1 2X2+X+1 V2 X2+ 2 dx v4 2/

Q.20 If for  non-zero x, a f(x) + bf —j = f — I - 5; where a ^ b then evaluate j  f(x) dx. vx

 ji/4

Q.21 J  c o s x-s m xd x Q.22 f   ( a X + b ) s £ C X t a n X  dx (a,b>0)

0 10 +sin 2x v J0 4 + tan x V' 7

(14)
(15)

Q.23 Evaluate: f ( 2 x + 3 ) f x d x . I (1 + cos x)

3/2

 p+ qn

Q.24 J |x. sinTtxl dx

Q.25 Show that J | cos x| dx = 2q + sinp where q s N  & -— < p <—

o 2 2

"5 2/3

Q.26 Show that the sum ofthe two integrals J e(x+5^dx+3 J Q9(x-2/3f dx is zerQ

it/4 Q.27

I

smx+cosx "o c os2x+sin4x 1 + x x3 1/3 71/2 dx Q.28 J * q <am V4.h rr\c yr 2— 72sin x — dx (a > 0, b > 0)v ' ' 0 n/2  _ f . I -t- X X. Q.30

j

a sin x+b cos x Vl+sinx+ .^1-sinx tan" ^/l+sm x - ,/l-sin x dx x . d x  p « .1.UA Q.31 (a) J Vto^dx ; (b) J // 2 2v,2 H ^ Vlx -a Ab ) 2 1

Q.3 2 j | x - t ! .cos7it dt where 'x' is any real number o Q.34 Provethat J = J - J * (n> 1) 0 1 + x 0 ( l- xn) X X Q.35 Showthat Je"-e"z i dz = ex^4f e ' ^4 dz o o Q . 3 7 ( a ) | l ^ , J» - , (b) f  d x 2a Q.33 j x sin-1 1 2 a - x 2 V a dx Q.36

J

r x

2 sin 2x,sin (y.cos x )

2 x - 7 t dx o l+x'Vx+x^x3 ' 0 1 + x 2 ' ^ OO 1 1 Q.38 Showthat f — — =2 o x + 2 x c o s 9 + 1 n d x 0 x2  + 2xcos9 + 1 sinB if 0 s (0,ic) 9 - 2 7i . sin 9 if 0 g ? dx 271 (a+b)

Q.39 Prove t h a t j (x2+ax+a2) (x2+bx+b V V^ab (a2+ab+b2) '

Q.40

j

x 2 (sin2x-cos2x) (1+sin 2x)cos2 x dx X , s, X r  u Q.41 Prove that J f f (t) dt n J VO J Q.42 J d x o (5 + 4 cos x)2 16 du= J f(u).(x-u)du. o Q.43 Evaluate J /n(Vl-x + Vl + x)dx 16 27t . 2 Q.44 (a) j t a n " 1 d x , (b) Evaluate J d0 a > b > 0

(ilZ?a«sa/   Classes  Definite & Indefinite Integration  [18]

(16)
(17)

 A

Q.45 Let  f(x) = - j /n cos y dy then prove that  f(x) = 2f

v4 2, - 2 f 71 X 4 _ 2 -x/n2. J t / 2 Hence evaluate J s e c t dt ~ . ^ , r x. lnx , , r a x. dx Q.46 Showthat J f ( - + - ) . dx = ln a. Jf (- +- ). x a x x a x

Q. 47 Evaluate the definite integral, j

1-(2x332 +x99 8 +4x1668-sinx69 1) -l 1 + x666 dx Q.48 Prove that ( a ) } V ( x - a ) ( P - x )

IM

 p (c)5 d x { xA/ ( x - a ) ( ) 3 - x ) V ^ P  p x.dx Q.49 If f(x) = 4 cos x 1 1

(cosx-1)2 (cosx + 1)2  (cosx-1)2

(cosx + 1)2 (cosx + 1)2 cos2x

1

/ n t a n- 1x - 1 ,

, find Jf( x) dx

Q.50 Evaluate:

Je

/ntan_ x-sin _1(cosx)dx.

o

 EXERCISE-III

Q.l If the derivative of f(x) wrtx is — - then show that f(x)is a periodic function.

f ( x )

Q.2 Find the range of the function,  f(x)= f  Sm X —7 .

1 —   2t cosx + t

Q.3 A function  f is defined in [-1,1] as f (x) =  2 x sin —   - cos — ; x ^ 0 ; f(0) = 0 ;

X X

f (I/71) — 0 .  Discuss the continuity and derivability of f at x=0. - 1 if - 2 < x < 0

Q.4 Let f(x) = [ I and g(x) = J f(t) dt. Define g (x) as a function of x and test the

x -* 1 if 0 < x < 2 _2

continuity and differentiability of g(x) in (-2,2).

Q.5 Prove the inequalities :

(a) 0 < J 0 2s x7dx_ 1 /3 8

M l

(b) 2 e~ 1/4 < } ex2"x dx < 2e2.

(c) a< f — < b then find a & b. (d) ^ < J

i 10+3cosx — 2 0

dx

2 + x2 " 6

Q.6 Determine a positive integer n<5, such that J ex(x- l)n dx = 16 - 6e.

(18)
(19)

Q.7  Using calculus

(a) If  | x | < 1 then find the sum of the series _ L + 2 x + 4 x 3 + 8 x ? + QO .

1 + X 1 + X2 1 + x4 1+ x8

/UN 1,1 I / ! .U * l - 2 x 2 x - 4x3 4x3- 8 x7 1 + 2X

(b) If |x| <1 provethat - + r  r  + r + .00 = - .

1 - x + x 1 — x + x 1 - x + x l +x + x2

x 1 x l x l x

(c) Prove the identity f (x) = tanx + - tan + t a n^ j + + 77 tan = — 7 cot ^77 - 2cot 2x

Q.8 If   (j)(x) = cos x - J (x -1)  cj)(t) dt. Thenfindthe value of   <|>" (x) + cj)(x).

2 a 0 " dx X  jlntdt Q.10 If y = x1 , find 7^- at x = e. dx 1 x d2

Q.9 If  y = - f f  (t) • sin a(x - 1) dt then prove that —^ + a2y =/(x).

9 * A^t*

1

Q. 11 If  f(x) = x + j [xy2+x2y] f(y) dy where x and y are independent variable. Find f(x).

dx

Q. 12 If f (9) = —w

de  I -~ COS0 co sx . Show that f ' (9) . sin 9 + 2 f(9). cos 9 = ~

r f' fx")

Q. 13(a) Let g(x) = xc. e2x & let f(x) = J e2t. (312 + 1)1/2 dt . For a certain value of'c', the limit of — ^

0 g' (x)

as x ->• 00 isfiniteand non zero. Determine the value of'c' and the limit.

f t2 dt J JaTt

(b) Find the constants 'a' (a > 0) and 'b' such that, Lim  — = 1.:

x-»o b x - si nx

Q. 14 If f: R - > R is a continuous and differentiable function such that,

x O x 2 x

J

f (t) dt + f ' " (3) | dt -

j

(t3) dt - f '

(1) J

(t2) dt + f " (2)

J

(t) dt

-1 x 1 X 3

thenfindthe value of f ' (4).

Q. 15 Given that Un= {x(l - x)}n & n > 2 prove that - n (n - 1) Un _ 2- 2 n(2n - l)Un _  p

1

further  if Vn - J ex. Un dx, prove that when n > 2, Vn+ 2n(2n- l). Vn _ r  n(n- 1) Vn _ 2 = 0

0

J?nt  %£n2

.2

equation.

" 1 - x if 0 < x < l

Q.17 Let f(x)= 0 if l < x < 2 • Define the function F(x) = J f(t) dt and show that F is

(2-x)2 if 2 < x< 3 °

continuous in [0, 3] and differentiable in (0,3).

f Ait 71 2

Q. 16 If  J —2—2 = (x > 0) then show that there can be two integral values of 'x' satisfying this

X ~F~ T 4

0

(20)
(21)

Q.18 Let f  be an injective function such that f(x) f(y) +2 = f(x) + f(y) + ffay) for all non negative real x& y w ±th £' (0) - 0 & f'' (1) = 2 # f(0). Find f(x) & show that, 3 J f(x) dx - x (f(x) + 2) is a constant.

Q.19 Evaluate : (a) ^  A

1/n (b)  L i m 1+- 1+- 1 + - 1+ -l/n (c) Lim I n+1 n+2 1 + 2 + + —4n3n . . . . . b f  dx 1 1

(d) Using ab initio prove that J — = —  - —

Q.20 Prove that sinx + sin 3x + sin 5x + .... + sin ( 2k- 1) x: sin

 2 kx k e N and hence sinx 71/2  prove that, j £ H L ^d x =: i + - + _ + ^ + 1 1 1 + 1 sin x 3 5 7 . 2 k-l "J? • 2

Q.21 If Un= dx, then show that U,, U2, U3, , Un  constitute an AP .

q sin x

Hence or otherwise find the value of Un.

Q. 22 Solve the equation for y as a function of x, satisfying

 X X

x • J y (t) dt = (x +1) j t •• y(t) dt, where x > 0.

o o

1

Q.23 Prove that: (a) Iffl n = j xm. (1 - x)n dx =

m!n! ( b> Im ; I 1= j xm. ( l n x )ndx = (-l )n (m+n+1)! n! m, n s N. m, n s N. ^n+i o (m+1

Q. 24 Find a positive real valued continuously differentiable functions/on the real line such that for all x

 f

 X

!

( x ) = / ( ( / ( t t f + C / ' W ^ j d t + e2

Q.25 Let f(x) be a continuously differentiable function then prove that, J [t] f' (t) dt = [x], f(x) - V f (k)

i k=i

where [• ] denotes the greatest integer  function and x > 1.

Q.26 Let f be a function such that  | f(u) - f(v) I < | u - v | for all real u & v in an interval [a, b]. Then:

(i) Prove that f is continuous at each point of  [a, b].

(ii) Assume that f is integrable on [a, b]. Prove that,

7t f dx

Q.27 Establish the inequality : — < I 7 = = f

6 o V 4 - x - x

f f(x) dx - (b -a ) f(c) (b-a)

2

, where a < c < b

<

Q. 28 Show that for a continuously thrice differentiable function f(x) f (x) -f (0 ) = x f ( 0 ) + ® ^ - + i }f "' (t )( x- t)2dt

2 o

n / v I m 1

Q.29 Prove that £ ( " l )k = o k  k 1 — T = S ( " ^ ( i f ) ,VK/ k + m + 1

k = o \ k / k + n + 1

(22)
(23)

Q.30 Let / and g  be function that are differentiable for all real numbers x and that have the following  properties: (1) /' (x )= /( x) -g (x ) (ii) g'(x)=g(x)-/(x) (iii)  f ( 0 ) = 5 (iv) g(   0 ) = 1

(a) Prove that/(x) + g  (x) = 6 for all x.

(b) Find/(x) and g  (x).

 EXERCISE-IV

Q 1   Ftad S J s n , i f : S n = ^ + T ^ + 7 4 = + +  — = = = = .  [REE'97,6] V4n -1 y4n -4 V3 n'+2n-l X

Q.2 (a) If g (x) = Jc o s 4 t d t , then g (x + %) equals :

(A)g(x) + g(7C) (B) g(x)-g(7C) (C)g(x)g(7C> (D) [g(x)/g(7l)] (b) Limit i g _ ^ e q u a l s : r=l Vn2+r 2 (A )l + V5 (B) - 1 + VJ ( Q - 1 + V2 (D )l + V2 e" (c) The value of J ————— dx is I H esinx 4 ?

(d) Let — F(x) = , x > 0 . If f — dx = F (k) - F (1) then one ofthe possible

dx x ' x

values ofki s .

(e) Determine the value of J 2 x 0 + s i n x) d x [JEE '9 7, 2 + 2 + 2 + 2 + 5]

„ 1 + COS X

Q.3 (a) If ff(t) dt = x + f t f ( t ) dt , then the value of /( l) is

(A)° 1/ 2 (B) 0 (C) 1 (D) - 1 / 2

i f  Y  \ i

(b) Prove that f tan"1 dx = 2 f tan 1x dx . Hence or otherwise, evaluate the integral

i U-x+x2; i

i

Jtan _1(l-x+x2)dx [JEE'98,2 + 8]

Q 4 E r a l u a t e [ R E E ' 9 8 - 6 1

(24)
(25)

Q.5 (a) If for al real number  y, [y] is the greatest integer less than or equal to y, then the value of the 371/2

integral j [2 sinx] dx is:

(b) (A) - n (B) 0 3,1/4 rl Y f — — — is equal to : L 1+ cosx (A) 2 (B) - 2 (C) 2

(C)

(D) * 2 / N T R  x3+ 3x + 2 , (c) Integrate: J — dx (x2+l ) (x + 1) ii

(d) Integrate: J „cosx . -cos x

e +e -dx

71/6

Q.6\\ Evaluate the integral J V3 c o s 2 x

cosx

[JEE '99, 2 + 2 + 7 + 3 (out of200)]

[REE'99, 6]

Q.7 (a) The value of the integral j logex dx is:

(A) 3/2 (B) 5/2 (C) 3 (D) 5

 x 

r 1 ' 1

(b) Let g( x) = J f(t ) dt, where f is such that < f( t) < 1 for t £ (0, 1] and 0< f(t) <

-o 2 2

for t G  (1,2]. Then g(2)  satisfies the inequality:

( A ) - | < g ( 2 ) < I (B) 0 < g (2) < 2 ( C ) ^ < g ( 2 ) < | ( D ) 2 <g ( 2) < 4

(c) If f (x) = {

(A) 0

ecosx . sin x for |x| < 2

2 otherwise , (B) 1  j Then j f(x)dx : (C) 2 (D)3 x t> t

(d) For x > 0, let f (x) = j dt. Find the function f(x) + f (1/x) and show that,

f(e) + f( l/ e) = 1/2. Q.8 (a) Sn - — l~r= + 1 1+t + + [JEE 2000, 1 + 1 + 1 +5] n + Vn Find   L i m i t S_ f sin t r u

(b) Given d t = a , find the value of —  d t in terms of a .

0 1 + t 471 - 2 4 7C + 2 t

[ REE 2000, Mains, 3 + 3 out of 100]

471 sm n—> co n t 2x + 2 Q.9 Evaluate f sin 1 W 4 X2+ 8 X + 13 IT/: Q.10 (a) Evaluate } dx. it/2 9 51 cos x r xdx  — 5 r r ~d x. (b) Evaluate J :

0 cos3 x + sin3 x / 0 1 + cos a sinx

[REE2001, 3+ 5]

(26)
(27)

X

Q. 11 (a) Let  f(x) = j  ^ 2 - t2 dt Then the real roots ofthe equation x2- f ' (x) = 0are

(A)±l (B) ± - "" ( C ) ± - (D) 0 and 1

(h) Let T > 0 be afixedreal number. Suppose/ is a continuous function such that for all x e R

T  3+3T

/ ( x + T) = /( x) . If I = f /f x; dx then the value of J ' j W dx is

0 3

(B)21 (C) 3 I (D) 61

(A) | I

(c) The integral JI [x] + / n j j - ^ J dx equals

( A ) - - (B)0 (C)l (D) 2/n (d) For  any natural number m, evaluate J (x3m + x2m + xm) (2x2m +3xm + 6)m dx, wher ex> 0 [JEE 2002(Scr.), 3+3+3] [JEE 2002 (Mains),4] n/2 n/4

Q.12 If f is an even function then prove that J f (cos2x) cosx dx= V2 J f (sin2x) cosx dx

0 0

[JEE 2003,(Mains) 2 out of 60] l

Q-i3

(

a

)

f ^

d x = o ( A ) f  + 1 ( B ) f - . (C)7t (D)l 0 (b) If jx f( x) dx =- ^t5, t > 0 , t h e n f 5 r 4 \ v25y 2 ( A )7

(B)

( O - f 2

(c) If y(x) = f   c o s x c°s ® DQ ^en find at x = TC.

2J, i+sin2 Ve d x (d) Evaluate J -dx. -it/3 2- co s X + -TC Q.14 (a) If Jt2(f(t))dt =(1-sinx),then/ sinx (A) 1/3 (B) i/V3 vV3y is (C)3 (D)l [JEE 2004, (Scr.)] [JEE 2004 (Mains), 2] [JEE 2004 (Mains), 4] [JEE 2005 (Scr.)] (D)V3

(28)
(29)

(b) J (x3+ 3x2 + 3x + 3 + (x +1) cos(x + l))dx is equal to

- 2

(A )- 4 (B)0 (C)4

 f

(c) Evaluate: fe|cos^ 2sin

0 V -cosx v2 ,+3 cos x' N  —  cosx v2 j j sin x dx. [JEE 2005 (Scr.)] (D)6 [JEE 2005, Mains,2]

Q15

  ^W5?^T

dXisequalt0

( A ) V 2 x4 - 2 x 2+ l + c

(B)

(C) x - 2 x z + l + C V2X 4 -2X2+1 2x2 + C [JEE 2006,3] Comprehension

^ ^

Q.16 Suppose we define the definite integral using the following formula (f(x)dx = (f (a )+ f( b) ), fo r

more accurate result for c e (a, b) F(c) = ^ (f (a) + f (c)) + — - (f (b) + f (c)). When c = p p ,

2 2 ^  b i_  b - a Jf (x)dx = ^ ( f ( a ) + f ( b ) + 2f (c>) a i t / 2

(a) | sin xdx is equal to

o

(A

) | ( l + V2) + ( C ) ^71

(D)

71

4V2  jf ( x ) d x _ i _ i (f ( t ) + f (a))

(b) If/(x ) is a polynomial and if Lim—

t->a 0 for all

a

 then the degree of 

 f 

 (x) can

atmost be

(A)l  (B)2  (C)3  (D)4

(c) If /"(x) < 0, V x s (a, b) and c is a point such that a < c < b, and (c,/ (c) ) is the point lying on the curve for which F(c) is maximum, then/'(c) is equal to

(A) f(b)-f(a)  b - a 2(f(b)-f(a))  b - a (C) 2f(b)~f(a) 2 b - a 5050} ( I - x5 ° R dx

Q. 17 Find the value of

J ( I- x5° R <

(D)0

[JEE 2006, 5 marks each]

[JEE 2006,6] dx

(30)
(31)

 ANSWER KEY

 EXERCISE-I

Q.l In l + Vl + 3cos 2 20 cos 20 + C ^ _ x + 1 Q.2 -1 x j o x 3

Q.3 - /n(cosx + sinx) + - + - (sin 2x + cos 2x) + c Q.4 - tan-1 x - ——  7 - — In

2 o 0 Q.5 2 tan-1  (x+Vx2+2x-l) + c  —  I all X - / . \ - — 8 4(x - 1 ) 16  f x - 1iN VX + V + c Q.6 I* .e/ - - + c

Q.7 (c) - (sin 20 ) In cos9 + sinG ] 1 cos9 - sin9j 2 1 - - /n( sec2 0) + c Q.8  - In tanx tanx+2 + c f / x + tan V Q.ll J (x+V^")'

Q.12 cos a. arc cos

-1 a tanx  JJ + c Q.IO + w hent = x + V ^ (x+VX2+ 2 1/2 f cosx\ vcosay

- sin a 1 ( • In sinx + Jsin ^x-sin 2 2""^ , +C ^ Q.13 —^ 3(l+4tan x)tt t1

Q.14  - In tan- + - sec, 1 2, x - +ta n - + cx

Q.16 (a + x) arc tan - ^ax + c

Q.18 xln (lnx) - ——  + c lnx 8(tan x) Q.15  V^Jl^x-2-Jl^ + arc cos Vx+c (x2+l \l + c Q.17 Q.19 In /x2 +1 9x xe" vl+xex j 2-31nfl+-^ l+xex V x + c Q . 2 0- / n ( l - x4) + c Q.21 6 t 4 t2 1  — - —  +1 + ~/n( l + t  z  ) - ta n-11 4 2 2

Q. 2 2 . +2tan"1 Jcosf   -In 1 + -yjcOSj

ycosf  v 1  - ycosi + C where t = x1/6 + c Q.23 -v x - l y + C  Q24. sin" 1  —sec — v.2 2 j ~ 1 , (4+3sin x+3cos x) Q.25 —In- —+c 24 (4-3sin x-3cos x) Q 27 1 VT+sin x-cos x

Q . 2 « 2 sin x - cos x —p=ln tan

V2

F

X 71 ^

2V3 V3 -sm x+cos x+ arc tan (sin x+cos x)+c  Q.28 -^n(secx) - ^ ^n(sec2x) +^n(sec3x) + c

Q. 29- 1  In

V sina Q.31  2x-3arctan

cotx+cota+^/cot2x+2cotacotx-l + c  Q.30 x sin x + co sx— + c x c o s x - s m x

' x ^

tan—+1

v 2 ,

+c Q.32 Vcos2x

smx - x - cotx . In (e (cosx + Vcos2x)j + c

(ilZ?a«sa/   Classes  Definite & Indefinite Integration

[1

8]

7

(32)
(33)

1 „ 1 t2 -  -Jit  + 1 1 . - , —

Q.33 /n(l +1) - - /n(l +1*) + ^ /n t2 + + 1 - j t a n *  + c w h e r e 1 = Vc o t x

 _ 1, X 1 2X

Q.34 —lntan tan —+c

2 2 4 2 Q.35 c - ( x2- l )2

Q.36 c - ecos x(x + cosec x) Q.37 sin-1 ax +b

cx

J +k Q.38 e x J ^ + c Q.39  20>> +c  _ lnx Q.40 arcsecx—, +c

i

I 2— Q.41 In , ' + V3tan Vu4+u2 + l /r l+2u

V3tr~

1

9^7x-10-x

2 V3 + c  where u = 3V

 1+x

Q.42 -

tan t + —

1 . f  V51 - 1r=

 

~7=

2V5

vv5t + 1

- |sin 1 x  - ^/l-x2 j  + c where t = h^-

1+x

x

Q.43 tan

.^2 sin 2x

v

sinx + cosx

y + c Q.44 4/nx+-+6tan-7 1( x) + 6xj +C X I T X 2 x  J 2 - X - X2 V 2 „ f 4 x + 2 V 2 J 2 x -Q.45 —i=arctan—p —+c Q.46 + — V3 V^+i) x 4

x

x

.

(2x+l

sin

^ 3

+ c - 2 x ^ Q . 4 7 — - J — - + c a - p y x- a 1 4 - - 2 15 , Q.48 n x x 2 + — 

In

4x

2

y l + x

8 V T + x - i 7 1 + X + 1 + c Q.49 V2 nl V2-t - —/n2 ' 1 - 0

vl + ty where t = cos9 and 9 = cosec' (cotx)

Q.50 cosec—a 2 tan

-1

\ v , 2 x y a cosec— 2/

 EXERCISE-II

2 ^ Q.l — Q.2 /n2 Q.3 6 - 2e Q.4 - - 1 Q.5 Q.6 £ In2 ft 2 64 8 Q.7 1 - sec(l) Q.8 — Q . 9 2 V2 + | (3 V3 - 2V2) Q.12 2n + l f 22 ^ 7t 17 J 7t Q . 1 3 - ( l - l n 4 ) Q.14 4V2-4/n(V2 + l) Q.15 ^ Q.16 Q . 1 7 ^ = Q . 1 8 - ^ ( e 2 * + l )  _ 71 16V2 _ (aln2-5a+^) Q.22 (a7t

+ 2b

)7t 3V3 Q.23 7t(7t + 3) Q.24 Q.21 i

3

371+1

7t2 V2 l"

arc tan arc ta

n-3

3

Q 27

(34)
(35)

Q.28 71 2a(a+b) 57t 3 Q.29 Q.30 ^ L Q.31 (a) ^=[rc+21n(V2-l)] (b) 16

12

2

2

2

2

Q.32—5- cos7ixf orO<x < 1; for x> 1 & — 2 f o r x ^ ° Q -3 3 —

71 71 71 4 Q . 3 6 -% Q. 37( a) f ( b ) ^ Q.40 ^ - 7 /n2 Q.42 ^ 16 4 27 Q.43 - In 2 +2 1 167t _  rr   271 Q.44 (a) — 2V3 (b) i - J ^ b2 Q.45 - / n 2Tt Q.47 71+ 4 666 32 Q.49 -2ti - — Q.50  — ( l + / n 2 ) + -8 4 2  EXERCISE-III , 71 TC ,

Q.2 - - , - (• Q.3 cont. & der. at x = 0

Q.4 g(x) is cont. in ( - 2, 2); g(x) is der. at x = 1  & not der. at x = 0 . Note that; -( x + 2) for - 2 < x < 0 g(x) = 2 2TI 27T -2 + x - ^ - for 0 <x< 1 Q.5 a= — & b = — Q. 6n = 3 ^ - - x - 1 f o r   1 <x< 2 Q.7 (a) -—- Q.8 - cos x Q . l O l + e Q. ll f(x) = x + 1—x 119 119  R

Q.13 (a) c = 1 and Limit  w i l l b e ( b)a = 4a nd b =1 Q.14 10

if 0<x<l 2 x2 X - T Q.16 x = 2 or 4 Q.17 F(x)= \ if l<x<2 k if 2<x<3 M . 3 1 2 Q.18 f(x) = l + x2 Q.19 (a) - (b) 2e(1/ 2)("-4) (c) 3 - / n 4 Q.21 Un= ^ e 2 Q.22 y = ^ e"1/x Q.24 f  (X) = ex +1  Q.30 f (x) = 3 + 2e2x; g (x) = 3 - 2e2x

(36)

References

Related documents

If the fibrous outer ring tears, disc tissue can protrude into the spinal canal (slipped disc or prolapse).. This leads to compression of the passing nerve endings, which

During his evidence he told the court that Mr Knight did not inform him that he had been receiving chiropractic treatment since 2005, that he had a history of neck pain for 15

everyone else who were not members of the First or Second Estates. There was an enormous logistical problem with the way in which the estates were divided for example, the First

Further, by showing that v τ is a modular unit over Z we give a new proof of the fact that the singular values of v τ are units at all imaginary quadratic arguments and obtain

Similarly, IHRICON organized an interaction with HEAD coalition members in Lalitpur district on July 24 to discuss issues related to local governments’ response to COVID-19,

A consequence of this perspective of woman directors being appointed as part of the symbolic management of the independence of the board is that, when these directors lose

more than four additional runs were required, they were needed for the 2 7-3 design, which is intuitive as this design has one more factor than the 2 6-2 design

11 In addition to the Provisional Regulations on Domain Name Registration, China has draft Regulations on Domain Name Registration Dispute Resolution (“Draft Regulations”).