Solved Problems by Ian Ray P. Genebraldo Solved Problems by Ian Ray P. Genebraldo Problem 7-1
Problem 7-1
An SI engine operating at 1200 RPM has a 10.2-m bore !ith the spar" pl#g An SI engine operating at 1200 RPM has a 10.2-m bore !ith the spar" pl#g o$set by %-mm
o$set by %-mm &rom enter&rom enter. 'he spar" . 'he spar" pl#g is (red at 20) pl#g is (red at 20) b'*+. It ta"es %.,) o&b'*+. It ta"es %.,) o& engine rotation &or omb#stion to develop and get into ame
engine rotation &or omb#stion to develop and get into ame propagatiopropagation moden mode !here the average ame speed is 1,./ mse.
!here the average ame speed is 1,./ mse. +al#late
+al#late a3
a3 'ime o& one omb#'ime o& one omb#stion proess a&ter ame has devstion proess a&ter ame has developed i.e. time &oreloped i.e. time &or ame &ront to reah the &#rthest
ame &ront to reah the &#rthest ylinder !all3. 4se5ylinder !all3. 4se5 b3
b3 +ran" angle posi+ran" angle position at the end otion at the end o& omb#stion.& omb#stion. Sol#tion
Sol#tion a3
a3 6lame travel d6lame travel distane boistane bore23 8o$setre23 8o$set *
*tt 10.2 m23 8 0.% 10.2 m23 8 0.% m ,.7 mm ,.7 m
'ime *
'ime *tt 9 9& & 0.0,7 m31,./ mse3 0.0,7 m31,./ mse3 0.0036 sec0.0036 sec
b3
b3 +omb#stion starts +omb#stion starts at 1:.,) bat 1:.,) b'*+'*+ 'ime o& o
'ime o& omb#stion in degmb#stion in degrees o& enginrees o& engine rotatione rotation 0.00:% se31200%0 revse3:%0)rev3 2,.;) 0.00:% se31200%0 revse3:%0)rev3 2,.;) +ran" position at end o&
+ran" position at end o& omb#stionomb#stion 2,.;) < 1:.,)
2,.;) < 1:.,) 12.4⁰ aTDC12.4⁰ aTDC
Problem 7-2 Problem 7-2
It is desired that ame termination be at the same ran" angle position !hen the speed o& the engine in Problem 7-1 is inreased to 2000 RPM. In this range ame development ta"es the same amo#nt o& real time and ame speed is related to engine speed as 9& is proportional to 0.;2=.
+al#late
a3 6lame speed at 2000 RPM. 4mse5
b3 +ran" angle position !hen the spar" pl#g sho#ld be (red. 3 +ran" angle position !hen ame propagation starts.
Sol#tion
a3 9el2000 0.;232000120031,./ ms3 24.23 m/sec
b3 'ime o& omb#stion development
t %.,)34:%0)rev31200%0 revse35 0.000;0 se 'ime o& omb#stion at 2000 rpm
t *& 9el& 0.0,7 m3 2>.2: mse3 0.002:, se
'otal time o& ignition and omb#stion at 2000 rpm t 0.000;0 se3 8 0.002:, se3 0.00:2, se 'otal time in degrees o& engine rotation
0.00:2, se32000%0 revse3:%0)rev3 :;)
6or omb#stion to end at 12.>) a'*+ spar" pl#g m#st be (red at :;) - 12.>) 26.6 bTDC
3 ?ngine rotation d#ring omb#stion
0.002:, se32000%0 revse3:%0)rev3 2/.2) +omb#stion m#st start at
2/.2) - 12.> 15.8⁰ bTDC
Problem 7-:
A +I engine !ith a :.2-inh bore and :.;-inh stro"e operates at 1/,0 RPM. In eah yle &#el in@etion starts at 1%) b'*+ and lasts &or 0.001; seond. +omb#stion
starts at /) b'*+. *#e to the higher temperat#re the ignition delay o& any &#el in@eted a&ter omb#stion starts is red#ed by a &ator o& t!o &rom the original I*. +al#late
a3 I* o& (rst &#el in@eted. 4se5
b3 I* o& (rst &#el in@eted in degrees o& engine rotation.
3 +ran" angle position !hen omb#stion starts on last &#el droplets in@eted. Sol#tion
a3 I* o& (rst &#el in@eted /) o& rotation
t /)34:%0)rev31/,0%0 revse35 0.00072 sec
b3 I* o& (rst &#el in@eted in degrees o& engine rotation start o& in@etion < start i& omb#stion
I* 1%) - /) 8⁰
3 Ignition delay is hal& o& original I* I* 0.00072 se32 0.000:% se
'ime bet!een the start o& in@etion and (nal in@etion o& &#el droplets t 0.001; se3 8 0.000:% se3 0.0022% se
In degrees o& engine rotation 0.0022% se31/,0%0 revse3:%0)rev3 2,.1)
+ran" position !hen last droplets start to omb#st 1%) b'*+ 8 2,.1) 9.1⁰ aTDC
Problem 7->
A :.2-liter SI engine is to be designed !ith bo!l-in-piston omb#stion hambers. ith a entral spar" pl#g and omb#stion at '*+ this gives a ame
travel distane o& B>. 'he engine is to operate !ith an average piston speed o& / mse and a b#rn angle o& 2,) o& ran" rotation. Stro"e and bore !ill be related by S 0.;,B.
+al#late
a3 Average ame speed i& the design is &or an in-line &o#r-ylinder engine. 4mse5
b3 Average ame speed i& the design is &or a 9/ engine. 4mse5 Sol#tion
a3 6or 1 ylinder o& a > ylinder engine
9d :.2 C3> 0./ C 0.000/ m: π >3B2S π >3B20.;,3
B 0.102:, m S 0.;,30.102:,3 0.0;72 m 6inding the engine speed
Dp / mse 2S= 2 stro"esrev30.0;72 mstro"e3=
= >1.1, revse 2>%; rpm
'ime o& ame t 2,)34:%0)rev3>1.1, revse35 0.001%; se
*istane o& ame travel *& B> 0.102:, m3> 0.02,,; m
6lame speed 9& *& t 0.02,,; m30.001%; se3 15.15
m/sec
b3 6or 1 ylinder o& 9/ engine
9d :.2 C3/ 0.> C 0.000> m: π >3B2S π >3B20.;,3
B 0.0/12>m S 0.;,30.0/12>3 0.0771/ m 6inding the engine speed
Dp / mse 2S= 2 stro"esrev30.771/ mstro"e3=
= ,1./: revse :110 rpm
'ime o& ame t 2,)34:%0)rev3,1./: revse35 0.001:> se
*istane o& ame travel *& B> 0.0/12> m3> 0.020:1 m
6lame speed 9& *& t 0.020:1 m30.001:> se3 15.15
m/sec
A large +I engine operating at :10 RPM has open omb#stion hambers and diret in@etion !ith 2%-m bores a 7:-m stro"e and a ompression ratio o&
1%.,1. 6#el in@etion in eah ylinder starts at 21) b'*+ and lasts &or 0.01; seonds. I* is 0.00%, seonds.
+al#late
a3 I* in degrees o& engine rotation.
b3 +ran" angle position !hen omb#stion starts. 3 +ran" angle position !hen in@etion stops. Sol#tion
a3 I* 0.00%, se3:10%0 revse3:%0)rev3 12.1)
b3 +ran" angle start o& omb#stion3 angle o& &#el in@etion 8 angle o& I* 21) b'*+ 8 12.1) 8.9⁰ bTDC
3 ?ngine rotation per in@etion d#ration o& &#el in@etion3rps3:%0)rev3 0.01; se3:10%0 revse3:%0)rev3 :,.:)in@etion
+ran" angle end o& in@etion3 angle o& &#el in@etion 8 engine rotation per in@etion