Polynomial, Power, and Rational Functions
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(2) 5144_Demana_Ch02pp169-274. 170. 1/13/06. 11:42 AM. Page 170. CHAPTER 2 Polynomial, Power, and Rational Functions. BIBLIOGRAPHY For students: Aha! Insight, Martin Gardner. W. H. Freeman, 1978. Available through Dale Seymour Publications. The Imaginary Tale of the Story of i, Paul J. Nahin. Mathematical Association of America, 1998.. Chapter 2 Overview Chapter 1 laid a foundation of the general characteristics of functions, equations, and graphs. In this chapter and the next two, we will explore the theory and applications of specific families of functions. We begin this exploration by studying three interrelated families of functions: polynomial, power, and rational functions. These three families of functions are used in the social, behavioral, and natural sciences. This chapter includes a thorough study of the theory of polynomial equations. We investigate algebraic methods for finding both real- and complex-number solutions of such equations and relate these methods to the graphical behavior of polynomial and rational functions. The chapter closes by extending these methods to inequalities in one variable.. 2.1 Linear and Quadratic Functions and Modeling What you’ll learn about. Polynomial Functions. ■. Polynomial Functions. Polynomial functions are among the most familiar of all functions.. ■. Linear Functions and Their Graphs. ■. Average Rate of Change. DEFINITION Polynomial Function. ■. Linear Correlation and Modeling. Let n be a nonnegative integer and let a0, a1, a2, . . . , an 1, an be real numbers with an 0. The function given by. ■. Quadratic Functions and Their Graphs. ■. Applications of Quadratic Functions. . . . and why Many business and economic problems are modeled by linear functions. Quadratic and higher degree polynomial functions are used to model some manufacturing applications.. f x anx n an 1x n 1 · · · a2x 2 a1x a0 is a polynomial function of degree n. The leading coefficient is an. The zero function f x 0 is a polynomial function. It has no degree and no leading coefficient.. Polynomial functions are defined and continuous on all real numbers. It is important to recognize whether a function is a polynomial function.. EXAMPLE 1 Identifying Polynomial Functions Which of the following are polynomial functions? For those that are polynomial functions, state the degree and leading coefficient. For those that are not, explain why not. 1 (a) f x 4x 3 5x (b) g x 6x 4 7 2 4 16 x 2 (d) k x 15x 2x4 (c) hx 9x continued.
(3) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 171. SECTION 2.1 Linear and Quadratic Functions and Modeling. BIBLIOGRAPHY. 171. SOLUTION (a) f is a polynomial function of degree 3 with leading coefficient 4.. For teachers: Explorations in Precalculus Using the TI-82/TI-83, with Appendix Notes for TI-85, Cochener and Hodge. 1997, Brooks/Cole Publishing Co., 1997.. (b) g is not a polynomial function because of the exponent 4.. Algebra Experiments II, Exploring Nonlinear Functions, Ronald J. Carlson and Mary Jean Winter. Addison-Wesley, 1993. Available through Dale Seymour Publications.. (d) k is a polynomial function of degree 4 with leading coefficient 2. Now try Exercise 1.. Videos: Polynomials, Project Mathematics!, California Institute of Technology. Available through Dale Seymour Publications.. (c) h is not a polynomial function because it cannot be simplified into polynomial 4 16x2 3x 2 4x. form. Notice that 9x. The zero function and all constant functions are polynomial functions. Some other familiar functions are also polynomial functions, as shown below.. OBJECTIVE Students will be able to recognize and graph linear and quadratic functions, and use these functions to model situations and solve problems.. Polynomial Functions of No and Low Degree. MOTIVATE Ask students how they think the graph of y (x 2)2 5 is related to the graph of y x2. (Translated 2 units right and 5 units up.). Name. Form. Degree. Zero function. f x 0. Undefined. Constant function. f x a a 0. 0. Linear function. f x ax b a 0. 1. Quadratic function. f x . 2. ax 2. bx c a 0. LESSON GUIDE Day 1: Polynomial Functions; Linear Functions and Their Graphs; Average Rate of Change Day 2: Linear Correlation and Modeling; Quadratic Functions and Their Graphs Day 3: Applications of Quadratic Functions. We study polynomial functions of degree 3 and higher in Section 2.3. For the remainder of this section, we turn our attention to the nature and uses of linear and quadratic polynomial functions.. Linear Functions and Their Graphs Linear equations and graphs of lines were reviewed in Sections P.3 and P.4, and some of the examples in Chapter 1 involved linear functions. We now take a closer look at the properties of linear functions.. REMARK Slant lines are also known as oblique lines.. A linear function is a polynomial function of degree 1 and so has the form f x ax b, where a and b are constants and a 0. If we use m for the leading coefficient instead of a and let y f x, then this equation becomes the familiar slope-intercept form of a line: y mx b.. SURPRISING FACT. Not all lines in the Cartesian plane are graphs of linear functions.. Vertical lines are not graphs of functions because they fail the vertical line test, and horizontal lines are graphs of constant functions. A line in the Cartesian plane is the graph of a linear function if and only if it is a slant line, that is, neither horizontal nor vertical. We can apply the formulas and methods of Section P.4 to problems involving linear functions..
(4) 5144_Demana_Ch02pp169-274. 172. 1/13/06. 11:42 AM. Page 172. CHAPTER 2 Polynomial, Power, and Rational Functions. EXAMPLE 2 Finding an Equation of a Linear Function. ALERT Some students will attempt to calculate slopes using x in the numerator and y in the denominator. Remind them that rise change in y slope . change in x run. Write an equation for the linear function f such that f 1 2 and f 3 2. SOLUTION Solve Algebraically We seek a line through the points 1, 2 and 3, 2. The slope is. REMARK Notice that the slope does not depend on the order of the points. We could use (x1, y1) (3, 2) and (x2, y2) (1, 2).. y2 y1 2 2 4 m 1. x2 x1 3 1 4 Using this slope and the coordinates of 1, 2 with the point-slope formula, we have y y1 mx x1 y 2 1x 1. y. y 2 x 1 3 (–1, 2) 2 1 –5 –4 –3 –2 –1 –1 –2 –3. y x 1 1 2 3 4 5 (3, –2). x. FIGURE 2.1 The graph of y x 1 passes through (1, 2) and (3, 2). (Example 2). Converting to function notation gives us the desired form: f x x 1. Support Graphically We can graph y x 1 and see that it includes the points 1, 2 and 3, 2. (See Figure 2.1.) Confirm Numerically Using f x x 1 we prove that f 1 2 and f 3 2: f 1 1 1 1 1 2, and f 3 3 1 3 1 2. Now try Exercise 7.. Average Rate of Change Another property that characterizes a linear function is its rate of change. The average rate of change of a function y f x between x a and x b, a b, is f b f a . ba You are asked to prove the following theorem in Exercise 85.. THEOREM Constant Rate of Change. A function defined on all real numbers is a linear function if and only if it has a constant nonzero average rate of change between any two points on its graph.. Because the average rate of change of a linear function is constant, it is called simply the rate of change of the linear function. The slope m in the formula f x mx b is the rate of change of the linear function. In Exploration 1, we revisit Example 7 of Section P.4 in light of the rate of change concept..
(5) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 173. SECTION 2.1 Linear and Quadratic Functions and Modeling. EXPLORATION 1. 173. Modeling Depreciation with a Linear Function. Camelot Apartments bought a $50,000 building and for tax purposes are depreciating it $2000 per year over a 25-yr period using straight-line depreciation. EXPLORATION EXTENSIONS. 1. What is the rate of change of the value of the building?. What would be different if the building were depreciating $2500 per year over a 20-year period?. 2. Write an equation for the value vt of the building as a linear function of. RATE AND RATIO. All rates are ratios, whether expressed as miles per hour, dollars per year, or even rise over run.. TEACHER’S NOTE It is important for students to see that slope (from previous courses) becomes the rate of change (in calculus), which we now foreshadow.. the time t since the building was placed in service. 3. Evaluate v0 and v16. $50,000; $18,000 4. Solve vt 39,000. t 5.5 yr. The rate of change of a linear function is the signed ratio of the corresponding line’s rise over run. That is, for a linear function f x mx b, rise change in y y rate of change m . run change in x x This formula allows us to interpret the slope, or rate of change, of a linear function numerically. For instance, in Exploration 1 the value of the apartment building fell from $50,000 to $0 over a 25-yr period. In Table 2.1 we compute yx for the apartment building’s value (in dollars) as a function of time (in years). Because the average rate of change yx is the nonzero constant 2000, the building’s value is a linear function of time decreasing at a rate of $2000/yr.. Table 2.1 Rate of Change of the Value of the Apartment Building in Exploration 1: y 2000x 50,000 x (time). y (value). 0. 50,000. EXTENSION Have students create a table like 2.1 but using x 0, 5.5, 16, and 25. They may be surprised to see that yx is still 2000.. 1 2 3 4. x. y. y x. 1. 2000. 2000. 1. 2000. 2000. 1. 2000. 2000. 1. 2000. 2000. 48,000 46,000 44,000 42,000. In Exploration 1, as in other applications of linear functions, the constant term represents the value of the function for an input of 0. In general, for any function f, f 0 is the initial value of f. So for a linear function f x mx b, the constant term b is the initial value of the function. For any polynomial function f x anx n · · · a1x a0, the constant term f 0 a0 is the function’s initial value. Finally, the initial value of any function—polynomial or otherwise—is the y-intercept of its graph..
(6) 5144_Demana_Ch02pp169-274. 174. 1/13/06. 11:42 AM. Page 174. CHAPTER 2 Polynomial, Power, and Rational Functions. We now summarize what we have learned about linear functions. Characterizing the Nature of a Linear Function Point of View. Characterization. Verbal. polynomial of degree 1. Algebraic. f x mx b m 0. Graphical. slant line with slope m and y-intercept b. Analytical. function with constant nonzero rate of change m: f is increasing if m 0, decreasing if m 0; initial value of the function f 0 b. Linear Correlation and Modeling In Section 1.7 we approached modeling from several points of view. Along the way we learned how to use a grapher to create a scatter plot, compute a regression line for a data set, and overlay a regression line on a scatter plot. We touched on the notion of correlation coefficient. We now go deeper into these modeling and regression concepts. Figure 2.2 shows five types of scatter plots. When the points of a scatter plot are clustered along a line, we say there is a linear correlation between the quantities represented by the data. When an oval is drawn around the points in the scatter plot, generally speaking, the narrower the oval, the stronger the linear correlation. ALERT Some students will attempt to determine whether the correlation is strong or weak by calculating a slope. Point out that these terms refer to how well a line can model the data, not to the slope of the line.. When the oval tilts like a line with positive slope (as in Figure 2.2a and b), the data have a positive linear correlation. On the other hand, when it tilts like a line with negative slope (as in Figure 2.2d and e), the data have a negative linear correlation. Some scatter plots exhibit little or no linear correlation (as in Figure 2.2c), or have nonlinear patterns. A number that measures the strength and direction of the linear correlation of a data set is the (linear) correlation coefficient, r.. Properties of the Correlation Coefficient, r 1. 1 r 1. 2. When r 0, there is a positive linear correlation. 3. When r 0, there is a negative linear correlation. 4. When r 1, there is a strong linear correlation. 5. When r 0, there is weak or no linear correlation.. Correlation informs the modeling process by giving us a measure of goodness of fit. Good modeling practice, however, demands that we have a theoretical reason for selecting a model. In business, for example, fixed cost is modeled by a constant function. (Otherwise, the cost would not be fixed.).
(7) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 175. SECTION 2.1 Linear and Quadratic Functions and Modeling. y. y. y 50. 50. 50. 40. 40. 40. 30. 30. 30. 20. 20. 20. 10. 175. 10. 10. x. x. x 10 20 30 40 50 Strong positive linear correlation. 10 20 30 40 50 Weak positive linear correlation. 10 20 30 40 50 Little or no linear correlation. (a). (b). (c). y. y. 50. 50. 40. 40. 30. 30. 20. 20. 10. 10 x. x. 10 20 30 40 50 Strong negative linear correlation. 10 20 30 40 50 Weak negative linear correlation. (d). (e). FIGURE 2.2 Five scatter plots and the types of linear correlation they suggest.. In economics, a linear model is often used for the demand for a product as a function of its price. For instance, suppose Twin Pixie, a large supermarket chain, conducts a market analysis on its store brand of doughnut-shaped oat breakfast cereal. The chain sets various prices for its 15-oz box at its different stores over a period of time. Then, using this data, the Twin Pixie researchers project the weekly sales at the entire chain of stores for each price and obtain the data shown in Table 2.2.. Table 2.2 Weekly Sales Data Based on Marketing Research Price per box. Boxes sold. $2.40 $2.60 $2.80 $3.00 $3.20 $3.40 $3.60. 38,320 33,710 28,280 26,550 25,530 22,170 18,260.
(8) 5144_Demana_Ch02pp169-274. 176. 1/13/06. 11:42 AM. Page 176. CHAPTER 2 Polynomial, Power, and Rational Functions. EXAMPLE 3 Modeling and Predicting Demand. ALERT Some graphers display a linear regression equation using a and b, where y a bx instead of y ax b. Caution students to understand the convention of the particular grapher they are using.. TEACHER’S NOTE On some graphers, you need to select Diagnostic On from the Catalog to see the correlation coefficient.. Use the data in Table 2.2 on the preceding page to write a linear model for demand (in boxes sold per week) as a function of the price per box (in dollars). Describe the strength and direction of the linear correlation. Then use the model to predict weekly cereal sales if the price is dropped to $2.00 or raised to $4.00 per box. SOLUTION Model We enter the data and obtain the scatter plot shown in Figure 2.3a. It appears that the data have a strong negative correlation. We then find the linear regression model to be approximately y 15,358.93x 73,622.50, where x is the price per box of cereal and y the number of boxes sold. Figure 2.3b shows the scatter plot for Table 2.2 together with a graph of the regression line. You can see that the line fits the data fairly well. The correlation coefficient of r 0.98 supports this visual evidence. Solve Graphically. [2, 4] by [10 000, 40 000] (a). Our goal is to predict the weekly sales for prices of $2.00 and $4.00 per box. Using the value feature of the grapher, as shown in Figure 2.3c, we see that y is about 42,900 when x is 2. In a similar manner we could find that y 12,190 when x is 4. Interpret If Twin Pixie drops the price for its store brand of doughnut-shaped oat breakfast cereal to $2.00 per box, sales will rise to about 42,900 boxes per week. On the other hand, if they raise the price to $4.00 per box, sales will drop to around 12,190 boxes per week. Now try Exercise 49. We summarize for future reference the analysis used in Example 3.. Regression Analysis [2, 4] by [10000, 40000] (b). 1. Enter and plot the data (scatter plot). 2. Find the regression model that fits the problem situation. 3. Superimpose the graph of the regression model on the scatter plot, and. observe the fit. 4. Use the regression model to make the predictions called for in the problem.. X=2. Y=42904.643 [0, 5] by [–10000, 80000] (c). FIGURE 2.3 Scatter plot and regression line graphs for Example 3.. Quadratic Functions and Their Graphs A quadratic function is a polynomial function of degree 2. Recall from Section 1.3 that the graph of the squaring function f x x 2 is a parabola. We will see that the graph of every quadratic function is an upward or downward opening parabola. This is because the graph of any quadratic function can be obtained from the graph of the squaring function f x x 2 by a sequence of translations, reflections, stretches, and shrinks..
(9) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 177. SECTION 2.1 Linear and Quadratic Functions and Modeling. 177. EXAMPLE 4 Transforming the Squaring Function. y. Describe how to transform the graph of f x x 2 into the graph of the given function. Sketch its graph by hand.. 5. 5. –5. x. (a) gx (1/2)x 2 3. (b) hx 3x 22 1. SOLUTION (a) The graph of gx 12x 2 3 is obtained by vertically shrinking the graph of f x x 2 by a factor of 12, reflecting the resulting graph across the x-axis, and translating the reflected graph up 3 units. See Figure 2.4a.. –5. (b) The graph of hx 3x 22 1 is obtained by vertically stretching the graph of f x x 2 by a factor of 3 and translating the resulting graph left 2 units and down 1 unit. See Figure 2.4b. Now try Exercise 19.. (a) y 5. 5. –5. x. –5 (b). FIGURE 2.4 The graph of f (x) . The graph of f x ax 2, a 0, is an upward-opening parabola. When a 0, its graph is a downward-opening parabola. Regardless of the sign of a, the y-axis is the line of symmetry for the graph of f x ax 2. The line of symmetry for a parabola is its axis of symmetry, or axis for short. The point on the parabola that intersects its axis is the vertex of the parabola. Because the graph of a quadratic function is always an upward- or downward-opening parabola, its vertex is always the lowest or highest point of the parabola. The vertex of f x ax 2 is always the origin, as seen in Figure 2.5. axis. axis. x2. (blue) shown with (a) g(x) (1/2)x 2 3 and (b) h(x) 3(x 2) 2 1. (Example 4). f(x) = ax2, a < 0. vertex vertex f(x) = ax2, a > 0. (a). (b). FIGURE 2.5 The graph f (x) ax 2 for (a) a 0 and (b) a 0.. Expanding f x a x h2 k and comparing the resulting coefficients with the standard quadratic form ax 2 bx c, where the powers of x are arranged in descending order, we can obtain formulas for h and k. f x ax h 2 k ax 2 2hx h 2 k. Expand (x h)3.. ax2 2ahx ah 2 k. Distributive property. ax 2 bx c. Let b 2ah and c ah2 k..
(10) 5144_Demana_Ch02pp169-274. 178. 1/13/06. 11:42 AM. Page 178. CHAPTER 2 Polynomial, Power, and Rational Functions. Because b 2ah and c ah 2 k in the last line above, h b 2a and k c ah 2. Using these formulas, any quadratic function f x ax 2 bx c can be rewritten in the form. y y = ax2 + bx + c. f x ax h2 k. x=– b,a>0 2a. This vertex form for a quadratic function makes it easy to identify the vertex and axis of the graph of the function, and to sketch the graph.. x. Vertex Form of a Quadratic Function Any quadratic function f x ax 2 bx c, a 0, can be written in the vertex form. (a) y. f x ax h 2 k.. y = ax2 + bx + c. x=– b,a<0 2a. The graph of f is a parabola with vertex h, k and axis x h, where h b 2a and k c ah2. If a 0, the parabola opens upward, and if a 0, it opens downward. (See Figure 2.6.). x. (b). The formula h b 2a is useful for locating the vertex and axis of the parabola associated with a quadratic function. To help you remember it, notice that b 2a is part of the quadratic formula b b2 4a c x . 2a. FIGURE 2.6 The vertex is at x b/(2a), which therefore also describes the axis of symmetry. (a) When a 0, the parabola opens upward. (b) When a 0, the parabola opens downward.. (Cover the radical term. You need not remember k c ah 2 because you can use k f h instead.. EXAMPLE 5 Finding the Vertex and Axis of a Quadratic Function Use the vertex form of a quadratic function to find the vertex and axis of the graph of f x 6x 3x 2 5. Rewrite the equation in vertex form. SOLUTION Solve Algebraically TEACHER’S NOTE Another way of converting a quadratic function from the polynomial form f (x) ax2 bx c to the vertex form f (x) a(x h)2 k is completing the square, a method used in Section P.5 to solve quadratic equations. Example 6 illustrates this method.. The standard polynomial form of f is f x 3x 2 6x 5. So a 3, b 6, and c 5, and the coordinates of the vertex are b 6 h 1 and 2a 2(3) k f h f 1 312 61 5 2. The equation of the axis is x 1, the vertex is 1,2, and the vertex form of f is f x 3x 12 2. Now try Exercise 27..
(11) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 179. SECTION 2.1 Linear and Quadratic Functions and Modeling. 179. EXAMPLE 6 Using Algebra to Describe the Graph of a Quadratic Function Use completing the square to describe the graph of f x 3x 2 12x 11. Support your answer graphically. SOLUTION Solve Algebraically. X=–2. Y=–1. f x 3x 2 12x 11. [–4.7, 4.7] by [–3.1, 3.1]. FIGURE 2.7 The graphs of f (x) . 12x 11 and y 3(x 2)2 1 appear to be identical. The vertex (2, 1) is highlighted. (Example 6) 3x2. 3x 2 4x 11. Factor 3 from the x terms.. 3x 2 4x 11 . 3x 2. 4x . 22. . 22. 11. 3x 2 4x 4 34 11 3x . 22. Prepare to complete the square. Complete the square. Distribute the 3.. 1. The graph of f is an upward-opening parabola with vertex 2, 1, axis of symmetry x 2, and intersects the x-axis at about 2.577 and 1.423. The exact values of the x-intercepts are x 2 3 3. Support Graphically The graph in Figure 2.7 supports these results.. Now try Exercise 33.. ASSIGNMENT GUIDE Day 1: Ex. 1–11 odds Day 2: Ex. 15–50, multiples of 5, 53 Day 3: 54, 55, 61, 63, 65, 67, 68, 84. COOPERATIVE LEARNING. We now summarize what we know about quadratic functions. Characterizing the Nature of a Quadratic Function Point of View. Characterization. Verbal. polynomial of degree 2. Algebraic. f x ax 2 bx c or f x ax h2 k a 0. Graphical. parabola with vertex h, k and axis x h; opens upward if a 0, opens downward if a 0; initial value y-intercept f 0 c;. Group Activity: Ex. 59, 60. NOTES ON EXERCISES Ex. 39–44 require the student to produce a quadratic function with certain qualities. Ex. 54, 56–63 offer some classical applications of quadratic functions. Ex. 65, 67, 68 are applications of quadratic and linear regression. Ex. 71–76 provide practice with standardized tests.. b b2 4a c x-intercepts 2a. ONGOING ASSESSMENT Self-Assessment: Ex. 3, 7, 21, 31, 33, 49, 55, 61, 63 Embedded Assessment: Ex. 40, 63. Applications of Quadratic Functions In economics, when demand is linear, revenue is quadratic. Example 7 illustrates this by extending the Twin Pixie model of Example 3.. EXAMPLE 7 Predicting Maximum Revenue Use the model y 15,358.93x 73,622.50 from Example 3 to develop a model for the weekly revenue generated by doughnut-shaped oat breakfast cereal sales. Determine the maximum revenue and how to achieve it..
(12) 5144_Demana_Ch02pp169-274. 180. 1/13/06. 11:42 AM. Page 180. CHAPTER 2 Polynomial, Power, and Rational Functions. SOLUTION Model Revenue can be found by multiplying the price per box, x, by the number of boxes sold, y. So the revenue is given by Rx x • y 15,358.93x2 73,622.50x, Maximum X=2.3967298 Y=88226.727 [0, 5] by [–10000, 100000]. FIGURE 2.8 The revenue model for Example 7.. a quadratic model. Solve Graphically In Figure 2.8, we find a maximum of about 88,227 occurs when x is about 2.40. Interpret To maximize revenue, Twin Pixie should set the price for its store brand of doughnutshaped oat breakfast cereal at $2.40 per box. Based on the model, this will yield a weekly revenue of about $88,227. Now try Exercise 55.. Recall that the average rate of change of a linear function is constant. In Exercise 78 you will see that the average rate of change of a quadratic function is not constant. In calculus you will study not only average rate of change but also instantaneous rate of change. Such instantaneous rates include velocity and acceleration, which we now begin to investigate. Since the time of Galileo Galilei (1564–1642) and Isaac Newton (1642–1727), the vertical motion of a body in free fall has been well understood. The vertical velocity and vertical position (height) of a free-falling body (as functions of time) are classical applications of linear and quadratic functions.. Vertical Free-Fall Motion The height s and vertical velocity v of an object in free fall are given by 1 st gt2 v0 t s0 2. and. vt gt v0,. where t is time (in seconds), g 32 ft/sec2 9.8 m/sec2 is the acceleration due to gravity, v0 is the initial vertical velocity of the object, and s0 is its initial height.. These formulas disregard air resistance, and the two values given for g are valid at sea level. We apply these formulas in Example 8, and will use them from time to time throughout the rest of the book. The data in Table 2.3 were collected in Boone, North Carolina (about 1 km above sea level), using a Calculator-Based Ranger™ (CBR™) and a 15-cm rubber air-filled ball. The CBR™ was placed on the floor face up. The ball was thrown upward above the CBR™, and it landed directly on the face of the device..
(13) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 181. SECTION 2.1 Linear and Quadratic Functions and Modeling. Table 2.3 Rubber Ball Data from CBR™ Time (sec). Height (m). 0.0000 0.1080 0.2150 0.3225 0.4300 0.5375 0.6450 0.7525 0.8600. 1.03754 1.40205 1.63806 1.77412 1.80392 1.71522 1.50942 1.21410 0.83173. 181. EXAMPLE 8 Modeling Vertical Free-Fall Motion Use the data in Table 2.3 to write models for the height and vertical velocity of the rubber ball. Then use these models to predict the maximum height of the ball and its vertical velocity when it hits the face of the CBR™. SOLUTION Model First we make a scatter plot of the data, as shown in Figure 2.9a. Using quadratic regression, we find the model for the height of the ball to be about st 4.676t2 3.758t 1.045, with R2 0.999, indicating an excellent fit. Our free-fall theory says the leading coefficient of 4.676 is g 2, giving us a value for g 9.352 m/sec2, which is a bit less than the theoretical value of 9.8 m/sec2. We also obtain v0 3.758 m/sec. So the model for vertical velocity becomes vt gt v0 9.352t 3.758. Solve Graphically and Numerically The maximum height is the maximum value of st, which occurs at the vertex of its graph. We can see from Figure 2.9b that the vertex has coordinates of about 0.402, 1.800.. [0, 1.2] by [–0.5, 2.0] (a). In Figure 2.9c, to determine when the ball hits the face of the CBR™, we calculate the positive-valued zero of the height function, which is t 1.022. We turn to our linear model to compute the vertical velocity at impact: v1.022 9.3521.022 3.758 5.80 m sec. Interpret The maximum height the ball achieved was about 1.80 m above the face of the CBR™. The ball’s downward rate is about 5.80 m/sec when it hits the CBR™.. Maximum X=.40183958 Y=1.8000558 [0, 1.2] by [–0.5, 2.0] (b). The curve in Figure 2.9b appears to fit the data extremely well, and R2 0.999. You may have noticed, however, that Table 2.3 contains the ordered pair 0.4300, 1.80392) and that 1.80392 1.800, which is the maximum shown in Figure 2.9b. So, even though our model is theoretically based and an excellent fit to the data, it is not a perfect model. Despite its imperfections, the model provides accurate and reliable predictions about the CBR™ experiment. Now try Exercise 63. REMINDER. Recall from Section 1.7 that R2 is the coefficient of determination, which measures goodness of fit.. Zero X=1.0222877 Y=0 [0, 1.2] by [–0.5, 2.0] (c). FIGURE 2.9 Scatter plot and graph of height versus time for Example 8.. FOLLOW-UP Ask the students to write the equation obtained when f(x) x2 is shifted 3 units to the left and 4 units down. ( f(x) x2 6x 5).
(14) 5144_Demana_Ch02pp169-274. 182. 1/13/06. 11:42 AM. Page 182. CHAPTER 2 Polynomial, Power, and Rational Functions. QUICK REVIEW 2.1. (For help, go to Sections A.2. and P.4). In Exercises 1– 2, write an equation in slope-intercept form for a line with the given slope m and y-intercept b. 1. m 8,. b 3.6. 2. m 1.8,. b 2. In Exercises 3– 4, write an equation for the line containing the given points. Graph the line and points. 3. 2, 4 and 3, 1. 4. 1, 5 and 2, 3. In Exercises 5–8, expand the expression. 5. x 32 x 2 6x 9. 6. x 42 x 2 8x 16. 7. 3x . 8. 3x 72 3x2 42x 147. 62. 3x 2. 36x 108. In Exercises 9–10, factor the trinomial. 9. 2x 2 4x 2 2(x 1)2. 10. 3x 2 12x 12 3(x 2)2. SECTION 2.1 EXERCISES In Exercises 1–6, determine which are polynomial functions. For those that are, state the degree and leading coefficient. For those that are not, explain why not. 1. f x 3x5 17. 2. f x 9 2x. 1 3. f x 2x 5 x 9 2. 4. f x 13. 3. 27x3 8x6 5. hx . (c). (d). (e). (f). 6. kx 4x 5x 2. In Exercises 7–12, write an equation for the linear function f satisfying the given conditions. Graph y f x. 7. f 5 1. and. f 2 4. 8. f 3 5. and. f 6 2. 9. f 4 6. and. f 1 2. 10. f 1 2. and. f 5 7. 11. f 0 3. and. f 3 0. 12. f 4 0. and. f 0 2. In Exercises 13–18, match a graph to the function. Explain your choice. 13. f x 2x 12 3 (a) 14. f x 3x 22 7 (d) 15. f x 4 3x 12 (b) 16. f x 12 2x 12 (f) 17. f x 2x . 12. 3 (e) 18. f x 12 2x . 12. (c). In Exercises 19–22, describe how to transform the graph of f x x 2 into the graph of the given function. Sketch each graph by hand. 1 19. gx x 32 2 20. hx x2 1 4 1 21. gx x 22 3 22. hx 3x 2 2 2 In Exercises 23–26, find the vertex and axis of the graph of the function. 23. f x 3x 12 5. 24. gx 3x 22 1. 25. f x 5x 12 7. 26. gx 2x 3 2 4. In Exercises 27–32, find the vertex and axis of the graph of the function. Rewrite the equation for the function in vertex form.. (a). (b). 27. f x 3x 2 5x 4. 28. f x 2x 2 7x 3. 29. f x 8x . 30. f x 6 2x 4x 2. x2. 3. 31. gx 5x 2 4 6x. 32. hx 2x 2 7x 4.
(15) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 183. SECTION 2.1 Linear and Quadratic Functions and Modeling. In Exercises 33–38, use completing the square to describe the graph of each function. Support your answers graphically. 33. f x x 2 4x 6 35. f x 10 16x . 34. gx x 2 6x 12. 37. f x 2x 2 6x 7. 38. gx 5x 2 25x 12. In Exercises 39–42, write an equation for the parabola shown, using the fact that one of the given points is the vertex. 39.. 40. (0, 5). (1, 5) (–1, –3). (2, –7) [–5, 5] by [–15, 15]. [–5, 5] by [–15, 15]. y 2(x 1)2 3. 41.. y 3(x 2)2 7. Age (months). Weight (pounds). 18 20 24 26 27 29 34 39 42. 23 25 24 32 33 29 35 39 44. (a) Draw a scatter plot of these data. (b) Writing to Learn Describe the strength and direction of the correlation between age and weight.. 42.. (1, 11). 49. Comparing Age and Weight A group of male children were weighed. Their ages and weights are recorded in Table 2.4. Table 2.4 Children’s Age and Weight. 36. hx 8 2x x 2. x2. 183. (–1, 5). 50. Life Expectancy Table 2.5 shows the average number of additional years a U.S. citizen is expected to live for various ages.. (4, –7). (2, –13). Table 2.5 U.S. Life Expectancy [–5, 5] by [–15, 15]. [–5, 5] by [–15, 15]. y 2(x 1)2 11. y 2(x 1)2 5. In Exercises 43 and 44, write an equation for the quadratic function whose graph contains the given vertex and point. 43. Vertex 1, 3, point 0, 5 y 2(x 1)2 3 11 2. 44. Vertex 2, 5, point 4, 27 y (x 2)2 5 In Exercises 45– 48, describe the strength and direction of the linear correlation. 45.. y. 46.. Strong positive. y. Strong negative. 50 40 30 20 10. 50 40 30 20 10. x 10 20 30 40 50. 48.. Weak positive. y. No correlation. 50 40 30 20 10. 50 40 30 20 10. x. x 10 20 30 40 50. 10 20 30 40 50 60 70 80. 67.4 57.7 48.2 38.8 29.8 21.5 14.3 8.6. Source: U.S. National Center for Health Statistics, Vital Statistics of the United States.. (b) Writing to Learn Describe the strength and direction of the correlation between age and life expectancy.. x. y. Life Expectancy (years). (a) Draw a scatter plot of these data.. 10 20 30 40 50. 47.. Age (years). 10 20 30 40 50. 51. Straight-Line Depreciation Mai Lee bought a computer for her home office and depreciated it over 5 years using the straight-line method. If its initial value was $2350, what is its value 3 years later? $940 52. Costly Doll Making Patrick’s doll-making business has weekly fixed costs of $350. If the cost for materials is $4.70 per doll and his total weekly costs average $500, about how many dolls does Patrick make each week? 32.
(16) 5144_Demana_Ch02pp169-274. 184. 1/13/06. 11:42 AM. Page 184. CHAPTER 2 Polynomial, Power, and Rational Functions. 53. Table 2.6 shows the average hourly compensation of production workers in manufacturing for several years. Let x be the number of years since 1970, so that x 5 stands for 1975, and so forth. Table 2.6 Production Worker Average Year 1975 1985 1995 2002. Hourly Compensation (dollars) 6.36 13.01 17.19 21.37. Source: U.S. Bureau of Labor Statistics as reported in The World Almanac and Book of Facts, 2005.. (a) Writing to Learn Find the linear regression model for the data. What does the slope in the regression model represent? (b) Use the linear regression model to predict the production worker average hourly compensation in the year 2010. 54. Finding Maximum Area Among all the rectangles whose perimeters are 100 ft, find the dimensions of the one with maximum area. 25
(17) 25 ft 55. Determining Revenue The per unit price p (in dollars) of a popular toy when x units (in thousands) are produced is modeled by the function price p 12 0.025x. The revenue (in thousands of dollars) is the product of the price per unit and the number of units (in thousands) produced. That is, revenue xp x12 0.025x. (a) State the dimensions of a viewing window that shows a graph of the revenue model for producing 0 to 100,000 units. (b) How many units should be produced if the total revenue is to be $1,000,000? either 107,335 units or 372,665 units 56. Finding the Dimensions of a Painting A large painting in the style of Rubens is 3 ft longer than it is wide. If the wooden frame is 12 in. wide, the area of the picture and frame is 208 ft2, find the dimensions of the painting. 11 ft by 14 ft 57. Using Algebra in Landscape Design Julie Stone designed a rectangular patio that is 25 ft by 40 ft. This patio is surrounded by a terraced strip of uniform width planted with small trees and shrubs. If the area A of this terraced strip is 504 ft2, find the width x of the strip. 3.5 ft. 58. Management Planning The Welcome Home apartment rental company has 1600 units available, of which 800 are currently rented at $300 per month. A market survey indicates that each $5 decrease in monthly rent will result in 20 new leases. (a) Determine a function Rx that models the total rental income realized by Welcome Home, where x is the number of $5 decreases in monthly rent. R(x) (800 20x)(300 5x) (b) Find a graph of Rx for rent levels between $175 and $300 (that is, 0 x 25) that clearly shows a maximum for Rx. (c) What rent will yield Welcome Home the maximum monthly income? $250 per month 59. Group Activity Beverage Business The Sweet Drip Beverage Co. sells cans of soda pop in machines. It finds that sales average 26,000 cans per month when the cans sell for 50¢ each. For each nickel increase in the price, the sales per month drop by 1000 cans. (a) Determine a function Rx that models the total revenue realized by Sweet Drip, where x is the number of $0.05 increases in the price of a can. R(x) (26,000 1000x)(0.50 0.05x) (b) Find a graph of Rx that clearly shows a maximum for Rx. (c) How much should Sweet Drip charge per can to realize the maximum revenue? What is the maximum revenue? 60. Group Activity Sales Manager Planning Jack was named District Manager of the Month at the Sylvania Wire Co. due to his hiring study. It shows that each of the 30 salespersons he supervises average $50,000 in sales each month, and that for each additional salesperson he would hire, the average sales would decrease $1000 per month. Jack concluded his study by suggesting a number of salespersons that he should hire to maximize sales. What was that number? 10 61. Free-Fall Motion As a promotion for the Houston Astros downtown ballpark, a competition is held to see who can throw a baseball the highest from the front row of the upper deck of seats, 83 ft above field level. The winner throws the ball with an initial vertical velocity of 92 ft/sec and it lands on the infield grass. (a) Find the maximum height of the base ball. (b) How much time is the ball in the air? About 6.54 sec (c) Determine its vertical velocity when it hits the ground. 62. Baseball Throwing Machine The Sandusky Little League uses a baseball throwing machine to help train 10-year-old players to catch high pop-ups. It throws the baseball straight up with an initial velocity of 48 ft/sec from a height of 3.5 ft. (a) Find an equation that models the height of the ball t seconds after it is thrown. h 16t 2 48t 3.5 (b) What is the maximum height the baseball will reach? How many seconds will it take to reach that height? 39.5 ft, 1.5 sec.
(18) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 185. SECTION 2.1 Linear and Quadratic Functions and Modeling. 63. Fireworks Planning At the Bakersville Fourth of July celebration, fireworks are shot by remote control into the air from a pit that is 10 ft below the earth’s surface. (a) Find an equation that models the height of an aerial bomb t seconds after it is shot upwards with an initial velocity of 80 ft/sec. Graph the equation. (b) What is the maximum height above ground level that the aerial bomb will reach? How many seconds will it take to reach that height? 90 ft, 2.5 sec 64. Landscape Engineering In her first project after being employed by Land Scapes International, Becky designs a decorative water fountain that will shoot water to a maximum height of 48 ft. What should be the initial velocity of each drop of water to achieve this maximum height? (Hint: Use a grapher and a guess-and-check strategy.). 185. (a) Find the slope of this section of the highway. 0.06 (b) On a highway with a 6% grade what is the horizontal distance required to climb 250 ft? 4167 ft (c) A sign along the highway says 6% grade for the next 7 mi. Estimate how many feet of vertical change there are along those 7 mi. (There are 5280 ft in 1 mile.) 2217.6 ft 67. A group of female children were weighed. Their ages and weights are recorded in Table 2.8. Table 2.8 Children’s Ages and Weights. 65. Patent Applications Using quadratic regression on the data in Table 2.7, predict the year when the number of patent application will reach 450,000. Let x 0 stand for 1980, x 10 for 1990 and so forth. 2006. Age (months). Weight (pounds). 19 21 24 27 29 31 34 38 43. 22 23 25 28 31 28 32 34 39. Table 2.7 U.S. Patent Applications Year. Applications (thousands). 1980 1990 1995 1998 1999 2000 2001 2002 2003. 113.0 176.7 228.8 261.4 289.5 315.8 346.6 357.5 367.0. (a) Draw a scatter plot of the data. (b) Find the linear regression model. y 0.68x 9.01 (c) Interpret the slope of the linear regression equation. (d) Superimpose the regression line on the scatter plot. (e) Use the regression model to predict the weight of a 30-monthold girl. 29.41 lb 68. Table 2.9 shows the median U.S. family income (in 2003 dollars) for selected years. Let x be the number of years since 1940.. Source: U.S. Census Bureau, Statistical Abstract of the United States, 2004–2005 (124th ed., Washington, D.C., 2004).. 66. Highway Engineering Interstate 70 west of Denver, Colorado, has a section posted as a 6% grade. This means that for a horizontal change of 100 ft there is a 6-ft vertical change.. 6% grade. Table 2.9 Median Family Income in the U.S. (in 2003 dollars) Year. Median Family Income ($). 1947 1973 1979 1989 1995 2000 2003. 21,201 43,219 45,989 49,014 48.679 54,191 52,680. Source: Economic Policy Institute, The State of Working America 2004/2005 (ILR Press, 2005). 6% GRADE. (a) Find the linear regression model for the data. (b) Use it to predict the median U.S. family income in 2010..
(19) 5144_Demana_Ch02pp169-274. 186. 1/13/06. 11:42 AM. Page 186. CHAPTER 2 Polynomial, Power, and Rational Functions. In Exercises 69– 70, complete the analysis for the given Basic Function.. In Exercises 73–76, you may use a graphing calculator to solve the problem.. 69. Analyzing a Function. In Exercises 73 and 74, f x mx b, f 2 3, and f 4 1. 73. Multiple Choice What is the value of m? E. BASIC FUNCTION The Identity Function. (B) 3. (A) 3. (E) 13. (D) 13. 74. Multiple Choice What is the value of b? C (A) 4. f x x Domain: Range: Continuity: Increasing-decreasing behavior: Symmetry: Boundedness: Local extrema: Horizontal asymptotes: Vertical asymptotes: End behavior:. (C) 1. (B) 113. (C) 73. (E) 13. (D) 1. In Exercises 75 and 76, let f x 2x 32 5. 75. Multiple Choice What is the axis of symmetry of the graph of f ? B (A) x 3. (B) x 3. (C) y 5. (D) y 5. (E) y 0. 76. Multiple Choice What is the vertex of f ? E (A) 0,0. (B) 3,5. (C) 3,5. (D) 3,5. (E) 3,5. Explorations 77. Writing to Learn Identifying Graphs of Linear Functions (a) Which of the lines graphed below are graphs of linear functions? Explain. (i), (iii), and (v). 70. Analyzing a Function. BASIC FUNCTION. (b) Which of the lines graphed below are graphs of functions? Explain. (i), (iii), (iv), (v), and (vi) (c) Which of the lines graphed below are not graphs of functions? Explain. (ii) is not a function.. The Squaring Function y. f x Domain: Range: Continuity: Increasing-decreasing behavior: Symmetry: Boundedness: Local extrema: Horizontal asymptotes: Vertical asymptotes: End behavior: x2. 3 2. 72. True or False The graph of the function f x x2 x 1 has no x-intercepts. Justify your answer.. 3 2 1. –5 –4 –3 –2 –1 –1 –2 –3. 1 2. 4 5. x. –5 –4 –3. –1 –1 –2 –3. (i). (ii). y. y. 1 2 3 4 5. x. 3 2 1. 3 2 1 –5 –4 –3 –2 –1. 1 2 3 4 5. x. –3. –5 –4 –3 –2 –1 –1 –2 –3. 1 2 3 4 5. (iii). (iv). y. y. Standardized Test Questions 71. True or False The initial value of f x 3x2 2x 3 is 0. Justify your answer. False. The initial value is f(0) 3.. y. 3 2 1. 3 2 1 –5 –4 –3 –2 –1 –1 –3. (v). x. 1 2 3. 5. x. –5 –4 –3 –2 –1 –1 –2 –3. 1 2 3 4 5. (vi). x.
(20) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 187. SECTION 2.1 Linear and Quadratic Functions and Modeling. 78. Average Rate of Change Let f x x2, gx 3x 2, hx 7x 3, kx mx b, and lx x3. (a) Compute the average rate of change of f from x 1 to x 3. 4. 80. Median-Median Line Read about the median-median line by going to the Internet, your grapher owner’s manual, or a library. Then use the following data set to complete this problem.. (b) Compute the average rate of change of f from x 2 to x 5. 7. 2, 8, 3, 6, 5, 9, 6, 8, 8, 11, 10, 13, 12, 14, 15, 4. (c) Compute the average rate of change of f from x a to x c. c a. (a) Draw a scatter plot of the data.. (d) Compute the average rate of change of g from x 1 to x 3. 3. (c) Find the median-median line equation and graph it.. (e) Compute the average rate of change of g from x 1 to x 4. 3. (d) Writing to Learn For this data, which of the two lines appears to be the line of better fit? Why?. (b) Find the linear regression equation and graph it.. (f) Compute the average rate of change of g from x a to x c. 3 (g) Compute the average rate of change of h from x a to x c. 7 (h) Compute the average rate of change of k from x a to x c. m (i) Compute the average rate of change of l from x a to x c. c 2 ac a 2. 79. Minimizing Sums of Squares The linear regression line is often called the least-square lines because it minimizes the sum of the squares of the residuals, the differences between actual y values and predicted y values: residual yi axi b,. Use these definitions to explain why the regression line obtained from reversing the ordered pairs in Table 2.2 is not the inverse of the function obtained in Example 3.. y 50. (a) Prove that the sum of the two solutions of this equation is ba. (b) Prove that the product of the two solutions of this equation is ca.. 83. Connecting Algebra and Geometry Identify the vertex of the graph of f x x ax b, where a and b are any real numbers. 84. Connecting Algebra and Geometry Prove that if x1 and x2 are real numbers and are zeros of the quadratic function f x ax2 bx c, then the axis of the graph of f is x x1 x22. 85. Prove the Constant Rate of Change Theorem, which is stated on page 172.. (xi, yi). 40. 81. Suppose b2 4ac 0 for the equation ax2 bx c 0.. 82. Connecting Algebra and Geometry Prove that the axis of the graph of f x x ax b is x a b2, where a and b are real numbers.. Extending the Ideas. where xi, yi are the given data pairs and y ax b is the regression equation, as shown in the figure.. 187. yi (axi b). 30 20 10. y ax b x 10 20 30 40 50. 85. Suppose f(x) mx b with m and b constants and m 0. Let x1 and x2 be real numbers with x1 x2. Then the average rate of change of f is f(x2) f(x1) m(x2 x1) (mx2 b) (mx1 b) m, a nonzero constant. On the other hand, suppose m and x1 are constants and m 0. Let x be x2 x1 x2 x1 x2 x1 f(x) f(x1) m. Then f(x) f(x1) m(x x1) and a real number with x x1 and let f be a function defined on all real numbers such that x x1 f(x) mx (f(x1) mx1). Notice that the expression f(x1) mx1 is a constant; call it b. Then f(x1) mx1 b; so, f(x1) mx1 b and f(x) mx b for all x x1. Thus f is a linear function..
(21) 5144_Demana_Ch02pp169-274. 188. 1/13/06. 11:42 AM. Page 188. CHAPTER 2 Polynomial, Power, and Rational Functions. 2.2 Power Functions with Modeling What you’ll learn about ■. Power Functions and Variation. ■. Monomial Functions and Their Graphs. ■. Graphs of Power Functions. ■. Modeling with Power Functions. Power Functions and Variation Five of the basic functions introduced in Section 1.3 were power functions. Power functions are an important family of functions in their own right and are important building blocks for other functions. DEFINITION Power Function. Any function that can be written in the form f x k • x a, where k and a are nonzero constants,. . . . and why Power functions specify the proportional relationships of geometry, chemistry, and physics.. is a power function. The constant a is the power, and k is the constant of variation, or constant of proportion. We say f x varies as the a th power of x, or f x is proportional to the a th power of x.. OBJECTIVE Students will be able to sketch power functions in the form of f(x) kxa (where k and a are rational numbers).. In general, if y f x varies as a constant power of x, then y is a power function of x. Many of the most common formulas from geometry and science are power functions.. MOTIVATE. Name. Formula. Power. Constant of Variation. Circumference. C 2r. 1. 2. Area of a circle. A. r 2. 2. . Force of gravity. F kd 2. 2. k. LESSON GUIDE. Boyle’s Law. V kP. 1. k. Day 1: Power Functions and Variation; Monomial Functions and Their Graphs Day 2: Graphs of Power Functions Day 3: Modeling with Power Functions. These four power function models involve output-from-input relationships that can be expressed in the language of variation and proportion:. Ask students to predict what the graphs of the following functions will look like when x 0, 0 x 1, and x 1: a) f(x) x3 b) f(x) x. • The circumference of a circle varies directly as its radius. TEACHING NOTES. • The area enclosed by a circle is directly proportional to the square of its radius.. 1. To help students with the meaning of directly and inversely proportional, have them calculate three or four areas of circles with different radii and note that as the radius increases so does the area. Ask students what would happen to the value of V in Boyle’s law if the value of P were increased. (As P increases in value, V decreases in value, therefore we say it is inversely proportional.). • The force of gravity acting on an object is inversely proportional to the square of the distance from the object to the center of the Earth.. 2. You may wish to have students graph one direct and one inverse variation in Quadrant I, either by hand or using a grapher, to show that direct variations are increasing functions, and inverse variations are decreasing in Quadrant I.. • Boyle’s Law states that the volume of an enclosed gas (at a constant temperature) varies inversely as the applied pressure. The power function formulas with positive powers are statements of direct variation and power function formulas with negative powers are statements of inverse variation. Unless the word inversely is included in a variation statement, the variation is assumed to be direct, as in Example 1..
(22) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 189. SECTION 2.2 Power Functions with Modeling. 189. EXAMPLE 1 Writing a Power Function Formula. ALERT Some students may have trouble entering exponents on a grapher. Careful attention must be given to the syntax and placement of parentheses.. From empirical evidence and the laws of physics it has been found that the period of time T for the full swing of a pendulum varies as the square root of the pendulum’s length l, provided that the swing is small relative to the length of the pendulum. Express this relationship as a power function. SOLUTION Because it does not state otherwise, the variation is direct. So the power is positive. The wording tells us that T is a function of l. Using k as the constant of variation gives us Tl kl k • l1 2.. Now try Exercise 17.. Section 1.3 introduced five basic power functions: 1 x, x 2, x 3, x 1 , and x 1 2 x. x Example 2 describes two other power functions: the cube root function and the inversesquare function.. EXAMPLE 2. Analyzing Power Functions. State the power and constant of variation for the function, graph it, and analyze it. 1 3 (a) f x x (b) gx 2 x SOLUTION (a) Because f x x x1 3 1 • x1 3, its power is 13, and its constant of variation is 1. The graph of f is shown in Figure 2.10a. 3. [–4.7, 4.7] by [–3.1, 3.1] (a). Domain: All reals Range: All reals Continuous Increasing for all x Symmetric with respect to the origin (an odd function) Not bounded above or below No local extrema No asymptotes 3 3 End behavior: lim x and lim x x→. x→. Interesting fact: The cube root function f x x is the inverse of the cubing function. 3. [–4.7, 4.7] by [–3.1, 3.1] (b). FIGURE 2.10 The graphs of 3. (a) f (x) x x 1/3 and (b) g (x) 1/x2 x2. (Example 2). (b) Because gx 1x2 x2 1 • x2, its power is 2, and its constant of variation is 1. The graph of g is shown in Figure 2.10b. Domain: , 0 0, Range: 0, Continuous on its domain; discontinuous at x 0 Increasing on , 0; decreasing on 0, Symmetric with respect to the y-axis (an even function) Bounded below, but not above No local extrema. continued.
(23) 5144_Demana_Ch02pp169-274. 190. 1/13/06. 11:42 AM. Page 190. CHAPTER 2 Polynomial, Power, and Rational Functions. Horizontal asymptote: y 0; vertical asymptote: x 0 End behavior: lim 1x 2 0 and lim1 x 2 0 x→. x→. Interesting fact: gx 1x 2 is the basis of scientific inverse-square laws, for example, the inverse-square gravitational principle F kd 2 mentioned above. So gx 1x 2 is sometimes called the inverse-square function, but it is not the inverse of the squaring function but rather its multiplicative inverse. Now try Exercise 27.. Monomial Functions and Their Graphs A single-term polynomial function is a power function that is also called a monomial function. DEFINITION Monomial Function. Any function that can be written as f x k or f x k • x n, where k is a constant and n is a positive integer, is a monomial function .. EXPLORATION EXTENSIONS Graph f(x) 2x, g(x) 2x3, and h(x) 2x5. How do these graphs differ from the graphs in Question 1? Do they have any ordered pairs in common? Now graph f(x) 2x, g(x) 2x3, and h(x) 2x5. Compare these graphs with the graphs in the first part of the exploration.. So the zero function and constant functions are monomial functions, but the more typical monomial function is a power function with a positive integer power, which is the degree of the monomial. The basic functions x, x2, and x3 are typical monomial functions. It is important to understand the graphs of monomial functions because every polynomial function is either a monomial function or a sum of monomial functions. In Exploration 1 we take a close look at six basic monomial functions. They have the form x n for n 1, 2, . . . , 6. We group them by even and odd powers.. EXPLORATION 1. Comparing Graphs of Monomial Functions. Graph the triplets of functions in the stated windows and explain how the graphs are alike and how they are different. Consider the relevant aspects of analysis from Example 2. Which ordered pairs do all three graphs have in common? (1, 1) x x2 x3 x4 x5 x6 (0, 0). 1. f x x, gx x 3, and hx x 5 in the window 2.35, 2.35. by 1.5, 1.5 , then 5, 5 by 15, 15 , and finally 20, 20 by 200, 200 . 2. f x x 2, gx x 4, and hx x 6 in the window 1.5, 1.5 by 0.5, 1.5 , then 5, 5 by 5, 25 , and finally 15, 15 by 50, 400 . From Exploration 1 we see that f x x n is an even function if n is even and an odd function if n is odd.. [0, 1] by [0, 1]. FIGURE 2.11 The graphs of f (x) x n, 0 x 1, for n 1, 2, . . . , 6.. Because of this symmetry, it is enough to know the first quadrant behavior of f x x n. Figure 2.11 shows the graphs of f x x n for n 1, 2, . . . , 6 in the first quadrant near the origin..
(24) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 191. SECTION 2.2 Power Functions with Modeling. 191. The following conclusions about the basic function f x x 3 can be drawn from your investigations in Exploration 1.. BASIC FUNCTION The Cubing Function. [–4.7, 4.7] by [–3.1, 3.1]. FIGURE 2.12 The graph of f(x) x 3.. f x x3 Domain: All reals Range: All reals Continuous Increasing for all x Symmetric with respect to the origin (an odd function) Not bounded above or below No local extrema No horizontal asymptotes No vertical asymptotes End behavior: lim x3 ∞ and lim x3 ∞ x→∞. x→∞. EXAMPLE 3 Graphing Monomial Functions Describe how to obtain the graph of the given function from the graph of gx x n with the same power n. Sketch the graph by hand and support your answer with a grapher. 2 (a) f x 2x3 (b) f x x 4 3 SOLUTION (a) We obtain the graph of f x 2x3 by vertically stretching the graph of gx x3 by a factor of 2. Both are odd functions. See Figure 2.13a. (b) We obtain the graph of f x 23x 4 by vertically shrinking the graph of gx x 4 by a factor of 23 and then reflecting it across the x-axis. Both are even functions. See Figure 2.13b. Now try Exercise 31. We ask you to explore the graphical behavior of power functions of the form xn and x1n, where n is a positive integer, in Exercise 65.. [–2, 2] by [–16, 16] (a). [–2, 2] by [–16, 16] (b). FIGURE 2.13 The graphs of (a) f(x) 2x3 with basic monomial g(x) x3, and (b) f(x) (2/3)x 4 with basic monomial g(x) x 4. (Example 3).
(25) 5144_Demana_Ch02pp169-274. 192. 1/13/06. 11:42 AM. Page 192. CHAPTER 2 Polynomial, Power, and Rational Functions. Graphs of Power Functions. y a< 0. a> 1. The graphs in Figure 2.14 represent the four shapes that are possible for general power functions of the form f x kx a for x 0. In every case, the graph of f contains 1, k. Those with positive powers also pass through 0, 0. Those with negative exponents are asymptotic to both axes.. a= 1. 0 < a< 1 (1, k). 1. 0. 2. 3. x. y 2. 3 x. 0 (1, k). In general, for any power function f x k • x a, one of three following things happens when x 0. • f is undefined for x 0, as is the case for f x x 12 and f x x .. (a). 1. When k 0, the graph lies in Quadrant I, but when k 0, the graph is in Quadrant IV.. 0 < a< 1. • f is an even function, so f is symmetric about the y-axis, as is the case for f x x2 and f x x 23. • f is an odd function, so f is symmetric about the origin, as is the case for f x x1 and f x x 73. Predicting the general shape of the graph of a power function is a two-step process as illustrated in Example 4.. a< 0. a> 1. a= 1. (b). FIGURE 2.14 The graphs of f (x) k • x a for x 0. (a) k 0, (b) k 0.. EXAMPLE 4 Graphing Power Functions f (x) k • x a State the values of the constants k and a. Describe the portion of the curve that lies in Quadrant I or IV. Determine whether f is even, odd, or undefined for x 0. Describe the rest of the curve if any. Graph the function to see whether it matches the description. (a) f x 2x3. (b) f x 0.4x 1.5. (c) f x x 0.4. SOLUTION (a) Because k 2 is positive and a 3 is negative, the graph passes through 1, 2 and is asymptotic to both axes. The graph is decreasing in the first quadrant. The function f is odd because 2 2 f x 2x3 3 3 2x3 f x. x x So its graph is symmetric about the origin. The graph in Figure 2.15a supports all aspects of the description. (b) Because k 0.4 is negative and a 1.5 1, the graph contains 0, 0 and passes through 1, 0.4. In the fourth quadrant, it is decreasing. The function f is undefined for x 0 because 2 2 f x 0.4x 1.5 x 3 2 x 3, 5 5 and the square-root function is undefined for x 0. So the graph of f has no points in Quadrants II or III. The graph in Figure 2.15b matches the description..
(26) 5144_Demana_Ch02pp169-274. 1/13/06. 11:42 AM. Page 193. SECTION 2.2 Power Functions with Modeling. [–4.7, 4.7] by [–3.1, 3.1] (a). 193. [–4.7, 4.7] by [–3.1, 3.1] (c). [–4.7, 4.7] by [–3.1, 3.1] (b). FIGURE 2.15 The graphs of (a) f (x) 2x3, (b) f (x) 0.4x 1.5, and (c) f (x) x 0.4. (Example 4) (c) Because k 1 is negative and 0 a 1, the graph contains 0, 0 and passes through 1, 1. In the fourth quadrant, it is decreasing. The function f is even because f x x0.4 x 25 x 2 x 2 5. ALERT. 5. x 2 x0.4 f x. 5. Some graphing calculators will only produce the portion of the graph in Figure 2.15c for x 0. Be sure to check the domain of any function graphed with technology.. So the graph of f is symmetric about the y-axis. The graph in Figure 2.15c fits the description. Now try Exercise 43. The following information about the basic function f(x) x follows from the investigation in Exercise 65.. BASIC FUNCTION The Square Root Function. [–4.7, 4.7] by [–3.1, 3.1]. FIGURE 2.16 The graph of f (x) x.. f x x Domain: 0, Range: 0, Continuous on 0, Increasing on 0, No symmetry Bounded below but not above Local minimum at x 0 No horizontal asymptotes No vertical asymptotes End behavior: lim x x→. Modeling with Power Functions Noted astronomer Johannes Kepler (1571–1630) developed three laws of planetary motion that are used to this day. Kepler’s Third Law states that the square of the period of orbit T (the time required for one full revolution around the Sun) for each planet is proportional to the cube of its average distance a from the Sun. Table 2.10 on the next page gives the relevant data for the six planets that were known in Kepler’s time. The distances are given in millions of kilometers, or gigameters (Gm)..
(27) 5144_Demana_Ch02pp169-274. 194. 1/13/06. 11:42 AM. Page 194. CHAPTER 2 Polynomial, Power, and Rational Functions. Table 2.10 Average Distances and Orbit Periods for the Six Innermost Planets Average Distance from Sun (Gm). Planet Mercury Venus Earth Mars Jupiter Saturn. 57.9 108.2 149.6 227.9 778.3 1427. Period of Orbit (days) 88 225 365.2 687 4332 10,760. Source: Shupe, Dorr, Payne, Hunsiker, et al., National Geographic Atlas of the World (rev. 6th ed.). Washington, DC: National Geographic Society, 1992, plate 116.. EXAMPLE 5 Modeling Planetary Data with a Power Function Use the data in Table 2.10 to obtain a power function model for orbital period as a function of average distance from the Sun. Then use the model to predict the orbital period for Neptune, which is 4497 Gm from the Sun on average. SOLUTION Model First we make a scatter plot of the data, as shown in Figure 2.17a. Using power regression, we find the model for the orbital period to be about T a 0.20a1.5 0.20a3 2 0.20 a3 . Figure 2.17b shows the scatter plot for Table 2.10 together with a graph of the power regression model just found. You can see that the curve fits the data quite well. The coefficient of determination is r2 0.999999912, indicating an amazingly close fit and supporting the visual evidence. Solve Numerically A BIT OF HISTORY. Example 5 shows the predictive power of a well founded model. Exercise 67 asks you to find Kepler’s elegant form of the equation, T2 a3, which he reported in The Harmony of the World in 1619.. To predict the orbit period for Neptune we substitute its average distance from the Sun in the power regression model: T4497 0.244971.5 60,313. Interpret It takes Neptune about 60,313 days to orbit the Sun, or about 165 years, which is the value given in the National Geographic Atlas of the World. Figure 2.17c reports this result and gives some indication of the relative distances involved. Neptune is much farther from the Sun than the six innermost planets and especially the four closest to the Sun—Mercury, Venus, Earth, and Mars. Now try Exercise 55..
(28) 5144_Demana_Ch02pp169-274. 1/16/06. 9:51 AM. Page 195. SECTION 2.2 Power Functions with Modeling. 195. Y1=0.2X^1.5. X=4497. Y=60313.472. [–100, 1500] by [–1000, 12000]. [–100, 1500] by [–1000, 12000]. [0, 5000] by [–10000, 65000]. (a). (b). (c). FIGURE 2.17 Scatter plot and graphs for Example 5.. FOLLOW-UP Ask . . . What would the graph of f (x) 3x1/2 look like? (Since 0 < 1/2 < 1, the graph is in the first quadrant and undefined for x < 0; the coefficient 3 stretches the graph and reflects it over the x-axis.). ASSIGNMENT GUIDE Day 1: Ex. 1–33 (multiples of 3) Day 2: 37, 38, 41, 42–48 Day 3: 51, 52, 55, 66, 68, 69. In Example 6, we return to free-fall motion, with a new twist. The data in the table come from the same CBR™ experiment referenced in Example 8 of Section 2.1. This time we are looking at the downward distance (in meters) the ball has traveled since reaching its peak height and its downward speed (in meters per second). It can be shown (see Exercise 68) that free-fall speed is proportional to a power of the distance traveled.. EXAMPLE 6. Modeling Free-Fall Speed versus Distance. Use the data in Table 2.11 to obtain a power function model for speed p versus distance traveled d. Then use the model to predict the speed of the ball at impact given that impact occurs when d 1.80 m.. COOPERATIVE LEARNING Table 2.11 Rubber Ball Data from CBR™ Experiment. Group Activity: Ex. 64. NOTES ON EXERCISES Ex. 27–48 encourage students to think about the appearance of functions without using a grapher. Ex. 51–54 are classical applications of monomial power functions. Ex. 55 and 57 are applications of regression analysis. Ex. 58–63 provide practice with standardized tests.. Distance (m). Speed (m/s). 0.00000 0.04298 0.16119 0.35148 0.59394 0.89187 1.25557. 0.00000 0.82372 1.71163 2.45860 3.05209 3.74200 4.49558. ONGOING ASSESSMENT Self-Assessment: Ex. 17, 27, 33, 43, 55, 57 Embedded Assessment: Ex. 43, 55, 66. SOLUTION Model Figure 2.18a on the next page is a scatter plot of the data. Using power regression, we find the model for speed p versus distance d to be about pd 4.03d 0.5 4.03d 1 2 4.03d.. WHY p?. We use p for speed to distinguish it from velocity v. Recall that speed is the absolute value of velocity.. (See margin notes.) Figure 2.18b shows the scatter plot for Table 2.11 together with a graph of the power regression equation just found. You can see that the curve fits the data nicely. The coefficient of determination is r 2 0.99770, indicating a close fit and supporting the visual evidence. continued.
(29) 5144_Demana_Ch02pp169-274. 196. 1/13/06. 11:42 AM. Page 196. CHAPTER 2 Polynomial, Power, and Rational Functions. Y1=4.03X^(1/2). X=1.8 [–0.2, 2] by [–1, 6] (a). Y=5.4068124 [–0.2, 2] by [–1, 6] (c). [–0.2, 2] by [–1, 6] (b). FIGURE 2.18 Scatter plot and graphs for Example 6.. A WORD OF WARNING. Solve Numerically. The regression routine traditionally used to compute power function models involves taking logarithms of the data, and therefore, all of the data must be strictly positive numbers. So we must leave out (0, 0) to compute the power regression equation.. To predict the speed at impact, we substitute d 1.80 into the obtained power regression model: p1.80 5.4. See Figure 2.18c. Interpret The speed at impact is about 5.4 msec. This is slightly less than the value obtained in Example 8 of Section 2.1, using a different modeling process for the same experiment. Now try Exercise 57.. QUICK REVIEW 2.2. (For help, go to Section A.1.). In Exercises 1–6, write the following expressions using only positive integer powers. 3. 1. x23 x2. 2. p52 p5. 3. d2 1d 2. 4. x7 1/x 7. 5.. q45. 5. 1 q4. 6. m1.5 1/ m3. In Exercises 7–10, write the following expressions in the form k • xa using a single rational number for the power a. 7. 9x3 3x 3/2 9.. 5 1.71x
(30) x 3. 4. 8. 8x5 2x 5/3 4x 10. 0.71x –1/2 32x3 3. –4/3. SECTION 2.2 EXERCISES In Exercises 1–10, determine whether the function is a power function, given that c, g, k, and represent constants. For those that are power functions, state the power and constant of variation. 1 1. f x x 5 2. f x 9x53 2 3. f x 3 • 2x 4. f x 13. 5. Em mc2 1 7. d gt2 2 k 9. I 2 d. 1 6. KEv kv5 2 4 8. V r3 3 10. F(a) m • a.
(31) 5144_Demana_Ch02pp169-274. 1/13/06. 11:43 AM. Page 197. SECTION 2.2 Power Functions with Modeling. In Exercises 11–16, determine whether the function is a monomial function, given that l and represent constants. For those that are monomial functions state the degree and leading coefficient. For those that are not, explain why not. 11. f x 4 13. y . 6x7. 15. S 4r2. 12. f x 3x5 14. y 2 . 5x. 16. A lw. In Exercises 17–22, write the statement as a power function equation. Use k for the constant of variation if one is not given. 17. The area A of an equilateral triangle varies directly as the square of the length s of its sides. A ks 2. 197. In Exercises 31–36, describe how to obtain the graph of the given monomial function from the graph of g x x n with the same power n. State whether f is even or odd. Sketch the graph by hand and support your answer with a grapher. 2 31. f x x 4 3 33. f x 1.5x 5 1 35. f x x 8 4. 32. f x 5x 3 34. f x 2x 6 1 36. f x x7 8. In Exercises 37–42, match the equation to one of the curves labeled in the figure. y. 18. The volume V of a circular cylinder with fixed height is proportional to the square of its radius r. V kr 2. a. b. 19. The current I in an electrical circuit is inversely proportional to the resistance R, with constant of variation V. I V/R. c d. 20. Charles’s Law states the volume V of an enclosed ideal gas at a constant pressure varies directly as the absolute temperature T. V kT x. 21. The energy E produced in a nuclear reaction is proportional to the mass m, with the constant of variation being c 2, the square of the speed of light. E mc 2. e. 22. The speed p of a free-falling object that has been dropped from rest varies as the square root of the distance traveled d, with a constant of variation k 2g. p 2gd In Exercises 23–26, write a sentence that expresses the relationship in the formula, using the language of variation or proportion. 23. w mg, where w and m are the weight and mass of an object and g is the constant acceleration due to gravity. 24. C D, where C and D are the circumference and diameter of a circle and is the usual mathematical constant. 25. n cv, where n is the refractive index of a medium, v is the velocity of light in the medium, and c is the constant velocity of light in free space. 26. d p 22g, where d is the distance traveled by a free-falling object dropped from rest, p is the speed of the object, and g is the constant acceleration due to gravity. In Exercises 27–30, state the power and constant of variation for the function, graph it, and analyze it in the manner of Example 2 of this section. 27. f x . 2x4. 1 4 29. f x x 2. 28. f x . 3x3. 30. f x 2x3. h. g. f. 2 37. f x x 4 (g) 3 39. f x 2x14 (d). 1 38. f x x5 (a) 2 40. f x x53 (g). 41. f x 2x2 (h). 42. f x 1.7x 23 (d). In Exercises 43–48, state the values of the constants k and a for the function f x k • x a. Describe the portion of the curve that lies in Quadrant I or IV. Determine whether f is even, odd, or undefined for x 0. Describe the rest of the curve if any. Graph the function to see whether it matches the description. 43. f x 3x14. 44. f x 4x23 2 46. f x x 52 5 48. f x x4. 45. f x 2x 43 1 47. f x x 3 2. In Exercises 49 and 50, data are given for y as a power function of x. Write an equation for the power function, and state its power and constant of variation. 49. x y. 2 2. 50. x y. 1 2. 4 0.5 4 4. 6 0.222. . . 9 6. 8 0.125 16 8. 25 10. 10 0.08.
(32) 5144_Demana_Ch02pp169-274. 198. 1/13/06. 11:43 AM. Page 198. CHAPTER 2 Polynomial, Power, and Rational Functions. 51. Boyle’s Law The volume of an enclosed gas (at a constant temperature) varies inversely as the pressure. If the pressure of a 3.46-L sample of neon gas at 302°K is 0.926 atm, what would the volume be at a pressure of 1.452 atm if the temperature does not change? 2.21 L 52. Charles’s Law The volume of an enclosed gas (at a constant pressure) varies directly as the absolute temperature. If the pressure of a 3.46-L sample of neon gas at 302°K is 0.926 atm, what would the volume be at a temperature of 338°K if the pressure does not change? 3.87L 53. Diamond Refraction Diamonds have the extremely high refraction index of n 2.42 on average over the range of visible light. Use the formula from Exercise 25 and the fact that c 3.00
(33) 108 m/sec to determine the speed of light through a diamond.. 57. Light Intensity Velma and Reggie gathered the data in Table 2.13 using a 100-watt light bulb and a Calculator-Based LaboratoryTM (CBLTM) with a light-intensity probe. (a) Draw a scatter plot of the data in Table 2.13 (b) Find the power regression model. Is the power close to the theoretical value of a 2? y 7.932 x1.987; yes (c) Superimpose the regression curve on the scatter plot. (d) Use the regression model to predict the light intensity at distances of 1.7m and 3.4 m. Table 2.13 Light Intensity Data for a 100-W Light Bulb. 1.24
(34) 108 m/sec. 54. Windmill Power The power P (in watts) produced by a windmill is proportional to the cube of the wind speed v (in mph). If a wind of 10 mph generates 15 watts of power, how much power is generated by winds of 20, 40, and 80 mph? Make a table and explain the pattern. 55. Keeping Warm For mammals and other warm-blooded animals to stay warm requires quite a bit of energy. Temperature loss is related to surface area, which is related to body weight, and temperature gain is related to circulation, which is related to pulse rate. In the final analysis, scientists have concluded that the pulse rate r of mammals is a power function of their body weight w. (a) Draw a scatter plot of the data in Table 2.12. (b) Find the power regression model. r 231.204 . w0.297. Distance (m). Intensity (W/m2). 1.0 1.5 2.0 2.5 3.0. 7.95 3.53 2.01 1.27 0.90. Standardized Test Questions 58. True or False The function f x x23 is even. Justify your answer. True, because f(x) (x)2/3 x2/3 f(x). 59. True or False The graph f x x13 is symmetric about the y-axis. Justify your answer.. (c) Superimpose the regression curve on the scatter plot.. In Exercises 60–63, solve the problem without using a calculator.. (d) Use the regression model to predict the pulse rate for a 450-kg horse. Is the result close to the 38 beats/min reported by A. J. Clark in 1927?. 60. Multiple Choice Let f x 2x12. What is the value of f 4? A 1 (A) 1 (B) 1 (C) 22 (D) (E) 4 22 61. Multiple Choice Let f x 3x13. Which of the following statements is true? E. Table 2.12 Weight and Pulse Rate of Selected Mammals Mammal Rat Guinea pig Rabbit Small dog Large dog Sheep Human. Body weight (kg). Pulse rate (beats/min). 0.2 0.3 2 5 30 50 70. 420 300 205 120 85 70 72. Source: A. J. Clark, Comparative Physiology of the Heart. New York: Macmillan, 1927.. 56. Even and Odd Functions If n is an integer, n 1, prove that f x x n is an odd function if n is odd and is an even function if n is even. If n is odd, f (x) (x)n xn f(x); if n is even, f(x) (x)n xn f(x).. (A) f 0 0. (B) f 1 3. (D) f 3 3. (E) f 0 is undefined. (C) f 1 1. 62. Multiple Choice Let f x x23. Which of the following statements is true? B (A) f is an odd function. (B) f is an even function. (C) f is neither an even nor an odd function. (D) The graph f is symmetric with respect to the x-axis. (E) The graph f is symmetric with respect to the origin. 63. Multiple Choice Which of the following is the domain of the function f x x32? B (A) All reals (D) ∞,0. (B) 0,∞. (C) 0,∞. (E) ∞,0 0,∞.
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