L E V E L - 1 (Objective)
1. If f(x) = 2sinx 3sin2x
x −
∫
where x ≠ 0 then Limitx→0
f′(x) has the value ;
(A) 0 (B) 1 (C) 2 (D) not defined
2. If 1 2 +
∫
sinx dx = A sin x 4 − 4 π then value of A is : (A) 2 2 (B) 2 (C) 1 2 (D) 4 2 3. If y =(
1+dxx2)
3 2∫
/ and y = 0 when x = 0, then value of y when x = 1 is :(A) 2 3 (B) 2 (C) 3 2 (D) 1 2 4. If cos cot tan 4x 1 x x + −
∫
dx = A cos 4x + B where A & B are constants, then :(A) A = -1/4 & B may have any value (B) A = - 1/8 & B may have any value
(C) A = -1/2 & B = -1/4 (D) none of these
5. dx
x 5+4
∫
cos = I tan-1 m tan x 2 + C then : (A) I = 2/3 (B) m = 3 (C) I = 1/3 (D) m = 2/3 6. Given (a > 0) , 1 xlogax∫
dx = loge a loge (loge x) is true for :(A) x > 1 (B) x > e (C) all x ∈ R (D) no real x .
7.
( )
cot−∫
1 e e x x dx is equal to : (A) 1 2 ln (e 2x + 1) - cot( )
−1 e e x x + x + c (B) 1 2 ln (e 2x + 1) + cot( )
−1 e e x x + x + c (C) 1 2 ln (e 2x + 1) - cot(
)
−1 e e x x - x + c (D) 1 2 ln (e 2x + 1) + cot( )
−1 e e x x - x + c 8. tan cot tan cot − − − − − +∫
11 11 x x x x dx is equal to : (A) 4 π x tan-1 x + 2 π ln (1 + x2) - x + c (B) 4 π x tan-1 x - 2 π ln (1 + x2) + x + c (C) 4 π x tan-1 x + 2 π ln (1 + x2) + x + c (D) 4 π x tan-1 x - 2 π ln (1 + x2) - x + cINDEFINITE
INTEGRATION
9. If
( )
x x x 4 2 2 1 1 + +∫
dx = A ln |x|+ B x1+ 2 + c , where c is the constant of integration then
(A) A = 1 ; B = -1 (B) A = -1 ; B = 1 (C) A = 1 ; B = 1 (D) A = -1 ; B = -1 10.
∫
l l n x x n x | | | | 1+ dx equals : (A) 2 3 1+ln x (ln | x | - 2) + c (B) 2 3 1+ ln x (ln | x |+ 2) + c (C) 1 3 1+ln x (ln | x | - 2) + c (D) 2 1+ln x (3 ln | x | - 2) + c 11. Antiderivative of sin sin 2 2 1 x x + w.r.t. x is : (A) x - 2 2 arctan(
2 tan x)
+ c (B) x - 1 2 arctan tan x 2 + c(C) x - 2 arctan
(
2 tan x)
+ c (D) x - 2 arctan tan x2
+ c
12.
∫
sin x . cos x . cos 2x . cos 4x . cos 8x . cos 16 x dx equals : (A) sin 16 1024 x + c (B) - cos 32 1024 x + c (C) cos 32 1096 x + c (D) - cos 32 1096 x + c 13. x x x 2 2 2 1 + +∫
cos cosec2 x dx is equal to :(A) cot x - cot -1 x + c (B) c - cot x + cot -1 x
(C) - tan -1 x - cos sec ec x x + c (D) - e n x l tan−1 - cot x + c
where 'c' is constant of integration .
14. 3 5 4 5 e e e e x x x x + − − −
∫
dx = Ax + B ln | 4e2x - 5 | + c then :(A) A = -1, B = -7/8; C = const. of integration (B) A = 1, B = 7/8; C = const. of integration (C) A = -1/8, B = 7/8 ; C = const. of integration (D) A = -1, B = 7/8; C = const. of integration 15. x x x − +
∫
11. 12 dx equals : (A) sin -1 1 x + x x 2 1 − (B) x x 2 1 − + cos -1 1 x + c (C) sec -1 x - x x 2 1 − + c (D) tan -1 x2+1 - x x 2 1 − + c 16. dx x−x∫
2 equals : (A) 2 sin -1x + c (B) sin -1 (2x - 1) + c (C) c - 2 cos -1 (2x - 1) (D) cos -1 2
17.
∫
2mx . 3nx dx when m, n ∈ N is equal to : (A) 2 3 2 3 mx nx m n n n + + l l + c (B) ( ) e m n n n m nl n nl x l l 2 3 2 3 + + + c (C)(
)
2 3 2 3 mx nx m n n . . l + c (D)( )
m n m n n n x x .2 .3 2 3 l + l + c 18. dx x x cos3 . sin2∫
equals : (A) 2 5 (tan x) 5/2 + 2 tan x + c (B) 2 5 (tan 2 x + 5) tan x + c (C) 2 5 (tan 2 x + 5) 2 tan x + c (D) none 19. If dx x x sin3 cos5∫
= a cot x + b tan3x + c where c is an arbitrary constant of integration then the values of ‘a’ and ‘b’ are respectively :(A) -2 & 2 3 (B) 2 & -2 3 (C) 2 & 2 3 (D) none 20. If
∫
eu . sin 2x dx can be found in terms of known functions of x then u can be :(A) x (B) sin x (C) cos x (D) cos 2x
21. cos cos sin sin 3 5 2 4 x x x x + +
∫
dx :(A) sinx - 6 tan-1 (sinx) + c (B) sin x - 2 sin-1 x + c
(C) sinx - 2 (sinx)-1 - 6 tan-1 (sin x) + c (D) sinx - 2 (sinx)-1 + 5 tan-1 (sinx) + c
22. ln x x x (tan ) sin cos
∫
dx equal : (A) 1 2 ln 2 (cot x) + c (B) 1 2 ln 2 (sec x) + c (C) 1 2 ln 2 (sinx secx) + c (D) 1 2 ln 2 (cos x cosecx) + c 23.∫
sec2 2 4 x− π dx equals : (A) c - 1 2 cot 2x+ 4 π (B) 1 2 tan 2x− 4 π + c (C) 12(tan 4x - sec 4x) + c (D) none
24. Primitive of
(
3 11)
4 4 2 x x x − + + w.r.t. x is : (A) x x4 + +x 1 + c (B) -x x4 + +x 1 + c (C) x x x + + + 1 1 4 + c (D) -x x x + + + 1 1 4 + c1.
∫
cos cos cos 5 4 1 2 3 x x x dx + − 2.∫
cos x . e x. x2 dx 3.∫
sin ( ) sin ( ) x a x a − + dx 4.∫
cot ( sin ) (sec ) x dx x x 1− +1 5.∫
cos cot cos cot . sec sec ec x x ec x x x x − + 1+ 2 dx 6.∫
d x x x sin +sec7.
∫
tan x . tan 2x . tan 3x dx 8.(
)
dx x x sin sin 2 +∫
α 9.∫
x x x x 2 2 ( sin + cos ) dx 10.∫
ln(
)
x x x cos cos sin + 2 2 dx 11. sin sin cos x x + x∫
dx 12.∫
e x x x x xsin . cos sin
cos 3 2 − dx 13.
∫
( d x ) a+ bcosx 2 (a > b) 14.∫
cos sin 2 x x dx 15. cot tan sin x x x − +∫
1 3 2 dx 16.(
5 41)
4 5 5 2 x x x x + + +∫
dx 17.(
x4dx−1)
2∫
18.∫
ex(
x)
x 2 2 1 1 + + ( ) dx 19.∫
x+ x2+ 2 dx 20.∫
x[
l n x(
)
x]
x 2 2 4 1 1 2 + + − ln dx 21.∫
l n x x (ln ) (ln ) + 1 2 dx 22.∫
( ) ( )
[
x−13d xx+2 5]
1 4/ 23.(
)
dx x3+3x2 +3x +1 x2 +2x−3∫
24.∫
( ) ( ) ax b dx x c x ax b 2 2 2 2 2 − − + 25.∫
e(
x)
x x x 2 1 1 2 2 − − − ( ) dx 26.∫
(
)
x x x 7 −10− 2 3 2/ dx 27.∫
(
)
x x x ln / 2 3 2 1 − dx 28.∫
1 1 3 − + x x dx x 29. 2 3 2 3 1 1 − + + −∫
xx xx dx 30.∫
(
x)
x x d x x + + + + 2 3 3 1 2 31. dx x3 (1+x)3∫
32.∫
2 2 2 − −x x x dx 33.∫
d x x x x ( −α) ( −α) ( −β) 34. Integrate 1 2 f′(x) w.r.t. x 4 , where f (x) = tan -1x + ln 1+x - ln 1−xL E V E L - 2 (Subjective)
LEVEL - 3
(Questions asked from previous Engineering Exams)1. Find the indefinite integral
∫
1 3 1 1 4[
1]
1 6 1 3 1 2 ( ) ( ) ( ) ( ) ( ) / / / / / x x l n x x x + + + + dx 2. Evaluate
∫
3 1 1 3 1 x x x + − + ( ) . ( ) dx . 3. Evaluate∫
f x x ( ) 3 1− dx ; where f(x) is a polynomial of second degree in x such that
f(0) = f(1) = 3 f(2) = - 3 .
4. Evaluate ,
∫
cos 2θ . ln cos sin cos sinθ θ
θ θ
+
− dθ .
5. Evaluate
∫
cos . sin cos . ( cos ) 2 4 1 2 4 2 x x x + x dx . 6. Integrate ,(
xx)
xx 3 2 2 3 2 1 1 + + + +∫
( ) dx .7. Let f(x) =
∫
ex (x - 1) (x - 2) dx then f decreases in the interval :(A) (-∞, 2) (B) (-2, -1) (C) (1, 2) (D) (2, ∞) 8. Evaluate ,
∫
sin -1 2 2 4 2 8 13 x x x + + + dx .1. b 2. d 3. d 4. b 5. a,b 6. b 7. c 8. d 9. c 10. a 11. a 12. b
LEVEL - 1 (Objective questions)
ANSWER KEY
13. b,c,d 14. d 15. c 16. a,b,d 17. b,c 18. b 19. a 20. c 21. c 22. a,c,d 23. a,b,c 24. b1. −(sinx+sin2x) 2 + c 2. 1 2 e x
[
(
x2)
x x 2 x]
1 1 − cos +( − ) . sin + c3. cos a . arc cos cos
cos x a
- sin a . ln
(
sinx + sin2x−sin2a)
+ c4. 1 2 ln tan x 2 + 1 4 sec² x 2 + tan x 2 + c 5. sin-1 1 2 2 2 sec x + c 6. 1 2 3 3 3 l n x x x x arc x x c + − − + + + + sin cos
sin cos tan (sin cos )
7. − − +
ln(sec )x 1 ln(sec x) ln(sec x)
2 2
1
3 3 + c
8. - 1
sinα ln
[
cotx+cotα+ cot x+ cot cotα x−]
2 2 1 + c 9. sin cos sin cos x x x x x x c − + + 10. cos sin 2xx - x - cotx . ln
(
e(
cosx+ cos2x)
)
+ c11. ln(1 + t) - 1 4 ln(1 + t 4) + 1 2 2 ln t t t t 2 2 2 1 2 1 − + + + - 1 2 tan -1 t2 + c where t = cot x 12. esinx (x - secx) + c 13. −
(
−)
+ +(
−)
− + b x a b a b x a a b arc a b a b x sin( cos ) / tan . tan
2 2 2 2 3 2 2 2+ c 14. - 1
(
)
2 2 2 1 2 1 1 2 2 2 ln x x l x x n x x cot cot cot cot cot cot − − + − + − + + c LEVEL - 2 (Subjective Questions)15. tan-1 2sin2 sin cos x x+ x + c 16. - x x x + + + 1 1 5 + c 17. 3 8 tan -1 x -
(
xx)
4 4 −1 - 3 16 ln x x − + 1 1 + c 18. e x x x − + 1 1+ c 19. 1 3(
x + x +)
2 3 2 2 / -(
)
2 2 2 1 2 x+ x + / + c 20.(
x)
x x x 2 2 3 2 1 1 9 2 3 1 1 + + − + . ln 21. xln (lnx) - x l n x + c 22. 4 3 1 2 1 4 x x c − + + / 23. x x x 2 2 2 3 8 1 + − + ( ) + 1 16 . cos -1 2 1 x+ + c 24. sin− + + 1 2 ax b cx k 25. ex 1 1 + − x x + c 26. 2 7 20 9 7 10 2 ( x ) x x c − − − + 27 arc x ln x x c sec − − + 2 1 28. ln u u u u c where u x x | | tan 2 4 2 1 2 3 1 1 3 1 2 3 1 1 − + + + + + = − + − 29. 8(
)
3 1 2 5 5 1 5 1 1 1 1 2 tan− + − sin− + − − − t n t t x x l + c where t = 1 1 + − x x 30. 2 3 arc 3 1 x x c tan ( + ) + 31. 15 5 2 4 1 2 2 x x x x + − + + 15 8 ln 1 1 1 1 + − + + x x + c 32. − − − + − + − − − − + 2 2 4 4 2 2 2 2 1 3 2 2 1 x x x n x x x x x l sin + c 33. α β−−2 . x−−βα + x c 34. - ln(1- x4)+c1. I = I1 + I2 + c , where ; I1 y y y y y y y y n y 8 7 6 5 4 3 2 12 8 8 7 28 6 56 5 70 4 56 3 28 2 8 1 = − + − + − + − + ; where y = x1/12 + 1
( )
I2 ez z e z z ez z z c 3 2 2 2 2 1 3 9 1 2 18 1 3 = − − − + − − + ; where z = ln (1 + x1/6) 2. 1 4 1 1 1 2 1 2 l nx x x x c + − − + − + ( ) 3. ln x x x 2 1 1 + + − + 23 arctan2x3+1 + c 4. (b) 1 2 (sin2θ) ln cos sin cos sin θ θ θ θ + − - 1 2 ln (sec2θ) + c 5. 2 ln (1+cos 2x) + 2 1+cos x2 - ln (1 + cos 2 2x) + c 6. 3 2 tan -1 x - 1 2 ln(1 + x) + 1 4 ln (1+x 2) + x x 1+ 2 + c 7. C 8. -3 2 2 2 3 2 2 3 1 2 4 8 13 1 2 x x x x + + − + + − tan log(
)
LEVEL - 3 (Questions asked from previous Engineering Exams)