MSET ENGINEERING CORPORATION SDN BHD
DOCUMENT TITLE: DESIGN CALCULATIONDOC. REF. NO.: MSETe/M2-152 SUBJECT: DAVIT CALC. ISO 9001:2000 REF: 4.0 1.0 MOMENT AND FORCES IN DAVIT AND VESSEL
(Ref:Pressure Vessel Design Manual 3rd Edition by Dennis R. Moss Page 291~295)
1.1 Load on davit : 1542.08Kg : 44.6 Kg = 1586.7 kg : 1.5 : 0.5 = 23348.39095 N = 7782.796984 N = 997mm = 889mm = 462mm = 30415490.2 Nmm Figure 1: Davit Weight of Blind, WL
Weight of Davit (Boom + Brace), W1 Axial Load, P = WL + W1
Vertical Impact Factor, Cv Horizontal Impact Factor, Ch Vertical Force, fv = Cv x P Horizontal Force, fh = Ch x P
1.2 Bending Moment in Davit Mast, M1
Length of Boom, L1 Length of Mast, L2 Length L5
2.0 STRESS IN DAVIT 2.1 Mast Properties Mast Material : SA 106B SCH 160 = 241.317 = 144.8 = 159.3 = 168.3mm Outside Radius, a = 84.15 mm = 18.26mm = 131.78 mm = 8607.1 = 292087.5 = 24579160.0
Radius of Gyration, r = Sqrt(I/A) = 53.4 mm
= 1.81
= 104.1
≤ 1
Calculate Combined Stress = 0.666
Since Calculate Combined Stress < 1 , Stress on Mast is
2.2 Boom Properties
Boom Material : SA 36
Boom Size : I Beam 152 x 152 x 37.2 kg/m
= 248.22 = 148.9 = 163.8 = 4735 = 91899 = 3.29 = 117.4 ≤ 1
Calculate Combined Stress = 0.739
Since Calculate Combined Stress < 1 , Stress on Boom is
Yield Stress, Fy N/mm2
Allowable Axial Stress, Fa = 0.6Fy N/mm2
Allowable Bending Stress, Fb = 0.66Fy N/mm2
Outside Diameter, Do Wall Thickness of Davit, tp Inside Diameter, Di
Cross Sectional Area, A1 = π/4 x(Do2-D
i2) mm2
Section Modulus, Z1 = (π/32Do)x (Do4-D
i4) mm3
Moment Inertia, I = π/64 x(Do4-D
i4) mm4
Axial Stress at Mast, fa = P/A N/mm2
Bending Stress at Mast, fb = M1/Z1 N/mm2
Combined Stress, fa/Fa + fb/Fb
Yield Stress, Fy N/mm2
Allowable Axial Stress, Fa = 0.6Fy N/mm2
Allowable Bending Stress, Fb = 0.66Fy N/mm2
Cross Sectional Area, A2 mm2
Section Modulus, Z2 mm3
Axial Stress at Boom, fa = P/A N/mm2
Bending Stress at Boom, fb = (fv xL5)/Z2 N/mm2 Combined Stress, fa/Fa + fb/Fb
3.0 WELDED DESIGN JOINT
(Ref:Pressure Vessel Handbook 12th Edition by Eugene F. Megyesy Page 459)
3.1 Davit Arm Bracket
Vertical Shear, V = 15128 N
Bending Moment, M = lV = 20180492 Nmm
Horizontal Weld Length,b = 224mm
Vertical Weld Length,d = 257mm
= 962 mm
Fillet Weld Used = 12mm
:
= 79584.3
Allowable load on weld,f = 9600psi
= 66.19
= 15.73 N/mm
= 253.57 N/mm
= 254.06 N/mm
Fillet Weld Leg Size,w =W/f = 3.84 mm
Since Calc. weld size > Weld used = Satisfactory
Length of Weld, Aw
Section Modulus (Bending Moment),Sw bd +(d2 /3)
mm2
N/mm2 Vertical Shear Forces,Ws =V/Aw
Bending Forces, Wb = M/Sw Resultant Force, W =(Wb2 + W
4.0 DESIGN OF LOCAL STRESS IN CYLINDRICAL SHELL
(Ref:Pressure Vessel Design Manual 3rd Edition by Dennis R. Moss Page 255~290)
4.1 Radial Load for Shell attachment
Half side vertical attachment, Cx =d/2 = 128.5 mm
= 112.0 mm Mean Radius, Rm = 620.6mm Shell thickness,t = 22.2mm Cx/Rm = 0.21 = 0.18 Load on attachment, F = 15128 N Kx from fig 5.13
Half side horizontal attachment, Cø =b/2
Cø/Rm
MSET ENGINEERING CORPORATION SDN BHD
DATE : 22/02/2010 ISSUE : 1
REVISION: 2 PAGE : 115 of 117
(Ref:Pressure Vessel Design Manual 3rd Edition by Dennis R. Moss Page 291~295)
= 15127.8048 N
= 437.79 N
Satisfactory
I Beam 152 x 152 x 37.2 kg/m
MSET ENGINEERING CORPORATION SDN BHD
DOCUMENT TITLE: DESIGN CALCULATIONDOC. REF. NO.: MSETe/M2-134
SUBJECT: PROPERTIES OF SECTION ISO 9001:2000 REF: 4.0
PROPERTIES OF SECTION
This table provides formula for calculating section Area, Moment of Inertia, Polar moment of inertia, Section Modulus, Radius of gyration and Centroidal distance for various cross section shapes.
Nomenclature :
A = Area
I = Moment of inertia J = Polar moment of inertia
Z = Section modulus = I/y
r = Radius of gyration mm = Sqrt (I/A)
y = Centriodal distance mm a) Rectangular relationships: A = b x h r = 0.289 x h y = h/2 b) Triangular relationships: A = b x h/2 r = 0.236 x h y = h/3 (Ref:Pressure Vessel Handbook 10th Edition by Paul Buthod Page 450 & 451)
mm2 mm4 mm4 mm3 I = (b x h3)/12 Z = (b x h2)/6 I = (b x h3)/36 Z = (b x h2)/24
c) Circle relationships:
r = d/4 y = d/2
d) Hollow circle relationships:
y = d/2
e) Half- Circle relationships:
r = 0.132 d y = 0.288 d
f) Half-Hollow Circle relationships:
Z = I/y A = π /4 x d2 I = π/64 x d4 Z = π/32 x d3 J = (π x d4) /32 A = π/4 x( d2 - di2) I = π/64 x( d4 - di4) Z = π /(32 x d) x (d4 - di4) J = (π x d4) /32 x (d4 - di4) r = sqrt ((d2 - di2) /16) wrong-to be check A = π x d2 /8 I = 0.007 d4 Z = 0.024 d3 A = 1.5708 (Ro2-r i2) I = 0.1098(Ro4-r i4) [0.283Ro2r i2 (Ro-ri)/(Ro+ri)]
r = Sqrt (I/A) y = 0.424(Ro3-r
g) Ellipse relationships: r = a/2 y = a h) T-Shape relationships: A = bs + ht Z = I/y r = Sqrt (I/A)
i) L-Shape(equal angle) relationships:
A = t(2a - t) Z = I/y r = Sqrt (I/A) A = π x ab I = 0.7854 a3b Z = 0.7854 a2b
I = 1/3{[ty3 + b(d-y)3] -[(b-t)(d-y-s)3]}
y = d - {[d2t + s2(b-t)]/2(bs +ht)}
I = 1/3{[ty3 + a(a-y)3]-[(a-t)(a-y-t)3]}
j) L-Shape(unqual angle) relationships: A = t(a + b - t) Z = I/y r = Sqrt (I/A) k) I-Shape relationships: A = bd-h(b-t) r = Sqrt (I/A) y = d/2
I = 1/3{[ty3 + a(b-y)3]-[(a-t)(b-y-t)3]}
y = a - {[t(2d + a) + d3]/2(d+a)}
I = [bd3 -h3(b-t)]/12 Z= [bd3 -h3(b-t)]/6d
MSET ENGINEERING CORPORATION SDN BHD
DATE : 31/03/2009 ISSUE :
REVISION: PAGE : of
This table provides formula for calculating section Area, Moment of Inertia, Polar moment of inertia, Section Modulus, Radius of gyration and Centroidal distance for various cross section
r = 0.132 d y = 0.288 d π x d4) /32 π/4 x( d2 - di2) π/64 x( d4 - di4) π /(32 x d) x (d4 - di4) π x d4) /32 x (d4 - di4) r = sqrt ((d2 - di2) /16) wrong-to be check A = π x d2 /8 I = 0.007 d4 Z = 0.024 d3 A = 1.5708 (Ro2-r i2) I = 0.1098(Ro4-r i4) [0.283Ro2r i2 (Ro-ri)/(Ro+ri)]
r = Sqrt (I/A) y = 0.424(Ro3-r
+ b(d-y)3] -[(b-t)(d-y-s)3]}
t + s2(b-t)]/2(bs +ht)}
+ a(a-y)3]-[(a-t)(a-y-t)3]}
+ a(b-y)3]-[(a-t)(b-y-t)3]}