Communication Systems, 5e
Chapter 4: Linear CW Modulation A. Bruce Carlson
Paul B. Crilly
Chapter 4: Linear CW Modulation
• Bandpass signals and systems
• Double-sideband amplitude modulation
• Modulation and transmitters
• Suppressed-sideband amplitude modulation
• Frequency conversion and demodulation
A family of AM Waveforms
• Double-Sideband, Carrier (AM in text)
• Double-Sideband, Suppressed Carrier (DSB in text)
t A t cos 2 f t
v
c
t A m t
A
c
t A 1 m t
A
c
Conventional AM
• Baseband
• Bandpass
• Fourier Domain
𝐴 𝑡 𝐴 ⋅ 1 𝜇 ⋅ 𝑚 𝑡
𝑣 𝑡 𝐴 ⋅ 1 𝜇 ⋅ 𝑚 𝑡 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
𝐴 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 𝐴 ⋅ 𝜇 ⋅ 𝑚 𝑡 ⋅ cos 2𝜋
𝑉 𝑓 𝐴
2 ⋅ 𝛿 𝑓 𝑓 𝛿 𝑓 𝑓 𝐴
2 ⋅ 𝜇 ⋅ 𝑀 𝑓 𝑓 𝑀 𝑓 𝑓
carrier message
AM Sidebands
• Assume that the message is a cosine wave
– messages are typically bounded by +/- 1.0
• The spectral response becomes
𝑚 𝑡 cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
𝑉 𝑓 𝐴
2 ⋅ 𝛿 𝑓 𝑓 𝛿 𝑓 𝑓 𝐴
4 ⋅ 𝜇 ⋅ 𝛿 𝑓 𝑓 𝑓 𝛿 𝑓 𝑓 𝑓
𝐴
4 ⋅ 𝜇 ⋅ 𝛿 𝑓 𝑓 𝑓 𝛿 𝑓 𝑓 𝑓
𝑀 𝑓 1
2 ⋅ 𝛿 𝑓 𝑓 𝛿 𝑓 𝑓
carrier
sidebands
sidebands
AM Positive Frequencies
• For the positive frequency segment of the spectrum
𝑉 𝑓 𝐴
4 ⋅ 𝜇 ⋅ 𝛿 𝑓 𝑓 𝑓 𝐴
2 ⋅ 𝛿 𝑓 𝑓 𝐴
4 ⋅ 𝜇 ⋅ 𝛿 𝑓 𝑓 𝑓
Lower sideband Carrier Upper sideband
Mag
fc m
c f
f fc fm Ac2
Ac4
Ac4
DSB (with Suppressed Carrier)
• Baseband
• Bandpass
• Fourier Domain
t A m t
A
c
t A m t cos 2 f t
v
c
c
c M f f
c M f f
c
2 f A
V
Message only, no carrier
DSB Sidebands
• Assume that the message is a cosine wave
– messages are typically bounded by +/- 1.0
• The spectral response becomes
t cos 2 f t
m
m
c m c m
c
m c
m c
c
f f
f f
f 4 f
A
f f
f f
f 4 f
f A V
f f
m f f
m
2 f 1
M
sidebands
sidebands
DSB Positive Frequencies
• For the positive frequency segment of the spectrum
c
c m
c f f
cf
m
4 f A
f 4 f
f A
V
No signal carrier, two sidebands
Lower sideband Upper sideband
Mag
fc m
c f
f fc fm Ac4 Ac4
Phasor Analysis AM
• Given a tone message …
𝑠 𝑡 𝐴 ⋅ 1 𝜇 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
• A positive frequency phasor can be defined and drawn
𝐴 𝑡 1 𝜇 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
𝑠 𝑡 𝐴
2 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 𝑠 𝑡 𝐴 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ cos 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ cos 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡
Phasor Analysis AM (2)
• A positive frequency phasor can be defined and drawn
𝑠 𝑡 𝐴
2 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 𝐴
2 ⋅ 𝜇 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡
The message phasors add so only the magnitude of the carrier phasor appears to change.
im a g
real A
c2
A
c4
A
c4
f
cf
m
f
m
Sideband phaser sum
𝑠 𝑡 𝐴
2 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 · 1 𝜇 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡
Phasor Analysis DSB
• Given a tone message …
𝑚 𝑡 𝐴 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
𝑠 𝑡 𝐴 ⋅ 𝐴 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡
𝑠 𝑡 𝐴 ⋅ 𝐴
2 ⋅ cos 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 cos 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡
• A positive frequency phasor can be defined and drawn
𝑠 𝑡 𝐴 ⋅ 𝐴
4 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡
Phasor Analysis DSB (2)
𝑠 𝑡 𝐴 ⋅ 𝐴
4 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡 exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 𝑓 ⋅ 𝑡
• A positive frequency phasor can be defined and drawn
im real
A 4 A
m c
A 4 A
m c
f
cf
m
f
m
Sideband phaser sum
𝑠 𝑡 𝐴 ⋅ 𝐴
4 ⋅ exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 · exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡 exp 𝑗 ⋅ 2𝜋 ⋅ 𝑓 ⋅ 𝑡
The message phasors add
so only the magnitude
appears to change.
Power and Trig Math Note
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1
𝑇⋅ 1 cos 2𝜋 ⋅ 2𝑓 ⋅ 𝑡
2 ⋅ 𝑑𝑡
𝑃 s 𝑡 lim
→
1
𝑡 s 𝑡 ⋅ 𝑑𝑡
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1
𝑇⋅ 1
2⋅ 𝑑𝑡 1 2⋅1
𝑇⋅ cos 2𝜋 ⋅ 2𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1 𝑇⋅1
2⋅ 𝑇 2
𝑇 2
1 2⋅1
𝑇⋅sin 2𝜋 ⋅ 2𝑓 ⋅ 𝑡 2𝜋 ⋅ 2𝑓
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1 2
1 2𝑇⋅ 1
2𝜋 ⋅ 2𝑓 sin 2𝜋 ⋅ 2𝑓 ⋅𝑇
2 sin 2𝜋 ⋅ 2𝑓 ⋅ 𝑇 2
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1 2
1 2𝑇⋅ 1
2𝜋 ⋅ 2𝑓 sin 2𝜋 sin 2𝜋
1
𝑇⋅ cos 2𝜋 ⋅ 𝑓 ⋅ 𝑡 ⋅ 𝑑𝑡 1 2
Average power in a periodic waveform s(t) Average power in
cos waveform
Power in AM Waveform
t A 1 m t cos 2 f t
s
c
c
2 c
c
2s
T
P s t A 1 m t cos 2 f t
S
c
2
2 2 2
c
s
A 1 2 m t m t cos 2 f t
P
2
c
22 2 c
2 c
2 c
2 c
2 c s
t f 2 cos t
m A
t f 2 cos t
m 2
A
t f 2 cos A
P
zero
mean
message
Power in AM
• Assume that the message is an independent, zero mean, random process
2
2
2 2 2
2
2
2
2 2
2 1 cos
lim 2
1 cos lim
T
T T c
c
T
T T c
c s
dt t
T f t
m A
dt t
T f A
P
22 2
c 2
s c
m t
2 A 2
P A
sb c
m 2
2 c 2
s
A
cA P P 2 P
P
Carrier and two
symmetric
sub-bands
Expected Value Math Note
• To compute power/energy we often take the expected value of the squared signal … particularly if random variables are involved.
– message is assumed to be a zero mean random variable – cosine could include a random phase offset
c c
c c
c
c c
c c
c c
c c
A P A
t m E A A
t m E t
m E A
t f t
m E t
f t
m E t
f E
A
t f t
m t
m E
A
t f t
m A
t v E
2 1 2
1
2 1 2
2 1 2 1
2 cos 2
cos 2
2 cos
2 cos 2
1
2 cos 1
2 2
2
2 2 2
2
2 2 2
2 2 2
2 2
2
2 2 2
2
2 2
t A m t f t
v
c 1 cos 2
c
Note: zero
thlag of the
autocorrelation function
Power Levels – Carrier Ratio
• Carrier to one sideband power
• Maximum magnitude of mod index and message
𝑃 𝑃
𝐴 2
1 2 ⋅ 𝐴
2 ⋅ 𝜇 ⋅ 𝑃
𝑃
𝑃 2
𝜇 ⋅ 𝑃
𝑃
𝑃 2
1 ⋅ 1 2 or 𝑃 1 2 ⋅ 𝑃
Power 4A
2 c
Ac228
Ac228
Carrier and symmetric
subbands
• Upper or Lower sideband to Total Signal power ratio
• At the maximum modulation index and message
Total Power Levels
or 𝑃
/1 4 ⋅ 𝑃
𝑃
/𝑃
1 2 ⋅ 𝐴
2 ⋅ 𝜇 ⋅ 𝑃 𝐴 2 𝐴
2 ⋅ 𝜇 ⋅ 𝑃
𝑃
/𝑃
1 ⋅ 1 2 2 ⋅ 1 ⋅ 1
𝑃
/𝑃
𝜇 ⋅ 𝑃
2 2 ⋅ 𝜇 ⋅ 𝑃
AM Signal Power Summary
• Most of the AM signal power is in the carrier.
– Less than 50% of the total signal power is in the message subbands !
• This seams like a waste of power, but it makes it easier to design an AM radio receiver !
– Lock on to the carrier
– Then demodulate the AM signal
DSB Power Levels
t A m t cos 2 f t
s
c
c
2 c
c
2DSB
T
P s t A m t cos 2 f t
S
2
c
2 c2
2
c
22 c
DSB
A m t cos 2 f t A m t cos 2 f t
P
2 P 1
A
P
DSB
c2
m
• All the power is in the message sidebands
Comparing AM and DSB
• DSB Power vs. 2 AM Sideband Power
– Assume 100% mod index, max m(t)=1 and the waveform maximum magnitudes are identical – For DSB, Ac=Amax
– For AM, Amax=Ac + Ac= 2ꞏAc
4 4 2 P
A 2 2 P
A P
P
2
m 2
2 max
m 2
max
sb
DSB
4+ times more message power
Comparing AM and DSB (2)
4 4 P
P
2 sb
DSB
Why would we use AM instead of DSB?
Power
c freq
m f
c f
f fc fm fc
m
c f
f
fcfm
Ac2 4 Ac2 28
Ac2 28
Ac24 Ac2 28
Ac2 28
Power
c freq
m f
c f
f fc fm fc
m
c f
f fc fm Ac28
Ac28
Ac28
Ac28
General Linear CW Modulation Concepts
• Baseband Signal
• Modulated Bandpass Signal
Bandpass signal
(a) Spectrum; (b) Waveform
Definition: 𝑉 𝑓
𝑋 𝑓 𝑓 𝑊 𝑓 𝑓 𝑊
0 0 𝑓 𝑓 𝑊 0 𝑓 𝑊 𝑓
Note: An artificial spectrum to show Conjugate symmetry about the modulation frequency
If the baseband signal crosses zero, the modulated signal envelope must go to zero and have a phase
reversal. (DSB w/SC only!)
Complex Signal Representation
• Conventional AM
• DSB (w/ suppressed carrier)
t A m t j f t
v
c 1 exp 2
c
t A m t j f t
v
c exp 2
c
t A j f t A m t j f t
v
c exp 2
c
c exp 2
c
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(a) Rotating phasor;
(b) Phasor diagram with rotation suppressed
CW Phasor Diagrams
t A t j f t j
v
complexexp 2
c t A t j
v
complexexp
Complex Phasor Representation
t j f t m t j f t
v exp 2
c exp 2
c
t m t j f t
v exp 2
c
AM Transmission - Blocks
• How do you make an AM signal?
2 fct
cos
tx Ac
t A
x
t
f t
s c 1 cos 2 c
t s t A 1 cos 2 f t cos 2 f t
s
c
m
c
AM Simulation
• SW CAD AM Circuits
– AMGen
– AMGenv2
Circuits: Bandpass Filter
• Passive RLC
C L jw
jw R
C L jw
jw f
H
|| 1
|| 1
L C w
w R j C
L jw jw R
C L jw
f jw
H 1
1
1 1
1 1
1
C w L
1
0
f f f
Q f w j
w w
w L
R C j f
H
0 0
0 0
1
1 1
1
L R C
Q
Q
BW f
0SW CAD Examples
• RLC BPF
– Fc=10 kHz BPF
• Sallen-Key LPF
– 6 th Order Butterworth, Fco=40 kHz
AM Transmission - Nonlinear
• Another way to make an AM signal?
t a x t a a x t f t a f t
x a a
t f a
t f t
x a
a t
x a t x a
t f t
f t
x t
x a t
f t
x a
t f t
x a t
f t
x a t NL
c c
c c
c c
c
c c
2 2 2 cos
2 cos 2 2
2 cos 2
cos 2
2 cos 2
cos 2
2 cos
2 cos 2
cos
2 2
1 2
2 1
2
2 2
2 1 2
2 1
2 2
2 1
2 2
1
t a a 2 x t cos 2 f t
s
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Spectral components in Non-linear AM Modulation
t a a x t a x t a a x t f t a f t
NL
c cos 2 2
c 2 2
cos 2 2
2 2
1 2
2 1
2
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DSB Balanced modulator
DSB Alternate Balanced Modulator
• Differentially balanced input drive
2 fc t
cos
AM Mod
AM Mod
t x1
1
c 2
A s
t
t A x
t
f t
s c cos 2 c
t A x t f t
AM
1
1 1 cos 2
t A x t f t
AM
2
2 1 cos 2
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cos 2 5 f t
5 t 1 f 3 2 3 cos t 1
f 2 1 cos t 1
square
c c cRing modulator
Using a Square Wave
• AM modulation using a square wave
f
cclock
t
x A
c t A x t f t
s
c 1 cos 2
c
t
s
Component Comments
• Built in to most ICs
• Linearity where desired
• 2 nd and 3 rd harmonics
• Filters …and more filters.
• LTC SwCAD Homework Problem
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