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A note on geometrically convex functions
Muhamet Emin Özdemir
1, Çetin Yildiz
1*and Mustafa Gürbüz
2*Correspondence: [email protected] 1Department of Mathematics, K. K. Education Faculty, Atatürk University, Campus, Erzurum, 25240, Turkey
Full list of author information is available at the end of the article
Abstract
In this paper, we establish several new inequalities for twice differentiable mappings that are connected with the celebrated Hermite-Hadamard integral inequality. MSC: Primary 26D15; secondary 26A51
Keywords: Hermite-Hadamard inequality; geometrically convex function; (
α
,m)-geometrically convex function1 Historical background and introduction
The following double inequality is well known in the literature as Hadamard’s inequality: Letf:I⊆R→Rbe a convex function defined on an intervalIof real numbers,a,b∈I
anda<b, we have
f
a+b
≤
b–a b
a
f(x)dx≤f(a) +f(b)
. (.)
Both inequalities hold in the reversed direction iff is concave.
It was first discovered by Hermite in in the Journal Mathesis (see []). Inequality (.) was nowhere mentioned in the mathematical literature until . Beckenbach, a leading expert on the theory of convex functions, wrote that inequality (.) was proven by Hadamard in (see []). In Mitrinovič found Hermite’s note in Mathesis. That is why, inequality (.) was known as the Hermite-Hadamard inequality.
A functionf : [a,b]⊂R→Ris said to be convex if wheneverx,y∈[a,b] andt∈[, ], the following inequality holds:
ftx+ ( –t)y≤tf(x) + ( –t)f(y).
We say thatf is concave if (–f) is convex. This definition has its origins in Jensen’s results from [] and has opened up the most extended, useful and multi-disciplinary domain of mathematics, namely, convex analysis. Convex curves and convex bodies have appeared in mathematical literature since antiquity and there are many important results related to them.
In [], Miheşan introduced the class of (α,m)-convex functions in the following way: The functionf : [,b]→Ris said to be (α,m)-convex, where (α,m)∈[, ], if for every
x,y∈[,b] andt∈[, ], we have
ftx+m( –t)y≤tαf(x) +m –tαf(y).
This class is usually denoted byKα
m(b).
In [], the concept of geometrically convex functions was introduced as follows.
Definition A functionf :I⊂R+→R+is said to be a geometrically convex function if
fxty–t≤f(x)tf(y)–t for allx,y∈Iandt∈[, ].
In [], the definition ofm- and (α,m)-geometric convexity was introduced as follows.
Definition Letf(x) be a positive function on [,b] andm∈(, ]. If
fxtym(–t)≤f(x)tf(y)m(–t)
holds for allx,y∈[,b] andt∈[, ], then we say that the functionf(x) ism-geometrically convex on [,b].
It is clear that when m= ,m-geometrically convex functions become geometrically convex functions.
Definition Letf(x) be a positive function on [,b] and (α,m)∈(, ]×(, ]. If
fxtym(–t)≤f(x)tαf(y)m(–tα)
holds for all x,y∈ [,b] and t∈ [, ], then we say that the function f(x) is (α,m )-geometrically convex on [,b].
Ifα=m= , the (α,m)-geometrically convex function becomes a geometrically convex function on [,b].
Lemma For x,y∈[,∞)and m,t∈(, ],if x<y and y≥,then
xtym(–t)≤tx+ ( –t)y. (.)
For some recent results connected with geometrically convex functions, see [–].
Definition Leta,b∈R,a,b= and|a| =|b|. Logarithmic mean for real numbers was introduced as follows:
L(a,b) = a–b ln|a|–ln|b|.
Theorem (see []) Let f,g: [a,b]→Rbe integrable functions,both increasing or both decreasing.Furthermore,let p: [a,b]→R+be an integrable function.Then
b
a
p(x)f(x)dx b
a
p(x)g(x)dx≤ b
a
p(x)dx b
a
p(x)f(x)g(x)dx. (.)
and so are the following special cases of(.):
b–a b
a
f(x)dx b
a
g(x)dx≤ b
a
f(x)g(x)dx
and
f(x)dx
g(x)dx≤
f(x)g(x)dx.
In order to prove our main results, we need the following lemma (see []).
Lemma Let f :I⊂R→Rbe a twice differentiable function on I◦,a,b∈I with a<b and f∈L[a,b].Then the following equality holds:
f(a) +f(b)
–
b–a b
a
f(x)dx=(b–a)
t( –t)fta+ ( –t)bdt.
In [], some inequalities of Hermite-Hadamard type for differentiable convex mappings were proven using the following lemma.
Lemma Let f :I⊂R→Rbe a twice differentiable function on I◦,a,b∈I◦with a<b.If f∈L[a,b],then
b–a b
a
f(x)dx–f
a+b
=(b–a)
m(t)fta+ ( –t)b+f( –t)a+tbdt,
where
m(t) = t
, t∈[, ),
( –t), t∈[ , ].
In this paper, we establish some integral inequalities of Hermite-Hadamard type related to geometrically convex functions and (α,m)-geometrically convex functions.
2 Results for geometrically convex functions
We will establish some new results connected with the right-hand side of (.).
Theorem Let f :I⊂R+→R+be a twice differentiable function on I◦,a,b∈I with a<b
and f∈L[a,b].If|f|qis geometrically convex and monotonically decreasing on[a,b]for
p> and t∈[, ],then we have
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)
––p√π ( +p) (+p)
p
Lf(a)q,f(b)qq, (.)
Proof From Lemma with the properties of modulus and using the Hölder inequality, we have
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)
t( –t)fta+ ( –t)bdt
≤(b–a)
t–tpdt
p
fta+ ( –t)bqdt
q
=(b–a)
––p√π ( +p) (
+p)
p
fta+ ( –t)bqdt
q
. (.)
We used the beta and gamma functions to evaluate the integral
t–tpdt=
tp( –t)pdt=β(p+ ,p+ ),
β(x,x) = –xβ
,x
and β(x,y) =(x)(y) (x+y).
Thus, we have
β(p+ ,p+ ) = –(p+)(
)(p+ )
(+p) , (.)
where() =√π.
Since|f|qis geometrically convex and monotonically decreasing on [a,b], we obtain
atb–t≤ta+ ( –t)b,
fta+ ( –t)bq≤fatb–tq.
Therefore, we have
I =
fta+ ( –t)bqdt
≤
fatb–tqdt
≤
f(a)tf(b)–tqdt
=Lf(a)q,f(b)q. (.)
By making use of inequalities (.) and (.) in (.), we obtain (.). This completes the
proof.
Theorem Let f :I⊂R+→R+be a twice differentiable function on I◦,a,b∈I with a<b
q≥and t∈[, ],then the following inequality holds:
f(a) +f(b)–
b–a b
a
f(x)dx≤(b–a)
p
f(b)·N(t,q),
where
N(t,q) =
t( –t) |
f(a)|
|f(b)| qt
dt
q .
Proof From Lemma and using the well-known power-mean inequality, we have
f(a) +f(b)
–
b–a b
a
f(x)dx
≤(b–a)
t( –t)fta+ ( –t)bdt
≤(b–a)
t( –t)dt
–q
t( –t)fta+ ( –t)bqdt
q
=(b–a)
–q
t( –t)fta+ ( –t)bqdt
q .
Since|f|qis geometrically convex and monotonically decreasing on [a,b], we have
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)
–q
t( –t)f(a)tf(b)–tqdt
q
=(b–a)
–q
f(b)
t( –t) |
f(a)|
|f(b)| qt
dt
q ,
which completes the proof.
Corollary In Theorem,since()p< ,for p> ,we have
f(a) +f(b)–
b–a b
a
f(x)dx≤(b–a)
f
(b)N(t,q).
Now, we will establish some new results connected with the left-hand side of (.).
Theorem Let f :I⊂R+→R+be a twice differentiable function on I◦,a,b∈I with a<b
and f∈L[a,b].If|f|qis geometrically convex and monotonically decreasing on [a,b]
and t∈[, ],then we have the following inequality:
b–a b a
f(x)dx–f
a+b
≤ (b–a)
(p+ )p
Lf(a)q,f(b)qq,
Proof From Lemma and using the well-known Hölder integral inequality, we get
b–aabf(x)dx–f
a+b
≤(b–a)
m(t)pdt
p
fta+ ( –t)bqdt
q
+
f( –t)a+tbqdt
q
.
Since|f|qis geometrically convex and monotonically decreasing on [a,b], we know that fort∈[, ],
fta+ ( –t)bq≤fatb–tq
≤f(a)tf(b)–tq.
Hence
b–a b a
f(x)dx–f
a+b
≤ (b–a)
(p+ )p
f(a)tf(b)–tqdt
q +
f(a)–tf(b)tqdt
q
= (b–a)
(p+ )p
Lf(a)q,f(b)q
q,
where we have used the fact that
m(t)pdt=
tpdt+
( –t)pdt= p(p+ ),
which completes the proof.
Corollary In Theorem,since
(p+)
p < ,for p> ,we have
b–a b a
f(x)dx–f
a+b
≤(b–a)
Lf(a)q,f(b)q
q.
Theorem Let f :I◦⊂R+→R+ be a twice differentiable function on I◦,a,b∈I with
a<b and f∈L[a,b].If|f|q is geometrically convex and monotonically decreasing on
[a,b]and q≥,then we have
b–a b a
f(x)dx–f
a+b
≤(b–a)
p
f(a)·A(t,q) +f(b)·B(t,q),
where
A(t,q) =
m(t)· |
f(b)|
|f(a)| qt
dt
q
, B(t,q) =
m(t)· |
f(a)|
|f(b)| qt
dt
Proof From Lemma and using the well-known power-mean inequality, we get
b–a b a
f(x)dx–f
a+b
≤(b–a)
m(t)dt
p
m(t)fta+ ( –t)bqdt
q
+
m(t)f( –t)a+tbqdt
q
.
Since|f|qis geometrically convex and monotonically decreasing on [a,b], we have
b–aabf(x)dx–f
a+b
≤(b–a)
()p
m(t)f(a)tf(b)–tqdt
q
+
m(t)f(a)–tf(b)tqdt
q
=(b–a)
()p
m(t)·
|f(b)|
|f(a)| qt
dt
q
+
m(t)·
|f(a)|
|f(b)| qt
dt
q
,
where we have used the fact that
m(t)dt=
tdt+
( –t)dt= ,
which completes the proof.
Corollary In Theorem,since()p< ,for p> ,we have the following inequality:
b–aabf(x)dx–f
a+b
≤(b–a)
f
(a)·A(t,q) +f(b)·B(t,q).
3 Results for(
α
,m)-geometrically convex functionsTheorem Let f : [,b]→R+ be a twice differentiable function, a∈[,b]and f∈
L[a,b].If|f|q is(α,m)-geometrically convex and monotonically decreasing on[a,b]for
b≥,p> , (α,m)∈(, ]and t∈(, ],we have
f(a) +f(b)–
b–a b
a
f(x)dx≤(b–a)
––p√π ( +p) (
+p)
p
f(b)mM(t,q,α),
wherep+q= and
M(t,q,α) =
| f(a)|
|f(b)|m qtα
dt
Proof From Lemma with the properties of modulus and using the Hölder inequality, we have
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)
t( –t)fta+ ( –t)bdt
≤(b–a)
t–tpdt
p
fta+ ( –t)bqdt
q
=(b–a)
––p√π ( +p) (
+p)
p
fta+ ( –t)bqdt
q .
Since|f|q is (α,m)-geometrically convex and monotonically decreasing on [a,b], by using (.) we obtain
I =
fta+ ( –t)bqdt
≤
fatbm(–t)qdt
≤
f(a)tαf(b)m(–tα)qdt
=f(b)mq
| f(a)|
|f(b)|m qtα
dt.
So, we have
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)
––p√π ( +p) (+p)
p
f(b)mq
|f(a)|
|f(b)|m qtα
dt
q
=(b–a)
|f(b)|m
––p√π ( +p) (+p)
p
|f(a)|
|f(b)|m qtα
dt
q ,
which completes the proof.
Corollary In Theorem, (i)If|f(a)|<|f(b)|m,then we get
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)|f(b)|m
––p√π ( +p) (+p)
p
| f(a)|
|f(b)|m qtα
dt
q
≤(b–a)|f(b)|m
––p√π ( +p) (+p)
p
| f(a)|
|f(b)|m qαt
dt
=(b–a)
|f(b)|m
––p√π ( +p) (+p)
p
×
|
f(a)|qα–|f(b)|mqα
|f(b)|mqα[ln|f(a)|qα–ln|f(b)|mqα]
q
=(b–a)
|f(b)|m(–α)
––p√π ( +p) (
+p)
p
Lf(a)qα,f(b)mqαq,
where we used the fact that if <μ≤, <t andα≤,we have
μtα≤μαt.
(ii)If|f(a)|=|f(b)|m,then we get
f(a) +f(b)–
b–a b
a
f(x)dx
≤(b–a)|f(b)|m
––p√π ( +p) (+p)
p .
Theorem Let f : [,b]→R+ be a twice differentiable function, a∈[,b]and f∈
L[a,b].If|f|and|f|qare(α,m)-geometrically convex and monotonically decreasing on
[a,b]for a,b≥,p> , (α,m)∈(, ]and t∈[, ],we have
b–aabf(x)dx–f
a+b
≤(b–a)
f(b)m
K dt+f(a)m
G dt
+
(p+ )p
f(b)m
Kqdt
q
+f(a)m
Gqdt
q
, (.)
where K= (|f|f(b(a)|)m| )t
α
,G= (|f|f((ab)|)m| )t
α and
p+
q= .
Proof By using Lemma and the properties of absolute value, we have
b–a b a
f(x)dx–f
a+b
≤(b–a)
tfta+ ( –t)bdt+
tf( –t)a+tbdt
+
( –t)fta+ ( –t)bdt+
( –t)f( –t)a+tbdt
=(b–a)
Sincetis increasing on [,
] and|f|is decreasing, by applying the Chebyshev inequality
toIandIand by applying the Hölder inequality toIandI, we get
b–aabf(x)dx–f
a+b
≤(b–a)
tdt
fta+ ( –t)bdt
+
tdt
f( –t)a+tbdt
+
( –t)pdt
p
fta+ ( –t)bqdt q +
( –t)pdt
p
f( –t)a+tbq dt
q
=(b–a)
fta+ ( –t)bdt+
f( –t)a+tbdt
+
(p+ )p
p+
p
fta+ ( –t)bqdt q +
f( –t)a+tbqdt
q
.
As|f|is decreasing,|f|and|f|qare (α,m)-geometrically convex, from (.) we have
b–a b a
f(x)dx–f
a+b
≤(b–a)
fatbm(–t)dt+
fam(–t)btdt
+
(p+ )p
p+
p
fatbm(–t)qdt q +
fam(–t)btqdt
q
≤(b–a)
f(a)tα
f(b)m(–tα)dt+
f(a)m(–tα)
f(b)tαdt
+
(p+ )p
p+
p
f(a)tαf(b)m(–tα)qdt q +
f(a)m(–tα)
f(b)tαqdt
q
,
Corollary Under the conditions of Theorem,if we choose fis symmetric about a+b,
then we have
b–aabf(x)dx–f
a+b
≤(b–a)|f(b)|m
K dt+
(p+ )p
Kqdt
q
.
Proof From (.) and by using the symmetric property off, we get
b–a b a
f(x)dx–f
a+b
≤(b–a)
fta+ ( –t)bdt+
f( –t)a+tbdt
+
(p+ )ppp+
fta+ ( –t)bqdt q +
f( –t)a+tbqdt
q
=(b–a)
fta+ ( –t)bdt
+
(p+ )p
p+
p
fta+ ( –t)bqdt
q
=(b–a)
fta+ ( –t)bdt
+
(p+ )pp
fta+ ( –t)bqdt
q
.
By using (α,m)-geometric convexity of|f|and|f|qand similar calculations, we get
b–aabf(x)dx–f
a+b
≤(b–a)
fatbm(–t)dt+
(p+ )pp
fatbm(–t)qdt
q
≤(b–a)
f(a)tα
f(b)m(–tα)dt
+
(p+ )p
f(a)tαf(b)m(–tα)qdt
q
=(b–a)
|f(b)|m
|f(a)|
|f(b)|m tα
dt+
(p+ )p
|f(a)|
|f(b)|m qtα
dt
q
.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
ÇY and MG carried out the design of the study and performed the analysis. MEÖ participated in its design and coordination. All authors read and approved the final manuscript.
Author details
1Department of Mathematics, K. K. Education Faculty, Atatürk University, Campus, Erzurum, 25240, Turkey.2Graduate School of Natural and Applied Sciences, A ˘gri ˙Ibrahim Çeçen University, A ˘gri, Turkey.
Received: 20 September 2013 Accepted: 11 April 2014 Published:12 May 2014
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