Math. Sci. VOL. 18 NO. 3 (1995) 417-436
417
NORMS
FOR
COPULAS
WILLIAM F. DARSOWandELWOOD T. OLSEN
Department
of Mathematics Illinois Instituteof TechnologyChicago, Illinois 60616
(Received October 19, 1993 and in revised form July 20, 1994)
ABSTRACT. We
considerseveral norms onthespanof the setC ofallcopulas. Dominance and equivalence relationshipsamongthenorms arediscussed, and completenessissues areaddressed. Themotivationfor the studyisdiscussed. Applications to the study ofoneparametersemigroups of copulasarealso addressed.KEY WORDS AND PHRASES.
Copulas, doubly stochastic measures, Banach algebras, oneparameter semigroups.
1991
AMS SUBJECT
CLASSIFICATION CODES.
46B20,28A35,
60J251.
INTRODUCTION.
A
copula is a function C[0,1]
2[0,
1]
satisfying the boundary conditionsC(x,O)
C(O,y)
O,C(x,
1)
x andC(1,y)
y, for all x,yE[0,
1],
and the monotonicity conditionc(,)
c(=, )
c(=,
u)
+
c(,
)
>
0wheneverxl ix2andyl
_<
y2. These conditions imply that Cis acontinuous function. Copulasareofinterestbecausetheylink jointdistributionsto marginal distributions: forany real valued random variables
X
andX2
with joint distributionF12
there is acopula C such thatF12(Xl,X2)
C(FI(xl),
F2(x2))
where
Ft
andF2
denote thecumulative distribution functions ofX
and X2, respectively. For aproof, seeSklar[6, 7].
Knowledge ofbasicproperties ofcopulas will beassumedin this paper, thoughreferenceswilloften be given when they are used. For a discussionof these properties,see
Darsow
et al.[2];
Sklar[6,
7].
Wedenote by C the setof all copulas. C is closedunder convexcombinations and under a
product operation
A
B defined byA
*B(x,
y)
A,2(x, t)B,z (t,
y)
Hereandin thesequel the subscripts and 2 denote partial derivatives:
aB(,
B,(,)
-x
’(’)
418 W. F. DARSOW AND E. T. OLSEN
The copulas
P(x,y)
xy andM(x,y)
min{x,y}
are null and unit elements with respect to theproduct operation" that is,A.P-P.A-P
A.M-M.A-A
for allcopulas
A,
asisreadily verified using the definition of the product.A
copula Eisidempotent ifE E E; both P and M areidempotent, and therearemany other idempotents.A
copulaA is left invertibleif there isa copulaB such that B A M and right invertible if thereis a
copula B such that A B M. If A is left invertible, its left inverse is the copula
AT
defined byAT(x,y)
A(y,x);
similarly, ifA isright invertible,its rightinverse isAT,
Darsow et al.[2].
Thereexist copulas which possess one-sidedbut not two-sidedinverses.ThesetCisalso closed under uniformlimits" if
A,
ECfor allnandAn
A uniformly, then necessarilyA
E C.In
fact, theset Cis acompact subset ofC([0,
1]
2)
under the uniformnorm. This is auseful property.However,
theproduct does not behave well under the uniformnorm. IfA,
A
uniformlyandB is anycopula,thenA,
BA
B andBA,
BA,
Darsow
et al.[2],
sothat the product is continuous ineachplace. But the productisnotjointlycontinuous. It can be shown that(two-sided)
invertible copulas are dense in C in the topology of uniform convergence. IfA, is a sequenceofinvertible copulas converging to anoninvertible copula, say P, thenAT
.
A,
M for all n butpT,
p p M It follows that the product is not jointly continuous. This is an inconvenientfact,
andapart of the motivationfor the research reported here was to find a natural topology on the set ofcopulas under which the product operationwas not only continuous ineach placebut also jointly continuous. The joint continuity issue is discussedat various points in the paper.
One
parameter semigroups of copulasarisenaturally in thestudyofMarkovprocesses,Dar-sowetal.
[2].
Let
Cbe anycopula, letEbeanidempotent copulasatisfying C E E C C,and leta beapositive number. Then
At
defined for>_
0byAt
e-t
(
E+
(at)C)k’
k--1
isasemigroupof copulas:
A+,
A.
At.
In
thedefinition,C denotes thek-fold product of C withitself;theseriesconvergesuniformlyfor allaandt, asiseasy toverify. The classicaltheoryofoneparametersemigroupsis developedin the context of Banach algebras. To investigate the applicability of the classicaltheoryto semigroups ofcopulas, it is natural, first, towork in the spanof
C,
whichwewilldenotespan(C),
ratherthanC itself, and, second,to seekanormunder which span(C)
is in fact a Banach algebra. This was a second part of the motivation for the research reported here. The application ofthisresearch tooneparametersemigroupsof copulas is discussedin Section 6 ofthispaper.The paper is organizedasfollows:
In
Section2, Preliminaries,wediscussspan(C)
and define thenormstobetreated insubsequent sections.In
Sections3, 4 and5,wediscuss the Minkowskinorm, Sobolev norms, and the Jordan norm onspan
(C),
respectively. Section 6 is devoted to semigroups ofcopulas and Section 7,to discussion andconclusions; inparticular, weshall makesome commentsabout compactnessinSection 7. 2.
PRELIMINARIES.
By
span(C)
wemeanthelinear spanofthe copulas the setofall finite real linear combi-nations of elements ofC.Any
elementA
span(C)
canbewritten intheformA-sB-tC
(2.1)
wheres and are nonnegative andB andC arecopulas. To seethis, observe thatif
A
akAk
419
where
Ak
EC and ak is arealnumber, then we can writeA s
Ak
Ak
sB tC8
a >0 a <0 wherethe last equality defines B and C and
s-
a
and t--a.
>0 a<0
(In
bothoftheforegoingequations, the sumistakentobezeroif theset summedover isempty.)
Observe that B andC are copulas, since C isclosed under convex combinations. We will makerepeated useof theobservation
(2.1),
usuallywithoutcomment.Wenowdefine thenorms wewillinvestigate.
Minkowski norm. The symbol B
-co(-C
UC)
denotes the convex hull of the set -Cthat is, the set of all convex combinations of members of C and -C. It is easy to see that span
(C)
UtRoB.
For
anyA
span(C)
defineIAM
inf{
>
0A
e
B}.
(2.2)
IIM
is sometimes referred to as a Minkowskifunctional; it is easy toverify that it is a norm on span(C),
e.g. Rudin[5].
Thereisamoreconvenient definitionof the Minkowski functional:AM
inf{s
+
t
s, 0andA
sB CforsomeB,
Ce
C}.
Itis easy to
veN
that(2.2)
and(2.a)
areequivalent definitions; weomit theproof.We
will show in Sectiona
that span(C)
is a Banach algebraunder the norm1"
I-
The problem with the Minkowski functionalisthatit isdiNcult tocomputeand thusiscumbersome to workwith.We
includesomeresults inSectiona
which facilitate the calculationofthe MinkowsN normforcertainspecial classes of elements ofspan(C).
Sobolevnorms. Sincethe product isdefined using first partialderivatives, it seemsnatural towork withnormswhich take derivativesinto account. It isreadily veNfied that
c
,(0,
form 0, and allp
e [1, ].
Wm’()
denotes theSobolevspace{lI
e
L(a)
andDI
e
L(a)
for all multi-indices forwhichI1
mHere,
C R,
amulti-index is ad-tuple ofnonnegative integers,]
denotes thesumof the components of,
and D denotes a distributional partial derivative.In
our ce, d 2 andm -0or1, sothat
(0,0), (1, 0)
or(0,
1),
andD(’)I
I,
D(’)I
I,t
andD(’)
It iswell known, e.g. Adams
[1],
that each of the Sobolevspaces so defined is a Banaeh spree(i.e.,
iscomplete)
under thenormdefinedby(2.4)
Wewillshow inSection 4 thatC isacompletemetric spaceunder the Sobolevnorms
]l" I[:,p
and that on C theproduct isjointly continuous with respect toIIx,
for[1, );
it isanopen issue whether the product is continuous
(jointly
orseparately)
with respect to the norm420 W. F. DARSOW AND E. T. OLSEN
any ofthe I4
....
P spaces. The issue of continuity ofthe product on span(C),
as opposedto Citself, is anopen one.
Jordannorm. Wehave occasionally foundit convenient towork withoneothernorm. It is well known, of.
Darsow
et al.[2],
that a copula induces a unique doubly stochastic probabilitymeasure ttcon[0,
1]
viatheassignmentasthemeasureofarectangle. Conversely, foranydoublystochastic measure#, thereis aunique
copula
C,
definedviac.(,)
(10,l
I0,l).
Thus, doublystochastic measures on
I0, 1]
2 and copulas are in one to one correspondence.An
element C E span(C)
inducesafinite signedmeasure on[0,
112
viathe definition(2.5).
Alllinear combinationsof doublystochastic measures areobtained in thismanner.It is also well known, cf. Italmos
[3],
that for anyfinite signedmeasure # thereexist mea-surable setsE + andE- such that E +NE-,
E +t_lE-[0,
1]
2and, for allmeasurable setsF,
#(E
+C)F) _>
0and#(E-
NF) _<
0. Itfollows that#+
and#-defined by.+(r)-
.(E
+r)
#-(F)--#(E-NF)
are measures.
Furthermore,
#+
and /z- are unique, though the sets E + and E- need not be. The decomposition ##+
it- ofa finite signed measure as the difference oftwo measures is called the Jordan decomposition. The set of finite signedmeasures is closed under real linear combinations,and it isaneasy exercisetoshowthatdefines anormonthe set under which the set isa Banach space, Halmos
[3,
p. 123,Ex.
(4)].
For A
E span(C)
wedefinethe "Jordan"(or
totalvariation)
normWe will show in Section 5 that the Jordan norm dominates, but is not equivalent to, the uniform normand isdominated by, butisnot equivalent to, the Minkowski functional.
We
will alsoshow that span(C)
isnot complete with respect to the Jordannorm. The continuity(or
lackthereof)
of the product in thetopologyof the Jordannormisanopenissue.3.
MINKOWSKI NORM.
We
willshow that span(C)
is aBanach algebraunder the Minkowskinorm. Theproofwill be by way oftwo preliminary lemmas and two theorems. Then we will state andprove some miscellaneousfactswhich areusefulincomputing theMinkowski normofanelement of span in somespecialcases.LEMMA
3.1. The Minkowskinormdominates theuniform(W
,)
normonspan(C).
PROOF.
ObservethatifA
sBtC,
where s,>_
0andB,
CC,
thenIlAIIo,o
<
[IBIIo,o
+
tllCIIo,
+
since the uniform norm ofany copula is 1. Thus,
IIAII0,o
is a lower bound ofthe set whosegreatestlower bound isthe Minkowskinorm. The desired conclusionfollows. | The infimum in the definition
(2.2)
of the Minkowski norm is actually achieved:421
PROOF. By
theproperty oftheinfimum, there existnumberss,,tn _>
0and copulasBn,Cn
such that A s,B,- t,C, and s,+
t,IIAIM.
ButB,(1,1)
C,(1, 1)
for all n, so s.tn
A(1, 1)
is aconstant(and
thusconvergent)
sequence. Itfollows thatthe sequences andt
both converge; call their limits s and t. Furthermore, sinceC is compact in the uniform topology, there is an increasing sequence ofindices nk such thatB,
andC.
both converge uniformly;call theiruniformlimits B and C. Clearly A sB tC.THEOREM
3.1.Span(C)is
complete under[[-
JIM.
PROOF.
Thisisaclassicalproof, adaptedtothecaseof copulas.Suppose
thatAn
isCauchy withrespectto[[-JIM.
Passingtoasubsequence, if needbe,assumethat[[A,+i-A[[M
2-(+)for alln. Using Lemma 3.2,we canfindnonnegative numbers
sn
andt
andcopulasB
andCn
such thatAn
snBn
tnCn
andsn
+
tn
]]AnM.
Observethat
(by
the triangleinequality)
the sequence of numbers]]An]]M
sn
+
tn
is Cauchy,and obsee also that
s-
t
A(1, 1)
is Cauchy, since byLemma
3.1 the Minkowski norm dominates the uniformnorm. It follows upontang
sums and differences that boths
andt
are Cauchy; call their limits s and t. Since C is compact, we can find an increasing sequence nk ofindices such that
Bn
andC
both converge uniformly; call their limits B and C. SetA- sB- tC and observe thatA span
(C).
ClearlyAn
A
uniformly, andA
A uniformly follows easily.To
completetheproof,obsee that we can writeA-AI+(A+I-A).
k=l
This istrue pointwise,by the argument above. But also
IIA
A.IIM
--II
(A+t-
A)IIM
2
-(+1.
hus,
I1
IIM
0, and span(C)
is completeunderIIM.
I
The followingtheorem completes theproofthat span
(C),
togetherwith the product,is Banachalgebra.It
isnot obvious, but definesanassociative binary operation onC, Darsow
et al.[2],
and assoeiativity fortheextensionof toall of span(C)
follows,
so weneednot address this issue.THEOREM
3.2.For
allA1,A2 e
span(C),
IIA
*A2IIM
[[AtIIMIIA2IIM.
PROOF.
WteAk
skBk- tkCk
where sk,tk 0, Bk,Ck
C and sk k--1,2. Thentt2
C2)
sis2
B1
*B2
C1
*A
A2
(ss2
+
tt2)(ss2
tlt2 8182
+
tit2st2 tls2
C
B2
+
B
(ts2
+
st2)(tls
lt2
tls2
+
sit2(ss2
+
tlt2)B’-
(ts2
+
st2)C’.
The last expression defines
B
andC;
clearly both are copulas, since C is closed under theproductand underconvex combinations. Itfollows that
422 W. F. DARSOW AND E. T. OLSEN
This completes theproofof the mainresult concerning the Minkowski norm. Observethat continuity of the product in each place, and also joint continuity, follow immediately from Theorem 3.2. We turn to the computation of
IIM
in specialcases.THEOREM
3.3. IfB and C areany two distinctleft(or
right)
invertiblecopulas, ands andareanynonnegative real numbers, then
IIsB
tell
M s /t.PROOF. Suppose
that B and C are left invertible and B#
C, and s,>
0. Clearlylimb
ClIM
<
+
.
Since B and C are left invertible,
B,1
andC,1
are 0or almost everywhere,Darsow
et al.[2].
It
is easy toseethat the measureof the set where the first partial derivativeB,1
is is1/2,
and similarly for themeasureof thesetwhereC,1
1. Since B#
C, it follows that the setsF
(x,
y)
lB,(x,
y)
andC,1 (x,
y)
0}
F2
{(x,
y)
B,i(x,
y)
0andC,(x,y)
1}
have
(equal)
nonzeromeasure. Now suppose thats,
>
0 andD,
EEC aresuch thatsB tC
sD
tE.
Take partialderivativeswithrespecttoxandevaluate at points
(x,
y)
EF1
where thederivatives of allfour copulas B, C, D andE exist(this
is almost all points of F1,[2])
to obtains
sB,l(x,y)- tC,
l(x,y)
s’D,l(x,y)- t’E,l(x,y))
<
s’
using the fact that the first partial derivatives ofany copulaliein
[0,
1],
wherevertheyexist,[2].
It
follows thats<
s’.
By
similarargument, evaluatingonF2,<
t’.
Thuss+
<
This completes theproofforleftinvertiblecopulas. The corresponding result forright invertible
copulas follows bytaking transposes. |
It
follows from the foregoing result that if B and C are any two distinct left(or
right)
invertiblecopulas, thenlib
-CIIM
2. The topology of the Minkowski norm, restricted to the group ofinvertiblecopulas, isaccordingly thediscretetopology.The next result concerns the Minkowski norm ofdifferences ofcopulas which are ordinal sums. The ordinalsumconstructionis asfollows:
Let
{(a,, bn)}neZ
bea partitionof[0,
1],
thatis, a finite or countable set ofdisjoint open intervals the closure ofwhose union is the whole interval.
To
eachne
2", assignacopulaA,.
DefineafunctionA
[0,
1]
2[0, 1]
via-
-
-
-
(,)
[.,
.12
A(x,y)
a,+
(b.
a,)A,(b,
an’
bn
a,M
(x,
y),
otherwise.ThenA isacopula, Darsowetal.
[2].
A
iscalled theordinal sumof the copulasAn
withrespecttothe given partition. Wewillwrite
A
@,ezAr,for theordinalsum.THEOREM
3.4.Let
A
,e2"A, and B,ezB,,
be copulas which areordinal sums withrespecttothesame partition of[0, 1].
ThenIIA
sll
M max[IA,
BnllM.
PrtOO.
w
,m
prot
rut
wn
Z-
{,}
n
(,)
(0,
a)
nd(, )
(,)
forsome
,
(E(0, 1).
The general result thenfollowsviaaninductiveargument.Thus, suppose thatA1,
A, B1
andBg arecopulas andwritec(-,_
-),
o
<
,
<
c(,)
c
c(,)
+
(
)c(
x1_),
1_))
,X<x,y<l(3.1)
whereC AorB.
Suppose
A1-
BI
sD1-tD2
wheres,>
0, D,D2
e
Cand[[A1-
Bt[[M
s+t"evaluate at(1, 1)
andconcludethatnecessarilys t. Similarly,supposeA2-B2
uEl-vE2
where u, v 0, El,
E2
E C andJJA2
B2JJM
u -t-v" evaluate at(1, 1)
and conclude that necessarily u v.Suppose
thats>
u(the
proofis similar ifsu)
andsetU 3 I1
F
-E
+
5I, k 1,2.8
Then
A2
B2
sF1
sF2.
It follows thatA- B sDi O
Fi
sD2
F2
so that
IIA
BIIM
_<
2s- maxk=,2IlAk-
BalIM.
The opposite inequalityutilizesaconstructionwehave occasionally found usefulintryingto work with the Minkowski norm.
Suppose
thatA
B sDrE,
wheres,_>
0,D,
E EC andIIA
BIIM
s+
t; evaluate at(1, 1)
and conclude that s t; evaluateat(x,A)
and(A,y)
and conclude(using
thefact that, by(3.1),
A
and Bagree at(x,A)
and(A, y))
D(x,
)
E(x,
)
for allx(3.2)
D(,
y)
E(,
y)
for ally.(3.3)
We
want to show thatIIAk- BkllM
<_
2S, k 1,2. Wewill show that the result holds for k 1; theproof fork 2 issimilar.Observe first that
O
(D(x
1y))-
D,(1x
1y)
<
Oz
o
D(
//- D,=( /
<
0--;(
Itfollows that if for any>
0weset(x)-
((l+e)x-
(,x,A))/
+e--D(A,A)
thefunctions4) and arestrictly increasingon
[0, 1].
(Observe
that necessarilyD(A, A)
_<
,k; this is a basicproperty of copulas, Darsow et al.[2].)
To complete the construction, define forall(,)
[0,
1--D(Ax,
Ay)
b
(, )
()()
+
E(,)
k
(,
)=
()()+
It
is readily verified thatD1
bl/(1
+e)
andE1
/1/(1
+e)
arecopulas;monotonocityfollows fromthe fact thatD
andE arecopulas and thefactthat and are increasing; theboundary conditionsforD1
areverifiedbydirect calculation,and those forE
follow from(3.2)
and(3.3).
Thedesiredresultnowfollowseasily.
For
all x, yE[0,
1]
wehavebyconstruction 1B
A(x,y)- B(x,y)
1--A(Ax
Ay)-
(.kx, Ay)
(using
(3.1))
s_
E-DS
(Ax,
Ay)
,
(Ax,
Ay)
424 W. F. DARSOW AND E. T. OLSEN
Thus, forany
>
O,IIA,
BI[IM
<_
(1
+
e)2s
(1
+
t)[IA
BI[M.
The theorem follows.I
Since span(C)
is aBanachalgebraunderI[" I[M,
the Minkowskinorm isanaturalone,and theissueof howtocomputeit becomes important. Wewillreturntotheissueofhow tocompute the Minkowski normagainin Theorem 5.2.4.
SOBOLEV NORMS.
Wewill workwith theSobolevseminorm
]A ]t,p
givenby[A[,p-
([A,t(z,y)[+[A,2(x,y)[’)dxdy
pe[1,o)
(4.1)
ess
sup[A,i(x,y)[,ess
sup[A,2(x,y)[},
pTHEOREM
4.1.For
all p{1, ol,
I"
Ii,p
isanorm onspan(C)
equivalent toI1"
IIx,-PROOF.
This follows from the fact that an element A span(C)
necessarily vanishes on the lower and left boundariesof[0,
1] 2.
The details of theproofcanbefoundin Adams[1].
One
ofourprincipal resultsisthat the product restricted toCis continuous in eachplaceand jointlycontinuousin thetopologyof
11,,
forp[1,
oc).
Whetherornot the corresponding result holdsforp o is an openissue,andwhatcanbesaid about continuityofthe product onallof span(C)
is alsoan open issue. Another principal result is that C is aclosed subset of Wi’’forallp[1, o],
so that Cisa completemetric space with respect toeach of theSobolevnorms considered. Puttingthe principal results together, we have that C is a complete metric space under
It,p,
forp[1,
o)
and that theproductbehaves well withrespect tothe metric. The utility of the Sobolevnormsonspan(C)
is much lessclear, both because the behavior of the product is not known, as notedabove, and because, as we shall show, span(C)
is notcomplete with respect to any of the Sobolev norms. This latter result will be proved by way
ofaresult ofindependent interest theSobolev normsonspan
(C)
are dominated by, but notequivalent to,the Minkowskinorm.
LEMMA
4.1. The topologies inducedonCby thenorms[1,
coincideforallpE[1,
o).
PROOF. We
willshow that for anyp>
1, thetopology induced byIi,p
coincides with thetopologyinducedbyll,1.
Since the first partial derivatives ofacopulaliebetween0and almostsurely,Darsowet al.[2]
wehaveIB-
Cll,v
<
IB-
CI
1/’forany copulasB andC Also,I,I
by by Hhlder’s inequality,
IB
-C]t,
_< [B
-Cll,.
It
follows thata ball inC in thetopology of11,1
necessarilycontains aballinthetopologyofll,
andvice versa. |Thetopologyof
]l,o
restrictedtoCis different fromthetopology ofI,l.
Toseethis,let
Bn
denote theordinal sumnxy, 0
<_
x,y<_ l/n
Bn(x,y)
min{x,y},
otherwise(4.2)
Thenby direct calculation
2
lB.
Mll,
3-
0 whereas[B.-Mll,oo=
for alln.Roughly, the topology
of[
[1,,
for p[1,
o),
is the topology of pointwise convergence of derivatives, since pointwiseconvergenceofderivatives implies convergence in thesenseofll,,
forp E[1,
o),
by the dominated convergence theorem, and convergence inthe senseofll,
implies the existenceofasubsequencewhose first partial derivatives converge pointwisea.e. The
topology of
I,o,
onthe otherhand, isthetopology ofuniform convergenceofderivatives.For
B ECandf
ELI([0,
1])
define425 It iseasy toverify that for
f
e
L,
B;f
is Lipschitzcontinuous withLipschitz constant and thusis absolutelycontinuous.d
B’fl
<
dLEMMA
4.2. Forall B Candf
LI([0,
1]),
I-z
--dyB;lfl
a.e.PROOF.
SincezB,9(z,
t)
isalmost surely nondecreasing,Darsow
et al.[2],
zB;f
is nondecreasing wheneverf
isnonnegative. The desired result follows immediately from the fact that for anyf
L1,
Ill-
f
andIll
+
f
areboth nonnegative. |THEOREM
4.2. The product onC is continuousineach place and also jointlycontinuous in thetopology of i,p for allp[1,
o).
PROOF. By
Lemma4.1, itsuffices to considerthecasep 1. Let B,, B and C becopulas,and suppose
IB-
Bnll,1
0. Weshow first thatIC.
B-C.Bnl,l
0andIB
.C-Bn *CI1,1
0. This will prove that is continuousin eachplace.Wewillshow that
II(B
C),1
-(S,
C),1110,1
0 andII(C
B),I
(C
B,,),1]10,1
0. Theprooffor partial derivatives with respect to thesecondargument issimilar.
Given
>
0, letC([0,
1]
2)
besuch thatIIC,1
[10,1
<
e/3.
C([0, 1]
2)
is the spaceof C functionsontheunitsquare which vanishontheboundary.We
canfind sucha sinceC
is denseinL1,
e.g. Adams[1].
Then[[(B
C),1
(B,
C),1110,1
[xx
(B
B,),2(x, s)C,1
(s, t)
ds[
dt dx<
Ixx
(B
B,),2(x,
s)dp(s,
t)
ds[
dt dx+
l
,(, )(
c,)(,
)l
e e
+
Bn,2(x’s)(-C,’)(s,t)dsldtdx
+
S,(z,s)l(--C,)(s,t)ldsdtdz
+
B,,2(z,
s)J(
c,)(s,
t)J
ds dt d.Here,
weintegratedby parts in thest
terminthe second expressiononthe right, andweusedLemma
4.2 toestimatethe lasttwo terms in the expression. Since 6C,
we canperformthe integration withrespecttoz in the last two terms toobtaintheestimate+
2I(
c,)(, t)l
II,tll0,lB
Blt,t
+
/3,
Choose N solargethatn
>
N impliesThenforall such n,
426 W. F. DARSOW AND E. ]7. OLSEN To complete theproof, observethat
II(C
B),-(c
Bn),ll0,-
[zz
C,2(x,s)(B-
Bn),t(s,t)dsldtdx
<
C,2(x, s)l(B
B,,),
(s, t)]
ds dt dxNIB-
B,,l,.
Here,
we usedLemma
4.2 and performed the integration with respect to x.It
follows thatII(c
*B),
(c
B),ll0,
0.Thus, is continuous in eachplace with respect to the topology
of[
[,p
forp Observe that the argument just given shows that foranythree copulas B, C andD,
II(c
*B),- (C
D),llo,
<
Is
Dl.,.
(4.3)
Wewill make use of this observation toshow joint continuity.To
that end, let B,,B,
C, and C be copulas, and suppose thatIB
B,,l,l
0andIC
C,ll,
0. Wewant to show thatIB
,C B,,*Crl,
0. WriteB ,CBn
,C,-Bn
*(C
-C,,)
+
(B
B,)
,C.ThenII(B
*C),
(B.
C.),llo,
_<
II[B.
*(C
C.)l,llo,
+
II[(B
B.)
C],llo,
<_
IC-
C.l,
+
I1[(- B.).
Cl,llo,.
We have used
(4.3)
here. he firserm
on herih
oes
o
zero byhypothesis and he second term goes tozerobythe onesided continuity of the operation proved above. Thus,II(U
.C),l-(Bn
Cn),ll0,1
0.By
an analogous argument,II(S
C),2
(B,
Cn),2[10,
0. Thus,IB
*C B,,C,,I,
0, and joint continuityis established. |We
turnnowtocompleteness issues.THEOREM
4.3.For
all p[1,
oo]
thetopologyof[
I,p
restrictedtoC isstronger than thetopology of uniform convergence.
PROOF. For
p>
2,I1"
II,p,
and thusI"
I,p,
dominates theuniform normII0,oo,
by theSobolevembeddingtheorem, Adams
[1].
Thus,
for eachp>
2,there isaconstantCp
such thatIIAII0,oo
_<
CIAI,
(4.)
for all
A
span(C).
This implies the desired result, forp>
2. Since byLemma
4.1 the topologies of[,
restricted to Ccoincidefor p[1,
oe),
the conclusion of thetheorem holds also forpE[1, 2],
though aninequalityoftheform(4.4)
neednothold forpE[1, 2].
|Observethat the topologies of
I,p
arestrictlystrongerthan that ofII0,o,
sinceif the topologies coincided, the product would be jointly continuous in the latter topology. This is not the case, however.Thereisasharperstatementwhichimplies Theorem 4.3 and whichwewillmakeuseoflater:
THEOREM
4.4.For
all p(1,
oe)
theweaktopology of W,
restrictedtoCcoincides with the topology of uniform convergence.PROOF.
A
sequence of copulasis weakly Cauchy in thesense ofW’p if and only if it is uniformlyCauchy,
and the weak and uniform limits are thesame. This follows easily from thefact that C is a compact subset ofL and from the fact that the unit ball in L
(which
contains both first partial derivatives ofanycopula)
isweakly sequentially compact. |THEOREM
4.5.For
allp[1, oe],
Cisacompletemetricspace under the metric427
PROOF.
This isacorollary of Theorem 4.3.Suppose
B isintheclose,reof(7in W1.p,
and letU,6Cbe such that
IB-
B,ll,p
0. Wewant toshowB C.By
Theorem4.3lIB-
Bn[[0,
0 andtheuniform limit ofasequenceof copulasisacopula, so BG.
[
Weturnnow to considerationof theSobolevnorms on allofspan
THEOREM
4.6.For
p[1, 1,
the Minkowskinormdominates thenorm[. [,p
onspan(C).
PROOF.
Sinceforp G[1,
),
A,
2/]A,,
itsuces
to establishthe result forp Since thefirst partial derivatives ofa copulalie in[0,
1]
a.s., the result forp follows viaanargumentsimilar to thatofLemma 3.1.
Toinvestigate theissue of whetherspan
(6)
iscomplete underanyoftheSobolev norms,we usethefollowingeasyconsequence ofthe open mappingtheorem(Rudin
[5]):
LEMMA
4.3. Let B be a Banach space under each of two norms. If one ofthe norms dominates theother, thetwo norms areequivalent.It follows from Theorem 4.6 and Lemma 4.3 that span
()
is complete under one of theSobolev norms if and only if that norm is equivalent to
JIM.
A
counterexample given inExample .1 below shows that thenorms are not equivalent.
By
Theorem 4.6 andLemma
4.3, therefore, span()
is not complete under any of the Sobolev norms. We canalways work with the closure ofspan(C)
in W,,
ifwewish, but the subspace span()
itselfis not closed.Before leaving the Sobolev norms, wecomment on the diculty of extending Theorem4.2,
concerning continuity of the product, toallofspan
().
Sinceasnoted above thenormsJIM
and,
are not equivalent, thereexist sequencesAn
sB, t,C,which are Cauchywith respect to,
for whichs
+
t
is an unbounded sequence. This cannot be accomodated withintheframeworkof theproofwehave given of Theorem 4.2. If, therefore, the product is continuousonallof span()
inthetopoloof[
[,,
it willhave to beshownbysomemodifiedorcompletely different line ofproof.
5.
JORDAN
NORM
Wecansay less about the Jordannormthan about thenormsconsideredabove. The question
ofhow the product behaves with respect to the topology ofthe Jordan norm is open. The principalinterestofthenormis thatit sheds lighton the behaviorof the othernorms.
THEOREM
5.1. The Jordannormdominatesthe uniformnorm onspan()
andisdominatedbythe Minkowskinorm.
PROOF. Let A
span().
Write Aforthe finitesied
measureinducedbyA
on[0, 1]
,
write A for its Jordan decomposition, where
(F)
A(F
E),
and writeIAI-
+
].
Then]]m]]j
]#A[([0,112).
Observethatforany
(x,
y)
6[0,
1]
2wehaveIA(x,y)l-
IA([0,
x]
x[0,])1
<
IAl([0,
x]
X[0,1)
<
[IallJ.
Take the supremumover(x,y) e [0,
11
and conclude thatIIAII0,oo
<
IIAIId.
Next,
observe that ifA
sB tC, wheres,_>
0, B, Ce
C and[IAIIM
s-}-t,wehavela([0,
1]
2)
#A(E
+)
SlaB(E
+)
--tlac(E
+)
<_ SlaB(E
+)
<_
sla([0,
1]
2)
----laA(E-)---SlaB(E-)
+
tlac(E-)
<_
tlaB(E-)
<_
using the fact that lab andlac are probability measures and that #A SlaB
tlaC. Sum
theforegoinginequalities and conclude that
I[A[Ij
<_
s+t-[JAIl
M. |We havearepresentationofthe Minkowski normwhichmakes useofthe Jordan
428 W. Fo DARSOW AND E. T. OLSEN
THEOREM
5.2. Let A E span(C),
let #A#-
#
be the Jordan decomposition of the finite signed measure induced byA,
as above, and setA+(x,y)
([0,
x]
[0,
y]),
andA-(x,y)
#([0,
x]
[0,
y]).
ThenIIAIIM--
max{llA
+,1(’,
1)11,
IIA,2(1,
+")11}
+ max{liAr(’,
1)]],
]IA(1,.)I]}.
PROOF. A
+ andA-
are continuous monotonicfunctions satisfyingA+(x,O)
A+(O,y)
A-(x,O)
A-(O,y)
O.These facts are easy to verify. They differ from copulas in that they satisfy different boundary conditions ontheupperand right boundaries of the unit square.
If
A
sB tC where B, C EC ands,_>
0, andIIAI]M
s+
t, then forxl<
x2using the Lipschitz conditionsatisfiedby the copula B. Sincesectionsof
A
+ arenondecreasing, first partial derivatives exist almosteverywhere, and theforegoinginequalities imply0
<
A+(x,y)
<
8 a.e.(5.2a)
By
similar reasoning,0
<_
A+,2(x,y)
<_
s a.e.(5.2b)
0_<A(x,y)_<t
a.e.(5.3a)
0_<A(x,y)_<t
a.e.(5.3b)
We
usethe notation"a.e."
in thestatementsaboveasshorthandforthe more precisestatements that, forally,(5.2a)
and(5.3a)
hold for almost allx andthat, forall x,(5.25)
and(5.3b)
hold for almost ally. It followsfrom(5.2)
and(5.3)
thatIIAIIM
s+
dominatesthe right hand sideof
(5.1),
which in particular must be finite.Toobtaintheconverseinequality, wemakeuseagain of theconstructionutilizedintheproof ofTheorem 3.4. Observe that, since
A-
A
+-
A
andA
is linear on the upper and right boundariesof[0, 1]
2,
we can write1
(A-(x2, 1)
A-(xl,
1))
(A+(x2,
1)
A+(xl,
1))
A(1, 1)
x2 x x2 x
1
(A-(1,W)
A-(1,Vl))
(A+(1,W)
A+(1,Vl))
A(1,
1)
Y2 Yl Y2 Yl
sothat also
max{ess
sup{A
5
(x,
1)},
esssup{A(1,
y)}}
max{ess
sup{A,+(x,
1)},
ess sup{A,(1,
y)}}
A(1,
1).
The right hand sideofthis expressionisnecessarily nonnegative.
Let
For any
>
0, setThen and
p
arestrictly increasingfunctions,and, by reasoningsimilar tothatused in theproofof Theorem3.4,both B and C arecopulas. Since byconstruction
A
(
+
e)B
(
+e
A(1,
1))C
itfollows that
IIAIIM
_<
2+
2e-A(1,
1).
Since
>
0isarbitrarily small,weobtainfinallyIIAIIM
<
2-A(1,
1)
<max{llA
+,1(’,
1)11oo,
IIm,2(1,
+
")11oo}
+
max{
A#("
1)11
IIA
(1,
)11
}
using
(5.4)
and the definitionof.
Thus, the right handsideof(5.1)
dominatesIIAIIM.
|Wenow give twoexamples.
In
the first,weconstruct asequence of elements of span(C)
on which the normsI1"
I1’
andI1"
IIM
are the same, and both diverge to+oo,
whereas the normI1,
isbounded.In
thesecond, weconstructasequenceofelements of span(C)
forwhichthenorms
IIJ
andI1"
II0,oo
areessentially the same, and both converge tozero, whereas thenormsI"
11,oo
andI1"
IIM
diverge to+oo.
Weshall then commentontheexamples.EXAMPLE
5.1.Let
n be aneveninteger. Partition[0,
1]
2 into n2 disjoint squares ofsidel/n:
letxk Ykk/n,
k 0,...,nandwritel<_j,k<n j=n, l<_k<n k--n,l<_j<n j--k--n
Definea finite signed measure #r on
[0,
1]
2 via theconditions that#,.,(Rjk)
(-1):+k/n
andthatthemassof#, bespreaduniformlyoneachRjk. Thatis, definett,via
#n(F n
Rj,)
(-1)J+}A(F
n
R3k)
n(_l)+kA(
F
NRjk)
,(R)
foranymeasurable setF,whereA denotes Lebesguemeasure on
[0, 1] 2.
TheJordan decomposition oftt, isasfollows"Set
E + Uj+kevenRjk E-
U3+koddR3k.
Then
#+(F)
#,(F
VE+)
and#-(F)
-tt,(F n
E-).
Observethat
nx
,
([0,
x]
x[0,
11)---
(5.6)
ny
t+(l
0’
11
[0,
-430 W.F. DARSOW AND E. T. OLSEN so that
B+
definedbyB+(,
)
2-.
n +(10,
l
10, 1)
is acopula. Equations
(5.6)
and(5.7)
aresatisfied with#
inplaceof#n, so+ thatB(x,y)-
-2([O,
xl
[0,
yl)
n isa copula. IfwedefineA,via
A,(x,y)
-/n([0,]
[0,
y])
wehave
n + n
An
B
-B-
e
span(C).
Itiseasy toseethat
I/Znl-
hA,sothatIIA,IIj
n. Usingformula(5.1),
togetherwith(5.5)
and
(5.6)
andtheanalogous formulaefor/,
weobtainalsoIIAnlIM
n. Wewishto computeIA,ll,o.
For(x,
y)
R3k
wecalculate, using(5.5)
-
(-1)
e+’+
(x
a:_l)
(-1)
+’
=1rn=l rn=l
3--1
+
(y
yk_)
(-1)
t+3+
n(x
xj_)(y
yk_:t)(-1)
a+k =1It
follows thatfor(x, y)
in the interiorofRk
wehavek--1
[A,l(x,y)[--[
-(-1)
j+m+
n(y-
yk_l)(-1)+[
<
2since
[y
yk_l[
< 1/n
andk--1
(-1)J+’n=-1,
0or1.rn--1
Similarly,
[An,2(,
y)[
_<
2 forall(x,
y)
interiortooneoftheRjk’s. It
followsthatIAI,
<
2. Thus,asnvaries overtheevenpositive integers,weobtainasequenceofelements in span(C)
whose Minkowski and Jordannorms areequal, and diverge to
+x,
but whoseW1,o norms areuniformlybounded above by 2.
EXAMPLE
5.2.Let
Bn
be the ordinal sumof(4.2)
above,
and defineAn
snM
tnBn
whereSn
tn
na,
forsome positive numbera. Thus,x
>_
lln
ory>_
lln
O<_x<_y<_l/n
Observe that
An
span(C)
for alln. WecalculateIIAllo,
IAl,oo,
IIAIIJ
andIIAIIM-An
easycalculation shows thatIt
is easy toverify that the maximum valueof[A(x,y)l
occursat(x,y)
(1/2n, 1/2n),
sothatIlAllo,
-/4.
(5.10)
431 L,
{(x,x)10
<
x< l/n};
and writeA2
for Lebesgue measure on[0,
1]
2 Then it is easy to verify that the Jordan decomposition of,
#A,. isgivenby+(F)-nAI(FML,)
#(F)
na+lA2
(F n
[0,
l/hi2).
It
followsthatIt
follows also thatIIA,IIJ-
I#,l(I0,
112)
2n’:’-’.
(5.11)
n+([0,
x]
x[0,
1])=
{
n
-l,nax’
otherwiseX
e I0, /n]
eI0,/n]
n+([0,1]
x[0, y])=
na_
otheise
Identical formulaeareobtainedfor $.
It follows,
using(5.1),
thatIIAnIIM
2na.
(5.12)
Nowfixa
e
(0, 1).
Observethatby(5.10)
and(5.11), IIAll0,
andIIAnlIJ,
whichdifferbya constant factorof8,both converge to0,whereas by(5.9)
and(5.12),
IAnlt,
andIIAnIIM,
which differbyaconstantfactorof 2, both diverge to+.
We
turn to theinterpretation ofthese twoexamples. Since the Minkowskinormdominates the Jordannorm, byTheorem5.1, and the twonormscannot be equivalent, by Example5.2, we obtain, by wayofLemma
4.3:THEOREM
5.3.Span
(C)
isnotcompleteunderthe Jordannorm.Obseethat Example5.1 completestheargument ofSection4 to similareffect: span
()
isnotaclosed subspace of W
,
for anyp[1, ].
Finally, obsee that in viewof Example5.2itcannot be true that
II"
Ila
dminatesI"
I,
and that in viewof Example5.1 it cannotbetruethatI"
It,
dominatesIIg.
6.
ONE
PARAMETER
SEMIGROUPS OF COPULAS
We
sayCt,
O,
isa oneparametersemigroupifCn+t
Cs
Ct
forall s,t.Obsee that
Ct
*Co
Co
*Ct
Ct;
setting 0 we observe thatC0
is necessarilyidempotent.
Thus,
ifCt
is asemigroup,C0
is anidempotentwhichcommuteswithCt
for
allt.If
forsome normlimt0
IIct
c011
0 andthe productis continuous in eachplaceinthe topolo ofthenorm,thenlim
IICt
Co
limIICt-to
Cto
Cto
IIC0
Co
co
0.o
Thatis, continuityat 0 implies fight continuityeye,where.
In
fact,
theexistenceofaright limit at 0implies right continuityeverywhereon(0,
),
for reasonablenorms:THEOREM
6.1.Suppose
isanormon aspace containing span(C),
and suppose that the product ong is continuous in eachplacein thetopolo ofthe norm and also that norm convergence implies pointwise convergence. LetC
be asemigroup ofcopulas, and suppose there isafunctionE
such thatlim0
IIc
Ell
0. ThenE
isidempotent,E
C
C
E
C
forall
>
0andlim
IIc
coll
0for ll 0>
0,PROOF.
Theproof
isanadaptationofaclassicalproof
tothecaseof copulas.432 W. F. DARSOW AND E. T. OLSEN
Since for
> to
> O,Ct
Cto
*Ct-to
Ct-to
Cto,
onesidedcontinuity of implies limIIC,
c,0
’11
0tl,to
lira
]]Ct-
ECt0][
O.Thus, rightlimits exist everywhere, andalso
limtl.to
Ct
Cto
*E ECto
for allto
> O.Itremains toshow that
Cto
Cto
*EE,Cto.
Itsufficestoshow thatCt
isrightcontinuous at asequenceofpointstn
converging toO,
since ifCt,.,
Ct,,
*E ECt,,
and> tn
thenCt
Ct-t,,
*Ct,,
Ct-t,,
*Ct,
*ECt
*E.Fix
(x,
y)
E[0, 1]
2,
and definef: [0, cz)
[0, 1]
viaf(t)
C,(x,
y).
Observethatsince norm convergenceimplies pointwise convergence, right limitslimttt0
.f(t)
exist everywhere. It follows by a classical argument(an
outline of the argument is given by Hille and Phillips[4,p.
282])
that the set
7)(x,
y)
ofdiscontinuities off
is countable. Now let(x,y)
vary over the rational pairs(p,
q)
E[0, 1}
2,
andset 7)UT)(p, q).
Then 7)is countable. Since copulasare all Lipsehitz continuouswith Lipsehitz constant 1, Darsow etal.[2],
hence equieontinuous, itfollowsthatlim
Ct
Cto
tto
pointwise for all
to
t
7). Since(0,
cz)
\
7) includes a sequence converging to 0, we have right continuity everywhere.That E is idempotent now follows easily from thefacts that E
Ct
Ct
*E
Ct
for all>
0, thatlimtt0
Ct
E and that the productiscontinuous ineach place. |Note
that Theorem6.1 requires only that the productbe continuous in eachplaceand that it isthe productrestrictedtoC,
ratherthanonallofspan(C),
forwhichcontinuityisrequired.Accordingly,we cantake any of
I1"
I[0,oo,
I"
It,v,
Pe [1,
cx)
or]].
]]M
forthenorminTheorem6.1,sincethe product is continuousin eachplace with respectto eachof these norms, and sincefor
eachnormconvergence implies pointwise convergence. The theoremthen states that asemigroup
Ct
for whicharight normlimit exists at 0is necessarily right continuouseverywhere in the senseofthenormtopology. Wedo not know whetherwe cantakeIla
or{.
11,oo
forthenorm in Theorem 6.1, since we do not know whether the product, restricted to C is continuous in eachplacein thetopologyof thesenorms.Note
alsothat,ifwe arewilling toassumethatlimt/0 Ct
exists,there is nolossofgenerality in making the stronger assumption thatCt
is right continuous at 0, sinceby Theorem 6.1, wecanalways redefineCo
to bethe limitE
limq0
Ct
and still haveasemigroup.We
address next the issueofwhether measurability implies continuity fora one parametersemigroup of copulas. There is a classical argument that this is the ease for one parameter
semigroups inaBanaeh algebra, Hille etal.
[4,
p.280].
In
the following discussion, measurability ofa function RB
where /3 is a Banaeh spacemeans"strong"
measurability, that is,f
ismeasurable ifforany compactsubset K C R,flK
is the limit pointwise almost everywhereofasequence of measurable functions with finite range.A
functionwithfinite range ismeasurable if the inverse imageofeach point in the range ismeasurable.We
will makeusebelowofthefollowing facts:1.
Strong
measurability implies "weak" measurability; a functionf
R /3 is weaklymeasurable if
u(f(t))
is ameasurablescalar valued functionforeach u/3*.2.
Strong
and weak measurabilityareequivalent when the Banachspace/3isseparable, Hille et al.[4,
p.73].
In
this connection, recall that the spaces W",v areseparable for pe [1, ),
433 3. (Approximation by continuous
functions:)
LetP(i)
denote the space of integrableB-valued functions with domain f C R; the set ofcontinuous Banach space valued functions is densein
P()
for allp6[1,
cx),
Hille et al.[4,
p.86].
Observe that if
f
R Bisright continuous, thenit is measurable. Toseethis, let/):a--t0
<
tl<
< tn--b
denoteapartition ofaclosedboundedinterval[a,
b]
anddefinef’P
viat=b
where
I[tk_,,t)
denotes thecharacteristicfunctionof the interval[tk-1, tk).
Then foranysequence of partitions forwhich themaximum subintervalwidth[P[
goes tozero,liml,l_.,0
lift
f[[
0forallt. Accordingly, ifwemake the assumption that asemigroup
Ct
isright continuous at 0 in the senseofsomenorm, then byTheorem6.1 and the preceding observation,Ct
is measurable in thesenseofthat samenorm.The classical argument that measurability implies continuity uses the Banach algebra in-equality. Theproofof the following theorem follows theclassical proofbut replacesthe Banach algebra inequality by amore restrictivecondition.
THEOREM
6.2.Suppose
Ct
is a one parameter semigroup ofcopulas.Suppose
also thatCt
is measurable in thesenseofanormsatisfying the followingconditions:(1)
Thereis anumberM1
such that[[Ct[[
< M1
for all t, and(2)
There is anumberM2
suchthat forany s, t, andullc
*cu
ct
c,,ll _<
M21lCs
ctll.
(6.1)
ThenCt
is continuous on(0,
x).
PROOF. Let
>
0;wewant to show that[ICt+,-Ctl]
0as/--,0. Let0<
a<
b<
andlet
I1
<
t-b. Thenforalls 6[a, b]
wehavec+,
c
(c+,_,
c._,)
c,
c,
(c+,_,
c._,).
The last term in thisexpressionis constant,hence bounded and integrable, andwehave
(6.3)
Condition
(1)
guarantees that the integrandofthe last integral above is bounded.By
a result mentioned above, togetherwithsome standardarguments, wecanfind a sequenceofuniformly bounded continuousfunctionsg
converging pointwisetothebounded measurable functionC almost everywhereonthe compact interval
[0, t],
that is, for almost all s,lies
g[I
0 as n cx. With C replaced byg’
the integral in the last term in(6.3)
goes to zeroas r/ 0.It
follows,
viathe triangle inequality and the dominated convergencetheorem, that434 W.F. DARSOW AND E. T. OLSEN
Wewillshow below that theSobolevnorm
[.
[1,
satisfies conditions(1)
and(2)
of Theorem6.2,and that as aresult measurability ofasemigroup
Ct
of copulas in thesenseof W1,P,
for p E[1,
x)),
impliescontinuityofthe semigroup in thesenseofW1,p,
p E[1,
o).
Weareunableto show thatcondition(2)
is satisfiedby the uniformnorm[[.
[[0,.
Itisanopen question whetherasemigroup whichis measurablein thesenseof the uniform normisnecessarily continuous. Weestablish the inequality
(6.1)
forp l, withM2
2. Observe first thatby
(4.3).
It follows thatI(C.
c)
Cl,,,
II((C
c)
c.),llo,
/II((c.
c)
This yields
(6.1)
in the case of],.
Observe that since[0,
]2
is compact, for p>
1, the W1,P([0,
1]
2)
normdominatesthe W’([0,
1]
2)
norm,someasurability in the sense of W1,pimplies measurability in the sense of Wt,t.
Accordingly, ifCt
is measurable in the senseofW’,
it ismeasurable also in thesenseof W,1,
whence, by Theorem6.2, it iscontinuous in thesense ofW’.
Since the topologies of Wl’p restricted to C coincide forp[1, x),
Lemma 4.1, weconclude that
C
is continuous in thesenseofW1,for allp[1, x).
Thus, a one parameter semigroup ofcopulas whichis measurable in thesense
of[
[,
is necessarilycontinuousin thesenseof],p,
forp[1,
x).
COROLLARY
6.1.A
semigroupCt
ofcopulaswhichis rightcontinuousat 0 in the uniformnormis continuousfor all(0, x)
in thenormI"
It,p
forallpE[1,
PROOF. Let
C
satisfylimt/0
IIc-
c0110,o
0, Then by Theorem6.1,Ct
is fight continuous everywherein the senseof the uniform norm. If is a continuous linear functional onW’([0,112),
p 5(1,
x),
(Ct)is
a right continuous real valued function, by Theorem4.4, hence measurable, by an observation above. Thus,
Ct
is weakly measurable in the senseof W’’.
Butweakand strong measurability areequivalent for theseparablespaces W’P,
1
_<
p<
oo, so,by Theorem6.2,
Ct
is continuousin thesenseof]
I,
forall>
0. |One
mightreasonablyexpect that fight continuity in thesenseoftheuniformnorm would imply measurability in thesense evenofthe Minkowski normIIM,
since on heuristicgrounds one expects reasonable functions to be measurable. Then right continuity at 0 in the uniformnormwould imply continuityforall
>
0 in thesenseofIIM,
directlybythe classical Banach algebra argument, without worrying about how to obtain(6.1)
in the caseof Sobolev norms. It is an openissuewhetherthis isthecase. Hille andPhillipsraisethesameissuein the related context of transition matricesofMarkov processes with discrete(but
notfinite)
range,[4,
p.635].
We
point out that measurability ofa Banach space valued functiondepends onthe normused,sothat thecopulavaluedfunctionsCt
hereofinterestmay be measurableornot, dependingonwhat Banach spacewetakeCto beasubset of.We
nowturn to the issue of analyticityofasemigroupCt.
THEOREM
6.3.Let
C
beasemigroup inC,
and supposethatlimit0
[IC
E[[M
0, whereE
Co.
Then thereis anA
E span(C),
satisfyingA
E
EA
A,
such thatC
eAtforall
>
0, whereeAt is definedby its seriesrepresentation, withtheconventionA
E.This is aclassicalresultforBanachalgebras;for aproof,seeHilleet al.
[4].
435 It follows from Theorem 6.3 andsomeother elementary arguments that a semigroup
Ct
of copulas possesses an exponential representationCt
eAt for some A E span(C)
if and only iflimt0
IICt-
EIIM
O,
where ECo.
This says roughly that the Minkowski norm isa naturalonefor oneparametersemigroups withgeneratorsinspan
(C).
It is by no means true that all one parameter semigroups of copulas possess exponential representations. Wenext exhibit aone parameter semigroup
C
which is right continuousat 0 in thesenseofII,p
forpE[1,
cx))
but not inthesenseofII,o
and hence, by Theorem4.6,also not in thesense of
IIM.
By
Corollary 6.2, therefore, the semigroup does not possess an exponential representation.EXAMPLE
6.1.It
wasshown inDarsowetal.[2]
that thecopulas ofaWienerprocess have theformwheres
<
andv
sSince the Wiener process is aMarkov process,wehave, fors
<
u<
t,C,;
C;t
C,;t.
(6.5)
Equation
(6.4)
implies thefollowingscalingproperty: ifr>
0 ands<
thenC,Ir;tlr
Cs;t-
(6.6)
Itfollows from
(6.5)
and(6.6)
that the familyof copulasBt
definedby(6.7)
where
Cs;t
is given by(6.4),
has the semigroup property for>
0, as is readily verified.(We
remark thatit is also possible to go backwards: if
B
isanyoneparametersemigroupof copulasandwe define
C’;
Bin
t
fors<
t, then the familyC;
satisfies the Markov condition(6.5)
and also the scalingproperty
(6.6)
ofaWienerprocess.)
Wewillshow that
limt0
list
MI],p
0forp(5[1,
cx))
but not forp Fromthedefinition,wehaveBt(x
y)
CeU2G-i(y)
C-(u).
du.x/et_l
It
follows,
aftermaking asubstitution in theintegral, thatSince
wehave
/_
et/2y
u _ua/2B,(C(x),
C(y))
G(
v/e
1)e
du.et/2y-
uf
vf,
y>
ulimC
()
tO y/et-
O,
y<
uJim
Bt(G(x)
G(y))
X(_oo,u](u)e
-’/2du LO/min{x,y}
e-u2/2du436 W. F. DARSOW AND E. T. OLSEN
||ence,
lim0
Bt
M pointwise, and sinceCiscompact in theuniform topology, also uniformly.By
similar arguments,limtl0
Bt,l
M,1 pointwisea.e. andlimt0
Bt,2M,2
pointwisea.e. From the foregoing results and thedominated convergencetheorem, weobtainlim
11Bt
M[[1,p
0t0
forp E
[1,
x).
The result does not hold forp oc, however; the partialderivativesBt,
andBt,2
arecontinuousforall
>
0,butM,1
andM,2
arenotcontinuousfunctions,hence not the uniform limitofcontinuous functions.That
Bt
possessesnoexponential representationnowfollowsfromanobservationmade above(see
discussionfollowing Theorem6.3).
Observethat ifBt
possessedanexponential representationBt
eAt then it would be true thatlimt.odBt/dt
A. It can be verified directly that the semigroupB
ofthis example does not possess an exponential representation, since the latter limit is0 except whenx y, when it isinfinite.7.
DISCUSSION.
We
conclude with some remarks about compactness. Recall that C is a compact subset of W’
and alsothat the product fails to be jointly continuous in the topology of uniform convergence. The question iswhetherC itselforany useful subset is compact underany ofthe othernormsaddressed. It iseasy toverify that if isanynormwhich dominatesthe uniform norm, and is compact under thetopology ofII,
then necessarily the product onC is not jointly continuous in thetopology ofI[.
This implies thatC is not acompact subset of WI’p forp E[1,
oo),
sincethe product isjointlycontinuous onCwith respect to thenorms ofthese Sobolev spaces, Theorem 4.2. Moregenerally, this seems toimply that we cannot obtainbothcompactness ofC and joint continuity of the product in asingle topology. We thought atone time that it might be possible to find a topology under which the group
G
C C of invertible copulas was acompact group. Butthis seemsunlikely, for thefollowing reasons:7
isdense inC inthe uniform topology, Darsowetah[2],
and thusis dense in the topology of anynormwhich is dominated by the uniform norm.Compactness
fails because7
is not closed.On
the otherhand, if dominatesthe uniformnorm,and
C,
is asequence of invertiblecopulas converging uniformly toanoninvertiblecopula, sayP,
thenif$ werecompactin thetopologyofII,
there would beasubsequence converging toanelementof7,
contradiction, sincethen thesubsequencewould necessarily also convergeuniformly to theelementof
G.
A
normwithrespect to whichG
wascompactcould accordingly neither dominatenorbe dominatedbythe uniformnorm.
We
consider itunlikely thatany normsin which the product behaves well will befoundto possess any usefulcompactnessproperties.REFERENCES
[1] R.A.
Adams, SobolevSpaces
(Academic
Press,
New York,1975}
[2]
W.F.
Darsow,
B.
Nguyen
andE.T. Olsen,
"CopulasandMarkovProcesses,"
Ill.J.Math. 36:600-642
(1992)
[3]
P.R.
Halmos,Measure
Theory(Van
Nostrand,Princeton,1950)
[4]
E. Hille andR.S.
Phillips, FunctionalAnalysis and Semi-groups(American
Mathematical Society,New York,1957)
[5]
W.Rudin, Functional Analysis(McGraw-Hill,
New
York,1973)
[6]
A. Sklar,
"Fonctionsde r6partition ndimensions et leurmarges,"
Publ.Inst.
Statist. Univ. Paris8:229-231(1959)
[7]
A. Sklar,
"RandomVariables,Joint Distribution Functions and Copulas,"