220 KV Sag Tension Calculation- Thyottar

POWER GRID CORPORATION OF INDIA LTD.

( A GOVERNMENT OF INDIA ENTERPRISER)

"SOUDAMINI", 3

FLOOR, PLOT NO.-2

SECTOR-29, GURGAON-122001, HARYANA

PROJECT

CONTRACTOR

TITLE

DRG. NO.

REVISION

PREPARED BY

CHECKED BY

APPROVED BY

DATE

1

23/3/2011

0

8/2/2011

REVISION

DATE

DESIGN, ENGINEERING, SUPPLY, ERECTION(INCLUDING CIVIL WORK), TESTING AND

COMMISSIONING FOR CONSTRUCTION OF SUB-STATION PACKAGE-'PB-S3' UNDER TRANSMISSION

SYSTEM ASSOCIATED WITH PALLATNA GBPP & BONGAIGAON TPS IN NORTH EASTERN REGION

EX WORKS SUPPLY CONTRACT AGREEMENT: REF. NO. C-62010-S219A-3/G7/CA-I/3476 DATED 6.10.2010

SERVICE CONTRACT AGREEMENT: REF. NO. C-62010-S219A-3/G7/CA-II/3477 DATED 6.10.2010

TPK

23/3/2011

PSC ENGINEERS PVT. LTD., KOLKATA

132KV BAY EXTENSION AT PURBO KANCHAN BARI SUB-STATION - SAG TENSION CALCULATION

AND STRINGING CHART

K2010PS003A-245

R1

ANUPAM

ANUPAM

REVISED AS PER PGCIL COMMENTS

ANUPAM

FIRST SUBMISSION FOR APPROVAL

ANUPAM

1.0

INTRODUCTION :

For 132kV Bay Extension at Purbo Kanchan Bari Sub-Station (Tripura)

1) Single Zebra ACSR Conductor is proposed for Transfer Bus - A & B.

2) Single Zebra ACSR Conductor is proposed for high level bus (jack bus).

3) The initial tensile force is considered as per technical specification i.e. 1000 kg per conductor for Single Zebra

ACSR.

The present report is brought out to determine tension and sag under different conditions for conductor

and also to check vertical clearances.

2.0

STANDARDS & REFERENCES :

Following standards/references are used for present report :-

i)

IS : 802 ( Part 1 / Sec 1 ) : 1995

ii)

IS : 875 ( Part 3 ) - 1987

iii)

Technical specification of PGCIL for substation package-'PB-S3' under transmission system associated with pallatna

GBPP & Bongaigaon TPS in nort eastern region.

iv)

Tamilnadu Electricity Board Engineer's association"Power Engineer's Hand-Book" (Part-I)

v)

Overhead Line Practice By John McCombe (Book)

vi)

Drawings -

Layout Plan- K2010PS003A-203 Rev. 2

Layout Sections- K2010PS003A-204 Rev.2

3.0

METHODOLOGY :

To compute sag and tension, calculations are carried out for following conditions as stated in clause 10 of IS 802

( Part 1 / Sec 1 ) : 1985.

a) 0

C -- Nil wind and 36 % wind Force.

b) 32

C -- Nil Wind and Full Wind Force.

b) 75

C -- Nil Wind condition.

Sag at these temperatures for Nil wind condition is checked for adequate Vertical clearance.Tension for 0

C & 36% wind,

32

C & full wind has been computed to check it against design value of 1T per conductor for Single Zebra ACSR

conductor.

4.0

CONCLUSION :

The results are tabulated in the table kept below as Annexure-A.

Sag and tension values for all temperatures from 0

C to 85

C and nil wind condition are tabulated in the table kept

below as Annexure-1, 2 & 3 respectively.

The Sample calculation for different conditions are enclosed herewith.

It is seen that the vertical clearances adopted are adequate.

SAG TENSION CALCULATION AND STRINIGING CHART FOR 132KV BAY EXTENSION AT PURBO KANCHAN BARI

SUB-STATION (TRIPURA)

SUMMARY

PSC Engineers Pvt. Ltd.

Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

132 KV 21 mtrs. Single Zebra Transfer Bus-A

= Maximum Sag + Phase to Phase clearance

= 0.93 + 1.3

= 3.63

Clearance actually provided = Tower height - Equipment Height

= 8 - 4.6 = 7.3 Margin available = 3.67 Hence it is Safe. 132 KV 52.55 mtrs. Single Zebra Jack Bus

= Maximum Sag + Phase to Phase clearance

= 1.64 + 1.3

= #REF!

Clearance actually provided = Higher Tower Height - Lower Tower Height

= 12.0 - 8.0

= #REF!

Margin available = #REF!

Hence it is Safe.

132 KV 52.50 mtrs. Single Zebra Transfer Bus-B

= Maximum Sag + Phase to Phase clearance

= 1.64 + 1.3

= #REF!

Clearance actually provided = Tower height - Equipment Height

= 8 - 4.6

= #REF!

Margin available = #REF!

Hence it is Safe. 75o_{C NIL 96 2.33} ----FULL 293 ----#REF! 156 1.69 0oC NIL 459 0.65 36% 500 TEMP. OF

CONDUCTOR WIND LOAD TENSION (Kgf)

----32oC NIL NIL 36% TENSION (Kgf) ANNEXURE-A

SAG-TENSION TABLE FOR CONDUCTOR WITH DIFFERENT SPANS

FOLLOWING SAG VALUES HAVE BEEN CALCULATED AS PER IS-802 (PART-2), 1993 FOR 132KV BAY EXTENSION AT PURBO KANCHAN BARI SUB-STATION (TRIPURA)

under sag condition.

#REF! SPAN LENGTH

NIL

FULL SPAN LENGTH TEMP. OF

CONDUCTOR WIND LOAD

SAG (m)

Minimum Phase-Phase / Phase-Ground clearance require

SAG (m) #REF! 0oC #REF! ----#REF!

Minimum Phase-Phase / Phase-Ground clearance require

#REF!

#REF! #REF!

75o_{C NIL}

32oC

under sag condition.

SPAN LENGTH TEMP. OF

CONDUCTOR WIND LOAD TENSION (Kgf) SAG (m)

0oC

NIL #REF! #REF!

36% #REF!

----32o_C

NIL #REF! #REF!

FULL #REF!

----Minimum Phase-Phase / Phase-Ground clearance require under sag condition.

1.0 Basic wind speed

V

=

39

m/sec

2.0 Design wind speed

V

=

V

x K

x K

Where

K

=

Risk co-efficient

=

1

K

=

Terrain roughness coefficient which is

=

1

Factor to convert 3 second peak

gust speed into

average speed of wind during 10

minutes period

K

=

1.375

Meteorological reference wind

speed

V

=

V

/ K

m/sec

28.36

V

=

28.36

3.0 Design wind pressure

P

=

0.6 V

2

=

482.70

N/m

49.25

Kgf/m

5.0 Wind load on each conductor

F

=

P

x c

x L x D x G

(Cl. 9.2 of Ref IS)

Where,

L

=

Wind span i.e. the sum of half the spans on either side in mtrs

C

=

Drag coefficient

=

1

D

=

Dia. of conductor

=

0.03177

G

=

Gust Response factor

---

Refer Table: 7 of IS 802

Part 1 / Sec 1, 1995

=

2.12

For 8 m height

Therefore

F

=

32.51

N/m

For12 m height

=

3.31

Kg/m

For 12 m height

ANNEXURE-B

CALCULATION OF WIND EFFECTS (Ref. IS 802 Part 1/Sec 1 : 1995)

PSC Engineers Pvt. Ltd.

Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

21M SPAN (SINGLE ZEBRA ACSR)---132kV Transfer Bus-A General Perticulars :

1 Span Length = 17.00 m

2 Girder width = 1.50 m

3 Span length excluding girder width = 15.5 m

4 Spacer Span = 0.00 m

5 Length of Disc Insulator String (One side) (li) = 3.00 m

6 Total Length of Hardware (With Turn Bucckle + Without Turn Bucckle) = 0.05 m

7 Diameter of disc insulator string (di) = 0.05 m

8 Length of conductor = 9.45 m

9 Span length excluding girder width ,Hardware and string ( L) = 9.45 m

10 Initial Tension per conductor = 500.00 Kg

11 Dia of Conductor = 0.0318 m

12 Weight of Conductor = 2.0040 Kg/m

13 No. of Spacers = 0.0000

14 Unit Weight of spacer = 0.0000 Kg

15 Unit weight of single tension disc insulator string = 165.0000 Kg

16 Unit weight of single tension hardware with turnbuckle. = 1.0000 Kg

17 Unit weight of single tension hardware without turnbuckle = 1.0000 Kg

18 Unit weight of Disc Insulator with hardware (Wi) = 166 Kg

19 Length of Turnbuckle (lt) = 0.0500 m

20 Width of Turnbuckle (Bt) = 0.0220 m

21 Weight of turnbuckle (Wt) = 1.0000 Kg

22 Weight of conductor with spacers = 2.0040 Kg/m

23 100% wind load on conductor per phase (n х FWC)---- [Refer Annexure-B] = 3.3100 Kg/m

24 Area of cross section of conductor AREA = 5.97 Sq.cm

25 Modulus of Elasticity of conductor ES = 686000.0000 Kg/Sq.cm

26 Coefficient of Thermal expansion ET = 0.0000193 /o

C

27 Maximum temperature considered Tmax = 85 oC

28 Number of subconductors n = 1 29 Bus Height h = 11.9 m f2 2 x { f2 - [f1 - (q1 2 х δ2 х L2 х E / 24 х f1 2 ) - E α t] } = q2 2 _{х δ}2 _{х L}2

x E / 24 …… Refer T.N.E.B. Handbook f2 2 x { f2 - [f1 - (q1 2 х δ2 х L2 х E / 24 х f1 2 ) - E α t] }-(q2 2 х δ2 х L2 х E / 24) = ₀ ……. Eq-(I)

The Sag can be calculated from the following equation

-q1*δ*L

2 _{…… Eq-(II)}

n 8 f2 Where,

f1 = Initial stress in conductor at temperature t1 (kg/cm 2

)

f2 = Final stress in conductor at temperature t2 (kg/cm 2

)

q1 = Still wind loading factor

q2 = 36% Maximum wind loading factor

q3 = Maximum wind loading factor

δ = Weight Factor in kg/m/cm2

L = Span (m)

E = Modulus of Elasticity in kg/cm2

α = Co-efficient of linear expansion

D = Overall Diameter of conductor (m)

A = Cross sectional area of conductor (cm2)

P2 = Wind load on conductor 36% (kgf/m)

P3 = Wind load on conductor (max.) (kgf/m)

SAG TENSION CALCULATIONS ( 132KV Single Zebra ACSR Conductor )

1.0 The equation for finding stress (f2) in different air conditions and for different temperature ranges is as under

t1 = Initial temperature (o C)

t2 = Final temperature (oC)

T1 = Initial tension in conductor at temp t1 = f1 x A (kgf)

T2 = Final tension in conductor at temp t2 = f2 x A (kgf)

S1 = Sag at initial condition T1 (m)

S2 = Sag at final condition T2 (m)

W A

= 2.00 Kg/m

Cross sectional area A = 5.97 cm2

Therefore δ = 0.34 kg/m/cm2 2.2 Wind factors At 36% wind P2 = 1.19 Kg/m At Full wind P3 = 3.3100 Kg/m 2.3 Loading factors q1 = 1 = 1.16 = 1.93 2.4 Temperature factors

E α t32 = 423.6736 (Starting condition is assumed

at 32oC and 36% of full wind)

E α t85 = 1125.383

E α t0 = 0

Therefore from above formulas sag can be calculated as, Sag = WcL

2

n8T2 ………. Eq-(III)

Where "n" represents nos. of subconductor

Here Sag is calculated at 00C, 320C and 850C for Nil wind condition.

Reference condition is assumed as 00C and 36% of Full Wind,

So, Tension at reference condition is,

T1 = 500 kgf

And Stress in conductor at reference condition is ,

Refer S.No. 23 above =

At Still wind

At 36% wind q2 =

Weight factor δ

=

3.0 Calculation of Sag and Tension

At Full wind q3

Weight of conductor with accessories/Phase Wc

2.0 Parameters 2.1

PSC Engineers Pvt. Ltd.

Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

nT1 A

f1 = 83.7521 kg/cm2

3.1.1 For Nil wind condition

:-i. SAG DUE TO CONDUCTOR

Reference stress at 00C and 36% of full wind condition is,

f1 = 83.75 kg/cm2

Now, = 55.5022

Tension Factor at Nill wind = = 287622.7691

E α t32 = 423.6736

Stress (f2) is calculated as under, f2 3 -f2 2 [ f1-((L 2 х δ2 x E х q2 2 ) / (24 х f1 2 ))-(E α t32) ] = (L 2 δ2 E q1 2 ) / (24) ………. Eq-(I) f2 3 -f2 2 _{х [206.40 - 50.3251 - 434.8411] - 932927.6838 =} 0 f2 = 26.12 Kg/cm2 Tension T2 = 155.94 Kg

Sag at 320C and Nill Wind (Sc) = WcL 2

n8T2

= 0.14 m

ii SAG DUE TO INSULATOR

The parameters required are expressed as follows,

U1 = √(li2 + (di/2)2 ) = 3.00 m U2 = √((li/2)2 + (di/2)2 ) = 1.50 m δ = Tan-1 [(di/2)/li] = 0.01 radians β = Tan-1 [di/li] = 0.02 radians

TP1 = (Wc*L/2) * U1 * Cosδ + Wi * U2 * Cosβ - n * T2 * U1 * Sinδ = 273.51

TP2 = n * T2 * U1 * Cosδ * + Wc * (L/2) * U1 * Sinδ + Wi * U2 * Sinβ = 472.21

φ = Tan-1

(TP1 / TP2) = 0.525 radians

Sag due to insulator = Si = U1 * Sin(φ + δ) = 1.53 m

iii SAG DUE TO TURNBUCKLE

The parameters required are expressed as follows,

V1 = √(It2 + (Bt/2) 2 ) = 0.05 m V2 = √((It/2)2 + (Bt/2)2 ) = 0.03 m δ1 = Tan-1 [(Bt/2)/It] = 0.22 radians 3.1 At 32o C f1 = 2 1 2 2 2 2 * 24 * * * f q E L 

24

*

*

*

q

E

L



β1 = Tan-1

[Bt/It] = 0.41 radians

TP3 = (Wc*(L/2)+Wi) *V1*Cosδ1+Wt* V2*Cosβ1-n*T2*V1*Sinδ1 = 7.083

TP4 = n*T2*V1*Cosδ1*+(Wc*(L/2)+Wi)*V1*Sinδ1+Wt*V2*Sinβ1 = 7.92

φ1 = Tan-1

(TP3 / TP4) = 0.73 radians

Sag due to Turnbuckle = St = V1 * Sin(φ1 + δ1)/2 = 0.02 m

Total maximum sag of single moose conductor Sg = Sc+Si+St = 1.69 m

Reference stress at 00

C and 36% of full wind condition is,

f1 = 83.75 kg/cm2

Now, = 55.5022

Tension Factor at Full wind = = 1072286.9289

E α t32 = 423.6736

Stress (f2) is calculated as under, f2 3 -f2 2 [ f1-((L 2 _{х δ}2 _{x E х q} 2 2_{) / (24 х f} 1 2_{))-(E α t} 32) ] = (L 2 _δ2 E q3 2 ) / (24) ………. Eq-(I) f2 3 -f2 2 х [206.40 - 50.3251 - 434.8411] - 10276580.2456 = 0 f2 = 49.11 Kg/cm2 Tension T2 = 293.21 Kg

3.2.1 For Nil wind condition

:-i. SAG DUE TO CONDUCTOR

Reference stress at 00C and 36% of full wind condition is,

f1 = 83.75 kg/cm2

Now, = 55.5022

Tension Factor at Nill wind = = 287622.7691

E α t85 = 1125.3830

Stress (f2) is calculated as under, f2 3 -f2 2 [ f1-((L 2 _{х δ}2 _{x E х q} 2 2_{) / (24 х f} 1 2_{))-(E α t} 32) ] = (L 2 _δ2 E q1 2 ) / (24) ………. Eq-(I) f2 3 -f2 2 х [206.40 - 50.3251 - 1019.1587] - 932927.6838 = 0 f2 = 16.07 Kg/cm2

3.1.2 For full wind condition

:-3.2 At 85o C 2 1 2 2 2 2

*

24

*

*

*

f

q

E

L



24

*

*

*

q

E

L



*

24

*

*

*

f

q

E

L



24

*

*

*

_E

_q

L



Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

Tension T2 = 95.96 Kg

Sag at 850

C and Nill Wind (Sc) = WcL

2

n8T2

= 0.23 m

ii SAG DUE TO INSULATOR

The parameters required are expressed as follows,

U1 = √(li2 + (di/2)2 ) = 3.00 m U2 = √((li/2)2 + (di/2)2 ) = 1.50 m δ = Tan-1 [(di/2)/li] = 0.01 radians β = Tan-1 [di/li] = 0.02 radians

TP1 = (Wc*L/2) * U1 * Cosδ + Wi * U2 * Cosβ - n * T2 * U1 * Sinδ = 275.01

TP2 = n * T2 * U1 * Cosδ * + Wc * (L/2) * U1 * Sinδ + Wi * U2 * Sinβ = 292.27

φ = Tan-1

(TP1 / TP2) = 0.75 radians

Sag due to insulator = Si = U1 * Sin(φ + δ) = 2.07 m

iii SAG DUE TO TURNBUCKLE

The parameters required are expressed as follows,

V1 = √(It2 + (Bt/2) 2 ) = 0.05 m V2 = √((It/2)2 + (Bt/2)2 ) = 0.03 m δ1 = Tan-1 [(Bt/2)/It] = 0.22 radians β1 = Tan-1 [Bt/It] = 0.41 radians

TP3 = (Wc*(L/2)+Wi) *V1*Cosδ1+Wt* V2*Cosβ1-n*T2*V1*Sinδ1 = 7.743

TP4 = n*T2*V1*Cosδ1*+(Wc*(L/2)+Wi)*V1*Sinδ1+Wt*V2*Sinβ1 = 6.74

φ1 = Tan-1

(TP3 / TP4) = 0.85 radians

Sag due to Turnbuckle = St = V1 * Sin(φ1 + δ1)/2 = 0.02 m

Total maximum sag of single moose conductor Sg = Sc+Si+St = 2.33 m

3.3.1 For Nil wind condition

:-i. SAG DUE TO CONDUCTOR

Reference stress at 00

C and 36% of full wind condition is,

f1 = 83.75 kg/cm2

Now, = 55.5022

Tension Factor at Nill wind = = 287622.7691

3.3 At 0o C 2 1 2 2 2 2

*

24

*

*

*

f

q

E

L



24

*

*

*

q

E

L



E α t0 = 0.0000

Stress (f2) is calculated as under, f2 3 -f2 2 [ f1-((L 2 х δ2 x E х q3 2 ) / (24 х f1 2 ))-(E α t32) ] = (L 2 δ2 E q1 2 ) / (24) ………. Eq-(I) f2 3 -f2 2 х [206.40 - 50.3251 - (0)] - 932927.6838 = 0 f2 = 76.89 Kg/cm2 Tension T2 = 459.06 Kg

Sag at 00C and Nill Wind (Sc) = WcL 2

n8T2

= 0.05 m

ii SAG DUE TO INSULATOR

The parameters required are expressed as follows,

U1 = √(li2

+ (di/2)2) = 3.00 m

U2 = √((li/2)2 + (di/2)2

) = 1.50 m

δ = Tan-1 [(di/2)/li] = 0.01 radians

β = Tan-1

[di/li] = 0.02 radians

TP1 = (Wc*L/2) * U1 * Cosδ + Wi * U2 * Cosβ - n * T2 * U1 * Sinδ = 265.93

TP2 = n * T2 * U1 * Cosδ * + Wc * (L/2) * U1 * Sinδ + Wi * U2 * Sinβ = 1381.57

φ = Tan-1

(TP1 / TP2) = 0.19 radians

Sag due to insulator = Si = U1 * Sin(φ + δ) = 0.59 m

iii SAG DUE TO TURNBUCKLE

The parameters required are expressed as follows,

V1 = √(It2 + (Bt/2) 2 ) = 0.05 m V2 = √((It/2)2 + (Bt/2)2 ) = 0.03 m δ1 = Tan-1 [(Bt/2)/It] = 0.22 radians β1 = Tan-1 [Bt/It] = 0.41 radians

TP3 = (Wc*(L/2)+Wi) *V1*Cosδ1+Wt* V2*Cosβ1-n*T2*V1*Sinδ1 = 3.749

TP4 = n*T2*V1*Cosδ1*+(Wc*(L/2)+Wi)*V1*Sinδ1+Wt*V2*Sinβ1 = 24.89

φ1 = Tan-1 (TP3 / TP4) = 0.15 radians

Sag due to Turnbuckle = St = V1 * Sin(φ1 + δ1)/2 = 0.01 m

Total maximum sag of single moose conductor Sg = Sc+Si+St = 0.65 m

Reference stress at 00

C and 36% of full wind condition is,

f1 = 83.75 kg/cm2

Now, = 55.5022

For 36% wind condition :-3.1.2 2 1 2 2 2 2 * 24 * * * f q E L  PSC Engineers Pvt. Ltd.

Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

Tension Factor at 36% wind = = 389315.2442

E α t0 = 0

Stress (f2) is calculated as under, f2 3 -f2 2 [ f1-((L 2 _{х δ}2 _{x E х q} 2 2_{) / (24 х f} 1 2_{))-(E α t} 32) ] = (L 2 _δ2 E q2 2 ) / (24) ………. Eq-(I) f2 3 -f2 2 х [206.40 - 50.3251 - (0)] - 2143865.0558 = 0 f2 = 83.75 Kg/cm2 Tension T2 = 500.00 Kg 4.0

SPAN TEMP. OF WIND SAG

LENGTH CONDUC. LOAD IN MTRS.

220 KV 17 mtrs. Single Moose

Vertical Clearance:

Minimum Phase-Phase / Phase-Ground Clearance require under Sag = Minimum Phase to Phase Clearance + Maximum Sag

condition = 1.3 + 2.04

= 3.63 mtrs.

Clearance actually provided = Tower Height - Equipment Height

= 11.9 - 4.6

= 7.30 mtrs.

Margin available = 3.67 mtrs.

Hence its Safe.

2.33 5.0 Verification of Clearances :-85o C 32oC 0o C 156 1.69 NIL 96 NIL 459 0.65 FULL 293 ---NIL 36% 500

---The results are tabulated

below:-TENSION= STRESS (f2) X AREA

Kgf

24

*

*

*

q

E

L



Temp. Final Stress Tension at nil wind condition Sag due to conductor Sag due to insulator Sag due to turnbuckle Deg. C Equation f2 T2 Sc Si St 1 0 -559984.31 183.71 890.10 0.06 0.08 0.02 2 1 -499344.34 173.48 840.52 0.07 0.09 0.03 3 2 -444652.24 163.71 793.16 0.07 0.09 0.03 4 3 -395671.70 154.43 748.20 0.08 0.10 0.03 5 4 -352109.06 145.68 705.81 0.08 0.10 0.03 6 5 -313616.32 137.48 666.11 0.09 0.11 0.03 7 6 -279800.11 129.86 629.18 0.09 0.12 0.03 8 7 -250234.44 122.81 595.01 0.10 0.12 0.04 9 8 -224478.92 116.32 563.56 0.10 0.13 0.04 10 9 -202095.11 110.37 534.72 0.11 0.14 0.04 11 10 -182662.01 104.93 508.36 0.11 0.14 0.04 12 11 -165787.90 99.96 484.31 0.12 0.15 0.04 13 12 -151117.77 95.44 462.39 0.12 0.16 0.05 14 13 -138336.42 91.31 442.40 0.13 0.16 0.05 15 14 -127169.18 87.55 424.17 0.14 0.17 0.05 16 15 -117379.49 84.11 407.52 0.14 0.18 0.05 17 16 -108765.52 80.97 392.28 0.15 0.18 0.05 18 17 -101156.23 78.08 378.31 0.15 0.19 0.06 19 18 -94407.25 75.43 365.47 0.16 0.20 0.06 20 19 -88396.80 72.99 353.65 0.16 0.20 0.06 21 20 -83022.49 70.74 342.73 0.17 0.21 0.06 22 21 -78197.96 68.65 332.62 0.17 0.22 0.06 23 22 -73850.34 66.72 323.24 0.18 0.22 0.07 24 23 -69917.99 64.92 314.52 0.18 0.23 0.07 25 24 -66348.57 63.24 306.38 0.19 0.23 0.07 26 25 -63097.58 61.67 298.78 0.19 0.24 0.07 27 26 -60127.03 60.20 291.67 0.20 0.25 0.07 28 27 -57404.36 58.82 284.99 0.20 0.25 0.07 29 28 -54901.57 57.52 278.70 0.21 0.26 0.08 30 29 -52594.52 56.30 272.78 0.21 0.26 0.08 31 30 -50462.25 55.15 267.20 0.22 0.27 0.08 32 31 -48486.61 54.06 261.92 0.22 0.27 0.08 33 32 -46651.74 53.03 256.91 0.22 0.28 0.08 34 33 -44943.75 52.05 252.16 0.23 0.28 0.08 35 34 -43350.48 51.12 247.65 0.23 0.29 0.08 36 35 -41861.20 50.23 243.36 0.24 0.29 0.09 37 36 -40466.42 49.39 239.27 0.24 0.30 0.09 38 37 -39157.74 48.58 235.37 0.24 0.30 0.09 39 38 -37927.71 47.81 231.65 0.25 0.31 0.09 40 39 -36769.68 47.08 228.08 0.25 0.31 0.09 41 40 -35677.69 46.37 224.67 0.26 0.32 0.09 42 41 -34646.43 45.70 221.40 0.26 0.32 0.09 0.67 0.63 0.64 0.65 0.66 0.59 0.60 0.61 0.62 0.55 0.56 0.57 0.58 0.50 0.52 0.53 0.54 0.45 0.47 0.48 0.49 0.40 0.41 0.43 0.44 0.34 0.36 0.37 0.39 0.28 0.30 0.31 0.33 0.23 0.24 0.26 0.27 0.18 0.19 0.20 0.22 Sg 0.17 Annexure-1

SAG AND TENSION VALUES FOR ALL TEMPERATURES FROM 00

C TO 850

C AND NIL WIND CONDITION 21 M SPAN (SINGLE ZEBRA ACSR)---132kV TRANSFER BUS-A

Sr. No.

Total max. sag of quad moose

conductor

PSC Engineers Pvt. Ltd.

Ex WSC Agreement Ref. C-62010-S219A-3/G7/CA-I/3476 Dt: 6.10.2010

Temp. Final Stress Tension at nil wind condition Sag due to conductor Sag due to insulator Sag due to turnbuckle Deg. C Equation f2 T2 Sc Si St Sg Sr. No.

Total max. sag of quad moose conductor 43 42 -33671.11 45.05 218.26 0.26 0.32 0.09 44 43 -32747.43 44.43 215.25 0.27 0.33 0.09 45 44 -31871.49 43.83 212.35 0.27 0.33 0.10 46 45 -31039.79 43.25 209.56 0.27 0.34 0.10 47 46 -30249.14 42.70 206.87 0.28 0.34 0.10 48 47 -29496.64 42.16 204.28 0.28 0.35 0.10 49 48 -28779.67 41.65 201.79 0.29 0.35 0.10 50 49 -28095.81 41.15 199.37 0.29 0.35 0.10 51 50 -27442.88 40.67 197.04 0.29 0.36 0.10 52 51 -26818.87 40.20 194.79 0.30 0.36 0.10 53 52 -26221.94 39.75 192.61 0.30 0.36 0.10 54 53 -25650.40 39.32 190.50 0.30 0.37 0.10 55 54 -25102.68 38.90 188.46 0.31 0.37 0.11 56 55 -24577.36 38.49 186.47 0.31 0.38 0.11 57 56 -24073.12 38.09 184.55 0.31 0.38 0.11 58 57 -23588.73 37.71 182.68 0.32 0.38 0.11 59 58 -23123.07 37.33 180.87 0.32 0.39 0.11 60 59 -22675.08 36.97 179.11 0.32 0.39 0.11 61 60 -22243.80 36.62 177.40 0.32 0.39 0.11 62 61 -21828.31 36.27 175.74 0.33 0.40 0.11 63 62 -21427.79 35.94 174.12 0.33 0.40 0.11 64 63 -21041.45 35.61 172.54 0.33 0.40 0.11 65 64 -20668.57 35.29 171.00 0.34 0.41 0.11 66 65 -20308.45 34.99 169.51 0.34 0.41 0.12 67 66 -19960.46 34.68 168.05 0.34 0.41 0.12 68 67 -19624.01 34.39 166.63 0.35 0.42 0.12 69 68 -19298.54 34.11 165.24 0.35 0.42 0.12 70 69 -18983.54 33.83 163.88 0.35 0.42 0.12 71 70 -18678.50 33.55 162.56 0.35 0.43 0.12 72 71 -18382.97 33.29 161.27 0.36 0.43 0.12 73 72 -18096.52 33.03 160.01 0.36 0.43 0.12 74 73 -17818.73 32.77 158.78 0.36 0.43 0.12 75 74 -17549.24 32.52 157.57 0.37 0.44 0.12 76 75 -17287.66 32.28 156.39 0.37 0.44 0.12 77 76 -17033.67 32.04 155.24 0.37 0.44 0.12 78 77 -16786.95 31.81 154.11 0.37 0.45 0.12 79 78 -16547.18 31.58 153.01 0.38 0.45 0.12 80 79 -16314.08 31.36 151.93 0.38 0.45 0.13 81 80 -16087.38 31.14 150.87 0.38 0.46 0.13 82 81 -15866.83 30.92 149.83 0.38 0.46 0.13 83 82 -15652.17 30.71 148.81 0.39 0.46 0.13 84 83 -15443.18 30.51 147.81 0.39 0.46 0.13 85 84 -15239.63 30.31 146.84 0.39 0.47 0.13 86 85 -15041.33 30.11 145.88 0.39 0.47 0.13 0.98 0.99 0.99 0.94 0.94 0.95 0.96 0.96 0.97 0.92 0.93 0.93 0.97 0.89 0.90 0.91 0.91 0.86 0.87 0.88 0.89 0.84 0.84 0.85 0.86 0.81 0.81 0.82 0.83 0.78 0.78 0.79 0.80 0.74 0.75 0.76 0.77 0.71 0.72 0.73 0.73 0.68 0.69 0.70