Mean Field Flory Huggins Lattice Theory
• Mean field: the interactions between molecules are assumed to be due to the interaction of a given molecule and an average field due to all the other
molecules in the system. To aid in modeling, the solution is imagined to be divided into a set of cells within which molecules or parts of molecules can be placed (lattice theory).
• The total volume, V, is divided into a lattice of No cells, each cell of volume v. The molecules occupy the sites randomly according to a probability based on their respective volume fractions. To model a polymer chain, one occupies xi adjacent cells.
• Following the standard treatment for small molecules (x1 = x2 = 1)
using Stirling’s approximation:
N
o=
N
1+
N
2=
n
1x
1+
n
2x
2V
=
N
ov
Ω1,2= N0! N1!N2! 1 M for M M ln M M ! ln = − >>ΔS
m=
k
(
−
N
1ln
φ
1−
N
2ln
φ
2)
φ
1 = ?Entropy Change on Mixing
Δ
S
m
Δ
S
m
N
o
= +
k
(
−φ
1
ln
φ
1
−φ
2
ln
φ
2
)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0 0.2 0.4 0.6 0.8 1 φ2The entropic contribution to ΔGm is thus seen to always
favor mixing if the random mixing approximation is used.
Remember this is for small molecules x1 = x2 = 1
Enthalpy of Mixing
Δ
H
m
• Assume lattice has
z
nearest-neighbor cells.
• To calculate the enthalpic interactions we consider
the number of
pairwise
interactions. The probability
of finding adjacent cells filled by component
i
, and
j
is
given by assuming the probability that a given cell is
occupied by species
i
is equal to the volume fraction
Δ
H
m
cont’dυ
ij
=
υ12 = N1z φ2υ
11 = N1zφ1 / 2υ
22 = N2 zφ2 / 2 H1,2 =υ
12ε
12 +υ
11ε
11 +υ
22ε
22 H1,2 = z N1φ2ε12 + z 2 N1φ1ε11 + z 2 N2 φ2 ε22 H1 = z N1 2 ε11 H2 = z N2 2 ε22 # of i,j interactions N1 + N2 = N0(
11 22)
1 2 12 0⎢⎣⎡ε − 12 ε +ε ⎥⎦⎤φφ = z N HM Δ ΔHM = z N1φ2ε12 + N1ε11 2(
φ1−1)
+ N2ε22 2(
φ2 −1)
⎡ ⎣ ⎢ ⎤ ⎦ ⎥Mixed state enthalpic interactions Pure state enthalpic
interactions
recall
χ
Parameter
• Define
χ
:
(
)
⎥⎦
⎤
⎢⎣
⎡
−
+
=
12 11 222
1
ε
ε
ε
χ
kT
z
χ
represents the chemical interaction between the components
Δ
H
MN
0=
k T
χ
φ
1φ
2•
Δ
G
M:
Δ
G
M= Δ
H
M−
T
Δ
S
MNote: ΔGM is symmetric in φ1 and φ2.
This is the Bragg-Williams result for the change in free energy for the mixing of binary metal alloys.
[
1 2 1 1 2 2]
0ln
ln
φ
φ
φ
φ
φ
χφ
+
+
=
kT
N
G
MΔ
[
1 1 2 2]
2 1 0ln
ln
φ
φ
φ
φ
φ
χφ
−
−
−
=
kT
kT
N
G
MΔ
Ned: add eqn for Computing Chi from Vseg (delta-delta)2/RT
Δ
G
M
(T,
φ
,
χ
)
• Flory showed how to pack chains onto a lattice and correctly evaluate
Ω1,2 for polymer-solvent and polymer-polymer systems. Flory made a complex derivation but got a very simple and intuitive result, namely that ΔSM is decreased by factor (1/x) due to connectivity of x
segments into a single molecule:
• Systems of Interest
- solvent – solvent x1 = 1 x2 = 1 - solvent – polymer x1 = 1 x2 = large - polymer – polymer x1 = large, x2 = large
⎥ ⎦ ⎤ ⎢ ⎣ ⎡ + − = 2 2 2 1 1 1 0 ln ln
φ
φ
φ
φ
x x k N SM Δ⎥
⎦
⎤
⎢
⎣
⎡
+
+
=
2 2 2 1 1 1 2 1 0ln
ln
φ
φ
φ
φ
φ
χφ
x
x
kT
N
G
MΔ
(
)
⎥⎦
⎤
⎢⎣
⎡
−
+
=
12 11 222
1
ε
ε
ε
χ
kT
z
Need to examine variation of ΔGM with T, χ, φi, and xi to determine phase behavior.
For polymers
Note possible huge asymmetry in x1, x2
Flory Huggins Theory
•
Many Important Applications
1. Phase diagrams
2. Fractionation by molecular weight, fractionation by composition
3. Tm depression in a semicrystalline polymer by 2nd component
4. Swelling behavior of networks (when combined with the theory of rubber elasticity)
The two parts of free energy per site
• ΔHM can be measured for low molar mass liquids and estimated for
nonpolar, noncrystalline polymers by the Hildebrand solubility approach. ΔSM = − φ1 x1 ln(φ1) − φ2 x2 ln(φ2) ΔHM = χ φ1 φ2 ΔGM N0 k T
S
H
Solubility Parameter
• Liquids
Δ
H
ν= molar enthalpy of vaporization
Hildebrand proposed that compatibility between
components 1 and 2 arises as their solubility parameters
approach one another
δ
1→ δ
2.
•
δ
pfor polymers
Take
δ
Pas equal to
δ
solvent for which there is:
(1) maximum in
intrinsic viscosity
for soluble polymers
(2) maximum in swelling of the polymer network
or (3) calculate an approximate value of
δ
Pby chemical group
contributions for a particular monomeric repeat unit.
δ = ΔE V ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 1/ 2 = cohesive energy density = ΔHν − R T Vm ⎡ ⎣ ⎢ ⎢ ⎤ ⎦ ⎥ ⎥ 1/ 2
Estimating the Heat of Mixing
Hildebrand equation:
V
m= average molar volume of solvent/monomers
δ
1,
δ
2= solubility parameters of components
Inspection of solubility parameters can be used to estimate
possible compatibility (miscibility) of solvent-polymer or
polymer-polymer pairs. This approach works well for
non-polar solvents with non-polar amorphous polymers.
Think: usual phase behavior for a pair of polymers?
Note: this approach is not appropriate for systems with specific
interactions, for which ΔHM can be negative.
Influence of
χ
on Phase Behavior
ΔSm -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 ΔH m -0.4 -0.2 0 0.2 0.4 0.6 0.8 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 ΔG m -1 -0.8 -0.6 -0.4 -0.2 0 0.2 0 0.2 0.4 0.6 0.8 1 χ = -1,0,1,2,3 χ = -1,0,1,2,3 Assume kT = 1 andx
1= x
2At what value of chi does the system go biphasic?
Expect
symmetry
-T
What happens to entropy for a pair of polymers?
Polymer-Solvent Solutions
• Equilibrium: Equal Chemical potentials:
so need partialmolar quantities j n P T i i
n
G
, , ,⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
=
μ
μ
1oμ
2oμ
1,
μ
2state
standard
in the
potential
chemical
the
is
and
activity
the
is
a
where
ln
0 i , , , 0μ
φ
φ
μ
μ
i i i m j n P T i m i i in
G
n
G
a
RT
∂
∂
∂
∂
=
⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
≡
≡
−
Δ
Δ
μ
1−
μ
10=
RT
ln
φ
1+
1
−
1
x
2⎛
⎝
⎜
⎞
⎠
⎟
φ
2+
χ φ
2 2⎡
⎣
⎢
⎤
⎦
⎥
solvent
μ
2−
μ
20=
RT
[
ln
φ
2−
(
x
2−
1
)
φ
1+
x
2χ φ
12]
polymer
Note: For a polydisperse system of chains, use x2 = <x2> the number average
Recall at equilibrium
μ
iα=
μ
iβ etcP.S. #1
Construction of Phase Diagrams
• Chemical Potential
• Binodal - curve denoting the region of 2 distinct
coexisting phases
μ
1' =
μ
1"
μ
2' =
μ
2"
or equivalently
μ
1' –
μ
1o=
μ
1" –
μ
1oμ
2' –
μ
2o=
μ
2" –
μ
2o⎥
⎦
⎤
⎢
⎣
⎡
+
+
=
2 2 2 1 1 1 2 1 0ln
ln
φ
φ
φ
φ
φ
χφ
x
x
kT
N
G
mΔ
j n P T i in
G
, , ,⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
=
μ
and since 2 , 2μ
Δ
Δ
=
⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
P T mn
G
⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
=
⎥
⎦
⎤
⎢
⎣
⎡
∂
∂
2 2 2 2n
G
n
G
m mφ
φ
Δ
Δ
Phases called prime and double prime
Binodal curve is given by finding common tangent to ΔGm(φ)
curve for each φ, T combination. Note with lattice model (x1 = x2) (can use volume
Construction of Phase Diagrams
cont’d
• Spinodal (Inflection Points)
• Critical Point
∂
2Δ
G
m∂
φ
22⎡
⎣
⎢
⎤
⎦
⎥ =
0
and
∂
3Δ
G
m∂
φ
23⎡
⎣
⎢
⎤
⎦
⎥ =
0
∂
2Δ
G
m∂
φ
22⎡
⎣
⎢
⎤
⎦
⎥
α=
0
∂
2Δ
G
m∂
φ
22⎡
⎣
⎢
⎤
⎦
⎥
β=
0
χ
c
φ
1,
c
Two phases Equilibrium Stability 0 0.0 0.2 0.4 0.6 0.8 1.0 1 2 3 χ N 4 5 6 One phase A φ'A A B B φ"A A' B B' Critical point φ Tlow Thigh hotDilute Polymer Solution
• # moles of solvent (n1) >> polymer (n2) and n1 >> n2x2• For a dilute solution:
φ
1 = n1v1 n1v1 + n2x2v2φ
2 = n2x2v2 n1v1 + n2x2v2 ~ n2x2 n1 Useful Approximationsφ
2 ≡ n2x2 n1 ~ X2x2 ln(1+ x) ≅ x − x 2 2 + x3 3 −... ln(1− x) ≅ − x − x 2 2 − x3 3 −...⎥
⎦
⎤
⎢
⎣
⎡
⎟
⎠
⎞
⎜
⎝
⎛ −
+
−
=
−
22 2 2 0 1 1χ
1
2
φ
φ
μ
μ
x
RT
Careful…Dilute Polymer Solution
cont’d
• Recall for an Ideal Solution the chemical potential is proportional to the activity which is equal to the mole fraction of the species, Xi
• Comparing to the expression we have for the dilute solution, we see the first term corresponds to that of an ideal solution. The 2nd term is called
the excess chemical potential
– This term has 2 parts due to
• Contact interactions (solvent quality) χ φ22 RT
• Chain connectivity (excluded volume) -(1/2) φ22 RT
• Notice that for the special case of
χ
= 1/2, the entire 2nd term disappears!This implies that in this special situation, the dilute solution acts as an Ideal solution.
The excluded volume effect is precisely compensated by the solvent quality effect.
Previously we called this the θ condition, so χ = 1/2 is also the theta point
2 2 2 2 1 0 1 1
ln
ln(
1
)
x
RT
RTX
X
RT
X
RT
φ
μ
μ
−
=
=
−
≅
−
=
−
μ1−μ10 = RT −φ2 x2 + χ − 1 2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ φ22 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ μ1 −μ10F-H Phase Diagram at/near
θ
condition
•
x
1= 1, x
2>> 1 and n
1>> n
2x
2χ
c=
1
2
1
x
1+
1
x
2⎛
⎝
⎜
⎜
⎞
⎠
⎟
⎟
2φ
1,c=
x
2x
1+
x
2Note strong asymmetry!
Find:
Symmetric when x1 = 1 = x2 T X2 = 1000 X2 = 100 X2 = 30 X2 = 10 X1= 1 Binodal Two phases 0.0 0.6Critical Composition &
Critical Interaction Parameter
x1 , x2 General 0.5 x1 = x2 = N Symmetric Polymer-Polymer x1 = 1; x2 = N Solvent-polymer 2 0.5 x1 = x2 = 1 2 low molar mass liquids
χ
cφ
1,cBinary System
x
21
+
x
21
2
1
+
1
x
2⎛
⎝
⎜
⎜
⎞
⎠
⎟
⎟
22
N
x
2x
1+
x
21
2
1
x
1+
1
x
2⎛
⎝
⎜
⎜
⎞
⎠
⎟
⎟
2Polymer Blends
Good References on Polymer Blends:• O. Olasbisi, L.M. Robeson and M. Shaw, Polymer-Polymer Miscibility, Academic Press (1979).
• D.R. Paul, S. Newman, Polymer Blends, Vol I, II, Academic Press (1978).
• Upper Critical Solution Temperature (UCST) Behavior Well accounted for by F-H theory with χ = a/T + b
• Lower Critical Solution Temperature (LCST) Behavior
FH theory cannot predict LCST behavior. Experimentally find that blend systems displaying hydrogen bonding and/or large thermal expansion factor difference between the respective
x1 = x2= N
Phase Diagram for UCST Polymer Blend
A polymer x1 segments v1 ≈ v2 & x1 ≈ x2
B polymer x2 segments
χ
=
A
T
+
B
∂Δ
G
m∂
φ
=
0
binodal
∂
2Δ
G
m∂
φ
2=
0 spinodal
∂
3Δ
G
m∂
φ
3=
0
critical point
Predicted from FH Theory
Figure by MIT OCW.
Two phases Equilibrium Stability 0 0.0 0.2 0.4 0.6 0.8 1.0 1 2 3 χ N 4 5 6 One phase A φ'A A B B φ"A A' B B' Critical point φ Tlow Thigh hot
2 Principal Types of Phase Diagrams
Konigsveld, Klentjens, Schoffeleers
Pure Appl. Chem. 39, 1 (1974) Nishi, Wang, Kwei Macromolecules, 8, 227 (1995)
Figure by MIT OCW.
Two-phase region Single-phase region UCST 0 φ 1 2 Tc T Two-phase region Single-phase region LCST 0 φ2 1 Tc T φ 60 0 0.2 0.4 0.6 0.8 1.0 80 100 120 140 160 180 T(oC) P1 PS Wps 0.2 0.4 0.6 0.8 100 140 2700 2100 T(oC) 180 PS-PVME PS-PI PS PVME
Assignment - Reminder
• Problem set #1 is due in class on
February 15th.