Journal of Inequalities and Applications Volume 2010, Article ID 329571,27pages doi:10.1155/2010/329571
Research Article
Potential Operators in Variable Exponent Lebesgue
Spaces: Two-Weight Estimates
Vakhtang Kokilashvili,
1, 2Alexander Meskhi,
1, 3and Muhammad Sarwar
41Department of Mathematical Analysis, A. Razmadze Mathematical Institute, 1. M. Aleksidze Street,
0193 Tbilisi, Georgia
2Faculty of Exact and Natural Sciences, Ivane Javakhishvili Tbilisi State University, 2 University Street,
0143 Tbilisi, Georgia
3Department of Mathematics, Faculty of Informatics and Control Systems, Georgian Technical University,
77 Kostava Street, 0175 Tbilisi, Georgia
4Abdus Salam School of Mathematical Sciences, GC University, 68-B New Muslim Town,
Lahore 54600, Pakistan
Correspondence should be addressed to Alexander Meskhi,[email protected]
Received 17 June 2010; Accepted 24 November 2010
Academic Editor: M. Vuorinen
Copyrightq2010 Vakhtang Kokilashvili et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Two-weighted norm estimates with general weights for Hardy-type transforms and potentials in variable exponent Lebesgue spaces defined on quasimetric measure spaces X, d, μ are established. In particular, we derive integral-type easily verifiable sufficient conditions governing two-weight inequalities for these operators. If exponents of Lebesgue spaces are constants, then most of the derived conditions are simultaneously necessary and sufficient for corresponding inequalities. Appropriate examples of weights are also given.
1. Introduction
We study the two-weight problem for Hardy-type and potential operators in Lebesgue spaces with nonstandard growth defined on quasimetric measure spacesX, d, μ. In particular, our aim is to derive easily verifiable sufficient conditions for the boundedness of the operators
Tα·f
x
X
fy
μBx, dx, y1−αxdμ
y, Iα·f
x
X
fy
dx, y1−αxdμ
y
1.1
inequalities when the weights are of special type and the exponentpof the space is constant. We assume that the exponent p satisfies the local log-H ¨older continuity condition, and if the diameter ofX is infinite, then we suppose that pis constant outside some ball. In the framework of variable exponent analysis such a condition first appeared in the paper 1, where the author established the boundedness of the Hardy-Littlewood maximal operator in
Lp·Rn. As far as we know, unfortunately, an analog of the log-H ¨older decay conditionat infinityforp:X → 1,∞is not known even in the unweighted case, which is well-known and natural for the Euclidean spacessee2–5. Local log-H ¨older continuity condition for the exponentp, together with the log-H ¨older decay condition, guarantees the boundedness of operators of harmonic analysis inLp·Rnspacessee, e.g.,6. The technique developed here enables us to expect that results similar to those of this paper can be obtained also for other integral operators, for instance, for maximal and Calder ´on-Zygmund singular operators defined onX.
Considerable interest of researchers is focused on the study of mapping properties of integral operators defined onquasimetric measure spaces. Such spaces with doubling measure and all their generalities naturally arise when studying boundary value problems for partial differential equations with variable coefficients, for instance, when the quasimetric might be induced by a differential operator or tailored to fit kernels of integral operators. The problem of the boundedness of integral operators naturally arises also in the Lebesgue spaces with nonstandard growth. Historically the boundedness of the maximal and fractional integral operators inLp·Xspaces was derived in the papers7–14. Weighted inequalities for classical operators inLpw·spaces, wherewis a power-type weight, were established in the papers10–12,15–19, while the same problems with general weights for Hardy, maximal, and fractional integral operators were studied in10,20–25. Moreover, in the latter paper, a complete solution of the one-weight problem for maximal functions defined on Euclidean spaces is given in terms of Muckenhoupt-type conditions.
It should be emphasized that in the classical Lebesgue spaces the two-weight problem for fractional integrals is already solved see 26, 27, but it is often useful to construct concrete examples of weights from transparent and easily verifiable conditions.
To derive two-weight estimates for potential operators, we use the appropriate inequalities for Hardy-type transforms on X which are also derived in this paper and Hardy-Littlewood-Sobolev-type inequalities forTα·andIα·inLp·Xspaces.
The paper is organized as follows: inSection 1, we give some definitions and prove auxiliary results regarding quasimetric measure spaces and the variable exponent Lebesgue spaces;Section 2is devoted to the sufficient governing two-weight inequalities for Hardy-type operators defined on quasimetric measure spaces, while inSection 3we study the two-weight problem for potentials defined onX.
Finally we point out that constants often different constants in the same series of inequalities will generally be denoted by c or C. The symbol fx ≈ gx means that there are positive constants c1 and c2 independent of x such that the inequality fx ≤ c1gx≤c2fxholds. Throughout the paper is denoted the functionpx/px−1by the
symbolpx.
2. Preliminaries
real-valued functionquasimetricdonX×Xsatisfying the conditions:
idx, y 0 if and only ifxy;
iithere exists a constanta1>0, such thatdx, y≤a1dx, z dz, yfor allx, y, z∈ X;
iiithere exists a constanta0>0, such thatdx, y≤a0dy, xfor allx, y,∈X.
We assume that the ballsBx, r : {y ∈ X : dx, y < r}are measurable and 0 ≤
μBx, r<∞for allx∈Xandr >0; for every neighborhoodVofx∈X, there existsr >0, such thatBx, r⊂V. Throughout the paper we also suppose thatμ{x}0 and that
Bx, R\Bx, r/∅, 2.1
for allx∈X, positiverandRwith 0< r < R < L, where
L:diamX supdx, y:x, y∈X. 2.2
We call the triple X, d, μ a quasimetric measure space. If μ satisfies the doubling conditionμBx,2r≤cμBx, r, where the positive constantcdoes not depend onx∈X
and r > 0, thenX, d, μis called a space of homogeneous typeSHT. For the definition, examples, and some properties of an SHT see, for example, monographs28–30.
A quasimetric measure space, where the doubling condition is not assumed, is called a nonhomogeneous space.
Notice that the conditionL <∞implies thatμX<∞because we assumed that every ball inXhas a finite measure.
We say that the measureμis upper AhlforsQ-regular if there is a positive constantc1
such thatμBx, r ≤ c1rQ for for allx ∈X andr > 0. Further,μis lower AhlforsQ-regular
if there is a positive constantc2 such thatμBx, r ≥ c2rq for allx ∈ X andr > 0. It is easy
to check that ifX, d, μis a quasimetric measure space andL <∞, thenμis lower Ahlfors regularsee also, e.g.,8for the case whendis a metric.
For the boundedness of potential operators in weighted Lebesgue spaces with constant exponents on nonhomogeneous spaces we refer, for example, to the monograph31, Chapter 6and references cited therein.
Letpbe a nonnegativeμ-measurable function onX. Suppose thatEis aμ-measurable set inX. We use the following notation:
p−E:inf
E p; p E:supE p; p−:p−X; p :p X;
Bx, r:y∈X :dx, y≤r, kBx, r:Bx, kr; Bxy:B
x, dx, y;
Bxy :B
x, dx, y; gB: 1
μB
B
gxdμx.
Assume that 1 ≤ p− ≤ p < ∞. The variable exponent Lebesgue space Lp·X
sometimes it is denoted byLpxXis the class of allμ-measurable functionsf onX for whichSpf:
X|fx|
pxdμx<∞. The norm inLp·Xis defined as follows:
f Lp·Xinf
λ >0 :Sp
f
λ
≤1
. 2.4
It is knownsee, e.g.,8,15,32,33thatLp·is a Banach space. For other properties of Lp·spaces we refer, for example, to32–34.
We need some definitions for the exponentpwhich will be useful to derive the main results of the paper.
Definition 2.1. Let X, d, μ be a quasimetric measure space and let N ≥ 1 be a constant. Suppose thatpsatisfies the condition 0 < p− ≤ p < ∞. We say thatp belongs to the class
PN, x, wherex∈X, if there are positive constantsbandcwhich might be depended on
xsuch that
μBx, Nrp−Bx,r−pBx,r≤c 2.5
holds for allr, 0< r ≤ b. Further,p ∈ PNif there are positive constantsbandcsuch that
2.5holds for allx∈Xand allrsatisfying the condition 0< r≤b.
Definition 2.2. LetX, d, μbe an SHT. Suppose that 0< p−≤p <∞. We say thatp∈LHX, x
psatisfies the log-H ¨older-type condition at a pointx ∈Xif there are positive constantsb
andcwhich might be depended onxsuch that
px−p
y≤ c
−lnμBxy
2.6
holds for allysatisfying the condition dx, y ≤ b. Further,p ∈ LHX psatisfies the log-H ¨older type condition onXif there are positive constantsbandcsuch that2.6holds for allx, ywithdx, y≤b.
We will also need another form of the log-H ¨older continuity condition given by the following definition.
Definition 2.3. LetX, d, μbe a quasimetric measure space, and let 0< p− ≤p <∞. We say
thatp ∈ LHX, xif there are positive constantsbandc which might be depended onx
such that
px−p
y≤ c
−lndx, y 2.7
It is easy to see that if a measureμis upper AhlforsQ-regular andp∈LHX resp.,
p∈LHX, x, thenp∈LHX resp.,p∈LHX, x. Further, ifμis lower AhlforsQ-regular andp∈LHX resp.,p∈LHX, x, thenp∈LHX resp.,p∈LHX, x.
Remark 2.4. It can be checked easily that ifX, d, μis an SHT, thenμBx0x ≈μBxx0.
Remark 2.5. LetX, d, μbe an SHT with L < ∞. It is knownsee, e.g., 8, 35 that ifp ∈
LHX, thenp∈ P1. Further, ifμis upper AhlforsQ-regular, then the conditionp ∈ P1 implies thatp∈LHX.
Proposition 2.6. Letcbe positive and let1 < p−X ≤ p X < ∞andp ∈ LHX(resp.,p ∈
LHX, then the functions cp·, 1/p·, andp· belong toLHX resp., LHX. Further if
p ∈ LHX, x resp.,p ∈ LHX, xthen cp·, 1/p·, andp·belong toLHX, x resp.,p ∈
LHX, x.
The proof of the latter statement can be checked immediately using the definitions of the classes LHX, x, LHX, LHX, x, and LHX.
Proposition 2.7. LetX, d, μbe an SHT and letp∈ P1. ThenμBxypx ≤cμByxpyfor all
x, y∈XwithμBx, dx, y≤b, wherebis a small constant, and the constantcdoes not depend onx, y∈X.
Proof. Due to the doubling condition for μ, Remark 1.1, the condition p ∈ P1 and the fact that x ∈ By, a1a0 1dy, x we have the following estimates: μBxypx ≤
μBy, a1a0 1dx, ypx ≤cμBy, a1a0 1dx, ypy ≤ cμByxpy, which proves the statement.
The proof of the next statement is trivial and follows directly from the definition of the classesPN, xandPN. Details are omitted.
Proposition 2.8. LetX, d, μbe a quasimetric measure space and letx0 ∈X. Suppose thatN ≥1
be a constant. Then the following statements hold:
iifp ∈ PN, x0(resp.,p ∈ PN, then there are positive constantsr0,c1, andc2 such
that for all0< r ≤r0and ally∈Bx0, r(resp., for allx0, ywithdx0, y< r≤r0), one
has thatμBx0, Nrpx0≤c1μBx0, Nrpy ≤c2μBx0, Nrpx0.
iiLetp ∈ PN, x0, then there are positive constantsr0,c1, andc2 (in general, depending
on x0) such that for allr (r ≤ r0) and allx, y ∈ Bx0, rone has μBx0, Nrpx ≤ c1μBx0, Nrpy≤c2μBx0, Nrpx.
iiiLetp∈ PN, then there are positive constantsr0,c1, andc2such that for all ballsBwith
radiusr(r≤r0) and allx, y∈B, one has thatμNBpx≤c1μNBpy≤c2μNBpx.
It is known thatsee, e.g., 32, 33 if f is a measurable function on X and E is a measurable subset ofX, then the following inequalities hold:
f Lpp·EE≤Sp
fχE
≤ f pL−p·EE, f Lp·E≤1;
f p−E
Lp·E≤Sp
fχE
≤ f pLp·EE, f Lp·E >1.
Further, H ¨older’s inequality in the variable exponent Lebesgue spaces has the following form:
E
fgdμ≤
1
p−E
1
p−E
f Lp·E g Lp·E. 2.9
Lemma 2.9. LetX, d, μbe an SHT.
iIfβis a measurable function onXsuch thatβ < −1and ifr is a small positive number, then there exists a positive constantcindependent ofrandxsuch that
X\Bx0,r
μBx0y
βxdμy≤cβx 1
βx μBx0, r
βx 1. 2.10
iiSuppose thatpandαare measurable functions onX satisfying the conditions1 < p− ≤ p <∞andα−>1/p−. Then there exists a positive constantcsuch that for allx∈Xthe
inequality
Bx0,2dx0,x
μBx, dx, yαx−1pxdμy≤cμBx0, dx0, x
αx−1px 1
2.11
holds.
Proof. Partiwas proved in35 see also31, page 372, for constantβ. The proof of Partii is given in31,Lemma 6.5.2, page 348for constantαandp, but repeating those arguments we can see that it is also true for variableαandp. Details are omitted.
Lemma 2.10. LetX, d, μbe an SHT. Suppose that0< p− ≤p <∞, thenpsatisfies the condition
p∈ P1(resp.,p∈ P1, x) if and only ifp∈LHX resp.,p∈LHX, x.
Proof. We follow1.
Necessity. Let p ∈ P1, and letx, y ∈ X with dx, y < c0 for some positive constantc0.
Observe thatx, y ∈B, whereB : Bx,2dx, y. By the doubling condition forμ, we have thatμBxy−|px−py| ≤cμB−|px−py|≤ cμBp−B−pB ≤ C, whereCis a positive constant which is greater than 1. Taking now the logarithm in the last inequality, we have thatp ∈
LHX. Ifp∈ P1, x, then by the same arguments we find thatp∈LHX, x.
Sufficiency. Let B : Bx0, r. First observe that If x, y ∈ B, then μBxy ≤ cμBx0, r.
Consequently, this inequality and the condition p ∈ LHX yield |p−B − p B| ≤
C/ − lnc0μBx0, r. Further, there exists r0 such that 0 < r0 < 1/2 and c1 ≤
lnμB/−lnc0μB ≤ c2, 0 < r ≤ r0, where c1 and c2 are positive constants. Hence
μBp−B−pB≤μBC/lnc0μB expClnμB/lnc
Let, now,p∈LHX, xand letBx :Bx, rwherer is a small number. We have that
p Bx−px≤c/−lnc0μBx, randpx−p−Bx≤c/−lnc0μBx, rfor some positive
constantc0. Consequently,
μBx
p−Bx−pBxμB x
px−pBxμB x
p−Bx−px≤cμB x
−2c/−lnc0μBx≤C.
2.12
Definition 2.11. A measure μ on X is said to satisfy the reverse doubling condition μ ∈
RDCX if there exist constantsA > 1 and B > 1 such that the inequality μBa, Ar ≥ BμBa, rholds.
Remark 2.12. It is known that if all annulus inX are not emptyi.e., condition2.1holds, thenμ∈ DCXimplies thatμ∈ RDCX see, e.g.,28, page 11, Lemma 20.
Lemma 2.13. Let X, d, μ be an SHT. Suppose that there is a point x0 ∈ X such that p ∈
LHX, x0. LetAbe the constant defined inDefinition 2.11. Then there exist positive constantsr0
andC(which might be depended onx0) such that for allr,0< r ≤r0, the inequality
μBA
p−BA−pBA≤C 2.13
holds, whereBA:Bx0, Ar\Bx0, rand the constantCis independent ofr.
Proof. Taking into account condition 2.1 and Remark 2.12, we have that μ ∈ RDCX. Let B : Bx0, r. By the doubling and reverse doubling conditions, we have thatμBA
μBx0, Ar−μBx0, r ≥ B −1μBx0, r ≥ cμAB. Suppose that 0 < r < c0, where c0
is a sufficiently small constant. Then by usingLemma 2.10we find thatμBAp−BA−pBA ≤
cμABp−BA−pBA≤cμABp−AB−pAB≤c.
In the sequel we will use the notation:
I1,k :
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
B
x0,A
k−1L a1
ifL <∞,
B
x0, Ak−1
a1
ifL∞,
I2,k :
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
Bx0,Ak 2a1L
\B
x0, Ak−1L
a1
if L <∞,
Bx0, Ak 2a1
\B
x0, Ak−1
a1
if L∞,
I3,k :
⎧ ⎨ ⎩
X\Bx0, Ak 2La1
if L <∞,
X\Bx0, Ak 2a1
Ek:
⎧ ⎨ ⎩
Bx0, Ak 1L
\Bx0, AkL
if L <∞,
Bx0, Ak 1
\Bx0, Ak
if L∞,
2.14
where the constantsAand a1 are taken, respectively, from Definition 2.11and the triangle
inequality for the quasimetricd, andLis a diameter ofX.
Lemma 2.14. LetX, d, μbe an SHT and let1 < p−x ≤px ≤qx≤q X< ∞. Suppose
that there is a pointx0∈Xsuch thatp, q∈LHX, x0. Assume that ifL∞, thenpx≡pc≡const andqx≡qc≡const outside some ball Bx0,a. Then there exists a positive constant C such that
k
fχI2,k Lp·X gχI2,k Lq·X≤C f Lp·X g Lq·X, 2.15
for allf∈Lp·Xandg∈Lq·X.
Proof. Suppose thatL ∞. To prove the lemma, first observe thatμEk ≈ μBx0, Akand μI2,k ≈ μBx0, Ak−1. This holds because μ satisfies the reverse doubling condition and,
consequently,
μEkμ
Bx0, Ak 1
\Bx0, Ak
μBx0, Ak 1
−μBx0, Ak
μBx0, AAk
−μBx0, Ak
≥BμBx0, Ak
−μBx0, Ak
B−1μBx0, Ak
.
2.16
Moreover, the doubling condition yieldsμEk ≤ μBx0, AAk ≤ cμBx0, Ak, where c > 1.
Hence,μEk≈μBx0, Ak.
Further, since we can assume thata1≥1, we find that
μI2,kμ
Bx0, Ak 2a1
\B
x0, Ak−1
a1
μBx0, Ak 2a1
−μB
x0, Ak−1
a1
μBx0, AAk 1a1
−μB
x0, Ak−1
a1
≥BμBx0, Ak 1a1
−μB
x0, Ak−1
a1
≥B2μB
x0, Ak
a1
−μB
x0, Ak−1
a1
≥B3μB
x0, Ak−1
a1
−μB
x0, Ak−1
a1
B3−1μB
x0, Ak−1
a1
.
2.17
Moreover, using the doubling condition for μ we have that μI2,k ≤ μBx0, Ak 2r ≤ cμBx0, Ak 1r ≤ c2μBx0, Ak/a1 ≤ c3μBx0, Ak−1/a1. This gives the estimates B3 −
For simplicity, assume thata1. Suppose thatm0is an integer such thatAm0−1/a1>1.
Let us split the sum as follows:
i
fχI
2,i Lp·X· gχI2,i Lq·X
i≤m0
· · ·
i>m0
· · · :J1 J2. 2.18
Sincepx≡pcconst, qx qcconst outside the ballBx0,1, by using H ¨older’s
inequality and the fact thatpc≤qc, we have
J2
i>m0
fχI2,i LpcX· gχI2,i LqcX≤c f Lp·X· g Lq·X. 2.19
Let us estimate J1. Suppose that fLp·X ≤ 1 and gLq·X ≤ 1. Also, by
Proposition 2.6, we have that 1/q ∈ LHX, x0. Therefore, by Lemma 2.13 and the fact
that 1/q ∈ LHX, x0, we obtain that μI2,k1/qI2,k ≈ χI2,kLq·X ≈ μI2,k1/q−I2,k and
μI2,k1/q
I
2,k ≈ χ
I2,kLq·X ≈ μI2,k1/q
−Ik, where k ≤ m0. Further, observe that these
estimates and H ¨older’s inequality yield the following chain of inequalities:
J1≤c
k≤m0
Bx0,Am01
fχI2,k Lp·X· gχI2,k Lq·X
χI2,k Lq·X· χI2,k Lq·X
χEkxdμx
c
Bx0,Am01
k≤m0
fχI2,k Lp·X· gχI2,k Lq·X
χI
2,k Lq·X· χI2,k Lq·X
χEkxdμx
≤c
k≤m0 fχI
2,k Lp·X
χI
2,k Lq·X
χEkx
Lq·Bx0,Am01
× k≤m0
gχI2,k Lq·X
χI2,k Lq·X
χEkx
Lq·Bx
0,Am01
:cS1
f·S2
g.
2.20
Now we claim thatS1f≤cIf, where
If: k≤m0
fχI
2,k Lp·X
χI
2k Lp·X
χEk·
Lp·Bx0,Am01
, 2.21
and the positive constantcdoes not depend onf. Indeed, suppose thatIf≤1. Then taking into accountLemma 2.13we have that
k≤m0
1
μI2,k
Ek
fχI 2,k
px
Lp·Xdμx
≤c
Bx0,Am01
k≤m0 fχI
2,k Lp·X
χI2,k Lp·X
χEkx
px
dμx≤c.
Consequently, sincepx≤qx, Ek⊆I2,kandfLp·X≤1, we find that
k≤m0
1
μI2,k
Ek
fχI 2,k
qx
Lp·Xdμx≤
k≤m0
1
μI2,k
Ek
fχI 2,k
px
Lp·Xdμx≤c. 2.23
This implies thatS1f≤c. Thus, the desired inequality is proved. Further, let us introduce
the following function:
Py:
k≤2
p I2,kχEky. 2.24
It is clear thatpy≤PybecauseEk⊂I2,k. Hence
If≤c
k≤m0
fχI2,k Lp·X
χI2k Lp·X
χEk·
LP·Bx0,Am01
2.25
for some positive constantc. Then, by using this inequality, the definition of the functionP, the conditionp∈LHX, and the obvious estimateχI2,k
pI2,k
Lp·X≥cμI2,k, we find that
Bx0,Am01
k≤m0
fχI2,k Lp·X
χI2,k Lp·X
χEkx
Px dμx
Bx0,Am01 ⎛
⎝
k≤m0 fχI
2,k pI2,k
Lp·X
χI 2,k
pI2,k
Lp·X
χEkx
⎞ ⎠dμx
≤c
Bx0,Am01 ⎛
⎝
k≤m0
fχI2,k pI2,k
Lp·X
μI2,k
χEkx
⎞
⎠dμx≤c
k≤m0 fχI
2,k pI2,k
Lp·X
≤c
k≤m0
I2,k
fxpxdμx≤c
X
fxpxdμx≤c.
2.26
Consequently,If≤ cfLp·X. Hence,S1f≤ cfLp·X. Analogously taking into
account the fact thatq∈DLXand arguing as above, we find thatS2g≤cgLq·X. Thus,
summarizing these estimates we conclude that
i≤m0
fχIi Lp·X gχIi Lq·X ≤c f Lp·X g Lq·X. 2.27
3. Hardy-Type Transforms
In this section, we derive two-weight estimates for the operators:
Tv,wfx vx
Bx0x
fywydμy, Tv,wfx vx
X\Bx0x
fywydμy.
3.1
Letabe a positive constant, and letpbe a measurable function defined onX. Let us introduce the notation:
p0x:p−
Bx0x
; p0x:
⎧ ⎨ ⎩
p0x ifdx0, x≤a;
pcconst ifdx0, x> a.
p1x:p−
Bx0, a\Bx0x
; p1x:
⎧ ⎨ ⎩
p1x if dx0, x≤a;
pcconst ifdx0, x> a.
3.2
Remark 3.1. If we deal with a quasimetric measure space withL < ∞, then we will assume
thataL. Obviously,p0≡p0andp1 ≡p1in this case.
Theorem 3.2. LetX, d, μbe a quasimetric measure space. Assume that p and qare measurable functions onXsatisfying the condition1 < p− ≤p0x≤qx≤q <∞. In the case whenL∞,
suppose thatp≡pc≡const,q≡qc≡const, outside some ballBx0, a. If the condition
A1: sup 0≤t≤L
t<dx0,x≤L
vxqx
dx0,x≤t
wp0xydμy
qx/p0x
dμx<∞, 3.3
holds, thenTv,wis bounded fromLp·XtoLq·X.
Proof. Here we use the arguments of the proofs of Theorem 1.1.4 in31,see page 7and of Theorem 2.1 in21. First, we notice thatp− ≤ p0x ≤pxfor allx∈ X. Letf ≥0 and let Spf≤1. First, assume thatL <∞. We denote
Is:
dx0,y<s
fywydμy fors∈0, L. 3.4
Suppose thatIL < ∞, thenIL∈ 2m,2m 1for somem∈ Z. Let us denotes
j : sup{s :
Is≤2j}, j ≤m, ands
thatIsj ≤2j, Is>2jfors > sj, and 2j ≤
sj≤dx0,y≤sj1fywydμy. Ifβ:limj→ −∞sj,
thendx0, x < Lif and only ifdx0, x ∈ 0, β∪
m
j−∞sj, sj 1. If IL ∞, then we take m ∞. Since 0 ≤ Iβ ≤ Isj ≤ 2j for every j, we have that Iβ 0. It is obvious that
Xj≤m{x:sj< dx0, x≤sj 1}. Further, we have that
Sq
Tv,wf
X
Tv,wfx
qxdμx
X
vx
Bx0,dx0,x
fywydμy
qx
dμx
X
vxqx
Bx0,dx0,x
fywydμy
qx dμx
≤ m j−∞
sj<dx0,x≤sj1
vxqx
dx0,y<sj1
fywydμy
qx dμx.
3.5
Let us denote
Bjx0:
x∈X :sj−1≤dx0, x≤sj
. 3.6
Notice that Isj 1 ≤ 2j 1 ≤ 4
Bjx0 wyfydμy. Consequently, by this estimate and
H ¨older’s inequality with respect to the exponentp0xwe find that
Sq
Tv,wf
≤c
m
j−∞
sj<dx0,x≤sj1
vxqx
Bjx0
fywydμy
qx dμx
≤c
m
j−∞
sj<dx0,x≤sj1
vxqxJkxdμx,
3.7
where
Jkx:
Bjx0
fyp0xdμy
qx/p0x
Bjx0
wyp0xdμy
qx/p0x
Observe now thatqx≥p0x. Hence, this fact and the conditionSpf≤1 imply that
Jkx≤c
Bjx0∩{y:fy≤1}
fyp0xdμy
Bjx0∩{y:fy>1}
fypydμy
qx/p0x
×
Bjx0
wyp0xdμyqx/p0 x
≤c
μBjx0
Bjx0∩{y:fy>1}
fypydμy
×
Bjx0
wyp0xdμy
qx/p0x .
3.9
It follows now that
Sq
Tv,wf
≤c
⎛
⎝m
j−∞
μBjx0
sj<dx0,x≤sj1
vxqx
×
Bjx0
wyp0xdμy
qx/p0x dμx
m
j−∞
Bjx0∩{y:fy>1}
fypydμy
sj<dx0,x≤sj1
vxqx
×
Bjx0
wyp0xdμy
qx/p0x dμx
⎞
⎠:cN1 N2.
3.10
SinceL <∞, it is obvious that
N1≤A1
m1
j−∞
μBjx0
≤CA1,
N2≤A1
m1
j−∞
Bjx0
fypydμy≤C
X
fypydμyA1Sp
f≤A1.
3.11
Let us now suppose thatL∞. We have
Tv,wfx χBx0,axvx
Bx0x
fywydμy
χX\Bx0,axvx
Bx0x
fywydμy:Tv,w1fx Tv,w2fx.
3.12
By using the already proved result forL <∞and the fact that diamBx0, a<∞, we
find thatTv,w1fLq·Bx
0,a≤cfLp·Bx0,a≤cbecause
A1a : sup
0≤t≤a
t<dx0,x≤a
vxqx
dx0,x≤t
wp0xydμy
qx/p0x
dμx≤A1<∞.
3.13
Further, observe that
Tv,w2fx χX\Bx0,axvx
Bx0x
fywydμyχX\Bx0,axvx
×
dx0,y≤a
fywydμy
χX\Bx0,axvx
a≤dx0,y≤dx0,x
fywydμy:Tv,w2,1fx Tv,w2,2fx.
3.14
It is easy to see thatsee also31, Theorems 1.1.3 or 1.1.4the condition
A1a:sup t≥a
dx0,x≥t
vxqcdμx
1/qc
a≤dx0,y≤t
wypcdμy
1/pc
<∞ 3.15
guarantees the boundedness of the operator
Tv,wfx vx
a≤dx0,y<dx0,x
fromLpcX\Bx
0, atoLqcX\Bx0, a. Thus,Tv,w2,2 is bounded. It remains to prove that
Tv,w2,1is bounded. We have
T2,1 v,w f
Lp·X
Bx0,ac
vxqcdμx
1/qc
Bx0,a
fywydμy
≤
Bx0,ac
vxqcdμx
1/qc
f Lp·Bx
0,awLp·Bx0,a.
3.17
Observe, now, that the conditionA1<∞guarantees that the integral
Bx0,ac
vxqcdμx 3.18
is finite. Moreover,N:wLp·Bx
0,a<∞. Indeed, we have that
N≤
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
Bx0,a
wypydμy
1/p−Bx0,a
ifwLp·Bx0,a≤1,
Bx0,a
wypydμy
1/pBx0,a
ifwLp·Bx
0,a>1.
3.19
Further,
Bx0,a
wypydμy
Bx0,a∩{w≤1}
wypydμy
Bx0,a∩{w>1}
wypydμy:I1 I2.
3.20
ForI1, we have thatI1≤μBx0, a<∞. SinceL∞and condition2.1holds, there exists
a pointy0 ∈ X such thata < dx0, y0 < 2a. Consequently,Bx0, a ⊂ Bx0, dx0, y0and py≥p−Bx0, dx0, y0 p0y0, wherey∈Bx0, a. Consequently, the conditionA1<∞
yieldsI2 ≤
Bx0,awy
p0y0dy < ∞. Finally, we have thatT2,1
v,wfLp·X ≤C. Hence,Tv,w is bounded fromLp·XtoLq·X.
Theorem 3.3. LetX, d, μbe a quasimetric measure space. Assume that p and qare measurable functions onX satisfying the condition1 < p− ≤ p1x ≤ qx ≤ q < ∞. IfL ∞, then, one
assumes thatp≡pc≡const,q≡qc≡const outside some ballBx0, a. If
B1 sup 0≤t≤L
dx0,x≤t
vxqx
t≤dx0,x≤L
wp1xydμy
qx/p1x
dμx<∞, 3.21
thenTv,w is bounded fromLp·XtoLq·X.
Remark 3.4. If p ≡ const, then the condition A1 < ∞ in Theorem 3.2 resp., B1 < ∞ in
Theorem 3.3 is also necessary for the boundedness of Tv,w resp., Tv,w from Lp·X to
Lq·X. See31, pages 4-5for the details.
4. Potentials
In this section, we discuss two-weight estimates for the potential operatorsTα· andIα· on quasimetric measure spaces, where 0< α− ≤ α < 1. Ifα ≡const , then we denoteTα·and Iα·byTαandIα, respectively.
The boundedness of Riesz potential operators inLp·Ωspaces, whereΩis a domain inRnwas established in5,6,36,37.
For the following statement we refer to11.
Theorem A. LetX, d, μbe an SHT . Suppose that1< p− ≤p <∞andp∈ P1. Assume that
ifL∞, thenp≡const outside some ball. Letαbe a constant satisfying the condition0< α <1/p . One setsqx px/1−αpx. Then,Tαis bounded fromLp·XtoLq·X.
Theorem Bsee9. LetX, d, μbe a nonhomogeneous space withL <∞and letNbe a constant defined by N a11 2a0, where the constantsa0 and a1 are taken from the definition of the
quasimetricd. Suppose that1 < p− < p <∞, p, α ∈ PNand thatμis upper Ahlfors 1-regular. One definesqx px/1−αxpx, where0 < α− ≤α < 1/p . ThenIα· is bounded from Lp·XtoLq·X.
For the statements and their proofs of this section, we keep the notation of the previous sections and, in addition, introduce the new notation:
vα1x:vx
μBx0x α−1
, wα1x:w−1x; vα2x:vx;
wα2x:w−1x
μBx0x α−1
;
Fx:
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
y∈X: d
x0, y
L A2a1 ≤d
x0, y
≤A2La
1dx0, x
, ifL <∞,
y∈X: d
x0, y
A2a1 ≤d
x0, y
≤A2a
1dx0, x
, ifL∞,
4.1
where Aand a1 are constants defined inDefinition 2.11 and the triangle inequality ford,
Theorem 4.1. LetX, d, μbe an SHT without atoms. Suppose that1 < p− ≤ p < ∞andαis a
constant satisfying the condition0 < α < 1/p . Letp∈ P1. One setsqx px/1−αpx. Further, if L ∞, then one assumes that p ≡ pc ≡ const outside some ball Bx0, a. Then the
inequality
vTαf Lq·X≤c wf Lp·X 4.2
holds if the following three conditions are satisfied:
aTv1
α ,wα1 is bounded fromL
p·XtoLq·X;
bTv2
α ,wα2 is bounded fromL
p·XtoLq·X;
cthere is a positive constantbsuch that one of the following inequalities hold: (1)v Fx≤
bwxforμ−a.e.x∈X; (2) vx≤bw−Fxforμ−a.e.x∈X.
Proof. For simplicity, suppose thatL < ∞. The proof for the caseL ∞is similar to that of the previous case. Recall that the setsIi,k, i1,2,3 andEkare defined inSection 2. Letf ≥0 and letgLq·X≤1. We have
X
Tαf
xgxvxdμx
0
k−∞
Ek
Tαf
xgxvxdμx
≤ 0 k−∞
Ek
Tαf1,k
xgxvxdμx 0
k−∞
Ek
Tαf2,k
xgxvxdμx
0
k−∞
Ek
Tαf3,k
xgxvxdμx :S1 S2 S3,
4.3
wheref1,kf·χI1,k, f2,k f·χI2,k, f3,kf·χI3,k.
Observe that ifx ∈ Ekandy ∈ I1,k, thendx0, y ≤ dx0, x/Aa1. Consequently, the
triangle inequality fordyieldsdx0, x ≤ Aa1a0dx, y, whereA A/A−1. Hence, by
usingRemark 2.4, we find thatμBx0x≤cμBxy. Applying conditionanow, we have that
S1≤c
μBx0x
α−1 vx
Bx0x
fydμy
LqxX
g
Lq·X≤c f Lp·X. 4.4
Further, observe that ifx∈Ekandy ∈I3,k, thenμBx0y≤ cμBxy. By conditionb,
Now we estimateS2. Suppose thatv Fx≤bwx. Theorem A andLemma 2.14yield
S2≤
k
Tαf2,k
·χEk·v· Lq·X gχEk· Lq·X
≤
k
v Ek Tαf2,k
· Lq·X g·χEk· Lq·X
≤c
k
v Ek f2,k Lp·X g·χEk· Lq·X
≤c
k
f2,k·w·χI2,k· Lp·X g·χEk· Lq·X
≤c f·w· Lp·X g· Lq·X≤c f·w· Lp·X.
4.5
The estimate ofS2for the case whenvx≤bw−Fxis similar to that of the previous one. Details are omitted.
Theorems4.1,3.2, and3.3imply the following statement.
Theorem 4.2. LetX, d, μbe an SHT. Suppose that1< p−≤p <∞andαis a constant satisfying the condition0 < α <1/p . Letp∈ P1. One setsqx px/1−αpx. IfL∞, then, one
supposes thatp≡pc ≡const outside some ballBx0, a. Then inequality4.2holds if the following
three conditions are satisfied:
i
P1 : sup 0<t≤L
t<dx0,x≤L
vx
μBx0x 1−α
qx
×
dx0,y≤t
w−p0xydμy
qx/p0x
dμx<∞;
4.6
ii
P2:sup 0<t≤L
dx0,x≤t
vxqx
×
t<dx0,y≤L
wyμBx0y
1−α−p1x dμy
qx/p1x
dμx<∞,
4.7
iiiconditioncofTheorem 4.1holds.
Remark 4.3. Ifp pc ≡const onX, then the conditionsPi < ∞,i 1,2, are necessary for
4.2. Necessity of the conditionP1 <∞follows by taking the test functionf w−pc
χBx0,t
in 4.2 and observing thatμBxy ≤ cμBx0x for thosex andy which satisfy the conditions dx0, x≥tanddx0, y≤tsee also31, Theorem 6.6.1, page 418for the similar arguments
fx w−pcxχ
X\Bx0,txμBx0x
α−1pc−1 and taking into account the estimateμB xy ≤
μBx0yfordx0, x≤tanddx0, y≥t.
The next statement follows in the same manner as the previous one. In this case, Theorem B is used instead of Theorem A. The proof is omitted.
Theorem 4.4. LetX, d, μbe a nonhomogeneous space withL <∞. LetNbe a constant defined by
Na11 2a0. Suppose that1< p−≤p <∞, p, α∈ PNand thatμis upper Ahlfors 1-regular.
We defineqx px/1−αxpx, where0< α−≤α <1/p . Then the inequality
v·Iα·f· Lq·X≤c w·f· Lp·X 4.8
holds if
i
sup
0≤t≤L
t<dx0,x≤L
vx
dx0, x1−αx
qx
Bx0,t
w−p0xydμy
qx/p0x
dμx<∞;
4.9
ii
sup
0≤t≤L
Bx0,t
vxqx
t<dx0,y≤L
wydx0, y
1−αy−p1x dμy
qx/p1x
dμx<∞,
4.10
andiiiconditioncofTheorem 4.1is satisfied.
Remark 4.5. It is easy to check that ifp andαare constants, then conditionsiand ii in
Theorem 4.4 are also necessary for4.8. This follows easily by choosing appropriate test functions in4.8 see alsoRemark 4.3.
Theorem 4.6. LetX, d, μbe an SHT without atoms. Let1< p−≤p <∞and letαbe a constant
with the condition0< α <1/p . One setsqx px/1−αpx. Assume thatphas a minimum atx0and thatp∈LHX. Suppose also that ifL∞, thenpis constant outside some ballBx0, a.
Letvandwbe positive increasing functions on0,2L. Then the inequality
vdx0,·
Tαf
· Lq·X≤c wdx0,·f· Lp·X 4.11
holds if
I1: sup 0<t≤L
I1t: sup 0<t≤L
t<dx0,x≤L
vdx0, x
μBx0x 1−α
qx
×
dx0,y≤t
w−p0xdx 0, y
dμy
qx/p0x
dμx<∞,
forL∞;
J1: sup 0<t≤L
t<dx0,x≤L
vdx0, x
μBx0x 1−α
qx
×
dx0,y≤t
w−px0dx 0, y
dμy
qx/px0
dμx<∞,
4.13
forL <∞.
Proof. We prove the theorem forL∞. The proof for the case whenL <∞is similar. Observe that by Lemma 2.10 the condition p ∈ LHX implies p ∈ P1. We will show that the conditionI1 < ∞ implies the inequalityvA2a1t/wt ≤ Cfor all t > 0, whereA anda1
are constants defined inDefinition 2.11and the triangle inequality ford, respectively. Indeed, let us assume thatt≤b1, whereb1is a small positive constant. Then, taking into account the
monotonicity ofvandwand the facts thatp0x p0x for smalldx0, xandμ∈RDCX,
we have
I1t≥
A2a
1t≤dx0,x<A3a1t
vA2a 1t
wt
qx
μBx0, t
α−1/p0xqx dμx
≥
vA2a 1t
wt
q−
A2a1t≤dx0,x<A3a1t
μBx0, t
α−1/p0xqx
dμx≥c
vA2a 1t
wt
q− .
4.14
Hence,c : limt→0vA2a1t/wt<∞. Further, ift > b2, whereb2 is a large number, then
sincepandqare constants, fordx0, x> t, we have that
I1t≥
A2a
1t≤dx0,x<A3a1t
vdx0, xqc
μBx0, t
α−1qc dμx
×
Bx0,t
w−pcxdμx
qc/pc dμx
≥C
vA2a 1t
wt
qc
A2a1t≤dx0,x<A3a1t
μBx0, t
α−1/pcqcdμx ≥c
vA2a 1t
wt
qc .
4.15
Now we show that the conditionI1<∞implies
sup t>0
I2t:sup
t>0
dx0,x≤t
vdx0, xqx
×
dx0,y>t
w−p1xdx 0, y
μBx0y
α−1p1xdμy
qx/p1x
dμx<∞.
4.16
Due to monotonicity of functionsvandw, the conditionp∈LHX,Proposition 2.6, Lemmas2.9, and2.10and the assumption thatphas a minimum atx0, we find that for all t >0,
I2t≤
dx0,x≤t
vt wt
qx
μBx0, t
α−1/px0qxdμx
≤c
dx0,x≤t
vt wt
qx
μBx0, t
α−1/px0qx0dμx
≤c
⎛
⎝
dx0,x≤t
vA2a 1t
wt
qx dμx
⎞
⎠μBx0, t−1≤ C.
4.17
Now,Theorem 4.2completes the proof.
Theorem 4.7. LetX, d, μbe an SHT withL <∞. Suppose thatp,qandαare measurable functions onXsatisfying the conditions:1 < p− ≤px≤qx≤q <∞and1/p− < α− ≤α <1. Assume
thatα∈ LHXand there is a pointx0 ∈ X such thatp, q ∈LHX, x0. Suppose also thatwis a
positive increasing function on0,2L. Then the inequality
Tα·fv Lq·X≤c wdx0,·f· Lp·X 4.18
holds if the following two conditions are satisfied:
I1: sup 0<t≤L
t≤dx0,x≤L
vx
μBx0x 1−αx
qx
×
dx0,x≤t
w−p0xdx 0, y
dμy
qx/p0x
dμx<∞;
I2: sup 0<t≤L
dx0,x≤t
vxqx
×
t≤dx0,x≤L
wdx0, y
×μBx0y
1−αx−p1x dμy
qx/p1x
dμx<∞.
Proof. For simplicity, assume thatL 1. First observe that by Lemma 2.10we havep, q ∈
P1, x0andα ∈ P1. Suppose thatf ≥ 0 andSpwdx0,·f· ≤ 1. We will show that SqvTα·f≤C.
We have
Sq
vTα·f
≤Cq
⎡
⎣
X
vx
dx0,y≤dx0,x/2a1
fyμBxy
αx−1 dμy
qx dμx
X
vx
dx0,x/2a1≤dx0,y≤2a1dx0,x
fyμBxy
αx−1 dμy
qx dμx
X
vx
dx0,y≥2a1dx0,x
fyμBxy
αx−1 dμy
qx dμx
⎤
⎦:CqI1 I2 I3.
4.20
First, observe that by virtue of the doubling condition forμ,Remark 2.4, and simple calculation we find thatμBx0x≤cμBxy. Taking into account this estimate andTheorem 3.2
we have that
I1≤c
X
vx
μBx0x 1−αx
dx0,y<dx0,x
fydμy
qx
dμx≤C. 4.21
Further, it is easy to see that ifdx0, y ≥2a1dx0, x, then the triangle inequality for dand the doubling condition forμyield thatμBx0y ≤ cμBxy. Hence, due toProposition 2.7,
we see thatμBx0y
αx−1≥cμB
xyαy−1for suchxandy. Therefore,Theorem 3.3implies that
I3≤C.
It remains to estimateI2. Let us denote:
E1x:B
x0x\B
x0,
dx0, x
2a1
; E2x:Bx
0,2a1dx0, x\Bx0x. 4.22
Then we have that
I2≤C
⎡
⎣
X
#
vx
E1xf
yμBxy
αx−1 dμy
$qx dμx
X
#
vx
E2xf
yμBxy
αx−1dμy
$qx dμx
⎤
⎦:cI21 I22.