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951

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Observation on the Binary Quadratic Equation

0

,

4

105

2

2

x

t

y

t

G. Sumathi1, A. Prathiba2

1

Assistant Professor, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.

2

PG Scholar, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.

Abstract: The binary quadratic equation is considered and a few interesting properties among the solutions are presented. Keywords:Binary quadratic, integral solutions, Generalized Fibonacci sequences, Generalized Lucas Sequences.

I. INTRODUCTION

The Binary quadratic equation of the form

y

2

Dx

2

1

, where D is a non-square positive integer has been studied by various Mathematicians for its non-trivial integral solutions when D takes different integral values [1-5]. In this context one may also refer [4,5]. These results have motivated us to search for the integral solutions of yet another binary quadratic equation representing a hyperbola. A few interesting properties among the solutions are presented.

II. NOTATIONS

1)

t

m,n : Polygonal number of rank

n

with size

m

2)

P

nm : Pyramidal number of rank

n

with size

m

3)

Pr

n : Pronic number of rank

n

4)

S

n : Star number of rank

n

5)

Ct

m,n : Centered Pyramidal number of rank

n

with size

m

6)

GF

n

k

,

s

: Generalized Fibonacci sequence number of rank n

7)

GL

n

k

,

s

: Generalized Lucas sequence number of rank n

III. METHODOFANALYSIS

The binary non-homogeneous quadratic Diophantine equation represents a hyperbola to be solved for its non-zero integral solutions is

2 105 2 4, 0

 

x t

y t

(1)

The smallest positive integer solution

x0,y0

of (1) is

 

t

x0 42 ,

 

t

y0412 (2)

To obtain the other solutions of (1), consider the pellian equation

y2 105x21 (3)

Applying the Brahmagupta lemma between the solutions (x0,y0) and (x~n,~yn), the other integer solutions of (1) are given by

 

 

n t

n t

n

f

g

x

105

2

2

41

2

2

4

1

 

 

n

t n

t

n

f

g

y

105

2

2

420

2

2

41

1

(2)

952

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A. A Few Numerical Examples Are Given In The Following Table 1

Tabe1: Examples

B. A Few Interesting Properties Are Given Below

1) The recurrence relations satisfied by the values of xn1 and yn1 are respectively.

0 2 164

2xn3 xn2 xn1 , n1,0,1...

0 2 164

2yn3 yn2 yn1 , n1,0,1...

A few interesting relations among the solutions are given below:

a) xn382xn2xn10

b) 4yn1xn241xn10

c) 4yn241xn2xn10

d) 4yn33361xn241xn10

e) 328yn1xn33361xn10

f)

8

y

n2

x

n3

x

n1

0

g) 328yn33361xn3xn10

h) yn241yn1420xn10

i) yn33361yn134440xn10

j) 41yn33361yn2420xn10

k) 4yn141xn33361xn20

l) 4yn2xn341xn20

m)

4

y

n3

41

x

n3

x

n2

0

n) 41yn2yn1420xn20

o) yn341yn2420xn20

p) 3361yn241yn1420xn30

q) 3361yn3yn134440xn30

r) yn3yn1840xn20

s) 41yn3yn2420xn30

t) yn1yn382yn20

n xn1 yn1

-1

 

t

2

4 41

 

2t

0

 

t

2

328 3361

 

2t

1

 

t

2

26892 275561

 

2t

2

 

t

2

2204816

 

t

(3)

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2) Each Of The Following Is A Nasty Number

a)

 

t

123x n 10083xn 12

 

2t

2 1

2 2 3

2    

b)

 

t

3xn 20163xn 8

 

2t

2 2

1

2 2 4

2    

c)

 

t

492y n 5040x n 12

 

2t

2 1

2 2 2

2    

d)

 

t

12y n 10080xn 12

 

2t

2 1

2 2 3

2    

e)

 

t

492y n 33883920xn 40332

 

2t

2 3361

1

2 2 4

2    

f)

 

t

10083xn 826683xn 12

 

2t

2 1

3 2 4

2    

g)

 

t

40332y n 5040xn 492

 

2t

2 41

1

3 2 2

2    

h)

 

t

40332y n 68880xn 12

 

2t

2 1

3 2 3

2    

i)

 

t

40332yn 33883920x n 492

 

2t

2 41

1

3 2 4

2   

j)

 

t

3306732y n 5040xn 40332

 

2t

2 3361

1

4 2 2

2    

k)

 

t

3306732y n 413280xn 492

 

2t

2 41

1

4 2 3

2    

l)

 

t

3306732yn 33883920xn 12

 

2t

2 1

4 2 4

2    

m)

 

t

34440yn 420y n 420

 

2t

2 35

1

3 2 2

2    

n)

 

t

40338yn 6yn 492

 

2t

2 41

1

4 2 2

2    

o)

 

t

80676y n 164y n 12

 

2t

2 1

4 2 3

2    

3) Each Of The Following Is A Cubical Integer

a)

 

41 3 4 3361 3 3 123 2 10083 1

2 2

1

 

  nnn

n

t x x x x

b)

 

3 5 6721 3 3 3 3 20163 1

2 4

1

 

  nnn

n

t x x x x

c)

 

82 3 3 840 3 3 246 1 2520 1

2 1

 

  nnn

n

t y x y x

d)

 

2 3 4 1680 2 2 6 2 5040 1

2 1

 

  nnn

n

t y x y x

e)

 

82 3 5 5647320 3 3 246 3 16941960 1

2 3361

1

 

  nnn

n

(4)

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f)

 

3361 3 5 275561 3 4 10083 3 826683 2

2 2

1

 

  nnn

n

t x x x x

g)

 

6722 3 3 840 3 4 20166 1 2520 2

2 41

1

 

  nnn

n

t y x y x

h)

 

6722 3 4 68880 3 4 20166 2 206640 2

2 2

1

 

  nnn

n

t y x y x

i)

 

6722 3 5 647320 3 4 20166 3 16941960 2

2 41

1

 

  nnn

n

t y x y x

j)

 

551122 3 3 840 3 5 1653366 1 2520 3

2 3361

1

 

  nnn

n

t y x y x

k)

 

551122 3 4 68880 3 5 1653366 2 206640 3

2 41

1

 

  nnn

n

t y x y x

l)

 

551122 3 5 5647320 3 5 1653366 3 16941960 3

2 1

 

  nnn

n

t y x y x

m)

 

34440 3 3 420 3 4 103320 1 1260 2

2 210

1

 

  nnn

n

t y y y y

n)

 

6723 3 3 3 5 20169 1 3 3

2 41

1

  

  nnn n

t y y y y

o)

 

13446 3 4 164 3 5 40338 2 492 3

2 1

 

  nnn

n

t y x y y

4) Each of the following expression is a biquadratic integer

a)

 

t

41xn 3361xn 164xn 13444x n 12

 

2t

2 2

1

4 2 3

2 4 4 5

4        

b)

 

t

x n 6721xn 4xn 26884xn 24

 

2t

2 4

1

2 2 4

2 4 4 6

4        

c)

 

t

82y n 840xn 328yn 3360xn 6

 

2t

2 1

2 2 2

2 4

4 4

4        

d)

 

t

2y n 1680xn 8yn 6720xn 6

 

2t

2 1

2 2 3

2 4 4 5

4        

e)

 

t

82yn 5647320x n 328y n 22589280xn 20166

 

2t

2 3361

1

2 2 4

2 4

4 6

4        

f)

 

t

3361x n 275561xn 13444x n 1102244x n 12

 

2t

2 2

1

3 2 4

2 5

4 6

4        

g)

 

t

6722yn 840xn 26888y n 3360xn 246

 

2t

2 41

1

3 2 2

2 5

4 4

4        

h)

 

t

6722y n 68880xn 26888y n 275520xn 6

 

2t

2 1

3 2 3

2 5

4 5

4        

i)

 

t

6722yn 56473270xn 26888yn 22589280x n 246

 

2t

2 41

1

3 2 4

2 5

4 6

4        

j)

 

t

551122y n 840x n 2204488y n 33604x n 20166

 

2t

2 3361

1

4 2 2

2 6

4 4

4        

k)

 

t

551122y n 68880xn 2204488yn 275520xn 246

 

2t

2 41

1

4 2 3

2 6

4 5

(5)

955

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l)

 

t

551122yn 5647320xn 2204488y n 22589280xn 6

 

2t

2 1 4 2 4 2 6 4 6

4        

m)

 

t

34440y n 420y n 137760y n 1680yn 1260

 

2t

2 210 1 3 2 2 2 5 4 4

4        

n)

 

t

6723yn y n 26892y n 4yn 246

 

2t

2 41 1 4 2 2 2 6 4 4

4        

o)

 

t

13446y n 164yn 53784y n 656yn 6

 

2t

2 1 4 2 3 2 6 4 5

4        

5) Each of the following expression is a quintic integer

a)

 

                     1 2 1 2 3 3 4 3 5 5 6 5 16805 205 50415 615 16805 205 3361 41 2 2 1 n n n n n n n n t x x x x x x x x b)

 

                     1 3 1 3 3 3 5 3 5 5 7 5 33605 5 100815 15 33605 5 6721 2 4 1 n n n n n n n n t x x x x x x x x c)

 

                     1 1 1 1 3 3 3 3 5 5 5 5 4200 410 12600 1230 4200 410 840 82 2 1 n n n n n n n n t x y x y x y x y d)

 

        1 2 1 2 2 2 4 3 5 5 6 5

8400

10

25200

30

8400

10

1680

2

2

1

n n n n n n n n t

x

y

x

y

x

y

x

y

e)

 

                     1 3 1 3 3 3 5 3 5 5 7 5 28236600 410 84709800 1230 28236600 410 5647320 82 2 3361 1 n n n n n n n n t x y x y x y x y f)

 

                     2 3 2 3 4 3 5 3 6 5 7 5 1377805 16805 4133415 50415 1377805 16805 275561 3361 2 2 1 n n n n n n n n t x x x x x x x x g)

 

                     2 1 2 1 4 3 3 3 6 5 5 5 3225 193555 9675 58065 3225 19355 6722 2 41 1 n n n n n n n n t x y x y x y x y h)

 

                     2 2 2 2 4 3 4 3 6 5 6 5 344400 33610 100830 100830 344400 33610 68880 6722 2 1 n n n n n n n n t x y y y x y x y i)

 

                     2 3 2 3 4 3 5 3 6 5 7 5 28236600 33610 84709800 100830 28236600 33610 5647320 6722 2 41 1 n n n n n n n n t x y x y x y x y j)

 

                     3 1 3 1 5 3 3 3 7 5 5 5 4200 2755610 12600 8266830 4200 2755610 840 551122 2 3361 1 n n n n n n n n t x y x y x y x y k)

 

                     3 2 3 2 5 3 4 3 7 5 6 5 34440 2755610 1033200 8266830 344400 2755610 68880 551122 2 41 1 n n n n n n n n t x y x y x y x y l)

 

                     3 3 3 3 5 3 5 3 7 5 7 5 2823660 2755610 84709800 8266830 28236600 27556100 5647320 551122 2 1 n n n n n n n n

t x y x

y x y x y m)

 

                     2 1 2 1 4 3 3 3 6 5 5 5 2100 172200 6300 516600 2100 172200 420 34440 2 210 1 n n n n n n n n

t y y y

y y y y y n)

 

                     3 1 3 1 5 3 3 3 7 5 5 5 5 33615 15 100845 5 33615 6723 2 41 1 n n n n n n n n t y y y y y y y y o)

 

                     3 2 3 2 5 3 4 3 7 5 6 5 820 67230 2460 201690 820 67230 164 13446 2 1 n n n n n n n n

t y y y

y y

y y

(6)

956

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6) Remarkable Observations

a) Employing linear combinations among the solutions of (1.1), one may generate integer solutions for other choices of hyperbola which are presented in table below.

S.No Hyperbola

Xn,Yn

1

 

t

n

n Y

X2420 2 164

    

  

 

 

 

2 1

1 2

2 164

3361 41

n n

n n

x x

x x

2

 

t

n

n Y

X 1680 1075844

1681 2 2

 

   

 

 

 

 

3 1

1 3

6723 6721

n n

n n

x x

x x

3

 

t

n

n Y

X2105 2 44

   

 

 

 

 

1 1

1 1

8 82

840 82

n n

n n

y x

x y

4

 

t

n

n Y

X 105 67244

1681 2 2

   

 

 

 

 

2 1

1 2

8 6722

1680 2

n n

n n

y x

x y

5

 

t

n

n Y

X2105 2 451852844

   

 

 

 

 

3 1

1 3

8 551122

5647320 82

n n

n n

y x

x y

6

 

t

n

n Y

X2420 2 164

   

 

 

 

 

3 2

2 3

164 13446

275561 3361

n n

n n

x x

x x

7

 

t

n n

Y

X

2

105

2

6724

4

   

 

 

 

 

1 2

2 1

656 82

840 6722

n n

n n

y x

x y

8

 

t

n

n Y

X2 105 2 44

 

   

 

 

 

 

2 2

2 2

656 6722

68880 6722

n n

n n

y x

x y

9

 

t

n

n Y

X2105 267244

   

 

 

 

 

3 2

2 3

656 551122

5647320 6722

n n

n n

y x

x y

10

 

t

n

n Y

X2105 2451852844

   

 

 

 

 

1 3

3 1

53784 82

840 551122

n n

n n

y x

x y

11

 

t

n

n Y

X2105 2 67244

   

 

 

 

 

2 3

3 2

53784 6722

68880 551122

n n

n n

y x

x y

12

 

t

n

n Y

X2105 244

   

 

 

 

 

3 3

3 3

53784 551122

5647320 551122

n n

n n

y x

x y

13

 

t

n

n Y

X2105 21764004

   

 

 

 

 

1 2

2 1

3361 41

420 34440

n n

n n

y y

y y

14

 

t

n

n Y

X 35301 2372227204

35280 2 2

 

   

 

 

 

 

1 3

3 1

6721 6723

n n

n n

y y

y y

15

 

t

n

n Y

X 21 352804

8820 2 2 

   

 

 

 

 

2 3

3 2

275561 3361

164 13446

n n

n n

y y

(7)

957

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b) Employing linear combinations among the solutions of (1.1), one may generate integer solutions for other choices of Parabola which are presented in table below.

S.No Parabola

Xn,Yn

1

 

 

t

n n

t

Y

X 210 44

2  2

            3 2 2 2 2 2 3 2 2 164 3361 41 n n n n x x x x

2

 

 

t

n n

t

Y

X 420 134484

2

1681  2 

            4 2 2 2 2 2 4 2 6723 6721 n n n n x x x x

3

 

 

t

n n t

Y

X 105 44

2  2 

            2 2 2 2 2 2 2 2 68 82 840 82 n n n n y x x y

4

 

 

t

n n t

Y

X 105 33624

2

1681  2 

            3 2 2 2 2 2 3 2 8 6722 1680 2 n n n n y x x y

5

 

 

t

n n t

Y

X 105 225926424

2 3361 2               4 2 2 2 2 2 4 2 8 551122 5647320 82 n n n n y x x y

6

 

 

t

n n

t

Y

X 210 44

2 2               2 2 3 2 3 2 2 2 656 82 840 6722 n n n n x x x y

7

 

 

t

n n t

Y

X 105 33624

2 41 2               2 2 3 2 3 2 2 2 656 82 840 6722 n n n n y x x y

8

 

 

t

n n t

Y

X 105 24

2  2

            3 2 3 2 3 2 3 2 656 6722 68880 6722 n n n n y x x y

9

 

 

t

n n t

Y

X 105 33624

2

41  2 

            4 2 3 2 3 2 4 2 656 551122 5647320 6722 n n n n y x x y

10

 

 

t

n n t

Y

X 105 225926424

2

3361  2 

            2 2 4 2 4 2 2 2 53784 82 840 551122 n n n n y x x y

11

 

 

t

n n t

Y

X 105 33624

2

41  2 

            3 2 4 2 4 2 3 2 53784 6722 68880 551122 n n n n y x x y

12

 

 

t

n n t

Y

X 105 24

2  2

            4 2 4 2 4 2 4 2 53784 551122 5647320 551122 n n n n y x x y

13

 

 

t

n n t

Y

X 105 1764004

2

210  2 

            2 2 3 2 3 2 2 2 3361 41 420 34440 n n n n y y y y

14

 

 

t

n n t

Y

X 861 28929604

2

35280  2

            2 2 4 2 4 2 2 2 6721 6723 n n n n y y y y

15

 

 

t

n n t

Y

X 21 176404

2

8820  2

(8)

958

©IJRASET: All Rights are Reserved

c) Employing the linear combination among the solutions of (1), one may generate integer solutions for other choices of straight line which are presented in the table below:

S.No. Straight line

Y,X

1 Y 2X Yxn36721xn1

1

2 3361

41   

xn xn

X

2 YX Y 82yn1840xn1

1

2 1680

2   

yn xn X

3 Y 41X Y 6722yn1840xn2

2

2 68880

6722   

yn xn

X

4 Y 3361X Y 82yn31680xn1

3

3 5647320

551122   

yn xn

X

5 YX Y 41xn23361xn1

2

3 275561

3361   

xn xn

X

6 Y 210X Y 34440yn1420yn2

1

1 840

82   

yn xn

X

7 Y 210X Y 34440yn1420yn2

3

2 164

13446   

yn yn

X

8 YX Y 6722yn35647320xn2

3 1

6723   

yn yn

X

9 Y 2X Y3361xn3275561xn2

1

2 1680

2   

yn xn X

10 Y 2X Y 176yn12yn2

2

3 275561

3361   

xn xn

X

11 Y 2X Yxn36721xn1

3

3 5647320

551122   

yn xn

X

12 YX Y 82yn1840xn1

3

2 164

13446   

yn yn

X

13 Y41X Y 6723yn1yn3

1

2 1680

2   

yn xn

X

14 Y 3361X Y 82yn35647320xn1

3

2 164

13446   

yn yn

X

15 YX Y 551122yn268880xn3

3 1

6723   

yn yn

X

d) The solutions in terms of special integer sequence namely, generalized Fibonacci sequence GFn

k,s

and Lucas sequence

k s

GLn , are exhibited below.

12

 

2 1

82,1

164

 

2 n1

82,1

t n

t

n GL GF

x

 

2

82, 1

1680

 

2

82, 1

2 41

1 1

1      

n

t n

t

n GL GF

(9)

959

©IJRASET: All Rights are Reserved

e) Employing the solutions (1),each of the following among the special polygonal, pyramidal, star numbers, pronic numbers is a congruent to under modulo 4

i)

2

1 , 3

3 2

1 5

3 105 1 12

             

  

 

x

x

y y

t p s

p

ii)

2 1

5 2

, 4

5

1 12 105 1

4

    

  

 

    

  

x

x y

y

s p ct

p

iii)

2

, 4

5 2

2 , 3 3

2

1 4 105 3

    

  

 

       

 

x x

y y

ct p t

p

iv)

2

, 3 5 2

1 3

105 6

                

x

x

y y

t p pr

p

v)

2

1 2 , 3 4

1 2

, 4

5

6 105 1 4

             

  

 

x x

x y

t p ct

p

vi)

2

2 , 3 3

2 2

1 3

2 3

105 1

36

             

  

 

 

y x

y y

t p s

p

vii)

2

2 , 3 3

2 2

1 5

3 105 1 12

             

  

 

x

x

y y

t p s

p

viii)

2

1 , 4 5

1 2

3 3

3 2

105 4

             

  

  

x x

y y

t p p

pt

ix)

2 1 , 4

3 1 4

1 2

, 6

5

3 105 1

6

    

 

     

  

 

 

x x x y

y

t p p ct

p

x)

2

, 3 5 2

1 2 , 3 4

1

105 6

                

 

x x

y y

t p t

p

REFERENCES

[1] Dickson.L.E, History of Theory of Numbers and Diophantine Analysis, Dover Publications, New York 2005.

[2] Mordell.L.J, Diophantine Equations, Academic Press, New York 1970.

[3] Carmicheal.R.D, The Theory of Numbers and Diophantine Analysis, Dover Publication, New York 1959.

[4] Gopalan .M.A, Sumathi.G, Vidhyalakshmi.S. “Observation on the hyperbola t

y x2 19 2 3

 ” , Scholars Journal of the Engineering and

Technology2014;2(2A):152-155.

[5] Gopalan .M.A, Sumathi.G, Vidhyalakshmi.S. “Observation on the hyperbola 2 26 2 1

  x

y , Bessel J.Math., Vol 4, Issue(1), 2014;21-25.

[6] On Special familes of Hyperbola, 2

4 2

2 2, 1

  

t

y k k

x The International Journal of Science and Technology, Vol 2, Issue(3), Pg.No.94-97, March

2014.

[7] Dr.G.Sumathi “Observation on the hyperbola 2 182 2 14

x

y ”, Journal of Mathematics and Informatics, Vol 11, 73-81, 2017

[8] Dr.G.Sumathi “Observation on the Pell Equation 2 14 2 4

  x

y ”, International Journal of Creative Research Thoughts, Vol 6, Issue 1, Pp1074-1084, March

2018

[9] Dr.G.Sumathi “Observation on the Equation 2 312 2 1

x

y ” International Journal of Mathematics Trends and Technology, Vol 50, Issue 4, 31-34, Oct

2017

[10] Dr.G.Sumathi “Observation on the Hyperbola 2 150 2 16

x

y ” International Journal of recent Trends in Engineering and Research, Vol 3, Issue 9,

References

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