Volume 30 No. 2 2017, 151-161
ISSN: 1311-1728 (printed version); ISSN: 1314-8060 (on-line version) doi:http://dx.doi.org/10.12732/ijam.v30i2.6
ON SOME TOPOLOGICAL PROPERTIES OF
GENERALIZED DIFFERENCE SEQUENCE SPACES DEFINED
G¨ulcan Atıci Turan Department of Mathematics
Fac. of Arts and Sciences Mu¸s Alparslan University
C block, Diyarbakır Road, 49250 – Mu¸s, TURKEY
Abstract: In this paper, we define new generalized difference sequence spaces
ℓMλ (∆m
v , u) and ℓλN(∆mv , u), where M= (Mk) and N = (Nk) are sequences of Orlicz functions such that Mk and Nk are mutually complementary for each
k. We also examine some topological properties and establish some inclusion relations between these spaces.
AMS Subject Classification: 46A45, 40A05
Key Words: difference sequence spaces, Orlicz function
1. Introduction
An Orlicz function is a function M : [0,∞)→[0,∞) which is continuous, non-decreasing and convex with M(0) = 0, M(x) >0 for x >0 and M(x) → ∞
asx→ ∞.
Lindenstrauss and Tzafriri [4] used the idea of Orlicz function to define the Orlicz sequence space
ℓM = (
x= (xk) :
∞
X
k=1 M
|xk|
ρ
<∞, for some ρ >0 )
which is a Banach space with the norm
kxk= inf (
ρ >0 :
∞
X
k=1 M
|xk|
ρ
≤1 )
.
It is well known that if M is a convex function and M(0) = 0, then M(λx)≤ λM(x) for allλwith 0≤λ≤1.
Any Orlicz functionMk always has the integral representation
Mk(x) = x Z
0
pk(t)dt,
wherepk, known as the kernel ofMk, is non-decreasing, is right continuous for
t >0,pk(0) = 0, pk(t)>0 for t >0 andpk(t)→ ∞ ast→ ∞. Given an Orlicz functionMk with kernel pk(t), define
qk(s) = sup{t:pk(t)≤s, s≥0}.
Thenqk(s) possesses the same properties aspk(t) and the function Nk, defined as
Nk(x) = x Z
0
qk(s)ds,
is an Orlicz function. The functions Mk and Nk are called mutually comple-mentary Orlicz functions [1].
The difference sequence spaces were introduced by Kızmaz [2] and the con-cept was generalized by Et and C¸ olak [7]. Later, Et and Esi [6] extended the difference sequence spaces to the sequence spaces
X(∆m
v ) ={x= (xk) : (∆mv xk)∈X}
forX=ℓ∞, corc0, wherev= (vk) be any fixed sequence of non-zero complex numbers and (∆m
v xk) = ∆mv−1xk−∆mv−1xk+1
, ∆m
v x= m P
i=0
(−1)i mi
vk+ixk+i for all k∈N.
The sequence spaces ∆mv (ℓ∞), ∆mv (c) and ∆mv (c0) are Banach spaces normed by
kxk∆= m X
i=1
|vixi|+k∆mv xk∞.
(i) Solid (or normal), if (αkxk) ∈ λ whenever (xk) ∈ λ for all sequences (αk) of scalars with |αk| ≤1.
(ii) Monotone, if provided λ contains the canonical preimages of all its stepspaces.
(iii) Perfect, ifλ=λαα, see [9].
Proposition 2. λis perfect⇒ λis normal⇒ λis monotone, see [9].
A Banach sequence space (λ, S) is called a BK-space, if the topology S
of λ is finer than the co-ordinatewise convergence topology, or equivalently, the projection maps Pi : λ → K, Pi(x) = xi, i ≥ 1 are continuous, where
K is the scalar field R (the set of all reals) or C (the complex plane). For x = (x1, ..., xn, ...) and n ∈ N (the set of natural numbers), we write the nth section ofx asx(n)= (x
1, ..., xn,0,0, ...). If{x(n)} tends tox in (λ, S) for each
x ∈ λ, we say that (λ, S) is an AK−space. The norm k.kλ generating the topology S of λis said to be monotone if kxkλ ≤ kykλ forx ={xi}, y ={yi}
∈λwith |xi| ≤ |yi|, for all i≥1, see [8].
Definition 3. Any two Orlicz functions M1 and M2 are said to be
equiv-alent, if there are positive constant α and β, and x0 such that M1(αx) ≤ M2(x)≤M1(β) for allx with 0≤x≤x0, see [9].
2. Main Results
Definition 4. Let Mk and Nk be mutually complementary functions for each k and letλ={λk} be a sequence of strictly positive real numbers. Then we define the following sequence spaces:
ℓMλ (∆m
v , u) ={x= (xk) : X
k≥1 ukMk
|∆m v xk|
λkρ
<∞, for someρ >0}
and
ℓλN(∆mv , u) ={x= (xk) : X
k≥1 ukNk
λk|∆mv xk|
ρ
<∞, for someρ >0}.
Theorem 5. Let M = (Mk) and N = (Nk) be two sequences of Orlicz functions. Then ℓMλ (∆m
v , u) and ℓλN(∆mv , u) are linear spaces over the field of
complex numbers.
Proof. Let x, y∈ℓMλ (∆m
v , u) and a, b∈C. Then there exist positive num-bersρ1 and ρ2 such that
X
k≥1 ukMk
|∆m v xk|
λkρ1
<∞
and
X
k≥1 ukMk
|∆m v yk|
λkρ2
<∞.
Define ρ3 = max (2|a|ρ1,2|b|ρ2). Since Mk are non-decreasing and convex functions and ∆m is linear, we have
X
k≥1 ukMk
|∆m
v (axk+byk)|
λkρ3
≤X
k≥1 ukMk
|∆m v xk|
λkρ1
+X
k≥1 ukMk
|∆m v yk|
λkρ2
<∞.
This proves that ℓMλ (∆m
v , u) is a linear space. The proof for ℓλN(∆mv , u) is similar.
The proofs of the following theorems are easy and thus omitted.
Theorem 6. The sequence spaceℓMλ (∆m
v , u)is a normed space with norm
kxk∆λ = m X
i=1
|xi|+ inf{ρ >0 : X
k≥1 ukMk
|∆m v xk|
λkρ
≤1}.
Theorem 7. The sequence space ℓλ
N(∆mv , u)is a normed space with norm
kxkλ∆= m X
i=1
|xi|+ inf{ρ >0 : X
k≥1 ukNk
λk|∆mvxk|
ρ
≤1}.
Theorem 8. The spaces ℓMλ (∆m
v , u),k.k∆λ
and ℓλ
N(∆mv , u),k.kλ∆
Theorem 9. The sequence spaces ℓMλ (∆m
v , u) equipped with the norm
k.k∆λ andℓλ
N(∆mv , u) equipped with the normk.kλ∆ areBK-spaces. Proof. The space ℓMλ (∆m
v , u),k.k∆λ
is a Banach space by Theorem 8. Now let
kxn−xk∆
λ →0
asn→ ∞. Then
|xn
k−xk| →0 asn→ ∞ for each k≤m and
inf{ρ >0 :X k≥1
ukMk
|∆m
v xnk−∆mv xk|
λkρ
≤1} →0
asn→ ∞for all k∈N. If ukMk
|∆m vx
n k−∆
m vxk|
λkkxk∆
λ
≤1, then |∆
m vx
n k−∆m
vxk|
λkkxk∆
λ
≤1
for all k. Therefore we also obtain
|∆mv xnk−∆mv xk| ≤λkkxn−xk∆λ . Since kxn−xk∆
λ →0, then |∆mv xkn−∆mv xk| →0 and m X i=0
(−1)i
m v
vk+i xnk+i−xk+i →0
asn→ ∞ for all k∈N. On the other hand, we may write
vk+m xnk+m−xk+m ≤ m X i=0
(−1)i
m v
vk+i xnk+i−xk+i + m 0
vk(xnk−xk) +... + m m−1
vk+m−1 xnk+m−1−xk+m−1
.
Then |xn
k−xk| → 0 as n → ∞ for all k ∈ N. Hence
ℓMλ (∆m
v , u),k.k∆λ
is a
BK-space.
The proof is similar for ℓλ
Theorem 10. Let M = (Mk) be a sequence of Orlicz functions. Then ℓMλ (∆m−1
v , u) ⊂ ℓMλ (∆mv , u). In general ℓMλ (∆iv, u) ⊂ ℓMλ (∆mv , u), for i = 1,2, ..., m−1.
Proof. Let x∈ℓMλ (∆m−1
v , u). Then X
k≥1 ukMk
∆m−1
v xk
λk2ρ
!
<∞.
Since Mk are non-decreasing and convex functions,
X
k≥1 ukMk
|∆m v xk|
λk2ρ
=X
k≥1 ukMk
∆mv−1xk−∆mv−1xk+1
λk2ρ
!
≤X
k≥1 ukMk
∆m−1
v xk
λkρ !
+X
k≥1 ukMk
∆m−1
v xk+1
λkρ !
<∞.
ThusℓMλ (∆m−1
v , u)⊂ℓMλ (∆mv , u). This completes the proof.
Theorem 11. Let N = (Nk) be a sequence of Orlicz functions. Then
ℓλ
N(∆mv−1, u) ⊂ ℓλN(∆mv , u). In general ℓλN(∆iv, u) ⊂ ℓNλ (∆mv , u), for i = 1,2, ..., m−1.
Proof. Letx∈ℓλ
N(∆mv−1, u). Then X
k≥1 ukNk
∆mv−1xk
λkρ !
<∞.
Since Nk are non-decreasing and convex functions
X
k≥1 ukNk
λk|∆mv xk| 2ρ
=X
k≥1 ukNk
λk
∆mv −1xk−∆mv−1xk+1 2ρ ! ≤X k≥1 ukNk
λk ∆m−1
v xk ρ ! +X k≥1 ukNk
λk ∆m−1
v xk+1
ρ
!
<∞.
Thusℓλ
N(∆mv−1, u)⊂ℓλN(∆mv , u). This completes the proof.
(i)ℓMλ (∆m
v , u)∩ℓTλ(∆mv , u)⊂ℓM+Tλ (∆mv , u),
(ii)If Mand T are equivalent, then ℓMλ (∆m
v , u) =ℓTλ(∆mv , u).
Proof. (i)Let x∈ℓMλ (∆m
v , u)∩ℓTλ(∆mv , u). Then X
k≥1 ukMk
|∆m v xk|
λkρ
<∞
and
X
k≥1 ukTk
|∆m v xk|
λkρ
<∞.
We have
(Mk+Tk)
|∆m v xk|
λkρ
≤
Mk
|∆m v xk|
λkρ
+
Tk
|∆m vxk|
λkρ
.
Applying P k≥1
and multiplyinguk both side of this inequality, we get,
X
k≥1
uk(Mk+Tk)
|∆m v xk|
λkρ
≤X
k≥1 ukMk
|∆m v xk|
λkρ
+X
k≥1 ukTk
|∆m v xk|
λkρ
.
This completes the proof.
(ii) The proof follows from Definition 3.
Theorem 13. LetN = (Nk)and T= (Tk) be any two sequence of Orlicz functions. Then we have:
(i)ℓλ
N(∆mv , u)∩ℓλT(∆mv , u)⊂ℓNλ +T(∆ m v , u),
(ii)If Mand T are equivalent, then ℓλ
N(∆mv , u) =ℓλT(∆mv , u).
Proof. (i)Let x∈ℓMλ (∆m
v , u)∩ℓTλ(∆mv , u). Then X
k≥1 ukNk
λk|∆mv xk|
ρ
<∞
and
X
k≥1 ukTk
λk|∆mv xk|
ρ
We have
(Nk+Tk)
λk|∆mv xk|
ρ
≤
Nk
λk|∆mv xk|
ρ
+
Tk
λk|∆mv xk|
ρ
.
Applying P k≥1
and multiplyinguk both side of this inequality, we get,
X
k≥1
uk(Nk+Tk)
λk|∆mv xk|
ρ
≤X
k≥1 ukNk
λk|∆mv xk|
ρ
+X
k≥1 ukTk
λk|∆mv xk|
ρ
.
This completes the proof.
(ii) The proof follows from Definition 3.
Theorem 14. Ifµis a normal sequence space containingλ, thenℓMλ (∆m v , u)
is a proper subspace ofµ. In addition, ifµis equipped with the monotone norm (quasi-norm) k.kµ, the inclusion map I :ℓMλ (∆m
v , u)→ µ(∆mv , u) is continuous
withkIk ≤ k{λk}kµ.
Proof. Letx∈ℓMλ (∆m
v , u). Since P
k≥1 ukMk
|∆m vxk|
λkρ
<∞ for someρ >0,
then there exists a constant K >0 such that |∆mvxk|
λkρ ≤K for all k∈
N. Since µ is a normal sequence space containing λ, we have (∆m
v xk) ∈ µ and so that
x∈µ(∆m
v ). Hence ℓMλ (∆mv , u)⊂µ(∆mv , u). Further, sinceMk(1) = 1 for all k∈N, then
X
k≥1 ukMk
|∆m v xk|
λkkxk∆λ !
≤1,
and so that
|∆mv xk| ≤λkkxk∆λ , for all k∈N. As k.kµ is monotone, kIxkµ = k(∆m
v xk)kµ ≤ k{λk}kµkxk
∆
λ and hence kIk ≤
k{λk}kµ.
Theorem 15. If η is a normal sequence space containing {λ1k} ≡ λ−1, then ℓλ
N(∆m) is a proper subspace of η. If the norm (quasi-norm) k.kη on η
is monotone, then the inclusion map J :ℓλ
N(∆mv , u) → η(∆mv , u) is continuous
withkJk ≤ {λ−1k }
The proof is similar to Theorem 10 and therefore we omit it.
3. Interrelationship between the Spaces ℓMλ (∆mv , u) and ℓλM(∆mv , u) If λk = 1 for all k ∈ N, then the sequence space ℓλM(∆mv , u) reduces to the sequence space
ℓM(∆mv, u) ={x= (xk) : X
k≥1 ukMk
| ∆m
v xk|
ρ
<∞, for someρ >0}.
Theorem 16. If λ = {λk} is a bounded sequence such that infλk >0,
thenℓλ
M(∆mv , u) =ℓMλ (∆vm, u) =ℓM(∆mv , u).
Proof. Let x∈ℓM(∆m
v , u). Then P
k≥1 ukMk
|∆m vxk|
ρ
<∞ for someρ >0. Since λ = {λk} is bounded, we can write a ≤ λk ≤ b for some b > a ≥ 0. Define ρ1 =ρb. Since Mk is increasing, it follows that P
k≥1 ukMk
λk|∆m vxk|
ρ1
≤
P
k≥1 ukMk
|∆m vxk|
ρ
<∞. HenceℓM(∆m
v , u)⊂ℓλM(∆mv , u). The other inclusion
ℓλ
M(∆mv , u)⊂ℓM(∆mv , u) follows from the inequality X
k≥1 ukMk
|∆m v xk|
ρ/a
≤X
k≥1 ukMk
λk|∆mv xk|
ρ
<∞.
Therefore, ℓλ
M(∆mv , u) =ℓM(∆mv , u). Similarly, one can prove ℓMλ (∆m
v , u) =ℓM(∆mv , u).
Theorem 17. If {λk} ∈ ℓ∞ with a = supk≥1λk ≥ 1 and {λ−1k } is
un-bounded, thenℓMλ (∆m
v , u)is properly contained inℓλM(∆mv, u)and the inclusion
mapT :ℓMλ (∆mv, u)→ℓλM(∆mv , u) is continuous with kTk ≤a2.
Proof. For any ρ >0 andρ′=ρa2, we have
X
k≥1 ukMk
λk|∆mv xk|
ρ′
≤X
k≥1 ukMk
|∆m v xk|
λkρ
<∞
We now show that the containment ℓMλ (∆m
v , u) ⊂ ℓλM(∆mv , u) is proper. From the unboundedness of the sequence {λ−1k }, choose a sequence {kn} of positive integers such thatλ−1kn ≥n. Define ∆
m
v x={∆mv xk}as follows: ∆mv xk =
1/n, k=kn, n= 1,2, ...
0, otherwise .
Then x∈ℓλ
M(∆mv , u); but x /∈ℓMλ (∆mv , u).
To prove the continuity of the inclusion mapT, let us first consider the case obtained fora= 1. For x∈ℓMλ (∆m
v ), we write
AMλ (∆mv , u) =
ρ >0 :X k≥1
Mk
|∆m v xk|
λkρ
≤1
and
BMλ (∆mv, u) =
ρ >0 :X k≥1
Mk
λk|∆mv xk|
ρ
≤1
.
Since Mk are increasing anda= 1, we getAMλ (∆vm, u)⊂BλM(∆mv , u). Hence
kxkλ∆= infBMλ (∆mv, u)≤infAMλ (∆mv , u) =kxk∆λ , (1)
i.e., kT(x)kλ∆≤ kxkλ∆. Thus T is continuous with kTk ≤1 =a2.
Ifa6= 1, defineβk = λak,k∈N. Thenβk ≤1 and from (1), it follows that
kxkβ∆≤ kxk∆β forx∈ℓMλ (∆mv , u). (2) Hence from (2)
kT(x)kλ∆=kxkλ∆≤a2kxk∆λ ,
i.e., T is continuous with kTk ≤a2. This completes the proof.
Theorem 18. If {λk} is unbounded with supk≥1λ−1k = d ≥ 1, λk > 0
for allk, thenℓλ
M(∆mv, u)is properly contained inℓMλ (∆mv , u) and the inclusion
mapU :ℓλ
M(∆mv , u)→ℓMλ (∆mv , u) is continuous with kUk ≤d2.
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