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ISSN 2229 – 5046
International Journal of Mathematical Archive- 8(10), Oct. – 2017 199
SOME NEW FAMILIES OF ODD GRACEFUL GRAPHS
AMIYA KUMAR BEHERA*
1, DEBDAS MISHRA
2AND PURNA CHANDRA NAYAK
31
Department of Mathematics,
Siksha ‘O’ Anusandhan University, Bhubaneswar, India.
2
Department of Mathematics,
C. V. Raman College of Engineering, Bhubaneswar, India.
3
Department of Mathematics,
Bhadrak (Autonomous) College, Bhadrak, India.
(Received On: 19-09-17; Revised & Accepted On: 16-10-17)
ABSTRACT
I
n this paper we give odd graceful labeling to Bistar, :2, 1n
K , K1,n,n , Coconut tree CT n,3 , K1,n+Kn,1 ,
n n
nC
K
K
,1+
4+
1, forn
≥
3
, nC K1,n 24 + ,
K
1,n+
nP
2+
K
n,1 ,K
1,n+
nP
3+
K
n,1 , C2r with every alternatevertex attached to a pendant vertex .
Key Words: Odd graceful labeling, Vertex labeling, edge labeling.
1. INTRODUCTION
A graph G with q edgesis said to be odd-graceful, if there is an injection f from V(G) to
{
0,1,2,,2q−1}
such that, when each edge {x, y} of G is assigned the labelf
( ) ( )
x
−
f
y
, the resulting edge labels are{
1,3,5,,2q−1}
. The concept of odd graceful graph was introduced in 1991 by Gnanajothi [1].Gnanajothi [1] proved that the class of odd-graceful graphs lies between the class of interlaced graphs and the class of bipartite graphs by showing that every interlaced graph has an odd-graceful labeling and every graph with an odd cycle
is not odd-graceful. She also proved the following graphs are odd-graceful:
P
n;C
n if and only if n is even;K
m,n;combs 1 n
P K (graphs obtained by joining a single pendent edge to each vertex of
P
n ); books ; crowns1 n C K (graphs obtained by joining a single pendent edge to each vertex of
C
n ) if and only if n is even ; the disjoint union ofcopies of
C
4; the one-point union of copies ofC
4;C
n×
K
2if and only if n is even; caterpillars; rooted trees of height 2; the graphs obtained fromP
n (n > 3) by adding exactly two leaves at each vertex of degree 2 ofP
n; thegraphs obtained from
P
n×
P
2 by deleting an edge that joins to end points of theP
n paths ; the graphs obtained from a star by adjoining to each end vertex the pathP
3 or by adjoining to each end vertex the pathP
4 . She conjectures that all trees are odd-graceful and proves the conjecture for all trees with order up to 10. Barrientos [2] has extended this to trees of order up to 12. For details in the progress made so far in this area one can refer to the latest Survey on graph labeling problems due to Gallian [3]. Here we are inspired by the works of Solairaju [4] and Moussa and Badr [5] and give odd graceful labeling to the graphs : Bistar, K1,n:2 ,n n
K1, , , Coconut tree CT n,3 , K1,n+Kn,1 ,
n
n nC K
K ,1+ 4+ 1, for
n
≥
3
, nC K1,n 24 + , K1,n +nP2+Kn,1 , K1,n +nP3+Kn,1 , C2r with every alternate vertex attached to a pendant vertex .
Corresponding Author: Amiya Kumar Behera*
1,
RESULTS
Theorem 2.1: A Bistar
B
m,n is odd graceful.Proof: Let
B
m,n be a Bistar containingm
+
n
+
2
vertices consisting of the set{
u u
1,
2,
v w
i,
j}
,
1,
,
i
=
m
,j
=
1
,
,
n
whereu
1 ,u
2 are the internal vertices andv
i,w
j are the vertices adjacent tou
1 ,u
2respectively. Let q be the total number of edges of
B
m,n such that q=m+n+1. Now the vertex labelling of theBistar
B
m,n are given as( )
u1 =0f ,f u
( )
2 =1,f v
( )
i=
2
q
− +
2
i
1,
i
=
1
,
2
,
,
m
,f
( )
w
j=
2
q
−
2
m
−
2
j
+
2
,
j
=
1
,
2
,
,
n
.The edge labelling of the Bistar is given as
f
( )
u
1v
i=
2
q
−
2
i
+
1
,
i
=
1
,
2
,
,
m
,f(
u2wj)
=2q−2m−2j+1,j=1,2 ,…,n. So the edge labelling of the Bistar consists of the labelled set
{
1
,
3
,
5
,
,
2
q
−
1
}
. Hence the BistarB
m,n is odd graceful.Figure-1: A Bistar
B
4,4 with an odd graceful labelingTheorem 2.2: K1,n:2 is odd graceful for every natural number n.
Proof: Let the set of vertices of K1,n:2 be
{
u
,
v
,
w
,
u
i,
v
i}
, i=1,,n. Let P3 be the path with vertices {u , v, w},where u, v, w are the internal vertices and
u
i,v
j the vertices adjacent to u, v and w respectively. Let(
K
1,n:
2
)
=
{
uw
,
vw
,
uu
i,
vv
i,
i
=
1
,
2
,
,
n
}
be then edge set of :2, 1n
K and q be the total number of edges
of :2 , 1n
K such that
q
=
2
n
+
2
. The vertex labeling :2 , 1nK is given as follows
f
( )
u
i=
2
i
−
1
,
i
=
1
,
,
n
,( )
v
n
i
i
n
f
i=
2
(
+
)
+
1
,
=
1
,
2
,
,
, f( )
u =0,f(v)=2,f(w)=4n+3, Now the induced edge labelling of :2 , 1nK
is as follows f
( )
uui =2i−1,i=1,,n ,f
(
vv
j)
=
2
(
n
+
j
)
−
1
,j
=
1
,
,
n
.f uw
(
)
=
4
n
+ =
3
2
q
−
1
( )
wv
=
4
n
+
1
=
2
q
−
3
f
. So the edge labelling ofK
1,n:
2
consists of the set{
1
,
3
,
5
,
,
2
q
−
1
}
. Hence2
:
, 1nK
is odd graceful.© 2017, IJMA. All Rights Reserved 201 Theorem-2.3:
K
1,n,n is odd graceful for every natural number n.Proof: Let the set of vertices of
K
1,n,n be{
u
,
u
i,
v
i}
such that the root vertex u is adjacent tou
i andu
i isadjacent to
v
i fori
=
1
,
,
n
. LetE
(
K
1,n,n)
=
{
uu
i,
u
iv
i}
be the edge set ofK
1,n,n . The vertex labelling ofn n
K
1, , are given asf
( )
u
=
0
,
f(ui)=4n−2i+1,f
(
v
i)
=
2
n
+
2
i
−
2
,
i
=
1
,
,
n
. Now the edge labellingof
K
1,n,n are given asf
( )
uu
i=
4
n
−
2
i
+
1
=
2
q
−
2
i
+
1
,f
(
u
iv
j)
=
2
n
−
4
i
+
3
,i
=
1
,
,
n
. So the edgelabelling of
K
1,n,n consists of the set{
1
,
3
,
5
,
,
2
q
−
1
}
. HenceK
1,n,n is odd graceful.Figure-3:The tree with an odd graceful labeling
Theorem-2.4: The Coconut tree CT n,3 is odd graceful.
Proof: Let the set of vertices of
CT
n
,
3
be{
u,v,w,ui,i=1,,n}
where u, v, w lie on the central path of3
,
n
CT
. LetE
CT
n
,
3
=
{
uu
i,
uv
,
vw
}
,i
=
1
,
,
n
be the edge set ofCT
n
,
3
. The vertex labellingof
CT
n
,
3
are given asf
( )
u
=
0
,
f
(
v
)
=
2
n
+
3
,
f
(
w
)
=
2
, ( )f ui = −2i 1,
i
=
1
,
,
n
. Now the edgelabelling of
CT
n
,
3
are given asf uv
( )
=
2
n
+
3
=
2
q
−
1,
f vw
(
)
=
2
n
+
1
=
2
q
−
3,
f uu
(
i)
= −
2
i
1,
1,
,
i
=
n
. So the edge labelling ofCT
n
,
3
consists of the set {1, 3, 5, - - - , 2q-1}. Hence the Coconut tree CT n,3 is odd graceful.Figure-4: The coconut tree
CT
5
,
3
with an odd graceful labelingTheorem-2.5: K1,n+Kn,1 is odd graceful for every natural number n.
Now the vertex labelling of
1 , , 1n Kn
K + is given by
f u
( )
=
0, ( )
f v
=
2 ,
n
f u
( )
i=
4
n
− +
2
i
1,
i
=
1,
,
n
.And the edge labelling of
K
1,n+
K
n,1 is given byf uu
( )
i=
4
n
− + =
2
i
1, 2
q
− +
2
i
1
f u v
(
i)
=
2
n
− +
2
i
1,
n
i
=
1
,
,
. So the edge labelling ofK
1,n+
K
n,1 consists of the set{
1
,
3
,
5
,
,
2
q
−
1
}
. Hence1 , , 1n Kn
K +
is odd graceful.
Figure-5: The graph
1 , 6 6 , 1 K
K + with an odd graceful
Theorem-2.6:
K
n,1+
nC
4+
K
1,n is odd graceful for every natural number n ≥ 3.Proof: Let the set of vertices of
n n nC K
K ,1+ 4+ 1, be
{
u
,
v
,
u
i,
v
i,
w
i,
i
=
1
,
,
n
}
where the verticesare in the order
u
i−
u
−
v
i−
v
−
w
i . Then edge set ofK
n,1+
nC
4+
K
1,n is{
u u uv v v vw
i,
i,
i,
i}
,
1,
,
i
=
n
. We define the vertex labelling f of G by f( )
u =0,f
( )
v
=
8
n
−
2
,( )
=
+
−
=
=
n
i
i
n
i
u
f
i,
,
2
,
3
2
8
1
,
1
( )
v
n
i
i
n
f
i=
12
−
2
+
1
,
=
1
,
,
2
( )
i 2 2 3 , 0 , , 1.f w = n+ i− i= − − − −n
The label of the edges of
K
n,1+
nC
4+
K
1,n are given by( )
1
,
1
,
8
2
3 ,
2, 3,
,
i
i
f u u
n
i
i
n
=
=
− +
=
− − −
( )
vw
=
6
n
−
2
i
+
1
,
i
=
0
,
−
−
−
,
n
−
1
f
i( )
v
v
n
i
i
n
f
i=
4
−
2
+
3
,
=
1
,
,
2
( )
i12
2
1,
1,
, 2 .
f uv
=
n
− +
i
i
= − − −
n
We observe that the label of the edges of
K
n,1+
nC
4+
K
1,n constitute the set{
1
,
3
,
5
,
,
2
q
−
1
}
. Hencen
n nC K
© 2017, IJMA. All Rights Reserved 203 Figure-6: The graph
K
n,1+
nC
4+
K
1,n with an odd gracefulTheorem 2.7:
n K nC 1,
2
4 + is odd graceful.
Proof: Let the vertices of
n K nC 1,
2
4 + consists of the set
{
u
,
v
,
u
i,
v
i,
w
,
w
i,
i
=
1
,
,
n
}
, where the vertices are adjacent in the orderu
−
u
i−
v
−
v
i−
w
−
w
i. The edge set ofn
K
nC
42+
1, is{
uu
i,
u
iv
,
vv
i,
v
iw
,
ww
i}
,i
=
1
,
,
n
. The vertex labelling f ofnC
42+
K
1,n are assigned as( )
u
4
n
,
f
=
f
(
u
i)
=
8
n
+
2
i
−
1
,
f
( )
v
=
0
,f
( )
v
i=
20
n
−
2
i
+
1
,i
=
1
,
,
2
n
,f
( )
w
=
16
n
,f
( )
w
i=
2
i
−
1
,n
i
=
1
,
,
2
.The label of the edges ofnC
42+
K
1,n are given by( )
uu =4n+2i−1,f i
f
(
u
iv
)
=
8
n
+
2
i
−
1
,
f
( )
vv
i=
20
n
−
2
i
+
1
,f
(
v
iw
)
=
4
n
−
2
i
+
1
,i
=
1
,
,
n
.(
i)
16
2
1
f ww
=
n
− +
i
,i=1,...2n. We observe that the label of the edges ofnC
42+
K
1,nconstitute the
set
{
1
,
3
,
5
,
,
2
q
−
1
}
. HencenC
K
1,n 24
+
is odd graceful.Theorem 2.8:
K
1,n+
nP
2+
K
n,1 is odd graceful.Proof: Let the vertices of K1,n+nP2+Kn,1 consists of the set
{
u
,
u
i,
v
,
v
i}
where the vertices are adjacentin the order
u u
− − −
iv
iv
. The edge set ofK
1,n+
nP
2+
K
n,1 is{
u
u
i,
u
iv
i,
v
iv
;
i
=
1
,
,
n
}
. The labeling of the vertices of1 , 2 ,
1n
nP
K
nK
+
+
are given byf
(
u
)
=
0
,f( )
ui =6n−2i+1,
f
(
v
)
=
2
n
−
1
n i
i n v
f( i) 4 4 2, 1, ,
, = − + = . The labeling of the edges of
K
1,n+
nP
2+
K
n,1 are given by( )
uu
n
i
f
u
v
n
i
f
v
v
n
i
i
n
f
i=
6
+
2
+
1
,
(
i i)
=
2
+
2
−
1
,
(
i)
=
2
−
4
+
3
,
=
1
,
,
. Now the edge labeling of1 , 2 ,
1n
nP
K
nK
+
+
constitute the set{
1
,
3
,
5
,
,
2
q
−
1
}
. Hence the graphK
1,n+
nP
2+
K
n,1 is an odd graceful graph.Figure-8: The graph
K
1,4+
4
P
2+
K
4,1 with an odd gracefulTheorem 2.9:
K
1,n+
nP
3+
K
n,1 is odd graceful.Proof: Let the vertices of
1 , 3 ,
1n nP Kn
K + + consists of the set
{ , , ,
u u v w w
i i i, }
where the vertices are adjacent in the orderu
−
u
i−
v
i−
w
i−
w
. The edge set of1 , 3 ,
1n nP Kn
K + + is
{
uu u v v v
i,
i i,
i;
.i
=
1,
, }
n
Thelabeling of the vertices of
1 , 3 ,
1n
np
K
nK
+
+
are given byf u
( )
=
0 ,
f u
( )
i=
8
n
− +
2
i
1,
f v
( )
i=
4
n
− +
4
i
2,
( )
(
i)
6
2
1),
4
f w
=
n
− +
i
f w
=
n
. The labeling of the edges of K1,n+nP3+Kn,1 are given by( )
i 8 2 1, ( i i) 4 2 1, ( i i) 2 2 1,f u u n= + i− f u v = n+ i− f v w = n+ i−
f w w
(
i)
=
2
n
− + =
2
i
1
i
1,
,
n
. Weobserve that the labels of the edges of
K
1,n+
nP
3+
K
n,1 constitute the set{
1
,
3
,
5
,
,
2
q
−
1
}
. Hence thegraph
K
1,n+
nP
3+
K
n,1 is an odd graceful graph.Figure-9: The graph
K
1,4+
4
P
3+
K
4,1with an odd graceful labelingTheorem-2.10: The graph C2r with every alternate vertex attached to a pendant vertex is odd graceful.
© 2017, IJMA. All Rights Reserved 205
2
1, 3,..., 2
1
( )
2, 4, 6,..., 2
2
4
2
2
i
n i
if
i
r
f u
i
if
i
r
r
if
i
r
−
=
−
=
=
−
−
=
and
0
1
( )
2
2
2
3
2
2
5, 7,..., 2
1
i
if
i
f u
n
i
if
i
n
i
if
i
r
=
=
− +
=
−
=
−
( ) ( )
u
f
u
n
( )
i
i
f
i−1−
i=
2
−
−
1
−
=
2
n
−
2
i
+
1
,
i
=
2
,
3
,
,
2
r
−
1
;f
(
u
2r−1) ( )
−
f
u
2r=
3
;( ) ( )
u
2−
f
u
1=
2
n
−
1
−
(
4
r
−
2
)
f
r =6
r
−
1
−
(
4
r
−
2
)
=
2
r
+
1
,f
( ) ( )
u
1−
f
v
1=
2
n
−
1
,( ) ( )
u
3−
f
v
3=
1
f
,f
(
u
2i−1) (
−
f
v
2i−1)
=
2
i
−
1
,i
=
3
,
4
,
,
r
. Observe that the set of all vertex labels ofthe graph is the set
{
1
,
3
,
5
,
,
2
n
−
1
}
. Hence, the given graph is odd graceful.Figure 10:
C
14 with every alternate vertices attached to a pendant vertex is odd graceful.REFERENCES
1. Gnanajothi R.B., (1991), Topics in Graph Theory, Ph. D. Thesis, Madurai Kamaraj University, India. 2. Barrientos C., Odd Graceful Graphs, Preprint.
3. Gallian J.A., A dynamic survey of graph labeling, Electronic Journal of Combinatorics, DS6, Eighteenth edition, December 17, 2015, url:http://www.combinatorics.org/Surveys/.
4. Solaraju A., Edge – Odd Graceful Graphs, Electronic Notes in Discrete Mathematics, 33 (2009), PP. 15 – 20. 5. Solaraju A., Edge – Odd Graceful Labeling of Crown Graphs, Proceedings of 1st Int Conference on Computer
Science from Algorithms to Applications (CSAA-2009), 8-10 2009, Cairo, PP. 15 – 20.
6. Graf A, A new graceful labeling for pendant graphs, Aequationes Mathematicae DOI
10.1007/s00010-012-0184-4
Source of support: Nil, Conflict of interest: None Declared.