Volume 2008, Article ID 702715,8pages doi:10.1155/2008/702715
Research Article
On the Univalence Criterion of a General
Integral Operator
Daniel Breaz1and H. ¨Ozlem G ¨uney2
1Department of Mathematics, “1 Decembrie 1918” University, Alba Iulia 510009, Romania
2Department of Mathematics, Faculty of Science and Arts, University of Dicle, Diyarbakir 21280, Turkey
Correspondence should be addressed to Daniel Breaz,[email protected]
Received 12 March 2008; Accepted 16 May 2008
Recommended by Paolo Ricci
In this paper we considered an general integral operator and three classes of univalent functions for which the second order derivative is equal to zero. By imposing supplimentary conditions for these functions we proved some univalent conditions for the considered general operator. Also some interesting particullar results are presented.
Copyrightq2008 D. Breaz and H. ¨Ozlem G ¨uney. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
Let unit disk and letAdenote the class of functionsfof the form
fz za2z2a3z3· · · z∈ U, 1.1
which are analytic in the open diskUand satisfy the conditionsf0 f0−10. Consider
S {f ∈ A:fare univalent functions inU}.
LetA2be the subclass ofAconsisting of functions of the form
fz z
∞
k3
akzk. 1.2
LetTbe the univalent subclass ofAwhich satisfies
z
2fz
fz2 −1
LetT2be the subclass ofTfor whichf0 0. LetT2,μbe the subclass ofT2consisting
of functions of the form1.2which satisfy
z2fz
fz2 −1
≤μ z∈ U 1.4
for someμ0< μ≤1, and let us denoteT2,1≡ T2. Furthermore, for some realpwith 0< p≤2
we define a subclassSpofAconsisting of all functionsfzwhich satisfy
fzz≤p z∈ U. 1.5
In1, Singh has shown that iffz∈ Sp, thenfzsatisfies
z2fz
fz2 −1
≤p|z|2 z∈ U. 1.6
Ahlfors2and Becker3had obtained the following univalence criterion.
Theorem 1.1. Let cbe a complex number,|c| ≤ 1, c / −1. If fz z a2z2 · · · is a regular
function inUand
c|z|2
1− |z|2zf
z
fz
≤1 1.7
for allz∈ U, then the functionfis regular and univalent inU.
In4, Pescar had obtained the following theorem.
Theorem 1.2see4. Letβbe a complex number,Reβ >0,ca complex number,|c| ≤ 1, c / −1,
andhz za2z2· · · a regular function inU. If
c|z|2β
1− |z|2βzh
z
βhz
≤1 1.8
for allz∈ U, then the function
Fβz
β z
0
tβ−1htdt 1/β
z· · · 1.9
is regular and univalent inU.
Lemma 1.3the general Schwarz lemma5. Let the functionfzbe regular in the diskUR
{z∈C;|z|< R},with|fz|< Mfor fixedM. Iffzhas one zero with multiplicity order bigger than
mforz0, then
fz≤ M Rm|z|
m, z∈ UR. 1.10
In6, Seenivasagan and Breaz consider forfi∈ A2i1,2, . . . , nandα1, α2, . . . , αn, β∈
C, the integral operator
Fα1,α2,...,αn,βz
β
z
0
tβ−1 n
i1
fit
t 1/αi
dt 1/β
. 1.11
When αi αfor all i 1,2, . . . , n, Fα1,α2,...,αn,βzbecomes the integral operator Fα,βz
considered in7.
2. Main results
Theorem 2.1. LetM ≥ 1,let the functionsfi ∈ Sp, fori ∈ {1, . . . , n},satisfy the condition1.6, letαi, βbe complex numbers, letReβ≥ni11pM1/|αi|, and letcbe a complex number.
If
|c| ≤1−Re1 β
n
i1
1pM1
|αi| ,
fiz≤M, 2.1
for allz∈ U, then the functionsFα1,α2,...,αn,βdefined in1.11are in the classS.
Proof. Define a function
hz z
0
n
i1
fit
t 1/αi
dt, 2.2
then we haveh0 h0−10. Also, a simple computation yields
hz n
i1
fiz
z 1/αi
,
zhz hz
n
i1
1 αi
zfiz
fiz −1
.
2.3
From2.3, we have
zhhzz
≤n
i1
1
αizfiz fiz
1
n
i1
1
|αi|
z2fiz fi2z
fizz1
. 2.4
From the hypothesis, we have |fiz| ≤ Mz ∈ U, i 1,2, . . . , n, then by the general Schwarz lemma, we obtain that
We apply this result in inequality2.4, then we obtain
zhhzz
≤n
i1
1 αi
z2f
iz
fiz2 M1
≤n
i1
1 αi
z2f
iz
fiz2 −1
MM1
n
i1
1
αipM|z|2M1
< n
i1
1pM1 αi .
2.6
We have
c|z|2β
1− |z|2βzh
z
βhz
c|z|2β
1− |z|2β1 β
n
i1
1 αi
zfiz
fiz −1
≤ |c||1 β|·
n
i1
1
|αi|
z2f
iz f2
iz ·
|fiz|
|z| 1
.
2.7
We obtain
c|z|2β1− |z|2βzh
z
βhz
<|c||1 β|
n
i1
1pM1 αi
≤ |c|Re1 β
n
i1
1pM1 αi .
2.8
So, from2.1we have
c|z|2β1− |z|2βzh
z
βhz
≤1. 2.9
ApplyingTheorem 1.2, we obtain thatFα1,α2,...,αn,βis univalent.
Theorem 2.2. LetM ≥ 1,let the functionsfi ∈ Sp, fori ∈ {1, . . . , n}, satisfy the condition1.6, letα, βbe complex numbers, letReβ≥n1pM1/|α|, and letcbe a complex number.
If
|c| ≤1− Re1 β
np1M1
|α| ,
fiz≤M, 2.10
for allz∈ U, then the function
Fα,βz
β z
0
tβ−1 n
i1
fit
t 1/α
dt 1/β
2.11
Proof. InTheorem 2.1, we considerα1α2· · ·αnα.
Corollary 2.3. Let the functionsfi∈ Sp, fori∈ {1, . . . , n}, satisfy the condition1.6, letαi, β be complex numbers, letReβ≥ni1p2/|αi|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ n
i1
p2 αi ,
fiz≤1, 2.12
for allz∈ U, then the functionFα1,α2,...,αn,βdefined in1.11is in the classS.
Proof. InTheorem 2.1, we considerM 1.
Corollary 2.4. LetM ≥ 1, let the functionf ∈ Spsatisfy the condition1.6, letα, βbe complex numbers, letReβ≥1pM1/|α|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ
1pM1
|α| ,
fz≤M 2.13
for allz∈ U, then the function
Gα,βz
β z
0
tβ−1
ft t
1/α dt
1/β
2.14
is in the classS.
Proof. InTheorem 2.1, we considern1.
Corollary 2.5. Let the functionf ∈ Spsatisfy the condition1.6, letα, βbe complex numbers, let Reβ≥p2/|α|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ p2
|α| ,
|fz| ≤1
2.15
for allz∈ U, then the function
Gα,βz
β z
0
tβ−1
ft t
1/α dt
1/β
2.16
is in the classS.
Theorem 2.6. LetM≥1, let the functionsfi∈ T2,μi, fori∈ {1, . . . , n}, satisfy the condition1.4, let
αi, βbe complex numbers, letReβ≥ni11μiM1/|αi|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ n
i1
1μiM1 αi ,
fiz≤M 2.17
for allz∈ U, then the functionFα1,α2,...,αn,βdefined in1.11is in the classS.
Proof. Define a function
hz z
0
n
i1
fit
t 1/αi
dt, 2.18
then we haveh0 h0−10. Also a simple computation yields
hz n
i1
fiz
z 1/αi
,
zhz hz
n
i1
1 αi
zf
iz fiz −1
.
2.19
From2.19, we have
zhhzz
≤n
i1
1
αizfiz fiz
1
n
i1
1
αiz2fiz f2
iz
fizz1
. 2.20
From the hypothesis, we have |fiz| ≤ Mz ∈ U, i 1,2, . . . , n, then by the general Schwarz lemma, we obtain that
fiz≤M|z| z∈ U, i1,2, . . . , n. 2.21
From2.20, we obtain zhhzz
≤n
i1
1 αi
z2f
iz
fiz2 M1
≤n
i1
1 αi
z2f
iz
fiz2 −1
MM1
≤n
i1
1
αiμiMM1
n
i1
1μiM1 αi .
We have
c|z|2β1− |z|2βzh
z
βhz
c|z|2β1− |z|2β1 β
n
i1
1 αi
zf
iz fiz −
1
≤ |c||1 β|·
n
i1
1
αiz2fiz fi2z
·|fiz| |z| 1
.
2.23
We obtain
c|z|2β1− |z|2βzh
z
βhz
≤ |c||1 β|
n
i1
1μiM1 αi
≤ |c|Re1 β
n
i1
1μiM1 αi .
2.24
So, from2.17we have
c|z|2β1− |z|2βzh
z
βhz
≤1. 2.25
ApplyingTheorem 1.2, we obtain thatFα1,α2,...,αn,βis univalent.
Corollary 2.7. LetM ≥1, let the functionsfi ∈ T2,μi, fori ∈ {1, . . . , n}, satisfy the condition1.4, letα, βbe complex numbers, letReβ≥n1μiM1/|α|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ
n1μiM1
|α| ,
fiz≤M 2.26
for allz∈ U, then the function
Fα,βz
β z
0
tβ−1 n
i1
fit
t 1/α
dt 1/β
2.27
is in the classS.
Proof. InTheorem 2.6, we considerα1α2· · ·αnα.
Corollary 2.8. Let the functionsfi ∈ T2,μi, fori ∈ {1, . . . , n}, satisfy the condition1.4, letαi, β be complex numbers, letReβ≥ni1μi2/|αi|, and letcbe a complex number.
If
|c| ≤1− 1
Reβ n
i1
μi2 αi ,
fiz≤1 2.28
Proof. InTheorem 2.6, we considerM 1.
Corollary 2.9. LetM ≥ 1, let the function f ∈ T2,μ satisfy the condition1.4, letα, βbe complex
numbers, letReβ≥1μM1/|α|, and letcbe a complex number. If
|c| ≤1− 1
Reβ
1μM1
|α| ,
fz≤M 2.29
for allz∈ U, then the function
Gα,βz
β z
0
tβ−1
ft t
1/α dt
1/β
2.30
is in the classS.
Proof. InTheorem 2.6, we considern1.
Corollary 2.10. Let the functionf ∈ T2,μsatisfy the condition1.4, letα, βbe complex numbers, let
Reβ≥μ2/|α|, and letcbe a complex number. If
|c| ≤1− 1
Reβ μ2
|α| ,
fz≤1 2.31
for allz∈ U, then the function
Gα,βz
β z
0
tβ−1
ft t
1/α dt
1/β
2.32
is in the classS.
Proof. InCorollary 2.9, we considerM1.
Acknowledgment
D. Breaz was supported by the GAR 20/2007.
References
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