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Hybrid projected subgradient-proximal algorithms for solving split equilibrium problems and split common fixed point problems of nonexpansive mappings in Hilbert spaces

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R E S E A R C H

Open Access

Hybrid projected subgradient-proximal

algorithms for solving split equilibrium

problems and split common fixed point

problems of nonexpansive mappings in

Hilbert spaces

Anteneh Getachew Gebrie

1

and Rabian Wangkeeree

1,2*

*Correspondence:

[email protected]

1Department of Mathematics,

Faculty of Science, Naresuan University, Phitsanulok, Thailand

2Research Center for Academic

Excellence in Mathematics, Naresuan University, Phitsanulok, Thailand

Abstract

In this paper, we propose two strongly convergent algorithms which combines diagonal subgradient method, projection method and proximal method to solve split equilibrium problems and split common fixed point problems of nonexpansive mappings in a real Hilbert space: fixed point set constrained split equilibrium problems (FPSCSEPs) in real Hilbert spaces. The computations of first algorthim requires prior knowledge of operator norm. To estimate the norm of an operator is not always easy, and if it is not easy to estimate the norm of an operator, we purpose another iterative algorithm with a way of selecting the step-sizes such that the implementation of the algorithm does not need any prior information as regards the operator norm. The strong convergence properties of the algorithms are established under mild assumptions on equilibrium bifunctions. We also report some

applications and numerical results to compare and illustrate the convergence of the proposed algorithms.

Keywords: nonexpansive mappings; common fixed point problem; equilibrium problem; split equilibrium problem; monotone bifunction; pseudomonotone bifunction; diagonal subgradient method; projected subgradient-proximal algorithm

1 Introduction

In 1994 Censor and Elfving [1] introduced a notion of the split feasibility problem, which is to find an element of a closed convex subset of the Euclidean space whose image un-der a linear operator is an element of another closed convex subset of a Euclidean space. Then, in 2009 Censor and Segal [2] introduced the split common fixed point problem (SCFPP) where split feasibility problem becomes a special case of SCFPP. Many convex optimization problems in a Hilbert space can be written in the form of SCFPP and SCFPPs have played an import role in the study of several unrelated problems arising in physics, finance, economics, network analysis, elasticity, optimization, water resources, medical images, structural analysis, image analysis and several other real-world applications (see,

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e.g., [3, 4]). As they have a wide range of applications SCFPPs have emerged as an inter-esting and fascinating research area of mathematics.

Letbe a nonempty closed convex subset of a real Hilbert space H equipped with the inner product·,·and with the corresponding norm · and letU:be an operator. We denote byFixU={x:Ux=x}the subset of fixed points ofU. We say thatUis nonexpansive ifU(x) –U(y) ≤ xyx,y.

Throughout the paper, unless otherwise is stated, we assume thatH1 andH2 be two real Hilbert spaces andA:H1→H2be a nonzero bounded linear operator. SupposeCbe nonempty closed convex subset ofH1andT:CCbe nonexpansive operator, andD be nonempty closed convex subset ofH2andV:DDbe nonexpansive operator. Given two bifunctionsf :C×C→Randg:D×D→R. The notationEP(f,C) represents the following equilibrium problem:find x∗∈C such that f(x∗,y)≥0∀yC, andSEP(f,C) represents its solution set. Many problems in physics, optimization, and economics can be reduced to find the solution of equilibrum problemEP(f,C); see,e.g., [5]. In 1997, Com-bettes and Hirstoaga [6] introduced an iterative scheme of finding the solution ofEP(f,C) under the assumption thatSEP(f,C) is nonempty. Later on, many iterative algorithms are considered to find the element ofFixT∩SEP(f,C); see [7–10]. In 2013, Kazmi and Rizvi [11] considered a split equilibrium problem (SEP):

findx∗∈H1such that ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

x∗∈C,

f(x∗,y)≥0, ∀yC,

u∗=Ax∗∈D,

g(u∗,u)≥0, ∀uD.

They introduced the iterative scheme which converges strongly to a common solution of the split equilibrium problem, the variational inequality problem and the fixed point prob-lem for a nonexpansive mapping. Many researchers have also been proposed algorithms for finding solution point of SEP; see, for example, [12–14] and the references therein. Hieu [14] proposed an algorithm for solving SEP which combines three methods includ-ing the projection method, the proximal method and the diagonal subgradient method. Recently, Dinh, Son, and Anh [15] considered the following fixed point set-constrained split equilibrium problems (FPSCSEPs):

findx∗∈Csuch that ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

x∗∈FixT,

f(x∗,y)≥0, ∀yC,

u∗=Ax∗∈FixV,

g(u∗,u)≥0, ∀uD.

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LetSFPSCSEP(f,C,T;g,D,V) or simplySdenotes the solution set of FPSCSEP (1). The problem (1) includes two fixed point set-constrained equilibrium problems (FPSCEPs). Consider the following fixed point set-constrained equilibrium problem (FPSCEP(f,

C,T)):

findx∗∈Csuch that ⎧ ⎨ ⎩

x∗∈FixT,

(3)

and letSFPSCEP(f,C,T) or simplyS1 denotes its solution set. Similarly, letFPSCEP(g,

D,V) denote the fixed point set-constrained equilibrium problem

findu∗∈Dsuch that ⎧ ⎨ ⎩

u∗∈FixV,

g(u∗,u)≥0, ∀uD,

(3)

andSFPSCEP(g,D,V) or simplyS2denotes its solution set. Therefore, from (1), (2), and (3) we haveS={x∗∈S1:Ax∗∈S2}. Moreover,S1={x∗∈C:x∗∈SEP(f,C)∩FixT}. Sim-ilarly,S2={u∗∈D:u∗∈SEP(g,D)∩FixV}. In [15], Dinh, Son, and Anh proposed the extragradient algorithms for finding a solution of the problem (FPSCSEP). Under certain conditions on parameters, the proposed iteration sequences are proved to be weakly and strongly convergent to a solution of (FPSCSEP). Furthermore, Dinh, Son, Jiao and Kim [16] proposed the linesearch algorithm which combines the extragradient method incor-porated with the Armijo linesearch rule for solving the problem (FPSCSEP) in real Hilbert spaces under the assumptions that the first bifunction is pseudomonotone with respect to its solution set, the second bifunction is monotone, and fixed point mappings are non-expansive. For obtaining a strong convergence result, they combined the proposed algo-rithm with hybrid cutting technique. The main advantages of the two mentioned extra-gradient methods are that they can be worked with pseudomonotone bifunctions and also the subproblems can be numerically solved more easily than subproblems in the proximal method. However, the problems of solving strongly convex optimization subproblems and of finding shrinking projections in [15, 16] is expensive excepts special cases when the fea-sible set has a simple structure.

In this paper, we propose two strongly convergent algorithms for finding a solution of the problem (FPSCSEP). In the first algorithm, two projections on feasible set and a projected subgradient step followed by a proximal step is need to be computed per each iteration. In the second algorithm, we propose a modification of the first algorithm where the second projection is performed on feasible set while the first projection over C is replaced by a projection onto a tangent plane to C in order to reduce the number of optimization sub-problems to be solved. Moreover, in the second algorithm, a way of selecting an adaptive step-size in the second projection has allowed us to avoid the prior knowledge of operator norm. Comparing with the algorithms in [15, 16], the proposed algorithms has a simple structure, and the metric projection, in general, is simpler than solving strongly convex optimization subproblems on a same feasible set and finding shrinking projections.

The paper is organized as follows. In the next section we describe the properties and lemmas which will be used in the proof for the convergence of the proposed algorithms. The algorithms and the convergence analysis of the algorithms is presented in the third section. Finally, in the last section we will see applications supported by an example and numerical results.

2 Preliminary

To investigate the convergence of our proposed algorithm, in this section we will introduce notations, and recall properties and technical lemmas which will be used in the sequel. We writexnxto indicate that the sequence{xn}converges weakly toxasn→ ∞, and

(4)

Letbe a subset of a real Hilbert spaceHandf :×→Rbe a bifunction. Thenf

is said to be

(i) strongly monotoneon, if there isM> 0(shortlyM-strongly monotone on) iff

f(x,y) +f(y,x)≤–Myx2, ∀x,y;

(ii) monotoneoniff

f(x,y) +f(y,x)≤0, ∀x,y;

(iii) pseudomonotoneonwith respect toxiff

f(x,y)≥0 implies f(y,x)≤0, ∀y.

We say thatf is pseudomonotone onwith respect toif it is pseudomonotone onwith respect to everyx. When=,fis called pseudomonotone on. Clearly, (i)⇒(ii)⇒(iii) for everyx.

Definition 2.1 Letbe a nonempty closed convex subset of a real Hilbert spaceH. The metric projection onis a mappingP:Hdefined by

P(x) =arg minyx:y.

Properties Letbe a nonempty closed convex subset of a real Hilbert spaceHand letP is a metric projection on. Sinceis nonempty, closed and convex,P(x) exists and is unique. From the definition ofP, it is easy to show thatPhas the following characteristic properties.

(i) For ally,

P(x) –xxy.

(ii) For allx,y,

P(x) –P(y)2≤ P(x) –P(y),xy, ∀x,yH.

(iii) For allx,yH,

xP(y)2+P(y) –y2≤ xy2.

(iv) z=P(x)if and only ifxz,yz ≤0,∀y.

Definition 2.2 LetHbe a Hilbert space andf:×→Rbe a bifunction wheref(x,·) is convex function for eachxin. Then for≥0 the-subdifferential (-diagonal subd-ifferential) off atx, denoted by∂f(x,·)(x) or∂f(x,x), is given by

∂f(x,·)(x) =

(5)

Lemma 2.1 Givenλ∈[0, 1],x,yH where H is Hilbert space.Then

λx+ (1 –λ)y2=λx2+ (1 –λ)y2–λ(1 –λ)xy2.

Lemma 2.2(Opial’s condition) For any sequence{xk}in the Hilbert space H with xkx,

the inequality

lim inf

k→+∞

xkx<lim inf

k→+∞

xky

holds for each yH with y=x.

The next lemma will be a useful tool to obtain the boundedness of the sequences gen-erated by the algorithms and also to obtain the convergence of the whole sequence to the solution.

Lemma 2.3 If{ak}∞k=0and{bk}∞k=0are two nonnegative real sequences such that

ak+1≤ak+bk, ∀k≥0

withk=0bk<∞,then the sequence{ak}∞k=0converges.

Lemma 2.4 Letbe closed and convex subset of a Hilbert space H.If U:is non-expansive,thenFixU is closed and convex.

Now, we assume that the bifunctions g:D×D→Randf :C×C→Rsatisfy the following assumptions, Condition A and Condition B, respectively.

Condition A

(A1) g(u,u) = 0, for alluD.

(A2) gis monotone onD,i.e.,g(u,v) +g(v,u)≤0, for allu,vD. (A3) For eachu,v,wD,

lim sup

α↓0

gαw+ (1 –α)u,vg(u,v).

(A4) g(u,·)is convex and lower semicontinuous onDfor eachuD.

Condition B

(B1) f(x,x) = 0for allxC.

(B2) f is pseudomonotone onCwith respect tox∈SEP(f,C),i.e., ifx∈SEP(f,C)then

f(x,y)≥0impliesf(y,x)≤0,∀yC.

(B3) f satisfies the following condition, called the strict paramonotonicity property:

x∈SEP(f,C),yC, f(y,x) = 0⇒y∈SEP(f,C).

(B4) f is jointly weakly upper semicontinuous onC×Cin the sense that, ifx,yCand {xk},{yk} ⊂Cconverge weakly toxandy, respectively, thenf(xk,yk)→f(x,y)as

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(B5) f(x,·)is convex, lower semicontinuous and subdifferentiable onC, for allxC. (B6) If{xk}is bounded sequence inCand

k→0, then the sequence{wk}with

wk kf(x

k,·)(xk)is bounded.

The following three results are from equilibrium programming in Hilbert spaces.

Lemma 2.5([17, Lemma 2.12]) Let g satisfies ConditionA.Then,for each r> 0and uH2,

there exists wD such that

g(w,v) +1

rvw,wu ≥0, ∀vD.

Lemma 2.6([17, Lemma 2.12]) Let g satisfy ConditionA.Then,for each r> 0and uH2,

define a mapping(called the resolvent of g),given by

Tg r(u) =

wD:g(w,v) +1

rvw,wu ≥0,∀vD

.

Then the following holds: (i) Trg is single-valued;

(ii) Trg is a firmly nonexpansive,i.e.,for allu,vH,

Trg(u) –Trg(v)2≤ Trg(u) –Trg(v),uv;

(iii) Fix(Trg) =SEP(g,D),whereFix(Trg)is the fixed point set ofTrg; (iv) SEP(g,D)is closed and convex.

Lemma 2.7 ([17, Lemma 2.12]) For r,s> 0 and u,vH2. Under the assumptions of Lemma2.6,then

Tg

r(u) –Tsg(v)≤ uv+ |sr|

s T

g s(v) –v

3 Main result

In this section, we propose two strongly convergent algorithms for solving FPSCSEPs (1) which combines three methods including the projection method, the proximal method and the diagonal subgradient method.

3.1 Projected subgradient-proximal algorithm

Algorithm 3.1

Initialization: Choosex0∈C. Take{ρk},{βk},{k},{rk},{δk}and{μk}such that

ρkρ> 0, βk≥0, k≥0, rkr> 0, 0 <a<δk<b< 1,

0 <cμkb< 1 A2,

k=0

βk

ρk = +∞,

k=0

βkk

ρk < +∞,

k=0

βk2< +∞.

Step 1: TakewkH

(7)

Step 2: Calculate

αk=

βk

ηk

, ηk=max

ρk,wk

and

yk=PC

xkαkwk

.

Step 3: Evaluate

tk=δkxk+ (1 –δk)T

yk.

Step 4: Evaluate

uk=TrgkAtk.

Step 5: Evaluate

xk+1=PC

tk+μkA

VukAtk.

Step 6: Setk:=k+ 1 and go to Step 1.

Remark 3.1 Sincef(x,·) is a lower semicontinuous convex function andC⊂domf(x,·) for everyxC, then thek-diagonal subdifferential∂kf(x

k,·)(xk)=for every k> 0. Moreover,ρkρ> 0. Therefore, each step of the algorithm are well defined, implying that Algorithm 3.1 is well defined.

Remark 3.2 fis pseudomonotone onCwith respect toSEP(f,C), then under Condition B ((B1) and (B4)), the setSEP(f,C) is closed and convex.

Therefore, by Lemma 2.4, Remark 3.2 and by the linearity property of the operatorA

the solution setSof the FPSCSEP is convex and closed. In this paper, the solution setSis assumed to be nonempty.

Lemma 3.1 Let{yk},{tk}and{xk}be sequences generated by Algorithm3.1.For xS,

tkx∗2≤xkx∗2+ 2αk(1 –δk)f

xk,x∗–Lk+ξk,

where

Lk= (1 –δk)xkyk 2

+δk(1 –δk)T

ykxk2

and

ξk= 2(1 –δk)

βkk

ρk

(8)

Proof Letx∗∈S. Fromyk=P

C(xkηβkkwk) andx∗∈Swe have

xkαkwkyk,ykx

≥0,

implying that

x∗–yk,xkykαkwk,x∗–yk

=αkwk,x∗–xk

+αkwk,xkyk

αkwk,x∗–xk

+αkwkxkyk. (4)

But alsoxkC. Thus,

xkαkwkyk,ykxk

≥0,

and this together with (4) gives us

xkyk,xkyk=xkyk2≤αkwk,xkyk

αkwkxkyk.

That is,

xkykαkwk.

Thus,

αkwkxkyk

αkwk2=

βkwk

ηk 2

=βk2

wk

max{ρk,wk} 2

βk2. (5)

SincexkCandwk∂kf(x

k,·)(xk) we have

fxk,x∗+k=f

xk,x∗–fxk,xk+k

wk,x∗–xk. (6)

Using the definitions ofαkandηkwe obtain

αk=

βk

ηk

= βk

max{ρk,wk}≤

βk

ρk

. (7)

From (4)-(7) we have

x∗–yk,xkykαkf

xk,x∗+βkk

ρk

+βk2. (8)

But

(9)

From (8) and (9) we have

ykx∗2≤xnx∗2–xkyk2+ 2αkf

xk,x∗+ 2βkk

ρk

+ 2βk2. (10)

Then by definition oftkwe have tkx∗2=δkxk+ (1 –δk)T

ykx∗2

=δk

xkx∗+ (1 –δk)

Tykx∗2

=δkxkx∗2+ (1 –δk)T

ykx∗2–δk(1 –δk)T

ykxk2

=δkxkx∗2+ (1 –δk)T

ykTx∗2–δk(1 –δk)T

ykxk2

δkxkx∗ 2

+ (1 –δk)ykx∗ 2

δk(1 –δk)T

ykxk2,

and this together with (10) we have

tkx∗2δ

kxkx∗ 2

+ (1 –δk)

xkx∗2–xkyk2

+ 2αkf

xk,x∗+ 2βkk

ρk + 2βk2

δk(1 –δk)T

ykxk2.

That is,

tkx∗2≤xkx∗2+ 2αk(1 –δk)f

xk,x∗–Lk+ξk,

where

Lk= (1 –δk)xkyk 2

+δk(1 –δk)T

ykxk2

and

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2.

Remark 3.3 Sincex∗∈SEP(C,f) we havef(x∗,x)≥0 for allxC, and by pseudomono-tonicity off with respect toSEP(C,f) we havef(x,x∗)≤0 for allxC. Thus since the sequence{xk}is inCwe havef(xk,x)0. Thus, we can also have

tkx∗2≤xkx∗2–Lk+ξk. (11)

Lemma 3.2 Let{yk},{uk},and{xk}be sequences generated by Algorithm3.1.Let xS. Then

xk+1–x∗2≤xkx∗2+ 2(1 –δk)αkf

xk,x∗+ξkKk,

where

Kk=μk

1 –μkA2V

ukAtk2+μkukAtk2+ (1 –δk)xkyk2

+δk(1 –δk)T

(10)

and

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2.

Proof Letx∗∈S. By Lemma 2.6, we have

Trg kAt

kAx∗2 =Trg

kAt

kTg rkAx

∗2

TrgkAtkTrgkAx∗,AtkAx

= TrgkAtkAx∗,AtkAx

=1 2T

g rkAt

kAx∗2

+AtkAx∗2–Trg kAt

kAtk2 .

That is,

Trg kAt

kAx∗2 ≤1

2T g rkAt

kAx∗2

+AtkAx∗2–Trg kAt

kAtk2

. (12)

In view of (12), we have

TrgkAtkAx∗2≤AtkAx∗2–TrgkAtkAtk2.

Thus,

VukAx∗2=VTrgkAtkVAx∗2

=TrgkAtkAx∗2

AtkAx∗2–TrgkAtkAtk2, (13)

which gives

Atkx∗,VukAtk

= Atkx∗+VukAtkVuk+Atk,VukAtk

= VukAx∗,VukAtkVukAtk2

=1 2V

ukAx∗2+VukAtk2–AtkAx∗2–VukAtk2

=1 2V

ukAx∗2–VukAtk2–AtkAx∗2.

Hence,

Atkx∗,VukAtk

=1 2V

ukAx∗2–VukAtk2–AtkAx∗2. (14)

From (13) and (14) we have

Atkx∗,VukAtk≤–1 2T

g rkAt

(11)

Then from (13) and (15) we have

xk+1x∗2

=PC

tk+μkA

VukAtkPC

x

tkx∗+μk

VukAtk2

=tkx∗2+μkA

VukAtk2+ 2μktkx∗,A

VukAtk

tkx∗2+μ2kA∗2VukAtk2+ 2μkA

tkx∗,VukAtk

tkx∗2+μ2kA∗2VukAtk2–μkTαgkAt

kAtk2

+VukAtk2

=tkx∗2–μk

1 –μkA2V

ukAtk2–μkTrgkAt

kAtk2

=tkx∗2–μk

1 –μkA2V

ukAtk2–μkukAtk2

=tkx∗2–μk

1 –μkA2V

ukAtk2–μkukAtk 2

.

That is,

xk+1–x∗2≤tkx∗2–μk

1 –μkA2V

ukAtk2–μkukAtk 2

. (16)

Therefore, from Lemma 3.1 and from (16) we have

xk+1–x∗2≤xkx∗2+ 2αk(1 –δk)f

xk,x∗–Lk+ξk

μk

1 –μkA2V

ukAtk2–μkukAtk 2

. (17)

That is,

xk+1–x∗2≤xkx∗2+ 2(1 –δk)αkf

xk,x∗+ξkKk, (18)

where

Kk=μk

1 –μkA2V

ukAtk2+μkukAtk 2

+ (1 –δk)xkyk 2

+δk(1 –δk)T

ykxk2

and

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2.

Lemma 3.3 Let{yk},{tk},{uk},and{xk}be sequences generated by Algorithm3.1.Then: (i) Forx∗∈S,the limit of the sequence{xkx∗2}exists(and{xk}is bounded). (ii) lim supk→∞f(xk,x) = 0for allxS.

(iii)

lim

k→∞V

ukAtk= lim

k→∞u

kAtk= 0,

lim

k→∞

xkyk= lim

k→∞

(12)

(iv)

lim

k→∞t

kxk= lim k→∞T

xkxk= lim

k→∞V

ukuk= 0.

Proof (i) Letx∗∈S. Sincef(xk,x)0,K

k≥0, from Lemma 3.2 we can have

xk+1–x∗2≤xkx∗2+ξk.

Observing thatξk= 2(1 –δk)βkρk

k + 2(1 –δk)β

2 k≤2

βkk

ρk + 2β

2

k and using the initialization condition of the parameters we can see that∞k=0ξk<∞.

Therefore,limk→∞xkx∗2exists and this implies that the sequence{xk}is bounded.

(ii) From lemma 3.2 we have

Kk+ 2(1 –δk)αk

fxk,x

xkx∗2–xk+1–x∗2+ξk

=xkx∗2–xk+1–x∗2+ 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2

xkx∗2–xk+1–x∗2+ 2βk

ρk

k+ 2βk2.

Summing up the above inequalities for everyN, we obtain

0≤ N

k=0

Kk+ 2(1 –δk)αk

fxk,x

N

k=0

xkx∗2–xk+1–x∗2+ 2βk

ρk

k+ 2βk2

.

This will yield

0≤ N

k=0

Kk+ N

k=0

2(1 –δk)αk

fxk,x

x0–x∗2–xN+1–x∗2+ 2 N

k=0

βk

ρk

k+ 2 N

k=0

βk2.

LettingN→+∞, we have

0≤

k=0

Kk+

k=0

2(1 –δk)αk

fxk,x∗< +∞.

Hence,

k=0

(13)

and

k=0

2(1 –δk)αk

fxk,x∗< +∞.

Since the sequence{xk}is bounded by Condition B(B6) the sequence{wk}is also bounded. Thus, there is a real numberwρsuch thatwkw. Thus,

αk=

βk

ηk

= βk

max{ρk,wk}

= βk

ρkmax{1,w

k

ρk }

βkρ

ρkw

. (20)

Noting

0≤2(1 –b)

k=0 αk

fxk,x∗≤ ∞

k=0

2(1 –δk)αk

fxk,x∗< +∞,

we have

0≤2(1 –b)

k=0 αk

fxk,x∗< +∞. (21)

From (20) and (21) we have

0≤2(1 –b)

k=0

βkρ

ρkw

fxk,x∗≤2(1 –b)

k=0 αk

fxk,x∗< +∞.

That is,

0≤2ρ(1 –b)

wk=0 βk ρk

fxk,x∗< +∞.

Since∞k=0βk

ρk = +∞and –f(x

,xk)0 we can conclude that

lim sup

k→∞ f

xk,x= 0

for allxS.

(iii) From (19) and since 0 <cμkb<A12, 0 <δk< 1 we have

lim

k→∞V

ukAtk2= lim

k→∞u

kAtk2 = lim

k→∞x

kyk2 = lim

k→∞T

ykxk2= 0.

Hence, the result follows.

(iv) The result follows from (iii) and from the following inequalities:

tkxkδkxk+ (1 –δk)T

ykxk= (1 –δk)xkT

ykxkTyk, TxkxkTxkTyk+xkTykxkyk+xkTyk,

(14)

Theorem 3.4 Assume ConditionAand ConditionBare satisfied and let{yk},{tk},{uk},

and{xk},be sequences generated by Algorithm3.1.Then the sequences{yk},{tk}and{xk}

converge strongly to a point pS and{uk}converge strongly to a point ApS2.Moreover,

p= lim

k→+∞PS

xk.

Proof Letx∗∈S. From Lemma 3.3(i) we have seen that the sequence{xk} is bounded. There exists a subsequence {xkj} of {xk} such that xkj pas j+, where pC

and

lim sup

j→+∞

fxkj,x= lim

i→+∞f

xki,x.

But by the weakly upper semicontinuity off(·,x∗) and by Lemma 3.3(ii) we have

fp,x∗≥lim sup

j→+∞

fxkj,x= lim

i→+∞f

xki,x=lim sup

k→+∞ f

xk,x∗= 0.

Sincex∗∈SandpCwe havef(x∗,p)≥0. Asf is pseudomonotone we havef(p,x∗)≤0. Thus, this together with the above fact givesf(x∗,p) = 0. Hence, by Condition B(B3) we havep∈SEP(f,C).

Since

ykj,h= ykjxkj,h+ xkj,h,hH1,

and usinglimk→+∞xkyk= 0 from Lemma 3.3 we haveykjpasj→+∞. Therefore,

AykjApasj→+∞. Similarly, we can havetkjpasj→+∞and henceAtkjApas j→+∞.

Assumep∈/FixT, that is,T(p)=p. Thus, using Opial’s condition and Lemma 3.3

lim inf

j→+∞x

kjp<lim inf

j→+∞x

kjT(p)

=lim inf

j→+∞x

kjTxkj+TxkjT(p)

≤lim inf

j→+∞

xkjTxkj+TxkjT(p)

=lim inf

j→+∞

TxkjT(p)

≤lim inf

j→+∞

xkjp,

which is a contradiction. Hence, it must be the case thatp∈FixT. Hence,

pS1. (22)

Sincelimk→+∞ukAtk= 0 and

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we have ukj Ap asj→+∞. Assume Ap/ FixV. Thus, using Opial’s condition and

Lemma 3.2

lim inf

j→+∞

ukjAp<lim inf

j→+∞

ukjV(Ap)

=lim inf

j→+∞u

kjVukj+VukjV(Ap)

≤lim inf

j→+∞u

kjVukj+VukjV(Ap)

=lim inf

j→+∞

VukjV(Ap)

=lim inf

j→+∞

ukjAp,

which is a contradiction. Hence, it must be the case thatAp∈FixV. Letr> 0. Assume

Ap∈/ Fix(Trg). Thus,Trg(Ap)=Ap. Thus, using Opial’s condition, Lemma 3.2, Lemma 3.3 we obtain the following:

lim inf

j→+∞At

kjAp<lim inf

j→+∞At

kjTg

r(Ap)

=lim inf

j→+∞At

kjukj+ukjTg

r(Ap)

≤lim inf

j→+∞

Atkjukj+ukjTg

r(Ap)

=lim inf

j→+∞

ukjTg

r(Ap)

=lim inf

j→+∞T

g rkj

AtkjTg

r(Ap)

≤lim inf

j→+∞

AtkjAp+|rkjr| rkj

TrgAtkjAtkj

=lim inf

j→+∞

AtkjAp+|rkjr| rkj

ukjAtkj

=lim inf

j→+∞

AtkjAp,

which is a contradiction. Hence, it must be the case thatAp∈Fix(Trg). By Lemma 2.6(iii) we haveAp∈SEP(g,D). Therefore,

ApS2. (23)

Therefore, from (22) and (23) we havepS. That is,pSandpis a weak cluster point of the sequence{xk}. By Lemma 3.3{xkp2}converges. Hence, we conclude that the sequence{xk}strongly converges top. As a result of this it is easy to see thattkpand

ykpasj→+∞. Moreover,AykAp,AtkAp, andAxkAp. From

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we haveukAp. We will end the proof by showingp=lim

k→+∞PS(xk). From Lemma 3.2 we have

xk+1–x∗2≤xkx∗2+ξk, ∀x∗∈S. (24)

Letzk=PS(xk). SincePS(xk)∈Swe have

xk+1–zk2≤xkzk2+ξk. (25)

But by property of metric projection we have

xk+1zk+12xk+1x∗2, xS.

Thus,

xk+1–zk+12≤xk+1–zk2. (26)

From (25) and (26) we have

xk+1–zk+12≤xkzk2+ξk.

Since∞k=0ξk<∞, by Lemma 2.3 we see thatlimk→+∞xkzk2exists. Using the

defini-tion of a metric projecdefini-tion we can have

PS

xnPS

xm2+xmPS

xm2≤xmPS

xn2. (27)

Letmn. Then using (24) and (27) we have

znzm2=PS

xnPS

xm2

xmPS

xn2–xmPS

xm2

=xmzn2–xmzm2

xm–1–zn2+ξm–1–xmzm 2

xnzn2+ m–1

i=n

ξm–1–xmzm 2

.

As a result of∞k=0ξk<∞andlimk→+∞xkzk2exists if we letm,n→+∞we can see thatznzm2→0. This implies the sequence{zk}is a Cauchy sequence and hence it converges to some pointzinS. Sincezk=P

S(xk) we have

xkzk,x∗–zk≤0, ∀x∗∈S.

Thus

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Thus,

zp2=pz,pz= lim

k→+∞x

kzk,pzk0.

Hence,p=zandlimk→+∞PS(xk) =p.

Let Id represents identity operator. Then, if T= Id and V = Id, then FPSCSEP (1) is reduced to SEP. Hence, Algorithm 3.1 can be rewritten as follows.

Algorithm 3.1B

Initialization: Choosex0∈C. Take{ρk},{βk},{k},{rk},{δk}and{μk}such that

ρkρ> 0, βk≥0, k≥0, rkr> 0, 0 <a<δk<b< 1,

0 <cμkb< 1 A2,

k=0

βk

ρk = +∞,

k=0

βkk

ρk < +∞,

k=0

βk2< +∞.

Step 1: TakewkH1such thatwk∂kf(x

k,·)(xk).

Step 2: Calculate

αk=

βk

ηk

, ηk=max

ρk,wk

and

yk=PC

xkαkwk

.

Step 3: Evaluate

tk=δkxk+ (1 –δk)yk.

Step 4: Evaluate

uk=TrgkAtk.

Step 5: Evaluate

xk+1=PC

tk+μkA

ukAtk.

Step 6: Setk:=k+ 1 and go to Step 1.

The following corollary is an immediate consequence of Theorem 3.4.

Corollary 3.5 Let H1 and H2be two real Hilbert spaces and A:H1→H2be a nonzero

(18)

ConditionAand ConditionBare satisfied and let{yk},{tk},{uk},and{xk},be sequences

generated by Algorithm3.1B.If S={x∗∈SEP(f,C) :Ax∗∈SEP(g,D)} =∅,then sequences

{yk},{tk}and{xk}converge strongly to a point pS and{uk}converges strongly to a point

Ap∈SEP(g,D).

3.2 Modified projected subgradient-proximal algorithm

The computation of Algorithm 3.1 involves the evaluation of two projections on the feasi-ble setCand the estimated value of operator normA. It is not an easy task to calculate or at least to estimate the operator normA. Based on Algorithm 3.1, we propose an algo-rithm with a way of selecting the step-sizes such that its implementation does not need any prior information as regards the operator norm, and the algorithm involves only one projection on the feasible setC.

For any α > 0 define hα(x) = 12VTαgA(x) –A(x)2 for all xH1, and so ∇hα(x) =

A∗(VTαgA(x) –A(x)).

Algorithm 3.2

Initialization: Choosex0C. Take{ρ

k},{βk},{k},{rk},{δk}and{ηk}such that

ρkρ> 0, βk≥0, k≥0, rk=r> 0, 0 <a<δk<b< 1,

0 <ηηk≤4 –η,

k=0

βk

ρk = +∞,

k=0

βkk

ρk < +∞,

k=0

βk2< +∞.

Step 1: FindwkH1such thatwk∂kf(x

k,·)(xk).

Step 2: Evaluateyk=P

Tk(xkαkwk) whereαk=

βk

ηk,ηk:=max{ρk,w

k}, andT

0=C,Tk= {zH1:tk–1+μk–1∇hr(tk–1) –xk,zxk ≤0}fork= 1, 2, 3, . . . .

Step 3: Evaluatetk=δ

kxk+ (1 –δk)T(yk).

Step 4: Evaluateuk=Trg(Atk).

Step 5: Evaluate

xk+1=PC

tk+μkhr

tk,

where

μk= ⎧ ⎨ ⎩

0, if∇hr(tk) = 0, ηkhr(tk)

hr(tk)2, otherwise.

Step 6: Setk=k+ 1 and go to Step 1.

Remark 3.4 By definition ofTk, we see thatTk is either half-space or the whole space

H1. Therefore, for eachk,Tkis closed and convex set, and the computation of projection

yk=PTk(x

kα

kwk) in Step 2 of Algorithm 3.2 is explicit and easier than the computation of projectionyk=P

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Lemma 3.6 Let{yk},{tk}and{xk}be sequences generated by Algorithm3.2. (i) CTkfor allk≥0.

(ii) Forx∗∈S,

tkx∗2≤xkx∗2+ 2αk(1 –δk)f

xk,x∗–Lk+ξk,

where

Lk= (1 –δk)xkyk 2

+δk(1 –δk)T

ykxk2

and

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2.

Proof (i) Fromxk=P

C(tk–1+μk–1∇hr(tk–1)) and by property of metric projection we have

tk–1+μk–1∇hr

tk–1–xk,zxk, ∀zC,

which together with the definition ofTkimplies thatCTk. (ii) Letx∗∈S. Fromyk=P

Tk(x

kβk

ηkw

k) andx,xkCT

kwe have

xkαkwkyk,ykx

≥0.

Then, with a similar proof as for Lemma 3.1 we have

tkx∗2≤xkx∗2+ 2αk(1 –δk)f

xk,x∗–Lk+θk,

where

Lk= (1 –δk)xkyk2+δk(1 –δk)T

ykxk2

and

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2.

Lemma 3.7 Let{yk},{uk},and{xk}be sequences generated by Algorithm3.2.For xS

xk+1–x∗2≤xkx∗2+ 2(1 –δk)αkf

xk,x∗+ξkKkωk,

where

Kk= (1 –δk)xkyk 2

+δk(1 –δk)T

ykxk2–TrgkAtkAtk2,

ξk= 2(1 –δk)

βkk

ρk

(20)

and

ωk= ⎧ ⎨ ⎩

0, ifhr(tk) = 0,

ηk(4 –ηk) hr(t

k)

hr(tk)2, otherwise.

Proof Letx∗∈S. By Lemma 2.6,

TrgAtkAx∗2=TrgAtkTrgAx∗2

TrgAtkTrgAx∗,AtkAx

= TrgAtkAx∗,AtkAx

=1 2T

g

rAtkAx∗ 2

+AtkAx∗2Tg

rAtkAtk 2

.

That is,

TrgAtkAx∗2≤1

2T g

rAtkAx∗ 2

+AtkAx∗2–TrgAtkAtk2. (28)

In view at (28) we get

Tg

rAtkAx∗ 2

AtkAx∗2–TrgAtkAtk2.

Hence,

VukAx∗2≤TrgAtkAx∗2≤AtkAx∗2–TrgAtkAtk2. (29)

Using (29) we have

tkx∗,∇hr

tk

= tkx∗,AVukAtk

= Atkx∗,VukAtk

= Atkx∗+VukAtkVuk+Atk,VukAtk

= VukAx∗,VukAtkVukAtk2

=1 2V

ukAx∗2+VukAtk2–AtkAx∗2–VukAtk2

=1 2V

ukAx∗2–VukAtk2–AtkAx∗2

≤–1 2T

g

rAtkAtk 2

+VukAtk2

= –1 2T

g

rAtkAtk 2

+ 2hr

tk.

That is,

tkx∗,∇hr

tk≤–1 2u

kAtk2+ 2h r

(21)

By Lemma 2.6 and (30), we have

xk+1–x∗2=PC

tk+μkhr

tkPC

x∗2

tk+μkhr

tkx∗2

=tkx∗2+μ2khr

tk2– 2μkhr

tk,tkx

tkx∗2+μkhr

tk2– 4μkhr

tkukAtk2

=tkx∗2–ukAtk2–4μkhr

tkμkhr

tk2.

That is,

xk+1–x∗2≤tkx∗2–ukAtk2–4μkhr

tkμkhr

tk2. (31)

Therefore, using (31) and Lemma 3.6, we have

xk+1–x∗2≤xkx∗2+ 2(1 –δk)αkf

xk,x∗+ξkKkωk,

where

Kk= (1 –δk)xkyk2+δk(1 –δk)T

ykxk2–ukAtk2,

ξk= 2(1 –δk)

βkk

ρk

+ 2(1 –δk)βk2,

and

ωk= 4μkhr

tkμkhr

tk2.

Note that by the definition ofμkwe have

ωk= ⎧ ⎨ ⎩

0, if∇hr(tk) = 0,

ηk(4 –ηk) hr(t

k)

hr(tk)2, otherwise.

Lemma 3.8 Let{yk},{tk},{uk},and{xk}be sequences generated by Algorithm3.2.Then: (i) Forx∗∈S,the limit of the sequence{xkx2}exists(and{xk}is bounded). (ii) lim supk→∞f(xk,x) = 0for allxS.

(iii)

lim

k→∞u

kAtk= lim k→∞x

kyk= lim k→∞T

ykxk= 0,

lim

k→∞t

kxk= lim k→∞T

xkxk= 0.

(iv)

lim

k→∞hr

tk= lim

k→∞

(22)

Proof (i) Letx∗∈S. Sincef(xk,x)0,K

k≥0,ωk≥0 from Lemma 3.2 we can have xk+1–x∗2≤xkx∗2+ξk.

Therefore, the result follows. (ii) From Lemma 3.7 we can have

ωk+Kk+ 2(1 –δk)αk

fxk,x∗≤xkx∗2–xk+1–x∗2+ξk

xkx∗2–xk+1–x∗2+ 2βk

ρk

k+ 2βk2.

Summing up the above inequalities for everyN, we obtain

0≤ N

k=0

ωk+Kk+ 2(1 –δk)αk

fxk,x

N

k=0

xkx∗2–xk+1–x∗2+ 2βk

ρk

k+ 2βk2

.

This will yield

0≤ N

k=0

ωk+ N

k=0

Kk+ N

k=0

2(1 –δk)αk

fxk,x

x0–x∗2–xN+1–x∗2+ 2 N

k=0

βk

ρk

k+ 2 N

k=0

βk2.

LettingN→+∞, we have

0≤

k=0

ωk+

k=0

Kk+

k=0

2(1 –δk)αk

fxk,x∗< +∞.

Hence,

k=0

ωk< +∞,

k=0

Kk< +∞,

k=0

2(1 –δk)αk

fxk,x∗< +∞. (32)

In the same way as proving Lemma 3.2 the result follows. (iii) From∞k=0Kk< +∞and 0 <δk< 1 we have

lim

k→∞u

kAtk2 = lim

k→∞x

kyk2 = lim

k→∞T

ykxk2= 0.

The remaining result follows from the following inequalities: tkxkδkxk+ (1 –δk)T

ykxk= (1 –δk)xkT

ykxkTyk

and

(23)

(iv) From (32) we have∞k=0[4μkhr(tk) – (μkhr(tk))2] < +∞. Without loss of general-ity, we can assume that∇hr(tk)= 0 for allk. Thus,

k=0[4μkhr(tk) – (μkhr(tk))2] < +∞ implies that

k=0

ηk(4 –ηk)

hr(tk) ∇hr(tk)2

< +∞.

Since 0 <ηηk≤4 –ηwe have

k=0

hr(tk) ∇hr(tk)2

< +∞.

Sincelimk→∞tkxk= 0 and{xk}is bounded,{tk}is also bounded. Thus, it follows from the Lipschitz continuity of∇hr(·) that{∇hr(tk)2}is bounded. This together with the last relation implies thatlimk→∞hr(tk) = 0. The inequalityV(uk) –uk ≤(2hr(tk))

1

2 +uk

Atkyields

lim

k→∞

Vukuk= 0.

Theorem 3.9 Assume ConditionAand ConditionBare satisfied and let{yk},{tk},{uk}, and{xk},be sequences generated by Algorithm3.2.Then the sequences{yk},{tk}and{xk}

converge strongly to a point pS and{uk}converge strongly to a point ApS2.Moreover,

p= lim

k→+∞PS

xk.

Proof With consideration of the definition ofhr(tk) the proof remains the same as for

Theorem 3.4.

For any α > 0 define hα(x) = 21TαgA(x) –A(x)2 for all xH1, and so ∇hα(x) =

A∗(TαgA(x) –A(x)). SettingT= Id andV= Id, the FPSCSEP (1) is reduced to SEP. Hence, Algorithm 3.2 can be rewritten as follows:

Algorithm 3.2B

Initialization: Choosex0C. Take{ρ

k},{βk},{k},{rk},{δk}and{ηk}such that

ρkρ> 0, βk≥0, k≥0, rk=r> 0, 0 <a<δk<b< 1,

0 <ηηk≤4 –η,

k=0

βk

ρk = +∞,

k=0

βkk

ρk < +∞,

k=0

βk2< +∞.

Step 1: FindwkH

1such thatwk∂kf(x

k,·)(xk).

Step 2: Evaluateyk=P Tk(x

kα

kwk) whereαk=βηk

k,ηk:=max{ρk,w

k}and

Tk= ⎧ ⎨ ⎩

C, ifk= 0,

(24)

Step 3: Evaluatetk=δ

kxk+ (1 –δk)yk.

Step 4: Evaluateuk=Tg r(Atk).

Step 5: Evaluate

xk+1=PC

tk+μkhr

tk,

where

μk= ⎧ ⎨ ⎩

0, if∇hr(tk) = 0, ηkhr(tk)

hr(tk)2, otherwise.

Step 6: Setk=k+ 1 and go to Step 1.

The following corollary is an immediate consequence of Theorem 3.9.

Corollary 3.10 Let H1and H2be two real Hilbert spaces and A:H1→H2be a nonzero

bounded linear operator.Suppose C be nonempty closed convex subset of H1,D be nonempty closed convex subset of H2,and f :C×C→Rand g:D×D→Rbe bifunction.Assume ConditionAand ConditionBare satisfied and let{yk},{tk},{uk},and{xk},be sequences

generated by Algorithm3.2B.If S={x∗∈SEP(f,C) :Ax∗∈SEP(g,D)} =∅,then sequences

{yk},{tk}and{xk}converge strongly to a point pS and{uk}converges strongly to a point Ap∈SEP(g,D).

4 Application and numerical result

In this section we will see some applications and we perform several numerical exper-iments to illustrate the computational performance of the proposed algorithms (Algo-rithm 3.1 and Algo(Algo-rithm 3.2) and we compare the convergence of one with the other.

LetA:H1→H2 be nonzero bounded linear operator whereH1 andH2 be two real Hilbert spaces, andCandDbe two nonempty closed convex subsets ofH1andH2, re-spectively. Letψ:C→Randφ:D→Rbe functions withψandφare convex and lower semicontinuous, andψ is upper semicontinuous and-subdifferentiable at every point inC. Then the following is an optimization problem:

findx∗∈H1such that ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

x∗∈C,

ψ(x∗)≤ψ(y), ∀yC,

u∗=Ax∗∈D,

φ(u∗)≤φ(v), ∀vD.

(33)

Setf(x,y) =ψ(y) –ψ(x) andg(u,v) =φ(v) –φ(u). Thus,gsatisfies Condition A andf sat-isfies Condition B as a result of the given conditions satisfied byψandφ. Therefore, op-timization problem (33) is SEP which is particular case of FPSCSEP, and Algorithm 3.1B and Algorithm 3.2B solves (33).

Let H be real Hilbert spaces, and C be nonempty closed convex subset of H. Let

(25)

multi-objective optimization problem:

minψ(x),φ(x)

s.t.xC.

(34)

Therefore, multi-objective optimization problem (34) is equilibrium problem which is also a particular case of FPSCSEP. Next we will see simple case optimization problem and its numerical result as an application. The algorithms are coded in Matlab R2017a (9.2.0.556344) and are operated on MacBook 1.1 GHz Intel Core m3 8 GB 1867 MHz LPDDR3.

Example 4.1 Consider the fixed point constrained optimization problem

findx∗∈Csuch that ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

x∗∈FixT,

ψ(x∗)≤ψ(y), ∀yC,

u∗=Ax∗∈FixV,

φ(u∗)≤φ(v), ∀vD,

where R=H1, R2=H2,A:H1→H2 given byA(x) = (–x2,x2),C={x∈R:x≥1},D= {(u1,u2)∈R2:u2–u1≥1},ψ:C→Rgiven byψ(x) = 2x+ 5, andφ:D→Rgiven by

φ(u) =φ(u1,u2) =u2–u1, and the nonexpansive mappingsT:CCgiven byT(x) =u+12 andV:DDgiven byV(u) =V(u1,u2) = (–u2, –u1).

Setf(x,y) =ψ(y) –ψ(x) = 2y– 2xandg(u,v) =φ(v) –φ(u) = (v2–v1) – (u2–u1). It is easy to check thatgandf satisfy Condition A and Condition B, respectively. It is also clear to see thatA∗(u) =A∗(u1,u2) = –12u1+12u2 andA= 12. Hence,FixT ={1},

SEP(f,C) ={1},FixV={(u1,u2)∈D:u2= –u1}, andSEP(g,D) ={(u1,u2)∈D:u2–u1= 1}. Therefore, SFPSCEP(f,C,T) = {1} and SFPSCEP(g,D,V) ={(–12,12)}. Since A(1) = (–12,12), we see that the solution set of this problem is singleton setS={p}wherep= 1.

Initialization for Algorithm3.1: Takeρk= 1,k= 0,μk=12,rk=10001 ,βk=log8k(+16k+4) and

δk=3

k+1+100

100(3k+1).

Initialization for Algorithm3.2: Takeρk= 1,k= 0,ηk= 1,rk=r=10001 ,βk=log8k(+16k+4)and

δk=3

k+1+100

100(3k+1).

Note that this choice of parameters satisfies the initialization of each of the algorithms. Choosex0∈C. Letxk,wk,yk,tk,x,yare inR, anduk= (uk1,u2k),v= (v1,v2) inR2. For this example Algorithm 3.1 is expressed as an iteration,

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

yk= ⎧ ⎨ ⎩

xkβ

k, ifxkβk≥0, 1, otherwise,

tk=δ

kxk+ (1 –δk)y

k+1

2 ,

uk= ( 1 1000–

1 2t

k, – 1 1000+

1 2t

k),

xk+1= ⎧ ⎨ ⎩

3tkuk 1+uk2

4 , if 3t kuk

1+uk2≥4, 1, otherwise,

Figure

Figure 1 Convergence of iteration (35).
Figure 2 Convergence of iteration (36).

References

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