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R E S E A R C H

Open Access

The modified split generalized

equilibrium problem for quasi-nonexpansive

mappings and applications

Kanyarat Cheawchan

1

and Atid Kangtunyakarn

1*

*Correspondence:

[email protected]

1Department of Mathematics,

Faculty of Science, King Mongkut’s Institute of Technology Ladkrabang, Bangkok, Thailand

Abstract

In this paper, we introduce a new problem, the modified split generalized equilibrium problem, which extends the generalized equilibrium problem, the split equilibrium problem and the split variational inequality problem. We introduce a new method of an iterative scheme{xn}for finding a common element of the set of solutions of variational inequality problems and the set of common fixed points of a finite family of quasi-nonexpansive mappings and the set of solutions of the modified split generalized equilibrium problem without assuming a demicloseness condition and

:= (1 –

ω)

I+

ω

T, whereTis a quasi-nonexpansive mapping and

ω

∈(0,12); a difficult proof in the framework of Hilbert space. In addition, we give a numerical example to support our main result.

MSC: 47B40; 47H10; 47J20

Keywords: The modified split generalized equilibrium problem;

Quasi-nonexpansive mapping; Variational Inequality problem; Fixed Point problem

1 Introduction

LetCbe a nonempty closed convex subset of a real Hilbert spaceH. The set of fixed points ofTis denoted byF(T). The mappingT:CCis said to bequasi-nonexpansiveif

Txpxp,

for allxCandpF(T).

Definition 1.1([1]) LetT:HH. Then the following are equivalent: 1. Tis firmly nonexpansive,

2. Tx–Ty2≤ x–y,TxTy,∀x,yH, 3. Tx–Ty, (IT)x– (IT)y ≥0,∀x,yH.

LetA:CHbe a mapping. Thevariational inequalityis to find a pointuCsuch that

Au,vu ≥0, (1.1)

(2)

for allvC. The set of solutions of (1.1) is denoted byVI(C,A). A mappingA:CHis calledα-inverse strongly monotoneif there exists a positive real numberα> 0 such that

AxAy,xyαAxAy2,

for allx,yC. They have been investigated in the literature; see, for example, [2, 3]. Let F be a bifunction ofC×CintoR, whereRis the set of real numbers. Theequilibrium problemforF:C×C→Ris to findxCsuch that

F(x,y)≥0, ∀y∈C. (1.2)

The set of solutions of (1.2) is denoted byEP(F). Equilibrium problems were introduced by [4] in 1994 and included many well-known problems such as variational inequality, optimization problem, nonexpansive mapping and fixed point problem; see, for example, [5–8].

LetF be a function ofC×CintoRand letf :HHbe a mapping. Thegeneralized equilibrium problemis to findxCsuch that

F(x,y) +f(x),yx≥0, (1.3)

for allyC. The set of solutions of (1.3) is denoted byEP(F,f). Whenf ≡0,EP(F,f) is denoted byEP(F) andF≡0,EP(F,f) is denoted byVI(C,f).

Throughout this section, letH1,H2be real Hilbert spaces and letC,Qbe nonempty

closed convex subsets of real Hilbert spacesH1andH2, respectively. LetA:H1→H2be

a bounded linear operator.

In 1994, Censor and Elfving [9] introduced thesplit feasibility problem(in short, SFP) which is to find a pointxCsuch thatAxQ. The set of all solutions of split feasibility problem is denoted byϕ={x∈C:AxQ}.

To solve the SFP, Byrne [10] introducedCQalgorithm whose sequence{xn}is generated

by

xn+1=PC1

xnγA∗(IPC2)Axn

,

where the initialx0∈H1 andγ ∈(0, 2/L),L is the spectral radius of the operatorAA

andA∗ is the adjoint ofA. Then the CQalgorithm converges to a solution of the SFP, whenever solutions exist. If there are no solutions of the SFP, theCQalgorithm converges to a minimizer of the function

1

2(IPC2)Ax 2

,

whenever such minimizers exist.

LetU:H1→H1andT:H2→H2be two nonlinear operators. Thesplit common fixed

points problem(SCFPP) [11, 12] is to find a pointx∗such that

(3)

The solution set of SCFPP is denoted by={p∗∈F(U) :Ap∗∈F(T)}. The split common fixed point problem is a generalization of the split feasibility problem.

In 2017, Wang [13] introduced a new method for solving SCFPP as follows:

xn+1=xnρn

(IU)xn+A∗(IT)Axn

,

whereρn⊂(0,∞) is chosen such that

ρn=

(IU)xn2+(IT)Axn2

(IU)xn+A∗(IT)Axn2

(1.4)

andUandTare firmly quasi-nonexpansive mappings. Then the sequence{xn}converges

weakly toz, wherez=limn→∞Pxn.

Censor et al. [11, 14] introduced the prototypicalsplit inverse problem(SIP) which is a generalization of the split common fixed points problem. In this, there are given two vector spacesXandYand a linear operatorA:XY. In addition, two inverse problems are involved. The first one, denoted IP1, is formulated in the spaceXand the second one,

denoted IP2, is formulated in the spaceY. Given these data, the split inverse problem is

formulated as follows:

find a pointx∗∈Xthat solves IP1, (1.5)

and such that

find a pointy∗∈Ythat solves IP2. (1.6)

This problem is used in many modeling arising in sensor networks, radiation therapy treat-ment planning, color imaging, etc.

Thesplit equilibrium problem(SEP) [12] is to findxCsuch that

F1(x,x)≥0, ∀x∈C, (1.7)

and such that

y=AxQ solvesF2(y,y)≥0, ∀yQ, (1.8)

whereF1:C×C→RandF2:Q×Q→Rbe nonlinear bifunctions. If we consider only

problem (1.7), it is the equilibrium problem and we denoted its solution set byEP(F1). The

solution set of SEP is denoted by={pEP(F1) :ApEP(F2)}. SEP is reduced toEP(F),

whereH1≡H2,F1≡F2andAI.EP(F) is an unifying model for several problems arising

in physics, engineering, science, optimization, economics, etc.

Thesplit variational inequality problems(in short, SVIP) were introduced and studied by Cencor et al. [11]: findxCsuch that

f1(x),xx

(4)

and such that

y=AxQ solvesf2(y),yy

≥0, ∀yQ, (1.10)

wheref1:CH1andf2:QH2are nonlinear mappings. The solution set of SVIP is

denoted by ={pVI(C,f1) :ApVI(Q,f2)}. The split variational inequality problems

have already been studied and used in practice as a model in intensity-modulated radia-tion therapy (IMRT) treatment planning; see, for example, [15] and the modeling of many inverse problems arising for phase retrieval and other real-world problems; for instance, in sensor networks in computerized tomography and data compression; see, for example, [16, 17].

By investigating SEP and SVIP, we introduce themodified split generalized equilibrium problem(MSGEP) which is to findx∗∈Csuch that

F1

x∗,x+f1

x∗,xx∗≥0, ∀x∈C, (1.11)

and such that

y∗=Ax∗∈Q solvesF2

y∗,y+f2

y∗,yy∗≥0, ∀y∈Q, (1.12)

whereF1:C×C→RandF2:Q×Q→Rare nonlinear bifunctions andf1:CH1and

f2:QH2are nonlinear mappings. The solution set of MSGEP is denoted by={p∗∈

EP(F1,f1) :Ap∗∈EP(F2,f2)}.

Remark1.1

1. If we putf1≡f2≡0in MSGEP then the MSGEP is reduced to SEP.

2. If we putF1≡F2≡0in MSGEP then the MSGEP is reduced to SVIP.

3. In the case of bifunctionsF1andF2are according to (A1)–(A4). From (1.11), (1.12)

and Lemma 2.2, we havex∗∈F(TF1

r (Irf1))andAx∗∈F(TsF2(Isf2)), for all

r,s> 0. So, MSGEP can be viewed as SCFPP.

MSGEP is a generalization of the generalized equilibrium problem, the split equilib-rium problem and the split variational inequality problem. So, this problem can be used in sensor networks, data compression, practice as a model in intensity-modulated radia-tion therapy (IMRT) treatment planning, robustness to marginal changes and equilibrium stability etc.

Example1.2 LetH1= [0, 6],H2= [0, 18],C= [2, 5] andQ= [6, 10]. LetA:H1→H2be

defined byAx= 3xfor allxH1. Let the mappingF1:C×C→Rbe defined by

F1

x∗,x= –x∗– 22+ (x– 2)2, ∀x,yC,

andF2:Q×Q→Rbe defined by

F2

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Let the mappingf1:CH1be defined byf1x=x–29 ,∀x∈Cand the mappingf2:QH2

be defined byf2x=x–67 ,∀x∈Q.

Then 2∈. Therefore 2 is a solution of MSGEP.

In 2012, Tain and Jin [18] introduced iterative algorithms involving a quasi-nonexpansive mapping. They generated the iterative as follows:

xn+1=αnγf(xn) + (IαnA)Tωxn,

whereAis a bounded linear operator onH,Tis a quasi-nonexpansive mapping onH,f is a contraction with coefficientaunder suitable conditions of the parametersαn,γ andω.

By assumingω∈(0,12),:= (1 –ω)I+ωTandTis demiclosed onH.

Motivated by SFP and SVIP, we introduced a new problem, the modified split general-ized equilibrium problem, which extends the generalgeneral-ized equilibrium problem, the split equilibrium problem and the split variational inequality problem. Many authors proved strong convergence theorem involving a quasi-nonexpansive mapping T by assuming := (1 –ω)I+ωTandTis demiclosed onH; a difficult proof. Motivated by [19], we

in-troduced Remark 2.5 and [11, 12] and [18], we introduce a new method of iterative scheme {xn}for finding a common element of the set of solutions of variational inequality

prob-lems and the set of common fixed points of a finite family of quasi-nonexpansive mappings and the set of solutions of the modified split generalized equilibrium problem without the condition above in the framework of a Hilbert space.

2 Preliminaries

LetH be a real Hilbert space with inner product·,·and norm · . Throughout this paper, we use the notations of weak and strong convergence by “” and “→”, respectively. Recall thatHsatisfiesOpial’s condition[20], i.e., for any sequence{xn}withxnx, the

inequalitylimn→∞infxnx<limn→∞infxny, holds for everyyHwithy=x.

For solving the equilibrium problem, we assume that the bifunctionF :C×C→R satisfy the following conditions:

(A1) F(x,x) = 0for allxC,

(A2) Fis monotone, i.e.,F(x,y) +F(y,x)≤0for allx,yC, (A3) for eachx,y,zC,limt↓0F(tz+ (1 –t)x,y)≤F(x,y),

(A4) for eachxC,yF(x,y)is convex and lower semicontinuous.

Lemma 2.1([4]) Let C be a nonempty closed convex subset of H and let F be a bifunction of C×C intoRsatisfying(A1)(A4).Let r> 0and xH.Then there exists zC such that

F(z,y) +1

ryz,zx ≥0, ∀yC.

Lemma 2.2([21]) Assume that F:C×C→Rsatisfies (A1)(A4).For r> 0,define a mapping Tr:HC as follows:

Tr(x) =

zC:F(z,y) +1

ryz,zx ≥0,∀yC

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(1) Tris single-valued,

(2) Tris firmly nonexpansive,i.e.,for anyx,yH,

Tr(x) –Tr(y)2≤

Tr(x) –Tr(y),xy

,

(3) F(Tr) =EP(F),

(4) EP(F)is closed and convex.

Lemma 2.3([22]) Let H be a real Hilbert space,let C be a nonempty closed convex subset of H and let A be a mapping of C into H.Let uC.Then,forλ> 0,

u=PC(IλA)uuVI(C,A),

where PCis the metric projection of H onto C.

Lemma 2.4 Let C be a nonempty closed convex subset of a real Hilbert space H.Let{Ti}Ni=1

be a finite family of quasi-nonexpansive mappings of C into H withNi=1F(Ti)=∅and let

0 <ai< 1with

N

i=1ai= 1.Then

N

i=1

F(Ti) =VI

C,

N

i=1

ai(ITi)

.

Proof In this lemma, we show thatNi=1F(Ti) =

N

i=1VI(C,ITi) and

N

i=1VI(C,ITi) =

VI(C,Ni=1ai(ITi)). Lastly, we have

N

i=1

F(Ti) =VI

C,

N

i=1

ai(ITi)

.

To start with, it is easy to see thatNi=1F(Ti)⊆

N

i=1VI(C,ITi). Next, we show that

N

i=1VI(C,ITi)⊆

N

i=1F(Ti). Letu

N

i=1VI(C,ITi) and

N

i=1F(Ti)=∅. So, we get

uVI(C,ITi),∀i= 1, 2, . . . ,N. We may write

uv, (ITi)u

≤0, ∀v∈C. (2.1)

There existsv∗∈Csuch thatv∗=Tiv∗,∀i= 1, 2, . . . ,N. SinceTiis a quasi-nonexpansive

mapping,∀i= 1, 2, . . . ,N, it follows that

Tiuv∗2

=uv∗– (ITi)u

2

=uv∗2– 2uv∗, (ITi)u

+(ITi)u

2

uv∗2. (2.2)

By using (2.1) and (2.2), we conclude that

(ITi)u

2

≤2uv∗, (ITi)u

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It implies thatuNi=1F(Ti). Therefore

N

i=1VI(C,ITi)⊆

N

i=1F(Ti). Hence

N

i=1

F(Ti) = N

i=1

VI(C,ITi).

After that, we show Ni=1VI(C,ITi) =VI(C,

N

i=1ai(ITi)) where 0 <ai < 1 and

N

i=1ai= 1. Observe that

u

N

i=1

VI(C,ITi)

uVI(C,ITi), ∀i= 1, 2, . . . ,N

⇔ (ITi)u,vu

≥0, ∀vCand∀i= 1, 2, . . . ,N

N

i=1

ai

(ITi)u,vu

≥0, ∀v∈C

N

i=1

ai(ITi)u,vu

≥0, ∀vC

uVI

C,

N

i=1

ai(ITi)

.

ThereforeNi=1VI(C,ITi) =VI(C,

N

i=1ai(ITi)). Hence

N

i=1F(Ti) =VI(C,

N i=1ai(I

Ti)).

Remark2.5 From Lemma 2.3 and Lemma 2.4, we have

N

i=1

F(Ti) =VI

C,

N

i=1

ai(ITi)

=F

PC

Iλ

N

i=1

ai(ITi)

,

for allλ> 0 and 0 <ai< 1 with

N i=1ai= 1.

Lemma 2.6([23]) Let{sn}be a sequence of nonnegative real numbers satisfying

sn+1≤(1 –αn)sn+δn, ∀n≥0,

where{αn}is a sequence in(0, 1)and{δn}is a sequence such that

(1) ∞

n=1

αn=∞, (2) lim sup n→∞

δn

αn

0 or

n=1

|δn|<∞.

Thenlimn→∞sn= 0.

3 Main results

Lemma 3.1 Let C and Q be nonempty closed convex subsets of a real Hilbert spaces H1and

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F2:Q×Q→Rbe the bifunctions satisfying(A1)(A4).Let f1:H1→H1be aρ-inverse

strongly monotone mapping and f2:H2→H2be a firmly nonexpansive mapping.Then

1. TF1

r (Irf1)andTsF2(Isf2)are nonexpansive mapping,

2.

TF1

r (Irf1)

p+γATF2

s (Isf2) –I

Ap

TF1

r (Irf1)

q+γATF2

s (Isf2) –I

Aq2

pq2+γ(γL– 1)TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2,

for all p,qC,where r∈(0, 2ρ),s∈(0, 1),γ ∈(0, 1/L),L is the spectral radius of the oper-ator AA and Ais the adjoint of A,TF1

r :H1→C defined by

TF1

r (x) =

zC:F1(z,y) +

1

ry–z,zx ≥0,∀y∈C ,

for all xH1and TsF2:H2→Q defined by

TF2

s (x) =

zQ:F2(z,y) +

1

sy–z,zx ≥0,∀y∈Q ,

for all xH2.

Proof Letp,qC. First, we show 1 is true. Sincef1 is aρ-inverse strongly monotone

mapping andr∈(0, 2ρ), we obtain TF1

r (Irf1)pTrF1(Irf1)q 2

≤ p–q2– 2rpq,f1pf1q+r2f1pf1q2

≤ p–q2+r(r– 2ρ)f1pf1q2

≤ p–q2.

ThusTF1

r (Irf1) is a nonexpansive mapping. Sincef2is a firmly nonexpansive mapping

ands∈(0, 1), we get

TF2

s (Isf2)pTsF2(Isf2)q 2

pq2– 2spq,f2pf2q+s2f2pf2q2

pq2–s(2 –s)f2pf2q2

≤ p–q2,

for allp,qQ. ThereforeTF2

s (Isf2) is a nonexpansive mapping.

Next, we show 2 is true. From Lemma 3.1(1), we have

TF1

r (Irf1)

p+γATF2

s (Isf2) –I

Ap

TF1

r (Irf1)

q+γATF2

s (Isf2) –I

Aq2

≤(pq) +γATF2

s (Isf2) –I

ApATF2

s (Isf2) –I

Aq2

≤ p–q2+ 2γApAq,TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq

+γ2LTF2

s (Isf2) –I

ApTF2

s (Isf2) –I

(9)

From the property ofTF2

s , we get

(Isf2)Ap– (Isf2)Aq 2

TF2

s (Isf2)ApTsF2(Isf2)Aq– (ApAq) + (ApAq) 2

=TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2

+ 2TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq,ApAq

+ApAq2. (3.2)

We have

(Isf2)Ap– (Isf2)Aq 2

=ApAq2– 2sApAq,f2Apf2Aq

+s2f2Apf2Aq2. (3.3)

From (3.2), (3.3) and the property of firmly nonexpansive mapping, we get

2TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq,ApAq

≤–TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2

– 2sApAq,f2Apf2Aq+s2f2Apf2Aq2

≤–TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2.

That is,

2γTF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq,ApAq

≤–γTF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2. (3.4)

Substituting (3.4) in (3.1), we obtain

TF1

r (Irf1)

p+γATF2

s (Isf2) –I

Ap

TF1

r (Irf1)

q+γATF2

s (Isf2) –I

Aq2

pq2–γTF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2

+γ2LTF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2

=p–q2+γ(γL– 1)TF2

s (Isf2) –I

ApTF2

s (Isf2) –I

Aq2.

Lemma 3.2 Let C be a nonempty closed convex subset of a real Hilbert space H and let T:CC be a quasi-nonexpansive mapping with F(T)=∅.Then

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Proof LetxCandzF(T). SinceT is a quasi-nonexpansive mapping, we get

Tx–z2=(xz) – (IT)x2

=x–z2– 2xz, (IT)x+(IT)x2

≤ x–z2.

We can conclude that

(IT)x2≤2xz, (IT)x.

Lemma 3.3 Let C be a nonempty closed convex subset of a real Hilbert space H.Let{Ti}Ni=1

be a finite family of quasi-nonexpansive mappings of C into itself withNi=1F(Ti)=∅.Then

PC

Iλ

N

i=1

ki(ITi)

xz

2

≤ x–z2,

for all xC,where0 <ki< 1with

N

i=1ki= 1and0 <λ< 1.

Proof LetxCandzNi=1F(Ti). From Remark 2.5 andz

N

i=1F(Ti), we have z

F(PC(Iλ(Ni=1ki(ITi)))) andz=Tiz,∀i= 1, 2, . . . ,N. SincePCis nonexpansive mapping,

0 <λ< 1 and Lemma 3.2, we have

PC

Iλ

N

i=1

ki(ITi)

xz

2

= PC

Iλ

N

i=1

ki(ITi)

xPC

Iλ

N

i=1

ki(ITi)

z

2

xz2– 2λ

N

i=1

ki

xz, (ITi)x

+λ2

N

i=1

ki(ITi)x2

≤ x–z2–λ

N

i=1

ki(ITi)x

2

+λ2

N

i=1

ki(ITi)x

2

xz2. (3.5)

Next, we prove a strong convergence theorem for solving the modified split generalized equilibrium problem (MSGEP).

Theorem 3.4 Let C and Q be nonempty closed convex subsets of a real Hilbert spaces H1

and H2,respectively.Let A:H1→H2be a bounded linear operator.Let D1,D2:CH1

beα, β-inverse strongly monotone mappings,respectively.Let F1:C×C→Rand F2 :

Q×Q→Rbe the bifunctions satisfying(A1)(A4).Let{Ti}Ni=1be a finite family of

quasi-nonexpansive mappings of C into itself withNi=1F(Ti)=∅.Let f1:H1→H1be aρ-inverse

strongly monotone mapping and f2:H2→H2be a firmly nonexpansive mapping.Assume

F=VI(C,D1)∩VI(C,D2)∩

N

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{yn}be sequences generated by

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

un=TrF1(Irf1)(xn+γA∗(TsF2(Isf2) –I)Axn),

yn=PC(Id1D1)(aun+ (1 –a)PC(Id2D2)un),

xn+1=αnu+βnxn+γnPC(Iλn(

N

i=1ki(ITi)))yn, ∀n∈N,

(3.6)

where d1∈(0, 2α),d2∈(0, 2β),r∈(0, 2ρ),s∈(0, 1),a∈[0, 1], 0 <ki< 1with

N i=1ki= 1,

γ ∈(0, 1/L),L is the spectral radius of the operator AA and Ais the adjoint of A.Also{αn},

{βn},{γn}are sequences in[0, 1]withαn+βn+γn= 1for all n∈N.Suppose the following

conditions hold:

(i) limn→∞αn= 0and

n=1αn=∞,

(ii) 0 <cβn,γnd< 1for somec,d> 0for alln≥1,

(iii) ∞n=1λn<∞and0 <λn< 1,

(iv) ∞n=1|αn+1–αn|<∞,

n=1|βn+1–βn|<∞.

Then{xn},{un}and{yn}converge strongly to z=PFu.

Proof Letx,yCandzF. First, we show that (Id1D1) is a nonexpansive mapping.

SinceD1is anα-inverse strongly monotone mapping, we obtain

(Id1D1)x– (Id1D1)y 2

=xy2– 2d1xy,D1xD1y+d21D1xD1y2

xy2+d1(d1– 2α)D1xD1y2≤ xy2.

Thus (Id1D1) is a nonexpansive mapping. By using the same method as above, we see that

(Id2D2) is a nonexpansive mapping. Sincef1is aρ-inverse strongly monotone mapping

andf2is a firmly nonexpansive mapping. From Lemma 3.1(1), we have (TrF1(Irf1)) and

(TF2

s (Isf2)) are nonexpansive mappings. Sincez

N

i=1F(Ti) and Lemma 3.3, we have

PC

Iλn

N

i=1

ki(ITi)

ynz

2

≤ ynz2. (3.7)

SincezVI(C,D1) andzVI(C,D2) and using the property of (Id1D1) and (Id2D2),

we get

ynz2=PC(Id1D1)

aun+ (1 –a)PC(Id2D2)un

PC(Id1D1)z 2

aunz2+ (1 –a)PC(Id2D2)unz

2

(3.8)

unz2. (3.9)

Sincez, we havez=TF1

r (Irf1)zandAz=TsF2(Isf2)Az. From Lemma 3.1(2) and

γ ∈(0, 1/L), we obtain

unz2=TrF1(Irf1)

xn+γA

TF2

s (Isf2) –I

Axn

TF1

r (Irf1)z 2

xnz2+γ( – 1)TsF2(Isf2) –I

Axn

2

(3.10)

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Using the definition ofxn, (3.7), (3.9) and (3.11), we get

xn+1–z=

αn(uz) +βn(xnz)

+γn

PC

Iλn

N

i=1

ki(ITi)

ynz

αnu–z+βnxnz+γnynz

αnu–z+βnxnz+γnunz

αnu–z+ (1 –αn)xnz.

Using induction, we can conclude that

xnz ≤max

u–z,x1–z

for alln≥1. This implies that the sequence{xn}is bounded and so are{yn}and{un}. From

Lemma 3.1 (2) andγ ∈(0, 1/L), we obtain

unun–12

=TF1

r (Irf1)

xn+γA

TF2

s (Isf2) –I

Axn

TF1

r (Irf1)

xn–1+γA

TF2

s (Isf2) –I

Axn–1

2

≤ xnxn–12+γ(γL– 1)TsF2(Isf2) –I

Axn

TF2

s (Isf2) –I

Axn–1

2

≤ xnxn–12. (3.12)

Next, we show thatlimn→∞xn+1–xn= 0. According to Eq. (3.12), we have

xn+1–xn

=

αnu+βnxn+γnPC

Iλn

N

i=1

ki(ITi)

yn

αn–1u+βn–1xn–1+γn–1PC

Iλn–1

N

i=1

ki(ITi)

yn–1

≤ |αnαn–1|u+βnxnxn–1+|βnβn–1|xn–1+γnynyn–1

+λn

N i=1

ki(ITi)

yn

N

i=1

ki(ITi)

yn–1

+|λnλn–1|

N i=1

ki(ITi)

yn–1

+|γnγn–1|

PC

Iλn–1

N

i=1

ki(ITi)

yn–1

(13)

+λn N i=1

ki(ITi)

yn

N

i=1

ki(ITi)

yn–1

+|λnλn–1|

N i=1

ki(ITi)

yn–1

+|γnγn–1|

PC

Iλn–1

N

i=1

ki(ITi)

yn–1

≤(1 –αn)xnxn–1+|αnαn–1|M+|βnβn–1|M+λnM

+|λnλn–1|M+|γnγn–1|M,

where

M:=max

n∈N

u,xn,

N i=1

ki(ITi)

yn+1–

N

i=1

ki(ITi)

yn , N i=1

ki(ITi)

yn , PC Iλn

N

i=1

ki(ITi)

yn .

From condition (i), (iii), (iv) and Lemma 2.6, we have

lim

n→∞xn+1–xn= 0. (3.13)

According to Eqs. (3.7), (3.9) and (3.10), we have

xn+1–z2≤αnuz2+γn

PC

Iλn

N

i=1

ki(ITi)

ynz

2

+βnxnz2–βnγn

xnPC

Iλn

N

i=1

ki(ITi)

yn 2

αnu–z2+βnxnz2+γnynz2

βnγn

xnPC

Iλn

N

i=1

ki(ITi)

yn 2 (3.14)

αnu–z2+βnxnz2+γnunz2

βnγn

xnPC

Iλn

N

i=1

ki(ITi)

yn 2 (3.15)

αnu–z2+ (1 –αn)xnz2+γnγ(– 1)TsF2(Isf2) –I

Axn

2

βnγn

xnPC

Iλn

N

i=1

ki(ITi)

yn 2 .

This implies that

γnγ(1 –)TsF2(Isf2) –I

Axn

2

αnu–z2+xnxn+1

xnz+xn+1–z

(14)

By using condition (i) and (3.13), we have

lim

n→∞T

F2

s (Isf2) –I

Axn= 0. (3.16)

By using the same method as (3.16), we have

lim

n→∞

xnPC

Iλn

N

i=1

ki(ITi)

yn

= 0. (3.17)

LetMn=xn+γA∗(TsF2(Isf2) –I)Axn. Applying the inequality (3.11), we have

Mnzxnz. (3.18)

Using the property of inverse strongly monotone operators and (3.18), we have

unz2=TrF1(Irf1)MnTrF1(Irf1)z 2

≤(Irf1)Mn– (Irf1)z 2

=Mnz2– 2rMnz,f1Mnf1z+r2f1Mnf1z2

xnz2+r(r– 2ρ)f1Mnf1z2. (3.19)

Substituting (3.19) in (3.15), we have

xn+1–z2≤αnuz2+βnxnz2

+γn

xnz2+r(r– 2ρ)f1Mnf1z2

αnuz2+ (1 –αn)xnz2+γnr(r– 2ρ)f1Mnf1z2.

That is,

γnr(2ρr)f1Mnf1z2≤αnuz2+xnxn+1

xnz+xn+1–z

.

According to condition (i) and (3.13), we get

lim

n→∞f1Mnf1z= 0. (3.20)

By the property of firmly nonexpansive mappings, we have

unz2=TrF1(Irf1)MnTrF1(Irf1)z 2

unz, (Irf1)Mn– (Irf1)z

=1 2

unz2+(Irf1)Mn– (Irf1)z 2

–(unz) –

(Irf1)Mn– (Irf1)z 2

(15)

That is,

unz2≤(Irf1)Mn– (Irf1)z 2

–(unMn) +r(f1Mnf1z) 2

Mnz2–

unMn2+ 2runMn,f1Mnf1z

+r2f1Mnf1z2

≤ Mnz2–unMn2+ 2runMnf1Mnf1z

r2f1Mnf1z2. (3.22)

Substituting (3.22) in (3.15), we get

xn+1–z2≤αnu–z2+βnxnz2+γn

Mnz2–unMn2

+ 2runMnf1Mnf1zr2f1Mnf1z2

αnu–z2+ (1 –αn)xnz2–γnunMn2

+ 2rγnunMnf1Mnf1z.

It follows that

γnunMn2≤αnu–z2+xnxn+1

xnz+xn+1–z

+ 2rγnunMnf1Mnf1z.

From condition (i), (3.13) and (3.20), we ensure that

lim

n→∞unMn= 0. (3.23)

From (3.16) and (3.23), we also have

unxn ≤ unMn+Mnxn

=unMn+xn+γA

TF2

s (Isf2) –I

Axnxn

≤ unMn+γATsF2(Isf2) –I

Axn.

Then we have

lim

n→∞unxn= 0. (3.24)

By using the same method as (3.19), we have

PC(Id2D2)unz2≤ xnz2+d2(d2– 2β)D2unD2z2. (3.25)

Substituting (3.8) and (3.25) in (3.14), we have

xn+1–z2≤αnu–z2+βnxnz2+γn

aunz2

+ (1 –a)PC(Id2D2)unz

(16)

αnu–z2+ (1 –αn)xnz2

+γn(1 –a)d2(d2– 2β)D2unD2z2.

We can conclude that

γn(1 –a)d2(2βd2)D2unD2z2

αnu–z2+xnxn+1

xnz+xn+1–z

.

According to condition (i) and (3.13), we get

lim

n→∞D2unD2z= 0. (3.26)

SincePCis a firmly nonexpansive mapping and using the same method as (3.21), we get

PC(Id2D2)unz2

≤1

2PC(Id2D2)unz

2

+(Id2D2)un– (Id2D2)z 2

PC(Id2D2)unz– (Id2D2)un+ (Id2D2)z 2

.

That is,

PC(Id2D2)unz

2

unz2–PC(Id2D2)unun

+d2(D2unD2z) 2

xnz2–PC(Id2D2)unun

2

+ 2d2PC(Id2D2)ununD2unD2z

d22D2unD2z2. (3.27)

Substituting (3.8) and (3.27) in (3.14), we have

xn+1–z2

αnuz2+βnxnz2+γn

aunz2+ (1 –a)PC(Id2D2)unz

2

αnu–z2+βnxnz2+γn

axnz2+ (1 –a)

xnz2

PC(Id2D2)unun

2

+ 2d2PC(Id2D2)ununD2unD2z

d22D2unD2z2

αnuz2+ (1 –αn)xnz2–γn(1 –a)PC(Id2D2)unun

2

+ 2d2γn(1 –a)PC(Id2D2)ununD2unD2z.

Therefore

γn(1 –a)PC(Id2D2)unun

2

αnu–z2+xnxn+1

xnz+xn+1–z

(17)

From condition (i), (3.13) and (3.26), we get

lim

n→∞PC(Id2D2)unun= 0. (3.28)

Letkn=aun+ (1 –a)PC(Id2D2)un. By using the same method as (3.19), we have

ynz2≤ xnz2+d1(d1– 2α)D1knD1z2. (3.29)

Substituting (3.29) in (3.14), we have

xn+1–z2

αnuz2+βnxnz2+γn

xnz2+d1(d1– 2α)D1knD1z2

αnu–z2+ (1 –αn)xnz2+d1(d1– 2α)γnD1knD1z2.

This implies that

d1(2αd1)γnD1knD1z2≤αnuz2+xnxn+1

xnz+xn+1–z

.

According to condition (i) and (3.13), we have

lim

n→∞D1knD1z= 0. (3.30)

By using the same method as (3.21), we have

ynz2≤

1 2

ynz2+(Id1D1)kn– (Id1D1)z2

–(ynkn) +d1(D1knD1z)2

.

That is,

ynz2≤ knz2–

ynkn2+ 2d1ynkn,D1knD1z

+d21D1knD1z2

≤ xnz2–ynkn2+ 2d1ynknD1knD1z

d12D1knD1z2. (3.31)

Substituting (3.31) in (3.14), we have

xn+1–z2≤αnu–z2+βnxnz2+γn

xnz2–ynkn2

+ 2d1ynknD1knd1zd21D1knD1z2

αnu–z2+ (1 –αn)xnz2–γnynkn2

(18)

This implies that

γnynkn2≤αnu–z2+xnxn+1

xnz+xn+1–z

+ 2γnd1ynknD1knD1z.

According to condition (i), (3.13) and (3.30), we get

lim

n→∞ynkn= 0. (3.33)

From (3.28) and (3.33)

ynunynkn+knun

≤ ynkn+ (1 –a)PC(Id2D2)unun,

we conclude that

lim

n→∞ynun= 0. (3.34)

By (3.24) and (3.34), we also conclude that

lim

n→∞ynxn= 0. (3.35)

Afterward, we show thatlim supn→∞u–z,xnz ≤0, wherez=PFu.

To show this, choose a subsequence{xnj}of{xn}such that

lim sup

n→∞ u–z,xnz=jlim→∞u–z,xnjz. (3.36)

Without loss of generality, we may assume thatxnj ωasj→ ∞. From (3.35), we obtain ynj ωasj→ ∞. From Lemma 2.3, we haveVI(C,D1) =F(PC(Id1D1)). Assume that ω∈/VI(C,D1), we haveω= PC(Id1D1)ω. Using Opial’s condition, (3.33), we obtain

lim inf

j→∞ ynjω<lim infj→∞

ynjPC(Id1D1)ω

≤lim inf

j→∞ PC(Id1D1)knjPC(Id1D1)ynj

+PC(Id1D1)ynjPC(Id1D1)ω ≤lim inf

j→∞

knjynj+ynjω

≤lim inf

j→∞ ynjω.

This is a contradiction, so we have

(19)

From (3.24), we haveunj ωasj→ ∞. By (3.28) and using the same method as (3.37), we obtain

ωVI(C,D2). (3.38)

Next, we show thatωNi=1F(Ti). From Lemma 2.5, we have

N

i=1

F(Ti) =F

PC

Iλnj

N

i=1

ki(ITi)

.

Assume thatω∈/Ni=1F(Ti), and thatω=PC(Iλnj(

N

i=1ki(ITi)))ω. Using Opial’s

con-dition, (3.17) and (3.35), we obtain

lim inf

j→∞ xnjω

<lim inf

j→∞

xnjPC

Iλnj

N

i=1

ki(ITi)

ω

≤lim inf

j→∞

xnjPC

Iλnj

N

i=1

ki(ITi)

ynj

+ PC Iλnj

N

i=1

ki(ITi)

ynjPC

Iλnj

N

i=1

ki(ITi)

xnj

+ PC Iλnj

N

i=1

ki(ITi)

xnjPC

Iλnj

N

i=1

ki(ITi)

ω

≤lim inf

j→∞

ynjxnj+λnj

N i=1

ki(ITi)

ynj

N

i=1

ki(ITi)

xnj

+xnjω+λnj

N i=1

ki(ITi)

xnj

N

i=1

ki(ITi)

ω

≤lim inf

j→∞ xnjω.

This is a contradiction, so we have

ω

N

i=1

F(Ti). (3.39)

After that, we show thatω. Assumeω∈/EP(F1,f1). SinceEP(F1,f1) =F(TrF1(Irf1)),

we obtainω=TF1

r (Irf1)ω. Using Opial’s condition and (3.23), we get

lim inf

j→∞ unjω<lim infj→∞

unjT

F1

r (Irf1)ω

≤lim inf

j→∞ T

F1

r (Irf1)MnjT

F1

r (Irf1)unj

+TF1

r (Irf1)unjT

F1

(20)

≤lim inf

j→∞

Mnjunj+unjω

≤lim inf

j→∞ unjω.

This is a contradiction, so we have

ωEP(F1,f1). (3.40)

Next, we show thatEP(F2,f2). SinceAis bounded linear operator so thatAxnj asj→ ∞. Assume∈/EP(F2,f2). SinceEP(F2,f2) =F(TsF2(Isf2)), we obtain=

TF2

s (Isfs). Using Opial’s condition and (3.16), we have

EP(F2,f2). (3.41)

We can conclude thatω. ThereforeωF. Sincexnj ωasj→ ∞, we have

lim sup

n→∞ u

z,xnz=lim

j→∞u–z,xnjz

=u–z,ωz ≤0. (3.42)

Finally, we show that the sequence{xn}converges strongly toz=PFu. By (3.7), (3.9) and

(3.11), we get

xn+1–z2=

αn(uz) +βn(xnz) +γn

PC

Iλn

N

i=1

ki(ITi)

ynz

2

βn(xnz) +γn

PC

Iλn

N

i=1

ki(ITi)

ynz

2

+ 2αnuz,xn+1–z

βnxnz+γnunz

2

+ 2αnuz,xn+1–z

≤(1 –αn)xnz2+ 2αnu–z,xn+1–z.

According to condition (i), (3.42) and Lemma 2.6, we can conclude that{xn}converges

strongly toz=PFu. By (3.24) and (3.35), we have{un}and{yn}converge strongly toz=

PFu. This completes the proof.

These results are directly proved from Theorem 3.4. Therefore, we omit the proof.

Corollary 3.5 Let C and Q be nonempty closed convex subsets of a real Hilbert space H1

and H2,respectively.Let A:H1→H2be a bounded linear operator.Let D1,D2:CH1

beα,β-inverse strongly monotone mappings,respectively.Let F1:C×C→Rand F2:Q×

Q→Rbe the bifunctions satisfying(A1)(A4).Let T be a quasi-nonexpansive mapping of C into itself.Let f1:H1→H1be aρ-inverse strongly monotone mapping and f2:H2→H2

(21)

given x1,uC,and let{xn},{un}and{yn}be sequences generated by

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

un=TrF1(Irf1)(xn+γA∗(TsF2(Isf2) –I)Axn),

yn=PC(Id1D1)(aun+ (1 –a)PC(Id2D2)un),

xn+1=αnu+βnxn+γnPC(Iλn(IT))yn, ∀n∈N,

where d1∈(0, 2α),d2∈(0, 2β),r∈(0, 2ρ),s∈(0, 1),a∈[0, 1],γ∈(0, 1/L),L is the spectral

radius of the operator AA and Ais the adjoint of A.Also{αn},{βn},{γn}are sequences

in[0, 1]withαn+βn+γn= 1for all n∈N.Suppose the conditions(i)(iv)of Theorem3.4

hold.Then{xn},{un}and{yn}converge strongly to z=PFu.

Corollary 3.6 Let C be nonempty closed convex subset of a real Hilbert space H1. Let

D1,D2:CH1beα,β-inverse strongly monotone mappings,respectively.Let F1:C×C→ Rbe the bifunction satisfying(A1)(A4).Let{Ti}Ni=1be a finite family of quasi-nonexpansive

mappings of C into itself withNi=1F(Ti)=∅.Let f1:H1→H1be aρ-inverse strongly

mono-tone mapping.AssumeF=VI(C,D1)∩VI(C,D2)∩

N

i=1F(Ti)∩EP(F1,f1)=∅.For given

x1,uC and let{xn},{un}and{yn}be sequences generated by

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

un=TrF1(Irf1)xn,

yn=PC(Id1D1)(aun+ (1 –a)PC(Id2D2)un),

xn+1=αnu+βnxn+γnPC(Iλn(

N

i=1ki(ITi)))yn, ∀n∈N,

where d1∈(0, 2α),d2∈(0, 2β),r∈(0, 2ρ),a∈[0, 1], 0 <ki< 1with

N

i=1ki= 1.Also{αn},

{βn},{γn}are sequences in[0, 1]withαn+βn+γn= 1for all n∈N.Suppose the conditions

(i)(iv)of Theorem3.4hold.Then{xn},{un}and{yn}converge strongly to z=PFu.

Corollary 3.7 Let C and Q be nonempty closed convex subsets of a real Hilbert space H1

and H2, respectively. Let A:H1→H2 be a bounded linear operator. Let D1,D2:C

H1 beα, β-inverse strongly monotone mappings, respectively.Let F1:C×C→Rand

F2:Q×Q→Rbe the bifunctions satisfying(A1)(A4).Let{Ti}Ni=1 be a finite family of

quasi-nonexpansive mappings of C into itself withNi=1F(Ti)=∅.AssumeF=VI(C,D1)∩

VI(C,D2)∩

N

i=1F(Ti)∩=∅.For given x1,uC and let{xn},{un}and{yn}be sequences

generated by

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

un=TrF1(xn+γA∗(TsF2–I)Axn),

yn=PC(Id1D1)(aun+ (1 –a)PC(Id2D2)un),

xn+1=αnu+βnxn+γnPC(Iλn(

N

i=1ki(ITi)))yn, ∀n∈N,

where d1∈(0, 2α),d2∈(0, 2β),a∈[0, 1], 0 <ki< 1with

N

i=1ki= 1,γ ∈(0, 1/L),L is the

spectral radius of the operator AA and Ais the adjoint of A.Also{αn},{βn},{γn}are

sequences in[0, 1]withαn+βn+γn= 1for all n∈N.Suppose the conditions(i)(iv)of

Theorem3.4hold.Then{xn},{un}and{yn}converge strongly to z=PFu.

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of fixed points of a quasi-nonexpansive mapping and the set of solutions of the modified split generalized equilibrium problem. From previous result, we can apply by using the same method as Theorem 4.5 in [24]. We have a strong convergence for finding a common element of the set of solutions of variational inequality problems and the set of fixed points of a finite family of nonspreading mappings and the set of solutions of the modified split generalized equilibrium problem. By using our main result, Theorem 3.4 reduces to the Corollary 3.6, the solution of the generalized equilibrium problem and Corollary 3.7, the split equilibrium problem. All theorems are found as regards the solution of common fixed points of a finite family of quasi-nonexpansive mappings without assuming:= (1 –ω)I+

ωT andTis demiclosed; a difficult proof in a framework of Hilbert space.

4 Application

The following knowledge is used to prove Theorem 4.4. A mappingT:CCis called nonspreading if

2Tx–Ty2≤ Txy2+Tyx2, ∀x,yC. (4.1)

Such a mapping is defined by Kohsaka and Takahashi [25].

In 2009, Iemoto and Takahashi [26] proved that (4.1) is equivalent to

Tx–Ty2≤ x–y2+ 2x–Tx,yTy, ∀x,yC. (4.2)

Remark4.1 A nonspreading mappingTwithF(T)=∅is quasi-nonexpansive mappingT.

Lemma 4.2([25]) Let H be a Hilbert space,let C be a nonempty closed convex subset of H,and let S be a nonspreading mapping of C into itself.Then F(S)is closed and convex.

In 2009, Kangtunyakarn and Suantai[27] introduced the S-mapping generated by T1,T2,T3, . . . ,TN andλ1,λ2, . . . ,λN as follows.

Definition 4.1 LetCbe a nonempty convex subset of a real Banach space. Let{Ti}Ni=1be

a finite family of (nonexpansive) mappings ofCinto itself. For eachj= 1, 2, . . . ,N, letαj=

(αj1,α2j,αj3)∈I×I×I, whereI∈[0, 1] andα1j+α2j+α3j= 1. Define the mappingS:CC as follows:

U0=I,

U1=α11T1U0+α21U0+α31I,

U2=α12T2U1+α22U1+α32I,

U3=α13T3U2+α23U2+α33I,

.. .

UN–1=αN1–1TN–1UN–2+αN2–1UN–2+α3N–1I,

S=UN =αN1TNUN–1+α2NUN–1+α3NI.

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Lemma 4.3([28]) Let C be a nonempty closed convex subset of a real Hilbert space.Let {Ti}Ni=1be a finite family of nonspreading mappings of C into C with

N

i=1F(Ti)=∅,and let

αj= (α1j,α

j

2,α

j

3)∈I×I×I,j= 1, 2, . . . ,N,where I= [0, 1],α

j

1+α

j

2+α

j

3= 1,α

j

1,α

j

3∈(0, 1)for

all j= 1, 2, . . . ,N– 1andαN1 ∈(0, 1],α3N∈[0, 1),α2j∈[0, 1)for all j= 1, 2, . . . ,N.Let S be the mapping generated by T1,T2, . . . ,TN andα1,α2, . . . ,αN.Then F(S) =

N

i=1F(Ti)and S is a

quasi-nonexpansive mapping.

By using these results, we obtain the following theorems.

Theorem 4.4 Let C and Q be nonempty closed convex subsets of a real Hilbert space H1

and H2,respectively.Let A:H1→H2be a bounded linear operator.Let D1,D2:CH1

beα,β-inverse strongly monotone mappings,respectively.Let F1:C×C→Rand F2:Q×

Q→Rbe the bifunctions satisfying(A1)(A4).Let{Ti}Ni=1be a finite family of nonspreading

mappings of C into C withNi=1F(Ti)=∅,and letαj= (α j

1,α

j

2,α

j

3)∈I×I×I,j= 1, 2, . . . ,N,

where I= [0, 1],αj1+α2j+α3j= 1,α1j,αj3∈(0, 1)for all j= 1, 2, . . . ,N– 1andα1N∈(0, 1],αN3 ∈ [0, 1),α2j∈[0, 1)for all j= 1, 2, . . . ,N.Let S be the mapping generated by T1,T2, . . . ,TNand

α1,α2, . . . ,αN.Let f1:H1→H1be aρ-inverse strongly monotone mapping and f2:H2→H2

be a firmly nonexpansive mapping.AssumeF=VI(C,D1)∩VI(C,D2)∩Ni=1F(Ti)∩=∅.

For given x1,uC and let{xn},{un}and{yn}be sequences generated by

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

un=TrF1(Irf1)(xn+γA∗(TsF2(Isf2) –I)Axn),

yn=PC(Id1D1)(aun+ (1 –a)PC(Id2D2)un),

xn+1=αnu+βnxn+γnPC(Iλn(IS))yn, ∀n∈N,

where d1∈(0, 2α),d2∈(0, 2β),r∈(0, 2ρ),s∈(0, 1),a∈[0, 1],γ∈(0, 1/L),L is the spectral

radius of the operator AA and Ais the adjoint of A.Also{αn},{βn},{γn}are sequences

in[0, 1]withαn+βn+γn= 1for all n∈N.Suppose the conditions(i)(iv)of Theorem3.4

hold.Then{xn},{un}and{yn}converge strongly to z=PFu.

Proof By using Corollary 3.5 and Lemma 4.3, we obtain the conclusion.

5 Example and numerical results

In this section, an example is given for supporting Theorem 3.4. In Example 5.1, we only instance an example in infinite dimensional Hilbert space for supporting Theorem 3.4. We omit the computer programming.

Example5.1 LetH1=H2=C=Q=2be the linear space whose elements consist of all

2-summable sequences (x1,x2, . . . ,xj, . . .) of scalars, i.e.,

2=

x:x= (x1,x2, . . . ,xj, . . .) and

j=1

|xj|2<∞

,

with an inner product·,·:2→Rdefined byx,y=

j=1xjyjwherex={xj}∞j=1,y=

{yj}∞j=1∈2and a norm · :2→Rdefined byx2= (

j=1|xj|2)

1

2 wherex={xj}∞

j=1∈2.

Let the mappingA:2→2be defined byAx= (x31,x32, . . . ,

xj

3, . . .) for all x={xj}∞j=1∈2

andA∗:2→2be defined byAz= (z31,z32, . . . ,

zj

Figure

Figure 1 The convergence comparison with different values N

References

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