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*Corresponding author

E-mail address: [email protected] Received October 29, 2018

1

Available online at http://scik.org Eng. Math. Lett. 2019, 2019:5

https://doi.org/10.28919/eml/3940 ISSN: 2049-9337

STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF

HARMONIC MULTIVALENT FUNCTIONS

ABBAS KAREEM WANAS1,* AND FIRAS HUSSEAN MAGHOOL2 1Department of Mathematics, College of Science, University of Al-Qadisiyah, Iraq

2 Department of Mathematics, College of Computer Science and Information Technology, University of Al-Qadisiyah, Iraq

Copyright Β© 2019 the authors. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Abstract: In this paper, we define and investigate a new class for higher-order derivatives of harmonic multivalent functions. We obtain coefficient inequalities, distortion bounds, extreme points, convex combination. Our results extend corresponding previously known results.

Keywords: harmonic multivalent functions; extreme points; convex combination; higher-order derivatives.

2010 AMS Subject Classification: 30C45, 30C50.

1.

I

NTRODUCTION

A continuous function 𝑓 = 𝑒 + 𝑖𝑣 is a complex valued harmonic function in a complex

domain β„‚ , if both 𝑒 and 𝑣 are real harmonic in β„‚. In any simply connected domain 𝐷 βŠ‚ β„‚, we

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analytic part of 𝑓 . A necessary and sufficient condition for 𝑓 to be locally univalent and sense-preserving in 𝐷 is that |β„Žβ€²(𝑧)| > |𝑔′(𝑧)| in 𝐷 (see Clunie and Sheil-Small [3]).

Denote by 𝐾ℋ(𝑝) the class of functions 𝑓 = β„Ž + 𝑔 that are harmonic univalent and sense-

preserving in the open unit disk π‘ˆ = {𝑧 ∈ β„‚: |𝑧| < 1}. For 𝑓 = β„Ž + 𝑔 ∈ 𝐾ℋ(𝑝) , we may express

the analytic functions β„Ž and 𝑔 as

β„Ž(𝑧) = 𝑧𝑝+ βˆ‘ π‘Ž 𝑛𝑧𝑛

∞

𝑛=𝑝+1

, 𝑔(𝑧) = βˆ‘ 𝑏𝑛𝑧𝑛

∞

𝑛=𝑝

, |𝑏𝑝| < 1 . (1.1)

Also denote by π‘Šβ„‹(𝑝) the subclass of 𝐾ℋ(𝑝) containing of all functions 𝑓 = β„Ž + 𝑔 , where β„Ž

and 𝑔are given by

β„Ž(𝑧) = π‘§π‘βˆ’ βˆ‘ π‘Ž 𝑛𝑧𝑛

∞

𝑛=𝑝+1

, 𝑔(𝑧) = βˆ’ βˆ‘ 𝑏𝑛𝑧𝑛

∞

𝑛=𝑝

, (π‘Žπ‘› β‰₯ 0, 𝑏𝑛 β‰₯ 0, |𝑏𝑝| < 1 ) . (1.2)

We denote by 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) the class of all functions of the form (1.1) that satisfy the

condition:

𝑅𝑒 {𝑧𝑓

(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧)} > 𝛽 |

𝑧𝑓(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧)βˆ’ 1| + 𝛼, (1.3)

where 𝑝 ∈ 𝑁 = {1,2, … }, π‘ž ∈ π‘π‘œ= 𝑁 βˆͺ {0} , 𝑝 > π‘ž , 0 ≀ 𝛼 < 𝑝 βˆ’ π‘ž , 𝛽 β‰₯ 0 , 0 ≀ 𝛾 < 1 and

for each 𝑓 = β„Ž + 𝑔̅ ∈ 𝐾𝐻(𝑝), we have

𝑓(π‘ž)(𝑧) = 𝛿(𝑝, π‘ž)π‘§π‘βˆ’π‘ž+ βˆ‘ 𝛿(𝑛, π‘ž)π‘Ž 𝑛 ∞

𝑛=𝑝+1

π‘§π‘›βˆ’π‘ž+ βˆ‘ 𝛿(𝑛, π‘ž)𝑏 𝑛 (𝑧̅ ∞

𝑛=𝑝

)π‘›βˆ’π‘ž,

𝛿(𝑝, π‘ž) = 𝑝!

(𝑝 βˆ’ π‘ž)!= {

1 (π‘ž = 0)

𝑝(𝑝 βˆ’ 1) … (𝑝 βˆ’ π‘ž + 1) (π‘ž β‰  0) .

Let π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) be the subclass of 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽), where

π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) = π‘Šβ„‹(𝑝) ∩ 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Remark 1.1.

(1) If 𝑝 = 1 and π‘ž = 0, we have π΄π‘Šβ„‹(1,0, 𝛾, 𝛼, 𝛽) = πΎπ‘Šβ„‹(𝛾, 𝛼, 𝛽) which was studied

by Atshan and Wanas [2].

(2) If 𝑝 = 1and π‘ž = 𝛽 = 0, we have π΄π‘Šβ„‹(1,0, 𝛾, 𝛼, 0) = 𝐢(𝛾, 𝛼) which was studied by

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STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF HARMONIC MULTIVALENT …

(3) If 𝑝 = 1 and π‘ž = 𝛾 = 𝛽 = 0, we have π΄π‘Šβ„‹(1,0,0, 𝛼, 0) = 𝐢(𝛼) which was studied by

Silverman [5] for analytic part.

Lemma 1.1. (Aqlan, [1]) Let 𝑀 = 𝑒 + 𝑖𝑣 and πœ‡ be a real number. Then 𝑅𝑒(𝑀) β‰₯ πœ‡ if and

only if

|𝑀 + (1 βˆ’ πœ‡)| β‰₯ |𝑀 βˆ’ (1 + πœ‡)|.

Lemma 1.2. (Aqlan, [1]) Let 𝑀 = 𝑒 + 𝑖𝑣 and πœ‡, 𝑑 be a real number. Then 𝑅𝑒(𝑀) β‰₯

πœ‡|𝑀 βˆ’ 1| + 𝑑 if and only if

𝑅𝑒{𝑀(1 + πœ‡π‘’π‘–πœƒ) βˆ’ πœ‡π‘’π‘–πœƒ} β‰₯ 𝑑 (βˆ’πœ‹ ≀ πœƒ ≀ πœ‹).

2.

M

AIN RESULT

In our first theorem, we introduce a sufficient coefficient bound for harmonic function in

𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Theorem 2.1. Let 𝑓 = β„Ž + 𝑔 with β„Ž and 𝑔 are given by (1.1). If

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼](|π‘Žπ‘›| + |𝑏𝑛|)

∞

𝑛=𝑝+1

≀ 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) βˆ’ 𝛼](1 βˆ’ |𝑏𝑝|), (2.1)

where 𝑝 ∈ 𝑁, π‘ž ∈ 𝑁0 , 𝑝 > π‘ž, 0 ≀ 𝛼 < 𝑝 βˆ’ π‘ž , 𝛽 β‰₯ 0 , 0 ≀ 𝛾 < 1, then 𝑓 is harmonic

multivalent sense preserving in π‘ˆ and 𝑓 ∈ 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Proof. For proving 𝑓 ∈ 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽), we must show that (1.3) holds true. by using Lemma

1.2 , it is sufficient to show that

𝑅𝑒 {𝑧𝑓(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧)(1 + π›½π‘’π‘–πœƒ) βˆ’ π›½π‘’π‘–πœƒ} > 𝛼 (βˆ’πœ‹ ≀ πœƒ ≀ πœ‹) ,

or equivalently

𝑅𝑒 {(1 + 𝛽𝑒

π‘–πœƒ)(𝑧𝑓(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)) βˆ’ π›½π‘’π‘–πœƒ(𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧))

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧) } > 𝛼.

If we put

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and

𝑀(𝑧) = 𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧).

In view of Lemma 1.1, we only need to prove that

|𝐿(𝑧) + (1 βˆ’ 𝛼)𝑀(𝑧)| βˆ’ |𝐿(𝑧) βˆ’ (1 + 𝛼)𝑀(𝑧)| β‰₯ 0.

Now,

|𝐿(𝑧) + (1 βˆ’ 𝛼)𝑀(𝑧)|

= |(1 + π›½π‘’π‘–πœƒ) ( 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 2)! π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 2)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘(𝑛 βˆ’ π‘ž βˆ’ 2)!𝑛! 𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

+ 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)!π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

)

βˆ’π›½π‘’π‘–πœƒ( 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)!π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

+ 𝛾𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 2)!π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝛾𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 2)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝛾𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 2)!𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

)

+(1 βˆ’ 𝛼) ( 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)!π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)!𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

+ 𝛾𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 2)!π‘§π‘βˆ’π‘žβˆ’1+ βˆ‘

𝛾𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 2)!π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1+

∞

𝑛=𝑝+1

βˆ‘ 𝛾𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 2)!𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

)|

= | 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![((𝑝 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑝 βˆ’ π‘ž + 1 βˆ’ 𝛼)] π‘§π‘βˆ’π‘žβˆ’1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑛 βˆ’ π‘ž + 1 βˆ’ 𝛼]π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑛 βˆ’ π‘ž + 1 βˆ’ 𝛼]𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

|

β‰₯ 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑝 βˆ’ π‘ž + 1 βˆ’ 𝛼]|𝑧|π‘βˆ’π‘žβˆ’1

βˆ’ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑛 βˆ’ π‘ž + 1 βˆ’ 𝛼]|π‘Žπ‘›||𝑧|π‘›βˆ’π‘žβˆ’1

∞

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STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF HARMONIC MULTIVALENT …

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + (1 βˆ’ 𝛼)𝛾) + 𝑛 βˆ’ π‘ž + 1 βˆ’ 𝛼]|𝑏𝑛||𝑧|π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

.

Similarly

|𝐿(𝑧) βˆ’ (1 + 𝛼)𝑀(𝑧)|

= | βˆ’π‘!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(𝛾 βˆ’ 1) + (1 + 𝛼)𝛾) βˆ’ 𝑝 + π‘ž + 1 + 𝛼]π‘§π‘βˆ’π‘žβˆ’1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) + (1 + 𝛼)𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 1 βˆ’ 𝛼]π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) βˆ’ (1 + 𝛼)𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 1 βˆ’ 𝛼]𝑏𝑛(𝑧)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

|

≀ 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(𝛾 βˆ’ 1) + (1 + 𝛼)𝛾) βˆ’ 𝑝 + π‘ž + 1 + 𝛼]|𝑧|π‘βˆ’π‘žβˆ’1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ (1 + 𝛼)𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 1 βˆ’ 𝛼] |π‘Žπ‘›||𝑧|π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ (1 + 𝛼)𝛾) + 𝑛 βˆ’ π‘ž + 1 βˆ’ 𝛼]|𝑏𝑛||𝑧|π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

.

Then

|𝐿(𝑧) + (1 βˆ’ 𝛼)𝑀(𝑧)| βˆ’ |𝐿(𝑧) βˆ’ (1 + 𝛼)𝑀(𝑧)|

β‰₯ 2𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

βˆ’ βˆ‘ 2𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]|π‘Žπ‘›|

∞

𝑛=𝑝+1

βˆ’ βˆ‘ 2𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]|𝑏𝑛| β‰₯

∞

𝑛=𝑝

0.

The harmonic multivalent function

𝑓(𝑧) = 𝑧𝑝+ βˆ‘ (𝑛 βˆ’ π‘ž βˆ’ 1)! π‘₯𝑛

𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑧𝑛

∞

𝑛=𝑝+1

+ βˆ‘ (𝑛 βˆ’ π‘ž βˆ’ 1)! 𝑦𝑛

𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼](𝑧)𝑛

∞

𝑛=𝑝

(6)

where

οƒ₯

ο‚₯

+ =p 1

n

|π‘₯𝑛| +

οƒ₯

ο‚₯

=p n

|𝑦𝑛| =(π‘βˆ’π‘žβˆ’1)!𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼], show that

the coefficient bound given by (2.1) is sharp. The functions of the form (2.2) are in the class

𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽), because

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝+1

Γ—

Γ— (𝑛 βˆ’ π‘ž βˆ’ 1)! |π‘₯𝑛|

𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

Γ—

Γ— (𝑛 βˆ’ π‘ž βˆ’ 1)! |𝑦𝑛|

𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

= βˆ‘ |π‘₯𝑛|

∞

𝑛=𝑝+1

+ βˆ‘|𝑦𝑛|

∞

𝑛=𝑝

= 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼].

The restriction placed in Theorem 2.1 on the moduli of the coefficients of 𝑓 = β„Ž + 𝑔 enables

us to conclude for arbitrary rotation of the coefficients of 𝑓 that the resulting functions would

still be harmonic multivalent and 𝑓 ∈ 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

In the following theorem, it is shown that the condition (2.1) is also necessary for functions in

π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Theorem 2.2. Let 𝑓 = β„Ž + 𝑔 with β„Ž and 𝑔 are given by (1.2) . Then 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) if and

only if

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]π‘Žπ‘›

∞

𝑛=𝑝+1

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑏𝑛

∞

𝑛=𝑝

≀𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! , (2.3)

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STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF HARMONIC MULTIVALENT …

Proof. Since π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) βŠ‚ 𝐴𝐾ℋ(𝑝, π‘ž, 𝛾, 𝛼, 𝛽), we only need to prove the "only if " part of

the theorem. Assume that 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽). Then by (1.3), we have

𝑅𝑒 {𝑧𝑓(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧)(1 + π›½π‘’π‘–πœƒ) βˆ’ π›½π‘’π‘–πœƒ} > 𝛼,

This is equivalent to

𝑅𝑒 {(1 + 𝛽𝑒

π‘–πœƒ) (𝑧𝑓(π‘ž+2)(𝑧) + 𝑓(π‘ž+1)(𝑧)) βˆ’ π›½π‘’π‘–πœƒ(𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧))

𝑓(π‘ž+1)(𝑧) + 𝛾𝑧𝑓(π‘ž+2)(𝑧) }

= 𝑅𝑒 {

𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(π›½π‘’π‘–πœƒ(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]π‘§π‘βˆ’π‘žβˆ’1 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑝 βˆ’ π‘ž βˆ’ 1))π‘§π‘βˆ’π‘žβˆ’1βˆ’ βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑝 βˆ’ π‘ž βˆ’ 1))π‘Žπ‘›! π‘›π‘§π‘›βˆ’π‘žβˆ’1

βˆ’βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽𝑒𝑛! π‘–πœƒ(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]π‘Žπ‘›π‘§π‘›βˆ’π‘žβˆ’1

βˆ’βˆ‘βˆž (𝑛 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑝 βˆ’ π‘ž βˆ’ 1))𝑏𝑛! 𝑛(𝑍̅)π‘›βˆ’π‘žβˆ’1 𝑛=𝑝

βˆ’ βˆ‘ (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽𝑒𝑛! π‘–πœƒ(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑏

𝑛(𝑍̅)π‘›βˆ’π‘žβˆ’1

∞

𝑛=𝑝

} β‰₯ 0. (2.4)

The above required condition (2.4) must hold for all values of 𝑧 in π‘ˆ. Upon choosing the values

of 𝑧 on the positive real axis where 0 ≀ 𝑧 = π‘Ÿ < 1, we must have

𝑅𝑒 { 𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)! [𝑝 βˆ’ π‘ž βˆ’ 𝛼 βˆ’ 𝛼𝛾(𝑝 βˆ’ π‘ž βˆ’ 1)]π‘Ÿπ‘βˆ’π‘žβˆ’1βˆ’ βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)! [𝑛 βˆ’ π‘ž βˆ’ 𝛼 βˆ’ 𝛼𝛾(𝑛 βˆ’ π‘ž βˆ’ 1)]π‘Žπ‘›! 𝑛 π‘Ÿπ‘›βˆ’π‘žβˆ’1

𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑝 βˆ’ π‘ž βˆ’ 1))π‘Ÿπ‘βˆ’π‘žβˆ’1βˆ’ βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑛 βˆ’ π‘ž βˆ’ 1))π‘Žπ‘›! 𝑛 π‘Ÿπ‘›βˆ’π‘žβˆ’1

βˆ’ βˆ‘βˆžπ‘›=𝑝(𝑛 βˆ’ π‘ž βˆ’ 1)! [𝑛 βˆ’ π‘ž βˆ’ 𝛼 βˆ’ 𝛼𝛾(𝑛 βˆ’ π‘ž βˆ’ 1)]𝑏𝑛! 𝑛 π‘Ÿπ‘βˆ’π‘žβˆ’1βˆ’π›½π‘’π‘–πœƒ[(𝑝 βˆ’ π‘ž βˆ’ 1)! (𝑝 βˆ’ π‘ž βˆ’ 1)(𝛾 βˆ’ 1)π‘Ÿπ‘! π‘βˆ’π‘žβˆ’1

βˆ’ βˆ‘βˆžπ‘›=𝑝(𝑛 βˆ’ π‘ž βˆ’ 1)! (1 + 𝛾(𝑛 βˆ’ π‘ž βˆ’ 1))𝑏𝑛! 𝑛 π‘Ÿπ‘›βˆ’π‘žβˆ’1

βˆ’ βˆ‘π‘›=𝑝+1∞ (𝑛 βˆ’ π‘ž βˆ’ 1)! (𝑛 βˆ’ π‘ž βˆ’ 1)(1 βˆ’ 𝛾)π‘Žπ‘›! 𝑛 π‘Ÿπ‘βˆ’π‘žβˆ’1+ βˆ‘βˆžπ‘›=𝑝(𝑛 βˆ’ π‘ž βˆ’ 1)! (𝑛 βˆ’ π‘ž βˆ’ 1)(1 βˆ’ 𝛾)𝑏𝑛! 𝑛 π‘Ÿπ‘βˆ’π‘žβˆ’1]

} β‰₯ 0.

Since 𝑅𝑒(-π‘’π‘–πœƒ) β‰₯ βˆ’|π‘’π‘–πœƒ| = βˆ’1, and letting π‘Ÿ ⟢ 1βˆ’, the above inequality reduces to

𝑝!

(𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] βˆ’ βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)!𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]π‘Žπ‘›

𝑝!

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βˆ’ βˆ‘βˆžπ‘›=𝑝+1(𝑛 βˆ’ π‘ž βˆ’ 1)!𝑛! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑏𝑛

β‰₯ 0.

This gives (2.3), and the poof is complete.

Next, we establish the distortion bounds for the function in π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) which yields a

covering result for this class.

Theorem 2.3. Let 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽). Then for |𝑧| = π‘Ÿ < 1, we have

|𝑓(𝑧)| β‰₯ (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’ (𝑝 βˆ’ π‘ž)[(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼](1 βˆ’ 𝑏𝑝)

(𝑝 + 1)[(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼] (2.5)

and

|𝑓(𝑧)| ≀ (1 + 𝑏𝑝)π‘Ÿπ‘+

(𝑝 βˆ’ π‘ž)[(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼](1 βˆ’ 𝑏𝑝)

(𝑝 + 1)[(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼] . (2.6)

Proof. Assume that 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽). Then by (2.3), we get

|𝑓(𝑧)| = |π‘§π‘βˆ’ βˆ‘ π‘Ž 𝑛𝑧𝑛

∞

𝑛=𝑝+1

βˆ’ βˆ‘ 𝑏𝑛(𝑧)𝑛

∞

𝑛=𝑝

| β‰₯ (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’ βˆ‘ (π‘Žπ‘› + 𝑏𝑛)π‘Ÿπ‘›

∞

𝑛=𝑝+1

β‰₯ (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’ βˆ‘ (π‘Žπ‘›+ 𝑏𝑛)π‘Ÿπ‘+1

∞

𝑛=𝑝+1

= (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’ (𝑝 βˆ’ π‘ž)!

(𝑝 + 1)! [(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼]Γ—

Γ— βˆ‘ (𝑝 + 1)! [(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼] (𝑝 βˆ’ π‘ž)!

∞

𝑛=𝑝+1

(π‘Žπ‘›+ 𝑏𝑛)π‘Ÿπ‘+1

β‰₯ (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’ (𝑝 βˆ’ π‘ž)!

(𝑝 + 1)! [(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼]

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝+1

(π‘Žπ‘›+ 𝑏𝑛)π‘Ÿπ‘+1

β‰₯ (1 βˆ’ 𝑏𝑝)π‘Ÿπ‘βˆ’(𝑝 βˆ’ π‘ž)[(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼](1 βˆ’ 𝑏𝑝)

(𝑝 + 1)[(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼] .

Relation (2.6) can be proved by using the similar statements. So the proof is completes.

The following covering result follows from the inequality (2.5) of theorem 2.3.

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STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF HARMONIC MULTIVALENT … {𝑀: |𝑀| < (1 βˆ’ 𝑏𝑝) βˆ’

(𝑝 βˆ’ π‘ž)[(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼](1 βˆ’ 𝑏𝑝)

(𝑝 + 1)[(𝑝 βˆ’ π‘ž)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 1 βˆ’ 𝛼] } βŠ‚ 𝑓(π‘ˆ)

In the next result, we discuss extreme points of π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Theorem2.4. Let 𝑓 be given by (1.2). Then 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) if and only if 𝑓 can be

expressed as

𝑓(𝑧) = βˆ‘(πœŽπ‘›β„Žπ‘›(𝑧) + πœ‰π‘›π‘”π‘›(𝑧)) ∞

𝑛=𝑝

, (𝑧 ∈ π‘ˆ),

where β„Žπ‘(𝑧) = 𝑧𝑝,

β„Žπ‘›(𝑧) = π‘§π‘βˆ’ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑧𝑛, 𝑛 = 𝑝 + 1, 𝑝 + 2, …

and

𝑔𝑛(𝑧) = π‘§π‘βˆ’

𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼](𝑧̅)𝑛, 𝑛 = 𝑝, 𝑝 + 1, … ,

βˆ‘(πœŽπ‘› + πœ‰π‘›) ∞

𝑛=𝑝

= 1, (πœŽπ‘› β‰₯ 0, πœ‰π‘› β‰₯ 0).

Inparticular , the extreme points of π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) are {β„Žπ‘›} and {𝑔𝑛}.

Proof: Assume that 𝑓 can be expressed by (2.7). Then, we have

𝑓(𝑧) = βˆ‘(πœŽπ‘›β„Žπ‘›(𝑧) + πœ‰π‘›π‘”π‘›(𝑧)) ∞

𝑛=𝑝

= βˆ‘(πœŽπ‘›+ πœ‰π‘›)𝑧𝑝 ∞

𝑛=𝑝

βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝+1

πœŽπ‘›π‘§π‘›

βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] 𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

πœ‰π‘›(𝑧̅)𝑛

= π‘§π‘βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝+1

πœŽπ‘›π‘§π‘›

βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] 𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

πœ‰π‘›(𝑧̅)𝑛.

(10)

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛 =𝑝+1

Γ—

Γ— 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] 𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]πœŽπ‘›

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

Γ—

Γ— 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] 𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]πœ‰π‘›

=𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! (βˆ‘(πœŽπ‘›+ πœ‰π‘›)

∞

𝑛=𝑝

βˆ’ πœŽπ‘)

= 𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! (1 βˆ’ πœŽπ‘)

≀ 𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! ,

and so 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

Conversely, let 𝑓 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽). putting

πœŽπ‘›=𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] π‘Žπ‘›, (𝑛 = 𝑝 + 1, 𝑝 + 2, … )

and

πœ‰π‘› =

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼] 𝑏𝑛, (𝑛 = 𝑝, 𝑝 + 1, … ).

We define πœŽπ‘ = 1 βˆ’ βˆ‘βˆžπ‘›=𝑝+1πœŽπ‘›βˆ’ βˆ‘βˆžπ‘›=π‘πœ‰π‘›. There fore

𝑓(𝑧) = π‘§π‘βˆ’ βˆ‘ π‘Ž

π‘›π‘§π‘›βˆ’ βˆ‘ 𝑏𝑛 ∞

𝑛=𝑝

(𝑧̅)𝑛

∞

𝑛=𝑝+1

= π‘§π‘βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]πœŽπ‘›π‘§π‘›

∞

𝑛 =𝑝+1

βˆ’ βˆ‘ 𝑝! (𝑛 βˆ’ π‘ž βˆ’ 1)! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

𝑛! (𝑝 βˆ’ π‘ž βˆ’ 1)! [(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) + 1 βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]πœ‰π‘›(𝑧̅)𝑛

∞

𝑛=𝑝

= π‘§π‘βˆ’ βˆ‘ (π‘§π‘βˆ’ β„Ž

𝑛(𝑧))πœŽπ‘› βˆ’ βˆ‘ (π‘§π‘βˆ’ 𝑔𝑛(𝑧))πœ‰π‘› ∞

𝑛 =𝑝 ∞

(11)

STUDY OF A NEW CLASS FOR HIGHER-ORDER DERIVATIVES OF HARMONIC MULTIVALENT … = (1 βˆ’ βˆ‘ πœŽπ‘›βˆ’ βˆ‘ πœ‰π‘›

∞ 𝑛 =𝑝 ∞ 𝑛 =𝑝+1 ) 𝑧𝑝+ βˆ‘ 𝜎 π‘›β„Žπ‘›(𝑧) βˆ’ βˆ‘ πœ‰π‘› 𝑔𝑛(𝑧) ∞ 𝑛 =𝑝 ∞ 𝑛 =𝑝+1 = πœŽπ‘β„Žπ‘(𝑧) + βˆ‘ πœŽπ‘›β„Žπ‘›(𝑧) βˆ’ βˆ‘ πœ‰π‘› 𝑔𝑛(𝑧) ∞ 𝑛 =𝑝 ∞ 𝑛 =𝑝+1 = βˆ‘ (πœŽπ‘›β„Žπ‘›(𝑧) + πœ‰π‘› 𝑔𝑛(𝑧)) ∞ 𝑛 =𝑝 ,

and this completes the proof of theorem 2.4.

Theorem 2.5. The class π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) is closed under convex combinations.

Proof. For 𝑗 = 1,2,3, …, let 𝑓𝑗 ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽) where 𝑓𝑗 is given by

𝑓𝑗(𝑧) = π‘§π‘βˆ’ βˆ‘ π‘Ž 𝑛,π‘—π‘§π‘›βˆ’ βˆ‘ 𝑏𝑛,𝑗 ∞ 𝑛=𝑝 (𝑧̅)𝑛 ∞ 𝑛=𝑝+1 .

Then by (2.3), we have

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛 =𝑝+1

π‘Žπ‘›,𝑗

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

𝑏𝑛,𝑗

≀ 𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! (2.8)

For βˆ‘βˆžπ‘—=1 πœ†π‘— = 1 , 0 ≀ πœ†π‘— ≀ 1, the convex combination of 𝑓𝑗 may be written as

βˆ‘ πœ†π‘— ∞ 𝑗=1 𝑓𝑗(𝑧) = π‘§π‘βˆ’ βˆ‘ (βˆ‘ πœ†π‘— ∞ 𝑗=1 π‘Žπ‘›,𝑗) π‘π‘›βˆ’ βˆ‘ (βˆ‘ πœ†π‘— ∞ 𝑗=1 𝑏𝑛,𝑗) ∞ 𝑛=𝑝 (𝑧̅)𝑛 ∞ 𝑛=𝑝+1 .

Then by (2.8), we have

βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞ 𝑛 =𝑝+1 (βˆ‘ πœ†π‘— ∞ 𝑗=1 π‘Žπ‘›,𝑗) + βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞ 𝑛=𝑝 (βˆ‘ πœ†π‘— ∞ 𝑗=1 𝑏𝑛,𝑗) = βˆ‘ πœ†π‘— ∞ 𝑗=1 { βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛 =𝑝+1

(12)

+ βˆ‘ 𝑛!

(𝑛 βˆ’ π‘ž βˆ’ 1)![(𝑛 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑛 βˆ’ π‘ž βˆ’ 𝛼]

∞

𝑛=𝑝

𝑏𝑛,𝑗}

≀ βˆ‘ πœ†π‘—

∞

𝑗=1

𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)!

= 𝑝! [(𝑝 βˆ’ π‘ž βˆ’ 1)(𝛽(1 βˆ’ 𝛾) βˆ’ 𝛼𝛾) + 𝑝 βˆ’ π‘ž βˆ’ 𝛼]

(𝑝 βˆ’ π‘ž βˆ’ 1)! .

Therefore

βˆ‘ πœ†π‘— ∞

𝑗=1

𝑓𝑗(𝑧) ∈ π΄π‘Šβ„‹(𝑝, π‘ž, 𝛾, 𝛼, 𝛽).

This completes the proof.

Conflict of Interests

The authors declare that there is no conflict of interests.

REFERENCES

[1] E. S. Aqlan, Some Problems Connected with Geometric Function Theory, Ph. D. Thesis, Pure University, Pure, 2004.

[2] W. G. Atshan, A. K. Wanas, On a new class of harmonic univalent function, Matematicki vesnik 65(4)(2013), 555-564.

[3] J. Clunie, T. Sheil-Small, Harmonic univalent functions, Ann. Acad. Aci. Fenn. Ser. A. I. Math. 9 (1984), 3-25. [4] A. O. Mostafa, A study on starlike and convex properties for hypergeometric functions, J. Ineq. Pure Appl.

Math. 10(3)(2009), Art. 87, 1-8.

References

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