ISSN 2319-8133 (Online)
(An International Research Journal), www.compmath-journal.org
The Sequence Space w F p ( , ) Defined By Means of The Modulus Function Sequences Among the Spaces
with Semi-Norms
1Kamil Akbayır and Tunay Bilgin
Department of Education of Mathematics and Natural Sciences, Faculty of Education, University of Yüzüncü Yıl, 65080, Van, TURKEY.
email:[email protected], [email protected].
DOI : http://dx.doi.org/10.29055/jcms/727 (Received on: January 7, 2018)
ABSTRACT
By means of the modulus function sequence F ( f
k) we have generalized the sequence space w f p ( , ) studied by Başarır
5and the sequence space
( , , , )
w A V f studied by Bilgin
9to build the sequence space w F p ( , ) and given some of its properties.
Keywords: Modulus function, Sequence spaces, Summability, Paranormed spaces.
1. INTRODUCTION
The idea of modulus function suggested by Nakano
25gained a new dimension to the studies of the sequence space. A function
f :
0,
0, satisfying the following properties is called a modulus function (Nakano
25):
i) f(x) 0
x 0,
ii) For every
x, y 0one has
f(x
y)
f(x)
f(y), iii) f is incresaing,
iv) f is continuous at 0 from right.
A modulus function f might be bounded or unbounded. From (ii)
f(x)
f(y)
f(x
y)and (iv) we see that f is everywhere continuous on
[0,).
Maddox
24defined the class of strong Cesàro summable sequences with respect to modulus, a generalization of the definition of the strong Cesàro summability, as w f . Connor
121 This work consists of a part of the Ph.D thesis of Kamil AKBAYIR titled “Modulus Fonksiyon Dizileri Yardımıyla Tanımlanmış Bazı Dizi Uzayları.”
generalized the definition of (Maddox
24) to w A f , summability method as any non- negative regular matrix instead of the Cesàro matrix.
We need to point out that so many spaces have been constructed by means of the modulus function (Banerji and Galiz
2; Soomer
28; Esi
14; Kolk
19,20,21,22,23; Esi and Et
13; Pehlivan and Fisher
26; Gupta and Bhola
16; Bilgin
7,8,10; Raj and Sharma
27; Karakaya and Şimşek
18; Bhardwaj and Bala
6; Işık
17and the others).
In this work by means of the modulus function sequence F ( f
k)
we will generalize the sequence space w f p ( , ) studied by Başarır
5and the sequence space w A V ( , , , ) f studied by Bilgin
9to build the sequence space w F p ( , ) and give some of its properties.
Let F f
kbe a modulus function sequence, and for every k p
k0 ,
sup
kk
H p
and C
,
k
k
b
a . The following conditions and inequalities will be used in our future discussion:
(M1)
sup
k( ) ,
k
f t
for t 0 , (M2) lim
0 k( ) 0,
t
f t
(uniform for k 1 ) (Kolk
19).
(E1) a
k b
k pk C a
k pk b
k pk , C max(1, 2
H1) t 0 (E2)
pk max 1,
H (Maddox
24)
2. MAIN RESULT
2.1. The Sequence Space w F p ( , ) and Some of Its Properties
Given a sequence x ( ) x
kand a modulus function sequence F f
kwe can define the following spaces:
1 0
1
1
1
( , ) ( ) : lim 0
( , ) ( ) : sup
k
k
n p
k k k
n k
n p
k k k
n k
w F p x x s n f x
w F p x x s n f x
Here by choosing the sequences F f
kand ( p
k) specifically one can obtain different spaces as special cases.
1
1
( , ) ( ) : lim
k0,
n p
k k k
n k
w F p x x s n
f x l for some l
Definition 2.1.1: Let x ( ) x
kbe a sequence for ( k IN ) . If for 0 we have
lim
1:
k0
n
n
k n x s
we say that the sequence x -statistically converges to the number s and we use the notation
S to express this situation (Başarır
5).
If we choose p
k p for k we write w f p , w
p f , . If we choose f x ( ) x we obtain w
p f , w
p defined by Başarır
3.
We will first give the linearity of the spaces w F p ( , ) and w F p
0( , ) .
Theorem 2.1.2: w F p ( , ) and w F p
0( , ) are linear spaces on C .
Proof: Here we will only show that w F p
0( , ) is linear, the linearity of w F p ( , ) can be seen by the same way. It is sufficient to show that x y w F p
0 , for
,
0,
x y w F p and for the scalars , C. From the inequality (E1) and definition of the modulus function we have
fk x
k y
k pk fk x
k y
k
pk
x
k y
k
pk
f
k x
k f
k y
k
pk C f k x
k
pk f
k y
k
pk
C T
Hf
k x
k
pk K
Hf
k y
k
pk CT
Hf
k x
k
pk CK f
H k y
k
pkwhere T and K are positive integers such that T 1 and K 1 . Thus we have
1
1
lim
kn p
k k k
n k
n
f x y
1
1
lim
kn p
H
k k
n k
CT n
f x
1
1
lim
kn p
H
k k
n k
CK n
f y
and hence we see that x y w F p
0 ,
. Let us now show that w F p
0 ,
is a para-normed linear topological space:
Theorem 2.1.3: The space w F p
0 ,
is a linear topological space para-normed by g
defined by
1 1
1
( ) sup
kn M
p
k k
n k
g x n
f x
Proof: It is clear that g ( ) 0, g x ( ) g ( x ) . Let x y , w F p
0 ,
. Since
k
1 p M
and 1
M , we see from the inequality (E2) and the definition of the modulus function that for each n we have
1 1
1
k
n p M
k k k
k
n
f x y
1 1
1
k
n p M
k k k k
k
n
f x f y
1 1
1
k
n M
p
k k
k
n
f x
1 1
1
k
n M
p
k k
k
n
f y
.
Now let C. When K 1 , from the definition of the modulus function we have
( )
g x
1 1
1
sup
kn M
p
k k
n k
n
f x
K
H Mg x ( ) . Now let 0 for any constant x with g x ( ) 0 . For 1
from Definition 2.1.1 we have
1
1
k
n p
k k
k
n
f x
, for n N ( ) (2.1) On the other hand, since f
kis continuous for 1 n N if we choose small enough we get
1
1
k
n p
k k
k
n
f x
. (2.2) When we consider (2.1) and (2.2) together when 0 we get g ( x ) 0 . Thus our proof is complete.
We will lastly give some inclusion relations:
Theorem 2.1.4: Let 0 p
k q
kand p q
k k
be bounded, then we have
, ,
w F q w F p
.
Proof: Let x w F q , . We can write t
k f
k x
k l
qkand
k k
k
p
q
such that 0
k 1
. Define
, 1 0, 1 ,
k k
k
k
t t
u t
,0, 1
1
k k
k k
v t
t t
.
Then we have t
k u
k v
k, t
kk u
kk v
kk. Thus it is clear that u
kk u
k t
k, v
kk v
k. Hence we obtain
1 1 1
1 1 1
k
n n n
k k k
k k k
n t n t n v
and this shows that x w F p , . Thus our proof is complete.
Lemma 2.1.5: Let p
k0 and q
k0 . If lim inf
k k 0
k
p q
then we have c q
0( ) c p
0( ) (Başarır and Et
4).
Theorem 2.1.6: Suppose that lim inf
k0
k
p
and (M2) is satisfied. Then if x
k l
we have
,
x
k l w F p .
Proof: Let x
k l
. From (M2) we have f
k x
k l 0
. Since lim inf
k0
k
p
from Lemma 2.1.5 we clearly have f
k x
k l
pk 0
for q
k 1, k
. We thus see that
,
x
k l w F p .
Theorem 2.1.7: Let 0 h inf p
k sup p
k H
and suppose that (M1), (M2) are satisfied.Then we have
( ) ( , ), w p w F p
0w p ( )
0w F p ( , )
and
w p ( )
w F p ( , ) .
Proof: We will only show the first inclusion, the others are obtained by the same way. Let 0 h inf p
k sup p
k H
and x w p ( ) then we have
1
1
( )
k0,
n p
n k
k
s p n
x l
( n ) .
Let (M2) 1 0 from (M2). For 0 t choose a with 0 0 1 t such that
k
( ) f t
. Write t
k x
k l
and suppose that
1 1 2
k
n p
k k
k
f t
where the first sum was taken over t
k
and the second sum was taken over t
k
. In this case
1h
n
and for
t
k we have
k k
1
kt t t
where t , denotes the integer part of t . From Definition 2.1.2 and (M1) for t
k
we get
k k