R E S E A R C H
Open Access
A basic problem of
(
p
,
q
)
-Bernstein-type
operators
Qing-Bo Cai
1and Xiao-Wei Xu
2**Correspondence:
2School of Mathematical Sciences,
Xiamen University, Xiamen, China Full list of author information is available at the end of the article
Abstract
In this note, we give an elaboration of a basic problem on convergence theorem of (p,q)-analogue of Bernstein-type operators. By some classical analysis techniques, we derive an exact class of (pn,qn)-integer satisfying limn→∞[n]pn,qn=∞with
limn→∞pn= 1 and limn→∞qn= 1 under 0 <qn<pn≤1. Our results provide an
erratum to corresponding results on (p,q)-analogue of Bernstein-type operators that appeared in recent literature.
MSC: 41A50
Keywords: (p,q)-integer; Bernstein-type approximation; convergence theorem; equivalent condition
1 Introduction
During the last decades, the applications ofq-calculus emerged as a new area in the field of approximation theory. The rapid development ofq-calculus has led to the discovery of various generalizations of Bernstein polynomials involvingq-integers. A detailed review of the results onq-Bernstein polynomials along with an extensive bibliography is given in []. Theq-Bernstein polynomials are shown to be closely related to theq-deformed binomial distribution []. It plays an important role in theq-boson theory giving aq-deformation of the quantum harmonic formalism []. Theq-analogue of the boson operator calculus has proved to be a powerful tool in theoretical physics. It provides explicit expressions for the representations of the quantum groupSUq() []. Meanwhile, the (p,q)-integers were
introduced in order to generalize or unify several forms ofq-oscillator algebras well known in the earlier physics literature related to the representation theory of single parameter quantum algebras [].
Recently, (p,q)-integers have been introduced into classical linear positive operators to construct new approximation processes. A sequence of (p,q)-analogue of Bernstein operators was first introduced by Mursaleen [, ]. Besides, (p,q)-analogues of Szász-Mirakyan [], Baskakov Kantorovich [], Bleimann-Butzer-Hahn [] and Kantorovich-type Bernstein-Stancu-Schurer [] operators were also considered, see [–]. For fur-ther developments, one can also refer to [, –]. These operators are double parameters corresponding topandqversus single parameterq-Bernstein-type operators [, , ]. The aim of these generalizations is to provide appropriate and powerful tools to applica-tion areas such as numerical analysis, computer-aided geometric design and soluapplica-tions of differential equations (see, e.g., []).
For example, consider the (p,q)-analogue of the Bernstein operators proposed in []. Givenf ∈C[, ] and <q<p≤, operatorsBn,p,qare defined as follows:
Bn,p,q(f;x)
:= pn(n–)
n
k=
n k
p,q
pk(k–)xk
n–k–
s=
ps–qsxf
[k]p,q
pk–n[n] p,q
, n= , , . . . , (.)
where, for any nonnegative integerkand <q<p≤, the (p,q)-integer [k]p,qis defined
by
[k]p,q:=pk–+pk–q+· · ·+qk–=
pk–qk
p–q (k= , , , . . .), []p,q:= , and the (p,q)-factorial [k]p,q! is defined by
[k]p,q! := []p,q[]p,q· · ·[k]p,q (k= , , . . .), []p,q! := .
For integersk,nwith ≤k≤n, the (p,q)-binomial coefficient is defined by
n k
p,q
:= [n]p,q! [k]p,q![n–k]p,q!
.
In general, we expectBn,p,q(f;x) to converge tof(x) asn→ ∞. But we see that, for fixed
value ofpandqwithq∈(, ) andp∈(q, ],
[n]p,q→ or /( –q) asn→ ∞.
To obtain a sequence of generalized (p,q)-analogue Bernstein polynomials which con-verge, we letqn∈(, ) andpn∈(qn, ] depend onn. We then choose a sequence (pn,qn)
such that [n]pn,qn→ ∞asn→ ∞, to ensure thatBn,p,q(f;x) converge tof(x).
The convergence theorems for (p,q)-analogue Bernstein-type operators were estab-lished in some recent papers (see [], Theorem . (Remark .), [], Theorem , and fur-ther reading [], Theorem ., [], Theorem ., [], Theorem , and [], Remark ., see also [, ]). For example, Mursaleen [] gives the following.
Theorem . Let <qn<pn≤such thatlimn→∞pn= andlimn→∞qn= .Then,for
each f ∈C[, ],Bn,pn,qn(f;x)converge uniformly to f on[, ].
All linear positive operators mentioned in the articles cited above require that limn→∞[n]pn,qn=∞; otherwise, these operators do not define approximation processes. However, the claim that bothlimn→∞pn= andlimn→∞qn= with <qn<pn≤ imply
thatlimn→∞[n]pn,qn=∞, in general, is not true. A counterexample is presented below. Example . Letpn= – /
√
n, then [n]pn,qn → for any sequence{qn}satisfying <
qn<pn. Indeed,
≤[n]pn,qn=p
n–
n +pnn–qn+· · ·+pnqnn–+qnn–
Later, the author [] presented a more accurate assertion: Letqn,pnsuch that <qn<
pn≤ andqn→,pn→,qnn→a,pnn→b(a<b) asn→ ∞, thenlimn→∞[n]pn,qn→ ∞. It is natural to ask: What is the class of sequences (pn,qn) satisfyinglimn→∞[n]pn,qn=∞ when limn→∞pn= andlimn→∞qn= under <qn<pn≤? Undoubtedly, this is an
important problem. In this note, we will solve this problem in Section .
2 Main results
For <qn<pn≤, setqn:= –αn,pn:= –βnsuch that ≤βn<αn< ,αn→,βn→
asn→ ∞. In the sequel, we use notationan∼bn(an,bn> )⇔limn→∞bann= . First, let us present the following auxiliary proposition.
Lemma . Let n∈N,then as n→ ∞we have
[n]pn,qn→ ∞ ⇒ e
nβn/n→. (.)
On the other hand,
enαn/n→ ⇒ [n]
pn,qn→ ∞. (.)
Proof We note that
[n]pn,qn=q
n–
n +pnqnn–+· · ·+pnn–qn+pnn–=qnn–
+pn/qn+· · ·+ (pn/qn)n–
>nqnn–=n( –αn)(–/αn)(n–)(–αn)∼n/enαn, n→ ∞. (.)
Similarly, we have
[n]pn,qn=q
n–
n +pnqnn–+· · ·+pnn–qn+pnn–=pnn–
+qn/pn+· · ·+ (qn/pn)n–
<npnn–=n( –βn)(–/βn)(n–)(–βn)∼n/enβn, n→ ∞. (.)
Therefore, from (.) and (.), for sufficiently largen, there exist two positive real num-bersCandCsatisfying
C·n/enαn< [n]pn,qn<C·n/e
nβn. (.)
This yields the proof.
The main result of this work is expressed by the next assertion. Theorem . The following statements are true:
(A) Iflimn→∞en(βn–αn)= andenβn/n→,then[n]pn,qn→ ∞.
(B) Iflimn→∞en(βn–αn)< andenβn(α
n–βn)→,then[n]pn,qn→ ∞.
(C) Iflimn→∞en(βn–αn)< ,lim
n→∞en(βn–αn)= andmax{enβn/n,enβn(αn–βn)} →,then
[n]pn,qn→ ∞. Conversely,
(B) Iflimn→∞en(βn–αn)< and[n]pn,qn→ ∞,thenen
βn(α
n–βn)→.
(C) If limn→∞en(βn–αn) < ,lim
n→∞en(βn–αn) = and [n]pn,qn → ∞, then max{en
βn/n,
enβn(α
Proof Case (A):
If limn→∞en(βn–αn) = , sincelimn→∞enαn/n=limn→∞enβn/n/en(βn–αn) → and
com-bined with (.) imply [n]pn,qn→ ∞(see Remark .). Case (B) and Case (B):
Iflimn→∞en(βn–αn)< . Note that, for sufficiently largen,
[n]pn,qn=p
n–
n
– (qn/pn)n
–qn/pn ∼
enβn
– ( – (αn–βn)/( –βn))n
(αn–βn)/( –βn)
. (.)
Since
αn–βn
–βn →
, (.)
it is not difficult to obtain from (.) andlimn→∞en(βn–αn)< that, for sufficiently largen,
there existsc∈(, ) such that
–αn–βn –βn
n
∼en(βn–αn)<c. (.)
Setdn:= – ( –α–n–ββnn)
n, then for sufficiently largen,d
n> –c. Thus, from (.), (.) and
(.), we have
[n]pn,qn∼ enβn ·
dn
αn–βn
, (.)
which entails that
[n]pn,qn→ ∞ ⇔ e
nβn(α
n–βn)→. (.)
This yields the proof of Case (B) and Case (B). Case (C) and Case (C):
If limn→∞en(βn–αn)< ,lim
n→∞en(βn–αn)= . Since the sequence <xn:=en(βn–αn)<
is bounded, set E := {x|xis a limit point of{xn},n ≥ }, then supE = from
limn→∞en(βn–αn)= . Now, we are going to extract a subsequence{xnk}of{xn}such that
(a) limk→∞xnk= , and
(b) E:={x|xis a limit point of{x
n} \ {xnk}}, withsupE
< .
We verify that it is possible to extract such a subsequence{xnk}. Since is a limit point ofA:={xn,n≥}, take a subsequence{xn()
k }ofAsuch that
limk→∞xn()
k = , setA
():=
{x
n()k ,k≥}and letA:=A\A
(). If is also a limit point ofA
, take a subsequence{xn() k }
of
Asuch thatlimk→∞xn()
k = , setA
():={x
n()k ,k≥}and letA:=A\A
(). Continuing this
process, we obtain a series of sequences, i.e.,A(),A(), . . . , setAf:=A\
s∈I⊆NA(s). Since
Ais a countable set, this process will stop until is not a limit point ofAf after finite or
countable steps; otherwise, we will see that is the only limit point ofA, which contradicts to the assumptions of Case (C). Then we can take the subsequence{xnk}=
s∈NA(s)which
satisfies (a) and (b).
Set {xnk}:={xn} \ {xnk}, it is obvious that {nk,k≥} ∪ {nk,k≥}=N. Then from
limn→∞xnk < from (b), we also have seen from (B) that [n]pn
k,qnk → ∞ ⇔ en
kβn k(α
nk–βnk)→ ask→ ∞. In summary,
(i) limn→∞[n]pn,qn=∞ ⇔for any subsequence{Nk}of a natural number set such that
limk→∞Nk=∞, we havelimk→∞[n]pNk,qNk=∞.
(ii) Since{nk}k≥and{nk}k≥are two subsequences of a natural number set such that
limk→∞nk=∞andlimk→∞nk=∞, thus ask→ ∞
lim
n→∞[n]pn,qn=∞ ⇒
⎧ ⎨ ⎩
[n]pnk,qnk→ ∞ ⇔ enkβnk/nk→,
[n]pn
k,qnk→ ∞ ⇔ e
nkβn
k(α
nk–βnk)→.
We assert that the inverse proposition of (ii) also holds. Indeed, for each sufficiently large N> , there exists a positive integerKsuch that for every natural numberk>K, we have
[n]pnk,qnk >N; meanwhile, for the previousN> , there exists a positive integerK such
that for every natural numberk>K, we have [n]pn
k,qnk
>N; taken=max{nK,nK}, for every natural numbern>n, we have [n]pn,qn>N, i.e.,limn→∞[n]pn,qn=∞. Now we have proved that ask→ ∞
lim
n→∞[n]pn,qn=∞ ⇔ :=
⎧ ⎨ ⎩
enkβnk/nk→, (c) en
kβnk (αn
k–βnk)→. (d)
(.)
Next, we infer that ask→ ∞
⇔ lim
n→∞max
enβn/n,enβn(α
n–βn)
= . (.)
‘⇐’ of (.) is straightforward. Now we show ‘⇒’. On the one hand, by Remark (.),
we know from (d) ofthaten
kβnk
/nk→, and combined with (c)enkβnk/nk→, we can showenβn/n→ by using a similar method as in the previous paragraph. On the other hand,enkβnk(αn
k–βnk)→ is straightforward (sincelimk→∞xnk=limk→∞e
nk(βnk–αnk)
= ,
and note (c) in ), and combined withen
kβnk (αn
k –βnk)→, we can also deduce that enβn(α
n–βn)→. This yields the proof of ‘⇒’ in (.).
Therefore, (C) and (C) follow from (.) and (.). Remark . In general, from (.) we have only [n]pn,qn→ ∞ ⇒en
βn/n→. However, if
limn→∞en(βn–αn)= holds, then we have the equivalent relationenβn/n→⇔[n]
pn,qn→ ∞from (A). Thus, we have:
(A) Iflimn→∞en(βn–αn)= , thenenβn/n→⇔[n]pn,qn→ ∞. Similarly, from (B) and (B), (C) and (C) we have
(B) Iflimn→∞en(βn–αn)< , thenenβn(αn–βn)→⇔[n]pn,qn→ ∞.
(C) Iflimn→∞en(βn–αn)< ,limn→∞en(βn–αn)= , thenmax{enβn/n,enβn(αn–βn)} →⇔
[n]pn,qn→ ∞.
Remark . In Case (B), we can also deduce directly from limn→∞en(βn–αn) < and
enβn(α
com-bined with the classical inequality on upper (lower) limit
lim
n→∞e
n(αn–βn)· lim
n→∞e
n(βn–αn)≥ lim
n→∞
en(αn–βn)·en(βn–αn)= ,
we havelimn→∞en(αn–βn)> . Thus, for sufficiently largen, there existsc
> such that
en(αn–βn)>c
. This means that < (logc)enβn/n<enβn/n·(n(αn–βn))→, and we have
seen thatenβn/n→.
Remark . Now we utilize Theorem . (Remark .) to elaborate Example . again. In the example,βn= /
√
n, whileenβn/n=e√n/n asn→ ∞, thus [n]
pn,qn∞.
Forpn= ,βn= ,qn= –αn, thenenβn/n= /n→ andenβn(αn–βn) =αn→. Thus
any case of (A)-(C) is straightforward. In this case, (pn,qn)-integer reduces toqn-integer,
and it is known that [n]qn→ ∞ ⇔qn→ as n→ ∞. See [], Theorem , and [],
formula (.).
3 Conclusion
In this note, we mainly obtain the sufficient and necessary conditions for (p,q)-integer [n]p,q tending to infinity as n→ ∞. The conclusion guarantees the (p,q)-analogue of
Bernstein-type operators to be approximation processes asn→ ∞.
Acknowledgements
The paper has been greatly improved by the efforts of the anonymous referees through their diligent reading of and perceptive comments on an initial draft.
This work is supported by the National Natural Science Foundation of China (Grant No. 61572020,11601266), the China Postdoctoral Science Foundation funded project (Grant No. 2015M582036) and the Natural Science Foundation of Fujian Province of China (Grant No. 2016J05017). We also thank Fujian Provincial Key Laboratory of Data Intensive Computing and Key Laboratory of Intelligent Computing and Information Processing of Fujian Province University.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
XWX carried out the proof of the main results. QBC read and approved the final manuscript.
Author details
1School of Mathematics and Computer Science, Quanzhou Normal University, Quanzhou, China.2School of Mathematical Sciences, Xiamen University, Xiamen, China.
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Received: 23 February 2017 Accepted: 1 June 2017 References
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