951
©IJRASET: All Rights are Reserved
Observation on the Binary Quadratic Equation
0
,
4
105
2
2
x
t
y
t
G. Sumathi1, A. Prathiba2
1
Assistant Professor, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.
2
PG Scholar, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.
Abstract: The binary quadratic equation is considered and a few interesting properties among the solutions are presented. Keywords:Binary quadratic, integral solutions, Generalized Fibonacci sequences, Generalized Lucas Sequences.
I. INTRODUCTION
The Binary quadratic equation of the form
y
2
Dx
2
1
, where D is a non-square positive integer has been studied by various Mathematicians for its non-trivial integral solutions when D takes different integral values [1-5]. In this context one may also refer [4,5]. These results have motivated us to search for the integral solutions of yet another binary quadratic equation representing a hyperbola. A few interesting properties among the solutions are presented.II. NOTATIONS
1)
t
m,n : Polygonal number of rankn
with sizem
2)
P
nm : Pyramidal number of rankn
with sizem
3)
Pr
n : Pronic number of rankn
4)
S
n : Star number of rankn
5)
Ct
m,n : Centered Pyramidal number of rankn
with sizem
6)
GF
n
k
,
s
: Generalized Fibonacci sequence number of rank n7)
GL
n
k
,
s
: Generalized Lucas sequence number of rank nIII. METHODOFANALYSIS
The binary non-homogeneous quadratic Diophantine equation represents a hyperbola to be solved for its non-zero integral solutions is
2 105 2 4, 0
x t
y t
(1)
The smallest positive integer solution
x0,y0
of (1) is
tx0 42 ,
t
y0412 (2)
To obtain the other solutions of (1), consider the pellian equation
y2 105x21 (3)
Applying the Brahmagupta lemma between the solutions (x0,y0) and (x~n,~yn), the other integer solutions of (1) are given by
n t
n t
n
f
g
x
105
2
2
41
2
2
4
1
nt n
t
n
f
g
y
105
2
2
420
2
2
41
1
952
©IJRASET: All Rights are Reserved
A. A Few Numerical Examples Are Given In The Following Table 1
Tabe1: Examples
B. A Few Interesting Properties Are Given Below
1) The recurrence relations satisfied by the values of xn1 and yn1 are respectively.
0 2 164
2xn3 xn2 xn1 , n1,0,1...
0 2 164
2yn3 yn2 yn1 , n1,0,1...
A few interesting relations among the solutions are given below:
a) xn382xn2xn10
b) 4yn1xn241xn10
c) 4yn241xn2xn10
d) 4yn33361xn241xn10
e) 328yn1xn33361xn10
f)
8
y
n2
x
n3
x
n1
0
g) 328yn33361xn3xn10
h) yn241yn1420xn10
i) yn33361yn134440xn10
j) 41yn33361yn2420xn10
k) 4yn141xn33361xn20
l) 4yn2xn341xn20
m)
4
y
n3
41
x
n3
x
n2
0
n) 41yn2yn1420xn20
o) yn341yn2420xn20
p) 3361yn241yn1420xn30
q) 3361yn3yn134440xn30
r) yn3yn1840xn20
s) 41yn3yn2420xn30
t) yn1yn382yn20
n xn1 yn1
-1
t2
4 41
2t0
t2
328 3361
2t1
t2
26892 275561
2t2
t2
2204816
t953
©IJRASET: All Rights are Reserved
2) Each Of The Following Is A Nasty Number
a)
t
123x n 10083xn 12
2t
2 1
2 2 3
2
b)
t
3xn 20163xn 8
2t
2 2
1
2 2 4
2
c)
t
492y n 5040x n 12
2t
2 1
2 2 2
2
d)
t
12y n 10080xn 12
2t
2 1
2 2 3
2
e)
t
492y n 33883920xn 40332
2t
2 3361
1
2 2 4
2
f)
t
10083xn 826683xn 12
2t
2 1
3 2 4
2
g)
t
40332y n 5040xn 492
2t
2 41
1
3 2 2
2
h)
t
40332y n 68880xn 12
2t
2 1
3 2 3
2
i)
t
40332yn 33883920x n 492
2t
2 41
1
3 2 4
2
j)
t
3306732y n 5040xn 40332
2t
2 3361
1
4 2 2
2
k)
t
3306732y n 413280xn 492
2t
2 41
1
4 2 3
2
l)
t
3306732yn 33883920xn 12
2t
2 1
4 2 4
2
m)
t
34440yn 420y n 420
2t
2 35
1
3 2 2
2
n)
t
40338yn 6yn 492
2t
2 41
1
4 2 2
2
o)
t
80676y n 164y n 12
2t
2 1
4 2 3
2
3) Each Of The Following Is A Cubical Integer
a)
41 3 4 3361 3 3 123 2 10083 1
2 2
1
n n n
n
t x x x x
b)
3 5 6721 3 3 3 3 20163 1
2 4
1
n n n
n
t x x x x
c)
82 3 3 840 3 3 246 1 2520 1
2 1
n n n
n
t y x y x
d)
2 3 4 1680 2 2 6 2 5040 1
2 1
n n n
n
t y x y x
e)
82 3 5 5647320 3 3 246 3 16941960 1
2 3361
1
n n n
n
954
©IJRASET: All Rights are Reserved
f)
3361 3 5 275561 3 4 10083 3 826683 2
2 2
1
n n n
n
t x x x x
g)
6722 3 3 840 3 4 20166 1 2520 2
2 41
1
n n n
n
t y x y x
h)
6722 3 4 68880 3 4 20166 2 206640 2
2 2
1
n n n
n
t y x y x
i)
6722 3 5 647320 3 4 20166 3 16941960 2
2 41
1
n n n
n
t y x y x
j)
551122 3 3 840 3 5 1653366 1 2520 3
2 3361
1
n n n
n
t y x y x
k)
551122 3 4 68880 3 5 1653366 2 206640 3
2 41
1
n n n
n
t y x y x
l)
551122 3 5 5647320 3 5 1653366 3 16941960 3
2 1
n n n
n
t y x y x
m)
34440 3 3 420 3 4 103320 1 1260 2
2 210
1
n n n
n
t y y y y
n)
6723 3 3 3 5 20169 1 3 3
2 41
1
n n n n
t y y y y
o)
13446 3 4 164 3 5 40338 2 492 3
2 1
n n n
n
t y x y y
4) Each of the following expression is a biquadratic integer
a)
t
41xn 3361xn 164xn 13444x n 12
2t
2 2
1
4 2 3
2 4 4 5
4
b)
t
x n 6721xn 4xn 26884xn 24
2t
2 4
1
2 2 4
2 4 4 6
4
c)
t
82y n 840xn 328yn 3360xn 6
2t
2 1
2 2 2
2 4
4 4
4
d)
t
2y n 1680xn 8yn 6720xn 6
2t
2 1
2 2 3
2 4 4 5
4
e)
t
82yn 5647320x n 328y n 22589280xn 20166
2t
2 3361
1
2 2 4
2 4
4 6
4
f)
t
3361x n 275561xn 13444x n 1102244x n 12
2t
2 2
1
3 2 4
2 5
4 6
4
g)
t
6722yn 840xn 26888y n 3360xn 246
2t
2 41
1
3 2 2
2 5
4 4
4
h)
t
6722y n 68880xn 26888y n 275520xn 6
2t
2 1
3 2 3
2 5
4 5
4
i)
t
6722yn 56473270xn 26888yn 22589280x n 246
2t
2 41
1
3 2 4
2 5
4 6
4
j)
t
551122y n 840x n 2204488y n 33604x n 20166
2t
2 3361
1
4 2 2
2 6
4 4
4
k)
t
551122y n 68880xn 2204488yn 275520xn 246
2t
2 41
1
4 2 3
2 6
4 5
955
©IJRASET: All Rights are Reserved
l)
t
551122yn 5647320xn 2204488y n 22589280xn 6
2t
2 1 4 2 4 2 6 4 6
4
m)
t
34440y n 420y n 137760y n 1680yn 1260
2t
2 210 1 3 2 2 2 5 4 4
4
n)
t
6723yn y n 26892y n 4yn 246
2t
2 41 1 4 2 2 2 6 4 4
4
o)
t
13446y n 164yn 53784y n 656yn 6
2t
2 1 4 2 3 2 6 4 5
4
5) Each of the following expression is a quintic integer
a)
1 2 1 2 3 3 4 3 5 5 6 5 16805 205 50415 615 16805 205 3361 41 2 2 1 n n n n n n n n t x x x x x x x x b)
1 3 1 3 3 3 5 3 5 5 7 5 33605 5 100815 15 33605 5 6721 2 4 1 n n n n n n n n t x x x x x x x x c)
1 1 1 1 3 3 3 3 5 5 5 5 4200 410 12600 1230 4200 410 840 82 2 1 n n n n n n n n t x y x y x y x y d)
1 2 1 2 2 2 4 3 5 5 6 58400
10
25200
30
8400
10
1680
2
2
1
n n n n n n n n tx
y
x
y
x
y
x
y
e)
1 3 1 3 3 3 5 3 5 5 7 5 28236600 410 84709800 1230 28236600 410 5647320 82 2 3361 1 n n n n n n n n t x y x y x y x y f)
2 3 2 3 4 3 5 3 6 5 7 5 1377805 16805 4133415 50415 1377805 16805 275561 3361 2 2 1 n n n n n n n n t x x x x x x x x g)
2 1 2 1 4 3 3 3 6 5 5 5 3225 193555 9675 58065 3225 19355 6722 2 41 1 n n n n n n n n t x y x y x y x y h)
2 2 2 2 4 3 4 3 6 5 6 5 344400 33610 100830 100830 344400 33610 68880 6722 2 1 n n n n n n n n t x y y y x y x y i)
2 3 2 3 4 3 5 3 6 5 7 5 28236600 33610 84709800 100830 28236600 33610 5647320 6722 2 41 1 n n n n n n n n t x y x y x y x y j)
3 1 3 1 5 3 3 3 7 5 5 5 4200 2755610 12600 8266830 4200 2755610 840 551122 2 3361 1 n n n n n n n n t x y x y x y x y k)
3 2 3 2 5 3 4 3 7 5 6 5 34440 2755610 1033200 8266830 344400 2755610 68880 551122 2 41 1 n n n n n n n n t x y x y x y x y l)
3 3 3 3 5 3 5 3 7 5 7 5 2823660 2755610 84709800 8266830 28236600 27556100 5647320 551122 2 1 n n n n n n n nt x y x
y x y x y m)
2 1 2 1 4 3 3 3 6 5 5 5 2100 172200 6300 516600 2100 172200 420 34440 2 210 1 n n n n n n n nt y y y
y y y y y n)
3 1 3 1 5 3 3 3 7 5 5 5 5 33615 15 100845 5 33615 6723 2 41 1 n n n n n n n n t y y y y y y y y o)
3 2 3 2 5 3 4 3 7 5 6 5 820 67230 2460 201690 820 67230 164 13446 2 1 n n n n n n n nt y y y
y y
y y
956
©IJRASET: All Rights are Reserved
6) Remarkable Observations
a) Employing linear combinations among the solutions of (1.1), one may generate integer solutions for other choices of hyperbola which are presented in table below.
S.No Hyperbola
Xn,Yn
1
tn
n Y
X2420 2 164
2 1
1 2
2 164
3361 41
n n
n n
x x
x x
2
tn
n Y
X 1680 1075844
1681 2 2
3 1
1 3
6723 6721
n n
n n
x x
x x
3
tn
n Y
X2105 2 44
1 1
1 1
8 82
840 82
n n
n n
y x
x y
4
tn
n Y
X 105 67244
1681 2 2
2 1
1 2
8 6722
1680 2
n n
n n
y x
x y
5
tn
n Y
X2105 2 451852844
3 1
1 3
8 551122
5647320 82
n n
n n
y x
x y
6
tn
n Y
X2420 2 164
3 2
2 3
164 13446
275561 3361
n n
n n
x x
x x
7
tn n
Y
X
2
105
2
6724
4
1 2
2 1
656 82
840 6722
n n
n n
y x
x y
8
tn
n Y
X2 105 2 44
2 2
2 2
656 6722
68880 6722
n n
n n
y x
x y
9
tn
n Y
X2105 267244
3 2
2 3
656 551122
5647320 6722
n n
n n
y x
x y
10
tn
n Y
X2105 2451852844
1 3
3 1
53784 82
840 551122
n n
n n
y x
x y
11
tn
n Y
X2105 2 67244
2 3
3 2
53784 6722
68880 551122
n n
n n
y x
x y
12
tn
n Y
X2105 244
3 3
3 3
53784 551122
5647320 551122
n n
n n
y x
x y
13
tn
n Y
X2105 21764004
1 2
2 1
3361 41
420 34440
n n
n n
y y
y y
14
tn
n Y
X 35301 2372227204
35280 2 2
1 3
3 1
6721 6723
n n
n n
y y
y y
15
tn
n Y
X 21 352804
8820 2 2
2 3
3 2
275561 3361
164 13446
n n
n n
y y
957
©IJRASET: All Rights are Reserved
b) Employing linear combinations among the solutions of (1.1), one may generate integer solutions for other choices of Parabola which are presented in table below.
S.No Parabola
Xn,Yn
1
tn n
t
Y
X 210 44
2 2
3 2 2 2 2 2 3 2 2 164 3361 41 n n n n x x x x
2
tn n
t
Y
X 420 134484
2
1681 2
4 2 2 2 2 2 4 2 6723 6721 n n n n x x x x
3
tn n t
Y
X 105 44
2 2
2 2 2 2 2 2 2 2 68 82 840 82 n n n n y x x y
4
tn n t
Y
X 105 33624
2
1681 2
3 2 2 2 2 2 3 2 8 6722 1680 2 n n n n y x x y
5
tn n t
Y
X 105 225926424
2 3361 2 4 2 2 2 2 2 4 2 8 551122 5647320 82 n n n n y x x y
6
tn n
t
Y
X 210 44
2 2 2 2 3 2 3 2 2 2 656 82 840 6722 n n n n x x x y
7
tn n t
Y
X 105 33624
2 41 2 2 2 3 2 3 2 2 2 656 82 840 6722 n n n n y x x y
8
tn n t
Y
X 105 24
2 2
3 2 3 2 3 2 3 2 656 6722 68880 6722 n n n n y x x y
9
tn n t
Y
X 105 33624
2
41 2
4 2 3 2 3 2 4 2 656 551122 5647320 6722 n n n n y x x y
10
tn n t
Y
X 105 225926424
2
3361 2
2 2 4 2 4 2 2 2 53784 82 840 551122 n n n n y x x y
11
tn n t
Y
X 105 33624
2
41 2
3 2 4 2 4 2 3 2 53784 6722 68880 551122 n n n n y x x y
12
tn n t
Y
X 105 24
2 2
4 2 4 2 4 2 4 2 53784 551122 5647320 551122 n n n n y x x y
13
tn n t
Y
X 105 1764004
2
210 2
2 2 3 2 3 2 2 2 3361 41 420 34440 n n n n y y y y
14
tn n t
Y
X 861 28929604
2
35280 2
2 2 4 2 4 2 2 2 6721 6723 n n n n y y y y
15
tn n t
Y
X 21 176404
2
8820 2
958
©IJRASET: All Rights are Reserved
c) Employing the linear combination among the solutions of (1), one may generate integer solutions for other choices of straight line which are presented in the table below:
S.No. Straight line
Y,X
1 Y 2X Y xn36721xn1
1
2 3361
41
xn xn
X
2 Y X Y 82yn1840xn1
1
2 1680
2
yn xn X
3 Y 41X Y 6722yn1840xn2
2
2 68880
6722
yn xn
X
4 Y 3361X Y 82yn31680xn1
3
3 5647320
551122
yn xn
X
5 Y X Y 41xn23361xn1
2
3 275561
3361
xn xn
X
6 Y 210X Y 34440yn1420yn2
1
1 840
82
yn xn
X
7 Y 210X Y 34440yn1420yn2
3
2 164
13446
yn yn
X
8 Y X Y 6722yn35647320xn2
3 1
6723
yn yn
X
9 Y 2X Y3361xn3275561xn2
1
2 1680
2
yn xn X
10 Y 2X Y 176yn12yn2
2
3 275561
3361
xn xn
X
11 Y 2X Y xn36721xn1
3
3 5647320
551122
yn xn
X
12 Y X Y 82yn1840xn1
3
2 164
13446
yn yn
X
13 Y41X Y 6723yn1yn3
1
2 1680
2
yn xn
X
14 Y 3361X Y 82yn35647320xn1
3
2 164
13446
yn yn
X
15 YX Y 551122yn268880xn3
3 1
6723
yn yn
X
d) The solutions in terms of special integer sequence namely, generalized Fibonacci sequence GFn
k,s
and Lucas sequence
k s
GLn , are exhibited below.
12
2 1
82,1
164
2 n1
82,1
t n
t
n GL GF
x
2
82, 1
1680
2
82, 1
2 41
1 1
1
n
t n
t
n GL GF
959
©IJRASET: All Rights are Reserved
e) Employing the solutions (1),each of the following among the special polygonal, pyramidal, star numbers, pronic numbers is a congruent to under modulo 4
i)
2
1 , 3
3 2
1 5
3 105 1 12
x
x
y y
t p s
p
ii)
2 1
5 2
, 4
5
1 12 105 1
4
x
x y
y
s p ct
p
iii)
2
, 4
5 2
2 , 3 3
2
1 4 105 3
x x
y y
ct p t
p
iv)
2
, 3 5 2
1 3
105 6
x
x
y y
t p pr
p
v)
2
1 2 , 3 4
1 2
, 4
5
6 105 1 4
x x
x y
t p ct
p
vi)
2
2 , 3 3
2 2
1 3
2 3
105 1
36
y x
y y
t p s
p
vii)
2
2 , 3 3
2 2
1 5
3 105 1 12
x
x
y y
t p s
p
viii)
2
1 , 4 5
1 2
3 3
3 2
105 4
x x
y y
t p p
pt
ix)
2 1 , 4
3 1 4
1 2
, 6
5
3 105 1
6
x x x y
y
t p p ct
p
x)
2
, 3 5 2
1 2 , 3 4
1
105 6
x x
y y
t p t
p
REFERENCES
[1] Dickson.L.E, History of Theory of Numbers and Diophantine Analysis, Dover Publications, New York 2005.
[2] Mordell.L.J, Diophantine Equations, Academic Press, New York 1970.
[3] Carmicheal.R.D, The Theory of Numbers and Diophantine Analysis, Dover Publication, New York 1959.
[4] Gopalan .M.A, Sumathi.G, Vidhyalakshmi.S. “Observation on the hyperbola t
y x2 19 2 3
” , Scholars Journal of the Engineering and
Technology2014;2(2A):152-155.
[5] Gopalan .M.A, Sumathi.G, Vidhyalakshmi.S. “Observation on the hyperbola 2 26 2 1
x
y , Bessel J.Math., Vol 4, Issue(1), 2014;21-25.
[6] On Special familes of Hyperbola, 2
4 2
2 2, 1
t
y k k
x The International Journal of Science and Technology, Vol 2, Issue(3), Pg.No.94-97, March
2014.
[7] Dr.G.Sumathi “Observation on the hyperbola 2 182 2 14
x
y ”, Journal of Mathematics and Informatics, Vol 11, 73-81, 2017
[8] Dr.G.Sumathi “Observation on the Pell Equation 2 14 2 4
x
y ”, International Journal of Creative Research Thoughts, Vol 6, Issue 1, Pp1074-1084, March
2018
[9] Dr.G.Sumathi “Observation on the Equation 2 312 2 1
x
y ” International Journal of Mathematics Trends and Technology, Vol 50, Issue 4, 31-34, Oct
2017
[10] Dr.G.Sumathi “Observation on the Hyperbola 2 150 2 16
x
y ” International Journal of recent Trends in Engineering and Research, Vol 3, Issue 9,