Solar radiation
(Sun Earth-Relationships)
Radiation and Climate Change FS 2012 Martin Wild
The Sun
Radiation and Climate Change FS 2012 Martin Wild
Solar Factoids (I)
• The sun, a medium-size star in the milky way galaxy, consisting of about 300 billion stars.
• A gaseous sphere of radius about 695‘500 km (about 109 times of Earth radius) => by far the largest object in the solar system
• Mass: 1.989 * 1030kg (99.8% of total mass of solar system)
Our Sun
The Sun
Radiation and Climate Change FS 2012 Martin Wild
Solar Factoids (II)
• Sun consists of 3 parts of hydrogen, one part of helium. Proportion changes over time.
• Sun‘s energy output is produced in the core of the sun by nuclear reactions (fusion of four hydrogen (H) atoms into one helium (He) atom).
• Sun is about 4.5 billion years old. Since its birth it has used up about half of the hydrogen in its core.
• Sufficient fuel remains for the Sun to continue radiating "peacefully" for another 5 billion years (although its luminosity will approximately double over that period), but eventually it will run out of hydrogen fuel.
The Sun
Radiation and Climate Change FS 2012 Martin Wild
Solar Factoids (III)
• The Sun's energy output is 3.84 * 1017Gigawatts: (a typical nuclear power plant produces 1 Gigawatt)
• The outer 500 km of the sun (“photosphere“) emits most of radiation received on Earth
• Radiation emitted by the photosphere closely approximates that of a blackbody of 5777K
Radiation and Climate Change FS 2012 Martin Wild
The Sun Emission of Sun
Effective surface temperature of the sun: 5778 K
=> Emission Bs (per m2) at the sun surface (Stefan-Boltzman law):
B
s= ! T
4=5.67 10
-8Wm
-2K
-4*(5778K)
4= 6.32*10
7Wm
-2=> Total emission of Sun ETOT:
E
TOT=4 " r
s2B
swith r
s=6.955 *10
8m= radius of the sun:
4 * 3.14* (6.955 *108m)2*6.32 107 Wm-2 =3.84 1026W= 3.84 1017GigaW
cf. World‘s energy cosumption: 15 TerraW (1.5 1013 W)
Area on Sun surface required to cover world‘s energy cosumption: 1.5 1013 W / Bs = 1.5 1013 W / 6.3 107 Wm-2=2.5 105m2=0.25 km2.
=>if we could harvest energy directly on the sun surface, 0.25 km2 would be sufficient to cover world‘s energy demands.
Radiation and Climate Change FS 2012 Martin Wild
Binding energy per nucleon in He core: 1.1*10-12 J
! Energy generated by one fusion reaction combining 4 H nuclei into one He core: 4 *1.1 10-12 J= 4.4 10-12J
Total energy per second emitted by sun: ETOT=3.84*1026W (Js-1)
! Number of fusion reactions per second = ETOT/ energy generated per fusion reaction= 3.84 1026Js-1/ 4.4 10-12 J = 0.9*1038s-1
1 proton mass= 1.67*10-27kg
=> per fusion reaction 4*1.67*10-27 kg of H is consumed.
Total amount of H consumed in the Sun per second:
= number of fusion reactions * amount of H consumed per reaction = 0.9*1038s-1*4*1.67e-27 kg= 6 *1011kg= 600 Mio Tons
=> Every second 600 Mio Tons of H are transformed to He
Radiation and Climate Change FS 2012 Martin Wild
Solar fusion
Total emission ETOT of Sun:
E
TOT =4 " r
s2* B
s! Total Emission of Sun (in W) distributed over a sphere (in m2) with radius a, where a= Earth-Sun Distance (semi major axis of Earth’s orbit, 149.6 * 109m), determines the Solar irradiance S per m2 at the Top of the Earth’s atmosphere (Solar Constant) at distance a :
Radiation and Climate Change FS 2012 Martin Wild
a S=1366Wm-2
Solar radiation
rs
S = 4 " r
s2B
s/ (4 " a
2) = (r
s/a)
2B
s=(6.955*10
8m / 149.6*10
9m)
2*6.32*10
7Wm
-2= 1366 Wm
-2Current best estimate from measurements: 1361 Wm-2
5 Wm-2 deviation may to difference from ideal black body and measurement uncertainties
More generally, if a planet is at distance rp from the sun, then the solar irradiance Sp (in Wm-2) onto the planet is:
Intensity of solar irradiance decreases with distance according to Inverse square law.
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Examples:
rs =6.955 *108m Bs=6.32*107 Wm-2
=>c=3.057* 1025W
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Planet Distance from Sun (109 m)
Intensity of solar radiation (Wm-2)
Venus 108 2620
Earth 149.6 1366
Mars 228 558
Sun Earth relationships
Earth‘s orbit around the Sun:
Earth's orbit is an ellipse and the sun is located in one of its focal points. Definition Ellipse: The sum of the distances from any point on the ellipse to the two focal points is constant (equal 2 x semi major axis a)
=> Sun Earth-distance r varies during the course of the year
Radiation and Climate Change FS 2012 Martin Wild semi major axis
Definitions:
Perihelion P: point on the orbit which is closest to the Sun Aphelion A: point on the orbit which is farthest from the Sun Eccentricity e: Amount by which orbit deviates from a perfect circle, where 0 is perfectly circular, and 1.0 is a parabola. Ratio of the distance between the foci of the ellipse to the length of the major axis of the ellipse.
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Definitions:
Solar constant S (1361 Wm-2): Solar irradiance obtained per m2 on a plane perpendicular to the sunbeam at distance a (semi major axis) from the Sun.
Distance a (semi major axis) sometimes also called 1 Astronomical Unit (AU)
# 150 Mio km
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
a
semi major axis
S
Earth-Sun distance varies over the course of a year:
! Insolation Sr at distance r:
a: semi major Axis:
r is a function of time of the year: r(t)
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
a
S
rS
Special cases:
Earth in Aphel: r=a+ae=a(1+e)
=>
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Earth in Perihel: r=a-ae=a(1-e)
Current e=0.0167:
7% difference in insolation between Perihel and Aphel
max. e in Earth history: 0.06:
27% difference in insolation between Perihel and Aphel
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
!
S
r( perihel)
S
r(aphel) =
(1 + e)
2(1 " e)
2=
(1 + 0.0167)
2(1 " 0.0167)
2= 1.07
!
Sr( perihel) Sr(aphel) =
S (1 " e)2
S (1 + e)2
= S
(1 " e)2 (1 + e)2
S =
(1 + e)2 (1 " e)2
Insolation G(r) received per m2 on average on the Earth sphere
Total energy taken out of solar flux by Earth disk: S R2*"
Total solar energy per m2 distributed over Earth sphere S R2*" / (4 R2*") = S/4= 340 Wm-2Radiation and Climate Change FS 2012 Martin Wild
Solar radiation Solar radiation
Radiation and Climate Change FS 2012 Martin Wild
Mean insolation on Earth GP over an entire orbital period P (annual mean insolation)
Integrating:
yields:
where e is the eccentricity of the elliptic orbit of Earth around the sun
!
G
P= S
4P
a
r(t)
"
# $ %
&
'
2
dt
0 P
( = S
4 1 ) e
2Solar radiation
Radiation and Climate Change FS 2012 Martin Wild
Current conditions: e=0.0167:
=>e effect:0.00014*340Wm-2=0. 033 Wm-2
Maximum eccentricity over past Million years: e=0.06:
=>e effect:0.0018*340Wm-2=0. 61 Wm-2
! term negligible for annual mean calculations
=> GP=S/4= 340Wm-2 annual mean insolation
Total solar energy received on earth:
4"r
2G
p=4"(6.37 10
6m)
2340*Wm
-2=1.74 10
17W (174 PetaW)
(174,000,000,000,000,000 J per second from the sun)
Compare: 1 average swiss nuclear power plant generates power on the order of 1 GigaW=109 W
! Solar energy incident on Earth compares to about 1.7 x 108 nuclear power plants (170 Mio. nuclear power plants)
Compare: World‘s current energy consumption: 15 TeraW (1.5$1013 W)
! 10’000 times smaller than solar energy incident on the planet
! solar energy received within less than one hour would be sufficient to cover one year of World‘s current energy consumption
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Desertec: Solar Power from the Desert
www.desertec.org
Within 6h deserts receive more energy from the sun than humankind consumes within a year
Radiation and Climate Change FS 2012 Martin Wild
Solar radiation
Radiation and Climate Change FS 2012 Martin Wild
Planetary albedo A:
Fraction of reflected solar radiation with respect to incoming solar radiation
Mean annual energy GA absorbed by the planet per m2 on the sphere:
A = 0.3 for Earth
Radiation and Climate Change FS 2012 Martin Wild
In equilibrium, absorbed shortwave energy GA (over the Earth disk) is balanced by longwave emission (over the Earth sphere) according to the Stefan-Boltzman law with an effective temperature Teff:
Effective Temperature Effective Temperature
Radiation and Climate Change FS 2012 Martin Wild
Effective temperature: (blackbody) temperature at which the emitted longwave equals the absorbed shortwave radiation.
• If the temperature of a planet is below the effective temperature it will emit less radiation than it absorbs => planet will warm until it reaches radiative equilibrium and effective temperature.
• if its temperature is above the effective temperature it will cool toward radiative equilibrium by emitting more radiation than it absorbs.
planet distance from sun (109m)
albedo (1-albedo) Teff (K)
Mercury 58 0.06 0.94 442
Venus 108 0.78 0.22 227
Earth 150 0.30 0.70 255
Mars 228 0.17 0.83 216
Jupiter 778 0.45 0.55 105
Effective Temperature of Planets
Radiation and Climate Change FS 2012 Martin Wild
Temperature (K)
Distance from sun
Exercices
Radiation and Climate Change FS 2012 Martin Wild
Daily course of sun
Surface insolation I (irradiance) at a specific location and time:
% solar zenith angle at that position and time
Solar Zenith angle % function of:
• Time of the day, expressed in hour angle H
• Latitude &
• Calender day (season), expressed as declination '
r function of time on Earth orbit.
Radiation and Climate Change FS 2012 Martin Wild
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Earth centered Cartesian coordinate system (x; y; z)
z-axis points to the North pole
x-axis in the equatorial plane with sun in the x-z-plane
points to local zenith at P points to the Sun
% is zenith angle at observer point P
Determination of zenith angle !
!
n !
!
s !
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Declination ": angle between the direction to the sun and to equatorial plane
Determination of zenith angle !
Declination varies over the year from +23°27’ (21. June) to -23°27’ (21. Dec)
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Hour Angle H:
Angle in the equatorial plane between the meridian of the observer P and the direction to the sun projected onto the equatorial plane.
Hour angle in radiance 0: solar noon
Determination of zenith angle !
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenith angle !
Local Zenith angle: Zenith angle at point P: Angle between local zenith and the direction to the sun
!
n !
!
s !
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenit angle !
Unit vector
1
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenit angle !
Unit vector
sin '
1
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenit angle !
Unit vector
1
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenit angle !
1
cos"cosH
H
Unit vector
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
Determination of zenit angle !
Unit vector
"#
sin"#
1
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
direction to the local zenith: direction to the sun at the location of an observer
With the scalar product we obtain the zenith angle % :
Fundamental equation for zenith angle %
The astronomical sunrise and sunset, +-H
0, are given for
the mathematical horizon at %="/2
where H
0is defined only for -1 ( cosH
0( 1. For cos H
0>
1, we have the polar night with no sunrise and for cosH
0<-1 we have the polar day with no sunset.
Daily course of sun
Radiation and Climate Change FS 2012 Martin Wild
!
cos" = cos H cos# cos$ + sin # sin $
with " = %
2 when H = H
00 = cos H
0cos # cos$ + sin # sin$
cos H
0= & sin # sin$
cos # cos$ = & tan # tan$
Daily insolation Id at a given location and date is obtained by integrating
for the hour angle from sunrise at -t0 to sunset at t0. Declination is kept constant during one day. Horizon at a zenith angle of 90°, => integral is evaluated from sunrise at –t0 to sunset at t0, with
where the hour angle H0 is measured in radian,
The integral can be evaluated analytically.
Daily insolation
Radiation and Climate Change FS 2012 Martin Wild
The integral can be evaluated analytically,
where H0 is the hour angle for sunrise at the mathematical horizon.
Radiation and Climate Change FS 2012 Martin Wild
Daily insolation
Radiation and Climate Change FS 2012 Martin Wild
!
cos"
# Ho Ho
$
dH =(cos H cos % cos& + sin % sin&)dH =
# Ho Ho
$
= sin H cos % cos& + sin % sin& ' H ]
# HH00= sin H
0cos % cos& + sin % sin& ' H
0# (sin(#H
0)cos % cos& + sin % sin& ' (#H
0))
= sin H
0cos % cos& + sin % sin& ' H
0# (#sin(H
0)cos % cos& # sin % sin & ' H
0)
= 2(sin H
0cos % cos& + sin % sin& ' H
0)
( I
d= S 86400
2)
a r
*
+ , -
. /
2
cos"
# Ho Ho
$
dH= 2S 86400
2)
a r
*
+ , -
. /
2
(sin H
0cos % cos& + sin % sin& ' H
0)
Daily insolation
Radiation and Climate Change FS 2012 Martin Wild