Volume 2008, Article ID 598319,10pages doi:10.1155/2008/598319
Research Article
Maximal Inequalities for Dependent Random
Variables and Applications
Soo Hak Sung
Department of Applied Mathematics, Pai Chai University, Taejon 302-735, South Korea
Correspondence should be addressed to Soo Hak Sung,[email protected]
Received 16 April 2008; Revised 3 June 2008; Accepted 7 July 2008
Recommended by Ondrej Dosly
For a sequence {Xn, n ≥ 1} of dependent square integrable random variables and a sequence
{bn, n≥1}of positive numbers, we establish a maximal inequality for weighted sums of dependent random variables. Applying this inequality, we obtain the almost sure convergence of ni1Xi/bi andni1Xi/bn.
Copyrightq2008 Soo Hak Sung. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
Throughout this paper let {Xn, n ≥ 1} be a sequence of random variables defined on a
probability spaceΩ,F, Pand let{bn, n ≥ 1}be a sequence of positive numbers. We assume
that there exists a sequence{ρn, n≥1}of nonnegative constants such that
sup
k≥1
EXkXkn≤ρn, forn≥1. 1.1
In this paper, we establish a maximal inequality for weighted sums of the dependent random variables satisfying1.1. Applying this inequality, we obtain under some suitable conditions on the sequence{ρn}that
n
i1 Xi
bi
converges a.s. asn−→ ∞ 1.2
and the strong law of large numbersSLLN
n
i1Xi
bn −→0 a.s. 1.3
For a sequence of dependent random variables satisfying 1.1, the SLLNs were established by Hu et al.1,2and Lyons3. Lyons3obtained an SLLN under the conditions
that VarXn O1and bn n. Without condition VarXn O1, Hu et al. 1 obtained
an SLLN, wherebn n.Hu et al.2also obtained an SLLN for more general sequence{bn}
bnnis replaced bynObn.
For other results on the SLLN for a sequence of correlated random variables, see Chandra
4, M ´oricz5,6, and Serfling7,8.
In this paper, we give a sufficient condition under which1.2and1.3hold. Our results
partially improve those of Hu et al. 1, 2. The technique used in our proof is the well-known method of subsequences. Note that the maximal inequality is used in the method of subsequences. Our maximal inequality for weighted sums of the dependent random variables satisfying1.1is sharper than that of Hu et al.2.
Throughout this paper, logxdenotes the natural logarithm.
2. Maximal inequalities for dependent random variables
To prove the maximal inequality for weighted sums of dependent random variables satisfying
1.1, the following lemma is needed.
Lemma 2.1. Let{Xn, n≥1}be a sequence of square integrable random variables satisfying1.1. Let
{bn, n≥1}be a sequence of positive numbers such that
n≤Dbn ∀n≥1and some constantD > 0. 2.1
Then for alln≥1, m > n,andδ >0,
m−1
in m
ji1
EXiXj
bibj ≤
D2C
δ
max{log 2δ,lognδ}
m−n
k1 ρk
k 1logk
1δ, 2.2
whereCδ2δ1max{1, δδe−δ}.
Proof. For simplicity of notation, letIn,m
m−1
in
m
ji1EXiXj/bibj.Then we get by 1.1
and2.1that for 1≤n < m,
In,m≤ m−1
in m
ji1 ρj−i
bibj
≤D2
m−1
in m
ji1 ρj−i
ij D2
m−n
k1
m−k
in
ρk
iik D2
m−n
k1 ρk
k
m−k
in
1
i −
1
ik
≤D2
m−n
k1 ρk
k
nk−1
in
1
i.
We next estimateinnk−11/i.Ifn1,then
nk−1
in
1
i
k
i1
1
i ≤1
k
1
1
xdx≤1logk≤1logk
1δ. 2.4
Ifn≥2,then
nk−1
in
1
i ≤
nk−1
n−1
1
xdxlog
1 k
n−1
≤2 log
1k
n
. 2.5
The log1k/nis estimated as follows:
log
1 k
n ≤ ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ log
1 √1
n
≤ logn
δ
lognδ√n ≤
2δδe−δ
lognδ ≤2δ
δe−δ1logk
1δ
lognδ , if 1≤k≤ √
n,
log
1k
n
2 logkδ
lognδ ≤2
δlogk
1δ
lognδ ≤2
δ1logk
1δ
lognδ , if k > √
n. 2.6
Thus, we have the desired estimate forIn,m:
In,m≤
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
D2m−n
k1 ρk
k 1logk
1δ, if n1,
D2
m−n
k1 ρk
k
2 max{2δ,2δδe−δ}
lognδ 1logk
1δ, if n≥2,
≤ D22δ1max{1, δδe−δ}
max{log 2δ,lognδ}
m−n
k1 ρk
k 1logk 1δ.
2.7
The following lemma is a maximal inequality for general dependent random variables.
Lemma 2.2. Let{Xn, n ≥ 1}be a sequence of square integrable random variables. Then for alla ≥ 0
andn≥1,
E
max
1≤k≤n
ak
ia1 Xi 2 ≤ log 2n
log 2
2an
ia1
EXi22
an−1
ia1
an
ji1
EXiXj
. 2.8
Proof. LetFa,nbe the joint distribution function ofXa1, . . . , Xan.Define a functiongon{Fa,n:
a≥0, n≥1}by
gFa,n
an
ia1
EX2i 2
an−1
ia1
an
ji1
Then we can easily obtain that fora≥0, k≥1,andm≥1,
gFa,k gFak,m≤gFa,km. 2.10
Moreover, we have that for alla≥0 andn≥1,
E
an
ia1 Xi
2
≤gFa,n. 2.11
By Serfling’s9generalization of the Rademacher-Menchoffmaximal inequality for orthogo-nal random variables,
E
max
1≤k≤n
ak
ia1 Xi
2 ≤
log 2n log 2
2
gFa,n. 2.12
Thus, the result is proved.
Combining Lemmas 2.1 and 2.2gives the following maximal inequality for weighted
sums of dependent random variables satisfying1.1.
Lemma 2.3. Let{Xn, n≥1}be a sequence of square integrable random variables satisfying1.1. Let
{bn, n≥1}be a sequence of positive numbers satisfying2.1. Then for alln≥1, m > n,andδ >0,
E
max
n≤i≤m
i
jn
Xj
bj
2
≤
log2m−n1 log 2
2m
in
EXi2 b2i
2D2Cδ
max{log 2δ,lognδ}
m−n
k1 ρk
k 1logk 1δ
, 2.13
whereCδ2δ1max{1, δδe−δ}.
3. Almost surely convergent series and strong laws of large numbers
In this section, we will assume that {Xn, n ≥ 1} is a sequence of square integrable random
variables satisfying1.1. A sufficient condition will be given under which1.2and1.3hold. We first state and prove one of our main results. The proof is based on the well known method of subsequences. Our proof is similar to that of Hu et al. 2. However, the maximal inequalityLemma 2.3used in the proof is sharper than that of Hu et al.2.
Theorem 3.1. Let{Xn, n≥1}be a sequence of square integrable random variables satisfying1.1. Let
{bn, n ≥ 1}be a sequence of positive numbers satisfying2.1. Suppose that the following conditions
hold:
i∞n1logn2EX2
n/b2n<∞,
ii∞n1logn4δρn/n <∞for someδ >0.
Proof. As noted in the introduction, if 0 < bn ↑ ∞,then1.2implies1.3. To prove 1.2, let
Snni1Xi/bi.ByLemma 2.1withδreplaced by 3δ, we have that form > n,
ESm−Sn2 m
in1 EX2i
b2
i
2
m−1
in1
m
ji1 EXiXj
bibj
≤ m
in1 EX2i
b2
i
2D2C3δ
max{log 23δ,logn3δ}
m−n−1
k1 ρk
k1logk 4δ
≤ ∞
in1 EX2
i
b2
i
2D2C3δ
max{log 23δ,logn3δ}
∞
k1 ρk
k 1logk
4δ −→0
3.1
asn → ∞byiandii. HereC3δ2δ4max{1,3δ3δe−3δ}.By the Cauchy convergence
criterion, there exists a random variableSsuch thatESn−S2 → 0 asn → ∞.It is easy to see
thatS2n → Sa.s. by the standard method. It remains to show that
max
2n<k≤2n1|Sk−S2
n| −→0 a.s. asn−→ ∞. 3.2
UsingLemma 2.3,i, andii, we get that
∞
n1
P max
2n<k≤2n1|Sk−S2
n|>
≤ 1 2
∞
n1
E max
2n<k≤2n1|Sk−S2
n|2
≤ 1 2
∞
n1
log 2n1 log 2
2 2n1
i2n1 EXi2
b2i
2D2C3δ
log2n13δ
2n−1
k1 ρk
k1logk 4δ
≤ 1
2log 22
∞
i3
log2i2EX2
i
b2
i
2D2C3δ
2log 23δ
∞
n1
n12
n3δ
∞
k1 ρk
k1logk
4δ <∞.
3.3
Then3.2follows by the Borel-Cantelli lemma.
Remark 3.2. Hu et al.2provedTheorem 3.1underiandii.
ii ∞n1ρn/nq<∞for some 0≤q <1.
Since conditioniiofTheorem 3.1is weaker thanii,Theorem 3.1improves the result of Hu et al.2.
We can now establish the following SLLN if condition2.1on{bn}is replaced by the
condition 0< bn↑ ∞.
Theorem 3.3. Let{Xn, n≥1}be a sequence of square integrable random variables satisfying1.1. Let
{bn, n ≥ 1} be a nondecreasing unbounded sequence of positive numbers. Suppose that the following
conditions hold:
ii∞n1ρn∞in1logi2/b2i <∞,
iii∞n1EXn2
∞
in1logi/ibi2<∞.
Then1.3holds.
To proveTheorem 3.3, we need the following lemma which is due to Fazekas and Klesov
10.
Lemma 3.4. Let {Xn, n ≥ 1}be a sequence of random variables and{bn, n ≥ 1}be a nondecreasing
unbounded sequence of positive numbers. Let {αn, n ≥ 1} be a sequence of nonnegative numbers.
Assume that for eachn≥1,
E
max
1≤i≤n
i
j1 Xj
r
≤n
i1
αi, for some constantr >0. 3.4
If∞n1αn/brn<∞,then1.3holds.
Proof ofTheorem 3.3. FromLemma 2.2,
E
max
1≤i≤n
i
j1 Xj 2 ≤ log 2n
log 2
2n
i1
EXi22
n−1
i1
n
ji1
EXiXj
. 3.5
Defineαn log 2n/log 22An−log 2n−1/log 22An−1forn ≥ 1,where A0 0 andAn
n
i1EX2i 2
n−1
i1
n
ji1EXiXjforn≥1.ThenEmax1≤i≤n|
i
j1Xj|2≤
n
i1αiand
αn
log 2n log 2
2
An−An−1 An−1
log 2n
log 2 2
−
log 2n−1 log 2
2
log 2n
log 2
2
EXn22 n−1
i1
EXiXn
log 2n
log 2 2
−
log 2n−1 log 2
2n−1
i1
EX2i 2
n−2
i1
n−1
ji1
EXiXj
.
3.6
ByLemma 3.4, it is enough to show that ∞
n1
log 2n2EX2
n
b2
n
<∞, 3.7
∞
n1
log 2n2 b2n
n−1
i1
EXiXn<∞, 3.8
∞
n2
log 2n2−log 2n−12
b2n
n−1
i1 EX2
i <∞, 3.9
∞
n3
log 2n2−log 2n−12
b2
n
n−2
i1
n−1
ji1
EXiXj<∞. 3.10
The following corollary shows that conditioniiofTheorem 3.3can be simplified under the additional condition2.1on{bn}.
Corollary 3.5. Let{Xn, n ≥ 1}be a sequence of square integrable random variables satisfying1.1.
Let{bn, n≥1}be a nondecreasing unbounded sequence of positive numbers satisfying2.1. Suppose
that the following conditions hold: i∞n1logn2EX2
n/b2n<∞,
ii∞n1logn2ρn/n <∞,
iii∞n1EX2
n
∞
in1logi/ibi2<∞.
Then1.3holds.
Proof. By2.1, we have that ∞
n1 ρn
∞
in1
logi2 b2
i
≤D2
∞
n1 ρn
∞
in1
logi2 i2 ≤C
∞
n1 ρn
logn2
n 3.11
for some constantC >0.Thus the result follows byTheorem 3.3.
Remark 3.6. ConditioniiofCorollary 3.5is weaker than conditioniiofTheorem 3.1. On the other hand, an additional condition is needed inCorollary 3.5namely conditioniiiabove.
Using the following lemma, we can omit condition iii of Theorem 3.3 if conditions
2.1 and3.12on {bn} are satisfied. If C1n ≤ bn ≤ C2nα for all n ≥ 1 and some constants
C1>0, C2>0,andα >0,then2.1and3.12hold.
Lemma 3.7. Let{bn, n ≥ 1}be a nondecreasing unbounded sequence of positive numbers satisfying
2.1. If
lim sup
n→ ∞
logbn
logn <∞, 3.12
then
b2
n
log2n
∞
in
logi
ib2i O1. 3.13 Proof. Without loss of generality, we may assume thati≤bifor alli≥1.
Let fixn.For eachk ≥ 1,definemk bymk min{i ≥ n: bi ≥ kbn}.Thenbmk ≥ kbn and nm1≤m2≤ · · · .It follows that
b2n
log2n
∞
in
logi ib2
i
b2n
log2n
∞
k1
mk1−1
imk
logi ib2
i
≤ bn2
log2n
∞
k1
1
b2
mk
mk1−1
imk
logi
i by 0< bn ↑
≤ b2n
log2n
∞
k1
1
kbn2 mk1−1
imk
logi i
≤ 1
log2n
∞
k1
1
k2
3
i1
logi i
mk1−1
3
logx x dx
≤ 1
log2n
∞
k1
1
k2
log 2
2
log 3
3
logmk1−12
2
,
where we assume in the casemk1mk,the sum
mk1−1
imk 0.Sincebi≥ifor alli≥1, bkbn1≥ kbn 1≥kbnandmk ≤kbn 1≤kbn1.So we have that
logmk1−12≤logk1bn2≤2
logk12 logbn2
. 3.15 Substituting this into3.14,3.13holds by3.12.
The following example shows thatLemma 3.7fails if3.12does not hold.
Example 3.8. Let φ0 1 andφn 2φn−1 forn ≥ 1.Define a sequence{bn, n ≥ 1}bybn
φk1ifφk≤n < φk1.Then 0< bn ↑ ∞andbn≥nfor alln≥1.Sincebφnφn1, we obtain that
logbφn
logφn
logφn1
logφn
φnlog 2
logφn −→ ∞ 3.16
asn → ∞.Hence3.12does not hold. We also obtain that forn≥2, b2φn
log2φn
∞
iφn logi
ib2i ≥
bφ2n
log2φn
φn1−1
iφn logi
ib2i
1
log2φn
φn1−1
iφn
logi i
≥ 1
log2φn
φn1
φn
logx x dx
1
2
φnlog 2 logφn
2 − 1
2 −→ ∞
3.17
asn → ∞.So3.13does not hold.
If{bn}satisfies2.1and3.12, then we can obtain the following SLLN.
Theorem 3.9. Let{Xn, n≥1}be a sequence of square integrable random variables satisfying1.1. Let
{bn, n ≥ 1}be a nondecreasing unbounded sequence of positive numbers satisfying 2.1and3.12.
Suppose that the following conditions hold:
i∞n1logn2EX2
n/b2n<∞.
ii∞n1logn2ρn/n <∞.
Then1.3holds.
Proof. ByLemma 3.7andi, we get
∞
n1 EXn2
∞
in1
logi
ib2i ≤O1
∞
n1
log2n1EX2
n
bn21 <∞, 3.18
Remark 3.10. Under condition 3.12,Theorem 3.9improves Theorem 3.1, since conditionii ofTheorem 3.9is weaker than conditioniiofTheorem 3.1.
If bn n for all n ≥ 1, then {bn} satisfies 2.1 and 3.12. Hence we can obtain the
following.
Corollary 3.11. Let{Xn, n≥ 1}be a sequence of square integrable random variables satisfying1.1.
Suppose that the following conditions hold.
i∞n1logn2EXn2/n2<∞.
ii∞n1logn2ρn/n <∞.
Then the SLLN holds. Namely,
n
i1Xi
n −→0a.s. 3.19 Remark 3.12. Lyons3proved an SLLN3.19under the conditions thatEX2nO1and
∞
n1 ρn
n <∞. 3.20
When EXn2 O1,condition iofCorollary 3.11 is obviously satisfied. Hu et al.1proved
an SLLN3.19under conditions3.21and3.22:
∞
n1
Hnϕ1
n2 <∞, 3.21
∞
n1 ρn
nϕ−1 <∞, 3.22
whereϕ 1√5/21.618· · ·is the golden ratio, andHx>0 is a nondecreasing function on0,∞such that EXn2 ≤ Hnfor alln ≥ 1.Conditioniiof Corollary 3.11is weaker than
3.22. In general, conditioniofCorollary 3.11is not comparable with3.21.
Acknowledgments
The author would like to thank the referees for helpful comments and suggestions that considerably improved the presentation of this paper. This work was supported by Korea
Science and Engineering Foundation KOSEF grant funded by Korea government MOST
no. R01-2007-000-20053-0.
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