SPLITTABILITY AND LOW SEPARATION AXIOMS
A.J. Hanna and T.B.M. McMaster
(Received August 2003)
Abstract. The power and usefulness of cleavability (also known as splittabil- ity) have been well established within the framework of topology by A.V.
Arhangel’skii and his associates. The concept was transferred to partially or- dered sets by D.J. Marron and T.B.M. McMaster. The connections between topology and order are here exploited as we examine the properties enjoyed by a topological space that is splittable over a collection of topological spaces each enjoying a low separation axiom.
1. Introduction
Given the close links between topology and order it is hardly surprising that the definition and basic results of splittability (for example, see [2, 3, 4]) transfer naturally from topological spaces to partially ordered sets [7, 8, 9, 10]. This article examines a selection of separation axioms weaker than T
1with respect to their splittability behaviour. The interested reader is referred to [6, 11, 12, 13, 14]
for more details on specific properties. In each case we determine, using a variety of techniques, whether the invariant is a splittability class or not: that is, we test whether splittability over a class of P spaces implies membership of P.
In some cases the ‘full force’ of splittability is not required in order to establish such a conclusion. For example, we sometimes find that pointwise splittability over a class of P spaces suffices to imply membership of P. For other invariants we find it necessary to strengthen the type of splittability used. Failing this, we need to insist on some further condition on the ‘split’ space coupled with the splitting property.
2. Preliminary Material
Definition 2.1. A topological space X is splittable [2] over a class P of topological spaces if for every subset A of X there exists a continuous map f : X → Y ∈ P such that f (A) ∩ f (X \ A) = ∅. We use the terms closed (open, onto) splittable to mean that the splitting maps may be chosen to be closed (open, onto). The space X is said to be pointwise splittable over P if splitting maps can be found at least for every singleton subset of X. When working with posets we need only replace the term ‘continuous map’ by that of ‘increasing map’ i.e. a map f for which x ≤ y in X implies f (x) ≤ f (y). A class of spaces P is said to be a splittability class if X splittable over P implies X ∈ P. It is easy to see that splittability classes must be expansive and hereditary.
1991 Mathematics Subject Classification Primary 06A06, 54C99.
Key words and phrases: splittable, submaximal, partially ordered set, low separation.
Definition 2.2. Let f : X → Y be a mapping between posets. We use the notations L(x) = {y ∈ X : y ≤ x} and M (x) = {y ∈ X : x ≤ y} and we say [8]
that:
(1) f is an L
Pmap if f (L(x)) = L(f (x)) for all x ∈ X, (2) f is an M
Pmap if f M (x) = M f (x) for all x ∈ X.
It is easily shown that L
Pmaps and M
Pmaps are increasing.
It is well known that a T
0topological space X generates a poset under the rela- tionship x ≤ y ⇐⇒ x ∈ {y}. Several topologies may be defined on a given poset that generate its order in this fashion. However, there is a weakest such topology:
Definition 2.3. Given a poset (X, ≤), the weak topology is the topology on X whose non-empty proper closed subsets are generated by the family {L(x) : x ∈ X}.
Thus we can consider the two point Sierpi´ nski space (denoted by C
2) as the poset on {1, 2} (with natural order) endowed with the weak topology. Likewise we denote by C
nthe topological space obtained by imposing the weak topology on the set {1, 2, . . . , n} with its usual ordering. Throughout this paper all posets will be treated as the topological spaces formed by imposing the weak topology unless stated otherwise.
Theorem 2.4. Let (X, τ ), (Y, τ
0) be finite T
0topological spaces and let (X, ≤
X), (Y, ≤
Y) be their corresponding poset representations. Let f : X → Y be a map from X to Y ; then
(1) f is a continuous map if and only if f is an increasing map, (2) f is an open continuous map if and only if f is an M
Pmap, and (3) f is a closed continuous map if and only if f is an L
Pmap.
Note also that all three left–to–right implications are valid without the assumption of finiteness here.
The following result of Marron [7] will prove invaluable throughout this paper.
Theorem 2.5. Let X be a finite poset; then X is splittable over C
nif and only if X contains neither an n + 1 element chain nor two disjoint n element chains.
Definition 2.6. Let (X, τ ) be a topological space. Then:
• X ∈ T
1if and only if, for all x ∈ X, {x} is τ –closed.
• X ∈ T
EFif and only if every finite subset of X is either τ –closed or τ –open.
• X ∈ T
ESif and only if, for all x ∈ X, {x} is either τ –closed or τ –open.
• X ∈ T
Dif and only if, for all x ∈ X, {x}\{x} is τ –closed.
• X ∈ T
0if and only if, for all x, y ∈ X, {x} = {y} implies x = y.
• X ∈ T
Fif and only if, given a finite subset F of X and x / ∈ F , there exists a τ –neighbourhood of one which excludes the other.
• X ∈ T
F Fif and only if, given two disjoint finite subsets F
1, F
2of X, there exists a τ –neighbourhood of one which excludes the other.
• X ∈ T
F Dif and only if X is both T
Fand T
D.
The results gathered together in the next theorem may all be deduced from their definitions in a routine manner.
Theorem 2.7. Each of the separation axioms described above is a splittability class.
With the exception of T
EFand T
F F, pointwise splittability over each invariant is sufficient to imply that invariant. Note in particular that T
F Dis a splittability class since it is the intersection of the two splittability classes T
Fand T
D.
Definition 2.8. Let (X, τ ) be a topological space. Then:
• X ∈ T
U Dif and only if, for all x ∈ X, either {x} is τ –closed or {x}\{x} is a union of disjoint τ –closed sets.
• X ∈ T
Aif and only if, for all x ∈ X, either {x} is τ –closed or {x} is τ –open or {x}\{x} is a point closure.
• X ∈ T
F Aif and only if X is both T
Fand T
A.
• X ∈ T
SDif and only if, for all x ∈ X, either {x} is τ –closed or {x}\{x} = {y}
where {y} is τ –closed.
• X ∈ T
SAif and only if, for all x ∈ X, either {x} is τ –closed or {x} is τ -open or {x}\{x} = {y} where {y} is τ –closed.
• X ∈ T
δif and only if, for all x ∈ X, either {x} is τ –closed or {x} \ {x} is a point closure.
• X ∈ T
ζif and only if, for all x ∈ X, either {x} is τ –closed or {x}\{x} is a union of incommensurable point closures. (A non-empty family F of subsets of X is incommensurable when for each distinct pair F
1, F
2∈ F , F
1* F
2and F
2* F
1.)
• X ∈ T
Yif and only if, for all x 6= y in X,{x} ∩ {y} has at most one element.
• X ∈ T
Y Yif and only if there exists p ∈ X such that for all x 6= y in X, {x} ∩ {y} = {x}, {y}, {p} or ∅.
• X ∈ T
Y Sif and only if, for all x 6= y in X, {x} ∩ {y} = {x}, {y} or ∅.
• X ∈ T
DDif and only if X is both T
Y Sand T
D.
• X ∈ door if and only if, for all A ⊆ X, A is either τ –closed or τ –open.
• X ∈ submaximal if and only if, for all A ⊆ X, A is locally τ –closed (i.e. the intersection of a τ –closed set and a τ –open set). Equivalently, X is submaximal if and only if every dense subset of X is τ –open.
3. Results
Proofs of the earlier results in this section are straightforward and have, apart from a couple of samples, been omitted. The first is due to A. V. Arhangel’skiˇı [3]
and shows in effect that door is a splittability class.
Theorem 3.1. A space is door if and only if it is splittable over the Sierpi´ nski space.
Theorem 3.2. A space is submaximal if and only if it splittable over a class of
submaximal spaces. Thus, submaximal is a splittability class.
Theorem 3.3. Let Y
SMbe the space shown below. A space is submaximal if and only if it is splittable over Y
SM.
i 1
i 3
i2 i4
@
@
@ @
Suppose that T
αand T
βare separation axioms such that T
βimplies T
α. If T
βfails to be a splittability class then ‘X is splittable over T
β’ does not imply X ∈ T
β. How can we best strengthen the condition to restore the result? Two methods are apparent; either restrict the class of mapping (for example ‘X is closed splittable over T
β’) or allow X to be nearly T
β(for example ‘X is T
αand splittable over T
β’).
Example 3.4. Let X be the space shown below.
i b
ia ic A
A A A
Define maps f
1, f
2, f
3: X → C
2as follows:
f
1(a) = 0 f
1(b) = 1 f
1(c) = 1, f
2(a) = 0 f
2(b) = 0 f
2(c) = 1, f
3(a) = 0 f
3(b) = 1 f
3(c) = 0.
Clearly these maps are increasing and split along each subset of X. Recall that X is not T
Y S(since {b} ∩ {c} = {a}) while C
2is T
Y S, so we have found a non-T
Y Sspace splittable over the class of T
Y Sspaces. That is, T
Y Sis not a splittability class. (Alternatively, if T
Y Sis a splittability class then door implies T
Y S– a contradiction.)
Note that the splittability of X over C
2follows directly from Theorem 2.5.
However, the maps f
1, f
2, f
3are actually L
P(therefore closed) and X is already T
Y Y; hence even the stronger condition ‘X is T
Y Yand closed splittable over the class of T
Y Sspaces’ does not imply that X is T
Y S. We can also see that ‘X is closed splittable over the class of T
DDspaces’ does not imply that X is a T
DDspace.
Lemma 3.5 ([6]). A space X is T
Fif and only if, for all x ∈ X, y ∈ {x}\{x}
implies {y} is closed.
Theorem 3.6. A space is T
Y Sif and only if it is open (pointwise) splittable over a class of T
Y Sspaces.
Corollary 3.7. A space is T
DDif and only if it is open (pointwise) splittable over a class of T
DDspaces.
Example 3.8. Let X be the space shown below; then X is neither T
δ, nor T
A, nor
T
SA. Clearly C
3is T
δ, T
Aand T
SA. It can be shown that X is M
Psplittable over
C
3so the condition ‘X is T
Dand open splittable over the class of T
δ(T
A, T
SA)
spaces’ does not imply that X is a T
δ(T
A, T
SA) space. Indeed we see that if X is
T
Dand open splittable over a class of T
SAspaces then X may fail even to be T
A.
i
y iz
ix iw
A A
A A
X
i1 i2 i3 C
3i
u
3iv
3ix
4ix
5ix
1ix
2A A
A A
A A
A A
Y
iy
1iy
2iy
3iy
4iy
5C
5Example 3.9. Let Y, C
5be the spaces shown above. We note that C
5is T
Awhile Y is not: because {x
4} is not closed nor is {x
4} \ {x
4} a point closure. Consider the three maps f : Y → C
5, g : Y → C
5, h : Y → C
5which take x
ito y
ifor i = 1, 2, 4 and 5 and whose definitions are completed as follows: f (u
3) = f (v
3) = y
3, g(u
3) = y
3and g(v
3) = y
2, h(u
3) = y
2and h(v
3) = y
3. These are continuous and closed, and they split Y along every one of its subsets over C
5. Moreover, Y and C
5are self–dual, so we can readily perceive open continuous maps that also suffice to split. Hence ‘Y is T
Dand both closed splittable and open splittable over T
A’ fails to imply that Y is T
A.
Theorem 3.10. A space is T
SAif and only if it is T
Aand is splittable over a class of T
SAspaces.
Theorem 3.11. A space is T
SAif and only if it is closed splittable over a class of T
SAspaces.
Corollary 3.12. A space is T
F Aif and only if it is closed splittable over a class of T
F Aspaces.
Example 3.13. Let X be the dual of the space used in Example 12. Dual argu- ments to those used there show that X is open splittable over C
2. Now X is not T
SD(since {a} is neither closed nor is {a}\{a} a closed singleton) while C
2is T
SD. Hence even the stronger condition ‘X is T
F Aand T
Yand open splittable over the class of T
SDspaces’ does not imply that X is a T
SDspace.
Theorem 3.14. A space is T
SDif and only if it is closed (pointwise) splittable over a class of T
SDspaces.
Theorem 3.15. A space is T
U Dif and only if it is (pointwise) splittable over a class of T
U Dspaces. Thus, T
U Dis a splittability class.
Theorem 3.16. A space is T
Yif and only if it is splittable over a class of T
Yspaces. Thus, T
Yis a splittability class.
Proof. Clearly every T
Yspace is splittable over itself. Suppose that X / ∈ T
Ybut that X is splittable over a class P of T
Yspaces. There must exist distinct x, y ∈ X such that {x} ∩ {y} is neither empty nor a singleton. We note first that by Theorem 2.7, X is T
Fso x / ∈ {y} and y / ∈ {x} via Lemma 3.5. Hence there must be distinct u, v ∈ {x} ∩ {y}. Consider the subspace Y = {u, v, x, y}. Since Y is finite and T
F, every singleton is either open or closed, so Y must have the topology τ = {∅, Y, {x}, {y}, {x, y}, {x, y, u}, {x, y, v}} (any stronger topology would fail to satisfy u, v ∈ {x} ∩ {y}). Note that this is just Y
SMas defined in Theorem 3.3.
Since X is splittable over P, so is Y . Choose continuous f : Y → Z ∈ P such that f
−1f ({x, u}) = {x, u}. Now f (Y ) is finite T
Yand hence T
ES.
• If |f (Y )| = 2 then f ({x, u}) is a singleton so {x, u} is open or closed in X.
• If |f (Y )| = 3 then f ({x, u}) or f ({y, v}) is a singleton so either {x, u} or {y, v}
is open in X.
• If |f (Y )| = 4 then f (Y ) cannot be T
Ysince f is continuous and T
Yis expansive.
We have reached a contradiction, hence no such X can exist. Example 3.17. Let X be the space defined on {x
i, y
i, z
i: i ∈ N} with y
i, z
i< x
ifor all i ∈ N as shown below; then X is T
F, but not T
Asince {x
1} is neither open, nor closed, nor is {x
1}\{x
1} a point closure.
i
y
1iz
1ix
1A A
A A
y
2i iz
2ix
2A A
A A
y
3i iz
3ix
3A A
A A
y
4i iz
4ix
4A A
A A
...
Let Y be the space defined on {a
i, b
i: i ∈ N} with b
i< a
ifor all i ∈ N as shown below; then Y is T
Fand T
A.
ib
1ia
1ib
2ia
2ib
3ia
3ib
4ia
4...
Given A ⊆ X define a map f : X → Y as follows:
If A ∩ {x
i, y
i, z
i} = {z
i} or {x
i, y
i} let f (x
i) = a
i, f (y
i) = a
i, f (z
i) = b
i. If A ∩ {x
i, y
i, z
i} = {y
i} or {x
i, z
i} let f (x
i) = a
i, f (y
i) = b
i, f (z
i) = a
i. Otherwise let f (x
i) = a
i, f (y
i) = b
i, f (z
i) = b
i.
Now f is continuous and f
−1f (A) = A so X is splittable over Y . Moreover f is an open map since f (X \ {z
i}) and f (X \ {y
i}) equal Y or Y \ {b
i} while f (X \ {y
i, z
i}) equals Y \ {b
i}. This shows that a space X may be T
F Dand open splittable over T
SDwithout even being T
A.
Example 3.18. Let X = {x, y, p, u, v, q} and Y = {a, b, c, d} be the spaces shown
below.
i
x iy
ip
A A A A
i
u iv
iq
A A A A X
ic ia
id ib Y
Examining Example 3.4 we see that X is closed splittable over Y . We note that Y is T
Y Ywhile X is not because {x} ∩ {y} = {p} 6= {q} = {u} ∩ {v}. Hence T
Y Yis not a splittability class. Moreover, even the stronger condition ‘X is T
Yand closed splittable over the class of T
Y Sspaces’ does not imply that X is a T
Y Yspace.
Lemma 3.19. A space X is T
Y Yif and only if X is open splittable over a class P of T
Y Yspaces and X has no six–point subspace with induced order as shown below.
i
x iy
ip
A A A A
i
w iz
iq
A A A A
Theorem 3.20. Let (X, ≤) be a partially ordered set, upon which is induced either the weak or the Alexandroff topology; then the space X is T
Y Yif and only if X is open splittable over a class of T
Y Yspaces.
Proof. Again we need only prove sufficiency. Let X be open splittable over a class P of T
Y Yspaces. We note that (X, ≤) has height less than or equal to 2. It is clear that if X has no subspace as depicted and labelled in Lemma 3.19 then X is Y
Y Y. We therefore assume that X contains this subspace.
Let B = {u ∈ X : u ∈ {v} \ {v} for some v ∈ X \ {x, w}}. Choose open continuous f : X → Y ∈ P that splits along A = {x, p, w} ∪ B. Clearly
f (p) ∈ {f (x)} ∩ {f (y)}, and f (q) ∈ {f (w)} ∩ {f (z)}.
(∗)
Consider G = X \ ({w} ∪ {x}) which is open in X. Clearly z ∈ G so f (z) ∈ f (G).
If f (w) ∈ f (G) then there exists a ∈ G such that f (a) = f (w) ∈ f (A). Since a / ∈ {w} ∪ {x} we must have a ∈ B. There exists b / ∈ A such that a ∈ {b} \ {b}
so f (a) ∈ {f (b)}. However, f (q) ∈ {f (w)} = {f (a)} contradicting Y ∈ T
Y Y, so f (w) / ∈ f (G). It follows that f (z) / ∈ {f (w)} so f (z) 6= f (q). For condition (∗) to hold in the T
Y Yspace Y we must have f (x) = f (p). If X has the Alexandroff topology then {x} is an increasing set in (X, ≤) and must be open. The set {f (x)}
is therefore open so f (p) = f (x) / ∈ {f (y)}, contradicting condition (∗). If X has
the weak topology we consider two separate cases.
Case 1. If f
−1f (y) is finite we label its points {a
1, a
2, . . . , a
n}. Set G = X \ ({a
1} ∪ {a
2} ∪ . . . ∪ {a
n} ∪ {y}).
Now x ∈ G so f (x) ∈ f (G). If f (y) ∈ f (G) then there exists b ∈ G such that f (y) = f (b) so b = a
ifor some i ≤ n. However, b = a
i∈ G – a contradiction. / Therefore f (y) / ∈ f (G) so f (p) = f (x) / ∈ {f (y)} contradicting condition (∗).
Case 2. If f
−1f (y) is infinite then the set f
−1({f (y)}) is both infinite and closed.
If f
−1({f (y)}) = X then f (w) ∈ {f (y)}. Hence f (q), f (w) ∈ {f (u)} ∩ {f (y)}, contradicting the fact that Y ∈ T
Y Y. There are also infinitely many u ∈ f
−1f (y) that are not members of B and therefore not contained in any point derived set.
It follows that f
−1({f (y)}) cannot be the union of finitely many point closures, a contradiction to X having the weak topology.
We deal next with the axiom T
ζ, which turns out to be tractible by the methods shown above but somewhat less easily. The strong link between partially ordered sets and topologies that are at least T
0is particularly valuable here, allowing us to characterize this and similar axioms in a convenient and intuitive fashion. For instance, in [13] we find the following definition: a topological space (X, τ ) is T
ζif and only if the induced order is a partial order such that, given x < y in X, then y has a pseudo-predecessor x such that x ≤ z. Here, a pseudo–predecessor of y is a maximal element of L(y)\{y}. A straightforward application of transfinite induction will show that a partially ordered set E that has no maximal element can be decomposed into the disjoint union of two sets, each of which is cofinal in E.
Splitting along one of these two sets provides a way to focus on maximality issues, which we now exploit.
Theorem 3.21. A space is T
ζif and only if it is closed splittable over a class of T
ζspaces.
Proof. As usual, the necessity of the condition is immediate. To establish the sufficiency, suppose if possible that X is not T
ζbut is splittable by closed continuous mappings over T
ζspaces. Because X is at least T
0, its induced order is a partial order, and in terms of it we may select x ∈ X such that the set E = {a ∈ X : a <
x but no pseudo–predecessor ofxlies abovea} is not empty. Express E as a disjoint union A ∪ B of sets, each cofinal in E, and select a
0∈ A. Take P to denote the set (possibly empty) of all pseudo–predecessors of x and find a closed continuous mapping f from X to a T
ζspace Y that splits along A ∪ P . Note (see Theorem 2.4) that f is increasing and an L
pmap.
Every point e of E can be made the first term of an increasing sequence e <
a
1< b
1< a
2< b
2< a
3< . . . that alternates between A and B, and whose images under the splitting map f must all be distinct. This shows, firstly, that f (a
0) is strictly less than f (x), and so f (x) has a pseudo–predecessor m for which f (a
0) ≤ m < f (x). Now m ∈ L f (x) = f L(x), so we may choose y ≤ x such that m = f (y). Clearly y < x and, by a second use of the above observation, y cannot belong to E. Thus x has a pseudo-predecessor P satisfying y ≤ p < x.
Again, f (a
0) ∈ L(m) = L f (y) = f L(y), so select z ≤ y for which f (z) = f (a
0).
The splitting condition assures us that z ∈ A ∪ P but, since z ≤ y ≤ p ∈ P, this is only possible when z = y = p. But now f (a
0) = f (z) = f (y) = m, which is contradicted by a third appeal to the above. This concludes the proof. The separation axioms T
Aand T
δrequire special treatment. The techniques previously employed to establish pleasing results break down. Instead we adopt a different approach by defining a weakened form of each axiom. This property is then bestowed on spaces to be split over a class of spaces with the original property. We begin with T
δ. We have already seen in previous examples that open splittability and closed splittability over a class of T
δspaces fail to imply T
δ. Below we define a weakened form of T
δand show that a space with this weakened property that is closed splittable over T
δmust itself be T
δ.
Definition 3.22. A space X is nearly T
δif and only if, for all x ∈ X, either {x} is closed or {x} \ {x} is a point closure or there exist A, B ⊆ X such that A ∩ B = ∅, {x}\{x} = A ∪ B, A ⊆ B and B ⊆ A. It is easily shown that T
δ⇒ nearly T
δ, but that nearly T
δdoes not even imply T
0.
Theorem 3.23. A space is T
δif and only if it is nearly T
δand closed splittable over a class of T
δspaces.
Proof. We need only prove sufficiency. Suppose that X / ∈ T
δbut X is nearly T
δand closed splittable over a class P of T
δspaces. There must exist x ∈ X so that {x} is not closed nor is {x}\{x} a point closure. Now there exist A, B ⊆ X satisfying the conditions in the definition. Choose continuous closed f : X → Y ∈ P with f
−1f (A) = A. Then, firstly:
f (A) ⊆ f (B) ⊆ f ({x}) = {f (x)} and f (B) ⊆ f (A).
Now {f (x)} is not closed since A 6= ∅, so there exists p ∈ Y for which {f (x)}\{f (x)} = {p}. As in the previous proof we can find c ∈ {x}\{x} such that f (c) = p, and this c must lie either in A or in B. The splitting condition assures us that f (A) and f (B) are disjoint. If c ∈ A then p ∈ f (A)\f (B) so either f (x) ∈ f (B) or f (B) ⊆ {p}\{p}
which is of the form {q}. The first case gives f (x) ∈ f (B) ⊆ f (A) ⊆ {p} which is a contradiction, while the second yields p ∈ f (A) ⊆ f (B) ⊆ {q} which is another.
On the other hand, if c ∈ B a like pair of contradictions arise. Remark 3.24. The order–theoretic description of T
δ, found in [13], permits an alternative view of the previous proof: a topology (X, τ ) is T
δif and only if the induced order ≤ is a partial order such that every non–minimal element of X has a predecessor (that is, a maximum strict lower bound).
Thus far, this account has presented only negative results concerning the separa- tion axiom T
A. Perhaps surprising, we can obtain a positive result by introducing a weaker version of T
Aanalogous to nearly T
ζ.
Definition 3.25. A space X is nearly T
Aif and only if, for all x ∈ X, either {x}
is open or {x} is closed or {x}\{x} is a point closure or there exist A, B ⊆ X such
that A ∩ B = ∅, {x} \{x} = A ∪ B, A ⊆ B and B ⊆ A. It is again easily seen
that T
A⇒ nearly T
A, but that nearly T
Adoes not even imply T
0. The proof of the
following proceeds largely as that of Theorem 3.21.
Theorem 3.26. A space is T
Aif and only if it is nearly T
Aand closed splittable over a class of T
Aspaces.
References
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A.J. Hanna
Queen’s University Belfast Belfast BT7 1NN
UNITED KINGDOM [email protected]
T.B.M. McMaster Queen’s University Belfast Belfast BT7 1NN
UNITED KINGDOM [email protected]