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System For Finding Location Domination Number Of A

Graph By The Fusion Of Vertex

Rajasekar. G

1

, Nagarajan. K

2

Department of Mathematics1,2, Jawahar Science College, Neyveli1,2 Email: grsmaths@gmail.com1 , n2a4g1r1j1@gmail.com2

Abstract- Locating-Dominating set (LD -set) of a graph , is a dominating set with the property that every vertices v in V G

 

S can be identified uniquely by the set of neighbours of v which are in S. In this paper a procedure for finding the locating-domination number of graph obtained by fusion of a single vertex from two graphs has been formulated. By this procedure the location domination number of Cm Cn, Windmill graph,

Dutch windmill graph and Friendship graph are been found.

Keywords-Dominating set; Locating set; Locating domination set; Fusion of vertex

1. INTRODUCTION

For any vertex v in V G

 

S, S v

 

is the set of vertices in S which are adjacent tov. Locating-dominating set was introduced by Slater [1, 2] which is defined as follows. A dominating set S is defined to be a locating-dominating set if S v( )S w( ), for anyv w V G, 

 

S. A locating dominating set is denoted by LD-set. The minimum cardinalities of an

LD-set in G is called the location-domination number of G and it is denoted by RD G( ). An LD -set with RD G( ) elements is called as a referencing-dominating set or an RD-set. The set of all RD-set of the given graph is denoted by S .

G. Rajasekar et al [3,4,5] have found location domination number of sum of graphs, graph connected by bridge and graph obtained by fusion of vertex.

The windmill graph Kn m or Wd n m

,

is the graph obtained by taking copies of the complete graph Kn with a vertex in common. The Dutch windmill graph Dn m is the graph obtained by taking

copies of the cycle Cn with a vertex in common.

2. PRELIMINARIES

Let G be the graph obtained from G1 and G2 by vertex fusion of vertices v1G1 and v2G2 to form a single new vertex v. Let us denote this graph G by

 

1 1

GG v G v2

 

2 .

Theorem 2.1. [4]: Let G1,G2 be any two graphs and

G be a graph obtained by fusion of vertices v1G1

and v2G2 to form a single vertex v, then

 

1

 

2 2

 

 

1

 

2

RD GRD G  RD GRD GRD G

Theorem 2.2. [4]: Let G1, G2 be any two graphs and

 

1 1

GG v G v2

 

2 . Fori1, 2, let Gi have an

RD-set Si such that viSi and S ui

   

ivi for all

 

i i i

uV GS.then RD G

 

RD G

 

1RD G

 

2 2

if and only if for i1, 2, Si

 

vi is the RD-set of

 

i i

Gv and

 

Φ

i

G i i

N v S  .

Theorem 2.3. [4]: Let G1, G2 be any two graphs and

 

1 1

GG v G v2

 

2 . If for both i1 and2 vi does

not belongs to anyone of the RD-set of Gi then

 

 

1

 

2

RD GRD GRD G .

Theorem 2.4. [4]: LetG1, G2 be any two graphs and

 

1 1

GG v G v2

 

2 . Let either G1 or G2 has atleast one RD-set S1 or S2 respectively such that

1 1

vS or v2S2 (say v1S1). If S1

 

v1 is the

RD-set of G1

 

v1 for some RD-set S1 then

 

RD G will be equal RD G

 

1RD G

 

2 1

otherwise RD G

 

will be equal RD G

 

1RD G

 

2 .

Theorem 2.5. [4]: Let G1, G2 be any two graphs and

 

1 1

GG v G v2

 

2 . Fori1, 2, let Gi have an

RD-set Si such thatviSi. If for every RD-set Si, there exist a vertex uiV G

 

iSi such that

   

i i i

S uv for both i1 and 2 then

 

 

1

 

2

RD GRD GRD G .

Theorem 2.6. [4]: Let G1, G2 be any two graphs and

 

1 1

GG v G v2

 

2 . For i1, 2, let Gi have an

RD-set Si such that viSi. If G2 has an RD-set 2

S such that S u2

   

2v2 for all u2V G

 

2S2 and G1 have no RD-set S1 such that S u1

   

1v1

for all u1V G

 

1S1 then

 

 

1

 

2 1

RD GRD GRD G  .

Remark2.1. [4]: Let G1, G2 be any two graphs and

 

1 1

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76

RD-set Si such that viSi and S ui

   

ivi for all

 

i i i

uV GS . For either i1 or 2 if Gi does not have any RD-set Si satisfying the both conditions

(i) Si

 

vi is the RD-set of Gi

 

vi (ii)

 

i

G i i

N v S  

then RD G

 

RD G

 

1RD G

 

2 1.

3. LOCATION DOMINATION NUMBER OF

A GRAPH BY THE FUSION OF VERTEX

Algorithm for finding location domination number of graph obtained by fusion of vertex is formulated with the aid of Theorem 2.2, 2.3, 2.4, 2.5, 2.6 and Remark 2.1. We see that location domination number of graph obtained by fusion of vertex depends on three feature of RD-set of the graph. The three properties are defined as follows:

Property 1: G has an RD-set SS such that vS

and S

 

v is the RD-set of G

 

v where v is the vertex considered for fusion.

Property 2: G has atleast one RD-set SS such that S u

   

v for all u V G

 

S and v is the considered for fusion.

Property 3: G has an RD-set SS such that vS

and NG

 

v S  where v is the vertex considered for fusion.

Based on these three properties we formulate a procedure in form of Table 1. and Table 2. to find the location domination number of graphs obtained by fusion of vertex.

Remark 3.1. Let GG v1

 

1 G v2

 

2 where v1 and 2

v are fused to form a single vertex v. If one of the following condition is true then RD-set S of G

doesn’t contains the vertex v.

(i) Both G1 and G2 doesn’t have any RD-set which contains the vertex v1 and v2 respectively (ii) Both G1 and G2 have any RD-set satisfying

Property 1, Property 2 and Property 3 simultaneously

Remark 3.2. If graph G doesn’t satisfy Property 1 then there is no need to check Property 3.

Table 1. Procedure for finding the location domination number of graphs obtained by fusion of vertex- Table 1

 

RD G v2S2 for all S2S2 v2S2 for some S2S2

1 1

vS for all S1S1 RD G

 

1 RD G

 

2

If G2 satisfies Property 1 then

 

 

1

 

2 1

RD GRD GRD G

otherwise

 

 

1

 

2

RD GRD GRD G

1 1

vS for some S1S1

If G1 satisfies Property 1 then

 

 

1

 

2 1

RD GRD GRD G

otherwise

 

 

1

 

2

RD GRD GRD G

Check Property 2 for the graph 1

[image:2.595.73.521.413.589.2]

G and G2. And refer Table 2

Table 2. Procedure for finding the location domination number of graphs obtained by fusion of vertex- Table 2

 

RD G G2 satisfies Property 2 G2 doesn’t satisfy Property 2

1

G satisfies Property 2

If both graphs G1 and G2 have RD-sets which satisfies Property 1, Property 2 and Property 3 simultaneously then

 

 

1

 

2 2

RD GRD GRD G

otherwise

 

 

1

 

2 1

RD GRD GRD G

 

 

1

 

2 1

RD GRD GRD G

1

G doesn’t satisfy

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77

4. LOCATION DOMINATION NUMBER OF

m

C Cn, WINDMILL GRAPH, DUTCH

WINDMILL GRAPH AND FRIENDSHIP GRAPH

This section deals with finding location domination number of Cm Cn, Windmill graph, Dutch windmill graph and Friendship graph which are obtained by vertex fusion. So let us first study the properties of Cn

and Kn related to vertex fusion.

Properties of Cn: Let the vertex label of Cn be 1, 2,..., n1, n

v v vv . For cycle it is always possible to have

a RD-set which contains the vertex considered for fusion.

 For n4,

v v1, 2

 

, v v2, 3

 

, v v3, 4

and

v v4, 1

are the possible RD-set. And Property 1 and Property 2 are not satisfied for any of the possible

RD-set.

 For n0 mod 5, i.e. n5k, k1.

v v v v2, 4, 7, ,...,9 v5k8,v5k6,v5k3,v5k1

is the only possible RD-set and it doesn’t satisfies Property 1, Property 2 as well as Property 3.

 For n1mod 5, i.e. n5k1, k1.

v v v v2, 4, 7, ,...,9 v5k3,v5k1,v5k1

is a RD-set such that

v v v v2, 4, 7, ,...,9 v5k3,v5k1

is the RD-set of

5 1

n k

Cv and S v

  

iv5k1

for all

  

2, 4, 7, ,...,9 5 3, 5 1, 5 1

i n k k k

vV Cv v v v v v v . Hence Property 1 and Property 2 is satisfied with respect to vertex v5k1. Whereas none of the vertices in the set

v v v v2, 4, 7, ,...,9 v5k3,v5k1,v5k1

are adjacent, so Property 3 is not satisfied.

 For n2 mod 5, i.e. n5k2, k1.

v v v v2, 4, 7, ,...,9 v5k3,v5k1,v5k2

is a RD-set such that S v

   

iv1 for all

  

2, 4, 7, ,...,9 5 3, 5 1, 5 2

i n k k k

vV Cv v v v v v v . Hence Property 2 is satisfied with respect to vertex v1. Whereas Property 1 and Property 3 is not fulfilled.

 For n3mod 5, i.e. n5k3, k0.

v v v v2, , , ,...,4 7 9 v5k3,v5k1,v5k2,v5k3

is a RD-set such that v5k3 satisfies Property 1, Property 2 and Property 3

 For n4 mod 5, i.e. n5k4, k1.

2, 4, 7, ,...,9 5k 3, 5k 1, 5k 2, 5k 4

Sv v v v vvvv  is a

RD-set such that S v

  

iv5k4

for all

 

i n

vV CS. Hence Property 2 is satisfied with respect to vertex v5k4. But Property 1 and Property 3 is not fulfilled.

Properties of Cn are concatenated in the following Table 3

Properties of Kn: Let the vertex label of Kn be 1, 2,..., n1, n

v v vv . For complete graph it is always

possible to have a RD-set which contains the vertex considered for fusion.

For n2, Property 1, Property 2 and Property 3 fails.

Clearly for n3, S

v v1, 2,..., vn2,vn1

is an

RD-set such that S

 

v1 is the RD-set of Kn

 

v1

   

n 1

S vv , S

 

v1 is the RD-set of Kn

 

v1

and NG

 

v1 S

v v2, ,...,3 vn2,vn1

 . Thus Kn

satisfy Property 1, Property 2 and Property 3.

Theorem4.1. Let GCm Cn then

 

 

 

, if , 0 mod 5 or , 4 or

0 mod 5 and 4 or 4 and 0 mod 5

m n

RD G

RD C RD C m n m n

m n

m n

RD

 

 

 

 

 

 

 

2,if , 3mod 5

1, otherwise

m n

m n

C RD C m n

RD C RD C

     

 



Proof. In cycle Cn, as vertex considered for fusion is in the RD-set, it is enough to check Table 2 alone.

As n3mod 5 satisfies Property 1, Property 2 and Property 3 while n0 mod 5 and n4 doesn’t satisfies Property 1, Property 2 and Property 3 we have that

Table 3. Properties of Cn related to vertex fusion

n

C

Vertex considered for fusion is in the RD

-set

Property 1 Property 2 Property 3

0 mod 5

n and

4

n Yes Not satisfied Not satisfied Not satisfied

1mod 5

n Yes Satisfied Satisfied Not satisfied

2 mod 5

n

4 mod 5

n except n4 Yes Not satisfied Satisfied Not satisfied

3mod 5

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78

 

 

 

, if , 0 mod 5 or , 4 or

0 mod 5 and 4 or 4 and 0 mod 5

m n

RD G

RD C RD C m n m n m n m n RD        

 

Cm RD C

 

n 2, if ,m n 3 mod 5

           

From Table 2, it is clear that for all other cases

 

RD G will be equal to RD C

 

mRD C

 

n 1.

Corollary 4.1. Let Fn be the friendship graph then

 

n

RD Fn.

Proof. F2C3 C3, hence by Theorem 4.1 RD C( 3

 

 

3) 3 3 2 2

CRD CRD C   and by Remark 3.1 the fused vertex will not be in any RD -set.

n

F is obtained by fusion any vertex of C3 to the vertex with maximum degree in Fn1 and by Table 1 we have

 

 

 

 

 

 

 

 

 

1 3

1 2 3

4 3 3

3 2 3

1

1

1

1 2 2 1 3

n n

n n

RD F RD F RD C RD F RD F RD C RD F RD F RD C RD F RD F RD C

                  

Thus RD F

 

n     n 1 2 1 n.

Theorem 4.2. For the Windmill graph Kn m ,

 

 

, if

2 2 , if 3

m n

m n

RD K

m n n

 

 

 .

Proof. K 2mSm and hence

 

 

2

 

m

m

RD KRD Sm.

For n3, Kn satisfy all Property 1, Property 2 and Property 3, hence

 

 

 

 

2 2 2 2

n n n

RD K RD K RD K n

  

 

and by Remark 3.1 the fused vertex will not be in any

RD-set.

 m n

K is obtained by fusion any vertex of Kn to the vertex with maximum degree in Knm1 and by Table 1 we have  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

1 1 2 4 3 3 2 1 1 1

1 2 2 1 1

3 2

m m

n n n

m m

n n n

n n n

n n n

RD K RD K RD K

RD K RD K RD K

RD K RD K RD K

RD K RD K RD K n n

n                      

Hence RD K

 

n mm n

2

.

Theorem 4.3. For the Dutch windmill graph Dn m ,

 

 

2

, if 0 mod 5 or 5

4

2

, if 3 mod 5 5

2

1 , otherwise 5 m n n m n n

RD D n

m m n

n m m                       

Proof. As Dn 2 Cn Cn, by Theorem 4.1 we have

that

 

 

2

2

2 , if 0 mod 5 or 5

4

2

2 2, if 3 mod 5 5

2

2 1, otherwise 5

n

n

n n

RD D n

n n                       

 m n

D is obtained by fusion of any vertex of Cn to the vertex of Dnm1 with maximum degree.

Case 1: For n0 mod 5 and n4, Dn 2 and Cn do not satisfies Property 2. Moreover Dnm1 also do not satisfies Property 2 for n0 mod 5 and n4. Hence we have  

 

 

 

 

 

 

  

 

 

 

 

3 2 1 2 1 2 3 5 2 1 5 2 5

n n n

m m

n n n

m m

n n n

n RD D RD D RD C

n

RD D RD D RD C m

n

RD D RD D RD C m

                              

Case 2: For n3mod 5, any RD-set of Dn 2 does not contains the vertex considered for fusion. As Cn

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79

 

 

 

 

 

 

 

 

 

 

 

 

3 2

1 2

1

1

2 3 3

5

1

2

1 1 5

2 1

5

n n n

m m

n n n

m m

n n n

RD D RD D RD C n

RD D RD D RD C

n

m m

n

RD D RD D RD C m m

 

  

  

 

  

     

 

     

 

Case 3: For all other possibilities we can similarly prove that

 

  2

1

5

m n

n RD Dmm

  .

ACKNOWLEDGMENTS

This research is supported by UGC scheme RGNF. Award letter F1-17.1/2014-15/RGNF-2014-15-SC-TAM-80373/(SAIII/Website).

REFERENCES

[1] Slater, P. J. (1988): Dominating and reference sets in a graph, J. Math. Phys. Sci., 22, pp. 445-455. [2] Slater, P. J. (1987): Dominating and location in

acyclic in graphs, Networks, 17, pp. 55-64. [3] Rajasekar, G.; Nagarajan, K. (2018): Algorithm

for finding Location Domination Number of a Graph connected by a Bridge, Int. J. of Pure and Applied Math., 118 (6), pp. 313-321.

[4] Rajasekar, G.; Nagarajan, K. (2017): Location Domination Number of Graph obtained by the Fusion of Single Vertex, Global J. of Pure and Applied Math., 13 (9), pp. 4425–4436.

Figure

Table 2. Procedure for finding the location domination number of graphs obtained by fusion of vertex- Table 2  

References

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