• No results found

SHORT CIRCUIT FORCE FOR EQUIPMENT 

N/A
N/A
Protected

Academic year: 2021

Share "SHORT CIRCUIT FORCE FOR EQUIPMENT "

Copied!
17
0
0

Loading.... (view fulltext now)

Full text

(1)

ABB LIMITED 

SHORT CIRCUIT FORCE FOR EQUIPMENT       

INTERCONNECTION 

Sheet 1 of 17 

We reserve all rights in this document and in the information therein. Reproduction, use or disclosure to third parties without express authority is strictly forbidden. © ABB eBoP.

SHORT CIRCUIT FORCE FOR  

EQUIPMENT INTERCONNECTION 

OWNER 

M/S SHREE CEMENT LTD. 

OWNER’S ENGINEER 

Evonik Energy Services (I) Pvt. Ltd., 

Noida 

EPC CONTRACTOR 

Cethar Vessels Limited,  

Tiruchirapalli 

eBOP CONTRACTOR 

ABB Limited, Faridabad 

R0 

 

21.04.2010 

 

 

 

RK/RM 

 

Rev 

No. 

Date 

Prepared 

by 

Reviewed 

by 

Approved 

by 

Remarks 

 

(2)

ABB LIMITED 

SHORT CIRCUIT FORCE FOR EQUIPMENT       

INTERCONNECTION 

Sheet 2 of 17 

REVISION STATUS SHEET 

 

 

 

REV. NO. 

 

DATE 

DESCRIPTION 

 

 

R0

 

 

21.04.2010 

FOR APPROVAL 

 

 

 

 

(3)

I System Data:

1.1 Nominal System voltage in kV

=

400

1.2 System short circuit current in A

(I"k3) =

40000

1.3 Factor for peak short circuit current

(κ) =

1.81

1.4 Phase spacing in m

(a m) =

7

1.5 System frequency in Hz

(f)

=

50

1.6 Auto Reclosing Feature

YES

II Conductor data:

2 1 Busbar selected

=

4" IPS (Schedule 80) Al

Short Circuit Force Calculation

(For Equipments)

2.1 Busbar selected

2.2 Outer diameter

(Do)

=

114.3

mm

2.3 Inner Diameter

(Di)

=

97.18

mm

2.4 Area of Cross section

(A)

=

2844

sq.mm

2.5 Moment of inertia

(J)

=

4.00E-06

m^4

2.6 Weight

(m')

=

7.678

kg/m

2.7 Young's Modulus

(E)

=

6.57E+10 N/ sq.m

III Reference

3.1 IEC 865 -1(1993): short circuit current calculation effects

4 IPS (Schedule 80) Al

(4)

IV

Legend:

Symbol

Unit

4.1 Initial symmetrical short circuit current (r.m.s)

I"k3

Amps

4.2 Peak short circuit current

Ip3

Amps

4.3 Effective distance between main conductors

am

m

4.4 Span between supports

l

m

4.5 Outer Diameter of the conductor

Do

m

4.6 Absolute permeability of vacuum

µo

4.7 Ratio of dynamic and static force on support (As per

equation in page no. 107 of IEC 865 -1(1993))

V

F

4.8 Ratio of stress for a main conductor with or with out three

phase auto reclosing (As per equation in page no. 109 of

IEC 865 -1(1993))

V

r

4.9 Factor for force on support (from table 3 of pg. 67 of IEC

865-1(1993))

a

4.10 Factor for relevant natural frequency estimation (From

table 3 of pg. 67 of IEC 865-1, 1993)

γ

4.11 Natural frequency of the tube

fc

Hz

4.12 Electromagnetic force

F m

kg

4.13 Total static weight of bus

M

kg

4.14 Reaction due to electrodynamic force

Fd

kg

4.15 Youngs Modulus of conductor

E

N/m²

(5)

V

Formulae Used

5.1 Peak value of short circuit current

(Ip3)

= I"k3 x k

x Sqr(2)

Amps

5.2

Electro magnetic force between

conductors

(Fm)

= µ x Sqr(3) x ( Ip3) ² x

l

kg

2 x 2 p

x 9.81 x am

5.3 Electro dynamic force on busbar

(Fd)

= Vf x Vr x a x Fm

kg

5.4 Natural Frequency of the tube

(fc)

=

γ x Sqr ( E J /m') Hz

l ²

5.5 Calculation of V

F

As per IEC 865-I (Page-107)

fc/f

V

F

<0.04

0.232+3.52*EXP(-1.45*k)+0.166*LOG10(fc/f)

0.04...0.8

MAX(0.839+3.52*EXP(-1.45*k)+0.6*LOG10(fc/f),2.38+6*LOG10(fc/f))

0.8...1.2

1.8

1.2...1.6

1.23+7.2*LOG10(fc/f)

1.6...2.4

2.7

2.4...2.74

8.59-15.5*LOG10(fc/f)

2.74...3.0

8.59-15.5*LOG10(fc/f)

3.0...6.0

1.5-0.646*LOG(fc/f)

>6

1

5.6 Calculation of V

r

fc/f

V

r

<=0.05

1.8

>0.05 and <1

1-0.615Log(fc/f)

>=1

1

(6)

VI Support Arrangement

Refer Figure 1

6.1 Equipment Dimension (Terminal to Terminal) in m 4.8 m

Left Right

6.2 Support Span in Metre (L) = 9 10.5 6.3 Equipment Dimension (Terminal to Terminal) in m 4.821 0 6.4 Support type for Equipment FIXED SIMPLE 6.5 Support type for other equipment SIMPLE FIXED

VII Calculation

7.1 Peak short circuit current Ip3 = 102389 A

Left Right 7.2 Factor a at Support A 0.625 0.375 7.3 Factor a at Support B 0.375 0.625 7.4 Factor b 0.73 0.73 7.5 Factor γ 2.45 2.45 7.6 Effective Distance (mts) l = 4.19 8.1 7.7 Electromagnetic forces between conductors Fm = 110.79 214.18 7.8 Natural frequency of the Tube (Hz) fc = 25.824 6.9099

7.9 Ratio fc / f = 0.5165 0.1382

7.10 Ratio of dynamic & Static force on supports VF = 1.0128 0.6692 7.11 Ratio of stress for main conductor with &

without 3 phase Auto reclosing VR = 1.1765 1.5286

7.12 Factor a 0.625 0.375

7.13 Dynamic force (Bending Force) (kg) Fd = 82.505 82.164 7.14 Total Dynamic force due to Left & Right spans = 164.67 kg

TYPICAL SHORT CIRCUIT FORCE CALCULATION FOR 400kV

ISOLATOR

(7)
(8)

VI Support Arrangement Refer Figure 2

6.1 Equipment Dimension (Terminal to Terminal) in m 4.821 m Left Right

6.2 Support Span in Metre (L) = 12 9

6.3 Equipment Dimension (Terminal to Terminal) in m 0.55 4.8

6.4 Support type for Equipment SIMPLE SIMPLE

6.5 Support type for other equipment FIXED FIXED

VII Calculation

7.1 Peak short circuit current Ip3 = 102389 A

Left Right 7.2 Factor a at Support A 0.375 0.375 7.3 Factor a at Support B 0.625 0.625 7.4 Factor b 0.73 0.73 7.5 Factor γ 2.45 2.45 7.6 Effective Distance (mts) l = 9.315 4.189

7.7 Electromagnetic forces between conductors Fm = 246.31 110.77 7.8 Natural frequency of the Tube (Hz) fc = 5.2249 25.836

7.9 Ratio fc / f = 0.1045 0.5167

7.10 Ratio of dynamic & Static force on supports VF= 0.5964 1.0129 7.11 Ratio of stress for main conductor with & without

3 phase Auto reclosing VR= 1.6032 1.1763

7.12 Factor a 0.375 0.375

7.13 Dynamic force (Bending Force) Fd = 88.317 49.492

7.14 Total Dynamic force due to Left & Right spans = 137.81 kg

TYPICAL SHORT CIRCUIT FORCE CALCULATION FOR 400kV

CIRCUIT BREAKER

(9)
(10)

VI Support Arrangement Refer Figure 3

6.1 Equipment Dimension (Terminal to Terminal) in m 0.55 m Left Right

6.2 Support Span in Metre (L) = 12 5.5

6.3 Equipment Dimension (Terminal to Terminal) in m 4.82 4.8

6.4 Support type for Equipment FIXED SIMPLE

6.5 Support type for other equipment SIMPLE FIXED

VII Calculation

7.1 Peak short circuit current Ip3 = 102389 A

Left Right 7.2 Factor a at Support A 0.625 0.375 7.3 Factor a at Support B 0.375 0.625 7.4 Factor b 0.73 0.73 7.5 Factor γ 2.45 2.45 7.6 Effective Distance (mts) l = 9.318 2.827

7.7 Electromagnetic forces between conductors Fm = 246.39 74.7526 7.8 Natural frequency of the Tube (Hz) fc = 5.2215 56.7273

7.9 Ratio fc / f = 0.1044 1.13455

7.10 Ratio of dynamic & Static force on supports VF= 0.5962 1.8 7.11 Ratio of stress for main conductor with & without

3 phase Auto reclosing VR= 1.6034 1

7.12 Factor a 0.625 0.375

7.13 Dynamic force (Bending Force) Fd = 147.22 50.458

7.14 Total Dynamic force due to Left & Right spans = 197.67 kg

TYPICAL SHORT CIRCUIT FORCE CALCULATION FOR 400kV

CURRENT TRANSFORMER

(11)
(12)

VI Support Arrangement Refer Figure 4

6.1 Equipment Dimension (Terminal to Terminal) in m 0 m Left Right

6.2 Support Span in Metre (L) = 10.5 0

6.3 Equipment Dimension (Terminal to Terminal) in m 4.8 0

6.4 Support type for Equipment FIXED

6.5 Support type for other equipment SIMPLE

VII Calculation

7.1 Peak short circuit current Ip3 = 102389 A

Left Right 7.2 Factor a at Support A 0.625 0 7.3 Factor a at Support B 0.375 0 7.4 Factor b 0.73 0 7.5 Factor γ 2.45 0 7.6 Effective Distance (mts) l = 8.1 0

7.7 Electromagnetic forces between conductors Fm = 214.18 0 7.8 Natural frequency of the Tube (Hz) fc = 6.9099 0

7.9 Ratio fc / f = 0.1382 0

7.10 Ratio of dynamic & Static force on supports VF= 0.6692 0 7.11 Ratio of stress for main conductor with & without

3 phase Auto reclosing VR=

1.529

7.12 Factor a 0.625 0

7.13 Dynamic force (Bending Force) Fd = 136.94 0

7.14 Total Dynamic force due to Left span = 136.94 kg

TYPICAL SHORT CIRCUIT FORCE CALCULATION FOR 400kV

BUS POST INSULATOR

(13)
(14)

Total Fd (Kg) Left Right Left Right Left Right Left Right Left Right Left Right Left Right Left Right Left Right FIXED SIMPLE SIMPLE FIXED 9 10.5 4.19 8.1 110.8 214.18 25.8 6.91 1.0128 0.6692 1.176 1.529 82.505 82.1638 SIMPLE SIMPLE FIXED FIXED 12 9 9.315 4.189 246.3 110.77 5.22 25.84 0.5964 1.0129 1.603 1.176 88.317 49.4919 FIXED SIMPLE SIMPLE FIXED 12 5.5 9.318 2.827 246.4 74.753 5.22 56.73 0.5962 1.8 1.603 1 147.22 50.458 FIXED 0 SIMPLE 0 10.5 0 8.1 0 214.2 0 6.91 0 0.6692 0 1.529 0 136.94 0

TABLE 1. Bending Force on 400kV Equipments

Equipment Support Other Equipment Support Fd (Kg) Distance between Eqpts(m) Effective Length(m) Fm (Kg) fc (Hz) Vr VF

(15)

1. FORMULAE USED

Electro magnetic force on flexible main conductors in 3 Phase System is given by

(F') = Mo * 0.75 * (ik3)² /(2 * pi * am)

(As per IEC-865-1 Page No. 39)

2. LEGEND

F' = Electro magnetic force in N/m

ik3 = Initial symmetrical short circuit current in amps

Mo = Absolute permeability of vacuum , 4 (pi) x 10^ (-7) in H/m

am = Effective distance between main conductor (phase spacing) in metres

3. SYSTEM DATA

System short circuit current (ik3) in Amps

=

40000

(i.e. 40 kA)

Phase spacing (am) in metres

=

7

4. CALCULATION

Refer Figure No.5

Electromagnetic force on conductor (TWIN Moose ACSR)

(Short circuit force) (F')

=

34.29 N/m

=

3.5 Kg/m

Force on CVT (15.13m span)

=

52.96 Kg

Force on LA (14.75m span)

=

51.63 Kg

CALCULATION OF SHORT CIRCUIT FORCE FOR TWIN MOOSE ACSR IN

400kV SYSTEM

(16)
(17)

Summary :

PART A

Calculation of Short Circuit force on Equipments with 4'' IPS Al. Tube

1.

Force for 400kV

=

164.67 kg

2.

Force for 400kV

=

137.81 kg

3.

Current Transformer

Force for 400kV

=

197.67 kg

4.

Bus Post Insulator

Force for 400kV

=

136.94 kg

PART B

Calculation of Short Circuit force on Equipments with TWIN MOOSE ACSR

1.

CVT

Force for 400kV

=

52.96 kg

1.

LA

Force for 400kV

=

51.63 kg

Isolator

Circuit Breaker

References

Related documents

If the short circuit of the IGBT occurs across the terminals of the drive, the low inductance of the short circuit results in high di/dt of the short circuit current and the

Although several methods are used to value a dental practice, the approaches best suited to—and typically used in—the industry are income-based and include a gross revenue

21      There are very few studies of the effects of interlocks on 

VRR provides that a reservist or member of the National Guard shall upon request be granted a leave of absence by such person's employer to perform active duty training or

categories above then the admissions committee will offer places first to children living nearest to the school defined ‘as the crow flies’ from the child’s permanent place

In the event that a merger results from the aggregation over companies with high mark-ups, irrespective of their overall share in the market, our profit share indicator of market

communities in the eastern Baltic region (Latvia) and in the South Ural (Russian Federation). We selected extremely rich fen and calcareous fen vegetation where Sch. ferrugineus

If the book financial statements are not recorded under the percentage-of-completion method of accounting for GAAP purposes, then the deferred construction costs are reclassified