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R E S E A R C H

Open Access

On a more accurate half-discrete

Hardy-Hilbert-type inequality related to the

kernel of exponential function

Jianquan Liao

*

and Bicheng Yang

*Correspondence: [email protected]

Department of Mathematics, Guangdong University of Education, Guangzhou, Guangdong 51003, P.R. China

Abstract

By applying the weight functions, the technique of real analysis and

Hermite-Hadamard’s inequality, a half-discrete Hardy-Hilbert-type inequality related to the kernel of exponential function with the best possible constant factor expressed by the gamma function is given. The more accurate equivalent forms, the operator expressions with the norm, the reverses, and some particular cases are considered.

MSC: 26D15

Keywords: Hardy-Hilbert-type inequality; weight function; equivalent form; reverse; operator

1 Introduction

Suppose thatp> ,p+q= ,f(x),g(y)≥,fLp(R+),gLq(R+),f p= (

fp(x)dx)

p>

,gq> , and we have the following Hardy-Hilbert integral inequality (cf.[]):

f(x)g(y) x+y dx dy<

π

sin(π/p)fpgq, ()

where the constant factor sin(ππ/p) is the best possible. Ifam,bn≥,a={am}∞m=∈lp,b=

{bn}∞n=∈lq,ap= (

m=a p m)

p> ,b

q> , then we have the following discrete analogy

of () with the same best possible constantsin(ππ/p)(cf.[]):

m=

n= ambn m+n<

π

sin(π/p)apbq. ()

Inequalities () and () are important in analysis and its applications (cf.[–]). Ifμi,υj>  (i,jN={, , . . .}),

Um:= m

i=

μi, Vn:= n

j=

νj(m,nN), ()

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then we have the following Hardy-Hilbert-type inequality (cf.[], Theorem , replacing

μ/mqamandυn/pbnbyamandbn):

m=

n= ambn Um+Vn

< π

sin(π

p)

m= apm

μpm–

p

n= bqn

νnq–

q

. ()

Forμi=υj=  (i,jN), inequality () reduces to ().

Note The authors of [] did not prove that () is valid with the best possible constant factor.

In , by introducing an independent parameterλ∈(, ], Yang [] gave an extension of () with the kernel (x+y)λ forp=q= . Following [], Yang [] gave some extensions of () and () as follows:

Ifλ,λ∈R,λ+λ=λ,(x,y) is a non-negative homogeneous function of degree –λ,

withk(λ) =(t, )tλ–dtR+,φ(x) =xp(–λ)–,ψ(x) =xq(–λ)–,f(x),g(y)≥,

fLp,φ(R+) =

f;fp,φ:=

φ(x)f(x)pdx

p

<∞

,

gLq,ψ(R+),fp,φ,gq,ψ> , then we have

(x,y)f(x)g(y)dx dy<k(λ)fp,φgq,ψ, ()

where the constant factork(λ) is the best possible. Moreover, if (x,y) keeps a finite

value and(x,y)xλ–(kλ(x,y)yλ–) is decreasing with respect tox>  (y> ), then, for

am,bn≥,

alp,φ=

a;ap,φ:=

n=

φ(n)|an|p

p

<∞

,

b={bn}∞n=∈lq,ψ,ap,φ,bq,ψ> , we have

m=

n=

(m,n)ambn<k(λ)ap,φbq,ψ, ()

where the constant factork(λ) is still the best possible.

In , by adding some conditions, Yang [] gave an extension of () as follows:

m=

n=

ambn (Um+Vn)λ

<B(λ,λ)

m=

Up(–λ)– m apm

μpm–

p

n=

Vq(–λ)– n bqn

νnq–

q

, ()

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Some other results including multidimensional Hilbert-type inequalities are provided by [–].

About the topic of half-discrete Hilbert-type inequalities with the non-homogeneous kernels, Hardyet al.provided a few results in Theorem  of []. But they did not prove that the constant factors are the best possible. However, Yang [] gave a result with the kernel (+nx)λ by introducing a variable and proved that the constant factor is the best possible. In  Yang [] gave the following half-discrete Hardy-Hilbert inequality with the best possible constant factorB(λ,λ):

f(x)

n= an (x+n)λ

dx<B(λ,λ)fp,φaq,ψ, ()

whereλ> ,  <λ≤,λ+λ=λ. Zhonget al.([, , ]) investigated several half-discrete Hilbert-type inequalities with particular kernels. Applying weight functions, a half-discrete Hilbert-type inequality with a general homogeneous kernel of degree –λR

and a best constant factork(λ) are obtained as follows:

f(x)

n=

(x,n)andx<k(λ)fp,φaq,ψ, ()

which is an extension of () (cf.[]). At the same time, a half-discrete Hilbert-type in-equality with a general non-homogeneous kernel and a best constant factor are given by Yang []. In -, Yanget al.published three books [, ] and [] concerned with building the theory of half-discrete Hilbert-type inequalities.

In this paper, by applying weight functions, the technique of real analysis, and Hermite-Hadamard’s inequality, a half-discrete Hardy-Hilbert-type inequality related to the ker-nel of exponential function with a best possible constant factor expressed by the gamma function is given, which is similar to () and an extension of () in the following particular kernel:

k(x,n) =

(nx)γ (α> ,  <γ≤).

Furthermore, the more accurate equivalent forms, the operator expressions with the norm, the reverses, and some particular cases are considered.

2 An example and some lemmas

In the following, we agree thatνn> , ≤τnνn (n∈N),Vn=

n

i=νi,μ(t) is a positive continuous function in R+= (,∞),

U() := ; U(x) :=

x

μ(t)dt<∞ x∈(,∞),

ν(t) :=νn,t∈(n–,n+] (n∈N), and

V

:= ; V(y) :=

y

 

ν(t)dt y∈  ,∞

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p= , , p +q = ,δ∈ {–, },f(x),an≥ (x∈R+,nN),fp,δ= (

δ(x)fp(x)dx)

p,

aq,= ( ∞

n=(n)b q n)

q, where

δ(x) :=U

p(–δσ)–(x)

μp–(x) (x∈R+), (n) :=

(Vnτn)q(–σ)–

νnq–

(n∈N).

Example  Forα> ,  <γ,σ≤, we seth(t) =

eαtγ (t∈R+).

(i) Settingu=αtγ, we find

k(σ) :=

– eαtγ dt=

γ ασ/γ

euuσγ–du=(σ/γ)

γ ασ/γR+, ()

where

(y) :=

evvy–dv (y> )

is called the gamma function (cf.[]).

(ii) We obtain, fort> ,α> ,  <γ ≤,h(t) =

eαtγ > ,h(t) = –αγtγ– 

eαtγ <  and

h(t) = –αγ(γ – )tγ–  eαtγ +

αγtγ–  eαtγ > .

(iii) Ifg(u) > ,g(u) < ,g(u) > , then we find that, fory∈(n–,n+),g(V(y)) > , d

dyg(V(y)) =g(V(y))νn< , and d

dyg

V(y)=gV(y)νn>  (n∈N);

For g(u) > , g(u) < , g(u) > , g(u) > , g(u)≤, g(u)≥ (u> ), we obtain g(u)g(u) > , (g(u)g(u))=g(u)g(u) +g(u)g(u) < , and

g(u)g(u)=g(u)g(u) + g(u)g(u) +g(u)g(u) >  (u> ). (iv) Forα> ,  <γ,σ≤,c> , we haveh(cV(y))Vσ–(y) > , d

dy(h(cV(y))V

σ–(y)) < ,

and

ddy

hcV(y)Vσ–(y)>  yn–  ,n+

 

,nN

.

Then by Hermite-Hadamard’s inequality (cf.[]), we have

hcV(n)–(n) <

n+

n–

hcV(y)–(y)dy (nN). ()

Lemma  If g(t) (> )is a strictly decreasing continuous function in(

,∞),which is strictly convex satisfying∞

g(t)dtR+,then we have

g(t)dt<

n= g(n) <

 

(5)

Proof By Hermite-Hadamard’s inequality and the decreasing property, we have

n+

n

g(t)dt<

n+

n

g(n)dt=g(n) <

n+

n–

g(t)dt (n∈N), ()

and, forn∈N, it follows that

n+

g(t)dt< n

n= g(n) <

n

n=

n+

n–

g(t)dt=

n+

 

g(t)dt,

n+

g(t)dt

n=n+

g(n)

n+

g(t)dt<∞.

Hence, choosing plus for the above two inequalities, we have ().

Lemma  Ifα> ,  <γ,σ≤,define the following weight coefficients:

ωδ(σ,x) :=

n=

eαUδγ(x)(Vnτn)γ

Uδσ(x)ν

n (Vnτn)–σ

, xR+, ()

δ(σ,n) :=

eαUδγ(x)(Vnτn)γ

(Vnτn)σμ(x)

U–δσ(x) dx, nN. ()

Then we have the following inequalities:

ωδ(σ,x) <k(σ) (x∈R+), ()

δ(σ,n)k(σ) (n∈N), ()

where k(σ)is indicated by().

Proof SinceVnτn

n+

 

ν(t)dtνn

 =

n

ν(t)dt=V(n), and, fort∈(n–

 ,n+

 ),νn= V(t), by () (forc=(x)) and (), we have

eαUδγ(x)(Vnτn)γ

Uδσ(x)

(Vnτn)–σ

≤ 

eαUδγ(x)Vγ(n) Uδσ(x)

V–σ(n)

<

n+

n–eαUδγ(x)Vγ(t)

Uδσ(x)

V–σ(t)dt (n∈N),

ωδ(σ,x) <

n=

νn

n+

n–eαUδγ(x)Vγ(t)

Uδσ(x)

V–σ(t)dt

=

n=

n+

n–

eαUδγ(x)Vγ(t)

Uδσ(x)V(t)

V–σ(t) dt

=

 

eαUδγ(x)Vγ(t)

Uδσ(x)V(t)

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Settingu=(x)V(t), by (), we find

ωδ(σ,x) <

(x)V()

(x)V( )

eαuγ

Uδσ(x)Uδ(x)

(uU–δ(x))–σ du

≤ ∞

  eαuγu

σ–du=k(σ).

Hence, () follows.

Settingu= (Vnτn)Uδ(x) in (), we finddu=δ(Vnτn)Uδ–(x)μ(x)dxand

δ(σ,n) =

δ

(Vnτn)(∞)

(Vnτn)()

eαuγu

σ–du.

Ifδ= , then

(σ,n) =

(Vnτn)U(∞)

eαuγu

σ–du

  eαuγu

σ–du;

ifδ= –, then

–(σ,n) = –

(Vnτn)U–(∞)

eαuγu

σ–du

  eαuγu

σ–du.

Hence, by (), we have ().

Remark  (i) We do not need the condition ofσ≤ in obtaining (). (ii) IfU(∞) =∞,

then we have

δ(σ,n) =k(σ) (n∈N). ()

For example, we setμ(t) =(+t)a(t> ; ≤a≤), then forx≥, we find

U(x) =

x

dt ( +t)a =

(+x)–a–

–a , ≤a< ,

ln( +x), a=  <∞,

U() = , andU(∞) =(+dtt)a=∞.

Lemma  Ifα> ,  <γ,σ≤,there exists nN,such that{νn}∞n=nis decreasing and

V(∞) =∞,then: (i)for xR+,we have

k(σ) –θδ(σ,x)<ωδ(σ,x), ()

where

θδ(σ,x) :=

k(σ)

(x)V(n

+)

– eαuγ du=O

(7)

(ii)for any b> ,we have

n=

νn (Vnτn)+b

= b

νb +bO()

. ()

Proof SinceVnτnVnVn+–νn+ =V(n+ ), andνnV(t) (t∈(n,n+ );nn), by (), we find

ωδ(σ,x)

n=n

eαUδγ(x)Vγ(n+)

Uδσ(x)ν

n+ V–σ(n+ )

=

n=n+

eαUδγ(x)Vγ(n)

Uδσ(x)ν

n V–σ(n)

>

n=n+

n+

n

eαUδγ(x)Vγ(t)

Uδσ(x)V(t)

V–σ(t) dt

=

n+

eαUδγ(x)Vγ(t)

Uδσ(x)V(t)

V–σ(t) dt.

Settingu=(x)V(t), in view ofV() =, by (), we find

ωδ(σ,x) >

(x)V(n

+)

–

eαuγ du=k(σ) –

(x)V(n+)

–

eαuγ du=k(σ)

 –θδ(σ,x).

We find

 <θδ(σ,x)≤  k(σ)

(x)V(n

+)

–du=(U

δ(x)V(n+ ))σ

σk(σ) (x∈R+),

and then () follows. Forb> , we find

n=

νn (Vnτn)+b

n=

νn V+b(n)=

νV+b()+

n=

νn V+b(n)

< +b

νb +

n=

n+

n–

V(x)dx V+b(x) =

+b

νb +

 

V(x)dx V+b(x)

= +b

νb + νb

b =

b

νb +b

+b

νb , ∞ n= νn (Vnτn)+b

n=n

νn (Vnτn)+b

n=n

νn+ V+b(n+ )

=

n=n+

νn V+b(n)>

n=n+

n+

n

V(x)dx V+b(x) =

n+

V(x)dx V+b(x)

= 

bVb(n+ )=  b

νb

+bVb(n

+ ) –ν–b b

.

SinceVb(n+)–ν–b

(8)

Note For example,νn=na(n∈N; ≤a≤) satisfies the conditions of{νn}∞n=in Lemma  (forn= ).

3 Main results and operator expressions

Theorem  Ifα> ,  <γ,σ ≤,then for p> ,  <fp,δ,aq,<∞,we have the

following equivalent inequalities:

I:= ∞ n= ∞ 

anf(x)

eαUδγ(x)(Vnτn)γ dx<

(σ/γ)

γ ασ/γ fp,δaq,, ()

J:=

n=

νn (Vnτn)–

f(x)dx eαUδγ(x)(V

nτn)γ p

<(σ/γ)

γ ασ/γ fp,δ, ()

J:=

μ(x) U–qδσ(x)

n=

an eαUδγ(x)(V

nτn)γ q

dx

q

<(σ/γ)

γ ασ/γ aq,. ()

Proof By Hölder’s inequality with weight (cf.[]), we have

f(x) eαUδγ(x)(Vnτn)γ dx

p

=

eαUδγ(x)(Vnτn)γ

U–qδσ(x)f(x)

(Vnτn) –σ

p μq(x)

(Vnτn) –σ

p μq(x)

U–qδσ(x)

dx

p

≤ ∞

(Vnτn)γ eαUδγ(x)(Vnτn)γ

U

p(–δσ)

q (x)fp(x)

(Vnτn)–σμ

p q(x) dx × ∞ 

(Vnτn)γ eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(p–)μ(x)

U–δσ(x) dx

p–

= (δ(σ,n)) p–

(Vnτn)–νn

eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν nfp(x) (Vnτn)–σμp–(x)

dx. ()

In view of () and the Lebesgue term by term integration theorem (cf.[]), we find

J≤

k(σ)q n= ∞   eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx

p

=k(σ)q

∞  ∞ n=  eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx

p

=k(σ)

q

ωδ(σ,x)U

p(–δσ)–(x)

μp–(x) f p(x)dx

p

. ()

Then by (), we have ().

By Hölder’s inequality (cf.[]), we have

I = ∞ n= νp n

(Vnτn) 

pσ

f(x) eαUδγ(x)(Vnτn)γ dx

(Vnτn) 

pσa

n

νn/p

(9)

Then by (), we have (). On the other hand, assuming that () is valid, we set

an:=

νn (Vnτn)–

eαUδγ(x)(Vnτn)γf(x)dx

p–

, nN.

Then we findJp=aqq,. IfJ= , then () is trivially valid; ifJ=∞, then () remains impossible. Suppose that  <J<∞. By (), we have

aqq,=Jp=I<k(σ)fp,δaq,,

aqq–,=J<k(σ)fp,δ,

and then () follows, which is equivalent to ().

Still by Hölder’s inequality with weight (cf.[]), we have

n=

an eαUδγ(x)(Vnτn)γ

q

=

n=

eαUδγ(x)(Vnτn)γ ·

U–qδσ(x)ν

p

n

(Vnτn) –σ

p ·

(Vnτn) –σ

p a

n

U–qδσ(x)ν/p

n

q

n=

eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σ

q–

×

n=

eαUδγ(x)(V

nτn)γ

(Vnτn)

q(–σ)

p

U–δσ(x)νq–

n aqn

= (ωδ(σ,x)) q–

Uqδσ–(x)μ(x)

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x)

U–δσ(x)νq–

n

aqn. ()

Then by () and the Lebesgue term by term integration theorem (cf.[]), it follows that

J<

k(σ)p

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqndx

q

=k(σ)p

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqndx

q

=k(σ)p

n=

δ(σ,n)

(Vnτn)q(–σ)–

νnq– aqn

q

. ()

Then by (), we have ().

By Hölder’s inequality (cf.[]), we have

I =

Uq–δσ(x)

μq(x)

f(x)

μq(x)

Uq–δσ(x)

n=

eαUδγ(x)(Vnτn)γan

dx

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Then by (), we have (). On the other hand, assuming that () is valid, we set

f(x) := μ(x) U–qδσ(x)

n=

eαUδγ(x)(Vnτn)γan

q–

, xR+.

Then we findJq=fpp,δ. IfJ= , then () is trivially valid; ifJ=∞, then () keeps impossible. Suppose that  <J<∞. By (), we have

fpp,

δ=J

q

 =I<k(σ)fp,δaq,, f

p–

p,δ=J<k(σ)aq,,

and then () follows, which is equivalent to ().

Therefore, (), (), and () are equivalent.

Theorem  As regards the assumptions of Theorem ,if there exists n∈N, such that

{νn}∞n=nis decreasing and U(∞) =V(∞) =∞,then the constant factor k(σ) =

(σ/γ)

γ ασ/γ in (), (),and()is the best possible.

Proof Forε∈(,), we setσ=σεq(∈(, )), andf=f(x),xR+,a={an}∞n=,

f(x) =

(σ+ε)–(x)μ(x),  <xδ,

, > , ()

an= (Vnτn)σ–νn= (Vnτn)σ

ε

q–ν

n, nN. ()

Then forδ=±, sinceU(∞) =∞, we find

{x>;<}

μ(x) U–δε(x)dx=

εU δε

(). ()

By (), (), and (), we obtain

fp,δaq,=

{x>;<}

μ(x)dx U–δε(x)

p

n=

νn (Vnτn)+ε

q

=

εU

δε

p()νε

+εO()

q

, ()

I:=

n=

eαUδγ(x)(V

nτn)γan f(x)dx

=

{x>;<}

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)σ–νnμ(x) U–δ(σ+ε)(x) dx

=

{x>;<}

ωδ(σ,x) μ(x) U–δε(x)dx

k(σ)

{x>;<}

 –θδ(σ,x) μ(x)

U–δε(x)dx

=k(σ)

{x>;<}

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=k(σ)

{x>;<}

μ(x)dx U–δε(x)

{x>;<}

O μ(x)

U–δ(σ+εp)(x)

dx

=

εk σε

q

Uδε() –εO().

If there exists a positive constant Kk(σ), such that () is valid when replacing k(σ) to K, then in particular, by Lebesgue term by term integration theorem, we have

εI<εKfp,δaq,, namely,

k σε q

Uδε() –εO()<K·Uδεp()

νε+εO()

q

.

It follows thatk(σ)≤K(ε→+). Hence,K=k(σ) is the best possible constant factor of ().

The constant factork(σ) in () (()) is still the best possible. Otherwise, we would reach a contradiction by () (()) that the constant factor in () is not the best

possi-ble.

Forp> , we find–p(n) = νn

(Vnτn)– (n∈N),

–q

δ (x) = μ(x)

U–qδσ(x)(x∈R+), and we define the following real normed spaces:

Lp,δ(R+) =

f;f=f(x),xR+,fp,δ<∞

,

lq,=

a;a={an}∞n=,aq,<∞

,

Lq,–q

δ (R+) =

h;h=h(x),xR+,hq,–q

δ <∞

,

lp,–p=

c;c={cn}∞n=,cp,–p<∞

.

Assuming thatfLp,δ(R+), setting

c={cn}∞n=, cn:=

eαUδγ(x)(Vnτn)γf(x)dx, nN,

we can rewrite () ascp,–p<k(σ)fp,δ<∞, namely,clp,–p.

Definition  Define a half-discrete Hardy-Hilbert-type operatorT:Lp,δ(R+)lp,–p

as follows: For any fLp,δ(R+), there exists a unique representationTf =clp,–p.

Define the formal inner product ofTf anda={an}∞n=∈lq,as follows:

(Tf,a) :=

n=

eαUδγ(x)(Vnτn)γf(x)dx

an. ()

Then we can rewrite () and () as follows:

(Tf,a) <k(σ)fp,δaq,, ()

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Define the norm of operatorTas follows:

T:= sup f(=θ)∈Lp,δ(R+)

Tfp,–p fp,δ

.

Then by (), it follows thatTk(σ). Since, by Theorem , the constant factor in () is the best possible, we have

T=k(σ) =(σ/γ)

γ ασ/γ . ()

Assuming thata={an}n∞=∈lq,, setting

h(x) :=

n=

eαUδγ(x)(Vnτn)γan, xR+,

we can rewrite () ashq,–q

δ <k(

σ)aq,<∞, namely,hLq,–δq(R+).

Definition  Define a half-discrete Hardy-Hilbert-type operatorT:lq,Lq,–δq(R+)

as follows: For any a={an}∞n= ∈lq,, there exists a unique representation Ta=h

Lq,–q

δ (R+). Define the formal inner product ofTaandfLp,δ(R+) as follows:

(Ta,f) :=

n=

eαUδγ(x)(Vnτn)γan

f(x)dx. ()

Then we can rewrite () and () as follows:

(Ta,f) <k(σ)fp,δaq,, ()

Taq,–q

δ

<k(σ)aq,. ()

Define the norm of operatorTas follows:

T:= sup

a(=θ)∈lq,

Taq,–q

δ

aq,

.

Then by (), we findTk(σ). Since, by Theorem , the constant factor in () is the best possible, we have

T=k(σ) =(σ/γ)

γ ασ/γ =T. ()

4 Some equivalent reverses In the following, we also set

δ(x) :=

 –θδ(σ,x)

Up(–δσ)–(x)

μp–(x) (x∈R+).

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Theorem  As regards the assumptions of Theorem,for p< ,  <fp,δ,aq,<∞,

we have the following equivalent inequalities with the best possible constant factor k(σ) =

(σ/γ)

γ ασ/γ :

I=

n=

anf(x)

eαUδγ(x)(Vnτn)γ dx>

(σ/γ)

γ ασ/γ fp,δaq,, ()

J=

n=

νn (Vnτn)–

f(x) eαUδγ(x)(Vnτn)γ dx

p

>(σ/γ)

γ ασ/γ fp,δ, ()

J=

μ(x) U–qδσ(x)

n=

an eαUδγ(x)(Vnτn)γ

q dx

q

>(σ/γ)

γ ασ/γ aq,. ()

Proof By the reverse Hölder inequality with weight (cf.[]), sincep< , in the similar way to obtaining () and (), we have

eαUδγ(x)(Vnτn)γf(x)dx

p

≤ (δ(σ,n))p–

(Vnτn)–νn

eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx.

Then by () and the Lebesgue term by term integration theorem, it follows that

J≥

k(σ)q

n=

eαUδγ(x)(V

nτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx

p

=k(σ)

q

ωδ(σ,x)

Up(–δσ)–(x)

μp–(x) f p(x)dx

p

.

Then by (), we have ().

By the reverse Hölder inequality (cf.[]), we have

I =

n=

ν

p

n

(Vnτn) 

pσ

f(x) eαUδγ(x)(Vnτn)γ dx

(Vnτn) 

pσa

n

νn/p

Jaq,. ()

Then by (), we have (). On the other hand, assuming that () is valid, we setanas in Theorem . Then we findJp=aqq,. IfJ=∞, then () is trivially valid; ifJ= , then () keeps impossible. Suppose that  <J<∞. By (), it follows that

aqq,=Jp=I>k(σ)fp,δaq,, a

q–

q,=J>k(σ)fp,δ,

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Still by the reverse Hölder’s inequality with weight (cf.[]), since  <q< , in the similar way to obtaining () and (), we have

n=

eαUδγ(x)(V

nτn)γan q

≥ (ωδ(σ,x))q–

Uqδσ–(x)μ(x)

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqn.

Then by () and the Lebesgue term by term integration theorem, it follows that

J>k(σ)

p

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqndx

q

=k(σ)

p

n=

δ(σ,n)(Vnτn) q(–σ)–

νnq– aqn

q

.

Then by (), we have ().

By the reverse Hölder inequality (cf.[]), we have

I =

Uq–δσ(x)

μq(x)

f(x)

μq(x)

Uq–δσ(x)

n=

an eαUδγ(x)(Vnτn)γ

dx

fp,δJ. ()

Then by (), we have (). On the other hand, assuming that () is valid, we setf(x) as in Theorem . Then we findJq=fpp,δ. IfJ=∞, then () is trivially valid; ifJ= , then () remains impossible. Suppose that  <J<∞. By (), it follows that

fpp,δ=J

q

 =I>k(σ)fp,δaq,, f

p–

p,δ=J>k(σ)aq,,

and then () follows, which is equivalent to ().

Therefore, inequalities (), (), and () are equivalent. Forε∈(,), we setσ=σε

q (∈(, )) andf=f(x),xR+,a={an}∞n=,

f(x) =

(σ+ε)–(x)μ(x),  <xδ,

, > ,

an= (Vnτn)σ–νn= (Vnτn)σ

ε

q–ν

n, nN.

By (), (), and (), we obtain

fp,δaq,=

εU

δε

p()

νε+εO()

q

,

I=

n=

anf(x) eαUδγ(x)(V

nτn)γ dx=

{x>;<}

ωδ(σ,x) μ(x) U–δε(x)dx

k(σ)

{x>;<}

μ(x) U–δε(x)dx=

εk σε

q

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If there exists a positive constantKk(σ), such that () is valid when replacingk(σ) toK, then in particular, we haveεI>εKfp,δaq,, namely,

k σε q

Uδε() >K·Uδεp()νε

+εO()

q

.

It follows thatk(σ)≥K(ε→+). Hence,K=k(σ) is the best possible constant factor of ().

The constant factork(σ) in () (()) is still the best possible. Otherwise, we would reach a contradiction by () (()) that the constant factor in () is not the best

possi-ble.

Theorem  As regards the assumptions of Theorem,if <p< ,  <fp,δ,aq,<∞,

then we have the following equivalent inequalities with the best possible constant factor k(σ) = γ α(σσ//γγ):

I=

n=

anf(x)

eαUδγ(x)(Vnτn)γ dx>

(σ/γ)

γ ασ/γ fp,δaq,, ()

J=

n=

νn (Vnτn)–

f(x)dx eαUδγ(x)(Vnτn)γ

p

>(σ/γ)

γ ασ/γ fp,δ, ()

J:=

( –θδ(σ,x))–qμ(x) U–qδσ(x)

n=

an eαUδγ(x)(Vnτn)γ

q dx

q

>(σ/γ)

γ ασ/γ aq,. ()

Proof By the reverse Hölder inequality with weight (cf.[]), since  <p< , in a similar way to obtaining () and (), we have

f(x) eαUδγ(x)(Vnτn)γ dx

p

≥ (δ(σ,n))p–

(Vnτn)–νn

eαUδγ(x)(V

nτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx.

In view of () and the Lebesgue term by term integration theorem, we find

Jk(σ)

q

n=

eαUδγ(x)(Vnτn)γ

U(–δσ)(p–)(x)ν n (Vnτn)–σμp–(x)

fp(x)dx

p

=k(σ)

q

ωδ(σ,x)U

p(–δσ)–(x)

μp–(x) f p(x)dx

p

.

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By the reverse Hölder inequality (cf.[]), we have

I =

n=

νn/p

(Vnτn) 

pσ

f(x) eαUδγ(x)(V

nτn)γ dx

(Vnτn) 

pσa

n

νn/p

Jaq,. ()

Then by (), we have (). On the other hand, assuming that () is valid, we setanas in Theorem . Then we findJp=aqq,. IfJ=∞, then () is trivially valid; ifJ= , then () remains impossible. Suppose that  <J<∞. By (), it follows that

aqq,=Jp=I>k(σ)fp,δaq,, a

q–

q,=J>k(σ)fp,δ,

and then () follows, which is equivalent to ().

Still by the reverse Hölder inequality with weight (cf.[]), sinceq< , we have

n=

an eαUδγ(x)(Vnτn)γ

q

≤ (ωδ(σ,x))q–

Uqδσ–(x)μ(x)

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqn.

Then by () and the Lebesgue term by term integration theorem, it follows that

J>k(σ)p

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)(–σ)(q–)μ(x) U–δσ(x)νq–

n

aqndx

q

=k(σ)

p

n=

δ(σ,n)

(Vnτn)q(–σ)–

νnq–

aqn

q

.

Then by (), we have ().

By the reverse Hölder inequality (cf.[]), we have

I =

 –θδ(σ,x)

pU

qδσ(x)

μq(x)

f(x)

×

( –θδ(σ,x))–pμq(x)

Uqδσ(x)

n=

an eαUδγ(x)(Vnτn)γ

dx

fp,δJ. ()

Then by (), we have (). On the other hand, assuming that () is valid, we setf(x) as in Theorem . Then we findJq=fpp,

δ. IfJ=∞, then () is trivially valid; ifJ= , then () keeps impossible. Suppose that  <J<∞. By (), it follows that

fp p,δ=J

q=I>k(σ)f

p,δaq,, f

p–

p,δ=J>k(σ)aq,,

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Therefore, inequalities (), (), and () are equivalent. Forε∈(,), we setσ=σ+εp andf =f(x),xR+,a={an}∞n=,

f(x) =

Uδσ–(x)μ(x),  <xδ,

, > ,

an= (Vnτn)σε–νn= (Vnτn)

σεq–

νn, nN.

By (), (), and (), we obtain

fp,δaq,

=

{x>;<}

 –OU(x)δσμ(x)dx U–δε(x)

p

n=

νn (Vnτn)+ε

q

=

ε

Uδε() –εO()

p

νε+εO()

q

,

I=

n=

eαUδγ(x)(V

nτn)γan f(x)dx

=

n=

{x>;<}eαUδγ(x)(Vnτn)γ

(Vnτn)σμ(x) U–δσ(x) dx

νn (Vnτn)+ε

n=

eαUδγ(x)(Vnτn)γ

(Vnτn)σμ(x) U–δσ(x) dx

νn (Vnβ)+ε

=

n=

δ(σ,n) νn (Vnτn)+ε

=k(σ)

n=

νn (Vnτn)+ε

=

εk σ+ ε

p

νε+εO()

.

If there exists a positive constantKk(σ), such that () is valid when replacingk(σ) toK, then, in particular, we haveεI>εKfp,δaq,, namely,

k σ+ε p

νε +εO()

>KUδε() –εO()

p

νε+εO()

q

.

It follows thatk(σ)≥K(ε→+). Hence,K=k(σ) is the best possible constant factor of ().

The constant factork(σ) in () (()) is still the best possible. Otherwise, we would reach the contradiction by () (()) that the constant factor in () is not the best

possi-ble.

5 Some corollaries and a remark

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Corollary  As regards the assumptions of Theorem, (i)for p> ,  <fp,,aq,<∞,

we have the following equivalent inequalities:

n=

anf(x) eαUδγ(x)(V

nτn)γ dx< (σ/γ)

γ ασ/γ fp,aq,, ()

n=

νn (Vnτn)–

f(x) eαUγ(x)(V

nτn)γ dx p

<(σ/γ)

γ ασ/γ fp,, ()

μ(x) U–(x)

n=

an eαUγ(x)(Vnτn)γ

q dx

q

<(σ/γ)

γ ασ/γ aq,; ()

(ii)for p< ,  <fp,,aq,<∞,we have the following equivalent inequalities:

n=

anf(x)

eαUγ(x)(Vnτn)γ dx>

(σ/γ)

γ ασ/γ fp,aq,, ()

n=

νn (Vnτn)–

f(x) eαUγ(x)(Vnτn)γ dx

p

>(σ/γ)

γ ασ/γ fp,, ()

μ(x) U–(x)

n=

an eαUγ(x)(Vnτn)γ

q dx

q

>(σ/γ)

γ ασ/γ aq,; ()

(iii)for <p< ,  <fp,,aq,<∞,we have the following equivalent inequalities:

n=

anf(x)

eαUγ(x)(Vnτn)γ dx>

(σ/γ)

γ ασ/γ fp,aq,, ()

n=

νn (Vnτn)–

f(x) eαUγ(x)(Vnτn)γ dx

p

>(σ/γ)

γ ασ/γ fp,, ()

( –θ(σ,x))–(x) U–(x)

n=

an eαUγ(x)(V

nτn)γ q

dx

q

>(σ/γ)

γ ασ/γ aq,. ()

The above inequalities are with the best possible constant factor γ α(σσ//γγ).

Forδ= – in Theorems -, we have the following inequalities with the homogeneous kernel of degree :

Corollary  As regards the assumptions of Theorem, (i)for p> ,  <fp,–,aq,< ∞,we have the following equivalent inequalities:

n=

anf(x)

(VnU–()n)γ

dx<(σ/γ)

γ ασ/γ fp,–aq,, ()

n=

νn (Vnτn)–

f(x)

(VnU–()n)γ

dx

p

<(σ/γ)

References

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