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http://dx.doi.org/10.4236/ojdm.2016.61002

On Mutually Orthogonal Graph-Path Squares

Ramadan El-Shanawany

Department of Physics and Engineering Mathematics, Faculty of Electronic Engineering, Menoufia University, Menouf, Egypt

Received 14 January 2015; accepted 14 December 2015; published 17 December 2015

Copyright © 2016 by author and Scientific Research Publishing Inc.

This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/

Abstract

A decomposition =

{

G G0, 1,,Gs1

}

of a graph H is a partition of the edge set of H into edge- disjoint subgraphs G G0, 1,,Gs1. If GiG for all i

{

0,1,,s1

}

, then  is a decomposition of H by G. Two decompositions =

{

G G0, 1,,Gn1

}

and =

{

F F0, 1,,Fn1

}

of the complete

bipartite graph Kn n, are orthogonal if, E G

( )

i

( )

Fj =1 for all i j,

{

0,1,,n1

}

. A set of decompositions

{

 0, 1,,k1

}

of Kn n, is a set of k mutually orthogonal graph squares (MOGS)

if i and j are orthogonal for all i j,

{

0,1,,k1

}

and ij. For any bipartite graph G with

n edges, N n G

(

,

)

denotes the maximum number k in a largest possible set

{

 0, 1,,k1

}

of

MOGS of Kn n, by 𝑮𝑮. Our objective in this paper is to compute N n G

(

,

)

where G=d+1

( )

F is a

path of length d with d + 1 vertices (i.e. Every edge of this path is one-to-one corresponding to an isomorphic to a certain graph F).

Keywords

Orthogonal Graph Squares, Orthogonal Double Cover

1. Introduction

In this paper we make use of the usual notation: Km n, for the complete bipartite graph with partition sets of sizes m and n, Pn+1 for the path on n + 1 vertices, DF for the disjoint union of D andF, DLv F for the

union of D and F with Lv (set of vertices) that belong to each other (i.e. union of D and F with common ver-tices of the set Lv belong to F and D), Kn for the complete graph on n vertices, K1 for an isolated vertex. The other terminologies not defined here can be found in [1].

(2)

sub-graphs G G0, 1,,Gs1. If GiG for all i

{

0,1,,s−1

}

, then  is a decomposition of H by G. Two

de-compositions =

{

G G0, 1,,Gn1

}

and  =

{

F F0, 1,,Fn1

}

of the complete bipartite graph Kn n, are or- thogonal if, E G

( )

i

( )

Fj =1 for all i j, ∈

{

0,1,,n−1

}

. Orthogonality requires that E G

( )

i = =n E F

( )

i

for all i

{

0,1,,n−1

}

. A set of decompositions

{

 0, 1,,k1

}

of Kn n, is a set of k mutually orthogonal graph squares (MOGS) if i and j are orthogonal for all i j, ∈

{

0,1,,k−1

}

and ij. We use the nota-tion N n G

(

,

)

for the maximum number k in a largest possible set

{

 0, 1,,k1

}

of MOGS of Kn n, by G, where G is a bipartite graph with n edges.

If two decompositions  and  of Kn n, by G are orthogonal, then   is an orthogonal double cover of Kn n, by G. Orthogonal decompositions of graphs and orthogonal double covers (ODC) of graphs have been studied by several authors; see the survey articles [2][3].

It is well-known that orthogonal Latin squares exist for every n

{ }

2, 6 . A family of k-orthogonal Latin squares of order n is a set of k Latin squares any two of which are orthogonal. It is customary to denote

( )

max

{

:

}

N n = kk MOLS be the maximal number of squares in the largest possible set of mutually ortho-gonal Latin squares MOLS of side n. A decomposition of Kn n, by nK2 is equivalent to a Latin square of side n; two decompositions  and  of Kn n, by nK2 are orthogonal if and only if the corresponding Latin squares of side n are orthogonal; and thus N n nK

(

, 2

)

=N n

( )

. The computation of N n

( )

is one of the most difficult problems in combinatorial designs; see the survey articles by Abel et al.[4] and Colbourn and Dinitz in

[5]. Since N n G

(

,

)

is a natural extension of N n

( )

, the study of N n G

(

,

)

for general graphs is interesting.

El-Shanawany [6] establishes the following: i) N n K

(

, 1,n

)

=2; ii)

(

)

(

)

(

)

3 4

6

2, 2, 3, 3, 5, 5

N P = N P = N P = and

(

7, 8

)

7

N P = ; iii) let p>2 be a prime number, then N p K

(

, 2+

(

(

p−1 2

)

)

P3

)

=p; iv) let p be a prime number, then N p p

(

,

(

−2

)

K2+P3

)

≥ −p 1. Based on ii), El-Shanawany [6] proposed:

Conjecturer 1. Let p be a prime number. Then N p P

(

, p+1

)

=p.

Sampathkumar et al.[7] have proved El-Shanawany conjectured. In the following section, we present another technique to prove this conjecture as in Theorem 8.

The two sets

{

0 0

(

)

}

0

0 ,1 ,, n−1 and

{

1 1

(

)

}

1

0 ,1 ,, n−1 denote the vertices of the partite sets of Kn n, . The

length of the edge x y0 1 of Kn n, is defined to be the difference yx, where x y, ∈n. Note that sums and

differences are carried over in n (that is, sums and differences are carried modulo n). Let G be a subgraph of

, n n

K without isolated vertices and let a

{

0,1,,n−1

}

. The a-translate of G, denoted by G+a, is the edge- induced subgraph of Kn n, induced by

{

(

x+a

) (

0 y+a

)

1:x y0 1∈E G

( )

}

. A subgraph G of Kn n, is half-starter

if E G

( )

=n and the lengths of all edges in G are mutually different.

Lemma 2 (see [8]). If G is a half-starter, then the union of all translates of G forms an edge decomposition of

, n n

K (i.e.

( )

,

(

)

n

n n a

E K =

E G+a ).

In what follows, we denote a half-starter G by the vector

( ) (

0 1 1

)

times

, , , n nn n n n

n

v G = v vv− ∈  =× × ×  ,

where v v0, ,1,vn1∈n and vi can be obtained from the unique edge

( ) (

vi 0 vi+i

)

1 of length i in G.

Theorem 3 (see [8]). Two half-starters

( ) (

0, ,1 , 1

)

n

n n

v G = v vv ∈ and

( ) (

0, 1, , 1

)

n

n n

v F = u uu ∈ are orthogonal if

{

viu ii: ∈n

}

=n.

If two half-starters v G

( )

and v F

( )

are orthogonal, then the set of translates of G and the set of translates of F are orthogonal.

A set of decompositions

{

(

)

( )

, : 0 1

}

n

i=

a∈ E Gi+a =E Kn n ≤ ≤ −i k

 of Kn n, } is a set of k mutually or-

thogonal graph squares (MOGS) if i and j are orthogonal for all i j, ∈

{

0,1,,k−1

}

and ij. Note that

(

)

(

)

(

)

1 1

,

0 0 n .

k k

i i n n

i i a E G a kE K

− −

= =

 

= ∈ + =

In the following, we define a G-square over additive group n.

(3)

( ) ( ) ( )

i

{

, : , , , n

}

E G = x yx y =i x y∈ are isomorphic to graph G.

We have already from Lemma 2 and Definition 4 that every half starter vector v G

( )

and its translates are equivalent to G-square. For more illustration, the first matrix 0 in equation (1) is equivalent to the first row in

Figure 3, which represented by the half starter vector v G

( ) (

00 = 0, 0, 2

)

and its translates.

Definition 5. Two squares matrices 0 and 1 of order n are said to be orthogonal if for any ordered pair

( )

a b, , there is exactly one position

(

x y,

)

for 0

(

x y,

)

=a and 1

(

x y,

)

=b.

Now, we shall derive a class of mutually orthogonal subgraphs of Kn n, by a given graph G as follow.

Definition 6. A set of matrices

{

i: 0≤ ≤ −i k 1

}

of Kn n, is called a set of k mutually orthogonal graph squares (MOGS) if i and j are orthogonal for all i j, ∈

{

0,1,,k−1

}

and ij.

Definition 7 (see [9]). Let F be a certain graph, the graph F-path denoted by d+1

( )

F , is a path of a set of vertices =

{

i: 0≤ ≤i d

}

and a set of edges  =

{

i: 0≤ ≤ −i d 1

}

if and only if there exists the following two bijective mappings:

1) Ψ :→ defined by Ψ

( )

i =Fi, where =

{

F F0, 1,,Fd1

}

is a collection of d graphs, each one is isomorphic to the graph F.

2)

φ

:→ defined by φ

( )

i =Xi, where =

{

Xi: 0≤ ≤i d;

iXi= ∅

}

is a class of disjoint sets of

vertices (i.e.,  decomposed into d+1 disjoint sets such that no two vertices within the same set are adja-cent).

As a special case if the given graph F is isomorphic to K1,1 then d+1

( )

K1,1 , is the natural path Pd+1 that is,

( )

1 1,1 1

d+ K =Pd+

 .

[image:3.595.186.439.335.700.2]

For more illustration, see Figure 1, Figure 2.

Figure 1.6

( )

K2,2 , the path of 6 sets of vertices (every sethas only 2

[image:3.595.193.436.337.503.2]

disjoint vertices) and 5 edges of K2,2.

Figure 2.6

( )

K1,3 , the path of 6 sets of vertices and 5 edges of K1,3.

E

0

E

1

E

2

E

3

E

4

v

0

v

1

v

2

v

3

v

4

v

5

E

0

E

1

E

2

E

3

E

4

(4)

Consider s≥0 paths of length k≥1, all attached to the same vertex (root vertex). This tree will be called

( )

,

T s k . Clearly, T s

( )

,1 is the star with s edges and T

( )

1,k is the path with k edges. Define Ls as a set of all leaves of T s k

( )

, i.e. Ls=

{

v v: is a leaf in T s k

( )

,

}

and L_

{ }

s =s.

In the following section, we will compute N n G

(

,

)

where G=d+1

( )

F such that F=K1,1 as in theorem 8 and

( )

3

1 3, 3 L

F=TK as in theorem 11.

2. Mutually Orthogonal Graph-Path Squares

The following result was shown in [7]. Here we present another technique for the proof.

Theorem 8. Let q be a prime number. Then N q

(

,q+1

( )

K1,1

)

=q.

Proof. Let Gij be a subgraph of Kq q, with q edges; for fixed j∈q and 0≤ ≤ −i q 1, define the q half- starter vectors as follows, v G

( )

ij =

(

j i, + −j 1, 2i+ −j 2 ,2 ,

( )(

−2 i+ +2

)

j,

( )(

−1 i+ +1

)

j

)

; our task is to prove the orthogonality of those q half-stater vectors in mutually. Let us define the half starter vector v G

( )

ij as

( )

(

)

k ij

v G =k ik + j for all k∈q. Then for all two different elements k l, ∈q, we have

( ) ( )

(

) (

) (

)

(

(

)

)

{

v Gk ijv Gl ij =k ikl i− =l kl ik+l

}

, then vk, vl are mutually orthogonal half-starter

vectors of graphs Gkj and Glj of Kq q, respectively iff

(

i

(

k+l

)

,q

)

=1. It remains to prove the isomor-phism of v Gk

( )

ij half starter graphs Gij of Kq q, for all k∈q. Let

( )

(

)

( ) (

)

k ij k is

v G =k ik + =j v G =k ik +s, and therefore j=s. Furthermore, if

( )

(

)

( )

(

)

k ij l ij

v G =k ik + =j v G =l i l− + j, then

(

kl

)

(

i

(

k+l

)

)

=0, since i

(

k+ ≠l

)

0 (orthogonality

of vk and vl), and therefore k=l. Moreover, for any i j, ∈q the

th

ij graph isomorphic to Gij has the edges:

( )

{

(

2

)

(

(

)

)

}

1 0 1 . ij

E G = − +i j i − +i j

An immediate consequence of the Theorem 8 and Conjecture 1 is the following result.

Example 9. The three mutually orthogonal decompositions (MOD) of K3,3 by P4 given in Figure 3 are associated with the three mutually orthogonal P4-squares as in Equation (1):

0 1 2

0 0 1 0 2 2 0 1 0

2 1 1 , 0 1 0 , 1 1 2 .

2 0 2 1 1 2 0 2 2

     

     

= = =

     

     

   (1)

[image:4.595.147.493.391.721.2]

Note that, every row in Figure 3 represents edge decompositions of K3,3 by P4.

Figure 3. 3MOD of K3,3 by P4.

0 0 0

G00 G01 G02

G11 G12

G20 G21 G22

G10

0 1 2

1 1

0 1 2

1 1

0 1 2

0 0 0

0 1 2 00 10 20

0 0 0

0 1 2 00 10 20

0 0 0

0 1 2

1 1

0 1 2

1 1

0 1 2 0 11 21

1 1

0 1 2

1 1

0 1 2 0 11 21

1 1

0 1 2

0 0 0

0 1 2 00 10 20

0 0 0

(5)
[image:5.595.154.482.81.180.2]

Figure 4.

(

( )

3

)

4 3,3 1

L

TK

 , the path of 4 vertices and 3 edges of

( )

3

1

3,3 L

TK .

The following result is a generalization of the Theorem 8.

Theorem 10. Let n be a prime power such that n=qx with integer power x≥1 of a prime number q and G be a subgraph of Kn n, . Then N n G

(

,

)

q.

Proof. For fixed j∈n, 0≤ ≤ −i q 1 and GijG, define the q half-starter vectors as follows,

( )

(

2

( )(

)

( )(

)

)

, 1, 2 2 , , 2 2 , 1 1 .

ij

v G = j i+ −j i+ −j  − i+ + ji+ + j (2)

Our task is to prove the orthogonality of those q half-starter vectors in mutually. Let us define the half starter vector v G

( )

ij as v Gk

( )

ij =k i

(

k

)

+ j for all k∈q. Then for all two different elements k l, ∈q, we

have

{

v Gk

( ) ( )

ijv Gl ij =k i

(

k

) (

l i− =l

) (

kl

)

(

i

(

k+l

)

)

}

, and then vk, vl are mutually orthogonal half-stater vectors of graphs Gkj and Glj of Kn n, respectively iff

(

i

(

k+l

)

,n

)

=1. It remains to prove the isomorphism of v Gk

( )

ij half starter graphs Gij of Kn n, for all k∈q. Let

( )

(

)

( ) (

)

k ij k is

v G =k ik + =j v G =k ik +s, and therefore j=s. Furthermore, if

( )

(

)

( )

(

)

k ij l ij

v G =k ik + =j v G =l i l− + j, then

(

kl

)

(

i

(

k+l

)

)

=0, since i

(

k+ ≠l

)

0 (orthogonality

of vk and vl), and therefore k=l. Moreover, for any 0≤ ≤ −i q 1,j∈n the

th

ij graph Gij isomorphic to G has the edges:

( )

{

(

2

)

(

( )

)

}

1

0 1 .

ij

E G = n i− +j n i i− − + j (3)

■ Note that, in the special case x=1 the Theorem 10 proved El-Shanawany conjecture; also, in the case

2, 1

q= x≠ , and G≠2K2, Theorem 10 constructed an orthogonal double cover of Kn n, by G. Furthermore, we can construct the following result using Theorem 10 in case x>1 and q=3.

Theorem 11. Let x≥2 be a positive integer such that 3x

n= and

(

( )

3

)

2 1

3x 1 3, 3 L

T K

+

 be a subgraph of

3 ,3x x

K . Then

(

(

( )

3

)

)

2 1

3 1

3 , x 3, 3 3.

L x

N  − + TK

Proof. The result follows from the vector in Equation (2) and its edges in Equation (3) with

( )

( )

3

1 , 3, 3 1

L d

G= + F F =TK such that E G

( )

=3x = E F d

( )

=9d, imply that d=3x−2 which define the number of graphs isomorphic to F. As a direct application of Theorem 11; see Figure 4. ■

Conjecture 12. N q

(

x,q+1

( )

K1,1

)

=qx if q is a prime number with an integer power x≥1.

Conjecture 13.

(

( )

3

)

1 1

, x 3, 3 L x

q sk

N q T K q

+

 

  ≥

 

   

if q is a prime number with an integer power x≥1 and

,

s k are positive integers.

References

[1] Balakrishnan, R. and Ranganathan, K. (2012) A Textbook of Graph Theory. Springer, Berlin.

http://dx.doi.org/10.1007/978-1-4614-4529-6

[2] Alspach, B., Heinrich, K. and Liu, G. (1992) Orthogonal Factorizations of Graphs. In: Dinitz, J.H. and Stinson, D.R., Eds., Contemporary Design Theory, Chapter 2, Wiley, New York, 13-40.

[3] Gronau, H.-D.O.F., Hartmann, S., Grüttmüller, M., Leck, U. and Leck, V. (2002) On Orthogonal Double Covers of

0 0 91 0 1 18

1 80

260

170 50

140

230

251 180

71 121

31

211

61 200

241 20

(6)

Graphs. Designs, Codes and Cryptography, 27, 49-91. http://dx.doi.org/10.1023/A:1016546402248

[4] Colbourn, C.J. and Dinitz, J.H. (eds.) (2007) Handbook of Combinatorial Designs. 2nd Edition, Chapman & Hall/CRC, London, Boca Raton.

[5] Colbourn, C.J. and Dinitz, J.H. (2001) Mutually Orthogonal Latin Squares: A Brief Survey of Constructions. Journal

of Statistical Planning and Inference, 95, 9-48. http://dx.doi.org/10.1016/S0378-3758(00)00276-7

[6] El-Shanawany, R. (2002) Orthogonal Double Covers of Complete Bipartite Graphs. Ph.D. Thesis, Universitat Rostock, Rostock.

[7] Sampathkumar, R. and Srinivasan, S. (2009) Mutually Orthogonal Graph Squares. Journal of Combinatorial Designs,

17, 369-373. http://dx.doi.org/10.1002/jcd.20216

[8] El-Shanawany, R., Gronau, H.-D.O.F. and Grüttmüller, M. (2004) Orthogonal Double Covers of Kn,n by Small Graphs.

Discrete Applied Mathematics, 138, 47-63. http://dx.doi.org/10.1016/S0166-218X(03)00269-5

Figure

Figure 1. ()6K2,2, the path of 6 sets of vertices (every sethas only 2
Figure 3. 3MOD of
Figure 4. 4

References

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